Related
So, I am trying to store 3 longs to a file, but it will a lot of data so I convert them to byte arrays and save them. My current method for saving them:
try (FileOutputStream output = new FileOutputStream(path, true)) {
//Put the data into my format
byte[] data = new byte[24];
main.getLogger().log(Level.INFO, "Saving most sig bits");
System.arraycopy(ByteUtils.longToBytes(uuid.getMostSignificantBits()), 0, data, 0, 8);
System.arraycopy(ByteUtils.longToBytes(uuid.getLeastSignificantBits()), 0, data, 8, 8);
System.arraycopy(ByteUtils.longToBytes(player.getTokens()), 0, data, 16, 8);
//Write data in the format
output.write(data);
}
longToBytes method:
private static ByteBuffer buffer = ByteBuffer.allocate(8);
public static byte[] longToBytes(long x) {
System.out.println(x);
buffer.putLong(0, x);
return buffer.array();
}
The byte array gets saved to the file, but the first byte gets truncated. the print statement in longToByes prints 8 three times.
The original longs are:
-9089798603852198353, -5339652910133477779, 5992
If I print the byte array I get:
-127, -38, -116, 84, 97, -116, 78, 47, -75, -27, -67, -8, 11, -100, -2, 109, 0, 0, 0, 0, 0, 0, 23, 104 (24 bytes)
But in the file I see:
ÚŒTaŒN/µå½ø(VT symbol)œþm(nul)(nul)(nul)(nul)(nul)(nul)(etb)h
which is 23 bytes (the first box doesn't show in notepad++)
but if I read it using
bytes = IOUtils.toByteArray(new FileReader(file));
I see:
64, -38, -116, 84, 97, -116, 78, 47, -75, -27, -67, -8, 11, -100, -2, 109, 0, 0, 0, 0, 0, 0, 23, 104 (24 bytes)
-127 is replaced with 64 somehow.
I concat the byte with "" to print it btw.
Do not use FileReader to read raw bytes from file. Use FileInputStream instead.
The problem with FileReader is that it reads chars, not bytes, from the file, by trying to decode the bytes using some character encoding (the default one if none was given).
bytes = IOUtils.toByteArray(new FileInputStream(file));
Alternatively you can use DataOutputStream to write long directly to an output stream and use DataInputStream to read from an input stream.
try (DataOutputStream out = new DataOutputStream(new FileOutputStream(file))) {
out.writeLong(uuid.getMostSignificantBits());
out.writeLong(uuid.getLeastSignificantBits());
out.writeLong(player.getTokens());
}
try (DataInputStream in = new DataInputStream(new FileInputStream(file))) {
long uuidMSB = in.readLong();
long uuidLSB = in.readLong();
long tokens = in.readLong();
}
I have to convert a byte array to string in Android, but my byte array contains negative values.
If I convert that string again to byte array, values I am getting are different from original byte array values.
What can I do to get proper conversion? Code I am using to do the conversion is as follows:
// Code to convert byte arr to str:
byte[] by_original = {0,1,-2,3,-4,-5,6};
String str1 = new String(by_original);
System.out.println("str1 >> "+str1);
// Code to convert str to byte arr:
byte[] by_new = str1.getBytes();
for(int i=0;i<by_new.length;i++)
System.out.println("by1["+i+"] >> "+str1);
I am stuck in this problem.
Your byte array must have some encoding. The encoding cannot be ASCII if you've got negative values. Once you figure that out, you can convert a set of bytes to a String using:
byte[] bytes = {...}
String str = new String(bytes, StandardCharsets.UTF_8); // for UTF-8 encoding
There are a bunch of encodings you can use, look at the supported encodings in the Oracle javadocs.
The "proper conversion" between byte[] and String is to explicitly state the encoding you want to use. If you start with a byte[] and it does not in fact contain text data, there is no "proper conversion". Strings are for text, byte[] is for binary data, and the only really sensible thing to do is to avoid converting between them unless you absolutely have to.
If you really must use a String to hold binary data then the safest way is to use Base64 encoding.
The root problem is (I think) that you are unwittingly using a character set for which:
bytes != encode(decode(bytes))
in some cases. UTF-8 is an example of such a character set. Specifically, certain sequences of bytes are not valid encodings in UTF-8. If the UTF-8 decoder encounters one of these sequences, it is liable to discard the offending bytes or decode them as the Unicode codepoint for "no such character". Naturally, when you then try to encode the characters as bytes the result will be different.
The solution is:
Be explicit about the character encoding you are using; i.e. use a String constructor and String.toByteArray method with an explicit charset.
Use the right character set for your byte data ... or alternatively one (such as "Latin-1" where all byte sequences map to valid Unicode characters.
If your bytes are (really) binary data and you want to be able to transmit / receive them over a "text based" channel, use something like Base64 encoding ... which is designed for this purpose.
For Java, the most common character sets are in java.nio.charset.StandardCharsets. If you are encoding a string that can contain any Unicode character value then UTF-8 encoding (UTF_8) is recommended.
If you want a 1:1 mapping in Java then you can use ISO Latin Alphabet No. 1 - more commonly just called "Latin 1" or simply "Latin" (ISO_8859_1). Note that Latin-1 in Java is the IANA version of Latin-1 which assigns characters to all possible 256 values including control blocks C0 and C1. These are not printable: you won't see them in any output.
From Java 8 onwards Java contains java.util.Base64 for Base64 encoding / decoding. For URL-safe encoding you may want to to use Base64.getUrlEncoder instead of the standard encoder. This class is also present in Android since Android Oreo (8), API level 26.
We just need to construct a new String with the array: http://www.mkyong.com/java/how-do-convert-byte-array-to-string-in-java/
String s = new String(bytes);
The bytes of the resulting string differs depending on what charset you use. new String(bytes) and new String(bytes, Charset.forName("utf-8")) and new String(bytes, Charset.forName("utf-16")) will all have different byte arrays when you call String#getBytes() (depending on the default charset)
Using new String(byOriginal) and converting back to byte[] using getBytes() doesn't guarantee two byte[] with equal values. This is due to a call to StringCoding.encode(..) which will encode the String to Charset.defaultCharset(). During this encoding, the encoder might choose to replace unknown characters and do other changes. Hence, using String.getBytes() might not return an equal array as you've originally passed to the constructor.
Why was the problem: As someone already specified:
If you start with a byte[] and it does not in fact contain text data, there is no "proper conversion". Strings are for text, byte[] is for binary data, and the only really sensible thing to do is to avoid converting between them unless you absolutely have to.
I was observing this problem when I was trying to create byte[] from a pdf file and then converting it to String and then taking the String as input and converting back to file.
So make sure your encoding and decoding logic is same as I did. I explicitly encoded the byte[] to Base64 and decoded it to create the file again.
Use-case:
Due to some limitation I was trying to sent byte[] in request(POST) and the process was as follows:
PDF File >> Base64.encodeBase64(byte[]) >> String >> Send in request(POST) >> receive String >> Base64.decodeBase64(byte[]) >> create binary
Try this and this worked for me..
File file = new File("filePath");
byte[] byteArray = new byte[(int) file.length()];
try {
FileInputStream fileInputStream = new FileInputStream(file);
fileInputStream.read(byteArray);
String byteArrayStr= new String(Base64.encodeBase64(byteArray));
FileOutputStream fos = new FileOutputStream("newFilePath");
fos.write(Base64.decodeBase64(byteArrayStr.getBytes()));
fos.close();
}
catch (FileNotFoundException e) {
System.out.println("File Not Found.");
e.printStackTrace();
}
catch (IOException e1) {
System.out.println("Error Reading The File.");
e1.printStackTrace();
}
Even though
new String(bytes, "UTF-8")
is correct it throws a UnsupportedEncodingException which forces you to deal with a checked exception. You can use as an alternative another constructor since Java 1.6 to convert a byte array into a String:
new String(bytes, StandardCharsets.UTF_8)
This one does not throw any exception.
Converting back should be also done with StandardCharsets.UTF_8:
"test".getBytes(StandardCharsets.UTF_8)
Again you avoid having to deal with checked exceptions.
private static String toHexadecimal(byte[] digest){
String hash = "";
for(byte aux : digest) {
int b = aux & 0xff;
if (Integer.toHexString(b).length() == 1) hash += "0";
hash += Integer.toHexString(b);
}
return hash;
}
I did notice something that is not in any of the answers. You can cast each of the bytes in the byte array to characters, and put them in a char array. Then the string is new String(cbuf) where cbuf is the char array. To convert back, loop through the string casting each of the chars to bytes to put into a byte array, and this byte array will be the same as the first.
public class StringByteArrTest {
public static void main(String[] args) {
// put whatever byte array here
byte[] arr = new byte[] {-12, -100, -49, 100, -63, 0, -90};
for (byte b: arr) System.out.println(b);
// put data into this char array
char[] cbuf = new char[arr.length];
for (int i = 0; i < arr.length; i++) {
cbuf[i] = (char) arr[i];
}
// this is the string
String s = new String(cbuf);
System.out.println(s);
// converting back
byte[] out = new byte[s.length()];
for (int i = 0; i < s.length(); i++) {
out[i] = (byte) s.charAt(i);
}
for (byte b: out) System.out.println(b);
}
}
This works fine for me:
String cd = "Holding some value";
Converting from string to byte[]:
byte[] cookie = new sun.misc.BASE64Decoder().decodeBuffer(cd);
Converting from byte[] to string:
cd = new sun.misc.BASE64Encoder().encode(cookie);
Following is the sample code safely converts byte array to String and String to byte array back.
byte bytesArray[] = { 1, -2, 4, -5, 10};
String encoded = java.util.Base64.getEncoder().encodeToString(bytesArray);
byte[] decoded = java.util.Base64.getDecoder().decode(encoded);
System.out.println("input: "+Arrays.toString(bytesArray));
System.out.println("encoded: "+encoded);
System.out.println("decoded: "+Arrays.toString(decoded));
Output:
input: [1, -2, 4, -5, 10]
encoded: Af4E+wo=
decoded: [1, -2, 4, -5, 10]
javax.xml.bind.DatatypeConverter should do it:
byte [] b = javax.xml.bind.DatatypeConverter.parseHexBinary("E62DB");
String s = javax.xml.bind.DatatypeConverter.printHexBinary(b);
byte[] bytes = "Techie Delight".getBytes();
// System.out.println(Arrays.toString(bytes));
// Create a string from the byte array without specifying
// character encoding
String string = new String(bytes);
System.out.println(string);
Heres a few methods that convert an array of bytes to a string. I've tested them they work well.
public String getStringFromByteArray(byte[] settingsData) {
ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(settingsData);
Reader reader = new BufferedReader(new InputStreamReader(byteArrayInputStream));
StringBuilder sb = new StringBuilder();
int byteChar;
try {
while((byteChar = reader.read()) != -1) {
sb.append((char) byteChar);
}
}
catch(IOException e) {
e.printStackTrace();
}
return sb.toString();
}
public String getStringFromByteArray(byte[] settingsData) {
StringBuilder sb = new StringBuilder();
for(byte willBeChar: settingsData) {
sb.append((char) willBeChar);
}
return sb.toString();
}
While base64 encoding is safe and one could argue "the right answer", I arrived here looking for a way to convert a Java byte array to/from a Java String as-is. That is, where each member of the byte array remains intact in its String counterpart, with no extra space required for encoding/transport.
This answer describing 8bit transparent encodings was very helpful for me. I used ISO-8859-1 on terabytes of binary data to convert back and forth successfully (binary <-> String) without the inflated space requirements needed for a base64 encoding, so is safe for my use-case - YMMV.
This was also helpful in explaining when/if you should experiment.
Using Kotlin on Android I found out it is handy to create some simple extension functions for that purpose.
Solution based on Base64 encoding/decoding to be able to pass via JSON, XML, etc:
import android.util.Base64
fun ByteArray.encodeToString() = String(Base64.encode(this, Base64.NO_WRAP), Charsets.UTF_8)
fun String.decodeToBytes(): ByteArray = Base64.decode(toByteArray(Charsets.UTF_8), Base64.NO_WRAP)
So you can use it
val byteArray = byteArrayOf(0, 1, 2, -1, -2, -3)
val string = byteArray.encodeToString()
val restoredArray = string.decodeToBytes()
import sun.misc.BASE64Decoder;
import sun.misc.BASE64Encoder;
private static String base64Encode(byte[] bytes)
{
return new BASE64Encoder().encode(bytes);
}
private static byte[] base64Decode(String s) throws IOException
{
return new BASE64Decoder().decodeBuffer(s);
}
I succeeded converting byte array to a string with this method:
public static String byteArrayToString(byte[] data){
String response = Arrays.toString(data);
String[] byteValues = response.substring(1, response.length() - 1).split(",");
byte[] bytes = new byte[byteValues.length];
for (int i=0, len=bytes.length; i<len; i++) {
bytes[i] = Byte.parseByte(byteValues[i].trim());
}
String str = new String(bytes);
return str.toLowerCase();
}
This one works for me up to android Q:
You can use the following method to convert o hex string to string
public static String hexToString(String hex) {
StringBuilder sb = new StringBuilder();
char[] hexData = hex.toCharArray();
for (int count = 0; count < hexData.length - 1; count += 2) {
int firstDigit = Character.digit(hexData[count], 16);
int lastDigit = Character.digit(hexData[count + 1], 16);
int decimal = firstDigit * 16 + lastDigit;
sb.append((char)decimal);
}
return sb.toString();
}
with the following to convert a byte array to a hex string
public static String bytesToHex(byte[] bytes) {
char[] hexChars = new char[bytes.length * 2];
for (int j = 0; j < bytes.length; j++) {
int v = bytes[j] & 0xFF;
hexChars[j * 2] = hexArray[v >>> 4];
hexChars[j * 2 + 1] = hexArray[v & 0x0F];
}
return new String(hexChars);
}
Here the working code.
// Encode byte array into string . TemplateBuffer1 is my bytearry variable.
String finger_buffer = Base64.encodeToString(templateBuffer1, Base64.DEFAULT);
Log.d(TAG, "Captured biometric device->" + finger_buffer);
// Decode String into Byte Array. decodedString is my bytearray[]
decodedString = Base64.decode(finger_buffer, Base64.DEFAULT);
You can use simple for loop for conversion:
public void byteArrToString(){
byte[] b = {'a','b','$'};
String str = "";
for(int i=0; i<b.length; i++){
char c = (char) b[i];
str+=c;
}
System.out.println(str);
}
byte[] image = {...};
String imageString = Base64.encodeToString(image, Base64.NO_WRAP);
Try to specify an 8-bit charset in both conversions. ISO-8859-1 for instance.
Read the bytes from String using ByteArrayInputStream and wrap it with BufferedReader which is Char Stream instead of Byte Stream which converts the byte data to String.
package com.cs.sajal;
import java.io.BufferedReader;
import java.io.ByteArrayInputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
public class TestCls {
public static void main(String[] args) {
String s=new String("Sajal is a good boy");
try
{
ByteArrayInputStream bis;
bis=new ByteArrayInputStream(s.getBytes("UTF-8"));
BufferedReader br=new BufferedReader(new InputStreamReader(bis));
System.out.println(br.readLine());
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
Output is:
Sajal is a good boy
You can do the following to convert byte array to string and then convert that string to byte array:
// 1. convert byte array to string and then string to byte array
// convert byte array to string
byte[] by_original = {0, 1, -2, 3, -4, -5, 6};
String str1 = Arrays.toString(by_original);
System.out.println(str1); // output: [0, 1, -2, 3, -4, -5, 6]
// convert string to byte array
String newString = str1.substring(1, str1.length()-1);
String[] stringArray = newString.split(", ");
byte[] by_new = new byte[stringArray.length];
for(int i=0; i<stringArray.length; i++) {
by_new[i] = (byte) Integer.parseInt(stringArray[i]);
}
System.out.println(Arrays.toString(by_new)); // output: [0, 1, -2, 3, -4, -5, 6]
But to convert the string to byte array and then convert that byte array to string, below approach can be used:
// 2. convert string to byte array and then byte array to string
// convert string to byte array
String str2 = "[0, 1, -2, 3, -4, -5, 6]";
byte[] byteStr2 = str2.getBytes(StandardCharsets.UTF_8);
// Now byteStr2 is [91, 48, 44, 32, 49, 44, 32, 45, 50, 44, 32, 51, 44, 32, 45, 52, 44, 32, 45, 53, 44, 32, 54, 93]
// convert byte array to string
System.out.println(new String(byteStr2, StandardCharsets.UTF_8)); // output: [0, 1, -2, 3, -4, -5, 6]
A string is a collection of char's (16bit unsigned). So if you are going to convert negative numbers into a string, they'll be lost in translation.
public class byteString {
/**
* #param args
*/
public static void main(String[] args) throws Exception {
// TODO Auto-generated method stub
String msg = "Hello";
byte[] buff = new byte[1024];
buff = msg.getBytes("UTF-8");
System.out.println(buff);
String m = new String(buff);
System.out.println(m);
}
}
I have a double(float/Decimal) value and I want to get the same byte array as produced by Java ByteBuffer in C#.
However the byte array produced by using ByteBuffer.PutDouble in Java and BinaryWriter in C# is different. Can someone please explain the implementation detail difference between the two.
Java:
ByteBuffer bytes = ByteBuffer.allocate(8).putDouble(0,1.12346);
bytes[] = {63, -15, -7, -83, -45, 115, -106, 54};
C#:
double value = 1.12346;
byte[] arr;
using (MemoryStream stream = new MemoryStream())
{
using (BinaryWriter writer = new BinaryWriter(stream))
{
writer.Write(value);
arr = stream.ToArray();
}
}
arr[] = {153, 211, 101, 49, 177, 249, 241, 63};
ByteBuffer is big endian by default and bytes are signed.
In C#, it's little endian by default and bytes are unsigned.
You have the same data in the opposite order, from a serialization point of view, the sign of the bytes is not important except it is a little confusing.
In C# you can use the EndianBinaryWriter BinaryWriter Endian issue
I have to convert a byte array to string in Android, but my byte array contains negative values.
If I convert that string again to byte array, values I am getting are different from original byte array values.
What can I do to get proper conversion? Code I am using to do the conversion is as follows:
// Code to convert byte arr to str:
byte[] by_original = {0,1,-2,3,-4,-5,6};
String str1 = new String(by_original);
System.out.println("str1 >> "+str1);
// Code to convert str to byte arr:
byte[] by_new = str1.getBytes();
for(int i=0;i<by_new.length;i++)
System.out.println("by1["+i+"] >> "+str1);
I am stuck in this problem.
Your byte array must have some encoding. The encoding cannot be ASCII if you've got negative values. Once you figure that out, you can convert a set of bytes to a String using:
byte[] bytes = {...}
String str = new String(bytes, StandardCharsets.UTF_8); // for UTF-8 encoding
There are a bunch of encodings you can use, look at the supported encodings in the Oracle javadocs.
The "proper conversion" between byte[] and String is to explicitly state the encoding you want to use. If you start with a byte[] and it does not in fact contain text data, there is no "proper conversion". Strings are for text, byte[] is for binary data, and the only really sensible thing to do is to avoid converting between them unless you absolutely have to.
If you really must use a String to hold binary data then the safest way is to use Base64 encoding.
The root problem is (I think) that you are unwittingly using a character set for which:
bytes != encode(decode(bytes))
in some cases. UTF-8 is an example of such a character set. Specifically, certain sequences of bytes are not valid encodings in UTF-8. If the UTF-8 decoder encounters one of these sequences, it is liable to discard the offending bytes or decode them as the Unicode codepoint for "no such character". Naturally, when you then try to encode the characters as bytes the result will be different.
The solution is:
Be explicit about the character encoding you are using; i.e. use a String constructor and String.toByteArray method with an explicit charset.
Use the right character set for your byte data ... or alternatively one (such as "Latin-1" where all byte sequences map to valid Unicode characters.
If your bytes are (really) binary data and you want to be able to transmit / receive them over a "text based" channel, use something like Base64 encoding ... which is designed for this purpose.
For Java, the most common character sets are in java.nio.charset.StandardCharsets. If you are encoding a string that can contain any Unicode character value then UTF-8 encoding (UTF_8) is recommended.
If you want a 1:1 mapping in Java then you can use ISO Latin Alphabet No. 1 - more commonly just called "Latin 1" or simply "Latin" (ISO_8859_1). Note that Latin-1 in Java is the IANA version of Latin-1 which assigns characters to all possible 256 values including control blocks C0 and C1. These are not printable: you won't see them in any output.
From Java 8 onwards Java contains java.util.Base64 for Base64 encoding / decoding. For URL-safe encoding you may want to to use Base64.getUrlEncoder instead of the standard encoder. This class is also present in Android since Android Oreo (8), API level 26.
We just need to construct a new String with the array: http://www.mkyong.com/java/how-do-convert-byte-array-to-string-in-java/
String s = new String(bytes);
The bytes of the resulting string differs depending on what charset you use. new String(bytes) and new String(bytes, Charset.forName("utf-8")) and new String(bytes, Charset.forName("utf-16")) will all have different byte arrays when you call String#getBytes() (depending on the default charset)
Using new String(byOriginal) and converting back to byte[] using getBytes() doesn't guarantee two byte[] with equal values. This is due to a call to StringCoding.encode(..) which will encode the String to Charset.defaultCharset(). During this encoding, the encoder might choose to replace unknown characters and do other changes. Hence, using String.getBytes() might not return an equal array as you've originally passed to the constructor.
Why was the problem: As someone already specified:
If you start with a byte[] and it does not in fact contain text data, there is no "proper conversion". Strings are for text, byte[] is for binary data, and the only really sensible thing to do is to avoid converting between them unless you absolutely have to.
I was observing this problem when I was trying to create byte[] from a pdf file and then converting it to String and then taking the String as input and converting back to file.
So make sure your encoding and decoding logic is same as I did. I explicitly encoded the byte[] to Base64 and decoded it to create the file again.
Use-case:
Due to some limitation I was trying to sent byte[] in request(POST) and the process was as follows:
PDF File >> Base64.encodeBase64(byte[]) >> String >> Send in request(POST) >> receive String >> Base64.decodeBase64(byte[]) >> create binary
Try this and this worked for me..
File file = new File("filePath");
byte[] byteArray = new byte[(int) file.length()];
try {
FileInputStream fileInputStream = new FileInputStream(file);
fileInputStream.read(byteArray);
String byteArrayStr= new String(Base64.encodeBase64(byteArray));
FileOutputStream fos = new FileOutputStream("newFilePath");
fos.write(Base64.decodeBase64(byteArrayStr.getBytes()));
fos.close();
}
catch (FileNotFoundException e) {
System.out.println("File Not Found.");
e.printStackTrace();
}
catch (IOException e1) {
System.out.println("Error Reading The File.");
e1.printStackTrace();
}
Even though
new String(bytes, "UTF-8")
is correct it throws a UnsupportedEncodingException which forces you to deal with a checked exception. You can use as an alternative another constructor since Java 1.6 to convert a byte array into a String:
new String(bytes, StandardCharsets.UTF_8)
This one does not throw any exception.
Converting back should be also done with StandardCharsets.UTF_8:
"test".getBytes(StandardCharsets.UTF_8)
Again you avoid having to deal with checked exceptions.
private static String toHexadecimal(byte[] digest){
String hash = "";
for(byte aux : digest) {
int b = aux & 0xff;
if (Integer.toHexString(b).length() == 1) hash += "0";
hash += Integer.toHexString(b);
}
return hash;
}
I did notice something that is not in any of the answers. You can cast each of the bytes in the byte array to characters, and put them in a char array. Then the string is new String(cbuf) where cbuf is the char array. To convert back, loop through the string casting each of the chars to bytes to put into a byte array, and this byte array will be the same as the first.
public class StringByteArrTest {
public static void main(String[] args) {
// put whatever byte array here
byte[] arr = new byte[] {-12, -100, -49, 100, -63, 0, -90};
for (byte b: arr) System.out.println(b);
// put data into this char array
char[] cbuf = new char[arr.length];
for (int i = 0; i < arr.length; i++) {
cbuf[i] = (char) arr[i];
}
// this is the string
String s = new String(cbuf);
System.out.println(s);
// converting back
byte[] out = new byte[s.length()];
for (int i = 0; i < s.length(); i++) {
out[i] = (byte) s.charAt(i);
}
for (byte b: out) System.out.println(b);
}
}
This works fine for me:
String cd = "Holding some value";
Converting from string to byte[]:
byte[] cookie = new sun.misc.BASE64Decoder().decodeBuffer(cd);
Converting from byte[] to string:
cd = new sun.misc.BASE64Encoder().encode(cookie);
Following is the sample code safely converts byte array to String and String to byte array back.
byte bytesArray[] = { 1, -2, 4, -5, 10};
String encoded = java.util.Base64.getEncoder().encodeToString(bytesArray);
byte[] decoded = java.util.Base64.getDecoder().decode(encoded);
System.out.println("input: "+Arrays.toString(bytesArray));
System.out.println("encoded: "+encoded);
System.out.println("decoded: "+Arrays.toString(decoded));
Output:
input: [1, -2, 4, -5, 10]
encoded: Af4E+wo=
decoded: [1, -2, 4, -5, 10]
javax.xml.bind.DatatypeConverter should do it:
byte [] b = javax.xml.bind.DatatypeConverter.parseHexBinary("E62DB");
String s = javax.xml.bind.DatatypeConverter.printHexBinary(b);
byte[] bytes = "Techie Delight".getBytes();
// System.out.println(Arrays.toString(bytes));
// Create a string from the byte array without specifying
// character encoding
String string = new String(bytes);
System.out.println(string);
Heres a few methods that convert an array of bytes to a string. I've tested them they work well.
public String getStringFromByteArray(byte[] settingsData) {
ByteArrayInputStream byteArrayInputStream = new ByteArrayInputStream(settingsData);
Reader reader = new BufferedReader(new InputStreamReader(byteArrayInputStream));
StringBuilder sb = new StringBuilder();
int byteChar;
try {
while((byteChar = reader.read()) != -1) {
sb.append((char) byteChar);
}
}
catch(IOException e) {
e.printStackTrace();
}
return sb.toString();
}
public String getStringFromByteArray(byte[] settingsData) {
StringBuilder sb = new StringBuilder();
for(byte willBeChar: settingsData) {
sb.append((char) willBeChar);
}
return sb.toString();
}
While base64 encoding is safe and one could argue "the right answer", I arrived here looking for a way to convert a Java byte array to/from a Java String as-is. That is, where each member of the byte array remains intact in its String counterpart, with no extra space required for encoding/transport.
This answer describing 8bit transparent encodings was very helpful for me. I used ISO-8859-1 on terabytes of binary data to convert back and forth successfully (binary <-> String) without the inflated space requirements needed for a base64 encoding, so is safe for my use-case - YMMV.
This was also helpful in explaining when/if you should experiment.
Using Kotlin on Android I found out it is handy to create some simple extension functions for that purpose.
Solution based on Base64 encoding/decoding to be able to pass via JSON, XML, etc:
import android.util.Base64
fun ByteArray.encodeToString() = String(Base64.encode(this, Base64.NO_WRAP), Charsets.UTF_8)
fun String.decodeToBytes(): ByteArray = Base64.decode(toByteArray(Charsets.UTF_8), Base64.NO_WRAP)
So you can use it
val byteArray = byteArrayOf(0, 1, 2, -1, -2, -3)
val string = byteArray.encodeToString()
val restoredArray = string.decodeToBytes()
import sun.misc.BASE64Decoder;
import sun.misc.BASE64Encoder;
private static String base64Encode(byte[] bytes)
{
return new BASE64Encoder().encode(bytes);
}
private static byte[] base64Decode(String s) throws IOException
{
return new BASE64Decoder().decodeBuffer(s);
}
I succeeded converting byte array to a string with this method:
public static String byteArrayToString(byte[] data){
String response = Arrays.toString(data);
String[] byteValues = response.substring(1, response.length() - 1).split(",");
byte[] bytes = new byte[byteValues.length];
for (int i=0, len=bytes.length; i<len; i++) {
bytes[i] = Byte.parseByte(byteValues[i].trim());
}
String str = new String(bytes);
return str.toLowerCase();
}
This one works for me up to android Q:
You can use the following method to convert o hex string to string
public static String hexToString(String hex) {
StringBuilder sb = new StringBuilder();
char[] hexData = hex.toCharArray();
for (int count = 0; count < hexData.length - 1; count += 2) {
int firstDigit = Character.digit(hexData[count], 16);
int lastDigit = Character.digit(hexData[count + 1], 16);
int decimal = firstDigit * 16 + lastDigit;
sb.append((char)decimal);
}
return sb.toString();
}
with the following to convert a byte array to a hex string
public static String bytesToHex(byte[] bytes) {
char[] hexChars = new char[bytes.length * 2];
for (int j = 0; j < bytes.length; j++) {
int v = bytes[j] & 0xFF;
hexChars[j * 2] = hexArray[v >>> 4];
hexChars[j * 2 + 1] = hexArray[v & 0x0F];
}
return new String(hexChars);
}
Here the working code.
// Encode byte array into string . TemplateBuffer1 is my bytearry variable.
String finger_buffer = Base64.encodeToString(templateBuffer1, Base64.DEFAULT);
Log.d(TAG, "Captured biometric device->" + finger_buffer);
// Decode String into Byte Array. decodedString is my bytearray[]
decodedString = Base64.decode(finger_buffer, Base64.DEFAULT);
You can use simple for loop for conversion:
public void byteArrToString(){
byte[] b = {'a','b','$'};
String str = "";
for(int i=0; i<b.length; i++){
char c = (char) b[i];
str+=c;
}
System.out.println(str);
}
byte[] image = {...};
String imageString = Base64.encodeToString(image, Base64.NO_WRAP);
Try to specify an 8-bit charset in both conversions. ISO-8859-1 for instance.
Read the bytes from String using ByteArrayInputStream and wrap it with BufferedReader which is Char Stream instead of Byte Stream which converts the byte data to String.
package com.cs.sajal;
import java.io.BufferedReader;
import java.io.ByteArrayInputStream;
import java.io.InputStreamReader;
import java.io.UnsupportedEncodingException;
public class TestCls {
public static void main(String[] args) {
String s=new String("Sajal is a good boy");
try
{
ByteArrayInputStream bis;
bis=new ByteArrayInputStream(s.getBytes("UTF-8"));
BufferedReader br=new BufferedReader(new InputStreamReader(bis));
System.out.println(br.readLine());
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
Output is:
Sajal is a good boy
You can do the following to convert byte array to string and then convert that string to byte array:
// 1. convert byte array to string and then string to byte array
// convert byte array to string
byte[] by_original = {0, 1, -2, 3, -4, -5, 6};
String str1 = Arrays.toString(by_original);
System.out.println(str1); // output: [0, 1, -2, 3, -4, -5, 6]
// convert string to byte array
String newString = str1.substring(1, str1.length()-1);
String[] stringArray = newString.split(", ");
byte[] by_new = new byte[stringArray.length];
for(int i=0; i<stringArray.length; i++) {
by_new[i] = (byte) Integer.parseInt(stringArray[i]);
}
System.out.println(Arrays.toString(by_new)); // output: [0, 1, -2, 3, -4, -5, 6]
But to convert the string to byte array and then convert that byte array to string, below approach can be used:
// 2. convert string to byte array and then byte array to string
// convert string to byte array
String str2 = "[0, 1, -2, 3, -4, -5, 6]";
byte[] byteStr2 = str2.getBytes(StandardCharsets.UTF_8);
// Now byteStr2 is [91, 48, 44, 32, 49, 44, 32, 45, 50, 44, 32, 51, 44, 32, 45, 52, 44, 32, 45, 53, 44, 32, 54, 93]
// convert byte array to string
System.out.println(new String(byteStr2, StandardCharsets.UTF_8)); // output: [0, 1, -2, 3, -4, -5, 6]
A string is a collection of char's (16bit unsigned). So if you are going to convert negative numbers into a string, they'll be lost in translation.
public class byteString {
/**
* #param args
*/
public static void main(String[] args) throws Exception {
// TODO Auto-generated method stub
String msg = "Hello";
byte[] buff = new byte[1024];
buff = msg.getBytes("UTF-8");
System.out.println(buff);
String m = new String(buff);
System.out.println(m);
}
}
I am trying to read data of a .wav file both in java and matlab and save as an array of bytes.
In java the code looks as follows:
public byte[] readWav2(File file) throws UnsupportedAudioFileException, IOException {
AudioFormat audioFormat;
AudioInputStream inputAIS = AudioSystem.getAudioInputStream(file);
audioFormat = inputAIS.getFormat();
ByteArrayOutputStream baos = new ByteArrayOutputStream();
// Read the audio data into a memory buffer.
int nBufferSize = BUFFER_LENGTH * audioFormat.getFrameSize();
byte[] abBuffer = new byte[nBufferSize];
while (true) {
int nBytesRead = inputAIS.read(abBuffer);
if (nBytesRead == -1) {
break;
}
baos.write(abBuffer, 0, nBytesRead);
}
byte[] abAudioData = baos.toByteArray();
return abAudioData;
}
In matlab I am using the wavread function:
[Y, FS] = wavread('sound.wav', 'native');
But the results I am getting are different.
In java the first 20 bytes:
53, 0, 19, 0, -71, -1, -80, -1, -99, -1, 10, 0, 87, 0, -69, -1, 123, -1, -77, -1
In matlab:
53, 19, -71, -80, -99, 10, 87, -69, -133, -77, 38, 143, 13, -100, 39, 45, -52, -83, -82, 56
Why every second byte in java is 0 or -1 where in matlab there isn't? Even though I skip the 0's and -1's where in java there is 123 for matlab there is -133? Why is it different?
Java is returning you 16-bit signed PCM data. Since each sample is 16 bits and a byte holds 8 bits, each sample spans two bytes in Java. What Matlab returns you is an array of the 16-bit samples directly.
Basically, the data is the same. It's just laid out differently in memory.
To access the samples in an easier way from Java you could do some bitwise arithmetic, like this:
int firstSample = (abAudioData[0]&0xFF) | (abAudioData[1]<<8);
Another way to read the samples is with the java.nio buffers:
ByteBuffer bb = ByteBuffer.wrap(abAudioData);
bb.order(ByteOrder.LITTLE_ENDIAN);
ShortBuffer sb = bb.asShortBuffer();
int firstSample = sb.get();