Difference between static declaration and non static declaration - java

Static variables: Are the class variables and they are not created separately for each object of the class.
Instance variables: Are also the class variables but are created for each object separately.
The above definitions are just for references.
Please explain why i am getting error in this class declaration.I know it is just because i have not of initialised x.
class non_static{
public static void main(String args[])
{
int x;
System.out.println(x);
}
}
But this class declaration is totally fine.
class static_example{
static int x;
public static void main(String args[])
{
System.out.println(x);
}
}
And output of this program is 0.
Please do explain me why static member is initialized with the default value while local variables are not.

It has nothing to do with static declaration vs instance declaration. It is local declaration, which does not have a default and will cause an error when it is used uninitialized.
public class Example {
private static int stattic;
private int instancee;
public void someMethod() {
System.out.println("I am static and 0: " + stattic);
System.out.println("I am not static and 0: " + instancee);
int locall;
System.out.println("I am causing an error because I have not been initialized: " + locall);
}
}

If you want to know the background on why Java specifies it like that, it has to do wih the limits of static code analysis. Memory allocated from the stack (and this is where the local vars are) can be confirmed positively by the compiler to be initialized before use. Not so with heap-allocated storage (static vars, instance vars). This is why the JLS requires the implementations to always zero out any heap storage before exposing a pointer to it.

Local variables must always be initialized with a value. For non-local variables (i.e. instance or static variables) the default is defined as the corresponding type's null values (null, zero or false).

In java the Instance Variables (ie class variables) are initialized to their default values.
But the Local Variables (ie Method variables) CAN NOT be used without initializing...
class static_example{
static int x;
public static void main(String args[])
{
System.out.println(x);
}
}
In the above example of yours, x is declared at Class scope... So it is already initialized to its default value 0, so its NOT GIVING any error..

Related

If we don't reference to a non initialized variable will it still allocate memory from it's default value?

My question is in regards of memory with non initialized variables.
Lets say we reference to a field like this:
class JustAClass {
static int a;
public static void main(String[] args){
System.out.println(a);
}
}
Now in the above example the variable a will be by default assigned a value of 0(which will acquire memory in RAM) and 0 will be printed in the console.
However what if we didn't make a reference to the a variable and simply ran the program like this:
class JustAClass {
static int a;
public static void main(String[] args){
}
}
Would a still acquire memory in this case?
Yes as it might be accessed in non trivial way which static compiler cannot detect - like using reflection.

Can static assignments be re-ordered by the compiler in Java 8+? [duplicate]

This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Java static class initialization
Why is the string variable updated in the initialization block and not the integer(even though the block is written first)
class NewClass
{
static
{
System.out.println(NewClass.string+" "+NewClass.integer);
}
final static String string="static";
final static Integer integer=1;
public static void main(String [] args)//throws Exception
{
}
}
My output is
static null
P.S:Also noticed that string variable initialization happens before the block only when i insert the final modifier. why is that?why not for integer as well?I have declared it as final static too
From section 12.4.2 of the JLS, snipped appropriately:
The procedure for initializing C is then as follows:
Then, initialize the final class variables and fields of interfaces whose values are compile-time constant expressions (§8.3.2.1, §9.3.1, §13.4.9, §15.28).
Next, execute either the class variable initializers and static initializers of the class, or the field initializers of the interface, in textual order, as though they were a single block.
So for non-compile-time-constants, it's not a case of "all variables" and then "all static initializers" or vice versa - it's all of them together, in textual order. So if you had:
static int x = method("x");
static {
System.out.println("init 1");
}
static int y = method("y");
static {
System.out.println("init 2");
}
static int method(String name) {
System.out.println(name);
return 0;
}
Then the output would be:
x
init 1
y
init 2
Even making x or y final wouldn't affect this here, as they still wouldn't be compile-time constants.
P.S:Also noticed that string variable initialization happens before the block only when i insert the final modifier.
At that point, it's a compile-time constant, and any uses of it basically inlined. Additionally, the variable value is assigned before the rest of the initializers, as above.
Section 15.28 of the JLS defines compile-time constants - it includes all primitive values and String, but not the wrapper types such as Integer.
Here is a short and straight forward answer to you question....
static Variable :
static Variables are executed when the JVM loads the Class, and the Class gets loaded when either its been instantiated or its static method is being called.
static Block or static Initializer Block :
static static Initializer Block gets Initialized before the Class gets instantiated or before its static method is called, and Even before its static variable is used.
///////// Edited Part /////////
class NewClass {
final static String string = "static";
final static Integer integer = 1;
static {
System.out.println(NewClas.string + " " + NewClas.integer);
}
public static void main(String [] args) { // throws Exception
new NewClas();
}
}
The above will print static 1.
The reason is that the JVM will do the optimization process known as Constant folding, doing an pre-calculation of the constant variables.
Moreover in your case the result was static null cause Constant folding is applied to Primitive type and not Wrapper Object, in your case its Integer...
They are initialized in the given order (fields and static blocks), that's why printed value is null, nothing was assigned to static fields that are defined after the static block.

Can i initialize static variable after the initialization?

What is the problem with below code?
class test {
static int a;
a=10;
}
If I'm writing like this (as above), I'm getting a compile time error.
class test {
static int a=10;
a=4;
}
For the second one, I'm not getting any error.
Neither of your examples should compile.
a=10;
is a statement, which is not valid directly inside a class declaration. You can only put the following directly inside a class:
Member declarations (member/static variable declarations (like static int a;), methods, nested classes and interfaces);
Static and instance initializers;
Constructors.
You need to put a statement inside a block, for example a static initializer:
static int a;
static {
a = 10;
}
which is equivalent to:
static int a = 10;
You need to use a static block of statement to do an assignment on an other line (outside a method)
class test {
static int a;
static { a=10; }
}
a=4; must be done in a valid scope
either a method or a constructor...
this line is valid instead
static int a=10;
because java allows youto declare and initialize in one statement!
If you want to initialize a after defining it as a null int, you can only do that in a function, because it is static.
must be initialized inside static block or init block or in constructor.
you can only initialized your member variable after declaration inside a function or block because it is static you should use static block
What you are currently doing is declaring a variable in a class decleration, which is not valid. Looking at this neither of your examples should give you any good result.
In a class declaration you can however initialize a variable:
static int a;
Then if you want to work with it you would have to create a method first (if you are not aware of this I would strongly advise to watch some youtube tutorials or read books about this topic) :
public void foo(int a){
a = 6; //Here you can play with your variables and change them
}
In class declararions you can: declarations methods, initializers and constructors. (there is a bit more you can do, however I would have a look at these points before diving in too deep).
Furthermore it seems that you are not aware what a static variable or a static method does, I think the following posts will help you with that:
difference between 'static int' and 'int' in java
What are static method and variables?
I hope I could help and have fun learning Java
Because for static memory allocated at the time of class loading
so we need do like this
class test {static int a =10;
public static void main(String args[]) { a=12 output(test.a (or) a);}}
A Java class body is should contain declarations and declaration with an initializer, not the standalone statements. Let's unwrap your requirement of initializing a static variable.
Static variables should not be initialized inside methods as these variables belong to the class. But they can be initiated inside the constructor.
public class Example {
static String name;
static int age;
Example() {
name = "James";
age = 34;
}
public static void main(String args[]) {
new Example();
System.out.println(Example.name);
System.out.println(Example.age);
}
}
Now the output will be :
James
34
If new Example(); is not called then the output will be :
null
0
This is because the static variables are initialized with an object creation and for each Example object name and age will be overwritten with the same value. But at least one object needs to be created for name and age to be initialized.
But if you declare a static and final instance variable, we cannot initialize that in the constructor, it is mandatory to initialize static and final variables at the class level. We can initialize while declaring the variable or using a static initialization block. This runs before the main() method in Java. Hence when the main() method is loaded this static variable will be initialized and the compiler will not throw any errors.
static final int name = "STRING";
static final int age;
static {
age = 10;
}
Putting all these things together,
A static variable can be initialized,
When declaring.
Inside a constructor.
Inside a static block.
A static final variable can be initialized,
When declaring.
Inside a static block.
A final variable can be initialized,
When declaring.
Inside a constructor (If you have more than one constructor in your class then it must be initialized in all of them).

Why can't i use static variable in java constructor?

The compiler says illegal modifier for parameter i.
Please tell me what I'm doing wrong. Why can't I use a static variable in a Java constructor?
class Student5{
Student5() {
static int i = 0;
System.out.println(i++);
}
public static void main(String args[]){
Student5 c1 = new Student5();
Student5 c2 = new Student5();
Student5 c3 = new Student5();
}
}
Because of where you are declaring i:
Student5(){
static int i=0;
System.out.println(i++);
}
the compiler treats it as a local variable in the constructor:
Local variables cannot be declared as static. For details on what modifiers are allowed for local variables, see Section 14.4 of the Java Language Specification.
Judging from what the code appears to be trying to do, you probably want i to be a static member of Student5, not a local variable in the constructor:
class Student5{
private static int i = 0;
Student5(){
System.out.println(i++);
}
. . .
}
If you want to declare static variable then declare it outside of the constructor, at class level like this -
public class Student5{
private static int i;
}
You declaration of static occurred at your constructor which is a local variable and local variable can not be static. And that's why you are getting - illegal modifier for parameter i. And finally for initializing static variable you may use a static initialization block (though it's not mandatory) -
public class Student5{
private static int i;
static {
i = 5;
}
}
This is how the language was designed.. What if you wanted to have another int field named i in the constructor?, then which i should be considered?. Also, static fields are initialized before the constructor is called i.e, during class initilization phase. A constructor gets called only when a new instance is created.
Imagine what would happen (supposed to happen) if you load and initialize a class but not create a new instance.
Static variables are variables that can be referenced without having an instance of the class. By defining one instead of a constructor, which is called when you create an instance of the class, you are contradicting yourself. Either make it defined without having an instance (outside of the constructor and static) or make it specific to an instance (inside the constructor and not static).
You might want to rethink what you are actually trying to do and if you really need a static variable.

In Java why would one initialize an int variable with 0 when it will be assigned 0 only by default when declared?

What purpose does it serve?
Just read an example in a book where the author has done so.
int numOfGuesses=0;
The automatic assignment to zero only applies to members, not to local variables. If it is a local variable and the = 0 is omitted then that variable has no value, not even zero. Attempting to use the value before it is assigned will result in a compile error. For example this code attempts to use an uninitialized local variable:
public class Program
{
public static void main(String[] args)
{
int numOfGuesses; // local variable
System.out.println(numOfGuesses);
}
}
and produces this compile error:
Program.java:6: variable numOfGuesses might not have been initialized
System.out.println(numOfGuesses);
Whereas this code using a member works and outputs zero:
public class Program
{
int numOfGuesses; // member variable
public void run()
{
System.out.println(numOfGuesses);
}
public static void main(String[] args)
{
new Program().run();
}
}
For members I tend to assign to zero explicilty if my code uses the fact that the initial zalue is zero, and omit the assignment if my code doesn't use the initial value (for example if it the value is assigned in the constructor or elsewhere). The result is the same either way, so it's just a style issue.
It's more explicit; some people like. Note that this applies only to fields -- local variables need to be initialized; there are no defaults.
The Java compilation and runtime differ.
When running the program, all classes are loaded with class loaders and they do the following:
This is done when class is used for the first time. Their execute order is defined by their order in the code.
run static blocks
static{
//do something here
}
initialize static variables
public static int number;
This will be initialized to zero 0;
The next group of initializations done is when creating an object.Their execute order is defined by their order in the code.
run non-static block
{
// do something here
}
initialize non-static(instance) variables
public int instance_number;
And this is when and why there is default initialization!
This is not true for methods because they don't have similar mechanism as classes.
So basically this means that you will have to initialize EXPLICITLY each method variable.enter code here

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