I receive following error when I save the object using Hibernate
object references an unsaved transient instance - save the transient instance before flushing
You should include cascade="all" (if using xml) or cascade=CascadeType.ALL (if using annotations) on your collection mapping.
This happens because you have a collection in your entity, and that collection has one or more items which are not present in the database. By specifying the above options you tell hibernate to save them to the database when saving their parent.
I believe this might be just repeat answer, but just to clarify, I got this on a #OneToOne mapping as well as a #OneToMany. In both cases, it was the fact that the Child object I was adding to the Parent wasn't saved in the database yet. So when I added the Child to the Parent, then saved the Parent, Hibernate would toss the "object references an unsaved transient instance - save the transient instance before flushing" message when saving the Parent.
Adding in the cascade = {CascadeType.ALL} on the Parent's reference to the Child solved the problem in both cases. This saved the Child and the Parent.
Sorry for any repeat answers, just wanted to further clarify for folks.
#OneToOne(cascade = {CascadeType.ALL})
#JoinColumn(name = "performancelog_id")
public PerformanceLog getPerformanceLog() {
return performanceLog;
}
Introduction
When using JPA and Hibernate, an entity can be in one of the following 4 states:
New - A newly created object that hasn’t ever been associated with a Hibernate Session (a.k.a Persistence Context) and is not mapped to any database table row is considered to be in the New or Transient state.
To become persisted we need to either explicitly call the persist method or make use of the transitive persistence mechanism.
Persistent - A persistent entity has been associated with a database table row and it’s being managed by the currently running Persistence Context.
Any change made to such an entity is going to be detected and propagated to the database (during the Session flush-time).
Detached - Once the currently running Persistence Context is closed all the previously managed entities become detached. Successive changes will no longer be tracked and no automatic database synchronization is going to happen.
Removed - Although JPA demands that managed entities only are allowed to be removed, Hibernate can also delete detached entities (but only through a remove method call).
Entity state transitions
To move an entity from one state to the other, you can use the persist, remove or merge methods.
Fixing the problem
The issue you are describing in your question:
object references an unsaved transient instance - save the transient instance before flushing
is caused by associating an entity in the state of New to an entity that's in the state of Managed.
This can happen when you are associating a child entity to a one-to-many collection in the parent entity, and the collection does not cascade the entity state transitions.
So, you can fix this by adding cascade to the entity association that triggered this failure, as follows:
The #OneToOne association
#OneToOne(
mappedBy = "post",
orphanRemoval = true,
cascade = CascadeType.ALL)
private PostDetails details;
Notice the CascadeType.ALL value we added for the cascade attribute.
The #OneToMany association
#OneToMany(
mappedBy = "post",
orphanRemoval = true,
cascade = CascadeType.ALL)
private List<Comment> comments = new ArrayList<>();
Again, the CascadeType.ALL is suitable for the bidirectional #OneToMany associations.
Now, in order for the cascade to work properly in a bidirectional, you also need to make sure that the parent and child associations are in sync.
The #ManyToMany association
#ManyToMany(
mappedBy = "authors",
cascade = {
CascadeType.PERSIST,
CascadeType.MERGE
}
)
private List<Book> books = new ArrayList<>();
In a #ManyToMany association, you cannot use CascadeType.ALL or orphanRemoval as this will propagate the delete entity state transition from one parent to another parent entity.
Therefore, for #ManyToMany associations, you usually cascade the CascadeType.PERSIST or CascadeType.MERGE operations. Alternatively, you can expand that to DETACH or REFRESH.
This happens when saving an object when Hibernate thinks it needs to save an object that is associated with the one you are saving.
I had this problem and did not want to save changes to the referenced object so I wanted the cascade type to be NONE.
The trick is to ensure that the ID and VERSION in the referenced object is set so that Hibernate does not think that the referenced object is a new object that needs saving. This worked for me.
Look through all of the relationships in the class you are saving to work out the associated objects (and the associated objects of the associated objects) and ensure that the ID and VERSION is set in all objects of the object tree.
Or, if you want to use minimal "powers" (e.g. if you don't want a cascade delete) to achieve what you want, use
import org.hibernate.annotations.Cascade;
import org.hibernate.annotations.CascadeType;
...
#Cascade({CascadeType.SAVE_UPDATE})
private Set<Child> children;
In my case it was caused by not having CascadeType on the #ManyToOne side of the bidirectional relationship. To be more precise, I had CascadeType.ALL on #OneToMany side and did not have it on #ManyToOne. Adding CascadeType.ALL to #ManyToOne resolved the issue.
One-to-many side:
#OneToMany(cascade = CascadeType.ALL, mappedBy="globalConfig", orphanRemoval = true)
private Set<GlobalConfigScope>gcScopeSet;
Many-to-one side (caused the problem)
#ManyToOne
#JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;
Many-to-one (fixed by adding CascadeType.PERSIST)
#ManyToOne(cascade = CascadeType.PERSIST)
#JoinColumn(name="global_config_id")
private GlobalConfig globalConfig;
This occurred for me when persisting an entity in which the existing record in the database had a NULL value for the field annotated with #Version (for optimistic locking). Updating the NULL value to 0 in the database corrected this.
This isn't the only reason for the error. I encountered it just now for a typo error in my coding, which I believe, set a value of an entity which was already saved.
X x2 = new X();
x.setXid(memberid); // Error happened here - x was a previous global entity I created earlier
Y.setX(x2);
I spotted the error by finding exactly which variable caused the error (in this case String xid). I used a catch around the whole block of code that saved the entity and printed the traces.
{
code block that performed the operation
} catch (Exception e) {
e.printStackTrace(); // put a break-point here and inspect the 'e'
return ERROR;
}
Don't use Cascade.All until you really have to. Role and Permission have bidirectional manyToMany relation. Then the following code would work fine
Permission p = new Permission();
p.setName("help");
Permission p2 = new Permission();
p2.setName("self_info");
p = (Permission)crudRepository.save(p); // returned p has id filled in.
p2 = (Permission)crudRepository.save(p2); // so does p2.
Role role = new Role();
role.setAvailable(true);
role.setDescription("a test role");
role.setRole("admin");
List<Permission> pList = new ArrayList<Permission>();
pList.add(p);
pList.add(p2);
role.setPermissions(pList);
crudRepository.save(role);
while if the object is just a "new" one, then it would throw the same error.
beside all other good answers, this could happen if you use merge to persist an object and accidentally forget to use merged reference of the object in the parent class. consider the following example
merge(A);
B.setA(A);
persist(B);
In this case, you merge A but forget to use merged object of A. to solve the problem you must rewrite the code like this.
A=merge(A);//difference is here
B.setA(A);
persist(B);
If your collection is nullable just try: object.SetYouColection(null);
This issue happened to me when I created a new entity and an associated entity in a method marked as #Transactional, then performed a query before saving. Ex
#Transactional
public someService() {
Entity someEntity = new Entity();
AssocaiatedEntity associatedEntity = new AssocaitedEntity();
someEntity.setAssociatedEntity(associatedEntity);
associatedEntity.setEntity(someEntity);
// Performing any query was causing hibernate to attempt to persist the new entity. It would then throw an exception
someDao.getSomething();
entityDao.create(someEntity);
}
To fix, I performed the query before creating the new entity.
To add my 2 cents, I got this same issue when I m accidentally sending null as the ID. Below code depicts my scenario (and OP didn't mention any specific scenario).
Employee emp = new Employee();
emp.setDept(new Dept(deptId)); // --> when deptId PKID is null, same error will be thrown
// calls to other setters...
em.persist(emp);
Here I m setting the existing department id to a new employee instance without actually getting the department entity first, as I don't want to another select query to fire.
In some scenarios, deptId PKID is coming as null from calling method and I m getting the same error.
So, watch for null values for PK ID
It can also happen when you are having OneToMany relation and you try to add the child entity to the list in parent entity, then retrieve this list through parent entity (before saving this parent entity), without saving child entity itself, e.g.:
Child childEntity = new Child();
parentEntity.addChild(childEntity);
parentEntity.getChildren(); // I needed the retrieval for logging, but one may need it for other reasons.
parentRepository.save(parentEntity);
The error was thrown when I saved the parent entity. If I removed the retrieval in the previous row, then the error was not thrown, but of course that's not the solution.
The solution was saving the childEntity and adding that saved child entity to the parent entity, like this:
Child childEntity = new Child();
Child savedChildEntity = childRepository.save(childEntity);
parentEntity.addChild(savedChildEntity);
parentEntity.getChildren();
parentRepository.save(parentEntity);
If you're using Spring Data JPA then addition #Transactional annotation to your service implementation would solve the issue.
I also faced the same situation. By setting following annotation above the property made it solve the exception prompted.
The Exception I faced.
Exception in thread "main" java.lang.IllegalStateException: org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: com.model.Car_OneToMany
To overcome, the annotation I used.
#OneToMany(cascade = {CascadeType.ALL})
#Column(name = "ListOfCarsDrivenByDriver")
private List<Car_OneToMany> listOfCarsBeingDriven = new ArrayList<Car_OneToMany>();
What made Hibernate throw the exception:
This exception is thrown at your console because the child object I attach to the parent object is not present in the database at that moment.
By providing #OneToMany(cascade = {CascadeType.ALL}) , it tells Hibernate to save them to the database while saving the parent object.
i get this error when i use
getSession().save(object)
but it works with no problem when I use
getSession().saveOrUpdate(object)
For the sake of completeness: A
org.hibernate.TransientPropertyValueException
with message
object references an unsaved transient instance - save the transient instance before flushing
will also occur when you try to persist / merge an entity with a reference to another entity which happens to be detached.
One other possible reason: in my case, I was attempting to save the child before saving the parent, on a brand new entity.
The code was something like this in a User.java model:
this.lastName = lastName;
this.isAdmin = isAdmin;
this.accountStatus = "Active";
this.setNewPassword(password);
this.timeJoin = new Date();
create();
The setNewPassword() method creates a PasswordHistory record and adds it to the history collection in User. Since the create() statement hadn't been executed yet for the parent, it was trying to save to a collection of an entity that hadn't yet been created. All I had to do to fix it was to move the setNewPassword() call after the call to create().
this.lastName = lastName;
this.isAdmin = isAdmin;
this.accountStatus = "Active";
this.timeJoin = new Date();
create();
this.setNewPassword(password);
There is another possibility that can cause this error in hibernate. You may set an unsaved reference of your object A to an attached entity B and want to persist object C. Even in this case, you will get the aforementioned error.
There are so many possibilities of this error some other possibilities are also on add page or edit page. In my case I was trying to save a object AdvanceSalary. The problem is that in edit the AdvanceSalary employee.employee_id is null Because on edit I was not set the employee.employee_id. I have make a hidden field and set it. my code working absolutely fine.
#Entity(name = "ic_advance_salary")
#Table(name = "ic_advance_salary")
public class AdvanceSalary extends BaseDO{
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id")
private Integer id;
#ManyToOne(fetch = FetchType.EAGER)
#JoinColumn(name = "employee_id", nullable = false)
private Employee employee;
#Column(name = "employee_id", insertable=false, updatable=false)
#NotNull(message="Please enter employee Id")
private Long employee_id;
#Column(name = "advance_date")
#DateTimeFormat(pattern = "dd-MMM-yyyy")
#NotNull(message="Please enter advance date")
private Date advance_date;
#Column(name = "amount")
#NotNull(message="Please enter Paid Amount")
private Double amount;
#Column(name = "cheque_date")
#DateTimeFormat(pattern = "dd-MMM-yyyy")
private Date cheque_date;
#Column(name = "cheque_no")
private String cheque_no;
#Column(name = "remarks")
private String remarks;
public AdvanceSalary() {
}
public AdvanceSalary(Integer advance_salary_id) {
this.id = advance_salary_id;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public Employee getEmployee() {
return employee;
}
public void setEmployee(Employee employee) {
this.employee = employee;
}
public Long getEmployee_id() {
return employee_id;
}
public void setEmployee_id(Long employee_id) {
this.employee_id = employee_id;
}
}
I think is because you have try to persist an object that have a reference to another object that is not persist yet, and so it try in the "DB side" to put a reference to a row that not exists
Case 1:
I was getting this exception when I was trying to create a parent and saving that parent reference to its child and then some other DELETE/UPDATE query(JPQL). So I just flush() the newly created entity after creating parent and after creating child using same parent reference. It Worked for me.
Case 2:
Parent class
public class Reference implements Serializable {
#Id
#Column(precision=20, scale=0)
private BigInteger id;
#Temporal(TemporalType.TIMESTAMP)
private Date modifiedOn;
#OneToOne(mappedBy="reference")
private ReferenceAdditionalDetails refAddDetails;
.
.
.
}
Child Class:
public class ReferenceAdditionalDetails implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#OneToOne
#JoinColumn(name="reference",referencedColumnName="id")
private Reference reference;
private String preferedSector1;
private String preferedSector2;
.
.
}
In the above case where parent(Reference) and child(ReferenceAdditionalDetails) having OneToOne relationship and when you try to create Reference entity and then its child(ReferenceAdditionalDetails), it will give you the same exception. So to avoid the exception you have to set null for child class and then create the parent.(Sample Code)
.
.
reference.setRefAddDetails(null);
reference = referenceDao.create(reference);
entityManager.flush();
.
.
In my case , issue was completely different. I have two classes let's say c1 & c2. Between C1 & C2 dependency is OneToMany. Now if i am saving C1 in DB it was throwing above error.
Resolution of this problem was to get first C2's id from consumer request and find C2 via repository call.Afterwards save c2 into C1 object .Now if i am saving C1, it's working fine.
I was facing the same error for all PUT HTTP transactions, after introducing optimistic locking (#Version)
At the time of updating an entity it is mandatory to send id and version of that entity. If any of the entity fields are related to other entities then for that field also we should provide id and version values, without that the JPA try to persist that related entity first as a new entity
Example: we have two entities --> Vehicle(id,Car,version) ; Car(id, version, brand); to update/persist Vehicle entity make sure the Car field in vehicle entity has id and version fields provided
Simple way of solving this issue is save the both entity.
first save the child entity and then save the parent entity.
Because parent entity is depend on child entity for the foreign key value.
Below simple exam of one to one relationship
insert into Department (name, numOfemp, Depno) values (?, ?, ?)
Hibernate: insert into Employee (SSN, dep_Depno, firstName, lastName, middleName, empno) values (?, ?, ?, ?, ?, ?)
Session session=sf.openSession();
session.beginTransaction();
session.save(dep);
session.save(emp);
One possible cause of the error is the inexistence of the setting of the value of the parent entity ; for example for a department-employees relationship you have to write this in order to fix the error :
Department dept = (Department)session.load(Department.class, dept_code); // dept_code is from the jsp form which you get in the controller with #RequestParam String department
employee.setDepartment(dept);
I faced this exception when I did not persist parent object but I was saving the child. To resolve the issue, with in the same session I persisted both the child and parent objects and used CascadeType.ALL on the parent.
My problem was related to #BeforeEach of JUnit. And even if I saved the related entities (in my case #ManyToOne), I got the same error.
The problem is somehow related to the sequence that I have in my parent.
If I assign the value to that attribute, the problem is solved.
Ex.
If I have the entity Question that can have some categories (one or more) and entity Question has a sequence:
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "feedbackSeq")
#Id
private Long id;
I have to assign the value question.setId(1L);
Just make Constructor of your mapping in your base class.
Like if you want One-To-One relation in Entity A, Entity B.
if your are taking A as base class, then A must have a Constructor have B as a argument.
How do get the object I want, without all of the child associations.
I have my class Site:
#Entity
#Table(name = "Sites")
public class Site {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "Id_Site", unique = true, nullable = false)
private long Id_Site;
private String ...;
private boolean ...;
private long ...;
private Date ...;
private Date ...;
private String ...;
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private Set<Sequence> sequences = new HashSet<>();
#ManyToOne
private ... ...;
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private Set<...> ... = new HashSet<>();
#ManyToOne
private ... ...;
public constructor...
public set..
public get..
}
I only need a Site object, without the Sequence Associations.
In my Sequence Table, I have:
#Entity
#Table(name = "Sequences")
public class Sequence {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "Id_Sequence", unique = true, nullable = false)
private long Id_Sequence;
private Date ....;
private Date ....;
private String ....;
private String ....;
private String ....;
private int ....;
private int ....;
private double ....;
private double ....;
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private Set<TraceSequence> traceSequences = new HashSet<>();
#ManyToOne(cascade = CascadeType.ALL)
private Site site;
public constructor...
public set..
public get..
}
When I use FetchType.Lazy, and call my method:
#Override
public Site findSiteByName(String Name_Site) {
List<Site> sites = entityManager.createQuery("SELECT s FROM Site s").getResultList();
for (Site item : sites) {
if (item.getNom_Site().equals(Name_Site)) {
return item;
}
}
return null;
}
I get this error:
failed to lazily initialize a collection of role: xxx.xxx.xxx.xxx.xxx.site.Site.sequences, could not initialize proxy - no Session
When I use FetchType.EAGER, I get not only a Site object, but I also get all sequence objects, and all objects of other sequence associations. (I know it is the normal response.)
Could someone who knows why this attempt at lazy initialization doesn't work, please, tell me how to resolve this problem.
These lazy errors happens when the jpa tries to get the data after the session is closed.
But using eager will influence all the queries that include that entity.
Try to use a join fetch in the query instead of the eager.
Somewhere in your code you are calling Site.GetSequences(), maybe iterating in the view or in another part of your code. It doesn't look like the piece of code you gave are generating the exception.
I you try to use a collection that is not loaded to your entity, the code throws the exception you mentioned.
To solve this, identify where you are using the sequences and load them before you use by changing the fetch to EAGER or using the JOIN FETCH in your query.
Returning a hibernate managed entity (or a collection of hibernate managed entities) will most likely cause these sort of problems unless you are super cautious on what is being returned and what was populated by hibernate when session was available.
I would say create a DTO (or a collection of DTO) and populate its fields the way you like. There are many Entity to DTO conversion framework; my fav is ModelMapper.
I also tend to agree with other suggestions to play with FetchType but since DTOs are populated by us we know what we populated as opposed to entity-relationships which are populated by hibernate based on annotations.
If you need something in the DTO you simply ask the entity and since session would be available at that point of time you could populate any field that you think you would need on the UI.
I don't want to hijack this topic towards DTO and Entity but that's how I would do it.
This may be helpful too Avoid Jackson serialization on non fetched lazy objects
Error happen becouse you try execute getSequences(), but becouse of is lazy and session is alredy closed hibernate rais the error.
To avoid this error read read sequencese inside query method, "inside" session, like this:
public Site findSiteByName(String Name_Site) {
List sites = entityManager.createQuery("SELECT s FROM Sites").getResultList();
for (Site item : sites) {
if (item.getNom_Site().equals(Name_Site)) {
item.getSites();
return item;
}
}
return null;
}
This is a lazy loading, you read collenction just when you need it!
As stated by other SE members above, you are getting this error because session is already closed.
If you want to load a particular object then you can use Hibernate.initialize method. it will execute one additional query to fetch the data of related entity.
Therefore, it is as per need basis and will not be executed all times as compared to Eager loading
I'm working on a project that aims to solve common JPA problems when mapping entities to DTOs using ModelMapper. This issue has already been solved on the project. Project link: JPA Model Mapper
On this scenario I believe that we'd want to simply get null for all lazy load entities. For this question specifically, this could be done by using de JPA Model Mapper to map an entity to DTO.
I've already answered the same issue on this question: How to solve the LazyInitializationException when using JPA and Hibernate
I am trying to use the #SQLDelete annotation of Hibernate to make soft deletion. It works well when the DB schema is static, i.e: passing it in the SQL.
Unfortunately, it seems the SQL is passed as is to EntityPersisters (cf EntityClass's method CustomSQL createCustomSQL(AnnotationInstance customSqlAnnotation) so I can't find a way to pass the schema name dynamically like in Native SQL queries using {h-schema}
Did anyone find a good workaround for this issue (I am using Hibernate 4.3.5)?
Edit: Unless there is a real solution, I ended up modifying the code source of org.hibernate.persister.entity.AbstractEntityPersister by replacing the schema placeholder when setting the custom SQL queries in method doLateInit.
Edit2: I have created an issue for this behaviour in Hibernate JIRA. I will create a pull request later today and I wish the Hibernate Team will accept it
Soft deletes using Hibernate annotations.
As linked author stated below:
I am currently working on a Seam application that has a need for soft deletes in the database. To the right you can see a snippet of my database diagram which contains a CUSTOMER and APP_USER table. This is just a straight forward one to many relationship but the important thing to note though is the “DELETED” field in each table. This is the field that will be used to track the soft delete. If the field contains a ‘1’ the record has been deleted and if it contains a ‘0’ the record hasn’t been deleted.
Before ORMs like Hibernate I would have had to track and set this flag myself using SQL. It wouldn’t be super hard to do but who wants to write a bunch of boilerplate code just to keep track of whether or not a record has been deleted. This is where Hibernate and annotations comes to the rescue.
Below are the 2 Entity classes that were generated by Hibernate using seamgen. I have omitted parts of the code for clarity.
Customer.java
//Package name...
//Imports...
#Entity
#Table(name = "CUSTOMER")
//Override the default Hibernation delete and set the deleted flag rather than deleting the record from the db.
#SQLDelete(sql="UPDATE customer SET deleted = '1' WHERE id = ?")
//Filter added to retrieve only records that have not been soft deleted.
#Where(clause="deleted <> '1'")
public class Customer implements java.io.Serializable {
private long id;
private Billing billing;
private String name;
private String address;
private String zipCode;
private String city;
private String state;
private String notes;
private char enabled;
private char deleted;
private Set appUsers = new HashSet(0);
// Constructors...
// Getters and Setters...
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "customer")
// Filter added to retrieve only records that have not been soft deleted.
#Where(clause = "deleted <> '1'")
public Set getAppUsers() {
return this.appUsers;
}
public void setAppUsers(Set appUsers) {
this.appUsers = appUsers;
}
}
AppUser.java
//Package name...
//Imports...
#Entity
#Table(name = "APP_USER")
//Override the default Hibernation delete and set the deleted flag rather than deleting the record from the db.
#SQLDelete(sql="UPDATE app_user SET deleted = '1' WHERE id = ?")
//Filter added to retrieve only records that have not been soft deleted.
#Where(clause="deleted <> '1'")
public class AppUser implements java.io.Serializable {
private long id;
private Customer customer;
private AppRole appRole;
private char enabled;
private String username;
private String appPassword;
private Date expirationDate;
private String firstName;
private String lastName;
private String email;
private String phone;
private String fax;
private char deleted;
private Set persons = new HashSet(0);
// Constructors...
// Getters and Setters...
}
The following 2 steps is all that I had to do to implement the soft delete.
Added the #SQLDelete annotation which overrides the default
Hibernate delete for that entity.
Added the #Where annotation to filter the queries and only return
records that haven’t been soft deleted. Notice also that in the
CUSTOMER class I added an #Where to the appUsers collection. This is
needed to fetch only the appUsers for that Customer that have not
been soft deleted.
Viola! Now anytime you delete those entities it will set the “DELETED” field to ‘1’ and when you query those entities it will only return records that contain a ‘0’ in the “DELETED” field.
Hard to believe but that is all there is to implementing soft deletes using Hibernate annotations.
Note:
also note that instead of using the #Where(clause="deleted ‘1’") statements you can use hibernate filter (http://docs.jboss.org/hibernate/stable/annotations/reference/en/html_single/#entity-hibspec-filters) to globally filter-out all ‘deleted’ entities. I found that defining 2 entity managers (‘normal’ one that filter deleted items, and one that doesn’t, for the rare cases…) is usually quite convenient.
Using EntityPersister
You can create a DeleteEventListener such as:
public class SoftDeleteEventListener extends DefaultDeleteEventListener {
/**
*
*/
private static final long serialVersionUID = 1L;
#Override
public void onDelete(DeleteEvent event, Set arg1) throws HibernateException {
Object o = event.getObject();
if (o instanceof SoftDeletable) {
((SoftDeletable)o).setStatusId(1);
EntityPersister persister = event.getSession().getEntityPersister( event.getEntityName(), o);
EntityEntry entityEntry = event.getSession().getPersistenceContext().getEntry(o);
cascadeBeforeDelete(event.getSession(), persister, o, entityEntry, arg1);
cascadeAfterDelete(event.getSession(), persister, o, arg1);
} else {
super.onDelete(event, arg1);
}
}
}
hook it into your persistence.xml like this
<property name = "hibernate.ejb.event.delete" value = "org.something.SoftDeleteEventListener"/>
Also, don't forget to update your cascades in your annotations.
Resource Link:
Hibernate: Overwrite sql-delete with inheritace
Custom SQL for CRUD operations
Custom SQL for create, update and delete
Use like this
#SQLDelete(sql = "UPDATE {h-schema}LEAVE SET STATUS = 'DELETED' WHERE id = ?", check = ResultCheckStyle.COUNT)
I think there are 2 way
First is to add:
app.datasource.schema=<schema_name>
to your application.properties.
The second is to use the schema in annotation to your table model
My application uses a lot of OneToMany and OneToOne references between domain level value-objects, most of them are entities, either being a super class or a subclass of something.I would like to provide my application a consistent(yet easy) way to save those instances and the actual method save() is as such
#Transactional
public void save(Post post){
try{
JPA.em().persist(post);
}catch (EntityExistsException eee){
JPA.em().merge(post);
}catch(ConstraintViolationException cve){
JPA.em().refresh(post);
}
}
The current problem is how to properly instantiate those object and which strategy choose in the cascadeType, i would like to save nested object when saving an object with references with other entities, it works now but only for the first time, after that i get a Unique index or primary key violation given that SQL insert into Utente (passwd, DTYPE, username) values (?, 'Redattore', ?) [23505-168].Clearly my JPA provider (hibernate 3.6.9) fails to not update an existing row, instead it tries to insert a new entry in the DB.Here are some classes i am using:
#Entity
#Table
public class Post extends Domanda {
#Column(nullable = false)
private String nome;
#OneToMany(cascade = CascadeType.ALL)
private List<Commento> commenti;
#OneToMany(cascade = CascadeType.ALL)
private List<Risorsa> risorse;
#OneToOne(cascade = CascadeType.ALL)
private NodoApprendimento nodo;
#Column
private int visibilità;
#Column
private boolean isDraft;
Post is referenced by a few classes among which i there is:
#Entity
public abstract class Partecipante extends Utente{
#OneToMany(cascade = CascadeType.ALL,
fetch = FetchType.LAZY)
private Set<Post> contributi;
Then i would like to know the proper way to initialize and persisteORupdate those referenced object in the database, thanks in advance.
This isn't a provider problem, but a usage issue. When you call persist, JPA does not require providers to execute an insert immediately - they are usually delayed to flush or commit time. So you will not get an EntityExistsException in most cases. Either way, the transaction state should be marked for rollback - you should not be relying on persist to determine if merge should be called. Either call em.find, or just call em.merge on your entity and allow the JPA provider to determine if it should do an insert or an update for you.