how to use Runtime.getRuntime() to execute a .java file - java

How to invoke another java program by using Java Runtime.getRuntime.exec()?
its been told for executing a program using java program we can use Runtime.getRuntime().
Here is an example. I can open a notepad by using Runtime.getRuntime().exec("notepad.exe");
Can any one help me to execute a Java file. Thanks in advance!

You can execute a java file like this.
Runtime.getRuntime().exec("java Test");
This is assuming that your environmental variable(Path) for java & classpath have already been set, else you need to set them too!

In fact you can't execute directly a .java file. It needs to be compiled first. The compiling could be done using a System java compiler that can be obtained using ToolProvider and running with Runtime.getRuntime().exec(String). A sample would be something like:
import java.io.FileOutputStream;
import java.io.IOException;
import javax.tools.JavaCompiler;
import javax.tools.ToolProvider;
public class JavaTest {
public static void main(String[] args) throws IOException {
JavaCompiler compiler = ToolProvider.getSystemJavaCompiler();
// creating a file, but you could load an existing one
FileOutputStream javaFile = new FileOutputStream("Test.java");
javaFile.write("public class Test { public static void main(String[] args) { javax.swing.JOptionPane.showMessageDialog(null, \"I'm here!\",\"Test\", 1);}}"
.getBytes());
// compiling it
JavaCompiler compiler = ToolProvider.getSystemJavaCompiler();
compiler.run(null, System.out, System.err, "Test.java");
// running it
Runtime.getRuntime().exec("java Test");
}
}

Related

Jython: Can not import python function in Java

I am trying to develop a simple Java application and I want it to use some Python code using Jython. I am trying to run a python method from a file and getting this error:
ImportError: cannot import name testFunction
Just trying a simple example so I can see where the problem is. My python file test.py is like this:
def testFunction():
print("testing")
And my Java class:
PythonInterpreter interpreter = new PythonInterpreter();
interpreter.exec("path_to_file\\test.py");
interpreter.exec("from test import testFunction");
So it can correctly find the module but behaves like there is no function called testFunction inside.
Execute script files as follows.
interpreter.execfile("path/to/file/test.py");
If you have functions declared in the script file then after executing the above statement you'll have those functions available to be executed from the program as follows.
interpreter.exec("testFunction()");
So, you don't need to have any import statement.
Complete Sample Code:
package jython_tests;
import org.python.util.PythonInterpreter;
public class RunJythonScript2 {
public static void main(String[] args) {
try (PythonInterpreter pyInterp = new PythonInterpreter()) {
pyInterp.execfile("scripts/test.py");
pyInterp.exec("testFunction()");
}
}
}
Script:
def testFunction():
print "testing"
Output:
testing

How to use Java Compile API to compile recursively? [duplicate]

I use the class javax.tools.JavaCompiler (jdk6) to compile a source file, but the source file depends on some jar file. How to set the classpath of the javax.tools.JavaCompiler?
The javax.tools.JavaCompiler#getTask() method takes an options parameter that allows to set compiler options. The following message describes an easy way to set them in order to access the calling program's classpath:
You need to configure the standard
java file manager to know about the
jar files(s) - you use the compiler
options argument to do that.
By default the java compiler object
only seems to know about the default
locations for bootclasspath, extdirs
and endorseddirs directories in terms
of its classpath.
You need to add the calling program's
current classpath to the java compiler
instance's which gets passed on the
the standard file manager, which will
then find classes in the jar files.
Here's how I do it in the compiler
wrapper I wrote
List<String> optionList = new ArrayList<String>();
// set compiler's classpath to be same as the runtime's
optionList.addAll(Arrays.asList("-classpath",System.getProperty("java.class.path")));
// any other options you want
optionList.addAll(Arrays.asList(options));
JavaCompiler.CompilationTask task = compiler.getTask(out,jfm,diagnostics,optionList,null,jfos);
All you'll need then is to get the proper classpath set when running the calling program.
The same problem occurred to me recently, finally I found two workarounds. You can set the class path either by invoke StandardJavaFileManager.setLocation(StandardLocation.CLASS_PATH, "YOUR_CLASS_PATH") or Compiler.getTask(ARG_0, ARG_1, ARG_2, CLASS_PATH_OPTIONS, just as the first answer posted here says.
I needed something simpler than the examples above.
The following is a self-contained example of using the built-in Java compiler, and setting the classpath for the compiler to use.
It is equivalent to creating a source file called HelloPrinter.java and then compiling it as follows:
javac -classpath C:\Users\dab\Testing\a.jar;c:\path\etc org\abc\another\HelloPrinter.java
Note how the classpath can be set using a String[] of options. This should be familiar if you're already used to running javac on the command line (as above).
This code is compatible with Java 6. You will need a JDK, not a JRE, for this to run. This example doesn't actually use the classpath. It all does is print "Hello". You can add an import statement to the generated source and call a method in an external Jar file to test this properly.
import java.io.File;
import java.io.FileOutputStream;
import java.io.PrintStream;
import javax.tools.JavaCompiler;
import javax.tools.ToolProvider;
public class JavaCompilerExample {
public static void main(String[] args) throws Exception {
String className = "HelloPrinter";
String directoryName = "org/abc/another";
new File(directoryName).mkdirs();
FileOutputStream fos = new FileOutputStream(directoryName+"/"+className+".java");
PrintStream ps = new PrintStream(fos);
ps.println(
"package "+directoryName.replace("/", ".") + " ; "
+ "public class " +className +
"{ public static void main(String[] args){System.out.println(\"Hello\");} }");
ps.close();
JavaCompiler javac = ToolProvider.getSystemJavaCompiler();
String javacOpts[] = {"-classpath",
"C:\\Users\\dab\\Testing\\a.jar;c:\\path\\etc;",
directoryName+"/"+className + ".java"};
if ( javac.run(null, null, null, javacOpts)!=0 ) {
System.err.println("Error");
System.exit(1);
}
}
}

Java Packages/Library Functions

I am trying to create a package of library functions for a main Java program but I am have some issues.
I don't know much about about Java packages and I am going through some documentary online.
I have created my directory as such
./Program/Program.java
./Program/TestFunc.java
./Program/classes/library/
The contents of TestFunc.java are
package library;
public class TestFunc {
public void message01() {
System.out.println("called message01");
}
public void message02() {
System.out.println("called message02");
}
}
I compiled it as I read in the documentation
javac -d ./Program/classes TestFunc.java
Which gives me
./Program/classes/library/TestFunc.class
Then I try to call it in Program.java
import library.*;
public class Program {
public static void main(String[] args) {
System.out.println("Starting Script");
}
}
When I try to compile using
javac -d ./Program/classes Program.java
I get the error
package library does not exist
Why is this?
You've used -d which says where to put the output, but you haven't told it that the same directory should also be used for input on the classpath. Use the -cp option for that:
javac -d classes -cp classes Program.java
(It's not clear whether you're trying to do this from inside the Program directory, or above it - your source filename appears to be inside the Program directory, but you're specifying the output directory as if you were in the directory above...)

Why isn't JOptionPane showing up?

I made a simple JOptionPane class that should pop up with a string, when I type:
javac Hellodialog.java
nothing happens at all. No error messages but nothing comes up.
import javax.swing.JOptionPane;
public class Hellodialog
{
public static void main(String[] args)
{
JOptionPane.showMessageDialog(null, "fsdfsdfdsfds");
}
}
compile into a java .class file
javac Hellodialog.java
run the java class
java Hellodialog
You use the javac command to compile your source to byte code, and the java command to run your compiled code.

How to set classpath when I use javax.tools.JavaCompiler compile the source?

I use the class javax.tools.JavaCompiler (jdk6) to compile a source file, but the source file depends on some jar file. How to set the classpath of the javax.tools.JavaCompiler?
The javax.tools.JavaCompiler#getTask() method takes an options parameter that allows to set compiler options. The following message describes an easy way to set them in order to access the calling program's classpath:
You need to configure the standard
java file manager to know about the
jar files(s) - you use the compiler
options argument to do that.
By default the java compiler object
only seems to know about the default
locations for bootclasspath, extdirs
and endorseddirs directories in terms
of its classpath.
You need to add the calling program's
current classpath to the java compiler
instance's which gets passed on the
the standard file manager, which will
then find classes in the jar files.
Here's how I do it in the compiler
wrapper I wrote
List<String> optionList = new ArrayList<String>();
// set compiler's classpath to be same as the runtime's
optionList.addAll(Arrays.asList("-classpath",System.getProperty("java.class.path")));
// any other options you want
optionList.addAll(Arrays.asList(options));
JavaCompiler.CompilationTask task = compiler.getTask(out,jfm,diagnostics,optionList,null,jfos);
All you'll need then is to get the proper classpath set when running the calling program.
The same problem occurred to me recently, finally I found two workarounds. You can set the class path either by invoke StandardJavaFileManager.setLocation(StandardLocation.CLASS_PATH, "YOUR_CLASS_PATH") or Compiler.getTask(ARG_0, ARG_1, ARG_2, CLASS_PATH_OPTIONS, just as the first answer posted here says.
I needed something simpler than the examples above.
The following is a self-contained example of using the built-in Java compiler, and setting the classpath for the compiler to use.
It is equivalent to creating a source file called HelloPrinter.java and then compiling it as follows:
javac -classpath C:\Users\dab\Testing\a.jar;c:\path\etc org\abc\another\HelloPrinter.java
Note how the classpath can be set using a String[] of options. This should be familiar if you're already used to running javac on the command line (as above).
This code is compatible with Java 6. You will need a JDK, not a JRE, for this to run. This example doesn't actually use the classpath. It all does is print "Hello". You can add an import statement to the generated source and call a method in an external Jar file to test this properly.
import java.io.File;
import java.io.FileOutputStream;
import java.io.PrintStream;
import javax.tools.JavaCompiler;
import javax.tools.ToolProvider;
public class JavaCompilerExample {
public static void main(String[] args) throws Exception {
String className = "HelloPrinter";
String directoryName = "org/abc/another";
new File(directoryName).mkdirs();
FileOutputStream fos = new FileOutputStream(directoryName+"/"+className+".java");
PrintStream ps = new PrintStream(fos);
ps.println(
"package "+directoryName.replace("/", ".") + " ; "
+ "public class " +className +
"{ public static void main(String[] args){System.out.println(\"Hello\");} }");
ps.close();
JavaCompiler javac = ToolProvider.getSystemJavaCompiler();
String javacOpts[] = {"-classpath",
"C:\\Users\\dab\\Testing\\a.jar;c:\\path\\etc;",
directoryName+"/"+className + ".java"};
if ( javac.run(null, null, null, javacOpts)!=0 ) {
System.err.println("Error");
System.exit(1);
}
}
}

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