i want to send an email this text
Destination : 6W - ATLANTA WEST!##$%^*!gemini!##$%^*!jfds!##$%^*!,Trailer Number : 000564,,Drop empty trailer at Plant Numbe :546,Pick up trailer at Plant Number :45, Bill Date : 25-Jan-2013,Bill Time - Eastern Time : 1,Trip Number :456,MBOL :546,Carrier :Covenant!##$%^*!test#shaw.com!##$%^*!transport#shaw.com!##$%^*!test#transport.com!##$%^*!antoalphi#gmail.com,Destination : 6W - ATLANTA WEST!##$%^*!gemini!##$%^*!jfds!##$%^*!,Customer Name : 567,Cusomer Delivery Address : 657567657,General Comments :657,Warehouse Comments : 65,Carrier Comments : ,Appointment Date :25-Jan-2013,Appointment Time : 1am,Rail Only :Standard,Total Weight : 45645
and i used this mailContent = URLDecoder.decode(Body, "UTF-8"); decode,
but it is giving me this exception URLDecoder: Illegal hex characters in escape (%) pattern - For input string: "^*"
could any one of you help me,how to solve this. I get this while sending mail.
Best Regards
You are trying to URL decode something that wasn't URL encoded in the first place. What's wrong with the body as it is? In other words, what happens if you just use:
mailContent = Body
(In URL encoding, the % character is used with two hexadecimal digits to encode characters that might cause problems, for example / would be encoded as %2F, as its ASCII code is 47 (decimal) or 2F (hex). In your body, % is followed by two characters that are not hexadecimal digits - that's how I can tell it hasn't been URL encoded, and why the decoder is erroring.)
Simply stop calling URLDecoder.decode() and you will stop getting the error! The string value you are passing to it is not URL encoded.
There are various forms of MIME encoding that you might want to consider, if you are sending an email with content that would not normally be allowed in an email message without encoding. There references might be handy:
What is allowed in SMTP: http://www.apps.ietf.org/rfc/rfc788.html
Basic MIME encoding: http://www.apps.ietf.org/rfc/rfc1341.html
Java MIME support: http://docs.oracle.com/javaee/1.4/api/javax/mail/internet/MimeUtility.html
For example, you might try:
String sendable = MimeUtility.encodeText(body,"UTF-8","BASE64")
Related
I am reading a JSON file in Java using this code:
String data = Files.readFile(jsonFile)
.trim()
.replaceAll("[^\\x00-\\x7F]", "")
.replaceAll("[\\p{Cntrl}&&[^\r\n\t]]", "")
.replaceAll("\\p{C}", "");
In my JSON file, there is a unique char: 'あ' (12354) that is interpreted to: "" (nothing) when reading the file.
How can I make this char show up in my variable "data"?
Due to answers I've got, I understand that the data is cleaned from high ASCII characters by adding replaceAll("[^\\x00-\\x7F]", ""). But what can I do if I want all high ASCII characters to be cleaned except this one 'あ'?
The character you want is the unicode character HIRAGANA LETTER A and has code U+3042.
You can simply add it to the list of valid characters:
...
.replaceAll("[^\\x00-\\x7F\\u3042]", "")
...
When the http content contains the char % ,io.netty.handler.codec.http.QueryStringDecoder.decodeComponent() will throw a IllegalArgumentException with message: invalid escape sequence `%" .......
Does that mean that the http content cannot contain the char %?
The request param is json str:
{"discountRate":"10%"}
The detail of the code can not show;
Percent signs have a special meaning in URLs. Literal percent signs need to be encoded as %25 https://www.urlencoder.io/learn/
I created a JSON file on the fly by using some runtime data and stored as string as like below:
JSON:
{
"ticketDetails": "kindle tracking ticket: TICKET0900060
Iimpact statement: impacted due to year 2020 format handling issue,
depending on the Gateway,
user can be asked to
try with another instrument.
Timeline: 00: 00 SAP Internal Declines spiked to 300 +
05: 22 AM flintron reported DECLINED errors since 0: 00 PST.
As per TDO,flitron is not seeing clear metrics impact " }
Note: I just copied the exact json which i'm getting at runtime. It containse \n space and exactly like above.
I can see few JSONObjects like ticketDetails is having huge description and when I tried to parse the above string is leading to parse error.
I tried the below way to eliminate the parse error by using
String removeSpecialCharacterFromJson= jsonString.replaceAll("[^A-Za-z0-9]","")
System.out.println(removeSpecialCharacterFromJson);
Sample Output:
kindletrackingticketTICKET0900060Iimpactstatementimpactedduetoyear2020formathandlingissue....[space between characters are removed and It's hard to read the string]
The above code removed all the special characters from the string and It will be successfully parsed. But the description is not having the space and It very hard to read the content after the above changes done.
I tried to escape the \s in the regular expression which is giving the original String value which is leading to parse exception.
String removeSpecialCharacterFromJson= jsonString.replaceAll("[^A-Za-z0-9\\s]","")
Is there anyohter way to handle this ? I just want to the ticketDetails to be readable format and It should not have any special characters and \n lines.
Can someone help me on this?
s in regular expression is not for space but for the whitespace
I guess that you may have some additional non allowed whitespace in your JSON string
Take a look at The JSON spec (RFC 7159):
Insignificant whitespace is allowed before or after any of the six structural characters.
ws = *(
%x20 / ; Space
%x09 / ; Horizontal tab
%x0A / ; Line feed or New line
%x0D ) ; Carriage return
Verify your values and look for improper whitespaces
I am passing a String value in a URL
eg: http://localhost:8080/webservice/useradmin/a%bghijlk123/0978+gh
The String "ab%ghijlk123/0978+gh" breaks the URL.
What are the available options to overcome this.
Is encoding the string the only option? There must be minimal code change. Any server side configurations can be used to achieve this?
Kindly provide suggestions please.
Is encoding the string the only option?
It is the only correct option.
Use URLEncoder.encode("ab%ghijlk123/0978+gh", "UTF-8"),
which will give you ab%25ghijlk123%2F0978%2Bgh, for a full URL of:
http://localhost:8080/webservice/useradmin/ab%25ghijlk123%2F0978%2Bgh
The URL http://localhost:8080/webservice/useradmin/a%bghijlk123/0978+gh is invalid.
The URL specification (RFC3986) says that path segments (the values separated by a /) may only consist of:
ALPHA: "a"-"z", "A"-"Z"
DIGIT: "0"-"9"
Special chars: - . _ ~ ! $ & ' ( ) * + , ; = : #
pct-encoded: "%" HEXDIG HEXDIG
Values that has to be disallowed because they have other meanings are: / (path separator), ? (start of query), # (start of fragment), and % (start of 2-digit hex encoded char).
As you can see, the % sign is only allowed as a percent-encoded character, so %bg makes the URL invalid.
If the part after the useradmin/ is supposed to be the value ab%ghijlk123/0978+gh, then it must be encoded as shown above.
If the server rejects that as "400:Bad request", then the server is in error.
I'm using the org.json.JSONObject to parse some json being sent to my servlet by an iphone. I was stuck for a while by why I would be getting an error message at all. The error message was:
org.json.JSONException: Unterminated string at 737 [character 738 line 1]
After printing out what I received, I see that the string sent was indeed cut short and stopped mid-json. I can't understand why it would be cut short. There's no limit on String size is there (or at least only a memory limit surely).
Has anyone else had thins error?
Cheers
Joe
json work well with \n but if you have any other special charachters in your meesage like
\ , # , & , # etc.. first convert them into their respective HEX value and then send your message.
If you're using the HTTP GET method to send data using query parameters, realize that there's a practical limit on the amount of data you can send that way. It's about 2000 characters (varies by server and client). You can easily exceed that when URL encoding a shorter string.
Json won't work if received string contain new line character like \n. Try to check for it and escape the character.