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Why is #Bean(initMethod="") not detecting given method in spring?

Edit Fixed by changing package.
I have this configuration file for spring framework
#Configuration
public class AppConfig {
#Bean(initMethod = "populateCache")
public AccountRepository accountRepository(){
return new JdbcAccountRepository();
}
}
JdbcAccountRepository looks like this.
#Repository
public class JdbcAccountRepository implements AccountRepository {
#Override
public Account findByAccountId(long
return new SavingAccount();
}
public void populateCache() {
System.out.println("Populating Cache");
}
public void clearCache(){
System.out.println("Clearing Cache");
}
}
I'm new to spring framework and trying to use initMethod or destroyMethod. Both of these method are showing following errors.
Caused by: org.springframework.beans.factory.support.BeanDefinitionValidationException: Could not find an init method named 'populateCache' on bean with name 'accountRepository'
Here is my main method.
public class BeanLifeCycleDemo {
public static void main(String[] args) {
ConfigurableApplicationContext applicationContext = new
AnnotationConfigApplicationContext(AppConfig.class);
AccountRepository bean = applicationContext.getBean(AccountRepository.class);
applicationContext.close();
}
}
Edit
I was practicing from a book and had created many packages for different chapters. Error was it was importing different JdbcAccountRepository from different package that did not have that method. I fixed it and it works now. I got hinted at this from answers.

Like you said, if you are mixing configurations types, it can be confusing. Besides, even if you created a Bean of type AccountRepository, because Spring does a lot of things at runtime, it can call your initMethod, even if the compiler couldn't.
So yes, if you have many beans with the same type, Spring can be confused an know which one to call, hence your exception.
Oh and by the way, having a Configuration creating the accountRepoisitory Bean, you can remove the #Repository from your JdbcAccountRepository... It is either #Configuration + #Bean or #Component/Repository/Service + #ComponentScan.
TL;DR
Here is more information and how Spring creates your bean : What object are injected by Spring ?
#Bean(initMethod = "populateCache")
public AccountRepository accountRepository(){
return new JdbcAccountRepository();
}
With this code, Spring will :
Detect that you want to add a Bean in the application Context
The bean information are retrieved from the method signature. In your case, it will create a bean of type AccountRepository named accountRepository... That's all Spring knows, it won't look inside your method body.
Once Spring is done analysing your classpath, or scanning the bean definitions, it will start instanciating your object.
It will therefor creates your bean accountRepository of type AccountRepository.
But Spring is "clever" and nice with us. Even if you couldn't write this code without your compiler yelling at you, Spring can still call your method.
To make sure, try writing this code :
AccountRepository accountRepository = new JdbcAccountRepository();
accountRepository.populateCache(); // Compiler error => the method is not found.
But it works for Spring... Magic.
My recommandation, but you might thinking the same now: If you have classes across many packages to answer different business case, then rely on #Configuration classes. #ComponentScan is great to kickstart your development, but reach its limit when your application grows...

You mix two different ways of spring bean declaration:
Using #Configuration classes. Spring finds all beans annotated with #Configuration and uses them as a reference to what beans should be created.
So if you follow this path of configuration - don't use #Repository on beans. Spring will detect it anyway
Using #Repository - other way around - you don't need to use #Configuration in this case. If you decide to use #Repository put #PostConstruct annotation on the method and spring will call it, in this case remove #Configuration altogether (or at least remove #Bean method that creates JdbcAccountRepository)

Annotate populateCache method with #PostConstruct and remove initMethod from #Bean. It will work.

Exception org.springframework.beans.factory.NoUniqueBeanDefinitionException. While configuring multiple jobs in quartz and spring 4 [duplicate]

Please explain the following about NoSuchBeanDefinitionException exception in Spring:
What does it mean?
Under what conditions will it be thrown?
How can I prevent it?
This post is designed to be a comprehensive Q&A about occurrences of NoSuchBeanDefinitionException in applications using Spring.

The javadoc of NoSuchBeanDefinitionException explains
Exception thrown when a BeanFactory is asked for a bean instance for
which it cannot find a definition. This may point to a non-existing
bean, a non-unique bean, or a manually registered singleton instance
without an associated bean definition.
A BeanFactory is basically the abstraction representing Spring's Inversion of Control container. It exposes beans internally and externally, to your application. When it cannot find or retrieve these beans, it throws a NoSuchBeanDefinitionException.
Below are simple reasons why a BeanFactory (or related classes) would not be able to find a bean and how you can make sure it does.
The bean doesn't exist, it wasn't registered
In the example below
#Configuration
public class Example {
public static void main(String[] args) throws Exception {
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext(Example.class);
ctx.getBean(Foo.class);
}
}
class Foo {}
we haven't registered a bean definition for the type Foo either through a #Bean method, #Component scanning, an XML definition, or any other way. The BeanFactory managed by the AnnotationConfigApplicationContext therefore has no indication of where to get the bean requested by getBean(Foo.class). The snippet above throws
Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException:
No qualifying bean of type [com.example.Foo] is defined
Similarly, the exception could have been thrown while trying to satisfy an #Autowired dependency. For example,
#Configuration
#ComponentScan
public class Example {
public static void main(String[] args) throws Exception {
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext(Example.class);
}
}
#Component
class Foo { #Autowired Bar bar; }
class Bar { }
Here, a bean definition is registered for Foo through #ComponentScan. But Spring knows nothing of Bar. It therefore fails to find a corresponding bean while trying to autowire the bar field of the Foo bean instance. It throws (nested inside a UnsatisfiedDependencyException)
Caused by: org.springframework.beans.factory.NoSuchBeanDefinitionException:
No qualifying bean of type [com.example.Bar] found for dependency [com.example.Bar]:
expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {#org.springframework.beans.factory.annotation.Autowired(required=true)}
There are multiple ways to register bean definitions.
#Bean method in a #Configuration class or <bean> in XML configuration
#Component (and its meta-annotations, eg. #Repository) through #ComponentScan or <context:component-scan ... /> in XML
Manually through GenericApplicationContext#registerBeanDefinition
Manually through BeanDefinitionRegistryPostProcessor
...and more.
Make sure the beans you expect are properly registered.
A common error is to register beans multiple times, ie. mixing the options above for the same type. For example, I might have
#Component
public class Foo {}
and an XML configuration with
<context:component-scan base-packages="com.example" />
<bean name="eg-different-name" class="com.example.Foo />
Such a configuration would register two beans of type Foo, one with name foo and another with name eg-different-name. Make sure you're not accidentally registering more beans than you wanted. Which leads us to...
If you're using both XML and annotation-based configurations, make sure you import one from the other. XML provides
<import resource=""/>
while Java provides the #ImportResource annotation.
Expected single matching bean, but found 2 (or more)
There are times when you need multiple beans for the same type (or interface). For example, your application may use two databases, a MySQL instance and an Oracle one. In such a case, you'd have two DataSource beans to manage connections to each one. For (simplified) example, the following
#Configuration
public class Example {
public static void main(String[] args) throws Exception {
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext(Example.class);
System.out.println(ctx.getBean(DataSource.class));
}
#Bean(name = "mysql")
public DataSource mysql() { return new MySQL(); }
#Bean(name = "oracle")
public DataSource oracle() { return new Oracle(); }
}
interface DataSource{}
class MySQL implements DataSource {}
class Oracle implements DataSource {}
throws
Exception in thread "main" org.springframework.beans.factory.NoUniqueBeanDefinitionException:
No qualifying bean of type [com.example.DataSource] is defined:
expected single matching bean but found 2: oracle,mysql
because both beans registered through #Bean methods satisfied the requirement of BeanFactory#getBean(Class), ie. they both implement DataSource. In this example, Spring has no mechanism to differentiate or prioritize between the two. But such mechanisms exists.
You could use #Primary (and its equivalent in XML) as described in the documentation and in this post. With this change
#Bean(name = "mysql")
#Primary
public DataSource mysql() { return new MySQL(); }
the previous snippet would not throw the exception and would instead return the mysql bean.
You can also use #Qualifier (and its equivalent in XML) to have more control over the bean selection process, as described in the documentation. While #Autowired is primarily used to autowire by type, #Qualifier lets you autowire by name. For example,
#Bean(name = "mysql")
#Qualifier(value = "main")
public DataSource mysql() { return new MySQL(); }
could now be injected as
#Qualifier("main") // or #Qualifier("mysql"), to use the bean name
private DataSource dataSource;
without issue. #Resource is also an option.
Using wrong bean name
Just as there are multiple ways to register beans, there are also multiple ways to name them.
#Bean has name
The name of this bean, or if plural, aliases for this bean. If left
unspecified the name of the bean is the name of the annotated method.
If specified, the method name is ignored.
<bean> has the id attribute to represent the unique identifier for a bean and name can be used to create one or more aliases illegal in an (XML) id.
#Component and its meta annotations have value
The value may indicate a suggestion for a logical component name, to
be turned into a Spring bean in case of an autodetected component.
If that's left unspecified, a bean name is automatically generated for the annotated type, typically the lower camel case version of the type name. For example MyClassName becomes myClassName as its bean name. Bean names are case sensitive. Also note that wrong names/capitalization typically occur in beans referred to by string like #DependsOn("my BeanName") or XML config files.
#Qualifier, as mentioned earlier, lets you add more aliases to a bean.
Make sure you use the right name when referring to a bean.
More advanced cases
Profiles
Bean definition profiles allow you to register beans conditionally. #Profile, specifically,
Indicates that a component is eligible for registration when one or
more specified profiles are active.
A profile is a named logical grouping that may be activated
programmatically via
ConfigurableEnvironment.setActiveProfiles(java.lang.String...) or
declaratively by setting the spring.profiles.active property as a JVM
system property, as an environment variable, or as a Servlet context
parameter in web.xml for web applications. Profiles may also be
activated declaratively in integration tests via the #ActiveProfiles
annotation.
Consider this examples where the spring.profiles.active property is not set.
#Configuration
#ComponentScan
public class Example {
public static void main(String[] args) throws Exception {
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext(Example.class);
System.out.println(Arrays.toString(ctx.getEnvironment().getActiveProfiles()));
System.out.println(ctx.getBean(Foo.class));
}
}
#Profile(value = "StackOverflow")
#Component
class Foo {
}
This will show no active profiles and throw a NoSuchBeanDefinitionException for a Foo bean. Since the StackOverflow profile wasn't active, the bean wasn't registered.
Instead, if I initialize the ApplicationContext while registering the appropriate profile
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext();
ctx.getEnvironment().setActiveProfiles("StackOverflow");
ctx.register(Example.class);
ctx.refresh();
the bean is registered and can be returned/injected.
AOP Proxies
Spring uses AOP proxies a lot to implement advanced behavior. Some examples include:
Transaction management with #Transactional
Caching with #Cacheable
Scheduling and asynchronous execution with #Async and #Scheduled
To achieve this, Spring has two options:
Use the JDK's Proxy class to create an instance of a dynamic class at runtime which only implements your bean's interfaces and delegates all method invocations to an actual bean instance.
Use CGLIB proxies to create an instance of a dynamic class at runtime which implements both interfaces and concrete types of your target bean and delegates all method invocations to an actual bean instance.
Take this example of JDK proxies (achieved through #EnableAsync's default proxyTargetClass of false)
#Configuration
#EnableAsync
public class Example {
public static void main(String[] args) throws Exception {
AnnotationConfigApplicationContext ctx = new AnnotationConfigApplicationContext(Example.class);
System.out.println(ctx.getBean(HttpClientImpl.class).getClass());
}
}
interface HttpClient {
void doGetAsync();
}
#Component
class HttpClientImpl implements HttpClient {
#Async
public void doGetAsync() {
System.out.println(Thread.currentThread());
}
}
Here, Spring attempts to find a bean of type HttpClientImpl which we expect to find because the type is clearly annotated with #Component. However, instead, we get an exception
Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException:
No qualifying bean of type [com.example.HttpClientImpl] is defined
Spring wrapped the HttpClientImpl bean and exposed it through a Proxy object that only implements HttpClient. So you could retrieve it with
ctx.getBean(HttpClient.class) // returns a dynamic class: com.example.$Proxy33
// or
#Autowired private HttpClient httpClient;
It's always recommended to program to interfaces. When you can't, you can tell Spring to use CGLIB proxies. For example, with #EnableAsync, you can set proxyTargetClass to true. Similar annotations (EnableTransactionManagement, etc.) have similar attributes. XML will also have equivalent configuration options.
ApplicationContext Hierarchies - Spring MVC
Spring lets you build ApplicationContext instances with other ApplicationContext instances as parents, using ConfigurableApplicationContext#setParent(ApplicationContext). A child context will have access to beans in the parent context, but the opposite is not true. This post goes into detail about when this is useful, particularly in Spring MVC.
In a typical Spring MVC application, you define two contexts: one for the entire application (the root) and one specifically for the DispatcherServlet (routing, handler methods, controllers). You can get more details here:
Difference between applicationContext.xml and spring-servlet.xml in Spring Framework
It's also very well explained in the official documentation, here.
A common error in Spring MVC configurations is to declare the WebMVC configuration in the root context with #EnableWebMvc annotated #Configuration classes or <mvc:annotation-driven /> in XML, but the #Controller beans in the servlet context. Since the root context cannot reach into the servlet context to find any beans, no handlers are registered and all requests fail with 404s. You won't see a NoSuchBeanDefinitionException, but the effect is the same.
Make sure your beans are registered in the appropriate context, ie. where they can be found by the beans registered for WebMVC (HandlerMapping, HandlerAdapter, ViewResolver, ExceptionResolver, etc.). The best solution is to properly isolate beans. The DispatcherServlet is responsible for routing and handling requests so all related beans should go into its context. The ContextLoaderListener, which loads the root context, should initialize any beans the rest of your application needs: services, repositories, etc.
Arrays, collections, and maps
Beans of some known types are handled in special ways by Spring. For example, if you tried to inject an array of MovieCatalog into a field
#Autowired
private MovieCatalog[] movieCatalogs;
Spring will find all beans of type MovieCatalog, wrap them in an array, and inject that array. This is described in the Spring documentation discussing #Autowired. Similar behavior applies to Set, List, and Collection injection targets.
For a Map injection target, Spring will also behave this way if the key type is String. For example, if you have
#Autowired
private Map<String, MovieCatalog> movies;
Spring will find all beans of type MovieCatalog and add them as values to a Map, where the corresponding key will be their bean name.
As described previously, if no beans of the requested type are available, Spring will throw a NoSuchBeanDefinitionException. Sometimes, however, you just want to declare a bean of these collection types like
#Bean
public List<Foo> fooList() {
return Arrays.asList(new Foo());
}
and inject them
#Autowired
private List<Foo> foos;
In this example, Spring would fail with a NoSuchBeanDefinitionException because there are no Foo beans in your context. But you didn't want a Foo bean, you wanted a List<Foo> bean. Before Spring 4.3, you'd have to use #Resource
For beans that are themselves defined as a collection/map or array
type, #Resource is a fine solution, referring to the specific
collection or array bean by unique name. That said, as of 4.3,
collection/map and array types can be matched through Spring’s
#Autowired type matching algorithm as well, as long as the element
type information is preserved in #Bean return type signatures or
collection inheritance hierarchies. In this case, qualifier values can
be used to select among same-typed collections, as outlined in the
previous paragraph.
This works for constructor, setter, and field injection.
#Resource
private List<Foo> foos;
// or since 4.3
public Example(#Autowired List<Foo> foos) {}
However, it will fail for #Bean methods, ie.
#Bean
public Bar other(List<Foo> foos) {
new Bar(foos);
}
Here, Spring ignores any #Resource or #Autowired annotating the method, because it's a #Bean method, and therefore can't apply the behavior described in the documentation. However, you can use Spring Expression Language (SpEL) to refer to beans by their name. In the example above, you could use
#Bean
public Bar other(#Value("#{fooList}") List<Foo> foos) {
new Bar(foos);
}
to refer to the bean named fooList and inject that.

Create a bean and autowire it

I currently have numerous classes with a field like
private MyStuff myStuff = new MyStuff();
It would be preferable if there was a MyStuff singleton which all the classes used. Our project has a MyConfiguration class with some Beans in it, but they don't seem to get used, at least not directly, so I can't use them for examples. I have been tasked to create a MyStuff bean in the MyConfiguration class, and then inject it into my other classes.
What I have so far:
#Configuration
public class MyConfiguration
{
#Bean
public MyStuff myStuff()
{
return new MyStuff();
}
}
public SomeClass
{
public void dealWithStuff()
{
someStuff.myMethod();
}
#Autowired
private MyStuff someStuff;
}
This compiles but does not run. someStuff is null when it tries to call myMethod(). Apparently it does not see the bean or make the connection. What am I missing?

I'm going to make an assumption, so correct me if I'm wrong: you are creating instances of SomeClass yourself. Something like
SomeClass someInstance = new SomeClass();
outside of any Spring component.
In this case, how do you expect Spring to inject anything since it's not even process it.
You need to let Spring create objects (beans) that need to have other beans injected.

The problem is naming. Refer to this for a complete description but briefly it says
If you intend to express annotation-driven injection by name, do not primarily use #Autowired, even if is technically capable of referring to a bean name through #Qualifier values. Instead, use the JSR-250 #Resource annotation, which is semantically defined to identify a specific target component by its unique name, with the declared type being irrelevant for the matching process.
It means that you should be doing something like this:
#Resource(name="myStuff")
public void setSomeStuff(MyStuff someStuff){
this.someStuff = someStuff;
}
The reason is that you have defined your bean as myStuff but referring it as someStuff.
Also to have a singleton instance, all you need is to define its scope as singleton in your Spring Configuration as following:
#Configuration
public class MyConfiguration
{
#Bean #Scope(BeanDefinition.SCOPE_SINGLETON)
public MyStuff myStuff()
{
return new MyStuff();
}
}

As I see in your code, your object reference name is "someStuff" but you are referring to myStuff you should use someStuff.myMethod();

Can #Autowire #Service beans but not members of a class instantiated with "new" keyword - even with context scanning configured

I have an app that's been working well with #Autowired #Service beans.
Now I'm adding a Validator class which is instantiated in the Controller:
BlueValidator validator = new BlueValidator(colors);
validator.validate(colorBlend, bindResult);
In the BlueValidator class I'm trying to #Autowire the blendService which is working as an #Autowired field elsewhere in the app:
public class BlueValidator implements Validator {
#Autowired
private BlendService blendService;
private Colors colors;
But for some reason after instantiating the BlueValidator, I keep getting NullPointerExceptions for the blendService.
Of course I've added the necessary context scanning:
<context:component-scan
base-package="com.myapp.controllers, com.myapp.services, com.myapp.validators" />
I also tried adding the#Autowired annotation to the constructor but that didn't help:
#Autowired
public BlueValidator(Colors colors) {
this.colors = colors;
}
Should I just pass the blendService to the BlueValidator and forget about the Autowiring or is there something obvious missing here?

If you just instantiate an object with new, Spring is not involved, so the autowiring won't kick in. Component scanning looks at classes and creates objects from them - it doesn't look at objects you create yourself.
This can be made to work, using Spring's AspectJ support, but it takes some effort.
Otherwise, you need to let Spring instantiate your objects if you wan autowiring to work.
Should I just pass the blendService to the BlueValidator and forget about the Autowiring
In your situation, I'd say yes, this is the least effort solution.

When you instantiate objects spring cannot do anything for them, so it does not get the dependencies injected (article).
In your case, you have a couple of options:
pass dependencies to the validator from the controller (where you can inject them)
make the validator a spring bean and inject it, instead of instantiating it
use #Configurable, which, via AspectJ, enables spring injection even in objects created with new

#Autowired is being used by Spring's ApplicationContext to populate those fields on creation. Since the ApplicationContext is not the one creating these beans (you are because of the keyword 'new'), they are not being autowired. You need to pass it in yourself if you are creating it.

Don't create validator manually -- allow to Spring do this work for you:
#Controller
class Controller {
#Autowired
BlueValidator validator;
void doSomething() {
...
validator.validate(colorBlend, bindResult);
...
}
}
Also pay attention that adding package com.myapp.validators to context:scan-packages not enough, you also should annotate your validator class with #Component annotation:
#Component
public class BlueValidator implements Validator {
#Autowired
private BlendService blendService;
(BTW this solution works in my project.)

Spring start a transaction with object created by new

I have a POJO class with a method annotated with #Transactional
public class Pojo {
#Transactional
public void doInTransaction() {
...
}
}
Spring declarative transaction management is based on AOP but I don't have any experience with that. My question is:
Is it possible that when invoking the (new Pojo).doInTransaction() alone, Spring will start a Transaction.

Spring declarative transaction
management is based on APO but I don't
have any experience with that.
I would recommend to start working with it and you will get the experience of using transaction advices using AOP. A good starting point is here.
Is it possible that when invoking the
(new Pojo).doInTransaction() alone,
Spring will start a Transaction.
No, you can't expect Spring to be aware of a bean that you manually invoked. However, it sounds like that you are wanting to avoid declarative transaction management and do programmatic transaction management. There is a way to do that with Spring using the Transaction Template. Is that what you were looking for?

It is somewhat possible, but in a cumbersome way: You must use the AutowireCapableBeanFactory mechanism.
Here is a transactional class as example
public interface FooBar{
void fooIze(Object foo);
}
public class FooBarImpl implements FooBar{
#Transactional
#Override
public void fooIze(final Object foo){
// do stuff here
}
}
And here is how we can use it:
public class FooService implements ApplicationContextAware{
private ApplicationContext applicationContext;
#Override
public void setApplicationContext(
final ApplicationContext applicationContext){
this.applicationContext = applicationContext;
}
public void serviceMethod(){
//declare variable as interface, initialize to implementation
FooBar fooBar = new FooBarImpl();
// try to use it, won't work, as it's not a proxy yet
Object target = new Object[0];
fooBar.fooIze(target); // no transaction
// now let spring create the proxy and re-assign the variable
// to the proxy:
fooBar = // this is no longer an instance of FooBarImpl!!!
(FooBar) applicationContext
.getAutowireCapableBeanFactory()
.applyBeanPostProcessorsAfterInitialization(fooBar,
"someBeanName");
fooBar.fooIze(fooBar); // this time it should work
}
}
This is not a best practice. For one thing, it makes your application highly aware of the Spring Framework and also, it violates the dependency injection principles. So use this only if there is no other way!

Yes, it is possible. Spring does not require the use of dynamic proxies for #Transactional to work. Instead, you can use "true AOP", as provided by AspectJ.
For the details, see http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/transaction.html#transaction-declarative-aspectj

The way Spring handle the transaction through Annotation is using AOP as you've said.
The AOP bit is implemented using Dynamic Proxies (see doc)
So in order to do so you'll need to retrieve an instance of your class (Pojo here) through the spring container since to make it work, Spring will return you a Dynamic Proxy over your Pojo that will automatically surround any annotated method with the transaction management code.
If you simply do a
Pojo p = new Pojo();
p.doInTransaction();
Spring doesn't have any role to play here and your method call won't be inside a transaction.
so what you need to do is something like this
ApplicationContext springContext = ...;
Pojo p = (Pojo) springContext.getBean("your.pojo.id");
p.doInTransaction();
Note: this is an example, you should prefer dependency injection instead of retrieving your bean manually from the context
By doing so, and with a properly configured Spring Context, Spring should have lookout your classes to scan for transactional annotation and automatically wrapped your beans into annotation aware dynamic proxies instances. From your point of view that doesn't change anything, you'll still cast your object to your own Classes, but if you try to print out the class name of your spring context Pojo bean, you'll get something as Proxy$... and not your original class name.
Have a look at this link anyway : link text