I have a String "Magic Word". I need to trim the string to extract "Magic" only.
I am doing the following code.
String sentence = "Magic Word";
String[] words = sentence.split(" ");
for (String word : words)
{
System.out.println(word);
}
I need only the first word.
Is there any other methods to trim a string to get first word only if space occurs?
String firstWord = "Magic Word";
if(firstWord.contains(" ")){
firstWord= firstWord.substring(0, firstWord.indexOf(" "));
System.out.println(firstWord);
}
You could use String's replaceAll() method which takes a regular expression as input, to replace everything after the space including the space, if a space does indeed exist, with the empty string:
String firstWord = sentence.replaceAll(" .*", "");
This should be the easiest way.
public String firstWord(String string)
{
return (string+" ").split(" ")[0]; //add " " to string to be sure there is something to split
}
modifying previous answer.
String firstWord = null;
if(string.contains(" ")){
firstWord= string.substring(0, string.indexOf(" "));
}
else{
firstWord = string;
}
String input = "This is a line of text";
int i = input.indexOf(" "); // 4
String word = input.substring(0, i); // from 0 to 3
String rest = input.substring(i+1); // after the space to the rest of the line
A dirty solution:
sentence.replaceFirst("\\s*(\\w+).*", "$1")
This has the potential to return the original string if no match, so just add a condition:
if (sentence.matches("\\s*(\\w+).*", "$1"))
output = sentence.replaceFirst("\\s*(\\w+).*", "$1")
Or you can use a cleaner solution:
String parts[] = sentence.trim().split("\\s+");
if (parts.length > 0)
output = parts[0];
The two solutions above makes assumptions about the first character that is not space in the string is word, which might not be true if the string starts with punctuations.
To take care of that:
String parts[] = sentence.trim().replaceAll("[^\\w ]", "").split("\\s+");
if (parts.length > 0)
output = parts[0];
You May Try This->
String newString = "Magic Word";
int index = newString.indexOf(" ");
String firstString = newString.substring(0, index);
System.out.println("firstString = "+firstString);
We should never make simple things more complicated. Programming is about making complicated things simple.
string.split(" ")[0]; //the first word.
Related
I want to replace a string by removing the s in the end
Example
Sticks -> Stick
STiCKs -> STiCK
StICks -> StICK
sticks -> stick
while using the
string.replace("sticks", "stick");
doesn't maintain case as it is case sensitive, so I'm seeking for a better option.
You could use a very simple regex for this mission.
(?i) guarantees that your regex will be treated case insensitive
Demo : (?i)(stick)s
Ideone Java Demo
string.replaceAll("(?i)(stick)s", "$1");
One possible solution is regular expressions:
StringBuffer sb = new StringBuffer();
Matcher matcher = Pattern.compile("(stick)s", Pattern.CASE_INSENSITIVE) .matcher(inputString);
while(matcher.find()) {
matcher.appendReplacement(sb, matcher.group(1));
}
matcher.appendTail(sb);
String outputString = sb.toString();
Edit: this is more or less what does String::replaceAll, but replaceAll doesn't give a case insensitive option.
If you just need to remove the 's' at the end of the String you can simply use substring method like this:
String myString = "sTiCks";
myString = myString.substring(0, myString.length()-1);
// Result "sTiCk"
If you need to remove a char or String from your String not knowing where this part will be, you can try something this:
String myString = "sTiCks";
// Part you want to delete
String stringToDelete = "Ck";
// Find where that part starts inside your String
int index = myString.indexOf(stringToDelete);
// If found, use substring method to take only what is before and after that part
if (index >= 0)
myString = myString.substring(0, index) + myString.substring(index + stringToDelete.length(), myString.length());
// Result "sTis"
This will delete the desired part only the first time it finds it. But if the part you want to delete appears more than once in your String you can modify the code to this:
String myString = "sTiCks";
// Part you want to delete
String stringToDelete = "s";
int index;
while ((index = myString.indexOf(stringToDelete)) >= 0)
myString = myString.substring(0, index) + myString.substring(index + stringToDelete.length(), myString.length());
// Result "TiCk"
I hope one of these solutions fits your case.
I don't really get why all the answers so far are so complex. You can just check the last character and if it's a s (or S) you use String#substring (documentation) and leave out the last character:
String text = "STiCks";
char lastCharacter = text.charAt(text.length() - 1);
if (lastCharacter == 'S' || lastCharacter == 's') {
text = text.substring(0, text.length() - 1);
}
If you want to apply that method to multiple words, for example in a sentence, tokenize the sentence first. Then apply the method to each word and rebuild the sentence.
String sentence = StiCks are nice, I like sticks"
String[] words = sentence.split(" ");
StringJoiner joiner = new StringJoiner(" ");
for (String word : words) {
joiner.add(removePluralSuffix(word));
}
String result = joiner.toString();
or the same with Streams:
String result = Arrays.stream(sentence.split(" "))
.map(this::removePluralSuffix)
.collect(Collectors.joining(" "));
Lets say I have this text: Thundering Blow I. What I need is something that makes it look like Thundering Blow - Removing the roman number at the end of the string.
I have tried trim() and some substring() methods but they all keep returning: Thundering Blow I back to me. Maybe it could remove everything after a I in the string? Would also be fine, but I cant seem to find a way to fix it.
You need this, removes all characters after second space
String s = "Thundering Blow I";
int k = s.indexOf(" ", s.indexOf(" ") + 1);
String res = s.substring(0,k);
System.out.println(res);
String newStr = s.substring(0, s.lastIndexOf(" "));
This is the whole code:
String s = "ThunderingI";
s = s.trim();
int ind = s.lastIndexOf(" ");
if (ind > 0) {
s = s.substring(0, ind).trim();
}
System.out.println(s);
You can split the string then concatenate a new string with index 0 and 1.
Easiest solution :)..
String[] tempArray = orgStr.split(" ");
String newStr = tempArray[0] + " " + tempArray[1];
You could try this.
String a = "Thundering Blow I";
String[] b = a.split(" ");
System.out.println(b[0]+" "+b[1]);
This will remove a single Roman numeral from the end of a string, if it exists:
String input = "Thundering Blow returning MMXVI";
input = input.replaceAll("\\s[CDILMVX]*$", "");
MMXVI is 2016 in Roman numerals in case you are wondering.
I have developed a speech to text program where the user can speak a short sentence and then inserts that into a text box.
How do I extract the first letters of each word and then insert that into the text field?
For example if the user says: "Hello World". I want to insert HW into the text box.
If you have a string, you could just split it using
input.split(" ") //splitting by space
//maybe you want to replace dots, etc with nothing).
The iterate over the array:
for(String s : input.split(" "))
And then get the first letter of every string in a list/array/etc or append it to a string:
//Outside the for-loop:
String firstLetters = "";
// Insdie the for-loop:
firstLetters = s.charAt(0);
The resulting function:
public String getFirstLetters(String text)
{
String firstLetters = "";
text = text.replaceAll("[.,]", ""); // Replace dots, etc (optional)
for(String s : text.split(" "))
{
firstLetters += s.charAt(0);
}
return firstLetters;
}
The resulting function if you want to use a list (ArrayList matches):
Basically you just use an array/list/etc as argument type and instead of text.split(" ") you just use the argument. Also, remove the line where you would replace characters like dots, etc.
public String getFirstLetters(ArrayList<String> text)
{
String firstLetters = "";
for(String s : text)
{
firstLetters += s.charAt(0);
}
return firstLetters;
}
Use split to get an array separated words, then you can get first N characters with substring(0, N).
Assuming the sentence only contain a-z and A-Z and " " to separate the words , If you want an efficient way to do it, I suggest the below method.
public String getResult(String input){
StringBuilder sb = new StringBuilder();
for(String s : input.split(" ")){
sb.append(s.charAt(0));
}
return sb.toString();
}
Then write it to the text field.
jTextField.setText(getResult(input_String));
You would want to extract the string, put it all into a list, and loop through
String[] old = myTextView.getText().split(" ");
String add="";
for(String s:old)
add+=""+s.charAt(0);
myTextView.setText(add);
Title seems to be simple. But I don't get a good Idea. This is the situation
I have String like this in my Java program
String scz="3282E81WHT-22/24";
I want to split the above string into 3 Strings, such that
first string value should be 3282e81,
Next string should be WHT(ie, the String part of above string and this part is Always of 3 Characters ),
Next String value should be 22/24 (Which will always occur after -)
In short
String first= /* do some expression on scz And value should be "3282e81" */;
String second= /* do some expression on scz And value should be "WHT" */;
String third= /* do some expression on scz And value should be "22/24" */;
Input can also be like
scz="324P25BLK-12";
So 324P25 will be first String, BLK will be second (of 3 Characters). 12 will be third ( After - symbol )
How to solve this?
You can use a regex like this (\d+[A-Z]\d+)([A-Z]+)-([/\d]+) and using Matcher.group(int) method you can get your string splitted into three groups.
Code snippet
String str = "3282E81WHT-22/24";
//str = "324P25BLK-12";
Pattern pattern = Pattern.compile("(\\d+[A-Z]\\d+)([A-Z]+)-([/\\d]+)");
Matcher match = pattern.matcher(str);
System.out.println(match.matches());
System.out.println(match.group(1));
System.out.println(match.group(2));
System.out.println(match.group(3));
Output
true
3282E81
WHT
22/24
Use this to split the entire string in to two
String[] parts = issueField.split("-");
String first = parts[0];
String second= parts[1];
Use this to split the first string into two
if (first!=null && first.length()>=3){
String lastThree=first.substring(first.length()-3);
}
if your String's Second part (WHT) etc will always be of 3 Characters then following code will surely help you
String scz = "3282E81WHT-22/24";
String Third[] = scz.split("-");
String rev = new StringBuilder(Third[0]).reverse().toString();
String Second=rev.substring(0,3);
String First=rev.substring(3,rev.length());
// here Reverse your String Back to Original
First=new StringBuilder(First).reverse().toString();
Second=new StringBuilder(Second).reverse().toString();
System.out.println(First + " " + Second + " " + Third[1]);
You can use subString() method to get this goals.
subString has numbers of overloads.
for first string
String first=scz.subString(0,6);
String second=scz.subString(7,9);
You can use following regex to take out the above type string:
\d+[A-Z]\d{2}|[A-Z]{3}|(?<=-)[\d/]+
In Java, you can use above regex in following way:
Pattern pattern = Pattern.compile("\\d+[A-Z]\\d{2}|[A-Z]{3}|(?<=-)[\\d/]+");
Matcher matcher = pattern.matcher("3282E81WHT-22/24");
while (matcher.find()) {
System.out.println(matcher.group());
}
Output:
3282E81
WHT
22/24
You could us a char array instead of a string so you can access specific characters withing the array.
Example
char scz[] = "3282E81WHT-22/24";
and access the separate characters just by specifying the place in which the array you want to use.
You can try this
String scz="3282E81WHT-22/24";
String[] arr=scz.split("-");
System.out.println("first: "+arr[0].substring(0,7));
System.out.println("second: "+arr[0].substring(7,10));
System.out.println("third: "+arr[1])
Check out my solution -
class Main {
public static void main(String[] args) {
String first = "";
String second = "";
String third = "";
String scz="3282E81WHT-22/24";
String[] portions = scz.split("-");
if (portions.length > 1) {
third = portions[1];
}
String[] anotherPortions = portions[0].split("[a-zA-Z]+$");
if (anotherPortions.length > 0) {
first = anotherPortions[0];
}
second = portions[0].substring(first.length());
System.out.println(first);
System.out.println(second);
System.out.println(third);
}
}
Live Demo.
String scz="3282E81WHT-22/24";
String[] array = scz.split("-");
String str1 = (String) array[0].subSequence(0, 7);
String str2 = array[0].substring(7);
Then the split will be in this order :)
str1
str2
array[1]
if the length of string is fixed for scz, first,second and third the you can use
String first=scz.subString(0,6);
String second=scz.subString(7,9);
String third=scz.subString(10,scz.length());
Trying to write a short method so that I can parse a string and extract the first word. I have been looking for the best way to do this.
I assume I would use str.split(","), however I would like to grab just the first first word from a string, and save that in one variable, and and put the rest of the tokens in another variable.
Is there a concise way of doing this?
The second parameter of the split method is optional, and if specified will split the target string only N times.
For example:
String mystring = "the quick brown fox";
String arr[] = mystring.split(" ", 2);
String firstWord = arr[0]; //the
String theRest = arr[1]; //quick brown fox
Alternatively you could use the substring method of String.
You should be doing this
String input = "hello world, this is a line of text";
int i = input.indexOf(' ');
String word = input.substring(0, i);
String rest = input.substring(i);
The above is the fastest way of doing this task.
To simplify the above:
text.substring(0, text.indexOf(' '));
Here is a ready function:
private String getFirstWord(String text) {
int index = text.indexOf(' ');
if (index > -1) { // Check if there is more than one word.
return text.substring(0, index).trim(); // Extract first word.
} else {
return text; // Text is the first word itself.
}
}
The simple one I used to do is
str.contains(" ") ? str.split(" ")[0] : str
Where str is your string or text bla bla :). So, if
str is having empty value it returns as it is.
str is having one word, it returns as it is.
str is multiple words, it extract the first word and return.
Hope this is helpful.
import org.apache.commons.lang3.StringUtils;
...
StringUtils.substringBefore("Grigory Kislin", " ")
You can use String.split with a limit of 2.
String s = "Hello World, I'm the rest.";
String[] result = s.split(" ", 2);
String first = result[0];
String rest = result[1];
System.out.println("First: " + first);
System.out.println("Rest: " + rest);
// prints =>
// First: Hello
// Rest: World, I'm the rest.
API docs for: split
for those who are searching for kotlin
var delimiter = " "
var mFullname = "Mahendra Rajdhami"
var greetingName = mFullname.substringBefore(delimiter)
like this:
final String str = "This is a long sentence";
final String[] arr = str.split(" ", 2);
System.out.println(Arrays.toString(arr));
arr[0] is the first word, arr[1] is the rest
You could use a Scanner
http://download.oracle.com/javase/1.5.0/docs/api/java/util/Scanner.html
The scanner can also use delimiters
other than whitespace. This example
reads several items in from a string:
String input = "1 fish 2 fish red fish blue fish";
Scanner s = new Scanner(input).useDelimiter("\\s*fish\\s*");
System.out.println(s.nextInt());
System.out.println(s.nextInt());
System.out.println(s.next());
System.out.println(s.next());
s.close();
prints the following output:
1
2
red
blue
None of these answers appears to define what the OP might mean by a "word". As others have already said, a "word boundary" may be a comma, and certainly can't be counted on to be a space, or even "white space" (i.e. also tabs, newlines, etc.)
At the simplest, I'd say the word has to consist of any Unicode letters, and any digits. Even this may not be right: a String may not qualify as a word if it contains numbers, or starts with a number. Furthermore, what about hyphens, or apostrophes, of which there are presumably several variants in the whole of Unicode? All sorts of discussions of this kind and many others will apply not just to English but to all other languages, including non-human language, scientific notation, etc. It's a big topic.
But a start might be this (NB written in Groovy):
String givenString = "one two9 thr0ee four"
// String givenString = "oňňÜÐæne;:tŵo9===tĥr0eè? four!"
// String givenString = "mouse"
// String givenString = "&&^^^%"
String[] substrings = givenString.split( '[^\\p{L}^\\d]+' )
println "substrings |$substrings|"
println "first word |${substrings[0]}|"
This works OK for the first, second and third givenStrings. For "&&^^^%" it says that the first "word" is a zero-length string, and the second is "^^^". Actually a leading zero-length token is String.split's way of saying "your given String starts not with a token but a delimiter".
NB in regex \p{L} means "any Unicode letter". The parameter of String.split is of course what defines the "delimiter pattern"... i.e. a clump of characters which separates tokens.
NB2 Performance issues are irrelevant for a discussion like this, and almost certainly for all contexts.
NB3 My first port of call was Apache Commons' StringUtils package. They are likely to have the most effective and best engineered solutions for this sort of thing. But nothing jumped out... https://commons.apache.org/proper/commons-lang/apidocs/org/apache/commons/lang3/StringUtils.html ... although something of use may be lurking there.
You could also use http://download.oracle.com/javase/6/docs/api/java/util/StringTokenizer.html
I know this question has been answered already, but I have another solution (For those still searching for answers) which can fit on one line:
It uses the split functionality but only gives you the 1st entity.
String test = "123_456";
String value = test.split("_")[0];
System.out.println(value);
The output will show:
123
The easiest way I found is this:
void main()
String input = "hello world, this is a line of text";
print(input.split(" ").first);
}
Output: hello
Assuming Delimiter is a blank space here:
Before Java 8:
private String getFirstWord(String sentence){
String delimiter = " "; //Blank space is delimiter here
String[] words = sentence.split(delimiter);
return words[0];
}
After Java 8:
private String getFirstWord(String sentence){
String delimiter = " "; //Blank space is delimiter here
String firstWord = Arrays.stream(sentence.split(delimiter))
.findFirst()
.orElse("No word found");
}
String anotherPalindrome = "Niagara. O roar again!";
String roar = anotherPalindrome.substring(11, 15);
You can also do like these