I have checked the tutorials and this should work but it doesn't. I have a string in one class that I want to use in another, but when I do, I get a null exception.
#ViewScoped
#ManagedBean
public class FileDirectoryViewer {
FileUploadController destination = new FileUploadController();
NewDestination = destination + username + "/";
And I am trying to get the destination from
#ViewScoped
#ManagedBean(name = "fileUploadController")
public class FileUploadController {
public String destination = "D:/Documents/NetBeansProjects/printing~subversion/fileupload/Uploaded/"; // main location for uploads
How do I get the destination from FileUploadController to FileDirectoryViewer?
The destination field of FileUploadController, has no access modifier, so it is package private by default.
If those two classes are in the same package, you can access it by creating an instance of the class, and using the . operator on the instance to access the property:
FileUploadController controller = new FileUploadController();
NewDestination = controller.destination + username + "/";
If they are not, you should implement a public String getDestination() method in FileUploadController that would return destination. You should call this method also by using the . operator: controller.getDestination().
Take into account there are several issues with the code you posted:
You're placing code outside a method in the FileDirectoryViewer class. In a class you can only define members (such as fields, or methods). Generally speaking, behavorial code goes inside of method declarations.
Using a hardcoded variable for a path property can be considered bad practice. Look into java.util.Properties for a start. Anyway, by the looks of the code, it doesn't make sense for the destination field to be an instance field, it could be static or defined in an interface.
Naming conventions for java recommend variable names to be camel case, and starting with lower case letters.
Related
I am writing a Java program where a method in one class needs to access a method of an object that is a member of another class. I can do this in at least two different ways, passing as a parameter, or directly accessing the object using the name of the class it is a member of. I find a lot of questions about pass-by-reference vs. pass-by-value, but I can't find anything that addresses this scenario.
Here is some pseudo-code showing what I mean:
// class of object to pass
class MyPrefs {
public String getPref(int i){
String s = ... //some code to get a String indexed by i
return s;
}
}
// class where object is instantiated
class Main {
protected static MyPrefs prefs = new MyPrefs();
}
Here are the two options I am looking at. In a third class, Toolbar, I can do either of these:
// pass as parameter
class Toolbar{
public void applyPrefs(MyPrefs p){
String s = p.getPref(1);
...
}
//or use qualified name of object
class Toolbar{
public void applyPrefs(){
String s = Main.prefs.getPref(1);
...
}
}
It works either way, what I would like to know is what are the merits or problems associated with each method, and if there is another way of doing this that I hadn't considered.
I hope this question doesn't get closed for being opinion-based because technically it is. So, I am not going to claim my answer is based on some undisputed best-practice, but I do believe it is generally accepted as the correct approach.
In my opinion, it would be either a variant of the first, and/or a combination of the two. For example:
public static String getProp(String prop) {
// use java.util.Properties to retrieve the property.
}
This works well when your application has a single property file. In cases you have multiple property files, you need to override this method and pass the path to the correct file.
public static String getProp(String filename, String prop) {
// use java.util.Properties to retrieve the property.
}
Where filename could be just the file name or the fully qualified name (with the path). I tend to keep all my property files in the same folder, so I "hard-code" the path and use that as the base location for my files, so most of the time when using this approach, I only need the actual file name.
I also have created utility methods to obtain specific properties where the name of the method implies what property I am obtaining. This is useful for people that are not too familiarized with the property keys.
public static String getXYZProp() {
// use java.util.Properties to load the properties.
return prop.getProperty("XYZ");
}
Alternatively, you should take advantage of the genetic method you created to do the same
public static String getXYZProp() {
return getProp("XYZ");
}
Or even something like
public static String getXYZProp() {
return getProp("someProps.properties", "XYZ");
}
It is OK to have multiple method that ultimately do the same thing. Think that some users will call the generic ones because they are more familiarized with the property keys while others will rely on method with names that help them figure out what properties they need to retrieve.
I implemented an object builder which takes a class name and tries to create a new instance object. The builder tries to inject services if any required. The class name is passed as a string in the current implementation. Here is an example
$className = '\Example\Application\ServiceClass';
$service = CiContext::newInstance($className);
However, this is not compatible with my IDE (eclipse) and the refactoring process does not find the class name (in the string form).
Is there any way to get the class name like java does?
Class classInstance = ServerClass.class;
In this case, the refactoring process finds the class reference and changes the class name.
Well, PHP7 class constant is supported on a class name. For example, the following code is correct in PHP 7.4:
$service = CiContext::newInstance(\Example\Application\ServiceClass::class);
This will solve my problem and the IDE find the class usage.
On the other hand, the class literal is going to support for objects too. For more information see class literal on object
I'd like to know whats the common style to maintain path constants for Rest Controllers.
For example you have something like that:
#RequestMapping(method = RequestMethod.GET, value = ANY_PATH_VALUE)
I do maintain those constants (in the example ANY_PATH_VALUE) at the moment in a class called PathConstants which looks like this:
public abstract class PathConstants {
public static final String ANY_PATH_VALUE = "/path/{SOME_ID}";
...
}
Is it a common way to keep those values straight at the method of the RestController class or is it like I do currently? Or is there a even more common way how to maintain this kind of stuff?
There are two sides to this,
It actually has close to zero performance problem. This has to something with readability.
The first view is keeping the values as native strings there itself in the controllers. This is more readable in the sense that you can directly check the exact API route when you enter the controller.
The second view is keeping it in some other file with static constants. Keeping all the routes like this actually gives you one common place where you can get to know all the API routes you currently support in your application.
I personally prefer the second i.e. keeping all the paths in a file called APIRoutes and further divided by domains.
public class APIRoutes {
public class SYSTEM {
public static final String HEALTH_CHECK = "api/v1/healthcheck";
public static final String LB_HEALTH_CHECK = "lb/v1/healthcheck";
}
public class API {
public static final String SAVE_X = "api/v1/save";
public static final String GET_X = "api/v1/get";
}
public class CACHE {
public static final String RELOAD_X = "cache/v1/load/x";
public static final String RELOAD_Y = "cache/v1/load/y";
}
}
This way in your controller, you have something like
#RequestMapping(method = RequestMethod.GET, value = APIRoutes.API.SAVE_X)
Using constants seems to be a quite reasonable approach. I would, however, define the constants in a final class with a private constructor throwing an AssertionError to enforce noninstantiability:
public final class PathConstants {
// Suppress default constructor for noninstantiability
private PathConstants() {
throw new AssertionError("No instances for you!");
}
public static final String PATH_TO_FOO = "foo";
public static final String PATH_TO_BAR = "bar";
}
Quoting the Item 4 from Effective Java 3rd edition from Joshua Bloch:
Because the explicit constructor is private, it is inaccessible outside the class. The AssertionError isn’t strictly required, but it provides insurance in case the constructor is accidentally invoked from within the class. It guarantees the class will never be instantiated under any circumstances. This idiom is mildly counterintuitive because the constructor is provided expressly so that it cannot be invoked. It is therefore wise to include a comment, as shown earlier.
As a side effect, this idiom also prevents the class from being subclassed. All constructors must invoke a superclass constructor, explicitly or implicitly, and a subclass would have no accessible superclass constructor to invoke.
You also could use something like #RequestMapping("${foo.bar}"), where foo.bar is a value defined in a property souce (such as an application.properties file or YAML variant).
Quoting the Spring MVC documentation:
URI path patterns can also have embedded ${…} placeholders that are resolved on startup by using PropertyPlaceHolderConfigurer against local, system, environment, and other property sources. You can use this, for example, to parameterize a base URL based on some external configuration.
I think it is a reasonable way to maintain paths. Just make sure you always build the paths from other constants. For example, if your path has version, you define the version as another variable.
public static final String VERSION_1 = "/v1";
public static final String USERS_V1 = VERSION_1 + "/users";
I have a class that must have some static methods. Inside these static methods I need to call the method getClass() to make the following call:
public static void startMusic() {
URL songPath = getClass().getClassLoader().getResource("background.midi");
}
However Eclipse tells me:
Cannot make a static reference to the non-static method getClass()
from the type Object
What is the appropriate way to fix this compile time error?
The Answer
Just use TheClassName.class instead of getClass().
Declaring Loggers
Since this gets so much attention for a specific usecase--to provide an easy way to insert log declarations--I thought I'd add my thoughts on that. Log frameworks often expect the log to be constrained to a certain context, say a fully-qualified class name. So they are not copy-pastable without modification. Suggestions for paste-safe log declarations are provided in other answers, but they have downsides such as inflating bytecode or adding runtime introspection. I don't recommend these. Copy-paste is an editor concern, so an editor solution is most appropriate.
In IntelliJ, I recommend adding a Live Template:
Use "log" as the abbreviation
Use private static final org.slf4j.Logger logger = org.slf4j.LoggerFactory.getLogger($CLASS$.class); as the template text.
Click Edit Variables and add CLASS using the expression className()
Check the boxes to reformat and shorten FQ names.
Change the context to Java: declaration.
Now if you type log<tab> it'll automatically expand to
private static final Logger logger = LoggerFactory.getLogger(ClassName.class);
And automatically reformat and optimize the imports for you.
As for the code example in the question, the standard solution is to reference the class explicitly by its name, and it is even possible to do without getClassLoader() call:
class MyClass {
public static void startMusic() {
URL songPath = MyClass.class.getResource("background.midi");
}
}
This approach still has a back side that it is not very safe against copy/paste errors in case you need to replicate this code to a number of similar classes.
And as for the exact question in the headline, there is a trick posted in the adjacent thread:
Class currentClass = new Object() { }.getClass().getEnclosingClass();
It uses a nested anonymous Object subclass to get hold of the execution context. This trick has a benefit of being copy/paste safe...
Caution when using this in a Base Class that other classes inherit from:
It is also worth noting that if this snippet is shaped as a static method of some base class then currentClass value will always be a reference to that base class rather than to any subclass that may be using that method.
In Java7+ you can do this in static methods/fields:
MethodHandles.lookup().lookupClass()
I wrestled with this myself. A nice trick is to use use the current thread to get a ClassLoader when in a static context. This will work in a Hadoop MapReduce as well. Other methods work when running locally, but return a null InputStream when used in a MapReduce.
public static InputStream getResource(String resource) throws Exception {
ClassLoader cl = Thread.currentThread().getContextClassLoader();
InputStream is = cl.getResourceAsStream(resource);
return is;
}
Simply use a class literal, i.e. NameOfClass.class
Try it
Thread.currentThread().getStackTrace()[1].getClassName()
Or
Thread.currentThread().getStackTrace()[2].getClassName()
getClass() method is defined in Object class with the following signature:
public final Class getClass()
Since it is not defined as static, you can not call it within a static code block. See these answers for more information: Q1, Q2, Q3.
If you're in a static context, then you have to use the class literal expression to get the Class, so you basically have to do like:
Foo.class
This type of expression is called Class Literals and they are explained in Java Language Specification Book as follows:
A class literal is an expression consisting of the name of a class, interface, array, or primitive type followed by a `.' and the token class. The type of a class literal is Class. It evaluates to the Class object for the named type (or for void) as defined by the defining class loader of the class of the current instance.
You can also find information about this subject on API documentation for Class.
I had the same problem !
but to solve it just modify your code as following.
public static void startMusic() {
URL songPath = YouClassName.class.getClassLoader().getResource("background.midi");
}
this worked fine with me hope it will also work fine with you.
Suppose there is a Utility class, then sample code would be -
URL url = Utility.class.getClassLoader().getResource("customLocation/".concat("abc.txt"));
CustomLocation - if any folder structure within resources otherwise remove this string literal.
Try something like this. It works for me. Logg (Class name)
String level= "";
Properties prop = new Properties();
InputStream in =
Logg.class.getResourceAsStream("resources\\config");
if (in != null) {
prop.load(in);
} else {
throw new FileNotFoundException("property file '" + in + "' not found in the classpath");
}
level = prop.getProperty("Level");
In my application I need data which is accessible for a few activities. I've read that a good solution is to use Application class for this. So I use it like this:
public class MyApplication extends Application {
private String str;
public String getStr(){
return str;
}
public void setStr(String s){
str = s;
}
}
and I can access this variable from activity like this:
MyApplication appState = ((MyApplication)getApplicationContext());
String str = appState.getStr();
It's ok, but I also have xml parser class:
public class MyXMLHandler extends DefaultHandler {
and if I try to do the same here
MyApplication app = ((MyApplication)getApplicationContext());
String str = app.getStr();
I'm getting The method getApplicationContext() is undefined for the type MyXMLHandler
How can I access my variable?
Well, usually an XML parser class should be independent of any special context. That means a developer should be able to use it no matter whether he's developing an application or a service or library or whathever.
The XML parser class should not make any assumptions as to the context it is being used in and where it gets parameters from (you'd restrict your parser to function only if it has access to an Application instance). The parser should not fetch its parameters, the parameters should be set by the caller.
You wouldn't want your XML parser class to show messages to the user, either, would you? Right: "What does an XML parser have to do with user interfaces?" Instead, you'd throw exceptions and make sure they are handled properly, for example depending on whether there's a user interface or not (logging).
So what you'd do is pass the parameters you need when constructing an instance of your XML parser. But you do not pass your application instance as a parameter (think again of dependencies), but you pass the necessary parameters from your application class.
In your example above:
MyApplication app = ((MyApplication)getApplicationContext());
MyXmlHandler handler = new MyXmlHandler(app.getStr());
You should really make sure to keep "tool stuff" separate from anything that would prevent you from using it universally. What would happen if you wanted to use your XML Parser class in another project where your parameter is not provided by the application context but some other class?
I'm sure that you can have a week-long discussion about object-oriented design and how things should be done - but that's basically how I'd do it...