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Android Unparseable date Exception

I get a Unparseable date when trying to parse a Date string that is sent to my android client.
This is the exception:
java.text.ParseException: Unparseable date: "2018-09-18T00:00:00Z" (at
offset 19) at java.text.DateFormat.parse(DateFormat.java:571)
The date format my C# based backend sends (The C# object Property is DateTime):
2018-09-18T00:00:00Z
My Java Code where it fails:
SimpleDateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss aa");
String targetDate = "2018-09-18T00:00:00Z";
Date date = dateFormat.parse(targetDate));
How can I change my code to parse the exact format sent by the backend?

You have to change the format String to:
SimpleDateFormat dateFormatParse = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss'Z'");
String targetDate = "2018-09-18T00:00:00Z";
Date dateString = dateFormatParse.parse(targetDate));

The date format sent by your backend follows ISO-8601 instant format.
You can use LocalDate.parse(targetDate, DateTimeFormatter.ISO_INSTANT) to parse it.
LocalDate supports only SDK 26+, android 8 and higher

UnParseable Date Exception :"2015-02-06T16:05:20"

I have a Date Variable "StartTime", in which i need to store this input String "2015-02-06T16:05:20"
I tried like below, but it gives Unparsable Date Exception. What i am doing wrong?
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String inputTime = "2015-02-06T16:05:20";
setStartTime(dateFormat.parse(inputTime));

You can change you date format to "yyyy-MM-dd'T'HH:mm:ss"
Read more Java SimpleDateFormat

Java parse exception

I created a hibernate program and when i tried to format the date i am getting the below mentioned error:
java.text.ParseException: Unparseable date
SimpleDateFormat formatter=new SimpleDateFormat("dd/MM/yyyy");
SimpleDateFormat formatter1=new SimpleDateFormat("yyyy-MM-dd");
Date date1=null;
Date date2=null;
Date startdate=(Date)formatter.parse(startDate);
Date enddate=(Date)formatter.parse(endDate);
How to resolve the parse exception?
Thanks in advance.

You are trying to parse startdate but it doesn't actually contain any date and hence the Exception.
You should try:
String strDate = "2012-10-20";
SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd");
Date startDate = formatter.parse(strDate);

Issue i am facing with dateFormat.parse(string)?

I have below code snippet
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd hh:mm:ss.SSS");
String processedContentDate="2012-04-10 12:53:28.033";
java.util.Date parsedDate = dateFormat.parse(processedContentDate);
java.sql.Timestamp timestamp = new java.sql.Timestamp(
parsedDate.getTime());
I get parsed date as Tue Apr 10 00:53:28 IST 2012 and timestamp as 2012-04-10 00:53:28.033 . i want to get the time exactly as 12:53:28.033(as in my original string)
not 00:53:28.033. Not getting why 12:53:28 is getting converted to 00:53:28. what should I do to get 12:53:28?
EDIT: After getting the response, I tried this small programme where current time is 14:34:38.899
but at both lines i.e at line 1 and line 2, I got below parsed date
2012-04-10 14:34:38.899
As per reply I should have got 02:34:38.899 at line 1 as date format is yyyy-MM-dd hh:mm:ss.SSS")
java.util.Date date= new java.util.Date();
String strDate=date.toString();
java.util.Date parsedDate;
java.util.Date parsedDate2;
SimpleDateFormat dateFormat = new SimpleDateFormat(
"yyyy-MM-dd hh:mm:ss.SSS");// line 1
SimpleDateFormat dateFormat2 = new SimpleDateFormat(
"yyyy-MM-dd HH:mm:ss.SSS");//line 2
try {
java.sql.Timestamp timestamp = new java.sql.Timestamp(date.getTime());
strDate=timestamp.toString();
parsedDate = dateFormat.parse(strDate);//line1
parsedDate2 = dateFormat2.parse(strDate);//line2

Define your dateFormat like that
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
HH instead of hh. See SimpleDateFormat

Your date format must be yyyy-MM-dd HH:mm:ss.SSS.
hh is hours in am/pm, while HH is hours in a day (that's where you mistake is). See SimpleDateFormat.

As per definition of Date.toString() and Timestamp.toString, the .toString() output is always using a 24-hour clock. If you want to show the time using AM/PM, you should use the dateformatter to print the date. As you are using the same date/time as a source for both (strDate will use 14:34), when you parse the date, the SimpleDateFormat using the 12-hour clock is "lenient" and allows parsing of 14 as an hour.
If you set
dateFormat.setLenient(false);
you'll probably find that the dateFormat.parse(strDate) will fail.
To print dates, I would never rely on toString, but always use a formatter.
System.out.println(dateFormat.format(parsedDate)); // should show ...02:36...
System.out.println(dateFormat2.format(parsedDate)); // should show ...14:36...
System.out.println(dateFormat.format(parsedDate2)); // should show ...02:36...
System.out.println(dateFormat2.format(parsedDate2)); // should show ...14:36...

Try below code:
SimpleDateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = fmt.parse("yourdate");
SimpleDateFormat fmtOut = new SimpleDateFormat("dd-MM-yyyy hh:mm a");String myDate = fmtOut.format(date);
If yourdate is 2016-06-10 12:06:43, then output will be 10-06-2016 12:06 pm.

Parse a date with the timezone "Etc/GMT"

My first attempt was:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
Date date = formatter.parse(string);
It throws ParseException, so I found this hack:
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss z");
TimeZone timeZone = TimeZone.getTimeZone("Etc/GMT");
formatter.setTimeZone(timeZone);
Date date = formatter.parse(string);
It did not work either, and now I'm stuck. It parses without problems if I just change the timezone to "GMT".
edit: An example string to parse would be "2011-11-29 10:40:24 Etc/GMT"
edit2: I would prefer not to remove timezone information completely. I am coding a server that receives the date from an external user, so perhaps other dates will have other timezones.
To be more precise: This specific date I receive is from the receipt from the apple server after making an in app purchase on an iphone app, but I could also receive dates from other sources.

Don't know if this question is still relevant to you, but if you use Joda time, this'll work:
DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss ZZZ").parseDateTime(s)
Without Joda time the following will work (bit more work though):
String s = "2011-11-29 10:40:24 Etc/GMT";
// split the input in a date and a timezone part
int lastSpaceIndex = s.lastIndexOf(' ');
String dateString = s.substring(0, lastSpaceIndex);
String timeZoneString = s.substring(lastSpaceIndex + 1);
// convert the timezone to an actual TimeZone object
// and feed that to the formatter
TimeZone zone = TimeZone.getTimeZone(timeZoneString);
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
formatter.setTimeZone(zone);
// parse the timezoneless part
Date date = formatter.parse(dateString);

It didn't work for me either the thing is I tried setting TimeZone of SimpleDateFormatter to "Etc/GMT" and then formatted a new date here is the output:
2011-11-30 10:46:32 GMT+00:00
So Etc/GMT is being translated as GMT+00:00
If you really want to stick to parse "2011-09-02 10:26:35 Etc/GMT" then following will help too without even considering explicit Timezone change:
java.text.SimpleDateFormat isoFormat = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss 'Etc/GMT'");
isoFormat.parse("2010-05-23 09:01:02 Etc/GMT");
Works fine.

Following code is working for me
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
sdf.setTimeZone(TimeZone.getTimeZone("Etc/GMT"));
try { System.out.println( sdf.parse("2011-09-02 10:26:35 Etc/GMT") );
} catch (ParseException e){
e.printStackTrace();
}