Java - Extracting a string from another string - java

I have a String like this:
http://www.fam.com/FAM#Bruno12/06/2011
How can I cut http://www.fam.com/FAM# and 12/06/2011 in order to get only Bruno.
The format is always:
http://www.fam.com/FAM#NAMEDATE
Is there a simple way to do this? Can you just explain me how?


Simply do this:
myString = original.substring(23, original.length() - 10);
23 is for http://www.fam.com/FAM#
original.length() - 10 is for 12/06/2011


Use :
String str = "http://www.fam.com/FAM#Bruno12/06/2011";
String[] arr = str.split("#|[\\d+/]"); // last index of arr is Bruno


If the string always starts with http://www.fam.com/FAM# then it's simple: that's 23 characters, so take the substring from position 23 (note that indices are zero-based).
String input = "http://www.fam.com/FAM#Bruno12/06/2011";
String result = input.substring(23);
If you want everything after the first # in the string, then search for # and take everything that comes after it:
int index = input.indexOf('#');
String result = input.substring(index + 1);
(error checking omitted for simplicity).
To remove the date, remove the last 10 characters.
See the API documentation of class String for useful methods.


use regex #(.*?)\\d\\d/ to capture it.


You should use standard URL parsing code, as at Could you share a link to an URL parsing implementation?
I expect the URL parser can cope with the fact that your Ref (i.e. "Bruno12/06/2011") contains slashes.
URL url = new URL(inputString);
String nameDate = url.getRef();
expresses what you want to do in the simplest and clearest form.

Related

String Replace Based On Variable Value

I've the following string: {"array 1":[ ....
And I would like to remove everything preceding [.
For that I use: .replace("{\"array 1\":", ""); and that works well.
However, I've several arrays, so I'd like to do the replace based on a variable that holds the array name.
For example:
String arr_name = "array 1";
....replace('{\"arr_name\":", "");
Is it possible to use variable key to replace a string?
EDIT:
I've ended up adding another element to parse the array in JSON which removed its name.
Thank you all for the quick comments and suggestions.

you can do a string format, here is an example of that :
String arr_name = "array 1";
....replace(String.format ("{\"%s\"", arr_name), "");

Just use a substring, starting at the index of [.
String input = "{\"array 1\":[key:value...";
String result = input.substring(input.indexOf('['));
This gives [key.value...

Split String in java by specified pattern

How to split this String in java such that I'll get the text occurring between the braces in a String array?
GivenString = "(1,2,3,4,#) (a,s,3,4,5) (22,324,#$%) (123,3def,f34rf,4fe) (32)"
String [] array = GivenString.split("");
Output must be:
array[0] = "1,2,3,4,#"
array[1] = "a,s,3,4,5"
array[2] = "22,324,#$%"
array[3] = "123,3def,f34rf,4fe"
array[4] = "32"

You can try to use:
Matcher mtc = Pattern.compile("\\((.*?)\\)").matcher(yourString);

The best solution is the answer by Rahul Tripathi, but your question said "How to split", so if you must use split() (e.g. this is an assignment), then this regex will do:
^\s*\(|\)\s*\(|\)\s*$
It says:
Match the open-parenthesis at the beginning
Match close-parenthesis followed by open-parenthesis
Match the close-parenthesis at the end
All 3 allowing whitespace.
As a Java regex, that would mean:
str.split("^\\s*\\(|\\)\\s*\\(|\\)\\s*$")
See regex101 for demo.
The problem with using split() is that the leading open-parenthesis causes a split before the first value, resulting in an empty value at the beginning:
array[0] = ""
array[1] = "1,2,3,4,#"
array[2] = "a,s,3,4,5"
array[3] = "22,324,#$%"
array[4] = "123,3def,f34rf,4fe"
array[5] = "32"
That is why Rahul's answer is better, because it won't see such an empty value.

Usually, you would want to use the split() function as this is the easiest way to split a string into multiple arrays when the string is broken up by a key char.
The main problem is that you need information inbetween two chars. The easiest way to solve this problem would to go through the string get ride of every instance of '('. This leaves the string looking like
String = "1,2,3,4,#) a,s,3,4,5) 22,324,#$%) 123,3def,f34rf,4fe) 32)"
And this is perfect, as you can split by the char ')' and not worry about the other bracket interfering with the split. I suggest using the replace("","") where it replaces every instance of the first parameter with the second parameter (we can use "" to delete it).
Here is some example code that may work :
String a = "(1,2,3,4,#) (a,s,3,4,5) (22,324,#$%) (123,3def,f34rf,4fe) (32)"
a = a.replace("(","");
//a is now equal to 1,2,3,4,#) a,s,3,4,5) 22,324,#$%) 123,3def,f34rf,4fe) 32)
String[] parts = a.split("\\)");
System.out.println(parts[0]); //this will print 1,2,3,4,#
I haven't tested it completely, so you may end up with unwanted spaces at the end of the strings you may need to get rid of!
You can then loop through parts[] and it should have all of the required parts for you!

Splitting string into substring in Java

I have one string and I want to split it into substring in Java, originally the string is like this
Node( <http://www.mooney.net/geo#wisconsin> )
Now I want to split it into substring by (#), and this is my code for doing it
String[] split = row.split("#");
String word = split[1].trim().substring(0, (split[1].length() -1));
Now this code is working but it gives me
"wisconsin>"
the last work what I want is just the work "wisconsin" without ">" this sign, if someone have an idea please help me, thanks in advance.

Java1.7 DOC for String class
Actually it gives you output as "wisconsin> " (include space)
Make subString() as
String word = split[1].trim().substring(0, (split[1].length()-3));
Then you will get output as
wisconsin
Tutorials Point String subString() method reference

Consider
String split[] = row.split("#|<|>");
which delivers a String array like this,
{"http://www.mooney.net/geo", "wisconsin"}
Get the last element, at index split.length()-1.

String string = "Enter parts here";
String[] parts = string.split("-");
String part1 = parts[0];
String part2 = parts[1];

you can just split like you did before once more (with > instead of #) and use the element [0] istead of [1]

You can just use replace like.
word.replace(char oldChar, char newChar)
Hope that helps

You can use Java String Class's subString() method.
Refer to this link.

Java string split with Multiple Characters Delimiter

I have a very complicated output from a function, which i need to use specific word from it.
For example, my output is:
oracle 11257 1 0 14:01 ? 00:00:00 ora_pmon_sas
I need to get just "sas" word, which is next to "ora_pmon_"
Another example:
oracle 6187 1 0 13:41 ? 00:00:00 ora_pmon_db2
I need to get "db2". So what should be my expression?
JAVA code:
insArray=line.split("what will be between these quotes?");

You could just do
String sub = s.substring(s.indexOf("ora_pmon_") + 9);

How about this one?
string = string.replaceAll(".*?ora_pmon_", "");
If you want multiple words in place of ora, then it will be
string = string.replaceAll(".*?(ora|kf|asm)_pmon_", "");

You can simply use String#substring(int i) combined with String#lastIndexOf(char ch)
For example:
String result = input.substring(input.lastIndexOf('_') + 1)

How to get specific string out of long string

I have the following String (it is variable, but classpath is always the same):
C:.Users.mho.Desktop.Eclipse.workspace.GIT.BLUBB...bin.de.test.class.mho.communication.InterfaceXmlHandler
and I want to get just
de.test.class.mho.communication.InterfaceXmlHandler
out of this string. The end
InterfaceXmlHandler
is variable, also the beginning before 'de' and the path itself is variable too, but
de.test.class.mho.
isn't variable.

Why not just use
String result = str.substring(str.lastIndexOf("de.test.class.mho."));

Instead of splitting you could get rid of the beginning of the string:
String input = "C:.Users.mho.Desktop.Eclipse.workspace.GIT.BLUBB...bin.de.test.class.mho.communication.InterfaceXmlHandler";
String output = input.replaceAll(".*(de\\.test\\.class\\.mho.*)", "$1");

You can create a string-array with String.split("de.test.class.mho."). The Array will contain two Strings, the second String will be what you want.
String longString = ""; //whatever
String[] urlArr = longString.split("de.test.class.mho.");
String result;
if(urlArr.length > 1) {
result = "de.test.class.mho." urlArr[1]; //de.test.class.mho.whatever.whatever.whatever
}

You can use replaceAll() to "extract" the part you want:
String part = str.replaceAll(".*(?=de\\.test\\.class\\.mho\\.)", "");
This uses a look-ahead to find all characters before the target, and replace them with a blank (ie delete them).
You could quite reasonably ignore escaping the dots for brevity:
String part = str.replaceAll(".*(?=de.test.class.mho.)", "");
I doubt it would give a different result.

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