How to do custom order on java ENUMS? - java

I have Enum class as
public enum ServiceTypes {
Zero("zero", 6, true),
AVL("Avl", 1, true),
VPS("vps", 2, true),
CALCULATOR("calculator", 3, true),
SIMULATOR("Simulator", 4, true),
CONTRACT("Contract Output", 5, true),
ALL("all", 7, true);
private static final OrderComparator orderComparator = new OrderComparator();
private static final OrderComparator nameComparator = new OrderComparator();
#Nonnull
public static ServiceTypes[] getOrderedServiceTypes() {
Arrays.sort(values(), orderComparator);
return values();
}
#Nonnull
public static ServiceTypes[] getNamedServiceTypes() {
Arrays.sort(values(), nameComparator);
return values();
}
private static final class OrderComparator implements Comparator<ServiceTypes> {
#Override
public int compare(final ServiceTypes o1, final ServiceTypes o2) {
return o1.getOrder().compareTo(o2.getOrder());
}
}
private static final class AlphabeticalOrder implements Comparator<ServiceTypes> {
#Override
public int compare(final ServiceTypes o1, final ServiceTypes o2) {
return o1.toString().compareTo(o2.toString());
}
}
}
When I test getOrderedServiceTypes(), I see Zero("zero", 6, true) as the first element , which is incorrect.
Seems like values() is not sorted based on the comparator.
How can I run the custom orders on Enum?

No, what's happening is that values() creates a new array each time, so you're sorting an array of the values and then returning a completely different array.
All you need to do is e.g.
ServiceTypes[] values = values();
Arrays.sort(values, orderComparator);
return values;

Seems like values() is not sorted based on the comparator.
Indeed. As per the specification (section 8.9.2):
(values[]) Returns an array containing the constants of this enum
type, in the order they're declared.
Sorting the array returned by values once isn't going to have any effect - a new array will be handed out on the next call. You can do this though:
public static ServiceTypes[] getNamedServiceTypes() {
ServiceTypes[] array = values();
Arrays.sort(array, nameComparator);
return array;
}
Or I would personally create an immutable list of them sorted each way you care about, and return that same list reference each time.

Just another observation. You are initializing both orderComparator and nameComparator as objects of OrderComparator. You need to take a look at it if it's not intended.

Related

Java Generics : Converting methods to a single method?

In my Spring Boot app, I have the following methods:
public class ContainsIntegerFilter implements CsvToBeanFilter {
private final int index;
private final List<Integer> values; // list types are different (Integer)
public boolean allowLine(String[] line) {
return values.contains(Integer.parseInt(line[index]));
}
}
public class ContainsStringFilter implements CsvToBeanFilter {
private final int index;
private final List<String> values; // list types are different (String)
public boolean allowLine(String[] line) {
return values.contains(line[index]);
}
}
And calling these methods like this:
final CsvToBeanFilter filter = new ContainsIntegerFilter(0, idList);
I want to merge these methods into a single method using generics. But I am not sure if the following approach is the most proper way? Or should I use an interface and call that interface instead of the merged method:
public abstract class ContainsFilter<T> implements CsvToBeanFilter {
private final int index;
private final List<T> values;
public boolean allowLine(T[] line) {
return values.contains(line[index]);
}
}
So, how can achieve this?
In first approach, you are always passing String[] array as method arguments (both for string and int).
In second approach, you are passing T[] array which will change based on type T.
If you pass can String[] array in one case & Integer[] array in another as method arguments, you can use first one. That keeps code clean.
Update:
Sample code for second approach:
public class ContainsFilter<T> {
private final int index = 1;
private List<? extends Object> values1 = List.of("test1", "test2");
private List<? extends Object> values2 = List.of(1, 2);
public void allowLine(T[] line) {
System.out.println(values1.contains(line[index]));
System.out.println(values2.contains(line[index]));
}
public static void main(String[] args) {
String[] line1 = new String[] {"test111", "test2"};
Integer[] line2 = new Integer[] {1, 2};
ContainsFilter<String> c1 = new ContainsFilter<String>();
c1.allowLine(line1);
ContainsFilter<Integer> c2 = new ContainsFilter<Integer>();
c2.allowLine(line2);
}
}

How to sort an ArrayList of objects based on multiple variation [duplicate]

I read about sorting ArrayLists using a Comparator but in all of the examples people used compareTo which according to some research is a method for Strings.
I wanted to sort an ArrayList of custom objects by one of their properties: a Date object
(getStartDay()). Normally I compare them by item1.getStartDate().before(item2.getStartDate()) so I was wondering whether I could write something like:
public class CustomComparator {
public boolean compare(Object object1, Object object2) {
return object1.getStartDate().before(object2.getStartDate());
}
}
public class RandomName {
...
Collections.sort(Database.arrayList, new CustomComparator);
...
}
Since Date implements Comparable, it has a compareTo method just like String does.
So your custom Comparator could look like this:
public class CustomComparator implements Comparator<MyObject> {
#Override
public int compare(MyObject o1, MyObject o2) {
return o1.getStartDate().compareTo(o2.getStartDate());
}
}
The compare() method must return an int, so you couldn't directly return a boolean like you were planning to anyway.
Your sorting code would be just about like you wrote:
Collections.sort(Database.arrayList, new CustomComparator());
A slightly shorter way to write all this, if you don't need to reuse your comparator, is to write it as an inline anonymous class:
Collections.sort(Database.arrayList, new Comparator<MyObject>() {
#Override
public int compare(MyObject o1, MyObject o2) {
return o1.getStartDate().compareTo(o2.getStartDate());
}
});
Since java-8
You can now write the last example in a shorter form by using a lambda expression for the Comparator:
Collections.sort(Database.arrayList,
(o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));
And List has a sort(Comparator) method, so you can shorten this even further:
Database.arrayList.sort((o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));
This is such a common idiom that there's a built-in method to generate a Comparator for a class with a Comparable key:
Database.arrayList.sort(Comparator.comparing(MyObject::getStartDate));
All of these are equivalent forms.
Classes that has a natural sort order (a class Number, as an example) should implement the Comparable interface, whilst classes that has no natural sort order (a class Chair, as an example) should be provided with a Comparator (or an anonymous Comparator class).
Two examples:
public class Number implements Comparable<Number> {
private int value;
public Number(int value) { this.value = value; }
public int compareTo(Number anotherInstance) {
return this.value - anotherInstance.value;
}
}
public class Chair {
private int weight;
private int height;
public Chair(int weight, int height) {
this.weight = weight;
this.height = height;
}
/* Omitting getters and setters */
}
class ChairWeightComparator implements Comparator<Chair> {
public int compare(Chair chair1, Chair chair2) {
return chair1.getWeight() - chair2.getWeight();
}
}
class ChairHeightComparator implements Comparator<Chair> {
public int compare(Chair chair1, Chair chair2) {
return chair1.getHeight() - chair2.getHeight();
}
}
Usage:
List<Number> numbers = new ArrayList<Number>();
...
Collections.sort(numbers);
List<Chair> chairs = new ArrayList<Chair>();
// Sort by weight:
Collections.sort(chairs, new ChairWeightComparator());
// Sort by height:
Collections.sort(chairs, new ChairHeightComparator());
// You can also create anonymous comparators;
// Sort by color:
Collections.sort(chairs, new Comparator<Chair>() {
public int compare(Chair chair1, Chair chair2) {
...
}
});
For sorting an ArrayList you could use the following code snippet:
Collections.sort(studList, new Comparator<Student>(){
public int compare(Student s1, Student s2) {
return s1.getFirstName().compareToIgnoreCase(s2.getFirstName());
}
});
JAVA 8 lambda expression
Collections.sort(studList, (Student s1, Student s2) ->{
return s1.getFirstName().compareToIgnoreCase(s2.getFirstName());
});
OR
Comparator<Student> c = (s1, s2) -> s1.firstName.compareTo(s2.firstName);
studList.sort(c)
Yes, you can. There are two options with comparing items, the Comparable interface, and the Comparator interface.
Both of these interfaces allow for different behavior. Comparable allows you to make the object act like you just described Strings (in fact, String implements Comparable). The second, Comparator, allows you to do what you are asking to do. You would do it like this:
Collections.sort(myArrayList, new MyComparator());
That will cause the Collections.sort method to use your comparator for it's sorting mechanism. If the objects in the ArrayList implement comparable, you can instead do something like this:
Collections.sort(myArrayList);
The Collections class contains a number of these useful, common tools.
With Java 8 you can use a method reference for your comparator:
import static java.util.Comparator.comparing;
Collections.sort(list, comparing(MyObject::getStartDate));
Since technologies appear everyday, the answer will change in the time. I took a look at LambdaJ and seems very interesting.
You can try solving these tasks with LambdaJ. You can find it here: http://code.google.com/p/lambdaj/
Here you have an example:
Sort Iterative
List<Person> sortedByAgePersons = new ArrayList<Person>(persons);
Collections.sort(sortedByAgePersons, new Comparator<Person>() {
public int compare(Person p1, Person p2) {
return Integer.valueOf(p1.getAge()).compareTo(p2.getAge());
}
});
Sort with lambda
List<Person> sortedByAgePersons = sort(persons, on(Person.class).getAge());
Of course, having this kind of beauty impacts in the performance (an average of 2 times), but can you find a more readable code?
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.Date;
public class test {
public static class Person {
public String name;
public int id;
public Date hireDate;
public Person(String iname, int iid, Date ihireDate) {
name = iname;
id = iid;
hireDate = ihireDate;
}
public String toString() {
return name + " " + id + " " + hireDate.toString();
}
// Comparator
public static class CompId implements Comparator<Person> {
#Override
public int compare(Person arg0, Person arg1) {
return arg0.id - arg1.id;
}
}
public static class CompDate implements Comparator<Person> {
private int mod = 1;
public CompDate(boolean desc) {
if (desc) mod =-1;
}
#Override
public int compare(Person arg0, Person arg1) {
return mod*arg0.hireDate.compareTo(arg1.hireDate);
}
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
SimpleDateFormat df = new SimpleDateFormat("mm-dd-yyyy");
ArrayList<Person> people;
people = new ArrayList<Person>();
try {
people.add(new Person("Joe", 92422, df.parse("12-12-2010")));
people.add(new Person("Joef", 24122, df.parse("1-12-2010")));
people.add(new Person("Joee", 24922, df.parse("12-2-2010")));
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Collections.sort(people, new Person.CompId());
System.out.println("BY ID");
for (Person p : people) {
System.out.println(p.toString());
}
Collections.sort(people, new Person.CompDate(false));
System.out.println("BY Date asc");
for (Person p : people) {
System.out.println(p.toString());
}
Collections.sort(people, new Person.CompDate(true));
System.out.println("BY Date desc");
for (Person p : people) {
System.out.println(p.toString());
}
}
}
Function & method reference
The Collections.sort method can sort a List using a Comparator you pass. That Comparator can be implemented using the Comparator.comparing method where you can pass a method reference as the necessary Function. Fortunately, the actual code is much simpler and shorter than this description.
For Java 8:
Collections.sort(list, comparing(ClassName::getName));
or
Collections.sort(list, comparing(ClassName::getName).reversed());
Another way is
Collections.sort(list, comparing(ClassName::getName, Comparator.nullsLast(Comparator.naturalOrder())));
Best easy way with JAVA 8 is for English Alphabetic sort
Class Implementation
public class NewspaperClass implements Comparable<NewspaperClass>{
public String name;
#Override
public int compareTo(NewspaperClass another) {
return name.compareTo(another.name);
}
}
Sort
Collections.sort(Your List);
If you want to sort for alphabet that contains non English characters you can use Locale... Below code use Turkish character sort...
Class Implementation
public class NewspaperClass implements Comparator<NewspaperClass> {
public String name;
public Boolean isUserNewspaper=false;
private Collator trCollator = Collator.getInstance(new Locale("tr_TR"));
#Override
public int compare(NewspaperClass lhs, NewspaperClass rhs) {
trCollator.setStrength(Collator.PRIMARY);
return trCollator.compare(lhs.name,rhs.name);
}
}
Sort
Collections.sort(your array list,new NewspaperClass());
You can Sort using java 8
yourList.sort(Comparator.comparing(Classname::getName));
or
yourList.stream().forEach(a -> a.getBObjects().sort(Comparator.comparing(Classname::getValue)));
From Java 8 and onward we don't have to use Collections.sort() directly. List interface has a default sort() method:
List<User> users = Arrays.asList(user1,user2,user3);
users.sort( (u1, u2) -> {
return u1.getFirstName.compareTo(u2.getFirstName());});
See http://visvv.blogspot.in/2016/01/sorting-objects-in-java-8.html.
Java 8 Lambda shortens the sort.
Collections.sort(stdList, (o1, o2) -> o1.getName().compareTo(o2.getName()));
You can use the Bean Comparator to sort on any property in your custom class.
Yes, that's possible for instance in this answer I sort by the property v of the class IndexValue
// Sorting by property v using a custom comparator.
Arrays.sort( array, new Comparator<IndexValue>(){
public int compare( IndexValue a, IndexValue b ){
return a.v - b.v;
}
});
If you notice here I'm creating a anonymous inner class ( which is the Java for closures ) and passing it directly to the sort method of the class Arrays
Your object may also implement Comparable ( that's what String and most of the core libraries in Java does ) but that would define the "natural sort order" of the class it self, and doesn't let you plug new ones.
I found most if not all of these answers rely on the underlying class (Object) to implement comparable or to have a helper comparable interface.
Not with my solution! The following code lets you compare object's field by knowing their string name. You could easily modify it not to use the name, but then you need to expose it or construct one of the Objects you want to compare against.
Collections.sort(anArrayListOfSomeObjectPerhapsUsersOrSomething, new ReflectiveComparator(). new ListComparator("name"));
public class ReflectiveComparator {
public class FieldComparator implements Comparator<Object> {
private String fieldName;
public FieldComparator(String fieldName){
this.fieldName = fieldName;
}
#SuppressWarnings({ "unchecked", "rawtypes" })
#Override
public int compare(Object object1, Object object2) {
try {
Field field = object1.getClass().getDeclaredField(fieldName);
field.setAccessible(true);
Comparable object1FieldValue = (Comparable) field.get(object1);
Comparable object2FieldValue = (Comparable) field.get(object2);
return object1FieldValue.compareTo(object2FieldValue);
}catch (Exception e){}
return 0;
}
}
public class ListComparator implements Comparator<Object> {
private String fieldName;
public ListComparator(String fieldName) {
this.fieldName = fieldName;
}
#SuppressWarnings({ "unchecked", "rawtypes" })
#Override
public int compare(Object object1, Object object2) {
try {
Field field = object1.getClass().getDeclaredField(fieldName);
field.setAccessible(true);
Comparable o1FieldValue = (Comparable) field.get(object1);
Comparable o2FieldValue = (Comparable) field.get(object2);
if (o1FieldValue == null){ return -1;}
if (o2FieldValue == null){ return 1;}
return o1FieldValue.compareTo(o2FieldValue);
} catch (NoSuchFieldException e) {
throw new IllegalStateException("Field doesn't exist", e);
} catch (IllegalAccessException e) {
throw new IllegalStateException("Field inaccessible", e);
}
}
}
}
You can try Guava Ordering:
Function<Item, Date> getStartDate = new Function<Item, Date>() {
public Date apply(Item item) {
return item.getStartDate();
}
};
List<Item> orderedItems = Ordering.natural().onResultOf(getStartDate).
sortedCopy(items);
Well if you using Java 8 or older version Here is the Best solution.
Collections.sort(studentList, Comparator.comparing(Student::getCgpa).reversed().thenComparing(Student:: getFname).thenComparing(Student::getId));
In this case, it will first sort with 'getCgpa' first and for the second part it will sort with getFname and getId. Which is field into the pojo class.
your customComparator class must implement java.util.Comparator in order to be used.
it must also overide compare() AND equals()
compare() must answer the question: Is object 1 less than, equal to or greater than object 2?
full docs: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Comparator.html
This code snippets might be useful. If you want to sort an Object
in my case I want to sort by VolumeName:
public List<Volume> getSortedVolumes() throws SystemException {
List<Volume> volumes = VolumeLocalServiceUtil.getAllVolumes();
Collections.sort(volumes, new Comparator<Volume>() {
public int compare(Volume o1, Volume o2) {
Volume p1 = (Volume) o1;
Volume p2 = (Volume) o2;
return p1.getVolumeName().compareToIgnoreCase(
p2.getVolumeName());
}
});
return volumes;
}
This works. I use it in my jsp.
With this library here you can sort the list of custom objects on multiple columns. The library uses version 8.0 features. Sample is also available there. Here is a sample to do
SortKeys sortKeys = new SortKeys();
sortKeys.addField("firstName")
.addField("age", true); // This (true) will sort the age descending
// Other ways to specify a property to the sorter are
// .addField("lastName", String.class);
// .addField("dob", Date.class, true);
// Instantiate a ListSorter
ListSorter listSorter = new ListSorter();
// Pass the data to sort (listToSort) and the "by keys" to sort (sortKeys)
List sortedList = (List<Person>) listSorter.sortList(listToSort, sortKeys);
You can have a look into this presentation hold at the Java Forum in Stuttgart Germany in 2016.
Only a few slides use German language, 99% of the content is "English based" Java source code; like
someCollection.sort(
OurCustomComparator
.comparing(Person::getName)
.thenComparing(Person::getId)
);
where OurCustomComparator is using default methods (and other interesting ideas). As shown, leading to very concise code to pick some getter method for sorting; and super simple chaining (or reversing) of sort criteria.
If you are into java8, you find a lot of material there to get you started.
New since 1.8 is a List.sort() method instead of using the Collection.sort()
so you directly call mylistcontainer.sort()
Here is a code snippet which demonstrates the List.sort() feature:
List<Fruit> fruits = new ArrayList<Fruit>();
fruits.add(new Fruit("Kiwi","green",40));
fruits.add(new Fruit("Banana","yellow",100));
fruits.add(new Fruit("Apple","mixed green,red",120));
fruits.add(new Fruit("Cherry","red",10));
// a) using an existing compareto() method
fruits.sort((Fruit f1,Fruit f2) -> f1.getFruitName().compareTo(f2.getFruitName()));
System.out.println("Using String.compareTo(): " + fruits);
//Using String.compareTo(): [Apple is: mixed green,red, Banana is: yellow, Cherry is: red, Kiwi is: green]
// b) Using a comparable class
fruits.sort((Fruit f1,Fruit f2) -> f1.compareTo(f2));
System.out.println("Using a Comparable Fruit class (sort by color): " + fruits);
// Using a Comparable Fruit class (sort by color): [Kiwi is green, Apple is: mixed green,red, Cherry is: red, Banana is: yellow]
The Fruit class is:
public class Fruit implements Comparable<Fruit>
{
private String name;
private String color;
private int quantity;
public Fruit(String name,String color,int quantity)
{ this.name = name; this.color = color; this.quantity = quantity; }
public String getFruitName() { return name; }
public String getColor() { return color; }
public int getQuantity() { return quantity; }
#Override public final int compareTo(Fruit f) // sorting the color
{
return this.color.compareTo(f.color);
}
#Override public String toString()
{
return (name + " is: " + color);
}
} // end of Fruit class
I prefer this process:
public class SortUtil
{
public static <T> List<T> sort(List<T> list, String sortByProperty)
{
Collections.sort(list, new BeanComparator(sortByProperty));
return list;
}
}
List<T> sortedList = SortUtil<T>.sort(unsortedList, "startDate");
If you list of objects has a property called startDate, you call use this over and over. You can even chain them startDate.time.
This requires your object to be Comparable which means you need a compareTo, equals, and hashCode implementation.
Yes, it could be faster... But now you don't have to make a new Comparator for each type of sort. If you can save on dev time and give up on runtime, you might go with this one.
using the java-8 stream api you can sort an ArrayList by:
Comparator<Person> birthdayComparator = Comparator.comparing(Person::getBirthday);
List<Person> sortedList = list.stream().sorted(birthdayComparator).collect(toList());
Using Java 8 use can define the Comparator in one line using Comparator.comparing()
Use any of the following way:
Option 1:
listToBeSorted.sort(Comparator.comparing(CustomObject::getStartDate));
Option 2:
Collections.sort(listToBeSorted, Comparator.comparing(CustomObject::getStartDate));
Your custom class can implement the "Comparable" interface, which requires an implementation of the CompareTo method. In the CompareTo method, you can then define what it means that an object is less than or more than the other object. So in your example, it can look something like this:
public class MyCustomClass implements Comparable<MyCustomClass>{
..........
#Override
public int compareTo(MyCustomClass a) {
if(this.getStartDate().before(a.getStartDate())){
return -1;
}else if(a.getStartDate().before(this.getStartDate())){
return 1;
}else {
return 0;
}
}
A negative number indicates that this is smaller than the object being compared to. A positive number indicates that this is larger than the compared to object and a Zero means that the objects are equal.
You can then use the collections.sort(myList) to sort your list without having to feed in a comparator. This method also has the advantage of having things sorted automatically if you use a sorted collection data structures like a TreeSet or a TreeMap.
You can check this article if you would like to read more about the Comparable interface (disclosure: I am the author ;) )
https://nullbeans.com/the-java-comparable-interface-automatic-sort-of-collections/
You could also use Springs PropertyComparator if you have just a String property path to the (nested) property you want to sort:
List<SomeObject> list = ...;
PropertyComparator<HitWithInfo> propertyComparator = new PropertyComparator<>(
"property.nested.myProperty", false, true);
list.sort(propertyComparator);
The drawback is, that this comparator silently ignores properties which does not exist or are not accessible and handles this as null value for comparison. This means, you should carefully test such a comparator or validate the existence of the property path somehow.
I have tried lots of different solutions available on internet but solution which works for me is available at below link.
https://www.java67.com/2017/07/how-to-sort-arraylist-of-objects-using.html

How to output the content of this list in certain order? [duplicate]

I read about sorting ArrayLists using a Comparator but in all of the examples people used compareTo which according to some research is a method for Strings.
I wanted to sort an ArrayList of custom objects by one of their properties: a Date object
(getStartDay()). Normally I compare them by item1.getStartDate().before(item2.getStartDate()) so I was wondering whether I could write something like:
public class CustomComparator {
public boolean compare(Object object1, Object object2) {
return object1.getStartDate().before(object2.getStartDate());
}
}
public class RandomName {
...
Collections.sort(Database.arrayList, new CustomComparator);
...
}
Since Date implements Comparable, it has a compareTo method just like String does.
So your custom Comparator could look like this:
public class CustomComparator implements Comparator<MyObject> {
#Override
public int compare(MyObject o1, MyObject o2) {
return o1.getStartDate().compareTo(o2.getStartDate());
}
}
The compare() method must return an int, so you couldn't directly return a boolean like you were planning to anyway.
Your sorting code would be just about like you wrote:
Collections.sort(Database.arrayList, new CustomComparator());
A slightly shorter way to write all this, if you don't need to reuse your comparator, is to write it as an inline anonymous class:
Collections.sort(Database.arrayList, new Comparator<MyObject>() {
#Override
public int compare(MyObject o1, MyObject o2) {
return o1.getStartDate().compareTo(o2.getStartDate());
}
});
Since java-8
You can now write the last example in a shorter form by using a lambda expression for the Comparator:
Collections.sort(Database.arrayList,
(o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));
And List has a sort(Comparator) method, so you can shorten this even further:
Database.arrayList.sort((o1, o2) -> o1.getStartDate().compareTo(o2.getStartDate()));
This is such a common idiom that there's a built-in method to generate a Comparator for a class with a Comparable key:
Database.arrayList.sort(Comparator.comparing(MyObject::getStartDate));
All of these are equivalent forms.
Classes that has a natural sort order (a class Number, as an example) should implement the Comparable interface, whilst classes that has no natural sort order (a class Chair, as an example) should be provided with a Comparator (or an anonymous Comparator class).
Two examples:
public class Number implements Comparable<Number> {
private int value;
public Number(int value) { this.value = value; }
public int compareTo(Number anotherInstance) {
return this.value - anotherInstance.value;
}
}
public class Chair {
private int weight;
private int height;
public Chair(int weight, int height) {
this.weight = weight;
this.height = height;
}
/* Omitting getters and setters */
}
class ChairWeightComparator implements Comparator<Chair> {
public int compare(Chair chair1, Chair chair2) {
return chair1.getWeight() - chair2.getWeight();
}
}
class ChairHeightComparator implements Comparator<Chair> {
public int compare(Chair chair1, Chair chair2) {
return chair1.getHeight() - chair2.getHeight();
}
}
Usage:
List<Number> numbers = new ArrayList<Number>();
...
Collections.sort(numbers);
List<Chair> chairs = new ArrayList<Chair>();
// Sort by weight:
Collections.sort(chairs, new ChairWeightComparator());
// Sort by height:
Collections.sort(chairs, new ChairHeightComparator());
// You can also create anonymous comparators;
// Sort by color:
Collections.sort(chairs, new Comparator<Chair>() {
public int compare(Chair chair1, Chair chair2) {
...
}
});
For sorting an ArrayList you could use the following code snippet:
Collections.sort(studList, new Comparator<Student>(){
public int compare(Student s1, Student s2) {
return s1.getFirstName().compareToIgnoreCase(s2.getFirstName());
}
});
JAVA 8 lambda expression
Collections.sort(studList, (Student s1, Student s2) ->{
return s1.getFirstName().compareToIgnoreCase(s2.getFirstName());
});
OR
Comparator<Student> c = (s1, s2) -> s1.firstName.compareTo(s2.firstName);
studList.sort(c)
Yes, you can. There are two options with comparing items, the Comparable interface, and the Comparator interface.
Both of these interfaces allow for different behavior. Comparable allows you to make the object act like you just described Strings (in fact, String implements Comparable). The second, Comparator, allows you to do what you are asking to do. You would do it like this:
Collections.sort(myArrayList, new MyComparator());
That will cause the Collections.sort method to use your comparator for it's sorting mechanism. If the objects in the ArrayList implement comparable, you can instead do something like this:
Collections.sort(myArrayList);
The Collections class contains a number of these useful, common tools.
With Java 8 you can use a method reference for your comparator:
import static java.util.Comparator.comparing;
Collections.sort(list, comparing(MyObject::getStartDate));
Since technologies appear everyday, the answer will change in the time. I took a look at LambdaJ and seems very interesting.
You can try solving these tasks with LambdaJ. You can find it here: http://code.google.com/p/lambdaj/
Here you have an example:
Sort Iterative
List<Person> sortedByAgePersons = new ArrayList<Person>(persons);
Collections.sort(sortedByAgePersons, new Comparator<Person>() {
public int compare(Person p1, Person p2) {
return Integer.valueOf(p1.getAge()).compareTo(p2.getAge());
}
});
Sort with lambda
List<Person> sortedByAgePersons = sort(persons, on(Person.class).getAge());
Of course, having this kind of beauty impacts in the performance (an average of 2 times), but can you find a more readable code?
import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.Date;
public class test {
public static class Person {
public String name;
public int id;
public Date hireDate;
public Person(String iname, int iid, Date ihireDate) {
name = iname;
id = iid;
hireDate = ihireDate;
}
public String toString() {
return name + " " + id + " " + hireDate.toString();
}
// Comparator
public static class CompId implements Comparator<Person> {
#Override
public int compare(Person arg0, Person arg1) {
return arg0.id - arg1.id;
}
}
public static class CompDate implements Comparator<Person> {
private int mod = 1;
public CompDate(boolean desc) {
if (desc) mod =-1;
}
#Override
public int compare(Person arg0, Person arg1) {
return mod*arg0.hireDate.compareTo(arg1.hireDate);
}
}
}
public static void main(String[] args) {
// TODO Auto-generated method stub
SimpleDateFormat df = new SimpleDateFormat("mm-dd-yyyy");
ArrayList<Person> people;
people = new ArrayList<Person>();
try {
people.add(new Person("Joe", 92422, df.parse("12-12-2010")));
people.add(new Person("Joef", 24122, df.parse("1-12-2010")));
people.add(new Person("Joee", 24922, df.parse("12-2-2010")));
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Collections.sort(people, new Person.CompId());
System.out.println("BY ID");
for (Person p : people) {
System.out.println(p.toString());
}
Collections.sort(people, new Person.CompDate(false));
System.out.println("BY Date asc");
for (Person p : people) {
System.out.println(p.toString());
}
Collections.sort(people, new Person.CompDate(true));
System.out.println("BY Date desc");
for (Person p : people) {
System.out.println(p.toString());
}
}
}
Function & method reference
The Collections.sort method can sort a List using a Comparator you pass. That Comparator can be implemented using the Comparator.comparing method where you can pass a method reference as the necessary Function. Fortunately, the actual code is much simpler and shorter than this description.
For Java 8:
Collections.sort(list, comparing(ClassName::getName));
or
Collections.sort(list, comparing(ClassName::getName).reversed());
Another way is
Collections.sort(list, comparing(ClassName::getName, Comparator.nullsLast(Comparator.naturalOrder())));
Best easy way with JAVA 8 is for English Alphabetic sort
Class Implementation
public class NewspaperClass implements Comparable<NewspaperClass>{
public String name;
#Override
public int compareTo(NewspaperClass another) {
return name.compareTo(another.name);
}
}
Sort
Collections.sort(Your List);
If you want to sort for alphabet that contains non English characters you can use Locale... Below code use Turkish character sort...
Class Implementation
public class NewspaperClass implements Comparator<NewspaperClass> {
public String name;
public Boolean isUserNewspaper=false;
private Collator trCollator = Collator.getInstance(new Locale("tr_TR"));
#Override
public int compare(NewspaperClass lhs, NewspaperClass rhs) {
trCollator.setStrength(Collator.PRIMARY);
return trCollator.compare(lhs.name,rhs.name);
}
}
Sort
Collections.sort(your array list,new NewspaperClass());
You can Sort using java 8
yourList.sort(Comparator.comparing(Classname::getName));
or
yourList.stream().forEach(a -> a.getBObjects().sort(Comparator.comparing(Classname::getValue)));
From Java 8 and onward we don't have to use Collections.sort() directly. List interface has a default sort() method:
List<User> users = Arrays.asList(user1,user2,user3);
users.sort( (u1, u2) -> {
return u1.getFirstName.compareTo(u2.getFirstName());});
See http://visvv.blogspot.in/2016/01/sorting-objects-in-java-8.html.
Java 8 Lambda shortens the sort.
Collections.sort(stdList, (o1, o2) -> o1.getName().compareTo(o2.getName()));
You can use the Bean Comparator to sort on any property in your custom class.
Yes, that's possible for instance in this answer I sort by the property v of the class IndexValue
// Sorting by property v using a custom comparator.
Arrays.sort( array, new Comparator<IndexValue>(){
public int compare( IndexValue a, IndexValue b ){
return a.v - b.v;
}
});
If you notice here I'm creating a anonymous inner class ( which is the Java for closures ) and passing it directly to the sort method of the class Arrays
Your object may also implement Comparable ( that's what String and most of the core libraries in Java does ) but that would define the "natural sort order" of the class it self, and doesn't let you plug new ones.
I found most if not all of these answers rely on the underlying class (Object) to implement comparable or to have a helper comparable interface.
Not with my solution! The following code lets you compare object's field by knowing their string name. You could easily modify it not to use the name, but then you need to expose it or construct one of the Objects you want to compare against.
Collections.sort(anArrayListOfSomeObjectPerhapsUsersOrSomething, new ReflectiveComparator(). new ListComparator("name"));
public class ReflectiveComparator {
public class FieldComparator implements Comparator<Object> {
private String fieldName;
public FieldComparator(String fieldName){
this.fieldName = fieldName;
}
#SuppressWarnings({ "unchecked", "rawtypes" })
#Override
public int compare(Object object1, Object object2) {
try {
Field field = object1.getClass().getDeclaredField(fieldName);
field.setAccessible(true);
Comparable object1FieldValue = (Comparable) field.get(object1);
Comparable object2FieldValue = (Comparable) field.get(object2);
return object1FieldValue.compareTo(object2FieldValue);
}catch (Exception e){}
return 0;
}
}
public class ListComparator implements Comparator<Object> {
private String fieldName;
public ListComparator(String fieldName) {
this.fieldName = fieldName;
}
#SuppressWarnings({ "unchecked", "rawtypes" })
#Override
public int compare(Object object1, Object object2) {
try {
Field field = object1.getClass().getDeclaredField(fieldName);
field.setAccessible(true);
Comparable o1FieldValue = (Comparable) field.get(object1);
Comparable o2FieldValue = (Comparable) field.get(object2);
if (o1FieldValue == null){ return -1;}
if (o2FieldValue == null){ return 1;}
return o1FieldValue.compareTo(o2FieldValue);
} catch (NoSuchFieldException e) {
throw new IllegalStateException("Field doesn't exist", e);
} catch (IllegalAccessException e) {
throw new IllegalStateException("Field inaccessible", e);
}
}
}
}
You can try Guava Ordering:
Function<Item, Date> getStartDate = new Function<Item, Date>() {
public Date apply(Item item) {
return item.getStartDate();
}
};
List<Item> orderedItems = Ordering.natural().onResultOf(getStartDate).
sortedCopy(items);
Well if you using Java 8 or older version Here is the Best solution.
Collections.sort(studentList, Comparator.comparing(Student::getCgpa).reversed().thenComparing(Student:: getFname).thenComparing(Student::getId));
In this case, it will first sort with 'getCgpa' first and for the second part it will sort with getFname and getId. Which is field into the pojo class.
your customComparator class must implement java.util.Comparator in order to be used.
it must also overide compare() AND equals()
compare() must answer the question: Is object 1 less than, equal to or greater than object 2?
full docs: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Comparator.html
This code snippets might be useful. If you want to sort an Object
in my case I want to sort by VolumeName:
public List<Volume> getSortedVolumes() throws SystemException {
List<Volume> volumes = VolumeLocalServiceUtil.getAllVolumes();
Collections.sort(volumes, new Comparator<Volume>() {
public int compare(Volume o1, Volume o2) {
Volume p1 = (Volume) o1;
Volume p2 = (Volume) o2;
return p1.getVolumeName().compareToIgnoreCase(
p2.getVolumeName());
}
});
return volumes;
}
This works. I use it in my jsp.
With this library here you can sort the list of custom objects on multiple columns. The library uses version 8.0 features. Sample is also available there. Here is a sample to do
SortKeys sortKeys = new SortKeys();
sortKeys.addField("firstName")
.addField("age", true); // This (true) will sort the age descending
// Other ways to specify a property to the sorter are
// .addField("lastName", String.class);
// .addField("dob", Date.class, true);
// Instantiate a ListSorter
ListSorter listSorter = new ListSorter();
// Pass the data to sort (listToSort) and the "by keys" to sort (sortKeys)
List sortedList = (List<Person>) listSorter.sortList(listToSort, sortKeys);
You can have a look into this presentation hold at the Java Forum in Stuttgart Germany in 2016.
Only a few slides use German language, 99% of the content is "English based" Java source code; like
someCollection.sort(
OurCustomComparator
.comparing(Person::getName)
.thenComparing(Person::getId)
);
where OurCustomComparator is using default methods (and other interesting ideas). As shown, leading to very concise code to pick some getter method for sorting; and super simple chaining (or reversing) of sort criteria.
If you are into java8, you find a lot of material there to get you started.
New since 1.8 is a List.sort() method instead of using the Collection.sort()
so you directly call mylistcontainer.sort()
Here is a code snippet which demonstrates the List.sort() feature:
List<Fruit> fruits = new ArrayList<Fruit>();
fruits.add(new Fruit("Kiwi","green",40));
fruits.add(new Fruit("Banana","yellow",100));
fruits.add(new Fruit("Apple","mixed green,red",120));
fruits.add(new Fruit("Cherry","red",10));
// a) using an existing compareto() method
fruits.sort((Fruit f1,Fruit f2) -> f1.getFruitName().compareTo(f2.getFruitName()));
System.out.println("Using String.compareTo(): " + fruits);
//Using String.compareTo(): [Apple is: mixed green,red, Banana is: yellow, Cherry is: red, Kiwi is: green]
// b) Using a comparable class
fruits.sort((Fruit f1,Fruit f2) -> f1.compareTo(f2));
System.out.println("Using a Comparable Fruit class (sort by color): " + fruits);
// Using a Comparable Fruit class (sort by color): [Kiwi is green, Apple is: mixed green,red, Cherry is: red, Banana is: yellow]
The Fruit class is:
public class Fruit implements Comparable<Fruit>
{
private String name;
private String color;
private int quantity;
public Fruit(String name,String color,int quantity)
{ this.name = name; this.color = color; this.quantity = quantity; }
public String getFruitName() { return name; }
public String getColor() { return color; }
public int getQuantity() { return quantity; }
#Override public final int compareTo(Fruit f) // sorting the color
{
return this.color.compareTo(f.color);
}
#Override public String toString()
{
return (name + " is: " + color);
}
} // end of Fruit class
I prefer this process:
public class SortUtil
{
public static <T> List<T> sort(List<T> list, String sortByProperty)
{
Collections.sort(list, new BeanComparator(sortByProperty));
return list;
}
}
List<T> sortedList = SortUtil<T>.sort(unsortedList, "startDate");
If you list of objects has a property called startDate, you call use this over and over. You can even chain them startDate.time.
This requires your object to be Comparable which means you need a compareTo, equals, and hashCode implementation.
Yes, it could be faster... But now you don't have to make a new Comparator for each type of sort. If you can save on dev time and give up on runtime, you might go with this one.
using the java-8 stream api you can sort an ArrayList by:
Comparator<Person> birthdayComparator = Comparator.comparing(Person::getBirthday);
List<Person> sortedList = list.stream().sorted(birthdayComparator).collect(toList());
Using Java 8 use can define the Comparator in one line using Comparator.comparing()
Use any of the following way:
Option 1:
listToBeSorted.sort(Comparator.comparing(CustomObject::getStartDate));
Option 2:
Collections.sort(listToBeSorted, Comparator.comparing(CustomObject::getStartDate));
Your custom class can implement the "Comparable" interface, which requires an implementation of the CompareTo method. In the CompareTo method, you can then define what it means that an object is less than or more than the other object. So in your example, it can look something like this:
public class MyCustomClass implements Comparable<MyCustomClass>{
..........
#Override
public int compareTo(MyCustomClass a) {
if(this.getStartDate().before(a.getStartDate())){
return -1;
}else if(a.getStartDate().before(this.getStartDate())){
return 1;
}else {
return 0;
}
}
A negative number indicates that this is smaller than the object being compared to. A positive number indicates that this is larger than the compared to object and a Zero means that the objects are equal.
You can then use the collections.sort(myList) to sort your list without having to feed in a comparator. This method also has the advantage of having things sorted automatically if you use a sorted collection data structures like a TreeSet or a TreeMap.
You can check this article if you would like to read more about the Comparable interface (disclosure: I am the author ;) )
https://nullbeans.com/the-java-comparable-interface-automatic-sort-of-collections/
You could also use Springs PropertyComparator if you have just a String property path to the (nested) property you want to sort:
List<SomeObject> list = ...;
PropertyComparator<HitWithInfo> propertyComparator = new PropertyComparator<>(
"property.nested.myProperty", false, true);
list.sort(propertyComparator);
The drawback is, that this comparator silently ignores properties which does not exist or are not accessible and handles this as null value for comparison. This means, you should carefully test such a comparator or validate the existence of the property path somehow.
I have tried lots of different solutions available on internet but solution which works for me is available at below link.
https://www.java67.com/2017/07/how-to-sort-arraylist-of-objects-using.html

I'm trying to create an arrayList that could accept both integers and array

How do I create a generic array list in Java that could accept both integers and array?
[123,[],112,[],10]
Both int (Integer wrapper) and array's common base class is Object. So create ArrayList using Object type.
ArrayList<Object> list= new ArrayList<Object>();
But this is not the right way to solve this problem and there is no use of Generics here to make run-time safety. So, re-design your program and allocate each type in seperate list or use any other appropriate Collection type.
Well, the fastest way might be create an auxiliar object that is composed by boths Integers and array letting you to use boths by equal
Create the array list at the Generalization level for all the objects you need in the List. In this case,i.e for int and array, it is java.lang.Object.
Here's a small test I ran:
public static void main(String[] args) {
List<Object> both = new ArrayList<Object>();
both.add(1);
both.add(args);
System.out.println(both);
}
Produces:
[1, [Ljava.lang.String;#1db9742]
As #AbtPst suggested, the most suitable solution would be to have a list of lists. This can be done in many different ways. Personally, I'd create a class with two constructors.
class NumericElement
{
private ArrayList<int> elements;
public NumericElement(int newElement)
{
elements = new ArrayList<int>();
elements.add(newElement);
}
public NumericElement(ArrayList<int> newElements)
{
elements = new ArrayList<int>(newElements); // copying array elements to the new array.
}
public ArrayList<int> getElements()
{
return elements;
}
}
Use a class which has an int and an array as its instance variables. Then create an ArrayList like
import java.util.ArrayList;
public class Hello {
public static void main(String[]args) {
ArrayList<Intarray> myArrayList = new ArrayList<Intarray>();
int[] arr = {3,4,5};
myArrayList.add(new Intarray(2,arr));
}
}
class Intarray {
private int numbers;
private int[] myArray;
public Intarray(int numbers, int[] myArray){
this.numbers = numbers;
this.myArray = myArray;
}
}
You can define a List class with a type-safe interface, hiding an unsafe List<Object> as an internal implementation detail.
This is more work than just using a List<Object> directly. If your list is used only by one class, just use a List<Object>, as an implementation detail of that one class. But if your list is exposed to access by more than just one class, consider using this type-safe approach.
First, define an interface that can represent either an int or a array of ints.
public interface IScalarOrArrayInt { }
And define a sub-interface for each possible element type:
public interface IScalarInt extends IScalarOrArrayInt {
public int getScalarInt();
}
public interface IArrayInt extends IScalarOrArrayInt {
public int[] getIntArray();
}
Then define your list class and its representation. It's interface can be a List<IScalarOrArrayInt>. The representation can be a List<Object>, so that you can put Integer and int[] objects into it directly, without wrapper objects.
public class ListOfScalarsAndArray extends AbstractList<IScalarOrArrayInt> {
private static List<Object> m_list = new ArrayList<Object>();
As noted in the AbstractList documentation, you'll want to define several methods to allow modifying your list. You can delegate them to the internal list, but wrap the return values.
#Override
public void add(int index, IScalarOrArrayInt element) {
m_list.add( index, element );
}
#Override
public IScalarOrArrayInt remove(int index) {
return wrap( m_list.remove( index ));
}
#Override
public IScalarOrArrayInt set(int index, IScalarOrArrayInt element) {
return wrap( m_list.set( index, element ));
}
For the convenience of callers, you can add some methods that accept an unwrapped int or int[]. For example:
public void add( int element ) {
m_list.add( element );
}
public void add( int[] element ) {
m_list.add( element );
}
To satisfy the standard List<> interface, you can wrap return values. Your class controls the internal list, so it alone controls the possible types of list members.
private IScalarOrArrayInt wrap( Object o ) {
if ( o instanceof Integer ) {
final int i = (Integer) o;
return new IScalarInt() {
#Override
public int getScalarInt() {
return i;
}
};
}
else {
assert( o instanceof int[] );
final int[] a = (int[]) o;
return new IArrayInt() {
#Override
public int[] getIntArray() {
return a;
}
};
}
}

Best practice for ordering a list with one of four rules

I have a range of objects which needs to be ordered with a rule. But I need to be able to switch the rules however I have a limited set of ordering rules. Which data structure would be the best choice for that?
As an example I have this class:
class Test {
public final int amount;
public final int cost;
public final String name;
public final int whatever;
// ...
// TODO: add a constructor to set the fields :-)
}
How can I store those fields to order them by amount, cost, name or whatever. But just one of that rules.
I could imagine to use an ArrayList or a HashSet where I call the sort function with a custom Comparator. But I cannot imagine that this is efficiency. I think this is important on a mobile device. What is a better way to achieve that?
You can not use an Set for sorting, as it does not have any order. How every the concept of having List and custom Comparator<T> is reasonable.
You should go with that solution and do not care about performance at this point. If you will be not satisfied from gained result then try to came up with better solution.
The best solution is reading data from storage in proper order. I do not know how your app store that structure. Therefore I can not help you with that. But implement the comparable solution and you will see that is not so bad.
What is important on mobile device is memory usage. If your application will use lot of those sorting operation you could create the Comparators as enums so they will be loaded only once and in addition can simplify the code
private enum TestComparator implements Comparator<Test> {
BY_NAME {
#Override
public int compare(Test o1, Test o2) {
//We validate first against null
return o1n.name.compareTo(o2.name);
}
}
BY_WHATEVER{
#Override
public int compare(Test o1, Test o2) {
//We validate first against null
return (o1.whatever<o2.whatever ? -1 : (o1.whatever==o2.whatever ? 0 : 1));
}
}
}
Do this:
class Test {
public final int amount;
public final int cost;
public final String name;
public final int whatever;
// ...
// TODO: add a constructor to set the fields :-)
class TestAmountComparator implements Comparator<Test> {
#Override
public int compare(Test t1, Test t2) {
return Integer.valueOf(t1.amount).compareTo(Integer.valueOf(t2.amount))
}
}
class TestCostComparator implements Comparator<Test> {
#Override
public int compare(Test t1, Test t2) {
return Integer.valueOf(t1.cost).compareTo(Integer.valueOf(t2.cost))
}
}
}
Store your Test objects in ArrayList (or any other Collection) and then sort them this way:
List<Test> list = new ArrayList<Test>(myTest); //your Test list
//sorting
Collections.sort(list, new TestAmountComparator()); //sort by amount
Collections.sort(list, new TestCostComparator()); //sort by cost
I would have preferred implementing Comparable interface and implement compareTo method in the class. It provides consistence behaviour of sorting across different data structures.
In this case Comparator interface will be used only if special sorting is required.
class Test implements Comparable {
public final int amount;
public final int cost;
public final String name;
public final int whatever;
// ...
//add equals ,hashcode, and compareTo method in the class...
// TODO: add a constructor to set the fields :-)
}
You can use TreeSet if instances are unique and comparable is implemented. Else otherwise you have to use lists and order them with Collection.sort function.
You can decide the DS based on access use. If you want to access the elements in sequence use LinkedList else user ArrayList
My version:
class Test3 implements Comparable<Test3> {
public int amount;
//...
Comparator<Test3> comparator;
public void setComparator(Comparator<Test3> comparator) {
this.comparator = comparator;
}
#Override
public int compareTo(Test3 o) {
return comparator.compare(this, o);
}
}
This is how we can use TreeSet without losing duplicates:
import java.util.Comparator;
import java.util.TreeSet;
public class Test {
int amount;
Test(int amount) {
this.amount = amount;
}
public static void main(String args[]) throws Exception {
Comparator<Test> c = new Comparator<Test>() {
#Override
public int compare(Test o1, Test o2) {
if (o1.amount >= o2.amount) {
return 1;
}
return -1;
}
};
TreeSet<Test> s = new TreeSet<Test>(c);
s.add(new Test(2));
s.add(new Test(1));
s.add(new Test(1));
for (Test t : s) {
System.out.println(t.amount);
}
}
}
This prints:
1
1
2

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