check if a class contains a method - java

I have a abstract class to create tools (like illustrator pen, selection etc).
The idea is that users can create easily new tools if they like.
Some tools have a method called, "draggingSelection".
I wonder if there is a way to check if a class has that object, and if so, run it.
(In this case draggingSelection returns a boolean)
So far i can figure out if the method exists or not.
I only can't get it the method to run.
I tried things with invoke but i fail at it. My method doesn't requite any parameters.
Could somone help.
public boolean draggingSelection() {
Method[] meths = activeTool.getClass().getMethods();
for (int i = 0; i < meths.length; i++) {
if (meths[i].getName().equals("draggingSelection")) {
// how can i run it?
//return meths[i].draggingSelection(); // wrong
}
}
return false;
}

Better solution in my opinion is to check if given object's class implements some interface.
However, to call draggingSelection method, do it on an object that you are testing:
activeTool.draggingSelection()

You could do that via reflection, but a far better solution would be to have an interface that has all the relevant methods:
public interface SelectionAware {
public void draggingSelection(SelectionEvent e);
}
Once you have that, you have (at least) two options to use it:
let your tools implement that interface and use myTool instanceof SelectionAware followed by a cast to call that method or
let the tool explicitly register itself as a listener in some appropriate init method.
Option 1 is closer to what you attempted to do, but restricts the use of that interface and is not really clean code (because your code needs to "guess" if some tool implements some interface).
Option 2 is probably slightly more work (where/when to register/unregister the listener? ...), but is definitely the cleaner approach. It also has the advantage that the listeners are not restricted to being tools: anything could register such a listener.

public interface Draggable {
public boolean draggingSelection(int foo, int bar);
}
Then when you have a class with this method just add implements Draggable. Example:
public class Selection implements Draggable {
public boolean draggingSelection(int foo, int bar) {
(insert code here)
return baz;
}
(insert rest of code here)
}
Therefore your example would be:
if (activeTool instanceof Draggable) {
((Draggable)activeTool).draggingSelection(foo, bar);
}

Related

How to verify whether a super class method was called in Spock?

Imagine I had the following class structure:
class Parent {
public void method() {
// Some calculations
}
}
class Child extends Parent {
#Override
public void method() {
super.method();
// Some additional logic
}
}
I am spock-testing the Child.method and want to verify if the Parent.method is called from the Child.method. I did some research and i haven't found any satisfying solution to solve my problem.
How can I verify in a Spock test that in the call of Child.method the superclass method (Parent.method) was called as well?
Known solution: In Child move the super.method() to a separate, package-private method.
I want to know whether there is a better solution.
tim_yates commented:
Why do you want to test this? Can't you tell as the super class calculations were performed?
I completely agree. I would not test this because as #Override implies, the contract is an override, delegation to the super class method is optional. Why would you force your users to call the super class method? But as Tim said, you can test for the side effects which are important to you. Here is a little example with one side effect being a field assignment and another being something written to System.out (maybe silly, but just in order to show something non-obvious with a mock):
package de.scrum_master.stackoverflow.q60167623;
public class Parent {
protected String name;
public void method() {
// Some calculations
System.out.println("parent method");
name = "John Doe";
}
}
package de.scrum_master.stackoverflow.q60167623;
class Child extends Parent {
#Override
public void method() {
super.method();
// Some additional logic
System.out.println("child method");
}
public static void main(String[] args) {
new Child().method();
}
}
package de.scrum_master.stackoverflow.q60167623
import spock.lang.Specification
class ChildTest extends Specification {
static final PrintStream originalSysOut = System.out
PrintStream mockSysOut = Mock()
def setup() {
System.out = mockSysOut
}
def cleanup() {
System.out = originalSysOut
}
def test() {
given:
def child = new Child()
when:
child.method()
then:
1 * mockSysOut.println({ it.contains("parent") })
child.name == "John Doe"
}
}
Update: What you want to do simply is not possible technically, and for a reason: It would break encapsulation, see here, here, indirectly also here. The method is overridden, the word says it all. Test for the (side) effect or the result of a method, not for its interaction (that it is actually called). Spock's interaction testing capabilities are over-used even though the Spock manual warns about over-specification in some places. It just makes your tests brittle. Interaction testing is okay for design patterns like publish/subscribe (Observer pattern) where it makes sense to test the interactions between objects as such.
If you need to enforce that some functionality in Parent is called, you should enforce it via design not tests.
abstract class Parent {
public final void method() {
// Some calculations
additionalLogic();
}
protected abstract void additionalLogic();
}
class Child extends Parent {
#Override
protected void additionalLogic() {
super.method();
// Some additional logic
}
}
You could of course not make it abstract and just add a no-op implementation for additionalLogic() instead.
tim_yates and kriegaex are the big beasts in the jungle when it comes to good and bad Spock, or TDD-style testing generally ... they have more than once (rightly) picked apart my questions in the way they do here, basically on the basis of testing the code rather than the implementation.
Sometimes it's difficult though. Maybe there can be cases in which you would want to test for the calling of super.doSomething(). I am just putting together, using TDD, having already done a "spike", in which I rushed ahead without testing, an editor for a TreeTableView. The "spike" can be seen here. In a constructive comment to my answer, kleopatra advised me to check (i.e. put an if in the app code) to make sure that super.startEdit() had indeed started the editing of the cell before going further, so in this case it is not sufficient to test the "side-effect" of super.startEdit() as being that isEditing() now returns true. You genuinely need to know that your class's startEdit() actually does nothing more nor less than call super.startEdit().
However, I don't believe it can be done, and tim_yates or kriegaex would almost certainly have said how you could do that if it were possible.
My suggested TDD solution would therefore be something like this:
def 'super start edit should be called if cell is not empty'(){
given:
// NB has to be GroovySpy because isEmpty() is final
DueDateEditor editor = GroovySpy( DueDateEditor ){
isEmpty() >> false
}
when:
editor.startEdit()
then:
1 * editor.callSuperStartEdit()
}
class DueDateEditor extends TreeTableCell {
#Override
void startEdit(){
if( ! isEmpty() ) {
// this is the line you have to add to make the test pass
callSuperStartEdit()
}
}
def callSuperStartEdit(){
super.startEdit()
}
}
I think you have to "spawn" an artificial single-purpose method since there is, precisely, no side effect at all!
PS I will in fact parameterise this test so that it returns true to isEmpty() in the second call, and require the method NOT to be called in that case.
I´ve never used the Spock framework, but i think you can check the type of the instance in the Parent.method with instance of operator or reflection.

Polymorphism with Static Methods

I'm creating a Mario clone where everything on the screen is an instance of ScreenElement. A ScreenElement is Landable if it can be landed on by Mario.
public class ScreenElement {
public boolean isLandable() {
return false;
}
}
Some classes override isLandable, for example:
public class GrassBlock extends ScreenElement {
#Override
public boolean isLandable() {
return true;
}
}
And classes that don't override isLandable should inherit it from the closest super class that does. That is to say, I need polymorphism.
Now this all works fine as long as isLandable is an instance method. However whether or not a given ScreenElement is Landable depends on the class, not the instance. So isLandable should really be static. But if I make it static, I cannot override it or inherit in sub classes that don't explicitly define it. Is there a simple workaround to this problem.
EDIT:
I do realize that the way I have it set up right now, it is working correctly but the reason I am bringing this up is because I have encountered a problem. Given a class that extends ScreenElement, I need to find out the result of isLandable. The only thing I could think of was this:
private <S extends ScreenElement> boolean isThisLandable(Class<S> category) {
return category.newInstance().isLandable();
}
I have to create a new instance to figure out something that doesn't depend on the instance, and this seems unnatural.
EDIT 2: Here's the specific piece of code that I'm dealing with.
private <S extends ScreenElement> S getGenericScreenElement(Mario mario, Class<S> category) {
for (ScreenElement element : screenElements) {
if (category.isInstance(element)) {
S elementToTest = category.cast(element);
if (elementToTest.isLandable()) {
//return elementToTest if it matches additional criteria
}
}
}
return null;
}
You're overthinking this.
In a nutshell, this code is doing exactly what you want it to do.
Here's what happens.
Your parent class, ScreenElement, defines by the isLandable() method by default, and it is always set to return false. By creating a new class that is a ScreenElement, if they wish to change this behavior, they must override that method to do so.
The fact that your GrassBlock does override this method is indicative that any instance of a GrassBlock will register true if its isLandable() property is checked.
With your code revision, you're still overthinking this.
All you need to do when you attempt to use an instance of ScreenElement - be that an instance of ScreenElement or any of its children - is to just call the method.
You shouldn't care about that property until you decide to check it, during its run. The way you're checking it now makes very little sense at all.
As an example:
ScreenElement vanillaElement = new ScreenElement();
GrassBlock block = new GrassBlock();
System.out.println(vanillaElement.isLandable()); // will print false
System.out.println(block.isLandable()); // will print true
More explicitly, with your sample code, you can greatly reduce it. Many of your statements to check against the type are unnecessary, especially when casting. You're guaranteed to have nothing more than a ScreenElement, and since isLandable() is defined on at least that, you will never run into a scenario in which you cannot call that method.
The above will turn your code into this. I leave the addition of your Mario parameter up to you since its purpose is unclear in this method.
private ScreenElement getGenericScreenElement(Mario mario) {
for (ScreenElement element : screenElements) {
if (element.isLandable()) {
//return element if it matches additional criteria
}
}
return null;
}
The fact that you need the methods to be overrideable and you want to do polymorphic dispatching means that they should not be static methods.
However whether or not a given ScreenElement is Landable depends on the class, not the instance.
So make the methods instance methods without using the instance state.

Questions on classes extending from a base class (Java)

I'm a beginner in Java trying to write a system of party quests for a game that I'm currently writing and I have a few questions I'd like to be answered. I've already gone around and asked other people, but they're not familiar in Java.
In the past I'd tried making a bunch of classes and accessing them with multiple get methods. I found that incredibly tedious to write and thought I could unify them under an abstract class/implemented class. Thus, the code looked more like this ...
DynastyPQInterface pq = new CustomPQ // or ....
DynastyPQInterface pq = new OtherCustomPQ
Of course, this presented difficulties such as being only able to use implemented methods. It didn't allow me to access the class' exclusive methods that I might want to use later on.
Ultimately, what I want to do is to be able to use a single get method to return any of these derived classes, but still retain the ability to just universally use the get method to call methods that they have in common, such as execute, create, end, while simultaneously allowing me to reach out to their exclusive methods specifically. Is there a way to do that, or is it impossible?
If it's still not clear ...
The code I have write now is a base class that is extended to the other classes in the manner ...
DynastyPQ (base) -> methods include (run(), execute(), end())
CustomAPQ (inherited from DynastyPQ) -> (has exclusive methods like getPoints())
CustomBPQ (inherited from DynastyPQ) -> (has exclusive methods like revivePlayer())
I want to write a get method so to rid myself of multiple. What I have right now is ...
DynastyPQ dynastyPQ;
DynastyPQ getPQ() {
return dynastyPQ;
}
void setPQ(DynastyPQ pq) {
dynastyPQ = pq;
}
Doing this ...
DynastyPQ pq = new CarnivalPQ();
I can only access DynastyPQ's methods rather than Carnival's methods.
Is there a way to access the exclusive methods while universally being able to execute the four base functions without regard to the type of class, or did I miss something earlier?
tl;dr -> I want one get method that universally returns all classes that inherit from class X; however, I want to be able to access each class's exclusive methods.
You can probably just cast the object to the derived class:
DynastyPQ pq = new CustomAPQ();
((CustomAPQ)pq).customAPQmethod();
If you don't know what is the dynamic type (the type you used after the new operator), you can use the instanceof keyword:
DynastyPQ pq = getPQ();
if (pq instanceof CustomAPQ) {
CustomAPQ a = (CustomAPQ)pq;
a.customAPQmethod();
} else if (pq instanceof CustomBPQ) {
CustomBPQ b = (CustomBPQ)pq;
b.customBPQmethod();
} else {
// Neither a CustomAPQ nor a CustomBPQ.
}
If you don't want to do that, you can use polymorphism:
class DynastyPQ {
final void run() {
// code.
}
final void execute() {
// code.
}
final void create() {
// code.
}
void specific1() {}
void specific2() {}
}
class CustomAPQ extends DynastyPQ {
#Override
void specific1() {
// do stuff specific to CustomAPQ.
}
#Override
void specific2() {
// do stuff specific to CustomAPQ.
}
}
class CustomBPQ extends DynastyPQ {
#Override
void specific1() {
// do stuff specific to CustomBPQ.
}
#Override
void specific2() {
// do stuff specific to CustomBPQ.
}
}
Now, you can do:
DynastyPQ pq = new CustomAPQ();
pq.specific1();
The called method will be CustomAPQ::specific1(). If specific1() was not declared in CustomAPQ, then, it will just do nothing.
Other than #CelineNOEL suggested it is not possible. Because you declared a class of type DynastyPQ, you can call only methods defined inside that class. In the moment you want to call specific method, not shared one, you know from which class it is and you can use casting to call that specific method.
((CustomAPQ)pq).customAPQmethod()
Shared methods you are using in code, when you don't know which class should execute same peace of code(or you want it to execute it different if you override share methods in every sub-class), and you delegate it to be resolved in runtime. So reconsider your design and in base class put methods that needs to be called dynamically. All other methods you are sure are specific for one class put only in that class. On that way your code will be cleaner and you will not mess thing that should be separated.

Can we write a function in Java that takes another function signature as a parameter and executes it? [duplicate]

This may be something common and trivial, but I seem to be having trouble finding a concrete answer. In C# there is a concept of delegates, which relates strongly to the idea of function pointers from C++. Is there a similar functionality in Java? Given that pointers are somewhat absent, what is the best way about this? And to be clear, we're talking first class here.
The Java idiom for function-pointer-like functionality is an an anonymous class implementing an interface, e.g.
Collections.sort(list, new Comparator<MyClass>(){
public int compare(MyClass a, MyClass b)
{
// compare objects
}
});
Update: the above is necessary in Java versions prior to Java 8. Now we have much nicer alternatives, namely lambdas:
list.sort((a, b) -> a.isGreaterThan(b));
and method references:
list.sort(MyClass::isGreaterThan);
You can substitue a function pointer with an interface. Lets say you want to run through a collection and do something with each element.
public interface IFunction {
public void execute(Object o);
}
This is the interface we could pass to some say CollectionUtils2.doFunc(Collection c, IFunction f).
public static void doFunc(Collection c, IFunction f) {
for (Object o : c) {
f.execute(o);
}
}
As an example say we have a collection of numbers and you would like to add 1 to every element.
CollectionUtils2.doFunc(List numbers, new IFunction() {
public void execute(Object o) {
Integer anInt = (Integer) o;
anInt++;
}
});
You can use reflection to do it.
Pass as parameter the object and the method name (as a string) and then invoke the method. For example:
Object methodCaller(Object theObject, String methodName) {
return theObject.getClass().getMethod(methodName).invoke(theObject);
// Catch the exceptions
}
And then use it as in:
String theDescription = methodCaller(object1, "toString");
Class theClass = methodCaller(object2, "getClass");
Of course, check all exceptions and add the needed casts.
No, functions are not first class objects in java. You can do the same thing by implementing a handler class - this is how callbacks are implemented in the Swing etc.
There are however proposals for closures (the official name for what you're talking about) in future versions of java - Javaworld has an interesting article.
This brings to mind Steve Yegge's Execution in the Kingdom of Nouns. It basically states that Java needs an object for every action, and therefore does not have "verb-only" entities like function pointers.
To achieve similar functionality you could use anonymous inner classes.
If you were to define a interface Foo:
interface Foo {
Object myFunc(Object arg);
}
Create a method bar which will receive a 'function pointer' as an argument:
public void bar(Foo foo) {
// .....
Object object = foo.myFunc(argValue);
// .....
}
Finally call the method as follows:
bar(new Foo() {
public Object myFunc(Object arg) {
// Function code.
}
}
Java8 has introduced lambdas and method references. So if your function matches a functional interface (you can create your own) you can use a method reference in this case.
Java provides a set of common functional interfaces. whereas you could do the following:
public class Test {
public void test1(Integer i) {}
public void test2(Integer i) {}
public void consumer(Consumer<Integer> a) {
a.accept(10);
}
public void provideConsumer() {
consumer(this::test1); // method reference
consumer(x -> test2(x)); // lambda
}
}
There is no such thing in Java. You will need to wrap your function into some object and pass the reference to that object in order to pass the reference to the method on that object.
Syntactically, this can be eased to a certain extent by using anonymous classes defined in-place or anonymous classes defined as member variables of the class.
Example:
class MyComponent extends JPanel {
private JButton button;
public MyComponent() {
button = new JButton("click me");
button.addActionListener(buttonAction);
add(button);
}
private ActionListener buttonAction = new ActionListener() {
public void actionPerformed(ActionEvent e) {
// handle the event...
// note how the handler instance can access
// members of the surrounding class
button.setText("you clicked me");
}
}
}
I have implemented callback/delegate support in Java using reflection. Details and working source are available on my website.
How It Works
We have a principle class named Callback with a nested class named WithParms. The API which needs the callback will take a Callback object as a parameter and, if neccessary, create a Callback.WithParms as a method variable. Since a great many of the applications of this object will be recursive, this works very cleanly.
With performance still a high priority to me, I didn't want to be required to create a throwaway object array to hold the parameters for every invocation - after all in a large data structure there could be thousands of elements, and in a message processing scenario we could end up processing thousands of data structures a second.
In order to be threadsafe the parameter array needs to exist uniquely for each invocation of the API method, and for efficiency the same one should be used for every invocation of the callback; I needed a second object which would be cheap to create in order to bind the callback with a parameter array for invocation. But, in some scenarios, the invoker would already have a the parameter array for other reasons. For these two reasons, the parameter array did not belong in the Callback object. Also the choice of invocation (passing the parameters as an array or as individual objects) belongs in the hands of the API using the callback enabling it to use whichever invocation is best suited to it's inner workings.
The WithParms nested class, then, is optional and serves two purposes, it contains the parameter object array needed for the callback invocations, and it provides 10 overloaded invoke() methods (with from 1 to 10 parameters) which load the parameter array and then invoke the callback target.
Check the closures how they have been implemented in the lambdaj library. They actually have a behavior very similar to C# delegates:
http://code.google.com/p/lambdaj/wiki/Closures
Relative to most people here I am new to java but since I haven't seen a similar suggestion I have another alternative to suggest. Im not sure if its a good practice or not, or even suggested before and I just didn't get it. I just like it since I think its self descriptive.
/*Just to merge functions in a common name*/
public class CustomFunction{
public CustomFunction(){}
}
/*Actual functions*/
public class Function1 extends CustomFunction{
public Function1(){}
public void execute(){...something here...}
}
public class Function2 extends CustomFunction{
public Function2(){}
public void execute(){...something here...}
}
.....
/*in Main class*/
CustomFunction functionpointer = null;
then depending on the application, assign
functionpointer = new Function1();
functionpointer = new Function2();
etc.
and call by
functionpointer.execute();

Java Methods - Taking a method AS AN ARGUMENT

I've come across some code that I can't share here but it declares a method WITHIN the paramter list of another method. I didnt even know that was possible. I dont really understand why its doing that. Can someone please explain to me some possible uses that you as a programmer would have for doing that? (Note: Since I can't show the code I dont expect an in-context explanation just generally)
Related:
What's the nearest substitute for a function pointer in Java?
Did the code look something like this?
obj.someMethod(myVar,3,new FooObject() {
public void bar() {
return "baz";
}
});
If so, then the method is not being passed to the other method as an argument, but rather an anonymous inner class is being created, and an instance of that class is being passed as the argument.
In the example above FooObject is an abstract class which doesn't implement the bar() method. Instead of creating a private class that extends FooObject we create an instance of the abstract class and provide the implementation of the abstract method in line with the rest of the code.
You can't create an instance of an abstract class so we have to provide the missing method to create a complete class defintion. As this new class is created on the fly it has no name, hence anonymous. As it's defined inside another class it's an anonymous inner class.
It can be a very handy shortcut, especially for Listener classes, but it can make your code hard to follow if you get carried away and the in line method definitions get too long.
In Java you can't pass methods as parameters. Could it have been passing not a method, but an anonymnous inner class?
This can be useful for passing behaviours between classes. Google "dependency injection" or "Inversion of control" for more information.
Have you ever seen the Functional Java?
It's a very interesting library that allows you programing like you would do in Scala.
I Wrote about this libs. I confess it is better to use in a more flexible syntax (BGGA closures) like Scala.
Using Functional Java with a high-order function like map on a list we have:
final List<Integer> numbers = list(1, 2, 3, 4, 5);
List<Integer> c = numbers.map(new F<Integer, Integer>() {
public Integer f(Integer arg) {
return arg * arg;
}
});
Another useful lib is lambdaj that offers nice ways to play like in Functional (FP) Programming.
Java has a limited syntax compared to FP languages. But you can still take some advantages of FP style, but you must be creative!
using java.lang.reflect.Method
example
public void callMethod(Method aMethod, int value) throws Exception {
aMethod.invoke(this, value);
}
public void print(Integer value) {
System.out.print(value);
}
public void println(Integer value) {
System.out.println(value);
}
public void demo() throws Exception {
Method println = this.getClass().getMethod("println", Integer.class);
Method print = this.getClass().getMethod("print", Integer.class);
callMethod(println, 10);
callMethod(print, 10);
}
The nearest thing to passing a function pointer in Java is passing an anonymous instance of an abstract class or interface. For example, a generic function type can be encoded in an interface like this:
public interface F<A, B> {
public B f(final A a);
}
You can then expect a method in another method's argument list:
public List<B> map(List<A> as, F<A, B> f) {
...
}
And you can call it with an anonymous instance of that interface:
map(myList, new F<Integer, String>() {
public String f(Integer i) {
return String.valueOf(i);
}
});
There's a library called Functional Java that exploits exactly this idea for great benefit glorious language Java.
It's not, per se, legal syntax in Java. Was it perhaps creating a new instance of an anonymous class?
You can also do something like this:
final Predicate somePredicate = new Predicate<Item>()
{
#Override
public boolean apply(Item item)
{
return item.someProperty().equals(something);
}
}
And use it like this:
List<Item> filteredList = filter(list, somePredicate);
I've done stuff like that before. I've also written methods that use a closure to build and return an anonymous implementation of an interface in a similar way:
Predicate isSomeColor(final Color color)
{
return new Predicate<Shape>()
{
#Override
public boolean apply(Shape shape)
{
return shape.getColor().equals(color);
}
}
}
List<Shape> redShapes = filter(shapes, isSomeColor(Color.RED);
All of this is still anonymous inner classes. Nowhere am I actually naming the class itself, I just have a reference to an instance of the class.
this is called reflection. there is a whole library of objects representing stuff like constructors, methods and such.
you can use it, for instance, in order to call a dynamic method that is determined on runtime.
Yes, declaration of a method within the parameter list of another method can be done. You can check out java.lang.reflect.Method
Using reflection, you retrieve a Method object representing the method you wish to pass as a parameter. Then you can call Method to invoke to make a call to that method.
Moreover, you can refer "Functional programming in the Java language" (http ://www.ibm.com/developerworks/java/library/j-fp.html) which can give you inside-out with examples.
The answers above are varying as to whether or not it is even possible. Is it possible through reflection? Is possible through the use of an anonymous inner class? We need to clarify this.
the closest to a function argument is
an instance of a anonymous class with exactly one method.
Runnable a = new Runnable(){
run(){
System.out.println("hello");
}
}
myMethod(a);
not pointer, but still you can write functions inline with some trick.
check my answer on another thread

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