Java unbounded counted semaphore? - java

I need to provide a method that blocks until all outstanding work in a BlockingQueue has been processed.
I was thinking I could handle this with a counted semaphore which would start at 0 and decrement as items are added to the queue and increment as they are completed. finish() would just acquire the semaphore, release it again and leave.
I could perhaps call reducePermits(). Does this work if permit count is already < 0? It's protected, so I would need to extend the Semaphore class to make it work.
My second best idea is to check the contents of the queue in a loop and sleep 100ms or so between checks. It works but seems kludgey.
Does this make sense? Anybody have an easier / cleaner way to suggest?
TIA,
- Tim.
public MyClass {
public class MySemaphore extends Semaphore {
public void seize() {
reducePermits(1);
}
}
private MySemaphore allDone = new MySemaphore();
void startSomething() {
allDone.seize();
}
void finishSomething() {
allDone.release();
}
void finish() {
allDone.acquire();
allDone.release();
}
}

You could drain the queue by calling drainTo(collection), then invoke processing yourself on all items (possibly via Futures etc), then your final processing.

Related

Notify multiple threads periodically

I'm working on a project that uses primitive Java concurrent structures such as wait(), notify(), notifyAll(), Thread.run(), synhronized etc.
On my project, there are multiple threads (a extension of Thread class) who will get an object from a queue periodically. Thus, I use a Timer class which has an inner TimerTask class.
My problem is that, I could not get how to make other threads wake up periodically. My main class is not these threads or timer classes. Thus I call their run from another class. I could not figure out how to make these threads wait and notify for one time per 100 miliseconds. My timer class is:
public class Controller extends Timer{
int counter;
TimerTask task;
final Controller c = this;
public class PeriodicTime extends TimerTask {
#Override
public void run() {
if(counter > 0) {
//do some stuff to wake up threads
}
counter++;
}
}
Controller () {
super ();
this.task = new PeriodicTime();
counter = 0;
this.schedule(task, 300, 100);
}
}
And my thread class is:
public class Element extends Thread {
public void run() {
// do something to get an object from another class (a queue)
}
}
Now, i'm really confused how to make periodic releasing to the thread class. I even could not get whether to use wait()/notify() or not.
As I told before, i'll create multiple Element class. They will work synchronized. Then, what should I do?
Make a list of Objects that will represent mutexes, Each Element thread will get one mutex from the list, while the timer task gets the list.
TimerTask calls notify() on every mutex object when the time period expires. This wakes up the Element threads.
Element threads process data from queue and when they are done they each call wait() on their mutex object.
Now you need thread safety built into the queue since there are multiple consumers, but not the blocking logic since it is handled by the TimerTask.
Also, if I understood you correctly, you want Elements put something back to queue as they process the data. For that you can use an auxilary queue that you can drain into the first one after elements are done or you can just swap them (This is done by TimerTask and requires an atomic counter that will get incremented when Element wakes up and decremented when it goes to sleep). Alternatively, you can use a "stop" value that you can put into queue just before you wake up Elements, and make them work until they reach it. For N element threads you would need to put N stop values so all of them get the message.
How to use mutexes:
List<Object> mutexList;
//initialize the list with plain Objects. You just need them to be separate instances.
....
//When creating Element threads add one object from the list to each Element.
....
//in Element code
public class Element extends Thread {
//This is one element from the list
private Object mutex;
public void run() {
// do something to get an object from another class (a queue)
//....
synchronized(mutex){
mutex.wait();
}
}
}
// in timerTask code
public class PeriodicTime extends TimerTask {
List<Object> mutexList;
#Override
public void run() {
if(counter > 0) {
//do some stuff to wake up threads
for(Object mutex:mutexList){
mutex.notify();
}
}
counter++;
}
}

Using sleep() and interrupt() to reuse thread

In a swing application, I would like to re-utilize a spawned thread instead of creating a new one to serve requests. This is because the requests would be coming in short intervals of time and the cost of creating a new thread for every request could be high.
I am thinking of using the interrupt() and sleep() methods to do this as below and would like to know any potential performance problems with the code:
public class MyUtils {
private static TabSwitcherThread tabSwitcherThread = null;
public static void handleStateChange(){
if(tabSwitcherThread == null || !tabSwitcherThread.isAlive()){
tabSwitcherThread = new TabSwitcherThread();
tabSwitcherThread.start();
}
else
tabSwitcherThread.interrupt();
}
private static class TabSwitcherThread extends Thread{
#Override
public void run() {
try {
//Serve request code
//Processing complete, sleep till next request is received (will be interrupted)
Thread.sleep(60000);
} catch (InterruptedException e) {
//Interrupted execute request
run();
}
//No request received till sleep completed so let the thread die
}
}
}
Thanks
I wouldn't use sleep() and interrupt() - I'd use wait() and notify() if I absolutely had to.
However, is there any real need to do this instead of using a ThreadPoolExecutor which can handle the thread reuse for you? Or perhaps use a BlockingQueue in a producer/consumer fashion?
Java already provides enough higher-level building blocks for this that you shouldn't need to go down to this level yourself.
I think what you're looking for is a ThreadPool. Java 5 and above comes with ThreadPoolExecutor. I would suggest you use what is provided with Java instead of writing your own, so you can save yourself a lot of time and hairs.
Of course, if you absolutely has to do it the way you described (hey, sometimes business requirement make our life hard), then use wait() and notify() as Jon suggested. I would not use sleep() in this case because you have to specified timeout, and you never know when the next request will come in. Having a thread that keep waking up then go back to sleep seems a bit wasteful of CPU cycle for me.
Here is a nice tutorial about the ThreadPoolExecutor.
EDIT:
Here is some code example:
public class MyUtils {
private static UIUpdater worker = null;
private static ExecutorService exeSrv = Executors.newFixedThreadPool(1);
public static void handleStateChange(){
if(tabSwitcherThread == null || !tabSwitcherThread.isAlive()){
worker = new UIUpdater();
}
//this call does not block
exeSrv.submit(worker, new Object());
}
private static class UIUpdater implements Runnable{
#Override
public void run() {
//do server request and update ui.
}
}
}

What is the correct way to pass data to a running thread

In most cases when you create your thread you can prepare the data beforehand and pass it into the constructor or method.
However in cases like an open socket connection you will typically already have a thread created but wish to tell it to perform some action.
Basic idea:
C#
private Thread _MyThread = new Thread(MyMethod);
this._MyThread.Start(param);
Java
private Thread _MyThread = new Thread(new MyRunnableClass(param));
this._MyThread.start();
Now what?
So what is the correct way to pass data to a running thread in C# and Java?
One way to pass data to a running thread is by implementing Message Queues. The thread that wants to tell the listening thread to do something would add an item to the queue of the listening thread. The listening thread reads from this thread in a blocking fashion. Causing it to wait when there are no actions to perform. Whenever another thread puts a message in the queue it will fetch the message, depending on the item and it's content you can then do something with it.
This is some Java / pseudo code:
class Listener
{
private Queue queue;
public SendMessage(Message m)
{
// This will be executed in the calling thread.
// The locking will be done either in this function or in the Add below
// depending on your Queue implementation.
synchronize(this.queue)
{
this.queue.put(m);
}
}
public Loop()
{
// This function should be called from the Listener thread.
while(true)
{
Message m = this.queue.take();
doAction(m);
}
}
public doAction(Message m)
{
if (m is StopMessage)
{
...
}
}
}
And the caller:
class Caller
{
private Listener listener;
LetItStop()
{
listener.SendMessage(new StopMessage());
}
}
Of course, there are a lot of best practices when programming paralllel/concurrent code. For example, instead of while(true) you should at the least add a field like run :: Bool that you can set to false when you receive a StopMessage. Depending on the language in which you want to implement this you will have other primitives and behaviour to deal with.
In Java for example you might want to use the java.util.Concurrent package to keep things simple for you.
Java
You could basically have a LinkedList (a LIFO) and proceed (with something) like this (untested) :
class MyRunnable<T> implements Runnable {
private LinkedList<T> queue;
private boolean stopped;
public MyRunnable(LinkedList<T> queue) {
this.queue = queue;
this.stopped = false;
}
public void stopRunning() {
stopped = true;
synchronized (queue) {
queue.notifyAll();
}
}
public void run() {
T current;
while (!stopped) {
synchronized (queue) {
queue.wait();
}
if (queue.isEmpty()) {
try { Thread.sleep(1); } catch (InterruptedException e) {}
} else {
current = queue.removeFirst();
// do something with the data from the queue
}
Thread.yield();
}
}
}
As you keep a reference to the instance of the LinkedList given in argument, somewhere else, all you have to do is :
synchronized (queue) {
queue.addLast(T); // add your T element here. You could even handle some
// sort of priority queue by adding at a given index
queue.notifyAll();
}
Edit: Misread question,
C#
What I normally do is create a Global Static Class and then set the values there. That way you can access it from both threads. Not sure if this is the preferred method and there could be cases where locking occurs (correct me if I'm wrong) which should be handled.
I haven't tried it but It should work for for the threadpool/backgroundworker as well.
One way I can think of is through property files.
Well, it depends a lot on the work that the thread is supposed to do.
For example, you can have a thread waiting for a Event (e.g. ManualResetEvent) and a shared queue where you put work items (can be data structures to be processed, or more clever commands following a Command pattern). Somebody adds new work to the queue ad signals the event, so the trhread awakes, gets work from the queue and start performing its task.
You can encapsulate this code inside a custom queue, where any thread that calls the Deque methods stops until somebody calls Add(item).
On the other hand, maybe you want to rely on .NET ThreadPool class to issue tasks to execute by the threads on the pool.
Does this example help a bit?
You can use delegate pattern where child threads subscribes to an event and main thread raises an event, passing the parameters.
You could run your worker thread within a loop (if that makes sense for your requirement) and check a flag on each execution of the loop. The flag would be set by the other thread to signal the worker thread that some state had changed, it could also set a field at the same time to pass the new state.
Additionally, you could use monitor.wait and monitor.pulse to signal the state changes between the threads.
Obviously, the above would need synchronization.

Queue with notifications on isEmpty() changes

I have an BlockingQueue<Runnable>(taken from ScheduledThreadPoolExecutor) in producer-consumer environment. There is one thread adding tasks to the queue, and a thread pool executing them.
I need notifications on two events:
First item added to empty queue
Last item removed from queue
Notification = writing a message to database.
Is there any sensible way to implement that?
A simple and naïve approach would be to decorate your BlockingQueue with an implementation that simply checks the underlying queue and then posts a task to do the notification.
NotifyingQueue<T> extends ForwardingBlockingQueue<T> implements BlockingQueue<T> {
private final Notifier notifier; // injected not null
…
#Override public void put(T element) {
if (getDelegate().isEmpty()) {
notifier.notEmptyAnymore();
}
super.put(element);
}
#Override public T poll() {
final T result = super.poll();
if ((result != null) && getDelegate().isEmpty())
notifier.nowEmpty();
}
… etc
}
This approach though has a couple of problems. While the empty -> notEmpty is pretty straightforward – particularly for a single producer case, it would be easy for two consumers to run concurrently and both see the queue go from non-empty -> empty.
If though, all you want is to be notified that the queue became empty at some time, then this will be enough as long as your notifier is your state machine, tracking emptiness and non-emptiness and notifying when it changes from one to the other:
AtomicStateNotifier implements Notifier {
private final AtomicBoolean empty = new AtomicBoolean(true); // assume it starts empty
private final Notifier delegate; // injected not null
public void notEmptyAnymore() {
if (empty.get() && empty.compareAndSet(true, false))
delegate.notEmptyAnymore();
}
public void nowEmpty() {
if (!empty.get() && empty.compareAndSet(false, true))
delegate.nowEmpty();
}
}
This is now a thread-safe guard around an actual Notifier implementation that perhaps posts tasks to an Executor to asynchronously write the events to the database.
The design is most likely flawed but you can do it relatively simple:
You have a single thread adding, so you can check before adding. i.e. pool.getQueue().isEmpty() - w/ one producer, this is safe.
Last item removed cannot be guaranteed but you can override beforeExecute and check the queue again. Possibly w/ a small timeout after isEmpty() returns true. Probably the code below will be better off executed in afterExecute instead.
protected void beforeExecute(Thread t, Runnable r) {
if (getQueue().isEmpty()){
try{
Runnable r = getQueue().poll(200, TimeUnit.MILLISECONDS);
if (r!=null){
execute(r);
} else{
//last message - or on after execute by Setting a threadLocal and check it there
//alternatively you may need to do so ONLY in after execute, depending on your needs
}
}catch(InterruptedException _ie){
Thread.currentThread().interrupt();
}
}
}
sometime like that
I can explain why doing notifications w/ the queue itself won't work well: imagine you add a task to be executed by the pool, the task is scheduled immediately, the queue is empty again and you will need notification.

Observer Design Pattern

In the Observer Design Pattern, the subject notifies all observers by calling the update() operation of each observer. One way of doing this is
void notify() {
for (observer: observers) {
observer.update(this);
}
}
But the problem here is each observer is updated in a sequence and update operation for an observer might not be called till all the observers before it is updated. If there is an observer that has an infinite loop for update then all the observer after it will never be notified.
Question:
Is there a way to get around this problem?
If so what would be a good example?
The problem is the infinite loop, not the one-after-the-other notifications.
If you wanted things to update concurrently, you'd need to fire things off on different threads - in which case, each listener would need to synchronize with the others in order to access the object that fired the event.
Complaining about one infinite loop stopping other updates from happening is like complaining that taking a lock and then going into an infinite loop stops others from accessing the locked object - the problem is the infinite loop, not the lock manager.
Classic design patterns do not involve parallelism and threading. You'd have to spawn N threads for the N observers. Be careful though since their interaction to this will have to be done in a thread safe manner.
You could make use of the java.utils.concurrent.Executors.newFixedThreadPool(int nThreads) method, then call the invokeAll method (could make use of the one with the timout too to avoid the infinite loop).
You would change your loop to add a class that is Callable that takes the "observer" and the "this" and then call the update method in the "call" method.
Take a look at this package for more info.
This is a quick and dirty implementation of what I was talking about:
import java.util.ArrayList;
import java.util.List;
import java.util.concurrent.Callable;
import java.util.concurrent.CopyOnWriteArrayList;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.TimeUnit;
public class Main
{
private Main()
{
}
public static void main(final String[] argv)
{
final Watched watched;
final List<Watcher> watchers;
watched = new Watched();
watchers = makeWatchers(watched, 10);
watched.notifyWatchers(9);
}
private static List<Watcher> makeWatchers(final Watched watched,
final int count)
{
final List<Watcher> watchers;
watchers = new ArrayList<Watcher>(count);
for(int i = 0; i < count; i++)
{
final Watcher watcher;
watcher = new Watcher(i + 1);
watched.addWatcher(watcher);
watchers.add(watcher);
}
return (watchers);
}
}
class Watched
{
private final List<Watcher> watchers;
{
watchers = new ArrayList<Watcher>();
}
public void addWatcher(final Watcher watcher)
{
watchers.add(watcher);
}
public void notifyWatchers(final int seconds)
{
final List<Watcher> currentWatchers;
final List<WatcherCallable> callables;
final ExecutorService service;
currentWatchers = new CopyOnWriteArrayList<Watcher>(watchers);
callables = new ArrayList<WatcherCallable>(currentWatchers.size());
for(final Watcher watcher : currentWatchers)
{
final WatcherCallable callable;
callable = new WatcherCallable(watcher);
callables.add(callable);
}
service = Executors.newFixedThreadPool(callables.size());
try
{
final boolean value;
service.invokeAll(callables, seconds, TimeUnit.SECONDS);
value = service.awaitTermination(seconds, TimeUnit.SECONDS);
System.out.println("done: " + value);
}
catch (InterruptedException ex)
{
}
service.shutdown();
System.out.println("leaving");
}
private class WatcherCallable
implements Callable<Void>
{
private final Watcher watcher;
WatcherCallable(final Watcher w)
{
watcher = w;
}
public Void call()
{
watcher.update(Watched.this);
return (null);
}
}
}
class Watcher
{
private final int value;
Watcher(final int val)
{
value = val;
}
public void update(final Watched watched)
{
try
{
Thread.sleep(value * 1000);
}
catch (InterruptedException ex)
{
System.out.println(value + "interupted");
}
System.out.println(value + " done");
}
}
I'd be more concerned about the observer throwing an exception than about it looping indefinitely. Your current implementation would not notify the remaining observers in such an event.
1. Is there a way to get around this problem?
Yes, make sure the observer work fine and return in a timely fashion.
2. Can someone please explain it with an example.
Sure:
class ObserverImpl implements Observer {
public void update( Object state ) {
// remove the infinite loop.
//while( true ) {
// doSomething();
//}
// and use some kind of control:
int iterationControl = 100;
int currentIteration = 0;
while( curentIteration++ < iterationControl ) {
doSomething();
}
}
private void doSomething(){}
}
This one prevent from a given loop to go infinite ( if it makes sense, it should run at most 100 times )
Other mechanism is to start the new task in a second thread, but if it goes into an infinite loop it will eventually consume all the system memory:
class ObserverImpl implements Observer {
public void update( Object state ) {
new Thread( new Runnable(){
public void run() {
while( true ) {
doSomething();
}
}
}).start();
}
private void doSomething(){}
}
That will make the that observer instance to return immediately, but it will be only an illusion, what you have to actually do is to avoid the infinite loop.
Finally, if your observers work fine but you just want to notify them all sooner, you can take a look at this related question: Invoke a code after all mouse event listeners are executed..
All observers get notified, that's all the guarantee you get.
If you want to implement some fancy ordering, you can do that:
Connect just a single Observer;
have this primary Observer notify his friends in an order you define in code or by some other means.
That takes you away from the classic Observer pattern in that your listeners are hardwired, but if it's what you need... do it!
If you have an observer with an "infinite loop", it's no longer really the observer pattern.
You could fire a different thread to each observer, but the observers MUST be prohibited from changing the state on the observed object.
The simplest (and stupidest) method would simply be to take your example and make it threaded.
void notify() {
for (observer: observers) {
new Thread(){
public static void run() {
observer.update(this);
}
}.start();
}
}
(this was coded by hand, is untested and probably has a bug or five--and it's a bad idea anyway)
The problem with this is that it will make your machine chunky since it has to allocate a bunch of new threads at once.
So to fix the problem with all the treads starting at once, use a ThreadPoolExecutor because it will A) recycle threads, and B) can limit the max number of threads running.
This is not deterministic in your case of "Loop forever" since each forever loop will permanently eat one of the threads from your pool.
Your best bet is to not allow them to loop forever, or if they must, have them create their own thread.
If you have to support classes that can't change, but you can identify which will run quickly and which will run "Forever" (in computer terms I think that equates to more than a second or two) then you COULD use a loop like this:
void notify() {
for (observer: observers) {
if(willUpdateQuickly(observer))
observer.update(this);
else
new Thread(){
public static void run() {
observer.update(this);
}
}.start();
}
}
Hey, if it actually "Loops forever", will it consume a thread for every notification? It really sounds like you may have to spend some more time on your design.

Categories