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How to get an HashMap<String,ArrayList<String>> from a given String Java

So I receive a String that contains a HashMap<String, ArrayList<String>> inside how do I debunk it till I get myself a new HashMap from that String.
This is the string :
String s= "{Lobby1=[John, Ana], Lobby2=[Tomas, Peter]}"
Keep in mind the string can be longer depending on the number of entries or puts
This is what i did to get ride of the "{ }":
s=s.substring(1,s.length()-1);
This gets me :
Lobby1=[John, Ana], Lobby2=[Tomas, Peter]
I don't know what to do now, how do I get an Arraylist and a String from that.

How about something like that:
private static final Pattern RE = Pattern.compile("^\\s*([^=\\[\\]]+)\\s*=\\s*\\[([^\\]]*)\\]\\s*(?:,(.*))?$");
public static void main(String args[]) {
String s = "Lobby1=[John, Ana], Lobby2=[Tomas, Peter]";
Map<String,List<String>> map = new HashMap<>();
Matcher matcher = RE.matcher(s);
while (matcher.matches()) {
String name = matcher.group(1);
List<String> list = Arrays.asList(
matcher.group(2).split("\\s*,\\s*"));
map.put(name, list);
String tail = matcher.group(3);
if (tail == null) {
break;
}
matcher = RE.matcher(tail);
}
System.out.println(map);
}

How to use a return string of another class using Java?

I'm using the follow code to generate random e-mails on the dataMap class:
public static String generateRandomEmail(int length) {
String allowedChars = "abcdefghijklmnopqrstuvwxyz" + "_-.";
String email = "";
String temp = RandomStringUtils.random(length, allowedChars);
email = temp.substring(0, temp.length() - 1)+"#mailinator.com";
System.out.println(email);
return email;
}
On my steps class, I need to use this email value, but I'm calling the method again, so it's generate another "email".
#Dado("que realizo a chamada no (.*) da (.*) informando (.*) e um email e (.*) novos")
public void verificarAmbiente(String srtAmbiente, String srtAPI, String srtToken, String srtSenha) {
System.out.println(srtAmbiente+srtAPI);
dataMap data = new dataMap();
int length = 15;
data.generateRandomEmail(length);
Map<String, String> emailContent = new HashMap<String,String>();
emailContent.put("email", data.generateRandomEmail(length));
Map<String, Object> postContent = new HashMap<String,Object>();
postContent.put("customer", emailContent);
postContent.put("password", srtSenha);
given().contentType(ContentType.JSON)
.header("Authorization", "Bearer "+srtToken)
.with().body(postContent)
.when().post(srtAmbiente+srtAPI).prettyPeek()
.then().statusCode(200);
}
I wanna transform the "return email" in a variable and call it in another class without execute the method again and change the value. Can you help me?
Thanks!

You need to store the generated email in a variable:
String email = data.generateRandomEmail(length);
And then you can just use the email variable later when you need the same email address.

Java: How to fill placeholders in a text with Map<String,String>?

I am working with a code where I want fill several string place holders with another strings. This is the example text I have used to test my code.
String myStr = "Media file %s of size %s has been approved"
This is how I fill the place holders. Since I expect to use several place holders I have used java Map<>.
Map<String, String> propMap = new HashMap<String,String>();
propMap.put("file name","20mb");
String newNotification = createNotification(propMap);
I used following method to create the string.
public String createNotification(Map<String, String> properties){
String message = "";
message = String.format(myStr, properties);
return message;
}
How do I replace two of '%s' with "file name" and "20mb"?

That's not what a Map is intended to do.
What you add is an entry "file name" -> "20 mb", which basically means the property "file name" has the value "20 mb". What you are trying to do with it is "maintain a tuple of items".
Note that the formatting string has a fixed amount of placeholder; you want a data structure that contains exactly the same amount of items; so essentially an array or a List.
Thus, what you want to have is
public String createNotification(String[] properties) {
assert(properties.length == 2); // you might want to really check this, you will run into problems if it's false
return String.format("file %s has size %s", properties);
}
If you want to create notifications of all items in a map, you need to do something like this:
Map<String,String> yourMap = //...
for (Entry<String,String> e : yourMap) {
System.out.println(createNotification(e.getKey(), e.getValue()));
}

Your approach to String#format is wrong.
It expects a variable amount of objects to replace the placeholders as the second argument, not a map. To group them all together, you can use an array or a list.
String format = "Media file %s of size %s has been approved";
Object[] args = {"file name", "20mb"};
String newNotification = String.format(format, args);

You can simply do this formatting using var-args:
String myStr = "Media file %s of size %s has been approved";
String newNotification = createNotification(myStr, "file name", "20mb");
System.out.println(newNotification);
Pass var-args in createNotification method, here is the code:
public static String createNotification(String myStr, String... strings){
String message = "";
message=String.format(myStr, strings[0], strings[1]);
return message;
}

I think %s is Python’s grammar to place holder, can’t use this in Java environment; and your method createNotification() defined needs two parameters, can’t only give one.

After trying several ways finally found a good solution. Place holders must be like this [placeholder] .
public String createNotification(){
Pattern pattern = Pattern.compile("\\[(.+?)\\]");
Matcher matcher = pattern.matcher(textTemplate);
HashMap<String,String> replacementValues = new HashMap<String,String>();
StringBuilder builder = new StringBuilder();
int i = 0;
while (matcher.find()) {
String replacement = replacementValues.get(matcher.group(1));
builder.append(textTemplate.substring(i, matcher.start()));
if (replacement == null){ builder.append(matcher.group(0)); }
else { builder.append(replacement); }
i = matcher.end();
}
builder.append(textTemplate.substring(i, textTemplate.length()));
return builder.toString()
}

Simplest way to strip an int out of a URL in Java?

I have a String containing a URL. I want to get just one piece of data out of it: an int that should be showing up in the query string.
So if the url is:
http://domain.tld/page.html?iVar=123
I want to get "123" into an int.
What's the most elegant way you know to do this?

You could try matching just that parameter in the URL string:
public static Integer getIVarParamValue(String urlStr) {
Pattern p = Pattern.compile("iVar=(\\d+)");
Matcher m = p.matcher(urlStr);
if (m.find()) {
return Integer.parseInt(m.group(1));
}
return null;
}

It seems you want to obtain get parameters and parse them. I have this method here (got it from somewhere on SO, I guess):
public static Map<String, List<String>> getQueryParams(String url) {
try {
Map<String, List<String>> params = new HashMap<String, List<String>>();
String[] urlParts = url.split("\\?");
if (urlParts.length > 1) {
String query = urlParts[1];
for (String param : query.split("&")) {
String[] pair = param.split("=");
String key = URLDecoder.decode(pair[0], "UTF-8");
String value = "";
if (pair.length > 1) {
value = URLDecoder.decode(pair[1], "UTF-8");
}
List<String> values = params.get(key);
if (values == null) {
values = new ArrayList<String>();
params.put(key, values);
}
values.add(value);
}
}
return params;
} catch (UnsupportedEncodingException ex) {
throw new AssertionError(ex);
}
}
So:
String var = WebUtils.getQueryParams(url).get("iVar");
int intVar = Integer.parseInt(var);

You can use the URL class.
i.e.:
URL myUrl = new URL("http://domain.tld/page.html?iVar=123");
String query = myUrl.getQuery(); //this will return iVar=123
//at this point you can either parse it manually (i.e. use some of the regexp in the other suggestions, or use something like:
String[] parts = query.split();
String variable = parts[0];
String value = parts[1];
This will work only for this case though and won't work if you have additional params or no params.
There are a number of solution that will split it into a param map online, you can see some here.

If it's really as simple as you describe: There is only 1 int in your URL and all you want is that int, I'd go for a regular expression. If it is actually more complicated see the other answers.
Pattern p = Pattern.compile("[0-9]+");
Matcher m = p.matcher("http://domain.tld/page.html?iVar=123");
if (m.find())
System.out.println(m.group());

This also could do the work :
public static int getIntParam(HttpServletRequest request, String name, int defaultValue) {
String value = request.getParameter(name);
try {
if (value != null) {
return Integer.valueOf(value);
}
} catch (NumberFormatException e) {
}
return defaultValue;
}
Hope it helps!

If the query string part of the URL is always the same (so if it was always iVar) you could use urlAsString.indexOf("iVar=") to find iVar= and then knowing the number is after that, extract the number. That is admittedly not the least brittle approach.
But if you're looking for all the query strings then Bozho's answer is much better.

Named placeholders in string formatting

In Python, when formatting string, I can fill placeholders by name rather than by position, like that:
print "There's an incorrect value '%(value)s' in column # %(column)d" % \
{ 'value': x, 'column': y }
I wonder if that is possible in Java (hopefully, without external libraries)?

StrSubstitutor of jakarta commons lang is a light weight way of doing this provided your values are already formatted correctly.
http://commons.apache.org/proper/commons-lang/javadocs/api-3.1/org/apache/commons/lang3/text/StrSubstitutor.html
Map<String, String> values = new HashMap<String, String>();
values.put("value", x);
values.put("column", y);
StrSubstitutor sub = new StrSubstitutor(values, "%(", ")");
String result = sub.replace("There's an incorrect value '%(value)' in column # %(column)");
The above results in:
"There's an incorrect value '1' in column # 2"
When using Maven you can add this dependency to your pom.xml:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-lang3</artifactId>
<version>3.4</version>
</dependency>

not quite, but you can use MessageFormat to reference one value multiple times:
MessageFormat.format("There's an incorrect value \"{0}\" in column # {1}", x, y);
The above can be done with String.format() as well, but I find messageFormat syntax cleaner if you need to build complex expressions, plus you dont need to care about the type of the object you are putting into the string

Another example of Apache Common StringSubstitutor for simple named placeholder.
String template = "Welcome to {theWorld}. My name is {myName}.";
Map<String, String> values = new HashMap<>();
values.put("theWorld", "Stackoverflow");
values.put("myName", "Thanos");
String message = StringSubstitutor.replace(template, values, "{", "}");
System.out.println(message);
// Welcome to Stackoverflow. My name is Thanos.

You can use StringTemplate library, it offers what you want and much more.
import org.antlr.stringtemplate.*;
final StringTemplate hello = new StringTemplate("Hello, $name$");
hello.setAttribute("name", "World");
System.out.println(hello.toString());

public static String format(String format, Map<String, Object> values) {
StringBuilder formatter = new StringBuilder(format);
List<Object> valueList = new ArrayList<Object>();
Matcher matcher = Pattern.compile("\\$\\{(\\w+)}").matcher(format);
while (matcher.find()) {
String key = matcher.group(1);
String formatKey = String.format("${%s}", key);
int index = formatter.indexOf(formatKey);
if (index != -1) {
formatter.replace(index, index + formatKey.length(), "%s");
valueList.add(values.get(key));
}
}
return String.format(formatter.toString(), valueList.toArray());
}
Example:
String format = "My name is ${1}. ${0} ${1}.";
Map<String, Object> values = new HashMap<String, Object>();
values.put("0", "James");
values.put("1", "Bond");
System.out.println(format(format, values)); // My name is Bond. James Bond.

Thanks for all your help! Using all your clues, I've written routine to do exactly what I want -- python-like string formatting using dictionary. Since I'm Java newbie, any hints are appreciated.
public static String dictFormat(String format, Hashtable<String, Object> values) {
StringBuilder convFormat = new StringBuilder(format);
Enumeration<String> keys = values.keys();
ArrayList valueList = new ArrayList();
int currentPos = 1;
while (keys.hasMoreElements()) {
String key = keys.nextElement(),
formatKey = "%(" + key + ")",
formatPos = "%" + Integer.toString(currentPos) + "$";
int index = -1;
while ((index = convFormat.indexOf(formatKey, index)) != -1) {
convFormat.replace(index, index + formatKey.length(), formatPos);
index += formatPos.length();
}
valueList.add(values.get(key));
++currentPos;
}
return String.format(convFormat.toString(), valueList.toArray());
}

This is an old thread, but just for the record, you could also use Java 8 style, like this:
public static String replaceParams(Map<String, String> hashMap, String template) {
return hashMap.entrySet().stream().reduce(template, (s, e) -> s.replace("%(" + e.getKey() + ")", e.getValue()),
(s, s2) -> s);
}
Usage:
public static void main(String[] args) {
final HashMap<String, String> hashMap = new HashMap<String, String>() {
{
put("foo", "foo1");
put("bar", "bar1");
put("car", "BMW");
put("truck", "MAN");
}
};
String res = replaceParams(hashMap, "This is '%(foo)' and '%(foo)', but also '%(bar)' '%(bar)' indeed.");
System.out.println(res);
System.out.println(replaceParams(hashMap, "This is '%(car)' and '%(foo)', but also '%(bar)' '%(bar)' indeed."));
System.out.println(replaceParams(hashMap, "This is '%(car)' and '%(truck)', but also '%(foo)' '%(bar)' + '%(truck)' indeed."));
}
The output will be:
This is 'foo1' and 'foo1', but also 'bar1' 'bar1' indeed.
This is 'BMW' and 'foo1', but also 'bar1' 'bar1' indeed.
This is 'BMW' and 'MAN', but also 'foo1' 'bar1' + 'MAN' indeed.

Apache Commons StringSubstitutor can be used. Note that StrSubstitutor is deprecated.
import org.apache.commons.text.StringSubstitutor;
// ...
Map<String, String> values = new HashMap<>();
values.put("animal", "quick brown fox");
values.put("target", "lazy dog");
StringSubstitutor sub = new StringSubstitutor(values);
String result = sub.replace("The ${animal} jumped over the ${target}.");
// "The quick brown fox jumped over the lazy dog."
This class supports providing default values for variables.
String result = sub.replace("The number is ${undefined.property:-42}.");
// "The number is 42."
To use recursive variable replacement, call setEnableSubstitutionInVariables(true);.
Map<String, String> values = new HashMap<>();
values.put("b", "c");
values.put("ac", "Test");
StringSubstitutor sub = new StringSubstitutor(values);
sub.setEnableSubstitutionInVariables(true);
String result = sub.replace("${a${b}}");
// "Test"

I am the author of a small library that does exactly what you want:
Student student = new Student("Andrei", 30, "Male");
String studStr = template("#{id}\tName: #{st.getName}, Age: #{st.getAge}, Gender: #{st.getGender}")
.arg("id", 10)
.arg("st", student)
.format();
System.out.println(studStr);
Or you can chain the arguments:
String result = template("#{x} + #{y} = #{z}")
.args("x", 5, "y", 10, "z", 15)
.format();
System.out.println(result);
// Output: "5 + 10 = 15"

There is nothing built into Java at the moment of writing this. I would suggest writing your own implementation. My preference is for a simple fluent builder interface instead of creating a map and passing it to function -- you end up with a nice contiguous chunk of code, for example:
String result = new TemplatedStringBuilder("My name is {{name}} and I from {{town}}")
.replace("name", "John Doe")
.replace("town", "Sydney")
.finish();
Here is a simple implementation:
class TemplatedStringBuilder {
private final static String TEMPLATE_START_TOKEN = "{{";
private final static String TEMPLATE_CLOSE_TOKEN = "}}";
private final String template;
private final Map<String, String> parameters = new HashMap<>();
public TemplatedStringBuilder(String template) {
if (template == null) throw new NullPointerException();
this.template = template;
}
public TemplatedStringBuilder replace(String key, String value){
parameters.put(key, value);
return this;
}
public String finish(){
StringBuilder result = new StringBuilder();
int startIndex = 0;
while (startIndex < template.length()){
int openIndex = template.indexOf(TEMPLATE_START_TOKEN, startIndex);
if (openIndex < 0){
result.append(template.substring(startIndex));
break;
}
int closeIndex = template.indexOf(TEMPLATE_CLOSE_TOKEN, openIndex);
if(closeIndex < 0){
result.append(template.substring(startIndex));
break;
}
String key = template.substring(openIndex + TEMPLATE_START_TOKEN.length(), closeIndex);
if (!parameters.containsKey(key)) throw new RuntimeException("missing value for key: " + key);
result.append(template.substring(startIndex, openIndex));
result.append(parameters.get(key));
startIndex = closeIndex + TEMPLATE_CLOSE_TOKEN.length();
}
return result.toString();
}
}

Apache Commons Lang's replaceEach method may come in handy dependeding on your specific needs. You can easily use it to replace placeholders by name with this single method call:
StringUtils.replaceEach("There's an incorrect value '%(value)' in column # %(column)",
new String[] { "%(value)", "%(column)" }, new String[] { x, y });
Given some input text, this will replace all occurrences of the placeholders in the first string array with the corresponding values in the second one.

You should have a look at the official ICU4J library. It provides a MessageFormat class similar to the one available with the JDK but this former supports named placeholders.
Unlike other solutions provided on this page. ICU4j is part of the ICU project that is maintained by IBM and regularly updated. In addition, it supports advanced use cases such as pluralization and much more.
Here is a code example:
MessageFormat messageFormat =
new MessageFormat("Publication written by {author}.");
Map<String, String> args = Map.of("author", "John Doe");
System.out.println(messageFormat.format(args));

As of 2022 the up-to-date solution is Apache Commons Text StringSubstitutor
From the doc:
// Build map
Map<String, String> valuesMap = new HashMap<>();
valuesMap.put("animal", "quick brown fox");
valuesMap.put("target", "lazy dog");
String templateString = "The ${animal} jumped over the ${target} ${undefined.number:-1234567890} times.";
// Build StringSubstitutor
StringSubstitutor sub = new StringSubstitutor(valuesMap);
// Replace
String resolvedString = sub.replace(templateString)
;

You could have something like this on a string helper class
/**
* An interpreter for strings with named placeholders.
*
* For example given the string "hello %(myName)" and the map <code>
* <p>Map<String, Object> map = new HashMap<String, Object>();</p>
* <p>map.put("myName", "world");</p>
* </code>
*
* the call {#code format("hello %(myName)", map)} returns "hello world"
*
* It replaces every occurrence of a named placeholder with its given value
* in the map. If there is a named place holder which is not found in the
* map then the string will retain that placeholder. Likewise, if there is
* an entry in the map that does not have its respective placeholder, it is
* ignored.
*
* #param str
* string to format
* #param values
* to replace
* #return formatted string
*/
public static String format(String str, Map<String, Object> values) {
StringBuilder builder = new StringBuilder(str);
for (Entry<String, Object> entry : values.entrySet()) {
int start;
String pattern = "%(" + entry.getKey() + ")";
String value = entry.getValue().toString();
// Replace every occurence of %(key) with value
while ((start = builder.indexOf(pattern)) != -1) {
builder.replace(start, start + pattern.length(), value);
}
}
return builder.toString();
}

Based on the answer I created MapBuilder class:
public class MapBuilder {
public static Map<String, Object> build(Object... data) {
Map<String, Object> result = new LinkedHashMap<>();
if (data.length % 2 != 0) {
throw new IllegalArgumentException("Odd number of arguments");
}
String key = null;
Integer step = -1;
for (Object value : data) {
step++;
switch (step % 2) {
case 0:
if (value == null) {
throw new IllegalArgumentException("Null key value");
}
key = (String) value;
continue;
case 1:
result.put(key, value);
break;
}
}
return result;
}
}
then I created class StringFormat for String formatting:
public final class StringFormat {
public static String format(String format, Object... args) {
Map<String, Object> values = MapBuilder.build(args);
for (Map.Entry<String, Object> entry : values.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
format = format.replace("$" + key, value.toString());
}
return format;
}
}
which you could use like that:
String bookingDate = StringFormat.format("From $startDate to $endDate"),
"$startDate", formattedStartDate,
"$endDate", formattedEndDate
);

I created also a util/helper class (using jdk 8) which can format a string an replaces occurrences of variables.
For this purpose I used the Matchers "appendReplacement" method which does all the substitution and loops only over the affected parts of a format string.
The helper class isn't currently well javadoc documented. I will changes this in the future ;)
Anyway I commented the most important lines (I hope).
public class FormatHelper {
//Prefix and suffix for the enclosing variable name in the format string.
//Replace the default values with any you need.
public static final String DEFAULT_PREFIX = "${";
public static final String DEFAULT_SUFFIX = "}";
//Define dynamic function what happens if a key is not found.
//Replace the defualt exception with any "unchecked" exception type you need or any other behavior.
public static final BiFunction<String, String, String> DEFAULT_NO_KEY_FUNCTION =
(fullMatch, variableName) -> {
throw new RuntimeException(String.format("Key: %s for variable %s not found.",
variableName,
fullMatch));
};
private final Pattern variablePattern;
private final Map<String, String> values;
private final BiFunction<String, String, String> noKeyFunction;
private final String prefix;
private final String suffix;
public FormatHelper(Map<String, String> values) {
this(DEFAULT_NO_KEY_FUNCTION, values);
}
public FormatHelper(
BiFunction<String, String, String> noKeyFunction, Map<String, String> values) {
this(DEFAULT_PREFIX, DEFAULT_SUFFIX, noKeyFunction, values);
}
public FormatHelper(String prefix, String suffix, Map<String, String> values) {
this(prefix, suffix, DEFAULT_NO_KEY_FUNCTION, values);
}
public FormatHelper(
String prefix,
String suffix,
BiFunction<String, String, String> noKeyFunction,
Map<String, String> values) {
this.prefix = prefix;
this.suffix = suffix;
this.values = values;
this.noKeyFunction = noKeyFunction;
//Create the Pattern and quote the prefix and suffix so that the regex don't interpret special chars.
//The variable name is a "\w+" in an extra capture group.
variablePattern = Pattern.compile(Pattern.quote(prefix) + "(\\w+)" + Pattern.quote(suffix));
}
public static String format(CharSequence format, Map<String, String> values) {
return new FormatHelper(values).format(format);
}
public static String format(
CharSequence format,
BiFunction<String, String, String> noKeyFunction,
Map<String, String> values) {
return new FormatHelper(noKeyFunction, values).format(format);
}
public static String format(
String prefix, String suffix, CharSequence format, Map<String, String> values) {
return new FormatHelper(prefix, suffix, values).format(format);
}
public static String format(
String prefix,
String suffix,
BiFunction<String, String, String> noKeyFunction,
CharSequence format,
Map<String, String> values) {
return new FormatHelper(prefix, suffix, noKeyFunction, values).format(format);
}
public String format(CharSequence format) {
//Create matcher based on the init pattern for variable names.
Matcher matcher = variablePattern.matcher(format);
//This buffer will hold all parts of the formatted finished string.
StringBuffer formatBuffer = new StringBuffer();
//loop while the matcher finds another variable (prefix -> name <- suffix) match
while (matcher.find()) {
//The root capture group with the full match e.g ${variableName}
String fullMatch = matcher.group();
//The capture group for the variable name resulting from "(\w+)" e.g. variableName
String variableName = matcher.group(1);
//Get the value in our Map so the Key is the used variable name in our "format" string. The associated value will replace the variable.
//If key is missing (absent) call the noKeyFunction with parameters "fullMatch" and "variableName" else return the value.
String value = values.computeIfAbsent(variableName, key -> noKeyFunction.apply(fullMatch, key));
//Escape the Map value because the "appendReplacement" method interprets the $ and \ as special chars.
String escapedValue = Matcher.quoteReplacement(value);
//The "appendReplacement" method replaces the current "full" match (e.g. ${variableName}) with the value from the "values" Map.
//The replaced part of the "format" string is appended to the StringBuffer "formatBuffer".
matcher.appendReplacement(formatBuffer, escapedValue);
}
//The "appendTail" method appends the last part of the "format" String which has no regex match.
//That means if e.g. our "format" string has no matches the whole untouched "format" string is appended to the StringBuffer "formatBuffer".
//Further more the method return the buffer.
return matcher.appendTail(formatBuffer)
.toString();
}
public String getPrefix() {
return prefix;
}
public String getSuffix() {
return suffix;
}
public Map<String, String> getValues() {
return values;
}
}
You can create a class instance for a specific Map with values (or suffix prefix or noKeyFunction)
like:
Map<String, String> values = new HashMap<>();
values.put("firstName", "Peter");
values.put("lastName", "Parker");
FormatHelper formatHelper = new FormatHelper(values);
formatHelper.format("${firstName} ${lastName} is Spiderman!");
// Result: "Peter Parker is Spiderman!"
// Next format:
formatHelper.format("Does ${firstName} ${lastName} works as photographer?");
//Result: "Does Peter Parker works as photographer?"
Further more you can define what happens if a key in the values Map is missing (works in both ways e.g. wrong variable name in format string or missing key in Map).
The default behavior is an thrown unchecked exception (unchecked because I use the default jdk8 Function which cant handle checked exceptions) like:
Map<String, String> map = new HashMap<>();
map.put("firstName", "Peter");
map.put("lastName", "Parker");
FormatHelper formatHelper = new FormatHelper(map);
formatHelper.format("${missingName} ${lastName} is Spiderman!");
//Result: RuntimeException: Key: missingName for variable ${missingName} not found.
You can define a custom behavior in the constructor call like:
Map<String, String> values = new HashMap<>();
values.put("firstName", "Peter");
values.put("lastName", "Parker");
FormatHelper formatHelper = new FormatHelper(fullMatch, variableName) -> variableName.equals("missingName") ? "John": "SOMETHING_WRONG", values);
formatHelper.format("${missingName} ${lastName} is Spiderman!");
// Result: "John Parker is Spiderman!"
or delegate it back to the default no key behavior:
...
FormatHelper formatHelper = new FormatHelper((fullMatch, variableName) -> variableName.equals("missingName") ? "John" :
FormatHelper.DEFAULT_NO_KEY_FUNCTION.apply(fullMatch,
variableName), map);
...
For better handling there are also static method representations like:
Map<String, String> values = new HashMap<>();
values.put("firstName", "Peter");
values.put("lastName", "Parker");
FormatHelper.format("${firstName} ${lastName} is Spiderman!", map);
// Result: "Peter Parker is Spiderman!"

There is Java Plugin to use string interpolation in Java (like in Kotlin, JavaScript). Supports Java 8, 9, 10, 11…​ https://github.com/antkorwin/better-strings
Using variables in string literals:
int a = 3;
int b = 4;
System.out.println("${a} + ${b} = ${a+b}");
Using expressions:
int a = 3;
int b = 4;
System.out.println("pow = ${a * a}");
System.out.println("flag = ${a > b ? true : false}");
Using functions:
#Test
void functionCall() {
System.out.println("fact(5) = ${factorial(5)}");
}
long factorial(int n) {
long fact = 1;
for (int i = 2; i <= n; i++) {
fact = fact * i;
}
return fact;
}
For more info, please read the project README.

The quick answer is no, unfortunately. However, you can come pretty close to a reasonable syntaks:
"""
You are $compliment!
"""
.replace('$compliment', 'awesome');
It's more readable and predictable than String.format, at least!

My answer is to:
a) use StringBuilder when possible
b) keep (in any form: integer is the best, speciall char like dollar macro etc) position of "placeholder" and then use StringBuilder.insert() (few versions of arguments).
Using external libraries seems overkill and I belive degrade performance significant, when StringBuilder is converted to String internally.

Try Freemarker, templating library.

I tried in just a quick way
public static void main(String[] args)
{
String rowString = "replace the value ${var1} with ${var2}";
Map<String,String> mappedValues = new HashMap<>();
mappedValues.put("var1", "Value 1");
mappedValues.put("var2", "Value 2");
System.out.println(replaceOccurence(rowString, mappedValues));
}
private static String replaceOccurence(String baseStr ,Map<String,String> mappedValues)
{
for(String key :mappedValues.keySet())
{
baseStr = baseStr.replace("${"+key+"}", mappedValues.get(key));
}
return baseStr;
}

I ended up with the next solution:
Create class TemplateSubstitutor with method substitute() and use it to format output
Then create a string template and fill it with values
import java.util.*;
public class MyClass {
public static void main(String args[]) {
String template = "WRR = {WRR}, SRR = {SRR}\n" +
"char_F1 = {char_F1}, word_F1 = {word_F1}\n";
Map<String, Object> values = new HashMap<>();
values.put("WRR", 99.9);
values.put("SRR", 99.8);
values.put("char_F1", 80);
values.put("word_F1", 70);
String message = TemplateSubstitutor.substitute(values, template);
System.out.println(message);
}
}
class TemplateSubstitutor {
public static String substitute(Map<String, Object> map, String input_str) {
String output_str = input_str;
for (Map.Entry<String, Object> entry : map.entrySet()) {
String key = entry.getKey();
Object value = entry.getValue();
output_str = output_str.replace("{" + key + "}", String.valueOf(value));
}
return output_str;
}
}

https://dzone.com/articles/java-string-format-examples String.format(inputString, [listOfParams]) would be the easiest way. Placeholders in string can be defined by order. For more details check the provided link.