I used to write a synchronized block like:
synchronized(foobar) {
// do something
}
But, recently I saw someone write:
synchronized(foobar) {
// do something
foobar.notifyAll();
}
Is foobar.notifyAll(); necessary? What happens if I omit it?
The short answer is that is depends on what you are doing.
If the goal of the synchronized block is simply to ensure that access / updates to a data structure are performed safely, then notify() or notifyAll() serves no purpose.
On the other hand, if the goal is to implement a "condition variable" then the notify() or notifyAll() calls work with a wait call like this ... for example:
private boolean flag;
private final Object mutex = new Object();
public void awaitFlag(boolean flag) {
synchronized (mutex) {
while (this.flag != flag) {
mutex.wait();
}
}
}
public void setFlag(boolean flag) {
synchronized (mutex) {
this.flag = flag;
mutex.notifyAll();
}
}
The above implements a simple mechanism where threads call awaitFlag() to wait for the flag to become true or false. When another thread calls setFlag() to change the flag, all of the threads that are currently waiting for the flag to change will get woken up by the notifyAll(). This is an example where the notifyAll() is essential to the working of the code.
So to understand whether the notify or notifyAll code is necessary, you need to figure out if some other code might call wait on the same mutex / lock object.
You don't need to do this. You only have to do it if the object (here foobar) is waiting to be notified. Notify only Wakes up all threads that are waiting on this object's monitor.
In Java, you can use wait(), notify() and notifyAll() to achieve thread co-ordination. See How to use wait and notify in Java?
The notifyAll() is to tell any other thread sleeping in a foobar.wait() that the current thread is about to release the lock and they can compete for the resource again.
Related
Please note that this is not the actual scenario. I created a sample scenario based on my actual implementation, to make it easy to review. I am also already getting the expected output too. However, I need to clarify some concepts regarding the wait() and notifyAll() methods in Java. (In here both these threads will starts there run method at once in the main thread.) So according to my knowledge, since thread B is sleeping, because you can see at the initial stage reamingCount is 400.
So thread B will calls its MUTEX.wait() and continue its sleep until some other thread invokes a notify() or notifyAll(), then after the remainingCount decrements to 0, thread A will call MUTEX.notifyAll(); to awake the thread B and MUTEX.wait() to release its already granted lock, and go to sleep until thread B notifies it.
When I call MUTEX.notifyAll() through thread A, won't thread B wake up and continue its task before thread A calls MUTEX.wait()?
I mean, you can see when thread A calls the MUTEX.notifyAll(), thread B will awake and check again if the condition in the while loop is true or false. So, since the remainingCount is equal to 0, thread B will exit the while loop and continue its task before thread A calls wait(). Won't this scenario break the principle of wait()? According to my knowledge thread B can only continue its execution when thread A calls wait().
public class A implements Runnable{
public static volatile remainingCount =400;
private final Object MUTEX;//Both class A and B holds the same object mutex
private void methodA(){
synchronized(MUTEX){
while(remainingCount == 0){
MUTEX.notifyAll();
MUTEX.wait();
}
//Perform it's usual task.In here remaining count will decrement during the process.
}
#Override
public void run() {
while(true){
methodA();
}
}
}
}
public class B implements Runnable{
private final Object MUTEX;//Both class A and B holds the same object mutex
private void methodB(){
synchronized(MUTEX){
while (A.remainingCount != 0) {
try {
MUTEX.wait();
} catch (InterruptedException ex) {
Logger.getLogger(InkServiceImpl.class.getName()).log(Level.SEVERE, null, ex);
}
}
//incrementing the A.remainingCount
MUTEX.notifyAll();
}
#Override
public void run() {
while(true){
methodB();
}
}
}
When a thread holding a lock calls wait() on the locked object, the thread is added to the object's wait set and the lock is released.
When a thread holding a lock calls notify(), and the wait set is not empty, a thread in the wait set is selected and removed. Likewise, calling notifyAll() removes all threads from the wait set.
Note: threads can also be removed from the wait set by a call to thread.interrupt().
When a thread is removed from the wait set and begins to run, the first step is to reacquire the lock. This happens before the return from wait().
This will not happen until the thread that called notify() or notifyAll() releases the lock by either calling wait() or exiting the synchronized block.
So, while your thread B has been enabled to run, it won't actually return from wait() until thread A releases the lock by calling MUTEX.wait(). Likewise, thread A is enabled to run when B calls MUTEX.notifyAll(), but doesn't return from wait() until thread B exits the synchronized(MUTEX) block.
I am using multi-threading in java for my program.
I have run thread successfully but when I am using Thread.wait(), it is throwing java.lang.IllegalMonitorStateException.
How can I make a thread wait until it will be notified?
You need to be in a synchronized block in order for Object.wait() to work.
Also, I recommend looking at the concurrency packages instead of the old school threading packages. They are safer and way easier to work with.
EDIT
I assumed you meant Object.wait() as your exception is what happens when you try to gain access without holding the objects lock.
wait is defined in Object, and not it Thread. The monitor on Thread is a little unpredictable.
Although all Java objects have monitors, it is generally better to have a dedicated lock:
private final Object lock = new Object();
You can get slightly easier to read diagnostics, at a small memory cost (about 2K per process) by using a named class:
private static final class Lock { }
private final Object lock = new Lock();
In order to wait or notify/notifyAll an object, you need to be holding the lock with the synchronized statement. Also, you will need a while loop to check for the wakeup condition (find a good text on threading to explain why).
synchronized (lock) {
while (!isWakeupNeeded()) {
lock.wait();
}
}
To notify:
synchronized (lock) {
makeWakeupNeeded();
lock.notifyAll();
}
It is well worth getting to understand both Java language and java.util.concurrent.locks locks (and java.util.concurrent.atomic) when getting into multithreading. But use java.util.concurrent data structures whenever you can.
I know this thread is almost 2 years old but still need to close this since I also came to this Q/A session with same issue...
Please read this definition of illegalMonitorException again and again...
IllegalMonitorException is thrown to indicate that a thread has attempted to wait on an object's monitor or to notify other threads waiting on an object's monitor without owning the specified monitor.
This line again and again says, IllegalMonitorException comes when one of the 2 situation occurs....
1> wait on an object's monitor without owning the specified monitor.
2> notify other threads waiting on an object's monitor without owning the specified monitor.
Some might have got their answers... who all doesn't, then please check 2 statements....
synchronized (object)
object.wait()
If both object are same... then no illegalMonitorException can come.
Now again read the IllegalMonitorException definition and you wont forget it again...
Based on your comments it sounds like you are doing something like this:
Thread thread = new Thread(new Runnable(){
public void run() { // do stuff }});
thread.start();
...
thread.wait();
There are three problems.
As others have said, obj.wait() can only be called if the current thread holds the primitive lock / mutex for obj. If the current thread does not hold the lock, you get the exception you are seeing.
The thread.wait() call does not do what you seem to be expecting it to do. Specifically, thread.wait() does not cause the nominated thread to wait. Rather it causes the current thread to wait until some other thread calls thread.notify() or thread.notifyAll().
There is actually no safe way to force a Thread instance to pause if it doesn't want to. (The nearest that Java has to this is the deprecated Thread.suspend() method, but that method is inherently unsafe, as is explained in the Javadoc.)
If you want the newly started Thread to pause, the best way to do it is to create a CountdownLatch instance and have the thread call await() on the latch to pause itself. The main thread would then call countDown() on the latch to let the paused thread continue.
Orthogonal to the previous points, using a Thread object as a lock / mutex may cause problems. For example, the javadoc for Thread::join says:
This implementation uses a loop of this.wait calls conditioned on this.isAlive. As a thread terminates the this.notifyAll method is invoked. It is recommended that applications not use wait, notify, or notifyAll on Thread instances.
Since you haven't posted code, we're kind of working in the dark. What are the details of the exception?
Are you calling Thread.wait() from within the thread, or outside it?
I ask this because according to the javadoc for IllegalMonitorStateException, it is:
Thrown to indicate that a thread has attempted to wait on an object's monitor or to notify other threads waiting on an object's monitor without owning the specified monitor.
To clarify this answer, this call to wait on a thread also throws IllegalMonitorStateException, despite being called from within a synchronized block:
private static final class Lock { }
private final Object lock = new Lock();
#Test
public void testRun() {
ThreadWorker worker = new ThreadWorker();
System.out.println ("Starting worker");
worker.start();
System.out.println ("Worker started - telling it to wait");
try {
synchronized (lock) {
worker.wait();
}
} catch (InterruptedException e1) {
String msg = "InterruptedException: [" + e1.getLocalizedMessage() + "]";
System.out.println (msg);
e1.printStackTrace();
System.out.flush();
}
System.out.println ("Worker done waiting, we're now waiting for it by joining");
try {
worker.join();
} catch (InterruptedException ex) { }
}
In order to deal with the IllegalMonitorStateException, you must verify that all invocations of the wait, notify and notifyAll methods are taking place only when the calling thread owns the appropriate monitor. The most simple solution is to enclose these calls inside synchronized blocks. The synchronization object that shall be invoked in the synchronized statement is the one whose monitor must be acquired.
Here is the simple example for to understand the concept of monitor
public class SimpleMonitorState {
public static void main(String args[]) throws InterruptedException {
SimpleMonitorState t = new SimpleMonitorState();
SimpleRunnable m = new SimpleRunnable(t);
Thread t1 = new Thread(m);
t1.start();
t.call();
}
public void call() throws InterruptedException {
synchronized (this) {
wait();
System.out.println("Single by Threads ");
}
}
}
class SimpleRunnable implements Runnable {
SimpleMonitorState t;
SimpleRunnable(SimpleMonitorState t) {
this.t = t;
}
#Override
public void run() {
try {
// Sleep
Thread.sleep(10000);
synchronized (this.t) {
this.t.notify();
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
Thread.wait() call make sense inside a code that synchronizes on Thread.class object. I don't think it's what you meant.
You ask
How can I make a thread wait until it will be notified?
You can make only your current thread wait. Any other thread can be only gently asked to wait, if it agree.
If you want to wait for some condition, you need a lock object - Thread.class object is a very bad choice - it is a singleton AFAIK so synchronizing on it (except for Thread static methods) is dangerous.
Details for synchronization and waiting are already explained by Tom Hawtin.
java.lang.IllegalMonitorStateException means you are trying to wait on object on which you are not synchronized - it's illegal to do so.
Not sure if this will help somebody else out or not but this was the key part to fix my problem in user "Tom Hawtin - tacklin"'s answer above:
synchronized (lock) {
makeWakeupNeeded();
lock.notifyAll();
}
Just the fact that the "lock" is passed as an argument in synchronized() and it is also used in "lock".notifyAll();
Once I made it in those 2 places I got it working
I received a IllegalMonitorStateException while trying to wake up a thread in / from a different class / thread. In java 8 you can use the lock features of the new Concurrency API instead of synchronized functions.
I was already storing objects for asynchronous websocket transactions in a WeakHashMap. The solution in my case was to also store a lock object in a ConcurrentHashMap for synchronous replies. Note the condition.await (not .wait).
To handle the multi threading I used a Executors.newCachedThreadPool() to create a thread pool.
Those who are using Java 7.0 or below version can refer the code which I used here and it works.
public class WaitTest {
private final Lock lock = new ReentrantLock();
private final Condition condition = lock.newCondition();
public void waitHere(long waitTime) {
System.out.println("wait started...");
lock.lock();
try {
condition.await(waitTime, TimeUnit.SECONDS);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
lock.unlock();
System.out.println("wait ends here...");
}
public static void main(String[] args) {
//Your Code
new WaitTest().waitHere(10);
//Your Code
}
}
For calling wait()/notify() on object, it needs to be inside synchronized block. So first you have to take lock on object then would be possible to call these function.
synchronized(obj)
{
obj.wait()
}
For detailed explanation:
https://dzone.com/articles/multithreading-java-and-interviewspart-2
wait(), notify() and notifyAll() methods should only be called in syncronized contexts.
For example, in a syncronized block:
syncronized (obj) {
obj.wait();
}
Or, in a syncronized method:
syncronized static void myMethod() {
wait();
}
I'm studying for an exam from a Book given by my professor and there is this code working with Threads and Synchronization: We want to be notified everytime the state changes (without missing a state change).
public class C {
private int state = 0; // the state
private boolean modified = false; // to show if the state was changed since actualization
public synchronized void printNewState() {
while (true) {
if (!modified) {
wait();
}
System.out.println(state);
modified = false;
notify();
}
}
public synchronized void setValue(int v) {
if (modified) {
wait();
}
state = v;
notify();
modified = true;
System.out.println("value set");
}
}
And then it's writen:
However, it is not guaranteed that notify() in the method SetValue(int) wakes up the printNewState Thread! In Java we solve this problem
with the help of notifyAll() and take a little busy waiting:
public synchronized void printNewState() {
while (true) {
while (!modified) {
wait();
}
System.out.println(state);
modified = false;
**notify();** \\(?)
}
}
public synchronized void setValue(int v) {
while (modified) {
wait();
}
state = v;
notifyAll();
modified = true;
System.out.println("value set");
}
I don't understand why the notify wasn't also changed to notifyAll()? It might not be guaranteed that this notify goes to a Thread of setValue(int) ???
Thank you
The notify() method wakes up a single waiting thread, whereas the notifyAll() method wakes up all the waiting threads. The problem is that with notify(), the thread that is woken up is effectively random.
If some other thread is accidentally or maliciously wait()ing on the same object, it could receive the notification instead of the thread you expect to wake up.
Take a look at this answer for some more information. The comments on that answer are also quite interesting.
EDIT
In the code sample you posted, the first notify() within printNewState() can handle only one update at a time, so it doesn't make sense to notify all waiting threads to post their updates. The code assumes, however, that only threads invoking setValue(int) are waiting.
Since public synchronized void setValue(int) is essentially the same as having synchronized(this) as the first line of the method, that isn't actually guaranteed. Any code that has a reference to an instance of C class can wait on it and screw up the code.
The synchronization and wait/notify actions should happen on an object lock/monitor. private final Object monitor = new Object(), synchronized(this.monitor), this.monitor.wait(), this.monitor.notifyAll(), etc.
I would also like to note that modified = true needs to be placed before notifyAll() in setValue(int), otherwise other waiting update threads will proceed without printNewState() noticing the update.
Also, private boolean modified should really be private volatile boolean modified, and the same for private int state, though an AtomicInteger may be a better option.
I am trying to understand how ReentrantLock works in java.
Lets consider a simple example below :
private ReentrantLock lock;
public void foo() {
lock.lock();
try{
...
}finally {
lock.unlock();
}
}
I was trying to figure out the call hierarchy of lock() method.
public void lock() {
sync.lock();
}
For FairSync :
final void lock() {
acquire(1);
}
For NonFairSync :
final void lock() {
if (compareAndSetState(0, 1))
setExclusiveOwnerThread(Thread.currentThread());
else
acquire(1);
}
Both lock() methods call acquire() method with argument as 1.
In AbstractQueuedSynchronizer class :
public final void acquire(int arg) {
if (!tryAcquire(arg) &&
acquireQueued(addWaiter(Node.EXCLUSIVE), arg))
selfInterrupt();
}
static void selfInterrupt() {
Thread.currentThread().interrupt();
}
If current thread cannot acquire a resource (i.e. some another thread has acquired this resource) , then current thread has to wait. In this case ReentrantLock calls selfInterrupt() method.
Now my question is how interrupt() method can stop a thread which is equivalent to wait() method in synchronized ?
Also , after the resource has been released by another thread, how currentThread start automatically? ( After calling unlock() method by another thread which is internally calling sync.release(1); )
I also tried to figure out how interrupt() method works from here but unable to find answer to my questions.
If current thread cannot acquire a resource (i.e. some another thread
has acquired this resource) , then current thread has to wait. In this
case ReentrantLock calls selfInterrupt() method.
No, if tryAcquire returns false, acquireQueued will be called. Internally, that method uses LockSupport#park to unschedule the thread. The javadoc states
If the permit is available then it is consumed and the call returns
immediately; otherwise the current thread becomes disabled for thread
scheduling purposes and lies dormant until one of three things
happens:
- [..]
- Some other thread interrupts the current thread;
It doesn't actually throw an InterruptedException in this case, the method just returns. To check if the corresponding thread was woken up due to an interrupt, it has to use Thread#interrupted() which returns true or false depending, but also clears the interrupt flag on the corresponding Thread instance.
So the acquireQueued propagates that interrupted value back up and lets acquire reset the interrupt flag on the Thread if needed in that little piece of code
if (!tryAcquire(arg) &&
acquireQueued(addWaiter(Node.EXCLUSIVE), arg))
selfInterrupt();
Also , after the resource has been released by another thread, how
currentThread start automatically?
Again, it makes uses of the LockSupport utility with unpark
Makes available the permit for the given thread, if it was not already
available. If the thread was blocked on park then it will unblock.
I want to have a boolean to notify some sections of the system that a specific service started.
For some strange reason I'm getting the error java.lang.IllegalMonitorStateException: object not locked by thread before notifyAll().
What is strange is that the notifyAll() is inside a synchronized block that takes control over the object that I call notifyAll() on.
My class starts like this:
public class MyService {
public static Boolean notifier = Boolean.valueOf(false);
#Override
public void start() {
synchronized (MyService.notifier) {
MyService.notifier = Boolean.valueOf(true);
MyService.notifier.notifyAll();
}
}
#Override
public void stop() {
synchronized (MyService.notifier) {
MyService.notifier = Boolean.valueOf(false);
MyService.notifier.notifyAll();
}
}
...
}
I'm working on an android application. I don't think it should affect anything, but I'm complementing the question with that comment in case that affects the way that java works.
Why am I getting the exception if the object is locked inside a synchronized block?
The line
MyService.notifier = Boolean.valueOf(true);
swaps out the object you're locking on, it overwrites the variable with a reference to a new object. So the object you acquired the lock on upon entering the block is not the same one that you're calling notifyAll on. All notifyAll knows is it hasn't acquired the lock on the object it's being called on, which is the new object created after the synchronize block was entered.
All the threads need to be using the same lock. Like Ian Roberts said, the lock belongs to the object. If you overwrite the object you have a new lock.