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How to display json response from the stream to the console

I'm trying to access all the jira issues using the jira-rest-api url in the following way:
URL url;
url = new URL("http://ficcjira.xyz.com/rest/api/2/search?jql=project=ABC&fields=timespent");
URLConnection conn = url.openConnection();
String auth = "username" + ":" + "password";
byte[] authBytes = auth.getBytes(StandardCharsets.UTF_8);
String encodedAuth = Base64.getEncoder().encodeToString(authBytes);
conn.setRequestProperty("Authorization", "Basic " + encodedAuth);
try (InputStream responseStream = conn.getInputStream()) {
//JsonElement element = new JsonParser(stream).parse(responseStream);
// To read response as a string:
MimeType contentType = new MimeType(conn.getContentType());
String charset = contentType.getParameter("charset");
#SuppressWarnings("resource")
String response =
new Scanner(responseStream, charset).useDelimiter("\\Z").next();
I get a response from the url as a JSON response. What do I do next to display the response to the console?
UPDATE:
Geting Null pointer exception when trying to do System.out.printn(response);

System.out.println(response) : to print to console
And also you can avoid boilerplate code by using the libraries. For example, you can replace all your code with below single line.
String response = IOUtils.toString(new URL("http://ficcjira.xyz.com/rest/api/2/search?jql=project=ABC&fields=timespent"));
IOUtils is part of apache commons.

You can simply use a System.out.print(); of the string response you streammed

MailChimp Integration in Java

I want to integrate MailChimp API in my java project. When I call Rest call using HttpURLConnection class, it responds with 401 code.
Here is my code:
URL url = new URL("https://us13.api.mailchimp.com/3.0/lists");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Content-Type", "application/json");
conn.setRequestProperty("Authorization", "apikey <my-key>");
String input = "<json data>";
OutputStream os = conn.getOutputStream();
//os.write(input.getBytes());
os.flush();
if (conn.getResponseCode() != HttpURLConnection.HTTP_CREATED) {
throw new RuntimeException("Failed : HTTP error code : " + conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
String output;
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();

I will suggest using Apache Commons Codec package for encoding.
It support various formats such as Base64 and Hexadecimal.
Earlier I was also facing the same issue. I am sharing the code that I used in my application for authenticating to Mailchimp API v-3.0
//basic imports
import org.apache.commons.codec.binary.Base64;
.
.
.
//URL to access and Mailchimp API key
String url = "https://us9.api.mailchimp.com/3.0/lists/";
//mailchimp API key
String apikey = xxxxxxxxxxxxxxxxxxxxxxxxxxx
// Authentication PART
String name = "Anything over here!";
String password = apikey; //Mailchimp API key
String authString = name + ":" + password;
byte[] authEncBytes = Base64.encodeBase64(authString.getBytes());
String authStringEnc = new String(authEncBytes);
URL urlConnector = new URL(url);
HttpURLConnection httpConnection = (HttpURLConnection) urlConnector.openConnection();
httpConnection.setRequestMethod("GET");
httpConnection.setDoOutput(true);
httpConnection.setDoInput(true);
httpConnection.setRequestProperty("Content-Type", "application/json; charset=UTF-8");
httpConnection.setRequestProperty("Accept", "application/json");
httpConnection.setRequestProperty("Authorization", "Basic " + authStringEnc);
InputStream is1 = httpConnection.getInputStream();
StringBuilder sb = new StringBuilder();
BufferedReader br = new BufferedReader(new InputStreamReader(is1, "utf-8"));
String line = null;
while ((line = br.readLine()) != null) {
sb.append(line + "\n");
}
br.close();
Now you can use StringBuilder Object sb to parse the output as required
Hope it resolves your issue :)

HTTP 401 response code means "not authorized".
You didn't set or pass your credentials properly. Is the certificate from the client set up? Here's an example of an HTTPS client.

HTTP 401 simply means you're not Authorized to send this request.
you can set username any string (the MailChimp docs suggest using anystring as a username) and your API key as a password.
In case of Postman request, you can set under the Authorization tab choose Basic Auth to set username and password. Below image shows the same.
More info about Adding/ Getting Members to/ from a Mailing List on MailChimp API 3.0, I find this article very useful.

Java alternative for curl -T

i must send one text string using java to a IP web cam, before it take picture. So after I read the camera user manual and searched in google, the only thing i found was using cURL. I install it and its run fine, and everything is okay, the text from the file appear in the video streaming. The command is this
curl -T test.xml http://admin:pass#192.168.0.1/Video/inputs/channels/2/overlays/text/2
and the content of test.xml is:
<TextOverlay xmlns="http://www.hikvision.com/ver10/XMLSchema" version="1.0">
<id>2</id>
<enabled>true</enabled>
<posX>5</posX>
<posY>5</posY>
<message>Text here </message>
</TextOverlay>
So I want to send this content using Java, I already tried using post and java.net but I get an error "Server returned HTTP response code: 403 for URL"
Here is my code:
System.out.println("Starting......");
URL url = new URL("http://192.168.0.1/Video/inputs/channels/2/overlays/text/2/");
String data = "<TextOverlay xmlns=\"http://www.hikvision.com/ver10/XMLSchema\" version=\"1.0\">\n"
+ "<id>2</id>\n"
+ "<enabled>true</enabled>\n"
+ "<posX>5</posX>\n"
+ "<posY>5</posY>\n"
+ "<message>Text here</message>\n"
+ "</TextOverlay>";
HttpURLConnection httpConnection = prepareConn(url, null, "admin", "pass");
httpConnection.setDoOutput(true);
httpConnection.setDoInput(true);
httpConnection.setRequestMethod("POST");
httpConnection.setRequestProperty ( "Content-Type", "text/xml" );
OutputStreamWriter out = new OutputStreamWriter(httpConnection.getOutputStream());
out.write(data);
out.flush();
out.close();
System.out.println("Printing......");
System.out.println(httpConnection.getResponseCode());
System.out.println(httpConnection.getResponseMessage());
InputStreamReader reader = new InputStreamReader(httpConnection.getInputStream());
StringBuilder buf = new StringBuilder();
char[] cbuf = new char[2048];
int num;
while(-1 != (num = reader.read(cbuf)))
{
buf.append(cbuf, 0, num);
}
String result = buf.toString();
System.out.println("\nResponse received from server after POST" + result);
}
static private HttpURLConnection prepareConn(final URL url, Properties request_props, String username, String password) throws Error, IOException
{
System.out.println("Authorization......");
if (!url.getProtocol().equalsIgnoreCase("http"))
throw new Error(url.toString() + " is not HTTP!");
final HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setConnectTimeout(300);
conn.setRequestMethod("POST");
final Properties DEFAULT_REQUEST_PROPS = new Properties();
DEFAULT_REQUEST_PROPS.setProperty("charset", "utf-8");
final Properties props = new Properties(DEFAULT_REQUEST_PROPS);
if (request_props != null)
for (final String name : request_props.stringPropertyNames())
props.setProperty(name, request_props.getProperty(name));
for (final String name : props.stringPropertyNames())
conn.setRequestProperty(name, props.getProperty(name));
if(null != username && null != password)
conn.setRequestProperty("Authorization", "Basic " + new BASE64Encoder().encode((username+":"+password).getBytes()));
return conn;
}
Hope someone can help :)
All the best !

I just use wrong RequestMethod, after deep research I found that i must use PUT not POST request. Now just change setRequestMethod("POST") to setRequestMethod("PUT") and works like a charm.

HTTP Basic Authentication Java

I am trying to get content from the website Socialcast which needs authentication. (First I do a HTTP Post with Basic Authentication and then I try a HTTP GET).
I tried several codes, I receive this as "result":
emily#socialcast.com:demo
Base64 encoded auth string: ZW1pbHlAc29jaWFsY2FzdC5jb206ZGVtbw==
* BEGIN
You are being redirected.
END *
Here is the code for HTTP Basic Auth:
try {
String webPage = "http://demo.socialcast.com";
String name = "emily#socialcast.com";
String password = "demo";
String authString = name + ":" + password;
System.out.println("auth string: " + authString);
byte[] authEncBytes = Base64.encodeBase64(authString.getBytes());
String authStringEnc = new String(authEncBytes);
System.out.println("Base64 encoded auth string: " + authStringEnc);
URL url = new URL(webPage);
URLConnection urlConnection = url.openConnection();
urlConnection.setRequestProperty("Authorization", "Basic " + authStringEnc);
InputStream is = urlConnection.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
int numCharsRead;
char[] charArray = new char[1024];
StringBuffer sb = new StringBuffer();
while ((numCharsRead = isr.read(charArray)) > 0) {
sb.append(charArray, 0, numCharsRead);
}
String result = sb.toString();
System.out.println("*** BEGIN ***");
System.out.println(result);
System.out.println("*** END ***");
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
However, when I try to do a GET afterwards, it says unauthorized.
The credentials are emily#socialcast.com/demo - those are provided by Socialcast Dev at the moment, as I also cannot access my own Socialcast instance.
Is this code wrong? How can I do it properly? BTW, I am using HttpClient 4.x.

Are you sending the credentials in each request? I think this is needed, otherwise the server does not have any other information to prove that you still are authorized to view other pages...

I'm not sure why this question is tagged with apache-httpclient-4.x when your example code doesn't use it. In fact, if you do use httpclient then you can get it to handle authentication for you quite easily, see here for the excellent tutorial.

Adding header for HttpURLConnection

I'm trying to add header for my request using HttpUrlConnection but the method setRequestProperty() doesn't seem working. The server side doesn't receive any request with my header.
HttpURLConnection hc;
try {
String authorization = "";
URL address = new URL(url);
hc = (HttpURLConnection) address.openConnection();
hc.setDoOutput(true);
hc.setDoInput(true);
hc.setUseCaches(false);
if (username != null && password != null) {
authorization = username + ":" + password;
}
if (authorization != null) {
byte[] encodedBytes;
encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + encodedBytes;
hc.setRequestProperty("Authorization", authorization);
}

I have used the following code in the past and it had worked with basic authentication enabled in TomCat:
URL myURL = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)myURL.openConnection();
String userCredentials = "username:password";
String basicAuth = "Basic " + new String(Base64.getEncoder().encode(userCredentials.getBytes()));
myURLConnection.setRequestProperty ("Authorization", basicAuth);
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
myURLConnection.setRequestProperty("Content-Length", "" + postData.getBytes().length);
myURLConnection.setRequestProperty("Content-Language", "en-US");
myURLConnection.setUseCaches(false);
myURLConnection.setDoInput(true);
myURLConnection.setDoOutput(true);
You can try the above code. The code above is for POST, and you can modify it for GET

Just cause I don't see this bit of information in the answers above, the reason the code snippet originally posted doesn't work correctly is because the encodedBytes variable is a byte[] and not a String value. If you pass the byte[] to a new String() as below, the code snippet works perfectly.
encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + new String(encodedBytes);

If you are using Java 8, use the code below.
URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;
String basicAuth = Base64.getEncoder().encodeToString((username+":"+password).getBytes(StandardCharsets.UTF_8));
httpConn.setRequestProperty ("Authorization", "Basic "+basicAuth);

Finally this worked for me
private String buildBasicAuthorizationString(String username, String password) {
String credentials = username + ":" + password;
return "Basic " + new String(Base64.encode(credentials.getBytes(), Base64.NO_WRAP));
}

Your code is fine.You can also use the same thing in this way.
public static String getResponseFromJsonURL(String url) {
String jsonResponse = null;
if (CommonUtility.isNotEmpty(url)) {
try {
/************** For getting response from HTTP URL start ***************/
URL object = new URL(url);
HttpURLConnection connection = (HttpURLConnection) object
.openConnection();
// int timeOut = connection.getReadTimeout();
connection.setReadTimeout(60 * 1000);
connection.setConnectTimeout(60 * 1000);
String authorization="xyz:xyz$123";
String encodedAuth="Basic "+Base64.encode(authorization.getBytes());
connection.setRequestProperty("Authorization", encodedAuth);
int responseCode = connection.getResponseCode();
//String responseMsg = connection.getResponseMessage();
if (responseCode == 200) {
InputStream inputStr = connection.getInputStream();
String encoding = connection.getContentEncoding() == null ? "UTF-8"
: connection.getContentEncoding();
jsonResponse = IOUtils.toString(inputStr, encoding);
/************** For getting response from HTTP URL end ***************/
}
} catch (Exception e) {
e.printStackTrace();
}
}
return jsonResponse;
}
Its Return response code 200 if authorizationis success

With RestAssurd you can also do the following:
String path = baseApiUrl; //This is the base url of the API tested
URL url = new URL(path);
given(). //Rest Assured syntax
contentType("application/json"). //API content type
given().header("headerName", "headerValue"). //Some API contains headers to run with the API
when().
get(url).
then().
statusCode(200); //Assert that the response is 200 - OK

It work for me.
I had to send request to another hand, and transfer header "Authorization" + jwt and some params via POST. By another side we formed jettyRequest with params and headers. If I send this sequence of code:
URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
// some code add params
then I received only params in a body.
If I send this:
URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
myURLConnection.setRequestMethod("POST");
// some code add params
then I received headers Authorization and params.

Step 1: Get HttpURLConnection object
URL url = new URL(urlToConnect);
HttpURLConnection httpUrlConnection = (HttpURLConnection) url.openConnection();
Step 2: Add headers to the HttpURLConnection using setRequestProperty method.
Map<String, String> headers = new HashMap<>();
headers.put("X-CSRF-Token", "fetch");
headers.put("content-type", "application/json");
for (String headerKey : headers.keySet()) {
httpUrlConnection.setRequestProperty(headerKey, headers.get(headerKey));
}
Reference link