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How to use CONCAT_WS() in Hibernate HQL

To combine multiple columns as one,
I found one answer
SELECT id,CONCAT_WS(',', field_1, field_2, field_3, field_4) list
FROM `table`;
This query working fine in SQL but it gives me error in HQL:
Error is .
(java.lang.IllegalStateException: No data type for node: org.hibernate.hql.internal.ast.tree.MethodNode )
please help me to find out what wrong i did, help me to know how to use CONCAT_WS() IN HQL
below how i written my HQL query
SELECT C1._URI,C1.HEALTH_FACILITY,C1.DISTRICT,CONCAT_WS(',', C1.BLOCKS_OF_BHUBRI, C1.BLOCKS_OF_GOLAGHAT, C1.BLOCKS_OF_HAILAKANDI) as Block_name
FROM GapAnalysisWashInHealthFacilitiesCore C1
any help will appreciate

CONCAT_WS is a function specific to mySql. HQL is a generic language and not aware of native SQL functions and syntax. If you really need the function, then you should use Hibernate's API for native SQL.
Session session = ...;
Query query = session.createSQLQuery("
SELECT id,CONCAT_WS(',', field_1, field_2, field_3, field_4) Block_name FROM `table`");
List result = query.list();
Then you may like to have a look at Result Transformers to get result as list of GapAnalysisWashInHealthFacilitiesCore objects.

How to use Hibernate to query a MySQL database with indexes

I have an application developed based on MySQL that is connected through Hibernate. I used DAO utility code to query the database. Now I need optimize my database query by indexes. My question is, how can I query data through Hibernate DAO utility code and make sure indexes are used in MySQL database when queries are executed. Any hints or pointers to existing examples are appreciated!
Update: Just want to make the question more understandable a little bit. Following is the code I used to query the MySQL database through Hibernated DAO utility codes. I'm not directly using HQL here. Any suggestions for a best solution? If needed, I will rewrite the database query code and use HQL directly instead.
public static List<Measurements> getMeasurementsList(String physicalId, String startdate, String enddate) {
List<Measurements> listOfMeasurements = new ArrayList<Measurements>();
Timestamp queryStartDate = toTimestamp(startdate);
Timestamp queryEndDate = toTimestamp(enddate);
MeasurementsDAO measurementsDAO = new MeasurementsDAO();
PhysicalLocationDAO physicalLocationDAO = new PhysicalLocationDAO();
short id = Short.parseShort(physicalId);
List physicalLocationList = physicalLocationDAO.findByProperty("physicalId", id);
Iterator ite = physicalLocationList.iterator();
while(ite.hasNext()) {
PhysicalLocation physicalLocation = (PhysicalLocation)ite.next();
List measurementsList = measurementsDAO.findByProperty("physicalLocation", physicalLocation);
Iterator jte = measurementsList.iterator();
while(jte.hasNext()){
Measurements measurements = (Measurements)jte.next();
if(measurements.getMeasTstime().after(queryStartDate)
&& measurements.getMeasTstime().before(queryEndDate)) {
listOfMeasurements.add(measurements);
}
}
}
return listOfMeasurements;
}

Just like with SQL, you don't need to do anything special. Just execute your queries as usual, and the database will use the indices you've created to optimize them, if possible.
For example, let's say you have a HQL query that searches all the products that have a given name:
select p from Product where p.name = :name
This query will be translated by Hibernate to SQL:
select p.id, p.name, p.price, p.code from product p where p.name = ?
If you don't have any index set on product.name, the database will have to scan the whole table of products to find those that have the given name.
If you have an index set on product.name, the database will determine that, given the query, it's useful to use this index, and will thus know which rows have the given name thanks to the index. It willl thus be able to only read a small subset of the rows to return the queries data.
This is all transparent to you. You just need to know which queries are slow and frequent enough to justify the creation of an index to speed them up.

Select records which doesn't have specific records in joined table

Hi I'm trying to select records from one table which doesn't have records in connected many-to-many table with specific values.
I will explain on sample tables:
documentation:
id_documentation
irrelevant_data
user:
id_user
irrelevant_data
documentation_user:
id_documentation
id_user
role
What I want to achieve is to select every single documentation which doesn't have user in specific role. Any ideas?
The main problem is that I'm using java's CriteriaBuilder to create query so using subqueries is impossible (I think).

You can add restrictions on your left join using: createAlias(java.lang.String, java.lang.String, int, org.hibernate.criterion.Criterion) method, see API.
Check this answer for an example on how to use the left join with a criteria.

Main problem does not exist - Criteria API do have SubQuery. Query itself selects instances of User and uses not in construct to limit results based to subquery. Subquery selects all users that are connected to document with specific role via DocumentationUser.

Try something like this (code not tested):
CriteriaQuery<Documentation> cq = cb.createQuery(Documentation.class);
Root<Documentation> u = cq.from(Documentation.class);
Subquery<Integer> sq = cq.subquery(Integer.class);
Root<User> su = sq.from(User.class);
sq.select(su.get("id_user"));
Join<User, DocumentationUser> du = su.join("documentationUserCollection");
sq.where(cb.equals(du.get("role"), "mySpecificRole"));
cq.where(cb.not(cb.in(u.get("id_user")).value(sq)));
See also this useful answer on SO.

How to convert nested SQL to HQL

I am new to the Hibernate and HQL. I want to write an update query in HQL, whose SQL equivalent is as follows:
update patient set
`last_name` = "new_last",
`first_name` = "new_first"
where id = (select doctor_id from doctor
where clinic_id = 22 and city = 'abc_city');
doctor_id is PK for doctor and is FK and PK in patient. There is one-to-one mapping.
The corresponding Java classes are Patient (with fields lastName, firstName, doctorId) and Doctor (with fields doctorId).
Can anyone please tell what will be the HQL equivalent of the above SQL query?
Thanks a lot.

String update = "update Patient p set p.last_name = :new_last, p.first_name = :new_first where p.id = some (select doctor.id from Doctor doctor where doctor.clinic_id = 22 and city = 'abc_city')";
You can work out how to phrase hql queries if you check the specification. You can find a section about subqueries there.

I don't think you need HQL (I know, you ask that explicitly, but since you say you're new to Hibernate, let me offer a Hibernate-style alternative). I am not a favor of HQL, because you are still dealing with strings, which can become hard to maintain, just like SQL, and you loose type safety.
Instead, use Hibernate criteria queries and methods to query your data. Depending on your class mapping, you could do something like this:
List patients = session.CreateCriteria(typeof(Patient.class))
.createAlias("doctor", "dr")
.add(Restrictions.Eq("dr.clinic_id", 22))
.add(Restrictions.Eq("dr.city", "abc_city"))
.list();
// go through the patients and set the properties something like this:
for(Patient p : patients)
{
p.lastName = "new lastname";
p.firstName = "new firstname";
}
Some people argue that using CreateCriteria is difficult. It takes a little getting used to, true, but it has the advantage of type safety and complexities can easily be hidden behind generic classes. Google for "Hibernate java GetByProperty" and you see what I mean.

update Patient set last_name = :new_last , first_name = :new_first where patient.id = some(select doctor_id from Doctor as doctor where clinic_id = 22 and city = abc_city)

There is a significant difference between executing update with select and actually fetching the records to the client, updating them and posting them back:
UPDATE x SET a=:a WHERE b in (SELECT ...)
works in the database, no data is transferred to the client.
list=CreateCriteria().add(Restriction).list();
brings all the records to be updated to the client, updates them, then posts them back to the database, probably with one UPDATE per record.
Using UPDATE is much, much faster than using criteria (think thousands of times).

Since the question title can be interpreted generally as "How to use nested selects in hibernate", and the HQL syntax restricts nested selects only to be in the select- and the where-clause, I would like to add here the possibility to use native SQL as well. In Oracle - for instance - you may also use a nested select in the from-clause.
Following query with two nested inner selects cannot be expressed by HQL:
select ext, count(ext)
from (
select substr(s, nullif( instr(s,'.', -1) +1, 1) ) as ext
from (
select b.FILE_NAME as s from ATTACHMENT_B b
union select att.FILE_NAME as s from ATTACHEMENT_FOR_MAIL att
)
)
GROUP BY ext
order by ext;
(which counts, BTW, the occurences of each distinct file name extension in two different tables).
You can use such an sql string as native sql like this:
#Autowired
private SessionFactory sessionFactory;
String sql = ...
SQLQuery qry = sessionFactory.getCurrentSession().createSQLQuery(sql);
// provide an appropriate ResultTransformer
return qry.list();

EJB-QL question how would I set a list as a parameter like: select o from table where id in (List<Long> listOfIds)

IN EJB-QL I am trying to create a query like this:
SELECT *
FROM table
WHERE id IN ([id1],[id2],[id3],...);
This is a normal query for oracle or mysql but how can I make EJB-QL set parameters as a list?
SELECT o
FROM ClassName
WHERE ClassNameId IN (List<Long> listOfIds);
is there a way to do this?
More importantly is would this be more efficient then running a separate query for each id in the list?
Any suggestions would be appreciated.
Edit: For clarity I am trying to run one query to return multiple rows based on a list of ids (not the entire table, not the contents of another table, but an arbitrary list of ids). I am hoping to be able to run this query once instead of running a normal find query multiple times (once for each of the ids in the list).
Thanks,
Jim

String queryStr = "select o from ClassName o where o.classNameId IN :ids";
Query query = entityManager.createQuery("queryStr");
List<Long> listOfIds = getIds();
query.setParameter("ids", listOfIds);
List<ClassName> classNameList = (List<ClassName>) query.getResultList();

I'm not an expert with EJB-QL. You might find the examples from here useful.
SELECT OBJECT (o) FROM Order AS o IN (o.lineItems) li
WHERE li.quantity = ?1