I need to extract a randomly generated part of an URL for a Selenium Test in Java.
When the browser opens a page, e.g.:
/edit_person.html?id=eb58cea3a3772ff656987792eb0a8c0f
then I'm able to show the url with:
String url = driver.getCurrentUrl();
but now I need to get only the randomly generated ID after the equals sign.
How do I extract the value of parameter id once I have the entire URL as a string in variable url?
URL.getQuery() will give the query portion as a String it is a simple regular expression match to isolate the part you want.
id=(.*) will get you what you want as long as it is the only thing in the query string.
This is how managed to solve the problem:
String url = driver.getCurrentUrl();
URL aURL = new URL(url);
url = aURL.getQuery();
String[] id = url.split("=");
System.out.println(id[1]);
Thanks to Jarrod Roberson!
Related
I have a URL with some dynamic parts
https://{env}-my-website.{domain}/UnDefault.aspx
And every time I want to go to another module I have to replace this part
UnDefault.aspx
with the module to which I want to navigate e.g.
Modules/Repairs/SNH.aspx
Is there an easy way to do that with Selenium or Regex?
this is what i tried :
String currentUrl = driver.getCurrentUrl();
String[] results = StringUtils.substringsBetween(currentUrl, "https", "?:cn|com");
String SNH= results[0]+"Modules/Repairs/SNH.aspx";
driver.navigate().to(SNH);
To replace the path part of the url (everything after the server):
String url = url.replaceAll("^(.*?//[^/]+/).*", "$1Modules/Repairs/SNH.aspx");
original url : http://pricecheckindia.com/go/store/ebay/52440?ref=velusliv
redirected url : http://www.ebay.in/itm/Asus-Zenfone-6-A600CG-A601CG-White-16-GB-/111471688863?pt=IN_Mobile_Phones&aff_source=DA
I need a program that will take the original url and print the redirected url.
How to get this done in java.
public static void main(String[] args) throws IOException, InterruptedException
{
String url = "http://pricecheckindia.com/go/store/ebay/52440?ref=velusliv";
Response response = Jsoup.connect(url).followRedirects(false).execute();
System.out.println(response.url());
}
It seems that you are being redirected via JavaScript code, which Jsoup doesn't support (it is simple HTML parser, not browser emulator). Your choice then is to either use tool which will support JavaScript like Selenium web driver, or parse your page to get url from click here link from
If it is taking too long to redirect, then please click here
text.
You can use Jsoup to get this link by adding to your current code
Document doc = response.parse();
String redirectUrl = doc.select("a:contains(click here)").attr("href");
System.out.println(redirectUrl);
which will return and print
http://rover.ebay.com/rover/1/4686-127726-2357-15/2?&site=Partnership_PRCCHK&aff_source=DA&mpre=http%3A%2F%2Fwww.ebay.in%2Fitm%2FAsus-Zenfone-6-A600CG-A601CG-White-16-GB-%2F111471688863%3Fpt%3DIN_Mobile_Phones%26aff_source%3DDA
so now all we need to do is parse query from this URL to get value of mpre key, which encoded version looks like
http%3A%2F%2Fwww.ebay.in%2Fitm%2FAsus-Zenfone-6-A600CG-A601CG-White-16-GB-%2F111471688863%3Fpt%3DIN_Mobile_Phones%26aff_source%3DDA
but after decoding it will actually represents
http://www.ebay.in/itm/Asus-Zenfone-6-A600CG-A601CG-White-16-GB-/111471688863?pt=IN_Mobile_Phones&aff_source=DA
To get value of this key and decode it you can use one of solutions from this question: Parse a URI String into Name-Value Collection. With help of method from accepted answer in previously mentioned question we can just invoke
URL address = new URL(redirectUrl);
Map<String,List<String>> urlQuerryMap= splitQuery(address);
String redirected = urlQuerryMap.get("mpre").get(0);
System.out.println(redirected);
to see result
http://www.ebay.in/itm/Asus-Zenfone-6-A600CG-A601CG-White-16-GB-/111471688863?pt=IN_Mobile_Phones&aff_source=DA
I am trying to build a java program that downloads files, but i get and exemption every time.
java.net.MalformedURLException: no protocol
the code for the URL is
URL site;
String urlString = "http://www.cs.drexel.edu/~spiros/teaching/CS575/slides/java.pdf";
site = new URL("urlString");
I have also tried:
String urlString = "www.cs.drexel.edu/~spiros/teaching/CS575/slides/java.pdf";
i have tried printing urlString to the console, it is being set correctly to ether one accordingly in each test. What am i missing
This is wrong :
site = new URL("urlString");
Use the variable:
site = new URL(urlString);
"urlString" is a string literal for the literal value urlString.
That isn't a valid URL.
You probably want to reference the variable, not write a string literal.
I am trying to replace url with another url.
Below is the example of source url
http://sysserver01.internal.com/web/www/internal/projectwork/resources/injury-prevention-and-recovery/avoiding-injury/overview-of-running-injuries/
so this url should be replace with below url,
http://sysserver01.internal.com/var/www/html/injury-prevention-and-recovery/avoiding-injury/overview-of-running-injuries/
It means if source url comes then the part after resources in source url must be appended with /var/www/html/(and rest of part after resources in source url).
This needs to be happen with rendom set of source url that contains resources string.
I dont have enough knowldege of string manipulation. So please someone help me to solve this query. Please try to solve it in JAVA as I choose this platform for my work.
String originalUrl = "http://sysserver01.internal.com/web/www/internal/projectwork/resources/injury-prevention-and-recovery/avoiding-injury/overview-of-running-injuries";
String newUrl = originalUrl.replaceAll("web/www/internal/projectwork/resources", "var/www/html");
String originalUrl = "http://sysserver01.internal.com/web/www/internal/projectwork/resources/injury-prevention-and-recovery/avoiding-injury/overview-of-running-injuries";
String newUrl = originalUrl.replace("web/www/internal/projectwork/resources", "var/www/html");
I'm trying to make use of google api as text-to-speech. So, I build a String then should pass it as a URL to a component to obtain a MP3 with the spoken words.
So, this is my code:
URI uri = new URI("http://translate.google.com/translate_tts?tl=es&q="+ URLEncoder.encode((String)this.text.getValue(), "UTF-8"));
When I make uri.toString() its return a well formed URL. If I copy and paste this output in the browser works pefectly.
But if I assign this returned String to the source property of a ice:outputMedia is not working. Then inspect the HTML generated in the page and the String in src property is:
http://translate.google.com/translate_tts?tl=es&q=Bobby+need+peanuts
The & symbol has been replaced by &.
How can I avoid this to make a valid URL?
You need to decode the url on the client side using Javascript.
var decoded = decodeURI(URI)