Matching Multiple Patterns in One Line - java

Can someone please tell me why my pattern: <p(\s+(.*)?)?>(.[^</p>]*)?</p> does not work correctly. Example matches:
<p>This is a test and anything can be here even other <tags>tags</tags></p>
<p style="test">This is a test</p>
<p></p>
And if the above were all on one line it should find 3 separate patterns. The link below demonstrates its true behaviour which is very odd...
http://regexr.com?33jrn
The matches it finds should always immediately start when it finds <p and immediately stop when it finds </p>

There are a couple of problems with your regex. Let's see what they look like.
Here's your regex: -
<p(\s+(.*)?)?>(.[^</p>]*)?</p>
Problem 1: - Notice the pattern (.*)?. It is not doing what you think. It is not a enforcing a reluctant behaviour on * quantifier. Rather it's a enforcing an optional quantifier (?) over a greedy * quantifier. It simply means match 0 or 1 repetition of (.*). For making it reluctant, you need to move ? inside the bracket. So, you need to use (.*?) instead of (.*)?.
Problem 2: - [^</p>] does not negate </p> rather it negates - <, /, p, > as separate characters. Note that in a character class, each character is taken literally. There is not grouping in there. So, (.[^</p>]*) means match a character if is not followed by 0 or more repetition of either of [</p>]. That is not what you want. If you want to match a sequence that is not </p>, then you can use a negative look-ahead like this: - ((?!</p>).)*. Now this will check first whether the following sequence is not </p>, then it matches the next character.
So, your regex pattern should be: -
<p(\s+(.*?))?>((?!</p>).)*</p>
Or, you can even simplify your regex to: -
<p[^>]*>((?!</p>).)*</p>

Try this:
<p.*?>.*?</p>
Please read about greedy and reluctant on this page: "Differences Among Greedy, Reluctant, and Possessive Quantifiers".

The problem is in (.[^</p>]*)?, which means:
a single char
followed by any char n times but not a <, neither a /, nor a p and nor a >
I guess you wanted to mean not the </p> string n times, but this is not the way to do it.
Try with .*? instead: <p(\s+(.*)?)?>.*?</p>.
While .* means match the longest string, .*? means match the shortest string.
For example, for the string #foo#bar#, .* will match #foo#bar# while .*? will match #foo#.

Related

How to match a string in this way?

I need to check if a String matches this specific pattern.
The pattern is:
(Numbers)(all characters allowed)(numbers)
and the numbers may have a comma ("." or ",")!
For instance the input could be 500+400 or 400,021+213.443.
I tried Pattern.matches("[0-9],?.?+[0-9],?.?+", theequation2), but it didn't work!
I know that I have to use the method Pattern.match(regex, String), but I am not being able to find the correct regex.
Dealing with numbers can be difficult. This approach will deal with your examples, but check carefully. I also didn't do "all characters" in the middle grouping, as "all" would include numbers, so instead I assumed that finding the next non-number would be appropriate.
This Java regex handles the requirements:
"((-?)[\\d,.]+)([^\\d-]+)((-?)[\\d,.]+)"
However, there is a potential issue in the above. Consider the following:
300 - -200. The foregoing won't match that case.
Now, based upon the examples, I think the point is that one should have a valid operator. The number of math operations is likely limited, so I would whitelist the operators in the middle. Thus, something like:
"((-?)[\\d,.]+)([\\s]*[*/+-]+[\\s]*)((-?)[\\d,.]+)"
Would, I think, be more appropriate. The [*/+-] can be expanded for the power operator ^ or whatever. Now, if one is going to start adding words (such as mod) in the equation, then the expression will need to be modified.
You can see this regular expression here
In your regex you have to escape the dot \. to match it literally and escape the \+ or else it would make the ? a possessive quantifier. To match 1+ digits you have to use a quantifier [0-9]+
For your example data, you could match 1+ digits followed by an optional part which matches either a dot or a comma at the start and at the end. If you want to match 1 time any character you could use a dot.
Instead of using a dot, you could also use for example a character class [-+*] to list some operators or list what you would allow to match. If this should be the only match, you could use anchors to assert the start ^ and the end $ of the string.
\d+(?:[.,]\d+)?.\d+(?:[.,]\d+)?
In Java:
String regex = "\\d+(?:[.,]\\d+)?.\\d+(?:[.,]\\d+)?";
Regex demo
That would match:
\d+(?:[.,]\d+)? 1+ digits followed by an optional part that matches . or , followed by 1+ digits
. Match any character (Use .+) to repeat 1+ times
Same as the first pattern

Confusion on Quantifiers? [duplicate]

I found this tutorial on regular expressions and while I intuitively understand what "greedy", "reluctant" and "possessive" qualifiers do, there seems to be a serious hole in my understanding.
Specifically, in the following example:
Enter your regex: .*foo // Greedy qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.
Enter your regex: .*?foo // Reluctant qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.
Enter your regex: .*+foo // Possessive qualifier
Enter input string to search: xfooxxxxxxfoo
No match found.
The explanation mentions eating the entire input string, letters been consumed, matcher backing off, rightmost occurrence of "foo" has been regurgitated, etc.
Unfortunately, despite the nice metaphors, I still don't understand what is eaten by whom... Do you know of another tutorial that explains (concisely) how regular expression engines work?
Alternatively, if someone can explain in somewhat different phrasing the following paragraph, that would be much appreciated:
The first example uses the greedy quantifier .* to find "anything", zero or more times, followed by the letters "f", "o", "o". Because the quantifier is greedy, the .* portion of the expression first eats the entire input string. At this point, the overall expression cannot succeed, because the last three letters ("f", "o", "o") have already been consumed [by whom?]. So the matcher slowly backs off [from right-to-left?] one letter at a time until the rightmost occurrence of "foo" has been regurgitated [what does this mean?], at which point the match succeeds and the search ends.
The second example, however, is reluctant, so it starts by first consuming [by whom?] "nothing". Because "foo" doesn't appear at the beginning of the string, it's forced to swallow [who swallows?] the first letter (an "x"), which triggers the first match at 0 and 4. Our test harness continues the process until the input string is exhausted. It finds another match at 4 and 13.
The third example fails to find a match because the quantifier is possessive. In this case, the entire input string is consumed by .*+ [how?], leaving nothing left over to satisfy the "foo" at the end of the expression. Use a possessive quantifier for situations where you want to seize all of something without ever backing off [what does back off mean?]; it will outperform the equivalent greedy quantifier in cases where the match is not immediately found.
I'll give it a shot.
A greedy quantifier first matches as much as possible. So the .* matches the entire string. Then the matcher tries to match the f following, but there are no characters left. So it "backtracks", making the greedy quantifier match one less character (leaving the "o" at the end of the string unmatched). That still doesn't match the f in the regex, so it backtracks one more step, making the greedy quantifier match one less character again (leaving the "oo" at the end of the string unmatched). That still doesn't match the f in the regex, so it backtracks one more step (leaving the "foo" at the end of the string unmatched). Now, the matcher finally matches the f in the regex, and the o and the next o are matched too. Success!
A reluctant or "non-greedy" quantifier first matches as little as possible. So the .* matches nothing at first, leaving the entire string unmatched. Then the matcher tries to match the f following, but the unmatched portion of the string starts with "x" so that doesn't work. So the matcher backtracks, making the non-greedy quantifier match one more character (now it matches the "x", leaving "fooxxxxxxfoo" unmatched). Then it tries to match the f, which succeeds, and the o and the next o in the regex match too. Success!
In your example, it then starts the process over with the remaining unmatched portion of the string, "xxxxxxfoo", following the same process.
A possessive quantifier is just like the greedy quantifier, but it doesn't backtrack. So it starts out with .* matching the entire string, leaving nothing unmatched. Then there is nothing left for it to match with the f in the regex. Since the possessive quantifier doesn't backtrack, the match fails there.
It is just my practice output to visualise the scene-
I haven't heard the exact terms 'regurgitate' or 'backing off' before; the phrase that would replace these is "backtracking", but 'regurgitate' seems like as good a phrase as any for "the content that had been tentatively accepted before backtracking threw it away again".
The important thing to realize about most regex engines is that they are backtracking: they will tentatively accept a potential, partial match, while trying to match the entire contents of the regex. If the regex cannot be completely matched at the first attempt, then the regex engine will backtrack on one of its matches. It will try matching *, +, ?, alternation, or {n,m} repetition differently, and try again. (And yes, this process can take a long time.)
The first example uses the greedy
quantifier .* to find "anything", zero
or more times, followed by the letters
"f" "o" "o". Because the quantifier is
greedy, the .* portion of the
expression first eats the entire input
string. At this point, the overall
expression cannot succeed, because the
last three letters ("f" "o" "o") have
already been consumed (by whom?).
The last three letters, f, o, and o were already consumed by the initial .* portion of the rule. However, the next element in the regex, f, has nothing left in the input string. The engine will be forced to backtrack on its initial .* match, and try matching all-but-the-last character. (It might be smart and backtrack to all-but-the-last-three, because it has three literal terms, but I'm unaware of implementation details at this level.)
So the matcher
slowly backs off (from right-to-left?) one letter at a time
until the rightmost occurrence of
"foo" has been regurgitated (what does this mean?), at which
This means the foo had tentatively been including when matching .*. Because that attempt failed, the regex engine tries accepting one fewer character in .*. If there had been a successful match before the .* in this example, then the engine would probably try shortening the .* match (from right-to-left, as you pointed out, because it is a greedy qualifier), and if it was unable to match the entire inputs, then it might be forced to re-evaluate what it had matched before the .* in my hypothetical example.
point the match succeeds and the
search ends.
The second example, however, is
reluctant, so it starts by first
consuming (by whom?) "nothing". Because "foo"
The initial nothing is consumed by .?*, which will consume the shortest possible amount of anything that allows the rest of the regex to match.
doesn't appear at the beginning of the
string, it's forced to swallow (who swallows?) the
Again the .?* consumes the first character, after backtracking on the initial failure to match the entire regex with the shortest possible match. (In this case, the regex engine is extending the match for .*? from left-to-right, because .*? is reluctant.)
first letter (an "x"), which triggers
the first match at 0 and 4. Our test
harness continues the process until
the input string is exhausted. It
finds another match at 4 and 13.
The third example fails to find a
match because the quantifier is
possessive. In this case, the entire
input string is consumed by .*+, (how?)
A .*+ will consume as much as possible, and will not backtrack to find new matches when the regex as a whole fails to find a match. Because the possessive form does not perform backtracking, you probably won't see many uses with .*+, but rather with character classes or similar restrictions: account: [[:digit:]]*+ phone: [[:digit:]]*+.
This can drastically speed up regex matching, because you're telling the regex engine that it should never backtrack over potential matches if an input doesn't match. (If you had to write all the matching code by hand, this would be similar to never using putc(3) to 'push back' an input character. It would be very similar to the naive code one might write on a first try. Except regex engines are way better than a single character of push-back, they can rewind all the back to zero and try again. :)
But more than potential speed ups, this also can let you write regexs that match exactly what you need to match. I'm having trouble coming up with an easy example :) but writing a regex using possessive vs greedy quantifiers can give you different matches, and one or the other may be more appropriate.
leaving nothing left over to satisfy
the "foo" at the end of the
expression. Use a possessive
quantifier for situations where you
want to seize all of something without
ever backing off (what does back off mean?); it will outperform
"Backing off" in this context means "backtracking" -- throwing away a tentative partial match to try another partial match, which may or may not succeed.
the equivalent greedy quantifier in
cases where the match is not
immediately found.
http://swtch.com/~rsc/regexp/regexp1.html
I'm not sure that's the best explanation on the internet, but it's reasonably well written and appropriately detailed, and I keep coming back to it. You might want to check it out.
If you want a higher-level (less detailed explanation), for simple regular expressions such as the one you're looking at, a regular expression engine works by backtracking. Essentially, it chooses ("eats") a section of the string and tries to match the regular expression against that section. If it matches, great. If not, the engine alters its choice of the section of the string and tries to match the regexp against that section, and so on, until it's tried every possible choice.
This process is used recursively: in its attempt to match a string with a given regular expression, the engine will split the regular expression into pieces and apply the algorithm to each piece individually.
The difference between greedy, reluctant, and possessive quantifiers enters when the engine is making its choices of what part of the string to try to match against, and how to modify that choice if it doesn't work the first time. The rules are as follows:
A greedy quantifier tells the engine to start with the entire string (or at least, all of it that hasn't already been matched by previous parts of the regular expression) and check whether it matches the regexp. If so, great; the engine can continue with the rest of the regexp. If not, it tries again, but trimming one character (the last one) off the section of the string to be checked. If that doesn't work, it trims off another character, etc. So a greedy quantifier checks possible matches in order from longest to shortest.
A reluctant quantifier tells the engine to start with the shortest possible piece of the string. If it matches, the engine can continue; if not, it adds one character to the section of the string being checked and tries that, and so on until it finds a match or the entire string has been used up. So a reluctant quantifier checks possible matches in order from shortest to longest.
A possessive quantifier is like a greedy quantifier on the first attempt: it tells the engine to start by checking the entire string. The difference is that if it doesn't work, the possessive quantifier reports that the match failed right then and there. The engine doesn't change the section of the string being looked at, and it doesn't make any more attempts.
This is why the possessive quantifier match fails in your example: the .*+ gets checked against the entire string, which it matches, but then the engine goes on to look for additional characters foo after that - but of course it doesn't find them, because you're already at the end of the string. If it were a greedy quantifier, it would backtrack and try making the .* only match up to the next-to-last character, then up to the third to last character, then up to the fourth to last character, which succeeds because only then is there a foo left after the .* has "eaten" the earlier part of the string.
Here is my take using Cell and Index positions (See the diagram here to distinguish a Cell from an Index).
Greedy - Match as much as possible to the greedy quantifier and the entire regex. If there is no match, backtrack on the greedy quantifier.
Input String: xfooxxxxxxfoo
Regex: .*foo
The above Regex has two parts:
(i)'.*' and
(ii)'foo'
Each of the steps below will analyze the two parts. Additional comments for a match to 'Pass' or 'Fail' is explained within braces.
Step 1:
(i) .* = xfooxxxxxxfoo - PASS ('.*' is a greedy quantifier and will use the entire Input String)
(ii) foo = No character left to match after index 13 - FAIL
Match failed.
Step 2:
(i) .* = xfooxxxxxxfo - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = o - FAIL
Match failed.
Step 3:
(i) .* = xfooxxxxxxf - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = oo - FAIL
Match failed.
Step 4:
(i) .* = xfooxxxxxx - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = foo - PASS
Report MATCH
Result: 1 match(es)
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.
Reluctant - Match as little as possible to the reluctant quantifier and match the entire regex. if there is no match, add characters to the reluctant quantifier.
Input String: xfooxxxxxxfoo
Regex: .*?foo
The above regex has two parts:
(i) '.*?' and
(ii) 'foo'
Step 1:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 0 having '' is a match.)
foo = xfo - FAIL (Cell 0,1,2 - i.e index between 0 and 3)
Match failed.
Step 2:
.*? = x - PASS (Add characters to the reluctant quantifier '.*?'. Cell 0 having 'x' is a match.)
foo = foo - PASS
Report MATCH
Step 3:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 4 having '' is a match.)
foo = xxx - FAIL (Cell 4,5,6 - i.e index between 4 and 7)
Match failed.
Step 4:
.*? = x - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4.)
foo = xxx - FAIL (Cell 5,6,7 - i.e index between 5 and 8)
Match failed.
Step 5:
.*? = xx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 5.)
foo = xxx - FAIL (Cell 6,7,8 - i.e index between 6 and 9)
Match failed.
Step 6:
.*? = xxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 6.)
foo = xxx - FAIL (Cell 7,8,9 - i.e index between 7 and 10)
Match failed.
Step 7:
.*? = xxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 7.)
foo = xxf - FAIL (Cell 8,9,10 - i.e index between 8 and 11)
Match failed.
Step 8:
.*? = xxxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 8.)
foo = xfo - FAIL (Cell 9,10,11 - i.e index between 9 and 12)
Match failed.
Step 9:
.*? = xxxxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 9.)
foo = foo - PASS (Cell 10,11,12 - i.e index between 10 and 13)
Report MATCH
Step 10:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 13 is blank.)
foo = No character left to match - FAIL (There is nothing after index 13 to match)
Match failed.
Result: 2 match(es)
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.
Possessive - Match as much as possible to the possessive quantifer and match the entire regex. Do NOT backtrack.
Input String: xfooxxxxxxfoo
Regex: .*+foo
The above regex has two parts: '.*+' and 'foo'.
Step 1:
.*+ = xfooxxxxxxfoo - PASS (Match as much as possible to the possessive quantifier '.*')
foo = No character left to match - FAIL (Nothing to match after index 13)
Match failed.
Note: Backtracking is not allowed.
Result: 0 match(es)
Greedy: "match the longest possible sequence of characters"
Reluctant: "match the shortest possible sequence of characters"
Possessive: This is a bit strange as it does NOT (in contrast to greedy and reluctant) try to find a match for the whole regex.
By the way: No regex pattern matcher implementation will ever use backtracking. All real-life pattern matcher are extremely fast - nearly independent of the complexity of the regular expression!
Greedy Quantification involves pattern matching using all of the remaining unvalidated characters of a string during an iteration. Unvalidated characters start in the active sequence. Every time a match does not occur, the character at the end is quarantined and the check is performed again.
When only leading conditions of the regex pattern are satisfied by the active sequence, an attempt is made to validate the remaining conditions against the quarantine. If this validation is successful, matched characters in the quarantine are validated and residual unmatched characters remain unvalidated and will be used when the process begins anew in the next iteration.
The flow of characters is from the active sequence into the quarantine. The resulting behavior is that as much of the original sequence is included in a match as possible.
Reluctant Quantification is mostly the same as greedy qualification except the flow of characters is the opposite--that is, they start in the quarantine and flow into the active sequence. The resulting behavior is that as little of the original sequence is included in a match as possible.
Possessive Quantification does not have a quarantine and includes everything in a fixed active sequence.

Replace substring of text matching regexp

I have text that looks like something like this:
1. Must have experience in Java 2. Team leader...
I want to render this in HTML as an ordered list. Now adding the </li> tag to the end is simple enough:
s = replace(s, ". ", "</li>");
But how do I go about replacing the 1., 2. etc with <li>?
I have the regular expression \d*\.$ which matches a number with a period, but the problem is is that is a substring so matching 1. Must have experience in Java 2. Team leader with \d*\.$ returns false.
Code
See regex in use here
\d+\.\s+(.*?)\s*(?=\d+\.\s+|$)
Replace
<li>$1</li>\n
Results
Input
Must have experience in Java 2. Team leader...
Output
<li>Must have experience in Java</li>
<li>Team leader...</li>
Explanation
\d+ Match one or more digits
\. Match the dot character . literally
\s+ Match one or more whitespace characters
(.*?) Capture any character any number of times, but as few as possible, into capture group 1
\s* Match any number of whitespace characters
(?=\d+\.\s+|$) Positive lookahead ensuring either of the following doesn't match
\d+\.\s+
\d+ Match one or more digits
\. Match the dot character . literally
\s+ Match one or more whitespace characters
$ Assert position at the end of the line
But how do I go about replacing the 1., 2. etc with <li>?
You can use String#replaceAll which can allow regex instead of replace :
s = s.replaceAll("\\d+\\.\\s", "</li>");
Note
You don't need to use $ in the end of your regex.
You have to escape dot . because it's mean any character in regex
You can use \s for one space or \s* for zero or more spaces or \s+ for one or more space
We want
<ol>
<li>one</li>
<li>two<li>
</ol>
This can be done as:
s = s.replaceAll("(?s)(\\d+\\.)\\s+(.*\\.)\\s*", "<li>$2</li></ol>");
s = s.replaceFirst("<li>", "<ol><li>");
s = s.replaceAll("(?s)</li></ol><li>", "</li>\n<li>");
The trick is to first add </li></ol> with a spurious </ol> that should only remain after the last list item.
(?s) is the DOTALL notation, causing . to also match line breaks.
In case of more than one numbered list this will not do. Also it assumes one single sentence per list item.

Regular expression not extracting correctly (Java Pattern / Matcher) [duplicate]

I found this tutorial on regular expressions and while I intuitively understand what "greedy", "reluctant" and "possessive" qualifiers do, there seems to be a serious hole in my understanding.
Specifically, in the following example:
Enter your regex: .*foo // Greedy qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.
Enter your regex: .*?foo // Reluctant qualifier
Enter input string to search: xfooxxxxxxfoo
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.
Enter your regex: .*+foo // Possessive qualifier
Enter input string to search: xfooxxxxxxfoo
No match found.
The explanation mentions eating the entire input string, letters been consumed, matcher backing off, rightmost occurrence of "foo" has been regurgitated, etc.
Unfortunately, despite the nice metaphors, I still don't understand what is eaten by whom... Do you know of another tutorial that explains (concisely) how regular expression engines work?
Alternatively, if someone can explain in somewhat different phrasing the following paragraph, that would be much appreciated:
The first example uses the greedy quantifier .* to find "anything", zero or more times, followed by the letters "f", "o", "o". Because the quantifier is greedy, the .* portion of the expression first eats the entire input string. At this point, the overall expression cannot succeed, because the last three letters ("f", "o", "o") have already been consumed [by whom?]. So the matcher slowly backs off [from right-to-left?] one letter at a time until the rightmost occurrence of "foo" has been regurgitated [what does this mean?], at which point the match succeeds and the search ends.
The second example, however, is reluctant, so it starts by first consuming [by whom?] "nothing". Because "foo" doesn't appear at the beginning of the string, it's forced to swallow [who swallows?] the first letter (an "x"), which triggers the first match at 0 and 4. Our test harness continues the process until the input string is exhausted. It finds another match at 4 and 13.
The third example fails to find a match because the quantifier is possessive. In this case, the entire input string is consumed by .*+ [how?], leaving nothing left over to satisfy the "foo" at the end of the expression. Use a possessive quantifier for situations where you want to seize all of something without ever backing off [what does back off mean?]; it will outperform the equivalent greedy quantifier in cases where the match is not immediately found.
I'll give it a shot.
A greedy quantifier first matches as much as possible. So the .* matches the entire string. Then the matcher tries to match the f following, but there are no characters left. So it "backtracks", making the greedy quantifier match one less character (leaving the "o" at the end of the string unmatched). That still doesn't match the f in the regex, so it backtracks one more step, making the greedy quantifier match one less character again (leaving the "oo" at the end of the string unmatched). That still doesn't match the f in the regex, so it backtracks one more step (leaving the "foo" at the end of the string unmatched). Now, the matcher finally matches the f in the regex, and the o and the next o are matched too. Success!
A reluctant or "non-greedy" quantifier first matches as little as possible. So the .* matches nothing at first, leaving the entire string unmatched. Then the matcher tries to match the f following, but the unmatched portion of the string starts with "x" so that doesn't work. So the matcher backtracks, making the non-greedy quantifier match one more character (now it matches the "x", leaving "fooxxxxxxfoo" unmatched). Then it tries to match the f, which succeeds, and the o and the next o in the regex match too. Success!
In your example, it then starts the process over with the remaining unmatched portion of the string, "xxxxxxfoo", following the same process.
A possessive quantifier is just like the greedy quantifier, but it doesn't backtrack. So it starts out with .* matching the entire string, leaving nothing unmatched. Then there is nothing left for it to match with the f in the regex. Since the possessive quantifier doesn't backtrack, the match fails there.
It is just my practice output to visualise the scene-
I haven't heard the exact terms 'regurgitate' or 'backing off' before; the phrase that would replace these is "backtracking", but 'regurgitate' seems like as good a phrase as any for "the content that had been tentatively accepted before backtracking threw it away again".
The important thing to realize about most regex engines is that they are backtracking: they will tentatively accept a potential, partial match, while trying to match the entire contents of the regex. If the regex cannot be completely matched at the first attempt, then the regex engine will backtrack on one of its matches. It will try matching *, +, ?, alternation, or {n,m} repetition differently, and try again. (And yes, this process can take a long time.)
The first example uses the greedy
quantifier .* to find "anything", zero
or more times, followed by the letters
"f" "o" "o". Because the quantifier is
greedy, the .* portion of the
expression first eats the entire input
string. At this point, the overall
expression cannot succeed, because the
last three letters ("f" "o" "o") have
already been consumed (by whom?).
The last three letters, f, o, and o were already consumed by the initial .* portion of the rule. However, the next element in the regex, f, has nothing left in the input string. The engine will be forced to backtrack on its initial .* match, and try matching all-but-the-last character. (It might be smart and backtrack to all-but-the-last-three, because it has three literal terms, but I'm unaware of implementation details at this level.)
So the matcher
slowly backs off (from right-to-left?) one letter at a time
until the rightmost occurrence of
"foo" has been regurgitated (what does this mean?), at which
This means the foo had tentatively been including when matching .*. Because that attempt failed, the regex engine tries accepting one fewer character in .*. If there had been a successful match before the .* in this example, then the engine would probably try shortening the .* match (from right-to-left, as you pointed out, because it is a greedy qualifier), and if it was unable to match the entire inputs, then it might be forced to re-evaluate what it had matched before the .* in my hypothetical example.
point the match succeeds and the
search ends.
The second example, however, is
reluctant, so it starts by first
consuming (by whom?) "nothing". Because "foo"
The initial nothing is consumed by .?*, which will consume the shortest possible amount of anything that allows the rest of the regex to match.
doesn't appear at the beginning of the
string, it's forced to swallow (who swallows?) the
Again the .?* consumes the first character, after backtracking on the initial failure to match the entire regex with the shortest possible match. (In this case, the regex engine is extending the match for .*? from left-to-right, because .*? is reluctant.)
first letter (an "x"), which triggers
the first match at 0 and 4. Our test
harness continues the process until
the input string is exhausted. It
finds another match at 4 and 13.
The third example fails to find a
match because the quantifier is
possessive. In this case, the entire
input string is consumed by .*+, (how?)
A .*+ will consume as much as possible, and will not backtrack to find new matches when the regex as a whole fails to find a match. Because the possessive form does not perform backtracking, you probably won't see many uses with .*+, but rather with character classes or similar restrictions: account: [[:digit:]]*+ phone: [[:digit:]]*+.
This can drastically speed up regex matching, because you're telling the regex engine that it should never backtrack over potential matches if an input doesn't match. (If you had to write all the matching code by hand, this would be similar to never using putc(3) to 'push back' an input character. It would be very similar to the naive code one might write on a first try. Except regex engines are way better than a single character of push-back, they can rewind all the back to zero and try again. :)
But more than potential speed ups, this also can let you write regexs that match exactly what you need to match. I'm having trouble coming up with an easy example :) but writing a regex using possessive vs greedy quantifiers can give you different matches, and one or the other may be more appropriate.
leaving nothing left over to satisfy
the "foo" at the end of the
expression. Use a possessive
quantifier for situations where you
want to seize all of something without
ever backing off (what does back off mean?); it will outperform
"Backing off" in this context means "backtracking" -- throwing away a tentative partial match to try another partial match, which may or may not succeed.
the equivalent greedy quantifier in
cases where the match is not
immediately found.
http://swtch.com/~rsc/regexp/regexp1.html
I'm not sure that's the best explanation on the internet, but it's reasonably well written and appropriately detailed, and I keep coming back to it. You might want to check it out.
If you want a higher-level (less detailed explanation), for simple regular expressions such as the one you're looking at, a regular expression engine works by backtracking. Essentially, it chooses ("eats") a section of the string and tries to match the regular expression against that section. If it matches, great. If not, the engine alters its choice of the section of the string and tries to match the regexp against that section, and so on, until it's tried every possible choice.
This process is used recursively: in its attempt to match a string with a given regular expression, the engine will split the regular expression into pieces and apply the algorithm to each piece individually.
The difference between greedy, reluctant, and possessive quantifiers enters when the engine is making its choices of what part of the string to try to match against, and how to modify that choice if it doesn't work the first time. The rules are as follows:
A greedy quantifier tells the engine to start with the entire string (or at least, all of it that hasn't already been matched by previous parts of the regular expression) and check whether it matches the regexp. If so, great; the engine can continue with the rest of the regexp. If not, it tries again, but trimming one character (the last one) off the section of the string to be checked. If that doesn't work, it trims off another character, etc. So a greedy quantifier checks possible matches in order from longest to shortest.
A reluctant quantifier tells the engine to start with the shortest possible piece of the string. If it matches, the engine can continue; if not, it adds one character to the section of the string being checked and tries that, and so on until it finds a match or the entire string has been used up. So a reluctant quantifier checks possible matches in order from shortest to longest.
A possessive quantifier is like a greedy quantifier on the first attempt: it tells the engine to start by checking the entire string. The difference is that if it doesn't work, the possessive quantifier reports that the match failed right then and there. The engine doesn't change the section of the string being looked at, and it doesn't make any more attempts.
This is why the possessive quantifier match fails in your example: the .*+ gets checked against the entire string, which it matches, but then the engine goes on to look for additional characters foo after that - but of course it doesn't find them, because you're already at the end of the string. If it were a greedy quantifier, it would backtrack and try making the .* only match up to the next-to-last character, then up to the third to last character, then up to the fourth to last character, which succeeds because only then is there a foo left after the .* has "eaten" the earlier part of the string.
Here is my take using Cell and Index positions (See the diagram here to distinguish a Cell from an Index).
Greedy - Match as much as possible to the greedy quantifier and the entire regex. If there is no match, backtrack on the greedy quantifier.
Input String: xfooxxxxxxfoo
Regex: .*foo
The above Regex has two parts:
(i)'.*' and
(ii)'foo'
Each of the steps below will analyze the two parts. Additional comments for a match to 'Pass' or 'Fail' is explained within braces.
Step 1:
(i) .* = xfooxxxxxxfoo - PASS ('.*' is a greedy quantifier and will use the entire Input String)
(ii) foo = No character left to match after index 13 - FAIL
Match failed.
Step 2:
(i) .* = xfooxxxxxxfo - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = o - FAIL
Match failed.
Step 3:
(i) .* = xfooxxxxxxf - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = oo - FAIL
Match failed.
Step 4:
(i) .* = xfooxxxxxx - PASS (Backtracking on the greedy quantifier '.*')
(ii) foo = foo - PASS
Report MATCH
Result: 1 match(es)
I found the text "xfooxxxxxxfoo" starting at index 0 and ending at index 13.
Reluctant - Match as little as possible to the reluctant quantifier and match the entire regex. if there is no match, add characters to the reluctant quantifier.
Input String: xfooxxxxxxfoo
Regex: .*?foo
The above regex has two parts:
(i) '.*?' and
(ii) 'foo'
Step 1:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 0 having '' is a match.)
foo = xfo - FAIL (Cell 0,1,2 - i.e index between 0 and 3)
Match failed.
Step 2:
.*? = x - PASS (Add characters to the reluctant quantifier '.*?'. Cell 0 having 'x' is a match.)
foo = foo - PASS
Report MATCH
Step 3:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 4 having '' is a match.)
foo = xxx - FAIL (Cell 4,5,6 - i.e index between 4 and 7)
Match failed.
Step 4:
.*? = x - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4.)
foo = xxx - FAIL (Cell 5,6,7 - i.e index between 5 and 8)
Match failed.
Step 5:
.*? = xx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 5.)
foo = xxx - FAIL (Cell 6,7,8 - i.e index between 6 and 9)
Match failed.
Step 6:
.*? = xxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 6.)
foo = xxx - FAIL (Cell 7,8,9 - i.e index between 7 and 10)
Match failed.
Step 7:
.*? = xxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 7.)
foo = xxf - FAIL (Cell 8,9,10 - i.e index between 8 and 11)
Match failed.
Step 8:
.*? = xxxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 8.)
foo = xfo - FAIL (Cell 9,10,11 - i.e index between 9 and 12)
Match failed.
Step 9:
.*? = xxxxxx - PASS (Add characters to the reluctant quantifier '.*?'. Cell 4 thru 9.)
foo = foo - PASS (Cell 10,11,12 - i.e index between 10 and 13)
Report MATCH
Step 10:
.*? = '' (blank) - PASS (Match as little as possible to the reluctant quantifier '.*?'. Index 13 is blank.)
foo = No character left to match - FAIL (There is nothing after index 13 to match)
Match failed.
Result: 2 match(es)
I found the text "xfoo" starting at index 0 and ending at index 4.
I found the text "xxxxxxfoo" starting at index 4 and ending at index 13.
Possessive - Match as much as possible to the possessive quantifer and match the entire regex. Do NOT backtrack.
Input String: xfooxxxxxxfoo
Regex: .*+foo
The above regex has two parts: '.*+' and 'foo'.
Step 1:
.*+ = xfooxxxxxxfoo - PASS (Match as much as possible to the possessive quantifier '.*')
foo = No character left to match - FAIL (Nothing to match after index 13)
Match failed.
Note: Backtracking is not allowed.
Result: 0 match(es)
Greedy: "match the longest possible sequence of characters"
Reluctant: "match the shortest possible sequence of characters"
Possessive: This is a bit strange as it does NOT (in contrast to greedy and reluctant) try to find a match for the whole regex.
By the way: No regex pattern matcher implementation will ever use backtracking. All real-life pattern matcher are extremely fast - nearly independent of the complexity of the regular expression!
Greedy Quantification involves pattern matching using all of the remaining unvalidated characters of a string during an iteration. Unvalidated characters start in the active sequence. Every time a match does not occur, the character at the end is quarantined and the check is performed again.
When only leading conditions of the regex pattern are satisfied by the active sequence, an attempt is made to validate the remaining conditions against the quarantine. If this validation is successful, matched characters in the quarantine are validated and residual unmatched characters remain unvalidated and will be used when the process begins anew in the next iteration.
The flow of characters is from the active sequence into the quarantine. The resulting behavior is that as much of the original sequence is included in a match as possible.
Reluctant Quantification is mostly the same as greedy qualification except the flow of characters is the opposite--that is, they start in the quarantine and flow into the active sequence. The resulting behavior is that as little of the original sequence is included in a match as possible.
Possessive Quantification does not have a quarantine and includes everything in a fixed active sequence.

Why does my regex containing \d{1,} together with a negative lookahead still match, where it shouldn't?

I'm trying to match a coordinate pair in a String using a Regex in Java. I explicitly want to exclude strings using negative lookahead.
to be matched:
558,228
558,228,
558,228,589
558,228,A,B,C
NOT to be matched:
558,228,<Text>
The Regex ^558,228(?!,<).* does the job, while ^\d{1,},\d{1,}(?!,<).* doesn't. It's the same regex with the metacharacter \d instead of values. Any ideas why?
The reason is the .* part at the end. It matches everything that wasn't matched earlier.
In combination with \d{1,}, which allows to match less than 3 digits, it will go like this:
^\d{1,},\d{1,}(?!,<) will match 558,22 and .* will match the remaining part 8,<Text>.
The problem is the \d{1,} part in combination with the .* at the end.
In your case
558,228,<Text>
The ^\d{1,},\d{1,}(?!,<) matches ">558,22" and the .* matches the rest "8,<Text>"
You can solve this using the possessive quanitifier ++
^\d+,\d++(?!,<)(.*)
See it here online on Regexr
\d++ is a seldom used possessive quantifier, which is here useful. ++ means match at least once as many as you can and do not backtrack. That means it will not give back the digits once it has found them.
Java Quantifier tutorial

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