So I am using one of the imgur api examples for uploading an image but am stuck on how I retrieve the upload link to view the image.
This is what I have so far, and from what I can tell it uploads it but that itself is not very useful without getting a link to the upload.
This is what I have thus far.
String IMGUR_POST_URI = "http://api.imgur.com/2/upload.xml";
String IMGUR_API_KEY = "MY API KEY";
String file = "C:\\Users\\Shane\\Pictures\\Misc\\001.JPG";
try
{
// Creates Byte Array from picture
ByteArrayOutputStream baos = new ByteArrayOutputStream();
System.out.println("Writing image...");
ImageIO.write(getBufferedImageFromImage(Toolkit.getDefaultToolkit().createImage(file)), "png", baos);
URL url = new URL(IMGUR_POST_URI);
System.out.println("Encoding...");
//encodes picture with Base64 and inserts api key
String data = URLEncoder.encode("image", "UTF-8") + "=" + URLEncoder.encode(Base64.encodeBase64String(baos.toByteArray()).toString(), "UTF-8");
data += "&" + URLEncoder.encode("key", "UTF-8") + "=" + URLEncoder.encode(IMGUR_API_KEY, "UTF-8");
System.out.println("Connecting...");
// opens connection and sends data
URLConnection conn = url.openConnection();
conn.setDoOutput(true);
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
System.out.println("Sending data...");
wr.write(data);
wr.flush();
}
catch(Exception e){e.printStackTrace();}
You should get back either an xml or json with the 'response' to the upload, according to the imgur docs.
I found this little snippet of code that is an example of getting the response after writing to a URL connection, maybe it will help you. This isn't specific to imgur but I think the code should be similar.
public static void main(String[] args) throws Exception {
String stringToReverse = URLEncoder.encode(args[1], "UTF-8");
URL url = new URL(args[0]);
URLConnection connection = url.openConnection();
connection.setDoOutput(true);
OutputStreamWriter out = new OutputStreamWriter(
connection.getOutputStream());
out.write("string=" + stringToReverse);
out.close();
BufferedReader in = new BufferedReader(
new InputStreamReader(
connection.getInputStream()));
String decodedString;
while ((decodedString = in.readLine()) != null) {
System.out.println(decodedString);
}
in.close();
}
Related
I am having troubles with posting http POST request in java. All the details are correct, but I am getting error for not valid API key.
I tried everything, and read every single post that I could find here but still no clue what is incorrect.
Here's the code:
String urlString = "https://example.com/";
url = new URL(urlString);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setDoOutput(true);
String data = URLEncoder.encode("api_key", "UTF-8")
+ "=" + URLEncoder.encode("xxxxx", "UTF-8");
urlConnection.connect();
OutputStreamWriter wr = new OutputStreamWriter(urlConnection.getOutputStream());
wr.write(data);
wr.flush();
try{
stream = urlConnection.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(stream, "UTF-8"), 8);
String result = reader.readLine();
System.out.println(result);
} catch (IOException e){
throw(new Throwable("An error occured:\n" + e));
}
I'm trying to send a POST request to grab comments but it doesn't work in Java while it does work with postman.
I get an 403 Forbidden error, but on postman it retrieves the data i need just fine..
Here's the Java code I'm trying to use to replicate the behavior.
String targetUrl = YOUTBE_COMMENTS_AJAX_URL;
String urlParameters = "action_load_comments=1&order_by_time=True&filter=jBjXVrS8nXs";
String updatedURL = targetUrl + "?" + urlParameters;
URL url = null;
InputStream stream = null;
HttpURLConnection urlConnection = null;
try {
url = new URL(updatedURL);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("POST");
urlConnection.setRequestProperty("content-type", "multipart/form-data");
urlConnection.setRequestProperty("user-agent", "USER_AGENT");
urlConnection.setDoOutput(true);
String data = URLEncoder.encode("video_id", "UTF-8")
+ "=" + URLEncoder.encode(youtubeId, "UTF-8");
data += "&" + URLEncoder.encode("session_token", "UTF-8") + "="
+ URLEncoder.encode(xsrfToken, "UTF-8");
data += "&" + URLEncoder.encode("page_token", "UTF-8") + "="
+ URLEncoder.encode(pageToken, "UTF-8");
urlConnection.connect();
OutputStreamWriter wr = new OutputStreamWriter(urlConnection.getOutputStream());
wr.write(data);
wr.flush();
stream = urlConnection.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(stream, "UTF-8"), 8);
String result = reader.readLine();
return result;
} catch (IOException e) {
e.printStackTrace();
} finally {
if (urlConnection != null) {
urlConnection.disconnect();
}
}
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
return null;
Here's an example of what postman is sending in their headers
It seems like your problem is here (see inline comments):
DataOutputStream wr = new DataOutputStream(conn.getOutputStream());
wr.writeBytes(urlParameters);
// you wrote your URL parameters into Body
wr.flush();
wr.close();
//You closed your body and told server - you are done with request
conn.getOutputStream().write(postDataBytes);
// you wrote data into closed stream - server does not care about it anymore.
You have to append your urlParameters directly to the URL when you open it
Then you have to write your Form Data into body as you do:
conn.getOutputStream().write(postDataBytes);
and then close output stream
I am really stuck on this problem and hoping for some help. I automatically log in to a Server and download a Excel (xlsx) File. The download seems to work fine, cause the size is the same as on the server and if I open the file with an XML-Editor it looks valid (compared to other excel Files).
But if I try to open the downloaded file with excel I got a "The file might be corrupt" message and it's not readable.
I tried to change the encoding of the file, the headers of the GET-Request, even tried to write it as Bytestream. Nothing changed.
Here are some relevant code snippets:
public HttpsURLConnection login()
{
HttpsURLConnection connection = null;
String user = "user";
String password = "password";
String authString = user + ":" + password;
byte[] authEncBytes = Base64.encodeBase64(authString.getBytes());
String authStringEnc = new String(authEncBytes);
try {
connection = (HttpsURLConnection)url.openConnection();
connection.setRequestMethod("GET");
connection.setRequestProperty("Authorization", "Basic " + authStringEnc);
connection.setRequestProperty("Content-Type", "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
//connection.setRequestProperty("Content-Type", "application/vnd.openxml");
connection.setRequestProperty("Accept", "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
//connection.setRequestProperty("Accept", "application/vnd.openxml");
connection.setRequestProperty("User-Agent", USER_AGENT);
connection.connect();
} catch (IOException e)
{
e.printStackTrace();
}
return connection;
}
The download class
private void sendGet(HttpsURLConnection con) throws Exception {
int responseCode = con.getResponseCode();
System.out.println("\nSending 'GET' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
String fileName = "test.xlsx";
file = new File(fileName);
if (!file.exists()) {
file.createNewFile();
}
//use FileWriter to write file
FileWriter fw = new FileWriter(file.getAbsoluteFile());
//BufferedWriter bw = new BufferedWriter(fw);
/**CharsetEncoder encoder = Charset.forName("UTF-8").newEncoder();
encoder.onMalformedInput(CodingErrorAction.REPORT);
encoder.onUnmappableCharacter(CodingErrorAction.REPORT);**/
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(
new FileOutputStream(fileName), "UTF-8"
));
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
bw.write(inputLine);
}
in.close();
bw.close();
//print result
//System.out.println(response.toString());
}
You can see my attempts in some of the commented lines.
I appreciate any help. Thanks in advance.
I am new to android.So i can any one sho me how to make a http get request such as
GET /photos?size=original&file=vacation.jpg HTTP/1.1
Host: photos.example.net:80
Authorization: OAuth realm="http://photos.example.net/photos",
oauth_consumer_key="dpf43f3p2l4k3l03",
oauth_token="nnch734d00sl2jdk",
oauth_nonce="kllo9940pd9333jh",
oauth_timestamp="1191242096",
oauth_signature_method="HMAC-SHA1",
oauth_version="1.0",
oauth_signature="tR3%2BTy81lMeYAr%2FFid0kMTYa%2FWM%3D"
in android(java)?
You're gonna want to get familiar with InputStreams and OutputStreams in Android, if you've done this in regular java before then its essentially the same thing. You need to open a connection with the request property as "GET", you then write your parameters to the output stream and read the response through an input stream. You can see this in my code below:
try {
URL url = null;
String response = null;
String parameters = "param1=value1¶m2=value2";
url = new URL("http://www.somedomain.com/sendGetData.php");
//create the connection
connection = (HttpURLConnection) url.openConnection();
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type",
"application/x-www-form-urlencoded");
//set the request method to GET
connection.setRequestMethod("GET");
//get the output stream from the connection you created
request = new OutputStreamWriter(connection.getOutputStream());
//write your data to the ouputstream
request.write(parameters);
request.flush();
request.close();
String line = "";
//create your inputsream
InputStreamReader isr = new InputStreamReader(
connection.getInputStream());
//read in the data from input stream, this can be done a variety of ways
BufferedReader reader = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
//get the string version of the response data
response = sb.toString();
//do what you want with the data now
//always remember to close your input and output streams
isr.close();
reader.close();
} catch (IOException e) {
Log.e("HTTP GET:", e.toString());
}
This is the method I have in my java application. It is reading the bytes correctly, I have logged to see if it was. The problem is that the php is not realizing the data is there. I have tested and the .php reads that $_POST is set, but is empty.
public void screenshot(BufferedImage screenshot) {
try {
ImageIO.write(screenshot, "png",
new File(Environment.getStorageDirectory().toString()
.concat(File.separator + SCRIPT_NAME + ".png")));
HttpURLConnection httpUrlConnection;
OutputStream outputStream;
BufferedInputStream fileInputStream;
BufferedReader serverReader;
int totalBytes;
String response = "";
String serverResponse = "";
String localFileName = Environment.getStorageDirectory().toString()
.concat(File.separator + SCRIPT_NAME + ".png");
// Establish a connection
httpUrlConnection = (HttpURLConnection) new URL(
"http://www.scripted.it/scriptoptions/utils/saveScreenshot.php?user="
+ SupraCrafter.statHandler.getUser())
.openConnection();
httpUrlConnection.setDoOutput(true);
httpUrlConnection.setDoInput(true);
httpUrlConnection.setRequestMethod("POST");
httpUrlConnection.setRequestProperty("Content-type",
"application/x-www-form-urlencoded");
outputStream = httpUrlConnection.getOutputStream();
// Buffered input stream
fileInputStream = new BufferedInputStream(new FileInputStream(
localFileName));
// Get the size of the image
totalBytes = fileInputStream.available();
// Loop through the files data
for (int i = 0; i < totalBytes; i++) {
// Write the data to the output stream
outputStream.write(fileInputStream.read());
}
// Close the output stream
outputStream.close();
// New reader to get server response
serverReader = new BufferedReader(new InputStreamReader(
httpUrlConnection.getInputStream()));
// Read the servers response
serverResponse = "";
while ((response = serverReader.readLine()) != null) {
serverResponse = serverResponse + response;
}
System.out.println(serverResponse);
// Close the buffered reader
serverReader.close();
} catch (Exception e) {
e.printStackTrace();
}
try {
URL url = new URL(
"http://scripted.it/scriptoptions/utils/setScreenshotStatus.php?user="
+ SupraCrafter.statHandler.getUser() + "&pass="
+ SupraCrafter.statHandler.getPass() + "&script="
+ SCRIPT_NAME + "&status=1");
BufferedReader in = new BufferedReader(new InputStreamReader(
url.openStream()));
in.close();
} catch (MalformedURLException e) {
} catch (IOException e) {
}
}
Here is the .php file:
<?
// Config
$uploadBase = "../screenshots/";
$uploadFilename = $_GET['user'] . ".png";
$uploadPath = $uploadBase . $uploadFilename;
// Upload directory
if(!is_dir($uploadBase))
mkdir($uploadBase);
// Grab the data
$incomingData = file_get_contents('php://input');
// Valid data?
if(!$incomingData)
die("No input data");
// Write to disk
$fh = fopen($uploadPath, 'w') or die("Error opening file");
fwrite($fh, $incomingData) or die("Error writing to file");
fclose($fh) or die("Error closing file");
echo "Success";
?>
It always echos 'no input data.'
You are not encoding the content with application/x-www-form-urlencoded. You should not simply copy the bytes into the HTTP payload, but instead encode it correctly.
application/x-www-form-urlencoded is not the only possible way of encoding it, multipart/form-data is another common choice. Both are supported by almost all webservers, and as a consequence by PHP.
A tutorial on how to encode using Java is here : http://www.devx.com/Java/Article/17679
Why don't you use Apache's HttpClient or similar library that already do that tedious work for you?
Apache HttpClient : http://hc.apache.org/httpcomponents-client-ga/