For testing, I've got three names in a text file.
Joe ,Smith
Jim ,Jones
Bob ,Johnson
I fixed the eternal looping by adding a second s=reader.readLine(); at the end of my while loop, but when I run the code below, I get the following output:
JoeSmith
JoeSmith
JimJones
JimJones
BobJohnson
BobJohnson
How can I prevent the duplicate names? Is my second s=reader.readLine(); placed incorrectly? * Crap. Nevermind. I'm printing the source data and the array fields created from it. Oy.
import java.nio.file.*;
import java.io.*;
import java.nio.channels.FileChannel;
import java.nio.ByteBuffer;
import static java.nio.file.StandardOpenOption.*;
import java.util.Scanner;
import java.text.*;
import javax.swing.JOptionPane;
//
public class VPass
{
public static void main(String[] args)
{
final String FIRST_FORMAT = " ";
final String LAST_FORMAT = " ";
String delimiter = ",";
String s = FIRST_FORMAT + delimiter + LAST_FORMAT ;
String[] array = new String[2];
Scanner kb = new Scanner(System.in);
Path file = Paths.get("NameLIst.txt");
try
{
InputStream iStream=new BufferedInputStream(Files.newInputStream(file));
BufferedReader reader=new BufferedReader(new InputStreamReader(iStream));
s=reader.readLine();
while(s != null)
{
array = s.split(delimiter);
String firstName = array[0];
String lastName = array[1];
System.out.println(array[0]+array[1]+"\n"+firstName+lastName);
s=reader.readLine();
}
}
catch(Exception e)
{
System.out.println("Message: " + e);
}
}
}
You never update s after the first loop iteration.
You code needs to be more along the lines of:
while ((s = reader.readLine()) != null)
{
array = s.split(delimiter);
String firstName = array[0].trim();
String lastName = array[1].trim();
System.out.println(array[0]+array[1]+"\n"+userName+password);
}
Edit: added trim() suggestion as per Sanchit's comment.
Subsequent edit after the question changed:
I fixed the eternal looping by adding a second s=reader.readLine(); at the end of my while loop, but when I run the code below, I get the following output:
JoeSmith
JoeSmith
JimJones
JimJones
BobJohnson
BobJohnson
If we look at your code:
while(s != null)
{
array = s.split(delimiter);
String firstName = array[0];
String lastName = array[1];
System.out.println(array[0]+array[1]+"\n"+firstName+lastName); // <-- this prints 2 lines of output
s=reader.readLine();
}
... you see you output 2 lines of output for every loop iteration.
Put s=reader.readLine(); again at the end of your while loop. Eventually it will become null and your loop will exit.
Related
I'm trying to concatenate strings in new lines when a condition is met. This is my input:
Concept
soft top cove
tonneau cove
interior persennin
Concept
Innen
Innenraum
Platz im Inneren
All I want to do is to concatenate all the strings after the string concept and to get the following output:
lemma, surface
soft top cove, tonneau cove|interior persennin
Innen, Innenraum|Platz im Inneren
I know if a string value is equal concept I want to go to the other line and write the string of the next line before a comma, than the strings from the other lines delimited by "|" e.g. soft top cove, tonneau cove|interior persenning
This is my code so far. Any suggestions are welcome!
Thank you:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileWriter;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.ArrayList;
import java.util.List;
public class Converter {
public static void main(String[] args) {
// TODO Auto-generated method stub
BufferedReader inputcsv = null;
List <String> zeilencsv = new ArrayList<String>();
try {
inputcsv = Files.newBufferedReader(Paths.get("ErsteDatei.csv"));
String content;
while ((content = inputcsv.readLine()) != null) {
zeilencsv.add(content);
System.out.println(content);
}
File outputcsv = new File("TwoColumnsResult.csv");
//creates new file
outputcsv.createNewFile();
FileWriter csvFilewriter = new FileWriter(outputcsv);
//arraylist loop
int counter_a=0;
int counter = 1;
for (String zeile:zeilencsv){
String concept = "Concept";
//check string value =concept?
if(zeile.toString().equals(concept)){
zeile="lemma,surface";
for(String zeile2:zeilencsv){
//here I don't know how to say give me the next line, write it as a word , put comma and than concatenate with a |
}
}
else {
counter++;
}
csvFilewriter.write(zeile+"\n");
counter++;
}
//write
csvFilewriter.flush();
//closes the file
csvFilewriter.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
so if I understood correctly you want that after finding "Concept" save the next line as text, concatenate a comma, then save the next line and concatenate a | and then save the next?
Well the code that you're using is kind of bizarre but what I would do is the next:
zeile="lemma,surface";
// I'll put a counter to distinguish where to put "," and "|"
int counter = 0;
// Then I need a string variable to save the line
String line = "";
for(String zeile2:zeilencsv){
if (count == 0){ //First iteration
line = zeile2.toString();
}
if(count == 1){ . //Second iteration add the comma
line = line + "," + zeile2.toString();
}
if(count == 2){ . //Second iteration add the pipe
line = line + "|" + zeile2.toString();
}
count++;
}
I hope that this is what you're looking for. If you would like to optimize the code, feel free to send me a message and we could work together.
I am trying to display the contents of multiple rows in a text file. I can do it no problem with a single line, but I add another line and I'm not sure what I need to add to my code to make it move on to the next line. I need myValues[1] to be the same as myValues[n] only to be the second line in the file. I believe I need to se a new String as the next line but I'm not sure exactly how with this setup.
package a3;
import java.io.*;
public class A3
{
public static void main(String [] args)
{
String animals = "animals.txt";
String line = null;
try
{
FileReader fileReader = new FileReader(animals);
BufferedReader bufferedReader = new BufferedReader(fileReader);
String aLine = bufferedReader.readLine();
String myValues[] = aLine.split(" ");
int n = 0;
while((line = bufferedReader.readLine()) != null)
{
System.out.println(myValues[n] + " " + myValues[1]);
n++;
}
bufferedReader.close();
}
catch(FileNotFoundException ex)
{
System.out.println("Unable to open file '" + animals + "'");
}
catch(IOException ex)
{
System.out.println("Error reading file '" + animals + "'");
}
}
}
Here is another simple way to read lines from a file and do the processing:
There is a java.io.LineNumberReader class which helps do it.
Sample snippet:
LineNumberReader lnr = new LineNumberReader(new FileReader(new File(filename)));
String line = null;
while ((line = lnr.readLine()) != null)
{
// Do you processing on line
}
In your code, the array myValues is never changed and always contains the values for the first line of text. You need to change it each time you get a new line, this is done in your while loop :
[...]
while((line = bufferedReader.readLine()) != null)
{
myValues[] = line.split(" ");
System.out.println(myValues[n] + " " + myValues[1]);
n++;
}
Obviously not tested...
You could also read all lines to a String list like this:
import java.io.File;
import java.io.IOException;
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.util.List;
List<String> lines = Files.readAllLines(new File(animals).toPath(), Charset.defaultCharset());
And than iterate over the line list, split the values and output them.
Below is what the text document looks like. The first line is the number of elements that I want the array to contain. The second is the ID for the product, separated by # and the third line is the total price of the products once again separated by #
10
PA/1234#PV/5732#Au/9271#DT/9489#HY/7195#ZR/7413#bT/4674#LR/4992#Xk/8536#kD/9767#
153#25#172#95#235#159#725#629#112#559#
I want to use the following method to pass inputFile to the readProductDataFile method:
public static Product[] readProductDataFile(File inputFile){
// Code here
}
I want to create an array of size 10, or maybe an arrayList. Preferably to be a concatenation of Customer ID and the price, such as Array[1] = PA/1234_153
There you go the full class, does exactly what you want:
import java.io.BufferedReader;
import java.io.FileReader;
import java.util.Arrays;
import java.io.FileNotFoundException;
import java.io.IOException;
class myRead{
public static void main(String[] args) throws FileNotFoundException, IOException {
BufferedReader inputFile = new BufferedReader(new FileReader("test.txt"));
String numberOfElements = inputFile.readLine();
//this is the first line which contains the number "10"
//System.out.println(numberOfElements);
String secondLine = inputFile.readLine();
//this is the second line which contains your data, split it using "#" as a delimiter
String[] strArray = secondLine.split("#");
//System.out.println(Arrays.toString(strArray));
//System.out.println(strArray[0]);
String thirdLine = inputFile.readLine();
//this is the third line which contains your data, split it using "#" as a delimiter
String[] dataArray = thirdLine.split("#");
//combine arrays
String[] combinedArray = new String[strArray.length];
for (int i=0;i<strArray.length;i++) {
combinedArray[i]=strArray[i]+"_"+dataArray[i];
System.out.println(combinedArray[i]);
}
}
}
OUTPUT:
PA/1234_153
PV/5732_25
Au/9271_172
DT/9489_95
HY/7195_235
ZR/7413_159
bT/4674_725
LR/4992_629
Xk/8536_112
kD/9767_559
The trick in what I am doing is using a BufferedReader to read the file, readLine to read each of the three lines, split("#"); to split each token using the # as the delimiter and create the arrays, and combinedArray[i]=strArray[i]+"_"+dataArray[i]; to put the elements in a combined array as you want...!
public static Product[] readProductDataFile(File inputFile){
BufferedReader inputFile = new BufferedReader(new FileReader(inputFile));
// the rest of my previous code goes here
EDIT: Everything together with calling a separate method from inside the main, with the file as an input argument!
import java.io.BufferedReader;
import java.io.FileReader;
import java.util.Arrays;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.File;
class myRead{
public static void main(String[] args) throws FileNotFoundException, IOException {
File myFile = new File("test.txt");
readProductDataFile(myFile);
}
public static String[] readProductDataFile(File inputFile) throws FileNotFoundException, IOException{
BufferedReader myReader = new BufferedReader(new FileReader("test.txt"));
String numberOfElements = myReader.readLine();
//this is the first line which contains the number "10"
//System.out.println(numberOfElements);
String secondLine = myReader.readLine();
//this is the second line which contains your data, split it using "#" as a delimiter
String[] strArray = secondLine.split("#");
//System.out.println(Arrays.toString(strArray));
//System.out.println(strArray[0]);
String thirdLine = myReader.readLine();
//this is the third line which contains your data, split it using "#" as a delimiter
String[] dataArray = thirdLine.split("#");
//combine arrays
String[] combinedArray = new String[strArray.length];
for (int i=0;i<strArray.length;i++) {
combinedArray[i]=strArray[i]+"_"+dataArray[i];
System.out.println(combinedArray[i]);
}
return combinedArray;
}
}
OUTPUT
PA/1234_153
PV/5732_25
Au/9271_172
DT/9489_95
HY/7195_235
ZR/7413_159
bT/4674_725
LR/4992_629
Xk/8536_112
kD/9767_559
You don't even need the first line. Just read the second line directly into a single string and then split it by using String,split() method.
Read more for split method here.
You could use something like this (Be aware that i can't test it at the moment)
BufferedReader in = null;
try {
in = new BufferedReader(new FileReader("fileeditor.txt"));
String read = null;
String firstLine=in.readLine();
//reads the first line
while ((read = in.readLine()) != null) {
// reads all the other lines
read = in.readLine();
String[] splited = read.split("#");
//split the readed row with the "#" character
for (String part : splited) {
System.out.println(part);
}
}
} catch (IOException e) {
System.out.println("There was a problem: " + e);
e.printStackTrace();
} finally {
try {
//close file
in.close();
} catch (Exception e) {
}
}
This is how you can do it using Java (don't forget to import):
public static Product[] readProductDataFile(File inputFile){
Scanner s = new Scanner(inputFile);
String data = "";
while(s.hasNext())
data += s.nextLine();
String[] dataArray = data.split("#");
}
You can try this way ..
Reading line by line and storing each row in a array.
Use while storing so it will split and save .
String[] strArray = secondLine.split("#");
Now use the for loop and concat the values as u wish and save ina third array .
For(int i=0 ;i< file.readline;i++)
{
string s = a[customerid];
s.concat(a[productid]);
a[k] =s;
}
My bad for the title, I am usually not good at making those.
I have a programme that will generate all permutations of an inputted word and that is supposed to check to see if those are words (checks dictionary), and output the ones that are. Really I just need the last the part and I can not figure out how to parse through a file.
I took out what was there (now displaying the "String words =") because it really made thing worse (was an if statement). Right now, all it will do is output all permutations.
Edit: I should add that the try/catch was added in when I tried turning the file in a list (as opposed to the string format which it is currently in). So right now it does nothing.
One more thing: is it possible (well how, really) to get the permutations to display permutations with lesser characters than entered ? Sorry for the bad wording, like if I enter five characters, show all five character permutations, and four, and three, and two, and one.
import java.util.List;
import java.util.Scanner;
import java.io.BufferedReader;
import java.io.File;
import java.io.InputStreamReader;
import java.io.IOException;
import org.apache.commons.io.FileUtils;
import static java.lang.System.out;
public class Permutations
{
public static void main(String[] args) throws Exception
{
out.println("Enter anything to get permutations: ");
Scanner scan = new Scanner(System.in);
String io = scan.nextLine();
String str = io;
StringBuffer strBuf = new StringBuffer(str);
mutate(strBuf,str.length());
}
private static void mutate(StringBuffer str, int index)
{
try
{
String words = FileUtils.readFileToString(new File("wordsEn.txt"));
if(index <= 0)
{
out.println(str);
}
else
{
mutate(str, index - 1);
int currLoc = str.length()-index;
for (int i = currLoc + 1; i < str.length(); i++)
{
change(str, currLoc, i);
mutate(str, index - 1);
change(str, i, currLoc);
}
}
}
catch(IOException e)
{
out.println("Your search found no results");
}
}
private static void change(StringBuffer str, int loc1, int loc2)
{
char t1 = str.charAt(loc1);
str.setCharAt(loc1, str.charAt(loc2));
str.setCharAt(loc2, t1);
}
}
If each word in your file is actually on a different line, maybe you can try this:
BufferedReader br = new BufferedReader(new FileReader(file));
String line = null;
while ((line = br.readLine()) != null)
{
... // check and print here
}
Or if you want to try something else, the Apache Commons IO library has something called LineIterator.
An Iterator over the lines in a Reader.
LineIterator holds a reference to an open Reader. When you have finished with the iterator you should close the reader to free internal resources. This can be done by closing the reader directly, or by calling the close() or closeQuietly(LineIterator) method on the iterator.
The recommended usage pattern is:
LineIterator it = FileUtils.lineIterator(file, "UTF-8");
try {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
} finally {
it.close();
}
I am implementing a RPN calculator in Java and need help creating a class to parse the equations into separate tokens.
My input file will have an unknown number of equations similar to the ones shown below:
49+62*61-36
4/64
(53+26)
0*72
21-85+75-85
90*76-50+67
46*89-15
34/83-38
20/76/14+92-15
I have already implemented my own generic stack class to be used in the program, but I am now trying to figure out how to read data from the input file. Any help appreciated.
I've posted the source code for my stack class at PasteBin, in case it may help.
I have also uploaded the Calculator with no filereading to PasteBin to show what I have done already.
I have now managed to get the file read in and the tokens broken up thanks for the help. I am getting an error when it reaches the end of the file and was wondering how to solve that?
Here is the code:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.StringTokenizer;
public class TestClass {
static public void main(String[] args) throws IOException {
File file = new File("testEquations.txt");
String[] lines = new String[10];
try {
FileReader reader = new FileReader(file);
BufferedReader buffReader = new BufferedReader(reader);
int x = 0;
String s;
while((s = buffReader.readLine()) != null){
lines[x] = s;
x++;
}
}
catch(IOException e){
System.exit(0);
}
String OPERATORS = "+-*/()";
for (String st : lines) {
StringTokenizer tokens = new StringTokenizer(st, OPERATORS, true);
while (tokens.hasMoreTokens()) {
String token = tokens.nextToken();
if (OPERATORS.contains(token))
handleOperator(token);
else
handleNumber(token);
}
}
}
private static void handleNumber(String token) {
System.out.println(""+token);
}
private static void handleOperator(String token) {
System.out.println(""+token);
}
}
Also How would I make sure the RPN works line by line? I am getting quite confused by the algorithms I am trying to follow.
Because all of the operators are single characters, you can instruct StringTokenizer to return them along with the numeric tokens.
String OPERATORS = "+-*/()";
String[] lines = ...
for (String line : lines) {
StringTokenizer tokens = new StringTokenizer(line, OPERATORS, true);
while (tokens.hasMoreTOkens()) {
String token = tokens.nextToken();
if (OPERATORS.contains(token))
handleOperator(token);
else
handleNumber(token);
}
}
As your question has now changed completely from it's original version - this is in response to your original one, which was how to use FileReader to get the values from your file.
This will put each line into a separate element of a String array. You should probably use an ArrayList instead, as it's far more flexible, but I have just done this as a quick demo - you can clean it up as you wish, although I notice the code you are using expects a String array as it's input. Perhaps you could read the values initially into an ArrayList, then copy that to an array once you have all the lines - that way you can put as many lines in as you wish and keep your code flexible for changes in the number of lines in your input file.
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public class TestClass {
static public void main(String[] args) {
File file = new File("myfile.txt");
String[] lines = new String[10];
try {
FileReader reader = new FileReader(file);
BufferedReader buffReader = new BufferedReader(reader);
int x = 0;
String s;
while((s = buffReader.readLine()) != null){
lines[x] = s;
x++;
}
}
catch(IOException e){
//handle exception
}
// And just to prove we have the lines right where we want them..
for(String st: lines)
System.out.println(st);
}
}
You mentioned before that you were using the code on this link:
http://www.technical-recipes.com/2011/a-mathematical-expression-parser-in-java/#more-1658
This appears to already deal with operator precedence doesn't it? And with parsing each String from the array and sorting them into numbers or operators? From my quick look it at least it appears to do that.
So it looks like all you need is for your lines to be in a String array, which you then pass to the code you already have. From what I can see anyway.
Obviously this doesn't address the issue of numbers greater than 9, but hopefully it helps with the first half.
:-)
public void actionPerformed(ActionEvent e) {
double sum=0;
int count = 0 ;
try {
String nomFichier = "Fichier.txt";
FileReader fr = new FileReader(nomFichier);
BufferedReader br = new BufferedReader(fr);
String ligneLue;
do {
ligneLue = br.readLine();
if(ligneLue != null) {
StringTokenizer st = new StringTokenizer(ligneLue, ";");
String nom = st.nextToken();
String prenom = st.nextToken();
String age = st.nextToken();
String tele = st.nextToken();
String adress = st.nextToken();
String codePostal = st.nextToken();
String ville = st.nextToken();
String paye = st.nextToken();
double note = Double.parseDouble(st.nextToken());
count++;
}
}
while(ligneLue != null);
br.close();
double mediane = count / 2;
if(mediane % 2 == 0) {
JOptionPane.showMessageDialog(null, "Le mediane dans le fichier est " + mediane);
}
else {
mediane +=1;
JOptionPane.showMessageDialog(null, "Le mediane dans le fichier est " + mediane);
}
}//fin try
catch(FileNotFoundException ex) {
System.out.println(ex.getMessage());
}
catch(IOException ex) {
System.out.println(ex.getMessage());
}
}