I want to save the image on disk such as c:/images which is captured by webcam using java ..and again I want to display that image on JForm as a label...
is this possible using java and netbeans
I'm new in java
you can save image
private static void save(String fileName, String ext) {
File file = new File(fileName + "." + ext);
BufferedImage image = toBufferedImage(file);
try {
ImageIO.write(image, ext, file); // ignore returned boolean
} catch(IOException e) {
System.out.println("Write error for " + file.getPath() +
": " + e.getMessage());
}
}
and read image from disk and show into label as
File file = new File("image.gif");
image = ImageIO.read(file);
JFrame frame = new JFrame();
JLabel label = new JLabel(new ImageIcon(image));
frame.getContentPane().add(label, BorderLayout.CENTER);
frame.pack();
frame.setVisible(true);
You can use BufferedImage to load an image from your hard disk :
BufferedImage img = null;
try {
img = ImageIO.read(new File("strawberry.jpg"));
} catch (IOException e) {
}
Try this link for further information. Reading/Loading Images in Java
And this one for saving the image. Writing/Saving an Image
try {
// retrieve image
BufferedImage bi = getMyImage();
File outputfile = new File("saved.png");
ImageIO.write(bi, "png", outputfile);
} catch (IOException e) {
...
}
Pure Java, not third party library needed:
byte[] image = /*your image*/
String filePath = /*destination file path*/
File file = new File(filePath);
try (FileOutputStream fosFor = new FileOutputStream(file)) {
fosFor.write(image);
}
//Start Photo Upload with No//
if (simpleLoanDto.getPic() != null && simpleLoanDto.getAdharNo() != null) {
String ServerDirPath = globalVeriables.getAPath() + "\\";
File ServerDir = new File(ServerDirPath);
if (!ServerDir.exists()) {
ServerDir.mkdirs();
}
// Giving File operation permission for LINUX//
IOperation.setFileFolderPermission(ServerDirPath);
MultipartFile originalPic = simpleLoanDto.getPic();
byte[] ImageInByte = originalPic.getBytes();
FileOutputStream fosFor = new FileOutputStream(
new File(ServerDirPath + "\\" + simpleLoanDto.getAdharNo() + "_"+simpleLoanDto.getApplicantName()+"_.jpg"));
fosFor.write(ImageInByte);
fosFor.close();
}
//End Photo Upload with No//
Related
I am trying to get a screenshot of my desktop and save it in specific folder, for this purpose, I wrote following method:
class Test(){
public static String screenshot(String outDir){
try {
Robot robot = new Robot();
String format = ".png";
String fileName = String.valueOf(System.currentTimeMillis()) + format;
Rectangle screenRect = new Rectangle(Toolkit.getDefaultToolkit().getScreenSize());
BufferedImage screenFullImage = robot.createScreenCapture(screenRect);
ImageIO.write(screenFullImage, format, new File(outDir + fileName));
System.out.println("Success");
return outDir + fileName;
} catch (AWTException | IOException e) {
e.printStackTrace();
}
return null;
}
}
I was planning to use the code like so:
Test.screenshot("C:\\temp\\");
So the magic is it does not write the screenshot file in the specific folder, but if I remove file extension and explicitly hardcode the name of the file it writes the result.
However, this code works:
public static String screenshot(){
try {
Robot robot = new Robot();
String format = "jpg";
String fileName = "XXX." + format;
Rectangle screenRect = new Rectangle(Toolkit.getDefaultToolkit().getScreenSize());
BufferedImage screenFullImage = robot.createScreenCapture(screenRect);
ImageIO.write(screenFullImage, format, new File("C:\\temp\\" + fileName));
System.out.println("Success");
return outDir + fileName;
} catch (AWTException | IOException e) {
e.printStackTrace();
}
return null;
}
What am I doing wrong here?
I have seen the javadoc. The problem is about the formatName, as doc say: formatName - a String containg the informal name of the format. => means that your format should only contain name, not include the dot (.). So that's why your hardcode run because your hardcode using the correct formatName
Here is the snippet where i save the image with a .png extension:
WritableImage img = rectCanvas.snapshot(new SnapshotParameters(), null);
JFileChooser chooser = new JFileChooser();
chooser.setCurrentDirectory(new File(System.getProperty("user.home")));
int result = chooser.showSaveDialog(null);
if (result == JFileChooser.APPROVE_OPTION) {
try {
File fileToSave = chooser.getSelectedFile();
ImageIO.write(SwingFXUtils.fromFXImage(img, null), "png", fileToSave);
} catch (IOException ex) {
Logger.getLogger(GuiClass.class.getName()).log(Level.SEVERE, null, ex);
}
}
I want .png to be my default file extension. However when i want to save an image to file and open the save dialog i have to enter the file name in the following format: filename.png. How can i get rid of the .png part and make it default?
What are you setting as the value of "fileToSave"? If that isn't .png, it shouldn't be a png extension.
See the following from oracle's documentation:
try {
// retrieve image
BufferedImage bi = getMyImage();
File outputfile = new File("saved.png");
ImageIO.write(bi, "png", outputfile);
} catch (IOException e) {
...
}
I'm trying to crop an image received from a form upload. Before I crop it I save it, then I retrieve it again as a BufferedImage (because I don't know how to turn a part into a buffered Image). I then crop this image, but when I try to save it again I get a java.io.FileNotFoundException (access denied)
The first image gets saved correctly, I get the exception when I try to pull it back.
Is it possible to turn my part into a buffered image and then save it? Instead of doing double work. or else is there some fix to my below code.
String savePath = "path";
File fileSaveDir = new File(savePath);
if (!fileSaveDir.exists()) {
fileSaveDir.mkdir();
}
for (Part part : request.getParts()) {
//functionality to ormit non images
String fileName = extractFileName(part);
part.write(savePath + "/" + fileName);
String imagePath = savePath + "/" + fileName;
BufferedImage img = null;
try {
img = ImageIO.read(new File(imagePath));
img = img.getSubimage(0, 0, 55, 55);
ImageIO.write(img, "jpg", fileSaveDir);
} catch (IOException e) {
System.out.println(e);
}
}
ImageIO.write((RenderedImage im, String formatName, File output));
Parameters:
im a RenderedImage to be written.
formatName a String containg the informal name of the format.
output a File to be written to.
As per documentation output file parameter is the file object where it would be image written where you have passed the parent directory file object.
I am using Apache Poi to read images from docx.
Here is my code:
enter code here
public Image ReadImg(int imageid) throws IOException {
XWPFDocument doc = new XWPFDocument(new FileInputStream("import.docx"));
BufferedImage jpg = null;
List<XWPFPictureData> pic = doc.getAllPictures();
XWPFPictureData pict = pic.get(imageid);
String extract = pict.suggestFileExtension();
byte[] data = pict.getData();
//try to read image data using javax.imageio.* (JDK 1.4+)
jpg = ImageIO.read(new ByteArrayInputStream(data));
return jpg;
}
It reads images properly but not in order wise.
For example, if document contains
image1.jpeg
image2.jpeg
image3.jpeg
image4.jpeg
image5.jpeg
It reads
image4
image3
image1
image5
image2
Could you please help me to resolve it?
I want to read the images order wise.
Thanks,
Sithik
public static void extractImages(XWPFDocument docx) {
try {
List<XWPFPictureData> piclist = docx.getAllPictures();
// traverse through the list and write each image to a file
Iterator<XWPFPictureData> iterator = piclist.iterator();
int i = 0;
while (iterator.hasNext()) {
XWPFPictureData pic = iterator.next();
byte[] bytepic = pic.getData();
BufferedImage imag = ImageIO.read(new ByteArrayInputStream(bytepic));
ImageIO.write(imag, "jpg", new File("D:/imagefromword/" + pic.getFileName()));
i++;
}
} catch (Exception e) {
System.exit(-1);
}
}
I have created a graphical image with the following sample code.
BufferedImage bi = new BufferedImage(50,50,BufferedImage.TYPE_BYTE_BINARY);
Graphics2D g2d = bi.createGraphics();
// Draw graphics.
g2d.dispose();
// BufferedImage now has my image I want.
At this point I have BufferedImage which I want to convert into an IMG Data URI. Is this possible? For example..
<IMG SRC="data:image/png;base64,[BufferedImage data here]"/>
Not tested, but something like this ought to do it:
ByteArrayOutputStream out = new ByteArrayOutputStream();
ImageIO.write(bi, "PNG", out);
byte[] bytes = out.toByteArray();
String base64bytes = Base64.encode(bytes);
String src = "data:image/png;base64," + base64bytes;
There are lots of different base64 codec implementations for Java. I've had good results with MigBase64.
You could use this solution which doesn't use any external libraries. Short and clean! It uses a Java 6 library (DatatypeConverter). Worked for me!
ByteArrayOutputStream output = new ByteArrayOutputStream();
ImageIO.write(image, "png", output);
DatatypeConverter.printBase64Binary(output.toByteArray());
I use Webdriver, get captcha, like this below:
// formatName -> png
// pathname -> C:/Users/n/Desktop/tmp/test.png
public static String getScreenshot(WebDriver driver, String formatName, String pathname) {
try {
WebElement element = driver.findElement(By.xpath("//*[#id=\"imageCodeDisplayId\"]"));
File screenshot = element.getScreenshotAs(OutputType.FILE);
// base64 data
String base64Str = ImageUtil.getScreenshot(screenshot.toString());
return base64Str;
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
public static String getScreenshot(String imgFile) {
InputStream in;
byte[] data = null;
try {
in = new FileInputStream(imgFile);
data = new byte[in.available()];
in.read(data);
in.close();
} catch (IOException e) {
e.printStackTrace();
}
String base64Str = new String(Base64.getEncoder().encode(data));
if (StringUtils.isAnyBlank(base64Str)) {
return null;
}
if (!base64Str.startsWith("data:image/")) {
base64Str = "data:image/jpeg;base64," + base64Str;
}
return base64Str;
}