I am trying to get the response from an Ajax call into a html label. I am using a tomcat server. Ia m able to see the description returned form the server however how do i get the responses into the lable text. Under is what i have tried:
Jquery
function GetDescription(Id){
$.ajax({
type:'GET',
url:'getDescription.htm',
data:{dId:Id},
dataType: 'json',
success: function (data) {
$('.TypeDesc').text = data.responseText;
}
});
}
$(document).ready(function() {
$(".photos").each(function(i){
if ($(this).val() != '') {
var image = new Image();
image.src = $(this).val();
image.onload = function(){
var typeId = document.getElementsByClassName("TypeId")[i].value;
GetDescription(typeId);
var ctx = document.getElementsByClassName("canvas")[i].getContext('2d');
ctx.drawImage(image,0,0, 320, 240);
}
}
});
});
html
</head>
<body>
<div id ="content">
<c:forEach items="${object}" var="i">
<div id="table">
<div>
<p><canvas class="canvas" height="240" width="320"></canvas>
</div>
Name:- ${i.fName} ${i.lName}
<input type="hidden" id="photo" value="${i.photo}" class="photos"/>
<input type="hidden" id="Number" value="${i.Number}" />
<input type="text" class="TypeId" value="${i.citizenTypeId}"/>
<label class="TypeDesc"></label>
</div>
</c:forEach>
</div>
</body>
</html>
The problem is that you're telling jQuery you're expecting JSON:
dataType: 'json',
...and so it's (trying to) parse the response as JSON and pass you an object, but then you're trying to use it like a raw XHR object.
If you want the text, remove the dataType or change it to dataType: 'text', and then use data which will be a string.
Your other problem is that text is a function, not a property, so you need to call it.
So:
dataType: 'text',
success: function (data) {
$('.TypeDesc').text(data);
}
Please add this to the parameters of the ajax call
success: function(data) {
$('.TypeDesc').each(function(){
$(this).text(data);
});
}
You need to give the lable a unique ID like id="TypeDesc{i}" or something different.
So you can refer to it something like this:
$('#TypeDesc{i}').text = data.responseText;
Related
I need to place returned JSON data in HTML Form. I called database using web services and get JSON data. What I want is to place these JSON data into HTML input fields.
Sample JSON data (Returned as an array)
[{"username":"demo","email":"demo#gmail.com","password":"123"}]
The code in List.jsp
<form>
Enter Username:<br>
<input type="text" id="usernameEn" name="username"><br>
<button id="btnGet">Get</button>
</form>
<br><br>
<form>
Username:<br>
<input type="text" id="username" name="username"><br>
Email:<br>
<input type="text" id="email" name="email"><br><br>
Password:<br>
<input type="text" id="password" name="password"><br><br>
</form>
<script type="text/javascript">
$(document).ready(function()
{
$("#btnGet").click(function(event)
{
event.preventDefault();
$.ajax({
type: 'GET',
url: "http://localhost:8080/WebServiceTest2/webresources/users/get/" + $('#usernameEn').val(),
dataType: "json",
success: function(data) {
console.log(data);
var userDetails = data;
renderDetails(userDetails);
},
error: function(jqXHR, textStatus, errorThrown) {
alert('Error: ' + textStatus);
}
});
});
});
function renderDetails(data)
{
$('#username').val(data.username);
$('#email').val(data.email);
$('#password').val(data.password);
};
</script>
Your REST service is returning an array, so to populate the form you'd have to access the first element of the array:
$('#username').val(data[0].username);
$('#email').val(data[0].email);
$('#password').val(data[0].password);
Or you could do the assignment higher up so you don't have to change your renderDetails() function:
var userDetails = data[0];
Probably best to also add a check to see whether the returned array is not empty.
I'm creating a JSP/Servlet web application and I'd like to upload a file to a servlet via Ajax. How would I go about doing this? I'm using jQuery.
I've done so far:
<form class="upload-box">
<input type="file" id="file" name="file1" />
<span id="upload-error" class="error" />
<input type="submit" id="upload-button" value="upload" />
</form>
With this jQuery:
$(document).on("#upload-button", "click", function() {
$.ajax({
type: "POST",
url: "/Upload",
async: true,
data: $(".upload-box").serialize(),
contentType: "multipart/form-data",
processData: false,
success: function(msg) {
alert("File has been uploaded successfully");
},
error:function(msg) {
$("#upload-error").html("Couldn't upload file");
}
});
});
However, it doesn't appear to send the file contents.
To the point, as of the current XMLHttpRequest version 1 as used by jQuery, it is not possible to upload files using JavaScript through XMLHttpRequest. The common workaround is to let JavaScript create a hidden <iframe> and submit the form to it instead so that the impression is created that it happens asynchronously. That's also exactly what the majority of the jQuery file upload plugins are doing, such as the jQuery Form plugin (an example).
Assuming that your JSP with the HTML form is rewritten in such way so that it's not broken when the client has JavaScript disabled (as you have now...), like below:
<form id="upload-form" class="upload-box" action="/Upload" method="post" enctype="multipart/form-data">
<input type="file" id="file" name="file1" />
<span id="upload-error" class="error">${uploadError}</span>
<input type="submit" id="upload-button" value="upload" />
</form>
Then it's, with the help of the jQuery Form plugin, just a matter of
<script src="jquery.js"></script>
<script src="jquery.form.js"></script>
<script>
$(function() {
$('#upload-form').ajaxForm({
success: function(msg) {
alert("File has been uploaded successfully");
},
error: function(msg) {
$("#upload-error").text("Couldn't upload file");
}
});
});
</script>
As to the servlet side, no special stuff needs to be done here. Just implement it exactly the same way as you would do when not using Ajax: How can I upload files to a server using JSP/Servlet?
You'll only need an additional check in the servlet if the X-Requested-With header equals XMLHttpRequest or not, so that you know how what kind of response to return for the case that the client has JavaScript disabled (as of now, it is mostly the older mobile browsers which have JavaScript disabled).
if ("XMLHttpRequest".equals(request.getHeader("X-Requested-With"))) {
// Return an Ajax response (e.g. write JSON or XML).
} else {
// Return a regular response (e.g. forward to JSP).
}
Note that the relatively new XMLHttpRequest version 2 is capable of sending a selected file using the new File and FormData APIs. See also HTML5 drag and drop file upload to Java Servlet and Send a file as multipart through XMLHttpRequest.
Monsif's code works well if the form has only file type inputs. If there are some other inputs other than the file type, then they get lost. So, instead of copying each form data and appending them to FormData object, the original form itself can be given to the constructor.
<script type="text/javascript">
var files = null; // when files input changes this will be initialised.
$(function() {
$('#form2Submit').on('submit', uploadFile);
});
function uploadFile(event) {
event.stopPropagation();
event.preventDefault();
//var files = files;
var form = document.getElementById('form2Submit');
var data = new FormData(form);
postFilesData(data);
}
function postFilesData(data) {
$.ajax({
url : 'yourUrl',
type : 'POST',
data : data,
cache : false,
dataType : 'json',
processData : false,
contentType : false,
success : function(data, textStatus, jqXHR) {
alert(data);
},
error : function(jqXHR, textStatus, errorThrown) {
alert('ERRORS: ' + textStatus);
}
});
}
</script>
The HTML code can be something like following:
<form id ="form2Submit" action="yourUrl">
First name:<br>
<input type="text" name="firstname" value="Mickey">
<br>
Last name:<br>
<input type="text" name="lastname" value="Mouse">
<br>
<input id="fileSelect" name="fileSelect[]" type="file" multiple accept=".xml,txt">
<br>
<input type="submit" value="Submit">
</form>
$('#fileUploader').on('change', uploadFile);
function uploadFile(event)
{
event.stopPropagation();
event.preventDefault();
var files = event.target.files;
var data = new FormData();
$.each(files, function(key, value)
{
data.append(key, value);
});
postFilesData(data);
}
function postFilesData(data)
{
$.ajax({
url: 'yourUrl',
type: 'POST',
data: data,
cache: false,
dataType: 'json',
processData: false,
contentType: false,
success: function(data, textStatus, jqXHR)
{
//success
},
error: function(jqXHR, textStatus, errorThrown)
{
console.log('ERRORS: ' + textStatus);
}
});
}
<form method="POST" enctype="multipart/form-data">
<input type="file" name="file" id="fileUploader"/>
</form>
This code works for me.
I used Commons IO's io.jar, Commons file upload.jar, and the jQuery form plugin:
<script>
$(function() {
$('#upload-form').ajaxForm({
success: function(msg) {
alert("File has been uploaded successfully");
},
error: function(msg) {
$("#upload-error").text("Couldn't upload file");
}
});
});
</script>
<form id="upload-form" class="upload-box" action="upload" method="POST" enctype="multipart/form-data">
<input type="file" id="file" name="file1" />
<span id="upload-error" class="error">${uploadError}</span>
<input type="submit" id="upload-button" value="upload" />
</form>
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if (isMultipart) {
// Create a factory for disk-based file items
FileItemFactory factory = new DiskFileItemFactory();
// Create a new file upload handler
ServletFileUpload upload = new ServletFileUpload(factory);
try {
// Parse the request
List items = upload.parseRequest(request);
Iterator iterator = items.iterator();
while (iterator.hasNext()) {
FileItem item = (FileItem) iterator.next();
if (!item.isFormField()) {
String fileName = item.getName();
String root = getServletContext().getRealPath("/");
File path = new File(root + "../../web/Images/uploads");
if (!path.exists()) {
boolean status = path.mkdirs();
}
File uploadedFile = new File(path + "/" + fileName);
System.out.println(uploadedFile.getAbsolutePath());
item.write(uploadedFile);
}
}
} catch (FileUploadException e) {
e.printStackTrace();
} catch (Exception e) {
e.printStackTrace();
}
}
I am trying to make an upload page which takes file to upload. I am using Spring framework here my query is on Upload button I am calling a JavaScript method which should send my file to controller using jQuery AJAX. Is there any way to pass this through JavaScript?
Following is the code which I am trying.
<body>
<div style="text-align: center; margin-top: 60px;">
<form enctype="multipart/form-data">
Select file:
<input type="file" name="dataFile" id="fileAttachment"/><br/><br/>
<div style="text-align: center; margin-top: 100px;">
<input style="cursor: pointer;" onmouseover="" onclick="uploadAttachment()" class="dialogbox" type="submit" value="Upload Report" />
</div>
</form>
</div>
</body>
JS:
<script language="Javascript">
function uploadAttachment(){
var Name = jQuery('#Name option:selected').text();
jQuery.post('upload',{Name:Name}
function(data){
if(data==1)
alert("success");
else
alert("failed");
});
}
</script>
on controller.java page following is the code written
#RequestMapping(value = "upload", method=RequestMethod.POST)
public #ResponseBody String upload(HttpServletRequest request, HttpServletResponse response,
#RequestParam("Name") String Name){
System.out.println(Name);
}
If you are in fact seeking a pure javascript way to upload an image/file, then the following tutorial from 2009 will tell you exactly how to do that:
http://igstan.ro/posts/2009-01-11-ajax-file-upload-with-pure-javascript.html
I ran into this when I wanted to add basic-authentication to a form submission, without enabling cookies. E.g. when you have username/password fields with your filename, file, etc fields.
Hope this helps!
I think you can try the following code to upload file with javascript.
function uploadAttachment(){
$('#fileAttachment').trigger('click');
if (typeof timer != 'undefined') {
clearInterval(timer);
}
timer = setInterval(function() {
if ($('#fileAttachment').val() != '') {
clearInterval(timer);
$.ajax({
url: 'YOUR_UPLOAD_URL',
type: 'post',
dataType: 'json',
data: new FormData($('#fileAttachment').closest('form')[0]),
cache: false,
contentType: false,
processData: false,
success: function(response){
}
});
}
}, 500);
}
You need to replace YOUR_UPLOAD_URL with your server upload URL.
refer.jvmhost.net/refer247/registration, this is my url,i have to fetch request to this url like user details and should get the appropriate response in json format with status n error if it contains ..dont give me android code..
this is html page.
<head>
<script type="text/javascript" src="json2.js"></script>
</head>
<body>
<div data-role="page" data-theme="c">
<div data-role="header" data-position="fixed" data-inset="true" class="paddingRitLft" data-theme="c">
<div data-role="content" data-inset="true"> <img src="images/logo_hdpi.png"/>
</div>
</div>
<div data-role="content" data-theme="c">
<form name="form" method="post" onsubmit="return validate()">
<div class="logInner">
<div class="logM">Already have an account?</div>
<div class="grouped insert refb">
<div class="ref first">
<div class="input inputWrapper">
<input type="text" data-corners="false" class="inputrefer" placeholder="Userid" name="userid" id="userid" />
</div>
<div class="input inputWrapper">
<input type="password" data-corners="false" class="inputrefer" placeholder="Password" name="password" id="password" />
</div> <input type="submit" data-inline="true" value="Submit" onclick="json2()">
<p>Forgot Password
</p>
</div>
</div>
<div class="logM">New user? Create refer Account</div>
<input type="button" class="btnsgreen" value="Sign Up! its FREE" class="inputrefer" data-corners="false" data-theme="c" />
</form>
</div>
</div>
<p style="text-align: center;">© refer247 2013</p>
</div>
</body>
this is json2.js
function json2()
{
var json1={"username":document.getElementById('userid').value,
"password":document.getElementById('password').value,
};
//var parsed = jsonString.evalJSON( true );
alert(json1["username"]);
alert(json1["password"]);
};
so tell me how to send the json data to that url n obtain some response like if email
id is already exist if u registering with that id ..then give some error
like email id already exist n if registerd succesfully then give respone like registerd successfully and status msg..200 okk...
You can use ajax to post json data to specified url/controller method. In the below sample I am posting an json object. You can also pass each parameter separately.
var objectData =
{
Username: document.getElementById('userid').value,
Password: document.getElementById('password').value
};
var objectDataString = JSON.stringify(objectData);
$.ajax({
type: "POST",
url: "your url with method that accpects the data",
dataType: "json",
data: {
o: objectDataString
},
success: function (data) {
alert('Success');
},
error: function () {
alert('Error');
}
});
And your method can have only one parameter of string type.
[HttpPost]
public JsonResult YourMethod(string o)
{
var saveObject = Newtonsoft.Json.JsonConvert.DeserializeObject<DestinationClass>(o);
}
$.ajax({
url: urlToProcess,
type: httpMethod,
dataType: 'json',
data:json1,
success: function (data, status) {
var fn = window[successCallback];
fn(data, callbackArgs);
},
error: function (xhr, desc, err) {
alert("error");
},
});
function addProductById(pId,pMqty){
$.getJSON("addtocart?pid=" + pId + "&minqty="+ pMqty +"&rand=" + Math.floor((Math.random()*100)+1), function(json) {
alert(json.msg);
});
}
Here is a simple example, which will call on button click or onclick event and call addtocart servlet and passes 2 argument with it i.e. pId and pMqty.
and after successful completion it return message in alert which is set in that servlet in json.
var json1={"username":document.getElementById('userid').value,
"password":document.getElementById('password').value,
};
$.ajax({
url: '/path/to/file.php',
type: 'POST',
dataType: 'text',//no need for setting this to JSON if you don't receive a json response.
data: {param1: json1},
})
.done(function(response) {
console.log("success");
alert(response);
})
.fail(function() {
console.log("error");
})
.always(function() {
console.log("complete");
});
on the server you can receive you json and decode it like so:
$myjson=json_decode($_POST['param1']);
Im using the following ajax code to submit data from a form to a servlet and then have the servlet send data back (havent quite mastered this part yet).
Side question, the variable id is obtained from the .jsp file by using
`<script> var id = '${id}' </script>`
Is there a better way to access this variable directly from inside a .js file that is loaded on the page ? It works as is but it seems messy.
$(document).ready(function () {
$('.doAction').click(function () {
var rel = parseInt($('.doAction:checked').attr('rel'));
$.ajax({
type: 'POST',
dataType: 'json',
cache: false,
data: {
rating: rel,
itemID: id
},
url: 'Ratings',
success: function (data) {
}
});
});
});
The HTML form code is
<div id=holder>
<div id="rating">
Rating
<form id="ratingsform" name="ratingsform">
<input class="doAction" type="radio" name="ra1" rel="1" />
<input class="doAction" type="radio" name="ra1" rel="2" />
<input class="doAction" type="radio" name="ra1" rel="3" />
<input class="doAction" type="radio" name="ra1" rel="4" />
<input class="doAction" type="radio" name="ra1" rel="5" />
</form>
</div>
</div>
So what i want to happen is when a radio button is selected, the form is disabled so that new radio buttons can't be pressed (so the servlet cant be spammed to death). When the servlet responds to the ajax post call, I would like to change the contents of the div "rating" to display the updated ratings and remove the ability to vote i.e remove the radio buttons / form. I have the server side code working except for figuring out how to return the values required which hopefully is pretty straight forward.
Any suggestions ?
well check my comments to understand the change
$(document).ready(function () {
var id = '${id}' // you can have it here
$('.doAction').click(function () {
var rel = $('.doAction:checked').attr('rel'); // you need not parse to int because it will always string in parameter
$('.doAction').prop('disabled', true); // to disable radio button
$.ajax({
type: 'POST',
dataType: 'html', // change this since your servlet response is html not json
cache: false,
data: {
rating: rel,
itemID: id
},
url: 'Ratings',
success: function (data) {
$('#rating').html(data); // assuming response as {"rating" : 4.4}
}
});
});
});
In your server-side scripting, you need to print the data you would like sent back, then call it through the success function of the $.ajax object:
// Other AJAX...
success:function(msg){
$('#rating').html(msg);
}
// Other AJAX
I'm not the most familier with JSP, however I believe the command is something like out.print().
// Your js
$(document).ready(function () {
$('.doAction').live('click',function () {
// If we click then it is checked
var rel = parseInt($(this).attr('rel'));
// The id of the input hidden
var id = $('#theID').val();
$.ajax({
type: 'POST',
dataType: 'json',
cache: false,
data: {
rating: rel,
itemID: id
},
url: 'Ratings',
success: function (data) {
// Displays the data returned by your servlet
$('#rating').html(data);
}
});
});
});
// HTML
<div id=holder>
<div id="rating">
Rating
<form id="ratingsform" name="ratingsform">
<input type="hidden" name="theID" value='${id}'/>
<input class="doAction" type="radio" name="ra1" rel="1" />
<input class="doAction" type="radio" name="ra1" rel="2" />
<input class="doAction" type="radio" name="ra1" rel="3" />
<input class="doAction" type="radio" name="ra1" rel="4" />
<input class="doAction" type="radio" name="ra1" rel="5" />
</form>
</div>
</div>
First of all, the server returns data? How is this returned? I would to this:
...
success: function (data) {
$("#ratings").html('<div class="rating '+rel+'stars"></div>');
}
...
And create 2 classes, one called rating and 5 more called 1,2,3,4,5stars, that would work.
Good luck!