Complexity of algorithm implementing Newton's method in finding square root - java

I have written a Java program to calculate the square root of a user-defined number using Newton's method. The main operations of the algo goes like that:
answer = guess - ((guess * guess - inputNumber) / (2 * guess));
while (Math.abs(answer * answer - inputNumber) > leniency) {
guess = answer;
answer = guess - ((guess * guess - inputNumber) / (2 * guess));
}
I'm now seeking to find the complexity of the algorithm (yup it's homework), and have read up from here that the time complexity of Newton's method is O(log(n) * F(x)).
However, from the above code snippet, I have interpreted the time complexity to be:
O(1+ ∑(1 to n) (1) ) = O(1+n) = O(n)
Not sure what I'm getting wrong here, but I can't seem to understand the disparity in big Os even after reading wiki's explanation.
Also, I am assuming that "complexity of algorithm" is synonymous to "time complexity". Is it right to do so?
Would really appreciate help in explaining this paradox, as I'm a newbie student with a few 'touch and go' programming modules worth of background.
Thanks in advance :)

The problem is that you actually know nothing about n in your calculation - you don't say what it should be. When you calculate the actual error of the next iteration of the algorithm (do it!), you'll see that eg. if a is at least 1 and error is less than 1, you basically double the number of valid places every iteration. So to get p decimal places, you have to perform log(p) iterations.

Related

Integer range in square root algorithm of Cracking the Code book

There is an algorithm in java for square root in cracking the code book as below:
int sqrt(int n) {
return sqrt_helper(n, 1, n);
}
int sqrt_helper(int n, int min, int max) {
if (max < min) return -1;
int guess = (min + max) / 2·,
if (guess *guess == n) {
return guess;
} else if (guess * guess < n) {
return sqrt_helper(n, guess + 1, max);
} else {
return sqrt_helper(n, min, guess - l);
}
}
The question is:
As min and max are integer, they can have any values in the range, i.e max = Integer.MAX_VALUE
So how not be worry about guess = (min + max) / 2 as it will cross the allowed range, or guess *guess also.
There are simple ways of getting around that problem (like min + (max - min) / 2).
The more serious integer overflow problem is guess * guess. You could change the test to compare guess with n / guess, which is slower but normally won't overflow. Or you could use a bit hack to find a better starting point (clz is useful here, if you have it), since you should be able to find a guess whose square is within the range of representable integers.
An interviewer might be even more impressed if you were able to provide the Newton-Raphson algorithm, which converges extremely rapidly.
Since you mention "Cracking the Coding Interview"...
Typically in the context of the average coding interview one wouldn't worry about implementation-specific details like this. The interviewer is trying to confirm basic competency and understanding - they'll rarely want to run your code, and it should be a given for both of you that the algorithm will break down at the extreme limits of your language's basic data types. If the interviewer asks specifically about limitations, then you could briefly mention that the function will fail for values higher than (Integer.MAX_VALUE / 2) in this language.
The limitation will apply to almost any algorithm you write for a coding interview, and no reasonable interviewer would expect you to specifically design your solution to mitigate this kind of edge case. I would find it extremely off-putting if I asked a candidate to write a function that produces Fibonacci numbers and they spent time trying to optimize the case where the output exceeds 16 digit values.
If for some reason you needed to find the square root of extremely large values using this algorithm in a real life scenario, I'd expect you'd to have to implement it using a generic big number library for your particular language. That being said, I wouldn't roll my own square root algorithm for any real use case under almost any circumstance.
You'd have to confirm your language. But in pseudo-code you can do something like:
int guess = ((min.ToBigInt() + max.ToBigInt()) / 2).ToInt()

Behind the scenes of recursion? [duplicate]

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One of the topics that seems to come up regularly on mailing lists and online discussions is the merits (or lack thereof) of doing a Computer Science Degree. An argument that seems to come up time and again for the negative party is that they have been coding for some number of years and they have never used recursion.
So the question is:
What is recursion?
When would I use recursion?
Why don't people use recursion?
There are a number of good explanations of recursion in this thread, this answer is about why you shouldn't use it in most languages.* In the majority of major imperative language implementations (i.e. every major implementation of C, C++, Basic, Python, Ruby,Java, and C#) iteration is vastly preferable to recursion.
To see why, walk through the steps that the above languages use to call a function:
space is carved out on the stack for the function's arguments and local variables
the function's arguments are copied into this new space
control jumps to the function
the function's code runs
the function's result is copied into a return value
the stack is rewound to its previous position
control jumps back to where the function was called
Doing all of these steps takes time, usually a little bit more than it takes to iterate through a loop. However, the real problem is in step #1. When many programs start, they allocate a single chunk of memory for their stack, and when they run out of that memory (often, but not always due to recursion), the program crashes due to a stack overflow.
So in these languages recursion is slower and it makes you vulnerable to crashing. There are still some arguments for using it though. In general, code written recursively is shorter and a bit more elegant, once you know how to read it.
There is a technique that language implementers can use called tail call optimization which can eliminate some classes of stack overflow. Put succinctly: if a function's return expression is simply the result of a function call, then you don't need to add a new level onto the stack, you can reuse the current one for the function being called. Regrettably, few imperative language-implementations have tail-call optimization built in.
* I love recursion. My favorite static language doesn't use loops at all, recursion is the only way to do something repeatedly. I just don't think that recursion is generally a good idea in languages that aren't tuned for it.
** By the way Mario, the typical name for your ArrangeString function is "join", and I'd be surprised if your language of choice doesn't already have an implementation of it.
Simple english example of recursion.
A child couldn't sleep, so her mother told her a story about a little frog,
who couldn't sleep, so the frog's mother told her a story about a little bear,
who couldn't sleep, so the bear's mother told her a story about a little weasel...
who fell asleep.
...and the little bear fell asleep;
...and the little frog fell asleep;
...and the child fell asleep.
In the most basic computer science sense, recursion is a function that calls itself. Say you have a linked list structure:
struct Node {
Node* next;
};
And you want to find out how long a linked list is you can do this with recursion:
int length(const Node* list) {
if (!list->next) {
return 1;
} else {
return 1 + length(list->next);
}
}
(This could of course be done with a for loop as well, but is useful as an illustration of the concept)
Whenever a function calls itself, creating a loop, then that's recursion. As with anything there are good uses and bad uses for recursion.
The most simple example is tail recursion where the very last line of the function is a call to itself:
int FloorByTen(int num)
{
if (num % 10 == 0)
return num;
else
return FloorByTen(num-1);
}
However, this is a lame, almost pointless example because it can easily be replaced by more efficient iteration. After all, recursion suffers from function call overhead, which in the example above could be substantial compared to the operation inside the function itself.
So the whole reason to do recursion rather than iteration should be to take advantage of the call stack to do some clever stuff. For example, if you call a function multiple times with different parameters inside the same loop then that's a way to accomplish branching. A classic example is the Sierpinski triangle.
You can draw one of those very simply with recursion, where the call stack branches in 3 directions:
private void BuildVertices(double x, double y, double len)
{
if (len > 0.002)
{
mesh.Positions.Add(new Point3D(x, y + len, -len));
mesh.Positions.Add(new Point3D(x - len, y - len, -len));
mesh.Positions.Add(new Point3D(x + len, y - len, -len));
len *= 0.5;
BuildVertices(x, y + len, len);
BuildVertices(x - len, y - len, len);
BuildVertices(x + len, y - len, len);
}
}
If you attempt to do the same thing with iteration I think you'll find it takes a lot more code to accomplish.
Other common use cases might include traversing hierarchies, e.g. website crawlers, directory comparisons, etc.
Conclusion
In practical terms, recursion makes the most sense whenever you need iterative branching.
Recursion is a method of solving problems based on the divide and conquer mentality.
The basic idea is that you take the original problem and divide it into smaller (more easily solved) instances of itself, solve those smaller instances (usually by using the same algorithm again) and then reassemble them into the final solution.
The canonical example is a routine to generate the Factorial of n. The Factorial of n is calculated by multiplying all of the numbers between 1 and n. An iterative solution in C# looks like this:
public int Fact(int n)
{
int fact = 1;
for( int i = 2; i <= n; i++)
{
fact = fact * i;
}
return fact;
}
There's nothing surprising about the iterative solution and it should make sense to anyone familiar with C#.
The recursive solution is found by recognising that the nth Factorial is n * Fact(n-1). Or to put it another way, if you know what a particular Factorial number is you can calculate the next one. Here is the recursive solution in C#:
public int FactRec(int n)
{
if( n < 2 )
{
return 1;
}
return n * FactRec( n - 1 );
}
The first part of this function is known as a Base Case (or sometimes Guard Clause) and is what prevents the algorithm from running forever. It just returns the value 1 whenever the function is called with a value of 1 or less. The second part is more interesting and is known as the Recursive Step. Here we call the same method with a slightly modified parameter (we decrement it by 1) and then multiply the result with our copy of n.
When first encountered this can be kind of confusing so it's instructive to examine how it works when run. Imagine that we call FactRec(5). We enter the routine, are not picked up by the base case and so we end up like this:
// In FactRec(5)
return 5 * FactRec( 5 - 1 );
// which is
return 5 * FactRec(4);
If we re-enter the method with the parameter 4 we are again not stopped by the guard clause and so we end up at:
// In FactRec(4)
return 4 * FactRec(3);
If we substitute this return value into the return value above we get
// In FactRec(5)
return 5 * (4 * FactRec(3));
This should give you a clue as to how the final solution is arrived at so we'll fast track and show each step on the way down:
return 5 * (4 * FactRec(3));
return 5 * (4 * (3 * FactRec(2)));
return 5 * (4 * (3 * (2 * FactRec(1))));
return 5 * (4 * (3 * (2 * (1))));
That final substitution happens when the base case is triggered. At this point we have a simple algrebraic formula to solve which equates directly to the definition of Factorials in the first place.
It's instructive to note that every call into the method results in either a base case being triggered or a call to the same method where the parameters are closer to a base case (often called a recursive call). If this is not the case then the method will run forever.
Recursion is solving a problem with a function that calls itself. A good example of this is a factorial function. Factorial is a math problem where factorial of 5, for example, is 5 * 4 * 3 * 2 * 1. This function solves this in C# for positive integers (not tested - there may be a bug).
public int Factorial(int n)
{
if (n <= 1)
return 1;
return n * Factorial(n - 1);
}
Recursion refers to a method which solves a problem by solving a smaller version of the problem and then using that result plus some other computation to formulate the answer to the original problem. Often times, in the process of solving the smaller version, the method will solve a yet smaller version of the problem, and so on, until it reaches a "base case" which is trivial to solve.
For instance, to calculate a factorial for the number X, one can represent it as X times the factorial of X-1. Thus, the method "recurses" to find the factorial of X-1, and then multiplies whatever it got by X to give a final answer. Of course, to find the factorial of X-1, it'll first calculate the factorial of X-2, and so on. The base case would be when X is 0 or 1, in which case it knows to return 1 since 0! = 1! = 1.
Consider an old, well known problem:
In mathematics, the greatest common divisor (gcd) … of two or more non-zero integers, is the largest positive integer that divides the numbers without a remainder.
The definition of gcd is surprisingly simple:
where mod is the modulo operator (that is, the remainder after integer division).
In English, this definition says the greatest common divisor of any number and zero is that number, and the greatest common divisor of two numbers m and n is the greatest common divisor of n and the remainder after dividing m by n.
If you'd like to know why this works, see the Wikipedia article on the Euclidean algorithm.
Let's compute gcd(10, 8) as an example. Each step is equal to the one just before it:
gcd(10, 8)
gcd(10, 10 mod 8)
gcd(8, 2)
gcd(8, 8 mod 2)
gcd(2, 0)
2
In the first step, 8 does not equal zero, so the second part of the definition applies. 10 mod 8 = 2 because 8 goes into 10 once with a remainder of 2. At step 3, the second part applies again, but this time 8 mod 2 = 0 because 2 divides 8 with no remainder. At step 5, the second argument is 0, so the answer is 2.
Did you notice that gcd appears on both the left and right sides of the equals sign? A mathematician would say this definition is recursive because the expression you're defining recurs inside its definition.
Recursive definitions tend to be elegant. For example, a recursive definition for the sum of a list is
sum l =
if empty(l)
return 0
else
return head(l) + sum(tail(l))
where head is the first element in a list and tail is the rest of the list. Note that sum recurs inside its definition at the end.
Maybe you'd prefer the maximum value in a list instead:
max l =
if empty(l)
error
elsif length(l) = 1
return head(l)
else
tailmax = max(tail(l))
if head(l) > tailmax
return head(l)
else
return tailmax
You might define multiplication of non-negative integers recursively to turn it into a series of additions:
a * b =
if b = 0
return 0
else
return a + (a * (b - 1))
If that bit about transforming multiplication into a series of additions doesn't make sense, try expanding a few simple examples to see how it works.
Merge sort has a lovely recursive definition:
sort(l) =
if empty(l) or length(l) = 1
return l
else
(left,right) = split l
return merge(sort(left), sort(right))
Recursive definitions are all around if you know what to look for. Notice how all of these definitions have very simple base cases, e.g., gcd(m, 0) = m. The recursive cases whittle away at the problem to get down to the easy answers.
With this understanding, you can now appreciate the other algorithms in Wikipedia's article on recursion!
A function that calls itself
When a function can be (easily) decomposed into a simple operation plus the same function on some smaller portion of the problem. I should say, rather, that this makes it a good candidate for recursion.
They do!
The canonical example is the factorial which looks like:
int fact(int a)
{
if(a==1)
return 1;
return a*fact(a-1);
}
In general, recursion isn't necessarily fast (function call overhead tends to be high because recursive functions tend to be small, see above) and can suffer from some problems (stack overflow anyone?). Some say they tend to be hard to get 'right' in non-trivial cases but I don't really buy into that. In some situations, recursion makes the most sense and is the most elegant and clear way to write a particular function. It should be noted that some languages favor recursive solutions and optimize them much more (LISP comes to mind).
A recursive function is one which calls itself. The most common reason I've found to use it is traversing a tree structure. For example, if I have a TreeView with checkboxes (think installation of a new program, "choose features to install" page), I might want a "check all" button which would be something like this (pseudocode):
function cmdCheckAllClick {
checkRecursively(TreeView1.RootNode);
}
function checkRecursively(Node n) {
n.Checked = True;
foreach ( n.Children as child ) {
checkRecursively(child);
}
}
So you can see that the checkRecursively first checks the node which it is passed, then calls itself for each of that node's children.
You do need to be a bit careful with recursion. If you get into an infinite recursive loop, you will get a Stack Overflow exception :)
I can't think of a reason why people shouldn't use it, when appropriate. It is useful in some circumstances, and not in others.
I think that because it's an interesting technique, some coders perhaps end up using it more often than they should, without real justification. This has given recursion a bad name in some circles.
Recursion is an expression directly or indirectly referencing itself.
Consider recursive acronyms as a simple example:
GNU stands for GNU's Not Unix
PHP stands for PHP: Hypertext Preprocessor
YAML stands for YAML Ain't Markup Language
WINE stands for Wine Is Not an Emulator
VISA stands for Visa International Service Association
More examples on Wikipedia
Recursion works best with what I like to call "fractal problems", where you're dealing with a big thing that's made of smaller versions of that big thing, each of which is an even smaller version of the big thing, and so on. If you ever have to traverse or search through something like a tree or nested identical structures, you've got a problem that might be a good candidate for recursion.
People avoid recursion for a number of reasons:
Most people (myself included) cut their programming teeth on procedural or object-oriented programming as opposed to functional programming. To such people, the iterative approach (typically using loops) feels more natural.
Those of us who cut our programming teeth on procedural or object-oriented programming have often been told to avoid recursion because it's error prone.
We're often told that recursion is slow. Calling and returning from a routine repeatedly involves a lot of stack pushing and popping, which is slower than looping. I think some languages handle this better than others, and those languages are most likely not those where the dominant paradigm is procedural or object-oriented.
For at least a couple of programming languages I've used, I remember hearing recommendations not to use recursion if it gets beyond a certain depth because its stack isn't that deep.
A recursive statement is one in which you define the process of what to do next as a combination of the inputs and what you have already done.
For example, take factorial:
factorial(6) = 6*5*4*3*2*1
But it's easy to see factorial(6) also is:
6 * factorial(5) = 6*(5*4*3*2*1).
So generally:
factorial(n) = n*factorial(n-1)
Of course, the tricky thing about recursion is that if you want to define things in terms of what you have already done, there needs to be some place to start.
In this example, we just make a special case by defining factorial(1) = 1.
Now we see it from the bottom up:
factorial(6) = 6*factorial(5)
= 6*5*factorial(4)
= 6*5*4*factorial(3) = 6*5*4*3*factorial(2) = 6*5*4*3*2*factorial(1) = 6*5*4*3*2*1
Since we defined factorial(1) = 1, we reach the "bottom".
Generally speaking, recursive procedures have two parts:
1) The recursive part, which defines some procedure in terms of new inputs combined with what you've "already done" via the same procedure. (i.e. factorial(n) = n*factorial(n-1))
2) A base part, which makes sure that the process doesn't repeat forever by giving it some place to start (i.e. factorial(1) = 1)
It can be a bit confusing to get your head around at first, but just look at a bunch of examples and it should all come together. If you want a much deeper understanding of the concept, study mathematical induction. Also, be aware that some languages optimize for recursive calls while others do not. It's pretty easy to make insanely slow recursive functions if you're not careful, but there are also techniques to make them performant in most cases.
Hope this helps...
I like this definition:
In recursion, a routine solves a small part of a problem itself, divides the problem into smaller pieces, and then calls itself to solve each of the smaller pieces.
I also like Steve McConnells discussion of recursion in Code Complete where he criticises the examples used in Computer Science books on Recursion.
Don't use recursion for factorials or Fibonacci numbers
One problem with
computer-science textbooks is that
they present silly examples of
recursion. The typical examples are
computing a factorial or computing a
Fibonacci sequence. Recursion is a
powerful tool, and it's really dumb to
use it in either of those cases. If a
programmer who worked for me used
recursion to compute a factorial, I'd
hire someone else.
I thought this was a very interesting point to raise and may be a reason why recursion is often misunderstood.
EDIT:
This was not a dig at Dav's answer - I had not seen that reply when I posted this
1.)
A method is recursive if it can call itself; either directly:
void f() {
... f() ...
}
or indirectly:
void f() {
... g() ...
}
void g() {
... f() ...
}
2.) When to use recursion
Q: Does using recursion usually make your code faster?
A: No.
Q: Does using recursion usually use less memory?
A: No.
Q: Then why use recursion?
A: It sometimes makes your code much simpler!
3.) People use recursion only when it is very complex to write iterative code. For example, tree traversal techniques like preorder, postorder can be made both iterative and recursive. But usually we use recursive because of its simplicity.
Here's a simple example: how many elements in a set. (there are better ways to count things, but this is a nice simple recursive example.)
First, we need two rules:
if the set is empty, the count of items in the set is zero (duh!).
if the set is not empty, the count is one plus the number of items in the set after one item is removed.
Suppose you have a set like this: [x x x]. let's count how many items there are.
the set is [x x x] which is not empty, so we apply rule 2. the number of items is one plus the number of items in [x x] (i.e. we removed an item).
the set is [x x], so we apply rule 2 again: one + number of items in [x].
the set is [x], which still matches rule 2: one + number of items in [].
Now the set is [], which matches rule 1: the count is zero!
Now that we know the answer in step 4 (0), we can solve step 3 (1 + 0)
Likewise, now that we know the answer in step 3 (1), we can solve step 2 (1 + 1)
And finally now that we know the answer in step 2 (2), we can solve step 1 (1 + 2) and get the count of items in [x x x], which is 3. Hooray!
We can represent this as:
count of [x x x] = 1 + count of [x x]
= 1 + (1 + count of [x])
= 1 + (1 + (1 + count of []))
= 1 + (1 + (1 + 0)))
= 1 + (1 + (1))
= 1 + (2)
= 3
When applying a recursive solution, you usually have at least 2 rules:
the basis, the simple case which states what happens when you have "used up" all of your data. This is usually some variation of "if you are out of data to process, your answer is X"
the recursive rule, which states what happens if you still have data. This is usually some kind of rule that says "do something to make your data set smaller, and reapply your rules to the smaller data set."
If we translate the above to pseudocode, we get:
numberOfItems(set)
if set is empty
return 0
else
remove 1 item from set
return 1 + numberOfItems(set)
There's a lot more useful examples (traversing a tree, for example) which I'm sure other people will cover.
Well, that's a pretty decent definition you have. And wikipedia has a good definition too. So I'll add another (probably worse) definition for you.
When people refer to "recursion", they're usually talking about a function they've written which calls itself repeatedly until it is done with its work. Recursion can be helpful when traversing hierarchies in data structures.
An example: A recursive definition of a staircase is:
A staircase consists of:
- a single step and a staircase (recursion)
- or only a single step (termination)
To recurse on a solved problem: do nothing, you're done.
To recurse on an open problem: do the next step, then recurse on the rest.
In plain English:
Assume you can do 3 things:
Take one apple
Write down tally marks
Count tally marks
You have a lot of apples in front of you on a table and you want to know how many apples there are.
start
Is the table empty?
yes: Count the tally marks and cheer like it's your birthday!
no: Take 1 apple and put it aside
Write down a tally mark
goto start
The process of repeating the same thing till you are done is called recursion.
I hope this is the "plain english" answer you are looking for!
A recursive function is a function that contains a call to itself. A recursive struct is a struct that contains an instance of itself. You can combine the two as a recursive class. The key part of a recursive item is that it contains an instance/call of itself.
Consider two mirrors facing each other. We've seen the neat infinity effect they make. Each reflection is an instance of a mirror, which is contained within another instance of a mirror, etc. The mirror containing a reflection of itself is recursion.
A binary search tree is a good programming example of recursion. The structure is recursive with each Node containing 2 instances of a Node. Functions to work on a binary search tree are also recursive.
This is an old question, but I want to add an answer from logistical point of view (i.e not from algorithm correctness point of view or performance point of view).
I use Java for work, and Java doesn't support nested function. As such, if I want to do recursion, I might have to define an external function (which exists only because my code bumps against Java's bureaucratic rule), or I might have to refactor the code altogether (which I really hate to do).
Thus, I often avoid recursion, and use stack operation instead, because recursion itself is essentially a stack operation.
You want to use it anytime you have a tree structure. It is very useful in reading XML.
Recursion as it applies to programming is basically calling a function from inside its own definition (inside itself), with different parameters so as to accomplish a task.
"If I have a hammer, make everything look like a nail."
Recursion is a problem-solving strategy for huge problems, where at every step just, "turn 2 small things into one bigger thing," each time with the same hammer.
Example
Suppose your desk is covered with a disorganized mess of 1024 papers. How do you make one neat, clean stack of papers from the mess, using recursion?
Divide: Spread all the sheets out, so you have just one sheet in each "stack".
Conquer:
Go around, putting each sheet on top of one other sheet. You now have stacks of 2.
Go around, putting each 2-stack on top of another 2-stack. You now have stacks of 4.
Go around, putting each 4-stack on top of another 4-stack. You now have stacks of 8.
... on and on ...
You now have one huge stack of 1024 sheets!
Notice that this is pretty intuitive, aside from counting everything (which isn't strictly necessary). You might not go all the way down to 1-sheet stacks, in reality, but you could and it would still work. The important part is the hammer: With your arms, you can always put one stack on top of the other to make a bigger stack, and it doesn't matter (within reason) how big either stack is.
Recursion is the process where a method call iself to be able to perform a certain task. It reduces redundency of code. Most recurssive functions or methods must have a condifiton to break the recussive call i.e. stop it from calling itself if a condition is met - this prevents the creating of an infinite loop. Not all functions are suited to be used recursively.
hey, sorry if my opinion agrees with someone, I'm just trying to explain recursion in plain english.
suppose you have three managers - Jack, John and Morgan.
Jack manages 2 programmers, John - 3, and Morgan - 5.
you are going to give every manager 300$ and want to know what would it cost.
The answer is obvious - but what if 2 of Morgan-s employees are also managers?
HERE comes the recursion.
you start from the top of the hierarchy. the summery cost is 0$.
you start with Jack,
Then check if he has any managers as employees. if you find any of them are, check if they have any managers as employees and so on. Add 300$ to the summery cost every time you find a manager.
when you are finished with Jack, go to John, his employees and then to Morgan.
You'll never know, how much cycles will you go before getting an answer, though you know how many managers you have and how many Budget can you spend.
Recursion is a tree, with branches and leaves, called parents and children respectively.
When you use a recursion algorithm, you more or less consciously are building a tree from the data.
In plain English, recursion means to repeat someting again and again.
In programming one example is of calling the function within itself .
Look on the following example of calculating factorial of a number:
public int fact(int n)
{
if (n==0) return 1;
else return n*fact(n-1)
}
Any algorithm exhibits structural recursion on a datatype if basically consists of a switch-statement with a case for each case of the datatype.
for example, when you are working on a type
tree = null
| leaf(value:integer)
| node(left: tree, right:tree)
a structural recursive algorithm would have the form
function computeSomething(x : tree) =
if x is null: base case
if x is leaf: do something with x.value
if x is node: do something with x.left,
do something with x.right,
combine the results
this is really the most obvious way to write any algorith that works on a data structure.
now, when you look at the integers (well, the natural numbers) as defined using the Peano axioms
integer = 0 | succ(integer)
you see that a structural recursive algorithm on integers looks like this
function computeSomething(x : integer) =
if x is 0 : base case
if x is succ(prev) : do something with prev
the too-well-known factorial function is about the most trivial example of
this form.
function call itself or use its own definition.

Modular arithmetic: Division over factorials % Prime

I want to efficiently calculate ((X+Y)!/(X!Y!))% P (P is like 10^9+7)
This discussion gives some insights on distributing modulo over division.
My concern is it's not necessary that a modular inverse always exists for a number.
Basically, I am looking for a code implementation of solving the problem.
For multiplication it is very straightforward:
public static int mod_mul(int Z,int X,int Y,int P)
{
// Z=(X+Y) the factorial we need to calculate, P is the prime
long result = 1;
while(Z>1)
{
result = (result*Z)%P
Z--;
}
return result;
}
I also realize that many factors can get cancelled in the division (before taking modulus), but if the number of divisors increase, then I'm finding it difficult to efficiently come up with an algorithm to divide. ( Looping over List(factors(X)+factors(Y)...) to see which divides current multiplying factor of numerator).
Edit: I don't want to use BigInt solutions.
Is there any java/python based solution or any standard algorithm/library for cancellation of factors( if inverse option is not full-proof) or approaching this type of problem.
((X+Y)!/(X!Y!)) is a low-level way of spelling a binomial coefficient ((X+Y)-choose-X). And while you didn't say so in your question, a comment in your code implies that P is prime. Put those two together, and Lucas's theorem applies directly: http://en.wikipedia.org/wiki/Lucas%27_theorem.
That gives a very simple algorithm based on the base-P representations of X+Y and X. Whether BigInts are required is impossible to guess because you didn't give any bounds on your arguments, beyond that they're ints. Note that your sample mod_mul code may not work at all if, e.g., P is greater than the square root of the maximum int (because result * Z may overflow then).
It's binomial coefficients - C(x+y,x).
You can calculate it differently C(n,m)=C(n-1,m)+C(n-1,m-1).
If you are OK with time complexity O(x*y), the code will be much simpler.
http://en.wikipedia.org/wiki/Combination
for what you need here is a way to do it efficiently : -
C(n,k) = C(n-1,k) + C(n-1,k-1)
Use dynamic programming to calculate efficient in bottom up approach
C(n,k)%P = ((C(n-1,k))%P + (C(n-1,k-1))%P)%P
Therefore F(n,k) = (F(n-1,k)+F(n-1,k-1))%P
Another faster approach : -
C(n,k) = C(n-1,k-1)*n/k
F(n,k) = ((F(n-1,k-1)*n)%P*inv(k)%P)%P
inv(k)%P means modular inverse of k.
Note:- Try to evaluate C(n,n-k) if (n-k<k) because nC(n-k) = nCk

Chosing right algorithm between O(n) and O(n^2) when constants are unknown

I have given run-time functions for two algorithms solving the same problem. Let's say -
For First algorithm : T(n) = an + b (Linear in n)
For second Algorithm: T(n) = xn^2 + yn + z (Quadratic in n)
Every book says linear in time is better than quadratic and of course it is for bigger n (how big?). I feel definition of Big changes based on the constants a, b, x, y and z.
Could you please let me know how to find the threshold for n when we should switch to algo1 from algo2 and vice-versa (is it found only through experiments?). I would be grateful if someone can explain how it is done in professional software development organizations.
I hope I am able to explain my question if not please let me know.
Thanks in advance for your help.
P.S. - The implementation would be in Java and expected to run on various platforms. I find it extremely hard to estimate the constants a, b, x, y and z mathematically. How do we solve this dilemma in professional software development?
I would always use the O(n) one, for smaller n it might be slower, but n is small anyway. The added complexity in your code will make it harder to debug and maintain if it's trying to choose the optimal algorithm for each dataset.
It is impossible to estimate the fixed factors in all cases of practical interest. Even if you could, it would not help unless you could also predict how the size of the input is going to evolve in the future.
The linear algorithm should always be preferred unless other factors come into play as well (e.g. memory consumption). If the practical performance is not acceptable you can then look for alternatives.
Experiment. I also encountered a situation in which we had code to find a particular instance in a list of instances. The original code did a simple loop, which worked well for several years.
Once, one of our customers logged a performance problem. In his case the list contained several thousands of instances and the lookup was really slow.
The solution of my fellow developer was to add hashing to the list, which indeed solved the customer's problem. However, now other customers started to complain because they suddenly had a performance problem. It seemed that in most cases, the list only contained a few (around 10) entries, and the hashing was much slower than just looping over the list.
The final solution was to measure the time of both alternatives (looping vs. hashing) and determining the point at which the looping become slower than hashing. In our case this was about 70. So we changed the algorithm:
If the list contains less than 70 items we loop
If the list contains more then 70 items we hash
The solution will probably be similar in your case.
You are asking a maths question, not a programming one.
NB I am going to assume x is positive...
You need to know when
an+b < xn^2 + yn + z
ie
0 < xn^2 + (y-a)n + (z-b)
You can plug this into the standard equation for solving quadratics http://en.wikipedia.org/wiki/Quadratic_equation#Quadratic_formula
And take the larger 0, and then you know for all values greater than this (as x positive) O(n^2) is greater.
You end up with a horrible equation involving x, y, a, z, and b that I very much doubt is any use to you.
Just profile the code with the expected inputs size, it's even better if you also add in a worst case input. Don't waste your time solving the equation, which might be impossible to derive in the first place.
Generally, you can expect O(n2) to be significantly slower than O(n) from size of n = 10000. Significantly slower means that any human can notice it is slower. Depending on the complexity of the algorithm, you might notice the difference at smaller n.
The point is: judging an algorithm based on time complexity allows us to ignore some algorithms that is clearly too slow for any input at the largest input size. However, depending on the domain of the input data, certain algorithm with higher complexity will practically outperform other algorithm with lower time complexity.
When we write an algorithm for a large scale purpose, we want it to perform good for large 'n'. In your case, depending upon a, b, x, y and z, the second algorithm may perform better though its quadratic. But no matter what the values of a, b, x, y and z are, there would be some lower limit of n (say n0) beyond which first algo (linear one) will always be faster than the second.
If f(n) = O(g(n))
then it means for some value of n >= n0 (constant)
f(n) <= c1*g(n)
So
if g(n) = n,
then f(n) = O(n)
So choose the algo depending upon you usage of n

Which is the best way to implement prime number finding algorithms in Java? How do we make library classes and use then in Java?

I want to make library classes in Java and use them in my future programs. I want these library classes to find prime numbers upto a certain number or even the next prime number or you can say solve most of the basic things related to prime numbers.
I have never made a Java Library Class. I aim to learn that doing this. Please help me without that by pointing out a tutorial or something. I am familiar with netbeans IDE.
I found out a few algorithms like Sieve of Eratosthenes and Sieve of Atkin. It would be great if you can point out a few more such efficient algorithms. I don't want them to be the best but at least good enough. My aim is to learn few things by implementing them. Because I have little practical coding experience I want to do it to improve my skills.
My friend suggested me to use Stream Classes and he was talking something about implementing it by giving the output of one file as an input to another to make my code clean. I didn't understand him very well. Please pardon me if i said anything wrong. What I want to ask in this point is, is that an efficient and OO way of doing what i want to do. If yes please tell me how to do that and if not please point out some other way to do it.
I have basic knowledge of the Java language. What I want to accomplish through this venture is gain coding experience because that is what everyone out here suggested, "to take up small things like these and learn on my own"
thanks to all of you in advance
regards
shahensha
EDIT:
In the Sieve of Eratosthenes and others we are required to store the numbers from 2 to n in a data structure. Where should I store it? I know I can use a dynamic Collection, but just a small question...If i want to find primes in the order of billions or even more (I will use Big Integer no doubt), but all this will get stored in the heap right? Is there a fear of overflow? Even if it doesn't will it be a good practice? Or would it be better to store the numbers or the list (on which we will perform actions depending on the algorithm we use) in a file and access it there? Sorry if my question was too noobish...
"Sieve of Eratosthenes" is good algorithm to find the prime numbers. If you will use google you can find ready implementation in java.
I'll add some thoughts to this:
There's nothing technically different about a Library Class, it's simply how you use it. To my mind, the most important thing is that you think hard about your public API. Make it bit enough to be useful to your prospective callers, keep it small enough that you have freedom to change the internal implementation as you see fit, and ensure that you have a good understanding of what your library does do and what it doesn't do. Don't try to do everything, just do one thing well. (And the API generally extends to documentation too, make sure you write decent Javadocs.)
Start with either of these as they are fine. If you design your API well, you can change this at any time and roll out version 1.1 that uses a different algorithm (or even uses JNI to call a native C library), and your callers can just drop in the new JAR and use your code without even recompiling. Don't forget that premature optimisation is the root of all evil; don't worry to much about making your first version fast, but focus on making it correct and making it clean.
I'm not sure why your friend was suggesting streams. Streams are a way of dealing with input and output of raw bytes - useful when reading from files or network connections, but generally not a good way to call another Java method. Your library shouldn't worry about input and output, it just needs to offer some methods for numerical calculations. So you should implement methods that take integers (or whatever is appropriate) and return integers.
For instance, you might implement:
/**
* Calculates the next prime number after a given point.
*
* Implementation detail: callers may assume that prime numbers are
* calculated deterministically, such that the efficiency of calling
* this method with a large parameter is not dramatically worse than
* calling it with a small parameter.
*
* #param x The lower bound (exclusive) of the prime number to return.
* Must be strictly positive.
* #return Colloquially, the "next" prime number after the given parameter.
* More formally, this number will be prime and there are no prime numbers
* less than this value and greater than <code>x</code> that are also
* prime.
* #throws IllegalArgumentException if <code>x</code> is not strictly
* positive.
*/
public long smallestPrimeGreaterThan(long x);
/**
* Returns all prime numbers within a given range, in order.
*
* #param lowerBound The lower bound (exclusive) of the range.
* #param upperBound The upper bound (exclusive) of the range.
* #return A List of the prime numbers that are strictly between the
* given parameters. This list is in ascending order. The returned
* value is never null; if no prime numbers exist within the given
* range, then an empty list is returned.
*/
public List<Long> primeNumbersBetween(long lowerBound, long upperBound);
No streams in sight! Uses of streams, such as outputting to the console, should be handled by applications that use your library and not by your library itself. This is what I meant in my first point about being clear of what your library does and doesn't do. You just generate the prime numbers; it's up to the caller to then do something cool with them.
But when you compare, the sieve of Atkin is faster than the sieve of Eratosthenes:
http://en.wikipedia.org/wiki/Prime_number_counting_function Also refer to this link where different functions are explained clearly :)
Good luck..
There is no such thing as "library class". I suppose you mean to make a class in such a way that does it's job in a reusable way. The way to do this is to have a clean interface - with minimal (if any) bindings to other libraries or to your execution environment (your main class etc).
The two you mention are "good enough". For your purpose you don't need to look any further.
Just read from System.in and write to System.out and that's it. Though, in your case, there is nothing to read.
To achieve what I think is your goal, you need to write a main class that hadles the execution environment - main function, initialize your algorithm, iteratively look for the next prime, and write it to System.out. Of course, you'll need another class to implement the algorithm. It should contain the internal state and provide a method for finding the next prime.
`IMO, keep aside the thought that you're making a library (.jar file according to my interpretation of this question).
Focus on creating a simple Java class first, like this:
//SieveOfEratosthenes.java
public class PrimeSieve{
public static void main(String args[])
{
int N = Integer.parseInt(args[0]);
// initially assume all integers are prime
boolean[] isPrime = new boolean[N + 1];
for (int i = 2; i <= N; i++) {
isPrime[i] = true;
}
// mark non-primes <= N using Sieve of Eratosthenes
for (int i = 2; i*i <= N; i++) {
// if i is prime, then mark multiples of i as nonprime
// suffices to consider mutiples i, i+1, ..., N/i
if (isPrime[i]) {
for (int j = i; i*j <= N; j++) {
isPrime[i*j] = false;
}
}
}
// count primes
int primes = 0;
for (int i = 2; i <= N; i++) {
if (isPrime[i]) primes++;
}
System.out.println("The number of primes <= " + N + " is " + primes);
}
}
Now, the next step; Implementing it for larger values, you can always use BigInteger. SO questions pertaining to the same:
Java BigInteger Prime numbers
Problems with java.math.BigInteger
BigNums Implementation
Try reading all questions related to BigInteger class on SO, BigInteger Tagged questions.
Hope this helps.

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