I want to know the best way how to notify another thread. For example, I have a background thread:
public void StartBackgroundThread(){
new Thread(new Runnable() {
#Override
public void run() {
//Do something big...
//THEN HOW TO NOTIFY MAIN THREAD?
}
}).start();
}
When it finished it has to notify main thread? If somebody knows the best way how to do this I'll appreciate it!
The typical answer is a BlockingQueue. Both BackgroundThread (often called the Producer) and MainThread (often called the Consumer) share a single instance of the queue (perhaps they get it when they are instantiated). BackgroundThread calls queue.put(message) each time it has a new message and MainThread calls 'queue.take()which will block until there's a message to receive. You can get fancy with timeouts and peeking but typically people want aBlockingQueueinstance such asArrayBlockingQueue`.
Purely based on your question you could do this:
public class test
{
Object syncObj = new Object();
public static void main(String args[])
{
new test();
}
public test()
{
startBackgroundThread();
System.out.println("Main thread waiting...");
try
{
synchronized(syncObj)
{
syncObj.wait();
}
}
catch(InterruptedException ie) { }
System.out.println("Main thread exiting...");
}
public void startBackgroundThread()
{
(new Thread(new Runnable()
{
#Override
public void run()
{
//Do something big...
System.out.println("Background Thread doing something big...");
//THEN HOW TO NOTIFY MAIN THREAD?
synchronized(syncObj)
{
System.out.println("Background Thread notifing...");
syncObj.notify();
}
System.out.println("Background Thread exiting...");
}
})).start();
}
}
and see this output
PS C:\Users\java> javac test.java
PS C:\Users\java> java test
Main thread waiting...
Background Thread doing something big...
Background Thread notifing...
Background Thread exiting...
Main thread exiting...
Just call notify()
public void run() {
try {
while ( true ) {
putMessage();
sleep( 1000 );
}
}
catch( InterruptedException e ) { }
}
private synchronized void putMessage() throws InterruptedException {
while ( messages.size() == MAXQUEUE )
wait();
messages.addElement( new java.util.Date().toString() );
notify();
}
You can't "notify the main thread".
The best approach is to use an ExecutorService, like this for example:
import java.util.concurrent.*;
// in main thread
ExecutorService executorService = Executors.newSingleThreadExecutor();
Future<?> future = executorService.submit(new Runnable() {
#Override
public void run() {
//Do something big...
}
});
future.get(); // blocks until the Runnable finishes
The classes are written specially to deal with asynchronous operations, and all the code in there is already written for you and bullet-proof.
Edit
If you don't want to block the main thread while waiting, wait within another thread:
final Future<?> future = executorService.submit(new Runnable() {
#Override
public void run() {
//Do something big...
}
});
new Thread(new Runnable() {
#Override
public void run() {
future.get(); // blocks until the other Runnable finishes
// Do something after the other runnable completes
}
}).start();
One thread notifying another thread is not a good way to do it. Its better to have 1 master thread that gives the slave thread work. The slave thread is always running and waits until it receives work. I recommend that you draw two columns and determine exactly where each thread needs to wait.
public void run()
{
//Do something big...
synchronized(this)
{
done = true;
}
}
Java includes libraries that make this really easy see ExecutorService and the following post
Producer/Consumer threads using a Queue
Related
I have a long running Runnable object and I wanted to provide a more graceful interrupt mechanism than having to call interrupt on the thread the object is running on.
The before code:
public class MyRunnable implements Runnable {
public void run() {
while(!Thread.currentThread().isInterrupted()) {
//do stuff
}
}
}
public class MyClass {
public static void main(String[] args) {
Runnable myRunnable = new MyRunnable();
Thread t = new Thread(myRunnable, "myRunnableThread");
t.start();
//do stuff
t.interrupt();
//do stuff
}
}
And the new code:
public class MyRunnable implements Runnable {
private Thread myThread = null;
public void run() {
myThread = Thread.currentThread();
while(!myThread.isInterrupted()) {
//do stuff
}
}
public void shutdown() {
if (myThread != null) {
myThread.interrupt();
//do other shutdown stuff
}
}
}
public class MyClass {
public static void main(String[] args) {
Runnable myRunnable = new MyRunnable();
Thread t = new Thread(myRunnable, "myRunnableThread");
t.start();
//do stuff
myRunnable.shutdown();
//do stuff
}
}
My question is, are there possible side effects or unknowns that holding a reference to your own thread, and providing limited access to that thread through public methods (as above) could cause? This is assuming that no-one ever calls the run() method directly, that it is always started from a new thread.
And I'm aware that I could use a volatile or atomic Boolean in the run() and shutdown() methods for communicating intent to shutdown, I'm more interested in learning than a solution. But solutions are still welcome!
For me your first approach is much better as less error prone and more "standard". But actually what you try to implement already exists (which proves that it makes sense and that it is not a bad practice but it is not easy to make it properly), it is called FutureTask, instead of shutdown you have cancel(boolean mayInterruptIfRunning) with true as value of mayInterruptIfRunning if you want to interrupt the thread running the task, I quote the javadoc:
Attempts to cancel execution of this task. This attempt will fail if
the task has already completed, has already been cancelled, or could
not be cancelled for some other reason. If successful, and this task
has not started when cancel is called, this task should never run. If
the task has already started, then the mayInterruptIfRunning
parameter determines whether the thread executing this task should be
interrupted in an attempt to stop the task.
For example:
// Task that will only sleep for 1 sec and print a message on interrupted
FutureTask<Void> myRunnable = new FutureTask<>(
new Callable<Void>() {
#Override
public Void call() throws Exception {
try {
System.out.println("Sleep");
Thread.sleep(1_000L);
} catch (InterruptedException e) {
System.out.println("Interrupted !!!");
throw e;
}
return null;
}
}
);
new Thread(myRunnable, "myRunnableThread").start();
// Wait long enough to make sure that myRunnableThread is sleeping
Thread.sleep(500L);
// Cancel the task and interrupt myRunnableThread
myRunnable.cancel(true);
Output:
Sleep
Interrupted !!!
It already has a reference:
Thread.currentThread()
From the javadoc:
Returns a reference to the currently executing thread object.
I want to have a class that starts a Thread and provides methods to pause and continue this Thread. My first approach was to have flag, which loops a sleep method as long as the value is true. Something like :
public class Bot {
private Thread t ;
private boolean isPaused;
public Bot(){
t = new Thread(new Runnable(){
#Override
public void run() {
while (true) {
System.out.println("Hi");
while(isPaused){
try {
Thread.sleep(200);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
});
t.start();
}
public void pauseBot(){
isPaused = true;
}
public void continueBot(){
isPaused = false;
}
}
But since the Thread is still running and wasting CPU, I dont find this to be a good solution. How would this look with wait() and notify().
I had a look at various tutorials about that topic but somehow I couldnt apply them to my issue.
Everytime I tried it I either got IllegalMonitorStateException or the code stopped my whole application and not just the Thread I wanted to be stopped.
Another question I have is: How do prevent the Thread from beeing paused at a critical moment e.g.
Runnable r = new Runnable(){
#Override
public void run() {
while(true){
task1();
task2();
//Thread mustn't be stopped from here....
task3();
task4();
task5();
task6();
task7();
//... to here
task8();
task9();
task10();
}
}
};
Because when task3() .... task7() deal with something that would expire while the Thread is paused there must be a way to let the Thread finish task7() until it pauses.
I hope you can help me with my issue.
Thanks in advance,
Flo
So given this is your Thread class:
public class MyThread extends Thread
{
First, you need an lock object. This object can be everything, and if you use an existing object this takes less memory. Also define a flag if the bot should be paused.
public Object lock = this;
public boolean pause = false;
Now, define a pause() and continue() method for the thread. This sets the pause flag.
public void pause ()
{
pause = true;
}
public void continue ()
{
pause = false;
Here you need to wake up the thread. Note the synchronized on the lock object so that you don't get an IllegalMonitorStateException.
synchronized (lock)
{
lock.notifyAll();
}
}
No, define a method that automatically pauses the thread when it should be paused. You might call this at every moment when the thread can be paused.
private void pauseThread ()
{
synchronized (lock)
{
if (pause)
lock.wait(); // Note that this can cause an InterruptedException
}
}
Now, you can define your thread in the run() method:
public void run ()
{
task1();
task2();
pauseThread();
task3();
task4();
task5();
task6();
task7();
pauseThread();
task8();
task9();
task10();
}
}
I am new to the Threading, so if please give me an advice for my case.
I would like create a new thread to do something and I don't care this thread can do complete or not.
I intend to use ExecutorCompletionService to do my job but this class is not suitable for me. It must call take or poll to drain a queue to avoid memory leak. So, this means I must wait until the thread complete. I read this from this question
This is the current code
ExecutorService executor = Executors.newCachedThreadPool();
CompletionService<Entity> completion = new ExecutorCompletionService<>(executor);
DoSomeThingClass doSomething = getInstance();
completion.submit(doSomething);
executor.shutdown();
// Continue to do other job and I don't care whenever doSomeThing is complete.
// However when doSomeThing finish, I don't need to do anything to avoid memory leak
For that reason, please give me an approach for my case and some skeleton code for example.
Thank you so much
You can mark this thread as "Daemon". And when your main thread completed, your app will exit.
public static void main(String[] args)
{
Thread t = new Thread(new Runnable() {
#Override
public void run() {
try {
TimeUnit.SECONDS.sleep(2);
} catch(InterruptedException e) {}
System.out.println("Thread 2 is finished");
}
});
t.setDaemon(true);
t.start();
System.out.println("Thread 1 is finished");
}
You can use Spring TaskExecutor, it is very useful to raise a thread to run a task.
import org.springframework.core.task.TaskExecutor;
public class TaskExecutorExample {
private class MessagePrinterTask implements Runnable {
private String message;
public MessagePrinterTask(String message) {
this.message = message;
}
public void run() {
System.out.println(message);
}
}
private TaskExecutor taskExecutor;
public TaskExecutorExample(TaskExecutor taskExecutor) {
this.taskExecutor = taskExecutor;
}
public void printMessages() {
for(int i = 0; i < 25; i++) {
taskExecutor.execute(new MessagePrinterTask("Message" + i));
}
}
}
You can check Spring Task Execution documentation here:
http://docs.spring.io/spring/docs/3.0.x/spring-framework-reference/html/scheduling.html
Along with you code your Future concept
Future ft=completion.submit(doSomething);
ft.get(timeOut, TimeUnit.MILLISECONDS);
here you can specify Time to execute Thread if it fail to get execute thread get kill(not 100% sure)means it try to interrupt the thread and try to kill
I can resolve my problem as the following code
public static void main(
String[] args) {
ExecutorService executor = Executors.newCachedThreadPool();
executor.execute(new Runnable() {
#Override
public void run() {
try {
TimeUnit.SECONDS.sleep(2);
} catch (InterruptedException e) {
} finally {
System.out.println("Thread 2 is finished");
}
}
});
executor.shutdown();
System.out.println("Thread 1 is finished");
}
This question already has answers here:
How to properly stop the Thread in Java?
(9 answers)
Closed 9 years ago.
I am having a problem trying to stop a thread instantly after a certain amount of time has elapsed, because thread.stop and similar others have been depreciated.
The thread that I am trying to stop uses my mouse and I need to stop it so that I can use my mouse in other ways.
What I was thinking is the code below, which was just to make another thread to watch how long the main thread has been running and if it is alive, stop it, but I can't accomplish this.
public void threadRun(int a) {
Thread mainThread = new Thread(new Runnable() {
#Override
public void run() {
// does things with mouse which may need to be ended while they
// are in action
}
});
Thread watchThread = new Thread(new Runnable() {
#Override
public void run() {
if (timeFromMark(mark) > a) {
if (mainThread.isAlive()) {
// How can I stop the mainThread?
}
}
}
});
}
You need to define a class for your second thread that extends runnable and pass the first thread as an argument.
Then you can stop the first thread.
But instead of doing this manually, have a look at the Java ThreadPoolExecuter and its awaitTermination(long timeout, TimeUnit unit) method. (http://docs.oracle.com/javase/7/docs/api/java/util/concurrent/ThreadPoolExecutor.html )
Will save a lot of work.
ExecutorService executor = Executors.newFixedThreadPool(1);
Runnable r = new Runnable() {
#Override
public void run() {
// TODO Auto-generated method stub
try {
System.out.println("doing stuff");
Thread.sleep(10000);
System.out.println("finished");
} catch (InterruptedException e) {
System.out.println("Interrupted before finished!");
}
}
};
executor.execute(r);
executor.shutdown();
try {
executor.awaitTermination(1, TimeUnit.SECONDS);
executor.shutdownNow();
} catch (InterruptedException e) {
//
}
System.out.println("Thread worker forced down. Continue with Application...");
Produces:
doing stuff
Interrupted before finished!
Thread worker forced down. Continue with Application...
Last two messages are nearly equal in terms of time and may change positions (its two different threads, continuing)
Java has deprecated methods for explicitly killing another thread (like Thread.stop / Thread.destroy). The right way is to make sure the operations on the other thread can handle being told to stop (for example, they expect an InterruptedException, which means you can call Thread.interrupt() in order to stop it).
Taken from How do I kill a thread from another thread in Java?
Killing/stopping threads is a bad idea. That's why they deprecated those methods. It's better to ask the thread to stop. E.g., something like the example below. (But note: if "do_something()" takes a long time, then you might want to use an interrupt to abort whatever it is.)
import java.util.concurrent.atomic.AtomicBoolean;
public class Stoppable {
private AtomicBoolean timeToDie = new AtomicBoolean(false);
private Thread thread;
public void start() {
if (thread != null) {
throw new IllegalStateException("already running");
}
thread = new Thread(new Runnable() {
public void run() {
while (!timeToDie.get()) {
// do_something();
}
}
});
thread.start();
}
public void stop() throws InterruptedException {
timeToDie.set(true);
thread.join();
thread = null;
}
}
I want a method that runs 2 or more methods in separate threads. I want be sure that method won't finish before all threads are done.
The best approach is to utilize the Executor Service API to manage a thread pool instead of starting an open-ended number of threads on your own.
ExecutorService pool = Executors.newCachedThreadPool();
for (Runnable r : new Runnable[] {
new R() { void r() { myMethod1(); }},
new R() { void r() { myMethod2(); }},
})
pool.execute(r);
pool.shutdown();
pool.awaitTermination(60, TimeUnit.SECONDS);
abstract class R implements Runnable
public final void run() { r(); }
abstract void r();
}
Note that it is not advisable to insist on every method running in its own, separate thread. Threads are quite heavyweight (each allocating a complete call stack) and performance actually decreases as the thread count increases far beyond the number of available processor cores.
I prefer something like this:
public static void runParallel(Runnable... runnables) throws InterruptedException {
final CountDownLatch done = new CountDownLatch(runnables.length);
for (final Runnable r: runnables) {
new Thread(new Runnable() {
public void run() {
try {
r.run();
} finally {
done.countDown();
}
}
}).start();
}
done.await();
}
An advantage of this approach is that it also works with thread pool (i.e. you can replace new Thread(...).start() with executor.submit(...)).
Also it allows you to use pre-existing thread pool, unlike solutions based on awaitTermination() that force you to create new pools for each invocation.
My solution is
Function:
public void runParallel(Runnable... runnables) throws InterruptedException {
List<Thread> threads = new ArrayList<Thread>(runnables.length);
for (Runnable runnable :runnables) {
Thread th = new Thread(runnable);
threads.add(th);
th.start();
}
for (Thread th : threads) {
th.join();
}
Use:
runParallel(new Runnable() {
#Override
public void run() {
method1()
}
}, new Runnable() {
#Override
public void run() {
method2()
}
}
);
any better ideas? Maybe there is a shorter way that I'm not aware of ;)
Following the API given by damienix:
public void runParallel(Runnable... runnables) throws InterruptedException {
final ExecutorService pool = Executors.newFixedThreadPool(runnables.length);
for (Runnable runnable: runnables) {
pool.submit(runnable);
}
pool.shutdown();
pool.awaitTermination(1, TimeUnit.MINUTES);
}