I am using hibernate to connect to my database for a project.
I would like to have a query that gets the products out of my database with the discription and name in a certain language. The parameter I have is the short name for the language, so first I would have to get the id of the language and then get the text in the required languages.
I have tried the following hql query, without success.
from Products as p
where p.productlanguages.languages.shortname like 'eng'
This is an image of the part of the database where the data should come from:
I have got the desired result with an sql query, but I can't seem to get it to work in hibernate. But I would prefer to do this in hql.
SELECT * FROM products p
INNER JOIN productlanguage pl ON pl.Products_id = p.id
WHERE pl.Languages_id =
(
SELECT id FROM languages
WHERE Shortname = 'eng'
);
Could anyone tell me how to build this hql query?
Thank you.
Try below:
from Products p INNER JOIN p.productlanguages pl
where pl.languages.shortname ='eng'
I am assuming that you have mapped Product-Productlanguages relationship as OneToMany and Productlanguages-Langages relationship as ManyToOne as depicted in your E-R diagram.
EDIT: There seems to be a typo in Productlanguage mapping at line public Languages getLanguages() {barcode, remove the barcode in the end.
#ManyToOne(fetch=FetchType.LAZY)
#JoinColumn(name="Languages_id", nullable=false, insertable=false, updatable=false)
public Languages getLanguages() {barcode
return this.languages;
}
Related
Context
I send some files to some enterprises every week. I need to restitute for each week and each enterprise whether the file is sent or not.
Tables
ent (enterprise)
wek (week)
fil (file : references wek and ent)
Solution with pure SQL
Make a cartesian product between ent and wek then left outer join fil. This works :
select * from
(
select * from wek, ent e
) as t1
left join fil f
on f.ent_id = t1.ent_id
and f.wek_id = t1.wek_id
Problem :
How to translate this into JPA (in the CriteriaBuilder way)?
For example, if I try :
CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<ResultClass> query = cb.createQuery(ResultClass.class);
Root<Week> week = query.from(Week.class);
Root<Enterprise> query.from(Enterprise.class);
Expression<???> cartesianProduct = ??? //How?
cartesianProduct.leftJoin(???_.file);
query.where(
cb.equal(file.get(File_.wek_id), week.get(Week.week_id));
)
Using 2 "from" clauses gives me the cartesian product but how do I left join this result?
Unstatisfaying solution :
Create a view :
CREATE VIEW view_ent_wek AS
SELECT ent_id as ent_id, wek_id as wek_id, ent_id || '-' || ent_id as id
FROM ent, wek;
Map it to an entity :
#Entity
#Table(name = "view_ent_wek")
public class WeekEnterprise {
#Id
#Column(name = "id")
private String id;
#ManyToOne
#JoinColumn(name = "ent_id")
private Enterprise enterprise;
#ManyToOne
#JoinColumn(name = "wek_id")
private Week week;
[...]
Then I can use it in a query :
Root<WeekEnterprise> weekEnterprise = query.from(WeekEnterprise.class);
weekEnterprise.join(...)
I don't like this solution because it makes me create a view that is obviously not necessary. Any idea?
I don't see the point of doing the reporting-style SQL query with JPA, let alone with Criteria Query.
Of course, JPA (and its implementations) do support tuple queries (as opposed to entity queries, see also: Hibernate tuple criteria queries), but tuple queries is not what JPA is good at. Imagine you want to change that report and add more calculations. Wouldn't it be much easier to do that with SQL?
Using JPA for mapping to Java objects and for transaction modelling still makes sense, and thus, your SQL view solution is already quite good, or if you prefer not to store the SQL in a view, use JPA's native query API:
List<Object[]> list = em.createNativeQuery(sql).getResultList();
Or:
List<WeekEnterprise> list = em.createNativeQuery(sql, WeekEnterprise.class)
.getResultList();
I have some ideas:
With 2 JPA queries. First: fetch the cartesian product of wek and enterprises. Second: take an inner join between wek, enterprises and files. Uses a map (wek_id+ent_id => Tuple(Wek, Ent, File)) to quickly identify where to put the file.
Write plain SQL queries and execute them with the JPA API.
(Didn't think much about this one) Create a back reference from Wek and Ent to File (lazy loaded) and then you should be able to continue your first idea.
Don't know much about JPA, but about Postgres. And I would suggest this superior query:
SELECT *
FROM wek CROSS JOIN ent
LEFT JOIN fil USING (ent_id, wek_id);
You don't need the subselect.
The only difference in the result (besides being shorter and faster): You get the columns ent_id and wek_id once in the output (which might solve a problem with duplicated column names).
Should be easy to translate to JPA now.
I am new to hibernate so I am pretty sure that some of you would be amused by this question. It has been driving me crazy. This is a hibernate query question.
I have two tables, Assuming one is outlet and one is flyers
outlet - outlet name,outlet address, merchantName
flyers - flyerId, flyerName, merchantName
so flyers belong to a merchant and a merchant has many outlets etc,
using hibernate, to get a simple query like to get the different outlets from the outlet table using the merchantName, I use the code:
public List<Outlet> getDealOutlet(#PathParam("merchant") String merchant) {
some code here....
outletsList = session.createQuery("from Outlet as outlet where outlet.merchantName = :merchant").setString( "merchant", merchant ).list();
some code here
}
And that works.
My question is how do I return the lists of outlets for a particular flyerId.
Any help is appreciated thanks
Is the question "How can I return the list of outlets for the merchant associated with a particular flyerId?"
If so, do you have a table merchants that's mapped to a class Merchant? That's the path to go down; Hibernate can easily let you query across joins, but if Hibernate doesn't know about the join because all you've got is a magic String called merchantName that you know happens to be the same in the two tables, then Hibernate can't help you out.
(Though of course you could run two queries, but I doubt that's what you're looking for.)
It depends on your mappings, if there is an Merchant entity, and both other entities have an association to it, it can be written as:
select o
from Outlet o
join o.merchant m
join m.flyers f
where f.id = :flyersId
Other wise you can do something like you do in SQL:
select o
from Outlet o, Flyers f
where o.merchant = f.merchant and f.id = :flyersId
I have following as table structure
**BPV table**
id, vid, bid
**vt table**
vid, name, gender
**uv table**
uvid, vid, cast,...
i want to write left join between BPV ,uv based on vid in hibernate (mysql)
bpv entity have vt as one to one as well as uv have vt with one to one but there is no bpv &uv in realation
Hibernate has Criteria API, which is a good way to execute queries in a OO approach. If you have your persistent entities, then you can do this:
Criteria criteria = session.createCriteria(BPV.class, "bpv");
criteria.createCriteria("bpv.vt", "vt", CriteriaSpecification.LEFT_JOIN);
criteria.createCriteria("vt.uv", "uv", CriteriaSpecification.LEFT_JOIN);
// add restrictions
return criteria.list();
Hibernate SQL:
from BPV where BPV.uv.cast = "your_condition"
It requires properly described entities and dependency;
or pure SQL:
select * from BPV left join uv on BPV.vid = uv.vid where uv.cast = "your_condition"
What you're asking for is not posible, there is a Theta Join solution but it only supports inner join, so you have to give up on that approach and do one of the following solutions:
Map the proper relationship:
If this query is a unusual escenario, you dont necesary have to change your actual mapping , you can make a new dto Class with the new mapping, and use that one for this query.
Use native SQL:
This is prettly simple too, use .createSQLQuery(), to run the native query and you can use .addScalar() + .setResultTransformer(Transformers.aliasToBean(someDto.class)) to get a list of your entity.
Hi I'm trying to select records from one table which doesn't have records in connected many-to-many table with specific values.
I will explain on sample tables:
documentation:
id_documentation
irrelevant_data
user:
id_user
irrelevant_data
documentation_user:
id_documentation
id_user
role
What I want to achieve is to select every single documentation which doesn't have user in specific role. Any ideas?
The main problem is that I'm using java's CriteriaBuilder to create query so using subqueries is impossible (I think).
You can add restrictions on your left join using: createAlias(java.lang.String, java.lang.String, int, org.hibernate.criterion.Criterion) method, see API.
Check this answer for an example on how to use the left join with a criteria.
Main problem does not exist - Criteria API do have SubQuery. Query itself selects instances of User and uses not in construct to limit results based to subquery. Subquery selects all users that are connected to document with specific role via DocumentationUser.
Try something like this (code not tested):
CriteriaQuery<Documentation> cq = cb.createQuery(Documentation.class);
Root<Documentation> u = cq.from(Documentation.class);
Subquery<Integer> sq = cq.subquery(Integer.class);
Root<User> su = sq.from(User.class);
sq.select(su.get("id_user"));
Join<User, DocumentationUser> du = su.join("documentationUserCollection");
sq.where(cb.equals(du.get("role"), "mySpecificRole"));
cq.where(cb.not(cb.in(u.get("id_user")).value(sq)));
See also this useful answer on SO.
I am new to the Hibernate and HQL. I want to write an update query in HQL, whose SQL equivalent is as follows:
update patient set
`last_name` = "new_last",
`first_name` = "new_first"
where id = (select doctor_id from doctor
where clinic_id = 22 and city = 'abc_city');
doctor_id is PK for doctor and is FK and PK in patient. There is one-to-one mapping.
The corresponding Java classes are Patient (with fields lastName, firstName, doctorId) and Doctor (with fields doctorId).
Can anyone please tell what will be the HQL equivalent of the above SQL query?
Thanks a lot.
String update = "update Patient p set p.last_name = :new_last, p.first_name = :new_first where p.id = some (select doctor.id from Doctor doctor where doctor.clinic_id = 22 and city = 'abc_city')";
You can work out how to phrase hql queries if you check the specification. You can find a section about subqueries there.
I don't think you need HQL (I know, you ask that explicitly, but since you say you're new to Hibernate, let me offer a Hibernate-style alternative). I am not a favor of HQL, because you are still dealing with strings, which can become hard to maintain, just like SQL, and you loose type safety.
Instead, use Hibernate criteria queries and methods to query your data. Depending on your class mapping, you could do something like this:
List patients = session.CreateCriteria(typeof(Patient.class))
.createAlias("doctor", "dr")
.add(Restrictions.Eq("dr.clinic_id", 22))
.add(Restrictions.Eq("dr.city", "abc_city"))
.list();
// go through the patients and set the properties something like this:
for(Patient p : patients)
{
p.lastName = "new lastname";
p.firstName = "new firstname";
}
Some people argue that using CreateCriteria is difficult. It takes a little getting used to, true, but it has the advantage of type safety and complexities can easily be hidden behind generic classes. Google for "Hibernate java GetByProperty" and you see what I mean.
update Patient set last_name = :new_last , first_name = :new_first where patient.id = some(select doctor_id from Doctor as doctor where clinic_id = 22 and city = abc_city)
There is a significant difference between executing update with select and actually fetching the records to the client, updating them and posting them back:
UPDATE x SET a=:a WHERE b in (SELECT ...)
works in the database, no data is transferred to the client.
list=CreateCriteria().add(Restriction).list();
brings all the records to be updated to the client, updates them, then posts them back to the database, probably with one UPDATE per record.
Using UPDATE is much, much faster than using criteria (think thousands of times).
Since the question title can be interpreted generally as "How to use nested selects in hibernate", and the HQL syntax restricts nested selects only to be in the select- and the where-clause, I would like to add here the possibility to use native SQL as well. In Oracle - for instance - you may also use a nested select in the from-clause.
Following query with two nested inner selects cannot be expressed by HQL:
select ext, count(ext)
from (
select substr(s, nullif( instr(s,'.', -1) +1, 1) ) as ext
from (
select b.FILE_NAME as s from ATTACHMENT_B b
union select att.FILE_NAME as s from ATTACHEMENT_FOR_MAIL att
)
)
GROUP BY ext
order by ext;
(which counts, BTW, the occurences of each distinct file name extension in two different tables).
You can use such an sql string as native sql like this:
#Autowired
private SessionFactory sessionFactory;
String sql = ...
SQLQuery qry = sessionFactory.getCurrentSession().createSQLQuery(sql);
// provide an appropriate ResultTransformer
return qry.list();