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How to make while loop check if there are 16 digits in a string

How do I make the loop check if there is 16 digits in a string and reset the string if there is not enough. I am trying to make a credit card program that will calculate the check digit. I have everything else working I just cant get the program to check the number of digits in the user inputted string.Thanks for any and all help!
import java.util.Scanner;
public class LuhnAlgorithm {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("Enter a number credit card number (Enter a blank line to quit: ");
String nums = input.nextLine();
int i = 0;
char chk = nums.charAt(15);
while(!nums .equals("") ) {
if (nums.length()<16 || nums.length() > 15){ //How do I get this line to reset the while loop?
System.out.println("ERROR! Number MUST have exactly 16 digits.");
}
int sum = 0;
for( i = 0; i < 15; i++) {
char numc = nums.charAt(i);
int num = Character.getNumericValue(numc);
if ( i % 2 == 0 ) {
num = num * 2;
if ( num >= 10) {
num = num - 9;
}
}
sum = num + sum;
}
int sum2 = sum % 10;
if (sum2 > 0) {
sum2 = 10 - sum2;
}
int chk2 = Character.getNumericValue(chk);
System.out.println("The check digit should be: " + sum2);
System.out.println("The check digit is: " + chk);
if ( sum2 == chk2) {
System.out.println("Number is valid.");
}
else {
System.out.println("Number is not valid. ");
}
System.out.print("Enter a number credit card number (Enter a blank line to quit:) ");
nums = input.nextLine();
}
System.out.println("Goodbye!");
input.close();
}
}

You can include your code that you only want done if the length ==16 in an if statement.
Meaning, instead of:
if (nums.length != 16) {
//code if there is an error
}
//code if there is no error
you can do:
if (nums.length == 16) {
//code if there is no error
} else {
//code if there is an error
}
(I also want to point out that you set chk = nums.charAt(15) before your while loop, but you don't reset it in the while loop for the next time the user inputs a new credit card number.)

You can bring the prompts and all your initialization except the scanner itself into the while loop. Then if they say "", break to exit the loop. If they say a number that is too short or too long, say continue to go back to the prompting.
Thus:
import java.util.Scanner;
public class main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
while (true) {
System.out.print("Enter a number credit card number (Enter a blank line to quit: ");
String nums = input.nextLine().trim();
if (nums.length() == 0) {
break; //exits while loop
}
if (nums.length() != 16) { //How do I get this line to reset the while loop?
System.out.println("ERROR! Number MUST have exactly 16 digits.");
continue; //goes back to the beginning right away
}
//still here, process the number
char chk = nums.charAt(15);
int sum = 0;
for (int i = 0; i < 15; i++) {
char numc = nums.charAt(i);
int num = Character.getNumericValue(numc);
if (i % 2 == 0) {
num = num * 2;
if (num >= 10) {
num = num - 9;
}
}
sum = num + sum;
}
int sum2 = sum % 10;
if (sum2 > 0) {
sum2 = 10 - sum2;
}
int chk2 = Character.getNumericValue(chk);
System.out.println("The check digit should be: " + sum2);
System.out.println("The check digit is: " + chk);
if (sum2 == chk2) {
System.out.println("Number is valid.");
} else {
System.out.println("Number is not valid. ");
}
}
System.out.println("Goodbye!");
input.close();
}
}

Java loop until user enters a value of 0. The values must be between 1-4 and if over 4, ask user to try inputting again

I need to create a loop where the user can input any amount of numbers between 1-4 and then I calculate the average. Typing 0 will end the program and calculate the average. Any value greater than 4 or less than 0 should not count and ask the user to input the value again. I'm stuck on the last part. I'm not sure if the while loop is the correct loop to use either. Thanks for any help
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
double sum = 0;
double count = 0;
while(input.hasNextInt()) {
int num = input.nextInt();
if (num == 0)
break;
if (num > 4)
System.out.println("Invalid number");
sum += num;
count += 1;
}
System.out.println("Average: " + sum/count);
}

You will always hit the lines:
sum += num;
count += 1;
Because the code just drops through from the second if statement.
The following would work - note the else if and else blocks will only be executed when the first if drops through:
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
double sum = 0;
double count = 0;
while(input.hasNextInt()) {
int num = input.nextInt();
if (num == 0) {
break;
}
else if (num > 4) {
System.out.println("Invalid number");
}
else {
sum += num;
count += 1;
}
}
System.out.println("Average: " + sum/count);
}

Why does my code not run?

I have this code:
import java.util.Scanner;
public class PositiveNegative { public static void main(String[] args) {
int numbers, plus = 0, minus = 0;
int count = 0;
double total = 0;
Scanner scan = new Scanner(System.in);
System.out.print("Enter an integer (0 to quit): ");
numbers = scan.nextInt();
while(numbers != 0)
{
total += numbers;
if(numbers > 0)
plus++;
if(numbers < 0)
minus++;
}
System.out.println("The number of positives is: " +plus);
System.out.println("The number of negatives is: " +minus);
System.out.println("The number of total is: " +total);
}
}
The problem with is that I try to run it and type the numbers but it does nothing. I want it so that when you type 0 it stops taking numbers and starts processing the code. What should I do?

Try this:
import java.util.Scanner;
public class PositiveNegative {
public static void main(String[] args) {
int numbers = 0, plus = 0, minus = 0;
double total = 0;
do{
Scanner scan = new Scanner(System.in);
System.out.print("Enter an integer (0 to quit): ");
numbers = Integer.valueOf(scan.nextLine());
total += numbers;
if (numbers > 0)
plus++;
if (numbers < 0)
minus++;
}
while (numbers != 0);
System.out.println("The number of positives is: " + plus);
System.out.println("The number of negatives is: " + minus);
System.out.println("The number of total is: " + total);
}
}
Put your Scanner in the while loop so that everytime loop start it will ask for User input.

You need to update numbers or your loop will run for ever. And I recommend using braces (and an else). Something like,
System.out.print("Enter an integer (0 to quit): ");
numbers = scan.nextInt();
while (numbers != 0) {
total += numbers;
if (numbers > 0) {
plus++;
} else if (numbers < 0) {
minus++;
}
System.out.print("Enter an integer (0 to quit): ");
numbers = scan.nextInt();
}
Alternatively, you could use a do-while loop. Then you only need one copy of the prompt. Like,
do {
System.out.print("Enter an integer (0 to quit): ");
numbers = scan.nextInt();
total += numbers;
if (numbers > 0) {
plus++;
} else if (numbers < 0) {
minus++;
}
} while (numbers != 0);

You have to modify numbers each time to make it work in your while.
So, in your existing code, just comment out numbers = scan.nextInt(); and use below--
// numbers = scan.nextInt(); //comment out this call
while ((numbers = scan.nextInt()) != 0) {
....
this will give you desired output--
Enter an integer (0 to quit): 9
4
-9
1
0
The number of positives is: 3
The number of negatives is: 1
The number of total is: 5.0

How would I correctly nest the if else statement? for the sum?

import java.util.Scanner;
public class DivisibleBy6or17 {
public static void main(String[] args) {
Scanner kbd = new Scanner (System.in);
System.out.print("How many Values To Read ? ");
int amount = kbd.nextInt();
int[] values = new int[amount];
int i = 0;
double divisible = 0;
int count = 0;
while (i < amount) {
System.out.print("Enter Value : ");
int nbr = kbd.nextInt();
if (nbr %6 == 0 || nbr % 17 == 0) {
divisible += nbr;
count++;
}
i++;
}
if (divisible == 0) {
System.out.print("NONE DIVISIBLE");
}
else {
System.out.print("Average: " + divisible/count);
}
}
}
so I want the sum of the numbers divisible by 16 or 17 so could I insert an if else for the sum then do the else for the average? I do not know where to insert the nested if statement for the sum

System.out.println(divisible); would print out the sum since you are just adding them all to that variable.
Please refer to my answer in https://stackoverflow.com/questions/28569527/how-would-i-manipulate-the-code-below-to-get-the-following-output/28570034#28570034

Trying to add sum of all even integers between 2 and the input, and I just get the input back

I'm attempting to write something for an assignment that takes the sum of all the even integers between 2 and the number entered by the user and prints it. If it is below 2 it should return an error. I'm getting an error for anything under 2, however, when I go have it return the sum it just returns the input.
I think I may have messed a variable up in this loop, but I can't see where I went wrong.
import java.util.Scanner;
public class EvenSum {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter a number larger than 2");
int num = input.nextInt();
if (num >= 2) {
int sum = 0;
for (int i = 2; i <= num; i +=2) {
sum += i;
}
System.out.println("The sum of all even numbers between 2 and the input is " + num);
} else {
System.out.println("Invalid, please enter a number above 2");
}
}
}

System.out.println("The sum of all even numbers between 2 and the input is " + num);
should be
System.out.println("The sum of all even numbers between 2 and the input is " + sum);
There is a formula to compute the answer without a loop, by the way. But perhaps that is not the point of the exercise?

It's because you return num instead of sum

Declare sum outside if statement, and print sum instead of num
package com.test;
import java.util.Scanner;
public class EvenSum {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Enter a number larger than 2");
int num = input.nextInt();
int sum = 0;
if (num >= 2) {
for (int i = 2; i <= num; i += 2) {
sum += i;
}
System.out
.println("The sum of all even numbers between 2 and the input is "
+ sum);
} else {
System.out.println("Invalid, please enter a number above 2");
}
}
}