I'm getting the error "Class "test2" is mapped, but is not included in any" in eclipse, however the class is included in persistence xml.
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0"
xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="test1">
<class>com.test.domains.test1</class>
<properties>
<!-- properties for schema1 here -->
</properties>
</persistence-unit>
<persistence-unit name="test2">
<class>com.test.test2</class>
<properties>
<!-- properties for schema 2 here -->
</properties>
</persistence-unit>
</persistence>
Why does this error appear. Do I have to configure it different for 2 db schemas?
Eclipse (or more specifically Dali) do have limitation, it does not support two persistence units. That is also told in their pages:
Currently Dali only supports one Persistence Unit and one Persistence
XML file per project. Other configurations can exist in a JPA project,
but the validation and defaults processing may not be correct when
multiple persistence units are used.
What it comes to JPA itself, persistence.xml seems to becorrect. There is no need to add same class to two persistence units.
Related
I'm trying to create a layered web proyect with an EAR. I divided the Entities from the DataAccess in order to only allow DataAccess to be called by BusinessLogic.
I'm actually getting this exception:
Object: co.edu.icesi.i2trading.entities.Statetype#21397ba0 is not a known entity type.
And I found here that I need to create a persistence.xml in the EAR, but I can't really understand how.
Sharing a persistence unit across components in a .ear file
I tried placing the XML file in the Configuration Files:
And referencing the jar with <jar-files> in the persistence.xml;
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="I2TradingDataAccessPU" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/I2DataSource</jta-data-source>
<jar-file>../I2TradingEntities.jar</jar-file>
<jar-file>../../I2TradingEntities.jar</jar-file>
<shared-cache-mode>NONE</shared-cache-mode>
<properties>
<property name="eclipselink.target-server" value="None"/>
<!-- <property name="eclipselink.logging.level" value="ALL"/> -->
<property name="eclipselink.logging.level" value="WARNING"/>
</properties>
</persistence-unit>
</persistence>
With no success. Any idea why? I'm very new to Web Developing and this is getting to my nerves.
I'm also getting this WARNING in the persistence.xml's DESIGN tab:
I believe that the instruction jar-file interprets any path from the file that holds the persistence.xml... So, your configuration specifies that the Entities JAR are siblings of your EAR file.
The best (and easy) solution for your problem is to put the given persistence.xmlat the META-INF folder of your I2TradingEntities.jar and remove the <jar-file> instructions from it ... This will instruct the Application Server to create a PersistenceContext called "I2TradingDataAccessPU" and to detect any #Entity Class contained in that JAR.
I need two or more than two connections in my web application using jpa
To use different data sources, add multiple persistence units (say, source-1 and source-2 in persistence.xml and create multiple EntityManagerFactoryes by name):
EntityManagerFactory emf1 = Persistence.createEntityManagerFactory("source-1");
EntityManagerFactory emf2 = Persistence.createEntityManagerFactory("source-2");
or, if you're working on Spring or Java EE application server, inject them by name also:
#PersistenceUnit(name = "source-1")
EntityManagerFactory emf1;
#PersistenceContext(unitName = "source-2") // as an option
EntityManager em2;
persistence.xml will thus look like the following:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="source-1" transaction-type="RESOURCE_LOCAL">
<properties>
<!-- source-1 properties here -->
</properties>
</persistence-unit>
<persistence-unit name="source-2" transaction-type="RESOURCE_LOCAL">
<properties>
<!-- source-2 properties here -->
</properties>
</persistence-unit>
</persistence>
Example of how to configure persistence unit, create EntityManager to manage entities and execute queries can be found here.
For single datasource jpa will use multiple connections internally.So you don't need to do anything.
I have created a Hibernate / JPA project and I'd like to create entities from tables.
While the tool works like a charm selecting a pure Hibernate configuration, in the JPA mode it does not work, claiming the absence of the persistence unit
As shown in the following photo, the persistence unit is located in the folder /src/main/resources/META-INF
This is the code of persistence.xml file:
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="socialsports" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistenceProvider</provider>
<jta-data-source>jdbc/LiveDataSource</jta-data-source>
</persistence-unit>
</persistence>
This is the result of my attempt to run Hibernate tools to generate entities:
Since it only doesn't work in JPA mode, the use of the deprecated org.hibernate.ejb.HibernatePersistenceProvider could be a problem. Try org.hibernate.jpa.HibernatePersistenceProvider instead.
In my Java/Seam/JbossAS app, I decided to externalize my Model classes (hibernate entities) and moved them into another project. The project produces model.jar, which is then used by the main app. The model.jar dependency is resolved by Ivy.
Building the main app with Ant works without problems. Then I copy manually the model.jar into 'mainapp.ear/lib' directory. Afterwards I deploy the app and there are no problems (although I notice that there are is no log info about found mappings). But when I want to login, I get the exception:
javax.el.ELException: javax.ejb.EJBTransactionRolledbackException:
org.hibernate.hql.ast.QuerySyntaxException: AppUser is not
mapped [select u from AppUser u where u.userName = :usernamePar]
There were no code changes in the meantime, just externalizing some of the classes into a jar. Does this mean, that I need the source code of the Model classes when compiling the main app?
The EntityManagerFactory is built for scanning entities only from the jar that has a /META-INF/persistence.xml file into.
In order to scan other jars you have to use <jar-file>:
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="manager1" transaction-type="JTA">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<jta-data-source>java:/DefaultDS</jta-data-source>
<mapping-file>ormap.xml</mapping-file>
<jar-file>MyApp.jar</jar-file>
<class>org.acme.Employee</class>
<class>org.acme.Person</class>
<class>org.acme.Address</class>
<shared-cache-mode>ENABLE_SELECTOVE</shared-cache-mode>
<validation-mode>CALLBACK</validation-mode>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
</properties>
</persistence-unit>
</persistence>
See 2.2.1 Packaging in Hibernate doc.
Also check if your hibernate mappings are correctly placed wrt hibernate config file. Note that hibernate mapping resources or classes are relative to the location of hibernate.cfg.xml file.
We created some libraries that all our projects will use, this libraries will provide the basic functionality of all our systems (login, some manage, etc). But the application itself could use another database.
What we did was to create the Persistence.xml with two persist units. And package all the core library entities in a jar called "LN-model.jar" and all of the entities of out test app in "App-model.jar". But for some reason we still obtain the following message.
Could not resolve a persistence unit corresponding to the persistence-context-ref-name [x.x.x.x.listener.InicializadorListener/em] in the scope of the module called [gfdeploy#/Users/zkropotkine/WORK/SeguridadCore/dist/gfdeploy/SeguridadCore-war_war]. Please verify your application.
Here's our Persistence.xml
<persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd">
<persistence-unit name="x" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/x</jta-data-source>
<jar-file>App-model.jar</jar-file>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
</properties>
</persistence-unit>
<persistence-unit name="y" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/y</jta-data-source>
<jar-file>LN-model.jar</jar-file>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties/>
</persistence-unit>
By the way we put the Persistence.xml in a jar, that we add to our Enterprise Project (EAR).
The problem is that the JPA does not know which is the persistence unit to use. when you have only one persistence unit this problem does not occur. To fix do the following:
You need to specify a persistence unit : #PersistenceContext(unitName="...") in the Ejb that do not have
You can add the annotations:
#PersistenceUnit(name = "x")
EntityManagerFactory entityManagerFactory;
#PersistenceContext(unitName = "y")
EntityManager entityManager;
Or you can create it manually:
EntityManagerFactory emfA = Persistence.createEntityManagerFactory("x", properties);
EntityManagerFactory emfB = Persistence.createEntityManagerFactory("y", properties);
For more details, please see the following link: https://docs.oracle.com/html/E25034_01/usingmultipledbs.htm
is very useful, to me helped me!