Can anybody explain me why below code is working on private member variable?
public class Person implements Comparable<Person> {
private String firstName;
public Person(String firstName) {
this.firstName = firstName;
}
#Override
public int compareTo(Person o) {
return firstName.compareToIgnoreCase(o.firstName); // why does it work? } }
}
}
EDIT Why o.firstName is getting compile ? where firstName is private variable.
The access modifiers control access per class rather than per instance. So, methods of class T can access all members (even private) of other class T's instances.
The Access Control from JLS 7 link for the curious. It says, "Note that accessibility is a static property that can be determined at compile time; it depends only on types and declaration modifiers."
Because private variables are visible within the class that declares them, and o is a Person.
The method "compareTo" is implemented in the "Person" class which naturally has access to it's private members. You override the method from the interface Comparable. So you are working with the same class in both cases.
Because objects of the same class can access each others private properties. This does not entirely break the separation of concerns because the code for such accesses must be in the same class so the class is still responsible for the property.
You are using the private members inside the class, that declares them, which is perfectly ok.
The declaring class always has access to all of its members, regardless of which instance of the class the members belong to.
Thus the following code compiles and works.
public class AClass {
private String name;
public AClass(String n) {name = n;}
public void mock(AClass other) {
System.out.pritln(this.name + ": \"" + other.name + " smells.\"");
}
public static void main(String[] args) {
AClass a = new AClass("Bully");
AClass b = new AClass("Nemesis");
a.mock(b);
}
}
Related
It's been a rather long time since I've messed around with Java Abstraction and/or Interfaces, but I'm coming back to it now for a project and something is getting on my nerves. Below is a snippet of my code.
public class A {
private static String name = "None";
private static String description = "No description";
public A() {}
public A(User user) {
user.setData(this);
}
public static String getName() {
return name;
}
public static String getDescription() {
return description;
}
}
public class B extends A {
private static String name = "B";
private static String description = "This is B";
public B() {}
public B(User user) {
super(user);
}
}
public class User {
private A a;
public void setData(A a) {
this.a = a;
}
public A getData() {
return a;
}
}
When I use B.getName() I expect it to return "B" but it's instead returning "None".
Now I'm obviously doing something wrong, and searching around didn't help a bit. I'm fairly positive that this is possible someway, unless I'm getting confused with another language.
Could someone please point me in the right direction? Thanks.
You called the getName method on the class B. B doesn't have a static method called getName, so it looks for it in the superclass, A, which does.
Maybe you expect B's version of name to override A's? Variables don't get overridden. A is accessing the static variable name defined on A, that the method was originally called on B doesn't affect that.
Inheritance and static methods don't work well together. OO concepts like polymorphism rely on runtime dispatching, the word static should imply the opposite of that. With polymorphism the program works at a high level of abstraction, referring to the objects by a super type and letting the subclasses work out the details. With static methods you have to refer to the specific subclass you want the method called on, so you don't have that level of abstraction.
Welcome back to Java again.
You are using static variable in class A and B. These variables are associated with class instead of the objects.
If you change your method to get name from the User, it will work as you are expecting.
You need to override the method getName():
public class B extends A {
private static String name = "B";
private static String description = "This is B";
public B() {}
#Override
public static String getName() {
return name;
}
public B(User user) {
super(user);
}
}
The problem you are facing lies in the definition of the methods getName and getDescription: They are defined in class A as static members. This means that even when calling B.getName() the actual call is A.getName() and there the static member variable value of name is set to None.
When thinking about inheritance you have be careful what you declare as static. This has nothing to do with Interfaces or abstract classes.
public class A {
protected String name = "None";
protected String description = "No description";
public A() {}
public A(User user) {
user.setData(this);
}
public String getName() {
return name;
}
public String getDescription() {
return description;
}
}
public class B extends A {
public B() {
name = "B";
description = "This is B"
}
public B(User user) {
super(user);
}
}
public class User {
private A a;
public void setData(A a) {
this.a = a;
}
public A getData() {
return a;
}
}
With the protected keyword you can access the fields from the extending class.
See also:
http://www.javatpoint.com/static-keyword-in-java
https://docs.oracle.com/javase/tutorial/java/javaOO/classvars.html
A couple of things to note in your class :
name and description are static variables in both A and B
getName is a static method in A
static variables are bound to the class and static methods can't be overridden
This is the expected behavior since getName() method of class A has access to member variable of its own class that is "name" of class A. It is NOT because of name is static even if you make it non-static and you access it as shown in below code snippet it would return "None". Remember that only methods get overridden not member variables. So "name" of class B is not overriding "name" of class "A".
B b = new B();
System.out.println(b.getName()); --> "None" ("name" is non-static)
----------------------------------------------
System.out.println(B.getName()); --> "None" ("name" is static)
Also, if you want to get "B" as output , override getName() method of class A in class B and make method and variable non-static.
This question already has answers here:
When should I use "this" in a class?
(17 answers)
Closed 7 years ago.
I'm trying to get an understanding of what the the java keyword this actually does.
I've been reading Sun's documentation but I'm still fuzzy on what this actually does.
The this keyword is a reference to the current object.
class Foo
{
private int bar;
public Foo(int bar)
{
// the "this" keyword allows you to specify that
// you mean "this type" and reference the members
// of this type - in this instance it is allowing
// you to disambiguate between the private member
// "bar" and the parameter "bar" passed into the
// constructor
this.bar = bar;
}
}
Another way to think about it is that the this keyword is like a personal pronoun that you use to reference yourself. Other languages have different words for the same concept. VB uses Me and the Python convention (as Python does not use a keyword, simply an implicit parameter to each method) is to use self.
If you were to reference objects that are intrinsically yours you would say something like this:
My arm or my leg
Think of this as just a way for a type to say "my". So a psuedocode representation would look like this:
class Foo
{
private int bar;
public Foo(int bar)
{
my.bar = bar;
}
}
The keyword this can mean different things in different contexts, that's probably the source of your confusion.
It can be used as a object reference which refers to the instance the current method was called on: return this;
It can be used as a object reference which refers to the instance the current constructor is creating, e.g. to access hidden fields:
MyClass(String name)
{
this.name = name;
}
It can be used to invoke a different constructor of a a class from within a constructor:
MyClass()
{
this("default name");
}
It can be used to access enclosing instances from within a nested class:
public class MyClass
{
String name;
public class MyClass
{
String name;
public String getOuterName()
{
return MyClass.this.name;
}
}
}
"this" is a reference to the current object.
See details here
The keyword this is a reference to the current object. It's best explained with the following piece of code:
public class MyClass {
public void testingThis()
{
// You can access the stuff below by
// using this (although this is not mandatory)
System.out.println(this.myInt);
System.out.println(this.myStringMethod());
// Will print out:
// 100
// Hello World
}
int myInt = 100;
string myStringMethod()
{
return "Hello World";
}
}
It's not used a lot unless you have code standard at your place telling you to use the this keyword. There is one common use for it, and that's if you follow a code convention where you have parameter names that are the same as your class attributes:
public class ProperExample {
private int numberOfExamples;
public ProperExample(int numberOfExamples)
{
this.numberOfExamples = numberOfExamples;
}
}
One proper use of the this keyword is to chain constructors (making constructing object consistent throughout constructors):
public class Square {
public Square()
{
this(0, 0);
}
public Square(int x_and_y)
{
this(x_and_y, x_and_y);
}
public Square(int x, int y)
{
// finally do something with x and y
}
}
This keyword works the same way in e.g. C#.
An even better use of this
public class Blah implements Foo {
public Foo getFoo() {
return this;
}
}
It allows you to specifically "this" object in the current context. Another example:
public class Blah {
public void process(Foo foo) {
foo.setBar(this);
}
}
How else could you do these operations.
"this" keyword refers to current object due to which the method is under execution. It is also used to avoid ambiguity between local variable passed as a argument in a method and instance variable whenever instance variable and local variable has a same name.
Example ::
public class ThisDemo1
{
public static void main(String[] args)
{
A a1=new A(4,5);
}
}
class A
{
int num1;
int num2;
A(int num1)
{
this.num1=num1; //here "this" refers to instance variable num1.
//"this" avoids ambigutiy between local variable "num1" & instance variable "num1"
System.out.println("num1 :: "+(this.num1));
}
A(int num, int num2)
{
this(num); //here "this" calls 1 argument constructor within the same class.
this.num2=num2;
System.out.println("num2 :: "+(this.num2));
//Above line prints value of the instance variable num2.
}
}
The keyword 'this' refers to the current object's context. In many cases (as Andrew points out), you'll use an explicit this to make it clear that you're referring to the current object.
Also, from 'this and super':
*There are other uses for this. Sometimes, when you are writing an instance method, you need to pass the object that contains the method to a subroutine, as an actual parameter. In that case, you can use this as the actual parameter. For example, if you wanted to print out a string representation of the object, you could say "System.out.println(this);". Or you could assign the value of this to another variable in an assignment statement.
In fact, you can do anything with this that you could do with any other variable, except change its value.*
That site also refers to the related concept of 'super', which may prove to be helpful in understanding how these work with inheritance.
It's a reference of actual instance of a class inside a method of the same class.
coding
public class A{
int attr=10;
public int calc(){
return this.getA()+10;
}
/**
*get and set
**/
}//end class A
In calc() body, the software runs a method inside the object allocated currently.
How it's possible that the behaviour of the object can see itself? With the this keyword, exactly.
Really, the this keyword not requires a obligatory use (as super) because the JVM knows where call a method in the memory area, but in my opinion this make the code more readeable.
It can be also a way to access information on the current context.
For example:
public class OuterClass
{
public static void main(String[] args)
{
OuterClass oc = new OuterClass();
}
OuterClass()
{
InnerClass ic = new InnerClass(this);
}
class InnerClass
{
InnerClass(OuterClass oc)
{
System.out.println("Enclosing class: " + oc + " / " + oc.getClass());
System.out.println("This class: " + this + " / " + this.getClass());
System.out.println("Parent of this class: " + this.getClass().getEnclosingClass());
System.out.println("Other way to parent: " + OuterClass.this);
}
}
}
Think of it in terms of english, "this object" is the object you currently have.
WindowMaker foo = new WindowMaker(this);
For example, you are currently inside a class that extends from the JFrame and you want to pass a reference to the WindowMaker object for the JFrame so it can interact with the JFrame. You can pass a reference to the JFrame, by passing its reference to the object which is called "this".
Every object can access a reference to itself with keyword this (sometimes called the this
reference).
First lets take a look on code
public class Employee {
private int empId;
private String name;
public int getEmpId() {
return this.empId;
}
public String getName() {
return this.name;
}
public void setEmpId(int empId) {
this.empId = empId;
}
public void setName(String name) {
this.name = name;
}
}
In the above method getName() return instance variable name.
Now lets take another look of similar code is
public class Employee {
private int empId;
private String name;
public int getEmpId() {
return this.empId;
}
public String getName() {
String name="Yasir Shabbir";
return name;
}
public void setEmpId(int empId) {
this.empId = empId;
}
public void setName(String name) {
this.name = name;
}
public static void main(String []args){
Employee e=new Employee();
e.setName("Programmer of UOS");
System.out.println(e.getName());
}
}
Output
Yasir Shabbir
this operator always work with instance variable(Belong to Object)
not any class variable(Belong to Class)
this always refer to class non static attribute not any other parameter or local variable.
this always use in non static method
this operator cannot work on static variable(Class variable)
**NOTE:**It’s often a logic error when a method contains a parameter or local variable that has the
same name as a field of the class. In this case, use reference this if you wish to access the
field of the class—otherwise, the method parameter or local variable will be referenced.
What 'this' does is very simply. It holds the reference of current
object.
This keyword holds the reference of instance of current class
This keyword can not be used inside static function or static blocks
This keyword can be used to access shadowed variable of instance
This keyword can be used to pass current object as parameter in function calls
This keyword can be used to create constructor chain
Source: http://javaandme.com/core-java/this-word
Check this example:
public interface IConstants {
public enum Levels {
LOW("30 points"), MEDIUM("50 points")
};
public enum Cars {
PORSCHE("250 km/h"), FORD("180 km/h")
}
}
I'd like to have an interface like this, because I want to access my enums this way:
String level = IConstants.Levels.MEDIUM;
String car = IConstants.Cars.PORSCHE;
The compiler shows this message:
constructor IConstants."enum name" is undefined.
Solved this way :
public class Constants {
public static class Levels {
public static String LOW = "30 points";
public static String MEDIUM = "50 points";
};
//... other classes
}
-useful for me in (my case) to have a "tree" in my constants, every constant starting by keyword Constants then subcategory and then value -> Constants.Levels.LOW.
//critize it if it's very bad practise, i agree all comments
-another maybe good thing that there will be all constants in one class
Like Boris the spider told you in comment declaring constants in interfaces is an anti pattern. However your problem comes from the fact that you are passing a String to any instance of your enum but you are not declaring a constructor for this
public enum Levels {
LOW("30 points"), MEDIUM("50 points")
private final String pts;
private Levels(String pts) {
this.pts = pts;
}
public String getPoints() {
return pts;
}
};
This should work.
You are missing constructors in both enums. A private variable and the constructor is required, e.g.
public enum Levels {
private String name;
public Levels(String name) {
this.name = name;
}
}
Also it is considered bad practice to put inner classes, constants in interfaces.
To add to other answers, it will still not compile after an enum constructor is added, because you are assigning a String variable to a Levels or Cars. Please use:
String level = IConstants.Levels.MEDIUM.methodToAccessString();
String car = IConstants.Cars.PORSCHE.methodToAccessString();
Replacing methodToAccessString() with whatever you call it, of course.
I have a question about putting a Java enum in the interface.
To make it clearer, please see the following code:
public interface Thing{
public enum Number{
one(1), two(2), three(3);
private int value;
private Number(int value) {
this.value = value;
}
public int getValue(){
return value;
}
}
public Number getNumber();
public void method2();
...
}
I know that an interface consists of methods with empty bodies. However, the enum I used here needs a constructor and a method to get an associated value. In this example, the proposed interface will not just consist of methods with empty bodies. Is this implementation allowed?
I am not sure if I should put the enum class inside the interface or the class that implements this interface.
If I put the enum in the class that implements this interface, then the method public Number getNumber() needs to return the type of enum, which would force me to import the enum in the interface.
It's perfectly legal to have an enum declared inside an interface. In your situation the interface is just used as a namespace for the enum and nothing more. The interface is used normally wherever you use it.
Example for the Above Things are listed below :
public interface Currency {
enum CurrencyType {
RUPEE,
DOLLAR,
POUND
}
public void setCurrencyType(Currency.CurrencyType currencyVal);
}
public class Test {
Currency.CurrencyType currencyTypeVal = null;
private void doStuff() {
setCurrencyType(Currency.CurrencyType.RUPEE);
System.out.println("displaying: " + getCurrencyType().toString());
}
public Currency.CurrencyType getCurrencyType() {
return currencyTypeVal;
}
public void setCurrencyType(Currency.CurrencyType currencyTypeValue) {
currencyTypeVal = currencyTypeValue;
}
public static void main(String[] args) {
Test test = new Test();
test.doStuff();
}
}
In short, yes, this is okay.
The interface does not contain any method bodies; instead, it contains what you refer to as "empty bodies" and more commonly known as method signatures.
It does not matter that the enum is inside the interface.
Yes, it is legal. In a "real" situation Number would implement Thing, and Thing would probably have one or more empty methods.
I can understand what inner class is and how to write program. My question is in what situation do programmers really need inner class?
Sometimes there is some functionality which is best represented as an object, but which is only meaningful within the context of another object, which does not necessarily need to be exposed to the outside world, and which can benefit from having access to the parent classes data (so as to not violate encapsulation).
The best example that I can think of is putting a Node class inside of a LinkedList. Nodes are only meaningful to the LinkedList, so they only exist within one. No one outside of the LinkedList cares about nodes or should have access to them.
An inner class allows us to remove that logic and place it into its own class. So from an object-oriented point of view, we've taken functionality out of where it doesn't belong and have put it into its own class.
Please go through this link....
http://www.javaworld.com/javaworld/javaqa/2000-03/02-qa-innerclass.html
Also as you know in Java exists nested classes, which is static inner clasess.
From previous posts becomes clear when we need to use an inner class but I think you also interested in the question "Why we need nested classes (static inner class)".
The answer is simply, there is the same purpose as for the inner class except few things.
1) The nested class (static inner) is required when we whant to exclude some logic that concerns another object but this logic might be used in outworld.
The simpliest examples is a builders or editors of some object. For example we have class Foo
which may have a lot of optional fields, to construct such object we may decide to introduce a builder class which will do this work.
public class Foo {
private int param1;
private int param2;
private int param3;
private Foo(FooBuilder builder) {
this.param1 = builder.param1;
this.param2 = builder.param2;
this.param3 = builder.param3;
}
public int getParam1() {
return param1;
}
public void setParam1(int param1) {
this.param1 = param1;
}
public int getParam2() {
return param2;
}
public void setParam2(int param2) {
this.param2 = param2;
}
public int getParam3() {
return param3;
}
public void setParam3(int param3) {
this.param3 = param3;
}
public static class FooBuilder {
private int param1;
private int param2;
private int param3;
public FooBuilder() {
}
public FooBuilder withParameter1(int param1) {
this.param1 = param1;
return this;
}
public FooBuilder withParameter2(int param2) {
this.param2 = param2;
return this;
}
public FooBuilder withParameter3(int param3) {
this.param3 = param3;
return this;
}
public Foo build() {
return new Foo(this);
}
}
}
This example illustrates at leas one reason why we need such classes
2) The second difference between inner and static inner classes is that the first one always has pointer to the parent class. Actully compiler creates synthetic field member for the non static inner class of the type of it's parent, exectly of this reason we can access private members of the parent class. The static inner clasess doesn't has such generated field member. For instance we has just simple parent class with declared non static inner class:
public class Foo {
public class FooBuilder {
}
}
but in fact if take into account the byte code it looks like:
public class Foo {
public class FooBuilder {
private Foo generatedNameHere;
}
}
if you want you can figure out this throught generated byte code.
One of the use of inner class is :
Inner class helps in multiple-inheritance. Inner class allows you to inherit from more than one non-interface.
//first case; can implement if two classes are interface
interface A { }
interface B { }
class X implements A, B { }
//second case; you can extend only one class. This case inner class can help to inherit other class as well
class D { }
abstract class E { }
class Z extends D {
void method() {
return new E() { }; //Anonymous inner class
}
}
When you want to specify a class that has sence only in context with the bounded one.
For example you write a MathOperations class that can execute four operations. So the operations can be represented as inner enum MathOps.
When the inner class is not used anywhere except the inbounded one.
You use anonymous inner classes to specify only the operation, for exmple if you want to sort a collection, you specify a Comparable class just for one method compare.
Collections.sort(employments, new Comparator<Employment>() {
#Override
public int compare(Employment o1, Employment o2) {
return o1.getStartDate().before(o2.getStartDate()) ? 1 : -1 ;
}
});
With inner classes you can access private members of the enclosing class.
They are useful for interface implementations that are only used by the enclosing class (event handlers in a application).
They are useful for providing fine grained access and creation control over an interface implementation that is retrieved externally (maybe something like an Iterator implementation).