view jar file through java code - java

I want to create one java application that will iterate an jar file and will give classes of that jar file.
I searched a lot but didn't get sufficient information.
I want java code that will open the jar file and will able to iterate that jar.

See:
java.util.jar.JarFile.entries()
http://docs.oracle.com/javase/6/docs/api/java/util/jar/JarFile.html#entries%28%29

Related

Can i write file located at classpath

I want to write a text file at classpath. want to make some changes in that file.
this is spring boot application and packaging it as a jar. So basically this text file is located in jar & I want to make changes to that file.
Don't know it is possible or not.
but please suggest to me how I can do that?
Files inside a jar can be read from (called resource files in general).
You cannot modify them directly though. For that, you need them to be outside the jar.
Possible duplicate of Updating resource files at runtime
If it is a .properties file though, there are ways to do it.
Following blog seems helpful (https://crunchify.com/java-properties-files-how-to-update-config-properties-file-in-java/)

Open Source Jar file and Failed to load Main-Class manifest

I downloaded an Open Source tool from www.openempi.org used to find duplicate patients. It is referred to as an EMPI tool (Enterprise Master Patient Index). I am a .Net programmer and not a Java programmer, but I have worked with other Java products where I receive a Jar file and run it like a Windows executable.
The zip file contained several Jar files but when I double-click on them I get Failed to load Main-Class manifest from.... After I Googled this term and reading a few posts about it, including several on this site, this seems to indicate that I should have done something different when creating the Jar file, but I didn't create the Jar file. Will I need to use Eclipse or some other tool to get past this, or is there something I'm doing wrong when try to load the Jar? Could it be a Java version issue?
The zip also contained a ./conf folder with several XML, CSV, and SQL files.
Greg
I don't think you want to execute the .jars found in that .zip file. Instead, you should try using the Application.html found after extracting from the openempi-webapp-web-versionhere.war.

Java Game refering to files

I have started getting into game programming.
My question is, that when I am working with files, either parsing data, writing to files, etc. Should I be using relative path names, or absolute pathnames, or something else which is better. I've heard about using jar files, but I am not sure
1. how that works
2. if it is a good way to do it.
So when developing a game that will be cross platform, what is the best method for managing files that the program will need to read from and write to.
there are several ways in which you can ship your code as a product. the most common are
packaging everything in one executable jar file.
having a set of folders where you place all necessary resources.
minecraft, for example, is written in java and distributed as a single executable jar file that contains all necessary class files and resources. to run the game (assuming you have java installed) all you need to do is double-click the jar file.
read this short tutorial about how to add a main class to a jar file.
either way, always treat classes and resources in your code as if they're in your classpath. for example, if you have a my.properties file on the root of the source tree then load it by using 'my.properties'. if you put it under a 'conf' folder then use 'conf/my.properties'.
i think it is the safest way not to get lost.
are you using maven?
The jar file is a zip of all your compiled *.class files and your resources. You can safely load your resources and even default data FROM a jar if you package your program, but you can NOT safely write data back to the jar. This detail is answered in depth already at
How can an app use files inside the JAR for read and write?
For information on how to package a jar see
http://docs.oracle.com/javase/tutorial/deployment/jar/

how to use a .so and .jar in a java android projet?

I'm working on a java android project. this project requires to use specific commands.
these commands are all developed in c++/c but I've been given two files (.jar and .so) that are supposed to "turn them into" java, so I can use them in my java android project.
The thing is, what am I supposed to do with these 2 files?? I've read a lot of stuff (mostly about creating the .jar and .so, but I don't care about this step, for I already have the 2 files)
I tried to import the .jar (import external lib), I tried to add the .so via the static loading :
//static {
// System.loadLibrary("MySoFile");
// }
All I get is a stack overflow error or a problem with the DEX file...
Has anybody ever tried to do this??
I don't seem to get the point here...all I want to do is being able to use the commands in the .jar file.... ://
thanks in advance!!
Take a look at this answer about adding jar files. '.so' files can usually just be drag and dropped to the project.
All you need to do is make sure the jar is in your classpath and you can then access the classes within this jar. A jar is just an archive of classes, you don't need to load the library into memory or something similar.
You may want to read the answer to the question here How to use classes from .jar files?

Modifying a file inside a jar

I would like to modify a file inside my jar. Is it possible to do this without extracting and re jarring, from within my application?
File i want to modify are configuration files, mostly xml based.
The reason i am interested in not un jarring is that the application is wrapped with launch4j if i unjar it i can't create the .exe file again.
You can use the u option for jar
From the Java Tutorials:
jar uf jar-file input-file(s)
"Any files already in the archive having the same pathname as a file being added will be overwritten."
See Updating a JAR File.
Much better than making the whole jar all over again. Invoking this from within your program sounds possible too. Try Running Command Line in Java
You can use Vim:
vim my.jar
Vim is able to edit compressed text files, given you have unzip in your environment.
Java jar files are the same format as zip files - so if you have a zip file utility that would let you modify an archive, you have your foot in the door. Second problem is, if you want to recompile a class or something, you probably will just have to re-build the jar; but a text file or something (xml, for instance) should be easily enough modified.
As many have said, you can't change a file in a JAR without recanning the JAR. It's even worse with Launch4J, you have to rebuild the EXE once you change the JAR. So don't go this route.
It's generally bad idea to put configuration files in the JAR. Here is my suggestion. Search for your configuration file in some pre-determined locations (like home directory, \Program Files\ etc). If you find a configuration file, use it. Otherwise, use the one in the JAR as fallback. If you do this, you just need to write the configuration file in the pre-determined location and the program will pick it up.
Another benefit of this approach is that the modified configuration file doesn't get overwritten if you upgrade your software.
Not sure if this help, but you can edit without extracting:
Open the jar file from vi editor
Select the file you want to edit from the list
Press enter to open the file do the changers and save it
pretty simple
Check the blog post for more details
http://vinurip.blogspot.com/2015/04/how-to-edit-contents-of-jar-file-on-mac.html
I have similar issue where I need to modify/update a xml file inside a jar file.
The jar file is created by a Spring-boot application and the location of the file is BOOT-INF/classes/properties
I was referring this document and trying to replace/update the file with this command:
jar uf myapp.jar BOOT-INF/classes/properties/test.xml
But with this, it wont change the file at the given location. I tried all the options also but wont work.
Note: The command I am executing from the location where jar file is present.
The solution I found is:
From the current location of jar file, I created folders BOOT-INF/classes/properties
Copy the test.xml file into the location BOOT-INF/classes/properties.
Run the same command again. jar uf myapp.jar BOOT-INF/classes/properties/test.xml
The xml file has been changed in the jar file.
Basically you need to create a folder structure like where the file is located into the jar file. Copy the file at that location and then execute the command.
The problem with the documentation is that, it does not have enough examples as well as explanation around common scenarios.
This may be more work than you're looking to deal with in the short term, but I suspect in the long term it would be very beneficial for you to look into using Ant (or Maven, or even Bazel) instead of building jar's manually. That way you can just click on the ant file (if you use Eclipse) and rebuild the jar.
Alternatively, you may want to actually not have these config files in the jar at all - if you're expecting to need to replace these files regularly, or if it's supposed to be distributed to multiple parties, the config file should not be part of the jar at all.
To expand on what dfa said, the reason is because the jar file is set up like a zip file. If you want to modify the file, you must read out all of the entries, modify the one you want to change, and then write the entries back into the jar file. I have had to do this before, and that was the only way I could find to do it.
EDIT
Note that this is using the internal to Java jar file editors, which are file streams. I am sure there is a way to do it, you could read the entire jar into memory, modify everything, then write back out to a file stream. That is what I believe utilities like 7-Zip and others are doing, as I believe the ToC of a zip header has to be defined at write time. However, I could be wrong.
Yes you can, using SQLite you can read from or write to a database from within the jar file, so that you won't have to extract and then re jar it, follow my post http://shoaibinamdar.in/blog/?p=313
using the syntax "jdbc:sqlite::resource:" you would be able to read and write to a database from within the jar file
Check out TrueZip.
It does exactly what you want (to edit files inline inside a jar file), through a virtual file system API. It also supports nested archives (jar inside a jar) as well.
Extract jar file for ex. with winrar and use CAVAJ:
Cavaj Java Decompiler is a graphical freeware utility that reconstructs Java source code from CLASS files.
here is video tutorial if you need:
https://www.youtube.com/watch?v=ByLUeem7680
The simplest way I've found to do this in Windows is with WinRAR:
Right-click on the file and choose "Open with WinRAR" from the context menu.
Navigate to the file to be edited and double-click on it to open it in the default editor.
After making the changes, save and exit the editor.
A dialogue will then appear asking if you wish to update the file in the archive - choose "Yes" and the JAR will be updated.
most of the answers above saying you can't do it for class file.
Even if you want to update class file you can do that also.
All you need to do is that drag and drop the class file from your workspace in the jar.
In case you want to verify your changes in class file , you can do it using a decompiler like jd-gui.
As long as this file isn't .class, i.e. resource file or manifest file - you can.

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