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SOAP client on Java 11

I need to consume a SOAP service, and I have seen on the spring tutorial that my java classes for consuming and receiving the services, can be automatically generated using a tool or a framework.
The thing is most tutorials rely on wsimport tool from the JDK...and after lots of hours trying I found out that for Java 11, this is deprecated.
After this I found this ,this, and this talking about some workarounds for this problem. I tried all of them, but my gradle.build starts generating dependencies issues around this libraries. I have tried to exclude the problematic libraries but it doesn´t solve the issue.
So I'm wondering how can I generate my SOAP client classes on a not so patched way?
Additional info: It's a contract first approach, the service is on the web and it is a ?wsdl url.

At the end, I just followed this tutorial, which was simple enough and allowed me to consume a SOAP web service and then build an XML file to process the info retrieved. Hopefully Java 11 will have some better support for this type of service on the near future, but meanwhile I solved my problem and maybe this post can be useful to someone with a similar task to perform.

ofcourse that I can share :) my coding:
import java.io.BufferedReader;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.URLConnection;
import lombok.extern.slf4j.Slf4j;
import org.apache.commons.lang3.StringEscapeUtils;
import org.apache.commons.lang3.StringUtils;
import org.springframework.stereotype.Service;
#Service
#Slf4j
public class GusGetCompanyRawXml {
public String getCompanyRawXmlData(String sessionKey, String polishVatId) {
String outputString = "";
try {
URL url = new URL("https://wyszukiwarkaregon.stat.gov.pl/wsBIR/UslugaBIRzewnPubl.svc");
URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;
ByteArrayOutputStream bout = new ByteArrayOutputStream();
String xmlInput =
"<soap:Envelope xmlns:soap=\"http://www.w3.org/2003/05/soap-envelope\"\n"
+ "xmlns:ns=\"http://CIS/BIR/PUBL/2014/07\" xmlns:dat=\"http://CIS/BIR/PUBL/2014/07/DataContract\">\n"
+ "<soap:Header xmlns:wsa=\"http://www.w3.org/2005/08/addressing\">\n"
+ "<wsa:To>https://wyszukiwarkaregontest.stat.gov.pl/wsBIR/UslugaBIRzewnPubl.svc</wsa:To>\n"
+ "<wsa:Action>http://CIS/BIR/PUBL/2014/07/IUslugaBIRzewnPubl/DaneSzukajPodmioty</wsa:Action>\n"
+ "</soap:Header>\n"
+ "<soap:Body>\n"
+ "<ns:DaneSzukajPodmioty>\n"
+ "<ns:pParametryWyszukiwania>\n"
+ "<dat:Nip>"+polishVatId+"</dat:Nip>\n"
+ "</ns:pParametryWyszukiwania>\n"
+ "</ns:DaneSzukajPodmioty>\n"
+ "</soap:Body>\n"
+ "</soap:Envelope>";
byte[] buffer;
buffer = xmlInput.getBytes();
bout.write(buffer);
byte[] b = bout.toByteArray();
String SOAPAction = "http://CIS/BIR/PUBL/2014/07/IUslugaBIRzewnPubl/Zaloguj";
httpConn.setRequestProperty("Content-Length", String.valueOf(b.length));
httpConn.setRequestProperty("Content-Type", "application/soap+xml; charset=utf-8");
httpConn.setRequestProperty("SOAPAction", SOAPAction);
httpConn.setRequestProperty("sid", sessionKey);
httpConn.setRequestMethod("POST");
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
OutputStream out = httpConn.getOutputStream();
//Write the content of the request to the outputstream of the HTTP Connection.
out.write(b);
out.close();
//Ready with sending the request.
//Read the response.
InputStreamReader inputStreamReader = new InputStreamReader(httpConn.getInputStream(), "UTF-8");
BufferedReader bufferedReader = new BufferedReader(inputStreamReader);
//
String responseString = "";
//Write the SOAP message response to a String.
while ((responseString = bufferedReader.readLine()) != null) {
if (StringUtils.contains(responseString, "<")) {
String unescapedString = StringEscapeUtils.unescapeXml(responseString);
String remove = StringUtils.remove(unescapedString, "\r");
outputString = outputString + remove;
}
}
} catch (IOException e){
log.error("Get customer data from gus failed",e.getStackTrace());
}
return outputString;
}
}

public BlnInitBookData initTrans(String ccode, String license) {
BlnInitBookData initBookData = null;
try {
BlnInitBook request = new BlnInitBook();
request.setLicenseType(license);
request.setStrCinemaCode(ccode);
initBookData = ((BlnInitBookResponse) getWebServiceTemplate().marshalSendAndReceive(hosted_server_URL, request,
new SoapActionCallback("URL_of_SOAP_api"))).getServiceResponse1()
.getBlnInitBookData();
} catch (final Exception e) {
logger.error(this.getClass().getName() + e.getMessage);
}
return initBookData;}
In Java, use the WebServiceGatewaySupport class, It worked for me. I generated SOAP requests, response classes.

File name missing in REST API via HTTP Post

I am doing a program which can take the file as input and send http://IPaddress:port_number/etc via REST API HTTP Post method, it will return me my file information in JSON format but in the return of my JSON data, I found out my file name and file type were missing. I only have two program doing the job ,one is sending the file to my server which install in VMware and one is receiving the JSON data from my server, my server only installed a malware scanning engine only Here is my JSON data return from my server
{
   "data_id":"7860ee33d8f14f8f931860dcf97d69a2",
   "file_info":{
      "display_name":"",
      "file_size":289,
      "file_type":"Not available",
      "file_type_description":"Not available",
      "md5":"b294bdea53f3a038d263d8b2e7cafbbc",
      "sha1":"b869fd379cb9743b6c0994494f3ea91a133622cd",
      "sha256":"0f88b399aa65ad75a4e0d1d03acfd31731c68ea54d5f4f5053d6904d192e5e22",
      "upload_timestamp":"2016-11-21T09:48:58.675Z" },
I had tested several code in online but it's also fail to display the file name in the JSON data, display_name will be the file name for my file. May I know is it because some information being miss out in the header and how do I include the file name during the return JSON data ? Here is my java source code
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import javax.activation.MimetypesFileTypeMap;
import java.io.*;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.mime.MultipartEntityBuilder;
import org.apache.http.entity.mime.content.FileBody;
import org.apache.http.impl.client.DefaultHttpClient;
public class SentFile {
public static void main(String [] args) throws ClientProtocolException, IOException
{
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("http://192.168.0.25:8008/file");
// File file = new File("testScanFile.txt");
//FileInputStream fileInputStream = new FileInputStream(file);
FileBody bin = new FileBody(new File("testScanFile.txt"));
// String mimeType = new MimetypesFileTypeMap().getContentType("testScanFile.txt");
HttpEntity reqEntity = MultipartEntityBuilder.create()
// .addBinaryBody("bin", new File("testScanFile.txt"),ContentType.APPLICATION_JSON,"testScanFile.txt").build();
.addPart("display_name", bin)
// .addPart("file",bin);
.build();
// post.addHeader("content-type","application/json");
// post.addHeader("Accept","application/json");
post.setEntity(reqEntity);
//InputStream is = new FileInputStream(file);
// post.setEntity(new FileEntity(file));
HttpResponse response = client.execute(post);
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String line = "";
while ((line = rd.readLine()) != null) {
// System.out.println(line);
PrintStream ps = new PrintStream(new FileOutputStream("data_id.txt"));
ps.print(line);
ps.close();
}
}
}

Is possible to call servlet from applet

I am not familiar with java and applets, so any one please let me know the possibilities for the following my questing.
I would like to call the Servlet from applet.. is this possible?
If the 1st one is possible can we store the Servlet output like XML data or string in the applet variable?
If the 2nd one is possible, then can get that that variable value using JavaScript or J Query?
If possible please give me the simple example.
Thanks in advance.

Yes you can. The servlet exposes a URL, which you can get with the help of the URLConnection class.
Again you can do this, see here on how you can use the URL connection.
You can do that too, create an applet to get the applet field, and look here on how you can invoke the method.
But all these sound awfully complicated. Why don't you tell us what you are trying to achieve, maybe there is a simpler way to do things.

One : yes you can call the servlet from applet making http calls
step 1 : make a http call to your servlet
step 2 : make your servlet return XML response
step 3 : parse xml response
using this program you can make a call to your servlet
package com.hussain;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.URI;
import java.util.ArrayList;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
public class callServlet {
public static void main(String[] args)
{
String servletResponse = callServlet.sendRequest("http://gdata.youtube.com/feeds/base/videos?max-results=10&start-//index=1&alt=json&orderby=published&author=astrobixweb");
callServlet.parseFromXMLResponse(servletResponse);
}
public static String sendRequest(String url) {
String result = "";
try {
HttpClient client = new DefaultHttpClient();
HttpParams httpParameters = client.getParams();
HttpConnectionParams.setConnectionTimeout(httpParameters, 5000);
HttpConnectionParams.setSoTimeout(httpParameters, 5000);
HttpConnectionParams.setTcpNoDelay(httpParameters, true);
HttpGet request = new HttpGet();
request.setURI(new URI(url));
HttpResponse response = client.execute(request);
InputStream ips = response.getEntity().getContent();
BufferedReader buf = new BufferedReader(new InputStreamReader(ips,"UTF-8"));
StringBuilder sb = new StringBuilder();
String s;
while (true) {
s = buf.readLine();
if (s == null || s.length() == 0)
break;
sb.append(s);
}
buf.close();
ips.close();
result = sb.toString();
} catch (Exception e) {
e.printStackTrace();
}
return result;
}
public static void parseFromXMLResponse(String respo)
{
// parse your XML response here
}
}

Moving in the flow of your question,
You may call the servlet from your applet:
Construct the url that will hit your servlet.
Use java.net.URLConnection object to hold the connection from your appletURLConnection con = urlToServlet.openConnection()
'con.setDoOutput(true)' => Application intends to write data to the URL connection.
Use the input and output streams to communicate with the Servlet.
con.getInputStream() and con.getOutputStream()
[Note: Don't forget to close all the connections and streams]
Now, use the data you obtained from the InputStream, in what so ever form you want.
Its extreamly simple, use this code:
In Applet:
public String getYourString(){ return responseFromServlet;}
In Javascript:
var jsResp = document.name_of_your_applet.getYourString();
Hope, you've got your answers!

How to consume REST in Java [duplicate]

This question already has answers here:
How do you create a REST client for Java? [closed]
(18 answers)
Closed 2 years ago.
Using Java tools,
wscompile for RPC
wsimport for Document
etc..
I can use WSDL to generate the stub and Classes required to hit the SOAP Web Service.
But I have no idea how I can do the same in REST.
How can I get the Java classes required for hitting the REST Web Service.
What is the way to hit the service anyway?
Can anyone show me the way?

Working example, try this:
package restclient;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
public class NetClientGet {
public static void main(String[] args) {
try {
URL url = new URL("http://localhost:3002/RestWebserviceDemo/rest/json/product/dynamicData?size=5");//your url i.e fetch data from .
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/json");
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP Error code : "
+ conn.getResponseCode());
}
InputStreamReader in = new InputStreamReader(conn.getInputStream());
BufferedReader br = new BufferedReader(in);
String output;
while ((output = br.readLine()) != null) {
System.out.println(output);
}
conn.disconnect();
} catch (Exception e) {
System.out.println("Exception in NetClientGet:- " + e);
}
}
}

As others have said, you can do it using the lower level HTTP API, or you can use the higher level JAXRS APIs to consume a service as JSON. For example:
Client client = ClientBuilder.newClient();
WebTarget target = client.target("http://host:8080/context/rest/method");
JsonArray response = target.request(MediaType.APPLICATION_JSON).get(JsonArray.class);

Its just a 2 line of code.
import org.springframework.web.client.RestTemplate;
RestTemplate restTemplate = new RestTemplate();
YourBean obj = restTemplate.getForObject("http://gturnquist-quoters.cfapps.io/api/random", YourBean.class);
Ref. Spring.io consuming-rest

The code below will help to consume rest api via Java.
URL - end point rest
If you dont need any authentication you dont need to write the authStringEnd variable
The method will return a JsonObject with your response
public JSONObject getAllTypes() throws JSONException, IOException {
String url = "/api/atlas/types";
String authString = name + ":" + password;
String authStringEnc = new BASE64Encoder().encode(authString.getBytes());
javax.ws.rs.client.Client client = ClientBuilder.newClient();
WebTarget webTarget = client.target(host + url);
Invocation.Builder invocationBuilder = webTarget.request(MediaType.APPLICATION_JSON).header("Authorization", "Basic " + authStringEnc);
Response response = invocationBuilder.get();
String output = response.readEntity(String.class
);
System.out.println(response.toString());
JSONObject obj = new JSONObject(output);
return obj;
}

Just make an http request to the required URL with correct query string, or request body.
For example you could use java.net.HttpURLConnection and then consume via connection.getInputStream(), and then covnert to your objects.
In spring there is a restTemplate that makes it all a bit easier.

If you also need to convert that xml string that comes as a response to the service call, an x object you need can do it as follows:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.StringReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.JAXB;
import javax.xml.bind.JAXBException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.CharacterData;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
public class RestServiceClient {
// http://localhost:8080/RESTfulExample/json/product/get
public static void main(String[] args) throws ParserConfigurationException,
SAXException {
try {
URL url = new URL(
"http://localhost:8080/CustomerDB/webresources/co.com.mazf.ciudad");
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "application/xml");
if (conn.getResponseCode() != 200) {
throw new RuntimeException("Failed : HTTP error code : "
+ conn.getResponseCode());
}
BufferedReader br = new BufferedReader(new InputStreamReader(
(conn.getInputStream())));
String output;
Ciudades ciudades = new Ciudades();
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null) {
System.out.println("12132312");
System.err.println(output);
DocumentBuilder db = DocumentBuilderFactory.newInstance()
.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(output));
Document doc = db.parse(is);
NodeList nodes = ((org.w3c.dom.Document) doc)
.getElementsByTagName("ciudad");
for (int i = 0; i < nodes.getLength(); i++) {
Ciudad ciudad = new Ciudad();
Element element = (Element) nodes.item(i);
NodeList name = element.getElementsByTagName("idCiudad");
Element element2 = (Element) name.item(0);
ciudad.setIdCiudad(Integer
.valueOf(getCharacterDataFromElement(element2)));
NodeList title = element.getElementsByTagName("nomCiudad");
element2 = (Element) title.item(0);
ciudad.setNombre(getCharacterDataFromElement(element2));
ciudades.getPartnerAccount().add(ciudad);
}
}
for (Ciudad ciudad1 : ciudades.getPartnerAccount()) {
System.out.println(ciudad1.getIdCiudad());
System.out.println(ciudad1.getNombre());
}
conn.disconnect();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
public static String getCharacterDataFromElement(Element e) {
Node child = e.getFirstChild();
if (child instanceof CharacterData) {
CharacterData cd = (CharacterData) child;
return cd.getData();
}
return "";
}
}
Note that the xml structure that I expected in the example was as follows:
<ciudad><idCiudad>1</idCiudad><nomCiudad>BOGOTA</nomCiudad></ciudad>

Look at Jersey. Again, REST is all about the data. And a tutorial here

JAX-RS but you can also use regular DOM that comes with standard Java

From your question its not clear whether you are using any frameworks.For REST you will be getting an WADL & Apache CXF recently added support for WADL-first development of REST services.Please go through http://cxf.apache.org/docs/index.html

You can able to consume a Restful Web service in Spring using RestTemplate.class.
Example :
public class Application {
public static void main(String args[]) {
RestTemplate restTemplate = new RestTemplate();
ResponseEntity<String> call= restTemplate.getForEntity("http://localhost:8080/SpringExample/hello",String.class);
System.out.println(call.getBody())
}
}
Reference

Apache Http Client APIs are very commonly used for calling HTTP Rest services.
Here is one of example of consuming HTTP GET call.
import java.io.IOException;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpUriRequest;
import org.apache.http.impl.client.HttpClientBuilder;
public class CallHTTPGetService {
public static void main(String[] args) throws ClientProtocolException, IOException {
HttpClient client = HttpClientBuilder.create().build();
HttpUriRequest httpUriRequest = new HttpGet("URL");
HttpResponse response = client.execute(httpUriRequest);
System.out.println(response);
}
}
Use following maven dependency if using Maven project.
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.1</version>
</dependency>
<!-- https://mvnrepository.com/artifact/org.apache.httpcomponents/httpmime -->
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpmime</artifactId>
<version>4.5.1</version>
</dependency>

Automate HTML form submission using Java to find grocery hours

I'm trying to automate form submission using Java to get the hours of a grocery store here:
www.giantfood.com
I've posted the query and the hidden miles and storeType fields of the form, but my output.html is just the original web header and footer with an error message in the body. What am I doing wrong?
import java.io.*;
import java.net.*;
public class PostHTML
{
public static void main(String[] args)
{
try
{
URL url = new URL( "http://www.giantfood.com/our_stores/locator/store_search.htm" );
HttpURLConnection hConnection = (HttpURLConnection)
url.openConnection();
HttpURLConnection.setFollowRedirects( true );
hConnection.setDoOutput( true );
hConnection.setRequestMethod("POST");
PrintStream ps = new PrintStream( hConnection.getOutputStream() );
ps.print("groceryStoreAddress=20814&groceryStoreMiles=10&storeType=GROCERY");
ps.close();
hConnection.connect();
if( HttpURLConnection.HTTP_OK == hConnection.getResponseCode() )
{
InputStream is = hConnection.getInputStream();
OutputStream os = new FileOutputStream("output.html");
int data;
while((data=is.read()) != -1)
{
os.write(data);
}
is.close();
os.close();
hConnection.disconnect();
}
}
catch(Exception ex)
{
ex.printStackTrace();
}
}
}
UPDATE
Thanks! Using &'s worked. I'm trying to use HttpClient but I'm getting another error now:
package clientwithresponsehandler;
import org.apache.http.client.ResponseHandler;
import org.apache.http.client.HttpClient;
import org.apache.http.impl.client.BasicResponseHandler;
import org.apache.http.impl.client.DefaultHttpClient;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;
/**
* This example demonstrates the use of the {#link ResponseHandler} to simplify
* the process of processing the HTTP response and releasing associated resources.
*/
public class ClientWithResponseHandler {
public static void main(String[] args) throws Exception {
HttpClient httpclient = new DefaultHttpClient();
try {
HttpPost httpost = new HttpPost("http://www.giantfood.com/our_stores/locator/store_search.htm");
System.out.println("executing request " + httpost.getURI());
List <NameValuePair> nvps = new ArrayList <NameValuePair>();
nvps.add(new BasicNameValuePair("groceryStoreAddress", "20878"));
nvps.add(new BasicNameValuePair("groceryStoreMiles", "10"));
nvps.add(new BasicNameValuePair("storeType", "GROCERY"));
httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));
// Create a response handler
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String responseBody = httpclient.execute(httpost, responseHandler);
System.out.println("----------------------------------------");
System.out.println(responseBody);
System.out.println("----------------------------------------");
} finally {
// When HttpClient instance is no longer needed,
// shut down the connection manager to ensure
// immediate deallocation of all system resources
httpclient.getConnectionManager().shutdown();
}
}
}
Output:
run:
executing request http://www.giantfood.com/our_stores/locator/store_search.htm
Exception in thread "main" org.apache.http.client.HttpResponseException: Moved Temporarily
at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:67)
at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:55)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:945)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:919)
at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:910)
at clientwithresponsehandler.ClientWithResponseHandler.main(ClientWithResponseHandler.java:39)
Java Result: 1
BUILD SUCCESSFUL (total time: 1 second)
I don't understand the Moved Temporarily error.

try to use
ps.print("groceryStoreAddress=20814&groceryStoreMiles=10&storeType=GROCERY")
instead
BTW, it's easier to use some http-library, like Apache HttpClient

Solved the Moved Temporarily by learning about HTML Redirects:
Httpclient 4, error 302. How to redirect?