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Character missing when use the InputStreamReader class in Java

I had written some codes to read from a text file char by char and then print it to the screen,but the result had made me feel confused,here it is:
this is the code that i had written
import java.io.*;
import java.nio.charset.StandardCharsets;
public class learnIO
{
public static void main(String[] args) throws IOException{
var in = new InputStreamReader(new FileInputStream("test1.txt"), StandardCharsets.UTF_8);
while(in.read() != -1){
System.out.println((char)in.read());
}
}
}
the content and encoding scheme of the file:
file test1.txt
test1.txt: ASCII text
cat test1.txt
hello, world!
the result is:
e
l
,
w
r
d
some char had missed，Why did this happen？

return type of read method of InputStreamReader is int that takes 4 bytes
and char type is 2 bytes so casting int to char you skip 2 bytes
refer to https://docs.oracle.com/javase/7/docs/api/java/io/InputStreamReader.html

You need to use InputStreamReader inside BufferedReader as from the official oracle documentation it says that
An InputStreamReader is a bridge from byte streams to character streams: It reads bytes and decodes them into characters using a specified charset. The charset that it uses may be specified by name or maybe given explicitly, or the platform's default charset may be accepted.
Each invocation of one of an InputStreamReader's read() methods may cause one or more bytes to be read from the underlying byte-input stream.
To enable the efficient conversion of bytes to characters, more bytes may be read ahead from the underlying stream than are necessary to satisfy the current read operation.
For top efficiency, consider wrapping an InputStreamReader within a BufferedReader. For example:
BufferedReader in
= new BufferedReader(new InputStreamReader(System.in));
So the solution to your problem can be solved using the following code
try {
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("hello.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
//Read File Line By Line
char c;
while ((c = (char) br.read()) != (char) -1) {
// Print the content on the console
String character = Character.toString(c);
System.out.println(character);
}
//Close the input stream
in.close();
} catch (Exception e) {//Catch exception if any
System.err.println("Error: " + e.getMessage());
}

Looping over InputStream truncating data

So this is a very simple problem with a simple solution that I'm just not seeing:
I'm trying to get a list of data through an InputStream, looping until I reach the end of the stream. On each iteration, I print the next line of text being passed through the InputStream. I have it working but for one small problem: I'm truncating the first character of each line.
Here's the code:
while (dataInputStream.read() >= 0) {
System.out.printf("%s\n", dataInputReader.readLine());
}
And the output:
classpath
project
est.txt
Now, I know what's going on here: the read() call in my while loop is taking the first char on each line, so when the line gets passed into the loop, that char is missing. The problem is, I can't figure out how to set up a loop to prevent that.
I think I just need a new set of eyes on this.

readLine for DataInputStream is deprecated. You may try wrapping it with a BufferedReader:
try
{
String line;
BufferedReader bufferedReader = new BufferedReader( new InputStreamReader( dataInputStream ) );
while( (line = bufferedReader.readLine()) != null )
{
System.out.printf("%s\n", line);
}
}
catch( IOException e )
{
System.err.println( "Error: " + e );
}
Also, I`m not sure, that it is a good idea to use available() due to this specification:
* <p>Note that this method provides such a weak guarantee that it is not very useful in
* practice.

Use one BufferedReader and InputStreamReader, here is one example:
InputStream in=...;
BufferedReader br = new BufferedReader(new InputStreamReader(in));
while (br.ready()) {
String line = br.readLine();
}

dataInputStream.read() reads the first character of the InputStream, the same as dataInputReader.readLine() reads the complete next line. Every read character or line is then gone. you can use the dataInputStream.available() to check if the InputStream has data available.
That should print the correct output:
while (dataInputStream.available()) {
System.out.printf("%s", dataInputReader.read());
}

String line;
while ((line = dataInputReader.readLine()) != null) {
System.out.println(line);
}

Search and Replace in a file using arraylist, Java

I wrote the below part of the code but I couldn't bind the arraylist with search and replace
so my csv file is as like below
1/1/1;7/6/1
1/1/2;7/7/1
I want to search the file 1.cfg for 1/1/1 and change it to 7/6/1 and 1/1/2 change to 7/7/1 and it goes so on.
Thank you all in advance
It's now only printing in a new file only the last line of the old File
import java.io.*;
import java.util.ArrayList;
import java.util.List;
public class ChangeConfiguration {
/**
* #param args
* #throws IOException
*/
public static void main(String[] args)
{
try{
// Open the file that is the first
// command line parameter
FileInputStream degistirilecek = new FileInputStream("c:/Config_Changer.csv");
FileInputStream config = new FileInputStream("c:/1.cfg");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(config);
DataInputStream degistir = new DataInputStream(degistirilecek);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
BufferedReader brdegis = new BufferedReader(new InputStreamReader(degistir));
List<Object> arrayLines = new ArrayList<Object>();
Object contents;
while ((contents = brdegis.readLine()) != null)
{
arrayLines.add(contents);
}
System.out.println(arrayLines + "\n");
String strLine;
//Read File Line By Line
while ((strLine = br.readLine()) != null) {
//Couldn't modify this part error is here :(
BufferedWriter out = new BufferedWriter(new FileWriter("c:/1_new.cfg"));
out.write(strLine);
out.close();
}
in.close();
degistir.close();
}catch (Exception e){//Catch exception if any
System.err.println("Error: " + e.getMessage());
}
}
}

You are opening the file for reading when you declare:
BufferedReader br = new BufferedReader(new InputStreamReader(in));
If you know the entire file will fit in memory, I recommend doing the following :
Open the file and read it's contents in memory into a giant string, then close the file.
Apply your replace in one shot to the giant string.
Open the file and write (e.g use a BufferedWriter) out the contents of the giant string, then close the file.
As a side note, your code as posted will not compile. The quality of the responses you receive are correlated with the quality of the question asked. Always include an SCCE with your question to increase the chance of getting a precise answer to your question.

can you elaborate the purpose of the program?
if it is a simple content replacement in a file.
then just read a line and store it in a string. then use string replace method for replacing a text in a string.
eg:
newStrog=oldString.replace(oldVlue,newValue);

Parsing in Java with C style?

I am new to java text parsing and I'm wondering what is the best way to parse a file when the format of each line is known.
I have a file that has the following format for each line:
Int;String,double;String,double;String,double;String,double;String,double
Note how the String,double act as a pair separated by a comma and each pair is separated by a semicolon.
A few examples:
1;art,0.1;computer,0.5;programming,0.6;java,0.7;unix,0.3
2;291,0.8;database,0.6;computer,0.2;java,0.9;undegraduate,0.7
3;coffee,0.5;colombia,0.2;java,0.1;export,0.4;import,0.5
I'm using the following code to read each line:
public static void main(String args[]) {
try {
// Open the file that is the first
// command line parameter
FileInputStream fstream = new FileInputStream("textfile.txt");
// Get the object of DataInputStream
DataInputStream in = new DataInputStream(fstream);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
// Read File Line By Line
while ((strLine = br.readLine()) != null) {
// Print the content on the console
System.out.println(strLine);
}
// Close the input stream
in.close();
} catch (Exception e) {// Catch exception if any
System.err.println("Error: " + e.getMessage());
}
}
Thanks in advance :)

You could use the Scanner class, for starters:
A simple text scanner which can parse primitive types and strings using regular expressions.

If you are truly trying to do "C" style parsing, where is the buffer which contains the characters being accumulated for the "next" field? Where is the check that sees if the field separator was read, and where is the code that flushes the current field into the correct data structure once the end of line / field separator is read?
A character by character read loop in Java looks like
int readChar = 0;
while ((readChar = in.read()) != -1) {
// do something with the new readChar.
}

You can provide a pattern and use the Scanner
String input = "fish1-1 fish2-2";
java.util.Scanner s = new java.util.Scanner(input);
s.findInLine("(\\d+)");
java.util.regex.MatchResult result = s.match();
for (int i=1; i<=result.groupCount(); i++)
System.out.println(result.group(i));
s.close();

Java: How to read a text file

I want to read a text file containing space separated values. Values are integers.
How can I read it and put it in an array list?
Here is an example of contents of the text file:
1 62 4 55 5 6 77
I want to have it in an arraylist as [1, 62, 4, 55, 5, 6, 77]. How can I do it in Java?

You can use Files#readAllLines() to get all lines of a text file into a List<String>.
for (String line : Files.readAllLines(Paths.get("/path/to/file.txt"))) {
// ...
}
Tutorial: Basic I/O > File I/O > Reading, Writing and Creating text files
You can use String#split() to split a String in parts based on a regular expression.
for (String part : line.split("\\s+")) {
// ...
}
Tutorial: Numbers and Strings > Strings > Manipulating Characters in a String
You can use Integer#valueOf() to convert a String into an Integer.
Integer i = Integer.valueOf(part);
Tutorial: Numbers and Strings > Strings > Converting between Numbers and Strings
You can use List#add() to add an element to a List.
numbers.add(i);
Tutorial: Interfaces > The List Interface
So, in a nutshell (assuming that the file doesn't have empty lines nor trailing/leading whitespace).
List<Integer> numbers = new ArrayList<>();
for (String line : Files.readAllLines(Paths.get("/path/to/file.txt"))) {
for (String part : line.split("\\s+")) {
Integer i = Integer.valueOf(part);
numbers.add(i);
}
}
If you happen to be at Java 8 already, then you can even use Stream API for this, starting with Files#lines().
List<Integer> numbers = Files.lines(Paths.get("/path/to/test.txt"))
.map(line -> line.split("\\s+")).flatMap(Arrays::stream)
.map(Integer::valueOf)
.collect(Collectors.toList());
Tutorial: Processing data with Java 8 streams

Java 1.5 introduced the Scanner class for handling input from file and streams.
It is used for getting integers from a file and would look something like this:
List<Integer> integers = new ArrayList<Integer>();
Scanner fileScanner = new Scanner(new File("c:\\file.txt"));
while (fileScanner.hasNextInt()){
integers.add(fileScanner.nextInt());
}
Check the API though. There are many more options for dealing with different types of input sources, differing delimiters, and differing data types.

This example code shows you how to read file in Java.
import java.io.*;
/**
* This example code shows you how to read file in Java
*
* IN MY CASE RAILWAY IS MY TEXT FILE WHICH I WANT TO DISPLAY YOU CHANGE WITH YOUR OWN
*/
public class ReadFileExample
{
public static void main(String[] args)
{
System.out.println("Reading File from Java code");
//Name of the file
String fileName="RAILWAY.txt";
try{
//Create object of FileReader
FileReader inputFile = new FileReader(fileName);
//Instantiate the BufferedReader Class
BufferedReader bufferReader = new BufferedReader(inputFile);
//Variable to hold the one line data
String line;
// Read file line by line and print on the console
while ((line = bufferReader.readLine()) != null) {
System.out.println(line);
}
//Close the buffer reader
bufferReader.close();
}catch(Exception e){
System.out.println("Error while reading file line by line:" + e.getMessage());
}
}
}

Look at this example, and try to do your own:
import java.io.*;
public class ReadFile {
public static void main(String[] args){
String string = "";
String file = "textFile.txt";
// Reading
try{
InputStream ips = new FileInputStream(file);
InputStreamReader ipsr = new InputStreamReader(ips);
BufferedReader br = new BufferedReader(ipsr);
String line;
while ((line = br.readLine()) != null){
System.out.println(line);
string += line + "\n";
}
br.close();
}
catch (Exception e){
System.out.println(e.toString());
}
// Writing
try {
FileWriter fw = new FileWriter (file);
BufferedWriter bw = new BufferedWriter (fw);
PrintWriter fileOut = new PrintWriter (bw);
fileOut.println (string+"\n test of read and write !!");
fileOut.close();
System.out.println("the file " + file + " is created!");
}
catch (Exception e){
System.out.println(e.toString());
}
}
}

Just for fun, here's what I'd probably do in a real project, where I'm already using all my favourite libraries (in this case Guava, formerly known as Google Collections).
String text = Files.toString(new File("textfile.txt"), Charsets.UTF_8);
List<Integer> list = Lists.newArrayList();
for (String s : text.split("\\s")) {
list.add(Integer.valueOf(s));
}
Benefit: Not much own code to maintain (contrast with e.g. this). Edit: Although it is worth noting that in this case tschaible's Scanner solution doesn't have any more code!
Drawback: you obviously may not want to add new library dependencies just for this. (Then again, you'd be silly not to make use of Guava in your projects. ;-)

Use Apache Commons (IO and Lang) for simple/common things like this.
Imports:
import org.apache.commons.io.FileUtils;
import org.apache.commons.lang3.ArrayUtils;
Code:
String contents = FileUtils.readFileToString(new File("path/to/your/file.txt"));
String[] array = ArrayUtils.toArray(contents.split(" "));
Done.

Using Java 7 to read files with NIO.2
Import these packages:
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
This is the process to read a file:
Path file = Paths.get("C:\\Java\\file.txt");
if(Files.exists(file) && Files.isReadable(file)) {
try {
// File reader
BufferedReader reader = Files.newBufferedReader(file, Charset.defaultCharset());
String line;
// read each line
while((line = reader.readLine()) != null) {
System.out.println(line);
// tokenize each number
StringTokenizer tokenizer = new StringTokenizer(line, " ");
while (tokenizer.hasMoreElements()) {
// parse each integer in file
int element = Integer.parseInt(tokenizer.nextToken());
}
}
reader.close();
} catch (Exception e) {
e.printStackTrace();
}
}
To read all lines of a file at once:
Path file = Paths.get("C:\\Java\\file.txt");
List<String> lines = Files.readAllLines(file, StandardCharsets.UTF_8);

All the answers so far given involve reading the file line by line, taking the line in as a String, and then processing the String.
There is no question that this is the easiest approach to understand, and if the file is fairly short (say, tens of thousands of lines), it'll also be acceptable in terms of efficiency. But if the file is long, it's a very inefficient way to do it, for two reasons:
Every character gets processed twice, once in constructing the String, and once in processing it.
The garbage collector will not be your friend if there are lots of lines in the file. You're constructing a new String for each line, and then throwing it away when you move to the next line. The garbage collector will eventually have to dispose of all these String objects that you don't want any more. Someone's got to clean up after you.
If you care about speed, you are much better off reading a block of data and then processing it byte by byte rather than line by line. Every time you come to the end of a number, you add it to the List you're building.
It will come out something like this:
private List<Integer> readIntegers(File file) throws IOException {
List<Integer> result = new ArrayList<>();
RandomAccessFile raf = new RandomAccessFile(file, "r");
byte buf[] = new byte[16 * 1024];
final FileChannel ch = raf.getChannel();
int fileLength = (int) ch.size();
final MappedByteBuffer mb = ch.map(FileChannel.MapMode.READ_ONLY, 0,
fileLength);
int acc = 0;
while (mb.hasRemaining()) {
int len = Math.min(mb.remaining(), buf.length);
mb.get(buf, 0, len);
for (int i = 0; i < len; i++)
if ((buf[i] >= 48) && (buf[i] <= 57))
acc = acc * 10 + buf[i] - 48;
else {
result.add(acc);
acc = 0;
}
}
ch.close();
raf.close();
return result;
}
The code above assumes that this is ASCII (though it could be easily tweaked for other encodings), and that anything that isn't a digit (in particular, a space or a newline) represents a boundary between digits. It also assumes that the file ends with a non-digit (in practice, that the last line ends with a newline), though, again, it could be tweaked to deal with the case where it doesn't.
It's much, much faster than any of the String-based approaches also given as answers to this question. There is a detailed investigation of a very similar issue in this question. You'll see there that there's the possibility of improving it still further if you want to go down the multi-threaded line.

read the file and then do whatever you want
java8
Files.lines(Paths.get("c://lines.txt")).collect(Collectors.toList());