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Split or tokenise a java String using a substring as delimiter

How to split or tokenise a String in java not based on regex but based on a substring?
String str = "{A={111={i=[a,b,c],ii=[e,f]}, 222={iii=[a,e]}}, B={333={i= [b,c]}}};
Now I want to tokenise or split the string based on substring "}}," and not regex "}},".

Although the String.split(String regex) function specifies that it takes a regular expression as a parameter, that does not stop you from escaping any special characters and splitting on a literal string.
To escape special characters in a regular expression, you can make use of the Pattern.quote(String s) function, or you can escape the individual characters using backslashes \\:
String escapedStr = Pattern.quote("}},");
String alternativeEscapedStr = "\\}\\},";
For the example you have provided however, you shouldn't need to escape anything:
String str = "{A={111={i=[a,b,c],ii=[e,f]}, 222={iii=[a,e]}}, B={333={i= [b,c]}}}";
String[] splitStr = str.split(Pattern.quote("}},"));
System.out.println(Arrays.toString(splitStr));
String[] splitStr2 = str.split("}},");
System.out.println(Arrays.toString(splitStr2));
Output:
[{A={111={i=[a,b,c],ii=[e,f]}, 222={iii=[a,e], B={333={i= [b,c]}}}]
[{A={111={i=[a,b,c],ii=[e,f]}, 222={iii=[a,e], B={333={i= [b,c]}}}]

String str = "{A={111={i=[a,b,c],ii=[e,f]}, 222={iii=[a,e]}}, B={333={i= [b,c]}}}";
String[] split = str.trim().split("}},");
Arrays.stream(split).forEach(s-> System.out.println(s));

cant make this delimiter work, java split

I need help making a delimiter for multiple characters
I need a String delimiter for
these characters
( ) " ; : , ? ! .
I've tried:
private String delimiter = "()\":;,?!.";
private String delimiter = "[()\":;,?!.]";
private String delimiter = "\\(\\)\"\\:\\;\\,\\?\\!\\.";
Seems I can only make them work one at a time..
Any insight is greatly appreciated.
If it matters this is how its going into array:
foo = line.split(delim);

If you want to split on any of those characters, you can separate each one with an alternation: |. Otherwise, the string will only be split when all of those characters are present.
String delimiter = "\\(|\\)|\"|\\:|\\;|\\,|\\?|\\!|\\.";
Also, you're unnecessarily escaping a few characters, this would also work:
String delimiter = "\\(|\\)|\"|:|;|,|\\?|!|\\.";

Almost there with nr. 3
#Test
public void delim() {
String delimiter = "[\\(\\)\"\\:\\;\\,\\?\\!\\.]";
String[] split = "Hello(World)How:are;You;doing,today?You!sir.I mean"
.split(delimiter);
System.out.println(Arrays.toString(split));
}
Output
[Hello, World, How, are, You, doing, today, You, sir, I mean]
You missed the square brackets.
To avoid all the quoting you may use Pattern#quote
String delimiter = "[" + Pattern.quote("()\":;,?!.") + "]";
Returns a literal pattern String for the specified String.
This method produces a String that can be used to create a Pattern that would match the string s as if it were a literal pattern.
Metacharacters or escape sequences in the input sequence will be given no special meaning.

| is required between:
delimiter = "\\(|\\)|\"|:|;|,|\\?|!|\\."

Java regex to split a string by using different delimiters

Suppose I want to split a string by either space character or the %20 string, how should I write my regex?
I tried the following, but it didn't work.
String regex = "[\\s+, %20]";
String str1 = "abc%20xyz";
String str2 = "abc xyz";
str1.split(regex);
str2.split(regex);
The regex doesn't seem to work on str1.

use the alternation |:
String regex = "(?:\\s+|%20)+";

String regex = "(\\s{1}+|%20{1}+)";

If you want to split by ONE space or ONE "%20", try this:
String regex = "(\\s|%20)";
If you want to split by AT LEAST ONE space or AT LEAST ONE "%20", then try this:
String regex = "(\\s+|(%20)+)";

How can I split a string by two delimiters?

I know that you can split your string using myString.split("something"). But I do not know how I can split a string by two delimiters.
Example:
mySring = "abc==abc++abc==bc++abc";
I need something like this:
myString.split("==|++")
What is its regularExpression?

Use this :
myString.split("(==)|(\\+\\+)")

How I would do it if I had to split using two substrings:
String mainString = "This is a dummy string with both_spaces_and_underscores!"
String delimiter1 = " ";
String delimiter2 = "_";
mainString = mainString.replaceAll(delimiter2, delimiter1);
String[] split_string = mainString.split(delimiter1);
Replace all instances of second delimiter with first and split with first.
Note: using replaceAll allows you to use regexp for delimiter2. So, you should actually replace all matches of delimiter2 with some string that matches delimiter1's regexp.

You can use this
mySring = "abc==abc++abc==bc++abc";
String[] splitString = myString.split("\\W+");
Regular expression \W+ ---> it will split the string based upon non-word character.

Try this
String str = "aa==bb++cc";
String[] split = str.split("={2}|\\+{2}");
System.out.println(Arrays.toString(split));
The answer is an array of
[aa, bb, cc]
The {2} matches two characters of the proceding character. That is either = or + (escaped)
The | matches either side
I am escaping the \ in java so the regex is actually ={2}|\+{2}

How to split the string using '^' this special character in java?

I want to split the following string "Good^Evening" i used split option it is not split the value. please help me.
This is what I've been trying:
String Val = "Good^Evening";
String[] valArray = Val.Split("^");

I'm assuming you did something like:
String[] parts = str.split("^");
That doesn't work because the argument to split is actually a regular expression, where ^ has a special meaning. Try this instead:
String[] parts = str.split("\\^");
The \\ is really equivalent to a single \ (the first \ is required as a Java escape sequence in string literals). It is then a special character in regular expressions which means "use the next character literally, don't interpret its special meaning".

The regex you should use is "\^" which you write as "\\^" as a Java String literal; i.e.
String[] parts = "Good^Evening".split("\\^");
The regex needs a '\' escape because the caret character ('^') is a meta-character in the regex language. The 2nd '\' escape is needed because '\' is an escape in a String literal.

try this
String str = "Good^Evening";
String newStr = str.replaceAll("[^]+", "");