I am trying to make a program in which I want, when I hit any url or u can say websites, all contents of that websites is being read by me. I am using URL class for this.
Here is my code ..
import java.net.*;
import java.io.*;
public class URLConnectionReader
{
public static void main(String[] args) throws Exception
{
URL oracle = new URL("http://www.oracle.com/index.html");
URLConnection yc = oracle.openConnection();
BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
in.close();
}
}
But In response it is showing view page source's contents, I want only web-page contents, not all. How can I do this?
Then parse that HTML you recieved using HTML parser (like jsoup)
web-page contents == page source. the browser analyze the html and visualize it for human eye.
if you want only the body text you can use jsoup:
String text = Jsoup.parse(html).body().text();
but you gonna get also some commercials, menus and other text that not necessary the content you wanted.
Related
How can i get spesific words from an url in java. Like i want to take datas from class which calling like blablabla.
Here is my code.
URL url = new URL("https://www.doviz.com/");
URLConnection connect = url.openConnection();
InputStream is = connect.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
while((line = br.readLine()) != null)
{
System.out.println(line);
}
Take a look at Jsoup , this will allow you to get the content of a web page and NOT the HTML code. Let's say it will play the role of the browser, it will parse the HTML tags into a human readable text.
Once you will get the content of your page in a String, you can count the occurrences of your word using any algorithm of occurrences count.
Simple example to use it:
import org.jsoup.Jsoup;
import org.jsoup.nodes.Document;
/* ........ */
String URL = "https://www.doviz.com/";
Document doc = Jsoup.connect(URL).get();
String text = doc.body().text();
System.out.println(text);
EDIT
If you don't want to use a parser (as you mentioned in the comment that you don't want external libraries), you will get the whole HTML code of the page, that's how you can do it
try {
URL url = new URL("https://www.doviz.com/");
BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
String str;
while ((str = in.readLine()) != null) {
str = in.readLine().toString();
System.out.println(str);
/*str will get each time the new line, if you want to store the whole text in str
you can use concatenation (str+ = in.readLine().toString())*/
}
in.close();
} catch (Exception e) {}
I'm new to java programming. I want only the web contents of the page. but the program I got gives me the html tags with the content which i don't want.
Can anyone help me with this?
Thank you.
My code looks like this:
import java.net.*;
import java.io.*;
public class URLReader {
public static void main(String[] args) throws Exception {
URL oracle = new URL("http://www.oracle.com/");
BufferedReader in = new BufferedReader(
new InputStreamReader(oracle.openStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
in.close();
}
}
If you really want only a small portion of the web page, you'll have to parse the HTML page you receive. There is no other way around. When you use your InputStreamReader to read the content of your page, you'll get the same thing your browser gets.
The only difference between the browser and your code is that the browser interprets the content.
You'll need to parse the HTML (XML) content you got to find the correct text.
Here is a nice tutorial you can follow to use the built-in Java XML parser: https://www.tutorialspoint.com/java_xml/java_dom_parser.htm
I want to get the value of "Yield" in "http://www.aastocks.com/en/ltp/rtquote.aspx?symbol=01319"
How can I do this with java?
I have tried "Jsoup" and my code like these:
public static void main(String[] args) throws IOException {
String url = "http://www.aastocks.com/en/ltp/rtquote.aspx?symbol=01319";
Document document = Jsoup.connect(url).get();
Elements answerers = document.select(".c3 .floatR ");
for (Element answerer : answerers) {
System.out.println("Answerer: " + answerer.data());
}
// TODO code application logic here
}
But it return empty. How can I do this?
Your code is fine. I tested it myself. The problem is the URL you're using. If I open the url in a browser, the value fields (e.g. Yield) are empty. Using the browser development tools (Network tab) you should get an URL that looks like:
http://www.aastocks.com/en/ltp/RTQuoteContent.aspx?symbol=01319&process=y
Using this URL gives you the wanted results.
The simplest solution is to create a URL instance pointing to the web page / link you want get the content using streams-
for example-
public static void main(String[] args) throws IOException
{
URL url = new URL("http://www.aastocks.com/en/ltp/rtquote.aspx?symbol=01319");
// Get the input stream through URL Connection
URLConnection con = url.openConnection();
InputStream is =con.getInputStream();
// Once you have the Input Stream, it's just plain old Java IO stuff.
// For this case, since you are interested in getting plain-text web page
// I'll use a reader and output the text content to System.out.
// For binary content, it's better to directly read the bytes from stream and write
// to the target file.
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
// read each line and write to System.out
while ((line = br.readLine()) != null) {
System.out.println(line);
}
}
I think Jsoup is critical in this purpose. I would not suspect a valid HTML document (or whatever).
I've looked for answers to this question on stackoverflow and google, couldn't really find what I was looking for.
When I want to retrieve data from a page, like this one, with this code
public class ConsoleSearch {
public static void main(String[] args) throws IOException {
URL url = new URL("http://www.stackoverflow.com");
URLConnection cnt = url.openConnection();
BufferedReader br = new BufferedReader(new InputStreamReader
(cnt.getInputStream()));
String content;
while((content = br.readLine()) != null){
System.out.println(content);
}
br.close();
}
}
I obviously get the HTML tags, and everything else that comes with it.
I can easily filter HTML using HtmlCleaner
The challenging part and where I find my self stuck is when I want to retrieve specific text from all the retrieved data.
For example, if I wanted to only retrieve text "Nova Scotia" and/or "Europe"... how would I do that?
Pattern p = Pattern.compile("Nova Scotia");
Matcher m = p.matcher(content);
boolean b = m.matches();
Just look into the above regex package and it will be helpful to you.
I'm just starting out on my Networking Assignment and I'm already stuck.
Assignment asks me to check the user provided website for links and to determine if they are active or inactive by reading the header info.
So far after googling, I just have this code which retrieves the website. I don't get how to go over this information and look for HTML links.
Here's the code:
import java.net.*;
import java.io.*;
public class url_checker {
public static void main(String[] args) throws Exception {
URL yahoo = new URL("http://yahoo.com");
URLConnection yc = yahoo.openConnection();
BufferedReader in = new BufferedReader(
new InputStreamReader(
yc.getInputStream()));
String inputLine;
int count = 0;
while ((inputLine = in.readLine()) != null) {
System.out.println (inputLine);
}
in.close();
}
}
Please help.
Thanks!
You can also try jsoup html retriever and parser.
Document doc = Jsoup.parse(new URL("<url>"), 2000);
Elements resultLinks = doc.select("div.post-title > a");
for (Element link : resultLinks) {
String href = link.attr("href");
System.out.println("title: " + link.text());
System.out.println("href: " + href);
}
With this code you can list and analyze all elements inside a div with class "post-title" from the url .
You can try this:
URL url = new URL(link);
Reader reader= new InputStreamReader((InputStream) url.getContent());
new ParserDelegator().parse(reader, new Page(), true);
Then Create a class called Page
class Page extends HTMLEditorKit.ParserCallback {
public void handleStartTag(HTML.Tag t, MutableAttributeSet a, int pos) {
if (t == HTML.Tag.A) {
String link = null;
Enumeration<?> attributeNames = a.getAttributeNames();
if (attributeNames.nextElement().equals(HTML.Attribute.HREF))
link = a.getAttribute(HTML.Attribute.HREF).toString();
//save link some where
}
}
}
I don't get how to go over this information and look for HTML links
I cannot use any external library on my Assignment
You have a couple of options:
1) You can read the web page into an HTMLDocument. Then you can get an iterator from the Document to find all the HTML.Tag.A tags. Once you find the attrbute tags you can get the HTML.Attribute.HREF from the attribute set of the attribute tag.
2) You can extend HTMLEditor.ParserCallback and implement the handleStartTag(...) method. Then whenever you find an A tag, you can get the href attribute which will again contain the link. The basic code for invoking the parser callback is:
MyParserCallback parser = new MyParserCallback();
// simple test
String file = "<html><head><here>abc<div>def</div></here></head></html>";
StringReader reader = new StringReader(file);
// read a page from the internet
//URLConnection conn = new URL("http://yahoo.com").openConnection();
//Reader reader = new InputStreamReader(conn.getInputStream());
try
{
new ParserDelegator().parse(reader, parser, true);
}
catch (IOException e)
{
System.out.println(e);
}
HtmlParser is what you need here. A lot of things can be done with it.
You need to get the HTTP status code that the server returned with the response. A server will return a 404 if the page does not exist.
Check out this:
http://download.oracle.com/javase/1.4.2/docs/api/java/net/HttpURLConnection.html
most specifically the getResponseCode method.
I would parse the HTML with a tool like NekoHTML. It basically fixes malformed HTML for you and allows to access it like XML. Then you can process the link elements and try to follow them like you did for the original page.
You can check out some sample code that does this.