i'm developing a web application using spring 3. i'm using tomcat 6 as the web container.
in my web.xml file i bound the file named applicationContext.xml as the spring definition file.
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext.xml</param-value>
</context-param>
from inside the applicationContext.xml file i'm trying to initialize a array list variable using the spring bean definition. i'm following the below configurations.. (im using jidea)
<bean id="registationController" class="com.test.RegistrationController">
<property name="registrationService" ref="registrationService"/>
<property name="validUrlsList" ref="myList"/>
</bean>
<util:list id="myList" value-type="java.lang.String">
<value>10.1.200.104</value>
<value>10.1.200.205</value>
</util:list>
i have loaded the
xmlns:util="http://www.springframework.org/schema/util"
namespace, and in RegistrationController.java class i have generated the getter and setter for the validUrlsList variable, jidea shows that my definitions are correct and i have properyly bound my vaiable to the bean definition. but when i try out the code it doesn't initialize the validUrlList variable? it's giving a null value? any thing i'm doing wrong here? any suggestions to sort this out?
java code is as follows.,,
private ArrayList validUrlsList;
public void setValidUrlsList(ArrayList validUrlsList) {
this.validUrlsList = validUrlsList;
}
public ArrayList getValidUrlsList() {
return validUrlsList;
}
then i call the method getRemoteIp by just passing the variable as follows.
if (getRemoteIP(req, validUrlsList)) {
-- Regards,Rangana
util:list is creating java.util.List instance, it is not said to create java.util.ArrayList.
You should change your declaration from
private ArrayList validUrlsList;
to
private List validUrlsList;
(and setter and getter as well).
Related
Consider a web based application with spring 4. The spring bean profiles is defined in web.xml like:
<context-param>
<param-name>spring.profiles.active</param-name>
<param-value>prod,edb,cas</param-value>
</context-param>
Now consider a bean is defined in spring-applicaiton-context.xml as
<util:properties id="myPolicy"
location=
"classpath:/configs/${ACCESS-ACTIVE-PROFILE-SECOND-ITEM}/my-policy.properties" />
Is it possible that I can access the list of active profiles and select the second one (in my example edb). In this way I can make my resource load dynamically when active profile changes.
This may help! I could get the active profile when web application starts with below code:
public void contextInitialized(ServletContextEvent event){
ApplicationContext applicationContext = WebApplicationContextUtils
.getWebApplicationContext(event.getServletContext());
String activeProfiles[] = applicationContext.getEnvironment().getActiveProfiles();
system.out.print(activeProfiles[1])
}
The syntax would be "#{environment.activeProfiles[1]}" - however, it's too early in the context life cycle; the activeProfiles is not set up before the SpEL is evaluated in this case.
What's wrong with
<beans profile="foo">
<util:properties id="myPolicy"
location="classpath:/configs/foo/my-policy.properties" />
</beans>
<beans profile="bar">
<util:properties id="myPolicy"
location="classpath:/configs/bar/my-policy.properties" />
</beans>
?
Actually, I just found that
"#{environment.getActiveProfiles()[1]}"
works - explicitly calling the getter causes the property to be loaded.
I need some help on injecting property value to a bean which is defined outside the web application.
The web application has a property file under src/main/resource.The spring application context xml has the property place holder defined as
<context:property-placeholder
location="classpath:test.properties,file:/etc/test1.properties"
ignore-resource-not-found="true"
/>
where test1.properties is another file which resides outside the application.The bean is injected with the property which is defined in the application (test.properties) ,but I want to inject the property that is defined in test1.properties (ideally the idea is to override the property values from application and read the one defined outside the application).
Thanks.
Hi use like below in applicationContext.xml
<util:properties id="property" location="classpath:test.properties"/>
In Java,
#Autowired
protected Properties property;
I guess this is what you are looking for
<context:property-placeholder location="file:c:/kp/sec.properties" order="1" ignore-resource-not-found="true" ignore-unresolvable="true" />
<context:property-placeholder location="classpath:kp-props.properties" order="2" />
If the file sec.properties exists take the value from sec.properties, if file or properties does not exist take the property from kp-props.properties file from resources directory(if the property is not found in either of place application will fail)
And say you have property my.prop and you can inject the property as follows.
#Component
public class KPProps {
#Value("${my.prop}")
private int props;
public void print(){
System.out.println(props);
}
}
<bean id="configuration" class="com.mypackage.util.Configuration" factory-method="getInstance">
<property name="path" value="${path.props.app.dev}"></property>
</bean>
Then I have the following in my class
Configuration.getInstance();
Whereas the spring application context is loaded in another class Factory like this
private Factory() {
context = new ClassPathXmlApplicationContext("META-INF/spring.xml");
}
The problem is that before Factory class is accessed the context does not load and the configuration object gives null for path whereas when Factory is accessed and after that path property is accessed it gives the correct path.
Please tell me how to do it correctly? That is how can i get my member variable path with correct data without accessing Factory class.
Assuming that you are using Spring WebMVC. There are 2 ways:
Putting you bean configurations to dispatcher config XML (mvc-dispatcher-servlet.xml)
Remain your spring.xml and specify it in web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>spring.xml</param-value>
</context-param>
In both cases, you will no longer need a class like Factory. Besides, because of that Spring creates beans in singleton scope by default, you do not need to implement a getInstance() method for your com.mypackage.util.Configuration class.
I have a class
public class MakeMeBean {
#Autowired private IAmBean var1;
private IAmNOTBean var2;
public MakeMeBean() {}
public MakeMeBean(IAmNOTBean var) {
this.var2 = var;
}
}
I want to make this class as a bean so I make a wireup.xml as
<bean id="make-me-bean" class="com.blah.blah.MakeMeBean">
<constructor-arg index="0" ref=<PUT REFERENCE BEAN HERE>
<constructor-arg index="1" <I don't want to put anything>
</bean>
Question
a.) How can I make a bean in which one instance variable is a bean and another not? I don't want to inject var2(another bean in wireup.xml)
b.) <PUT REFERENCE BEAN HERE> is a bean imported from jar file, how can I make reference to this bean in wireup.xml
You can't just have some beans in context that you created and another half that spring created (at least not that simple), if you want to manage the instances over spring, spring should have the objects on its context. Of course you have the possibility to instantiate the objects in the context, and after the instantiation you could invoke some setters to set some properties.
In order to use another to user another bean, that I suppose comes from another Spring context, the other spring context needs to be imported in the first one. In order to import a context file you can use:
<import resource="resourcePath" />
I Am very new to Spring. I have an Interface (MessageHandler ) which has a get method, this method returns a list of Implementations of another interface (messageChecker).
public interface MessageHandler {
public void process(BufferedReader br);
public void setMessageCheckerList(List mcList);
[B]public List getMessageCheckerList();[/B]
}
In my Spring XML configuration , i have something like this ,along with other beans
<bean id="messageHandler" class="com.XXX.messagereceiver.MessageHandlerImpl">
<property name="messageCheckerList" ref="checkerList"/>
</bean>
<bean id="checkerList" class="java.util.ArrayList">
<constructor-arg>
<list>
<ref bean="HL7Checker"/>
</list>
</constructor-arg>
</bean>
<bean id="HL7Checker" class="com.XXX.messagereceiver.HL7CheckerImpl">
<property name="messageExecutor" ref="kahootzExecutor"/>
</bean>
Here i am passing a checkerlist - which is a list of Implementations ( For now i have only 1) of the Interface (messageChecker)
Checkerlist is containing references to Bean Id's which are actual implementaions.
HL7Checker is an implementation of an Interface messageChecker.
But when i run the main program, When i inject the bean "messageHandler" and call the getMessageCheckerList, It returns a null value. These getter and setter methods are working fine without using spring.
I am not sure what seems to be the problem.
I don't know the answer for you troubles, but I would check:
is the setter setMessageCheckerList(List) in messageHandler bean called? (either using some debugger or some trace output like System.out...). If it's not, there's probably something wrong with your Spring XML configuration setup. The bean definition you posted requires the property to be set and Spring wouldn't create the messageHandler bean without setting the property.
who calls the setMessageCheckerList(List) setter? Or even more precise, what code writes to the field which stores the value of the property? Maybe the field is initialized properly by Spring but gets overwritten to null later on?
are you sure you call the getMessageCheckerList on the very same object Spring has configured for you (that is, the messageHandler bean). The definition you have posted clearly states an instance of MessageHandlerImpl is created by Spring, but it doesn't prevent other instances to be created in other ways. So maybe the instance created by Spring holds the proper value, but you run the get... on a wrong instance?