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How to tell Spring to instantiate selected beans without providing constructor args?

Problem:
I'm integrating with a library written by the other team. This library provides a set of classes that I'm using in my Spring-driven application. Every bean in my application is in singleton scope.
Also 99% of the classes from that library uses constructor injection.
I'm using XML and my configuration looks very similar to the following:
<bean id="lib.service1" class="lib.Service1"/>
<bean id="lib.service2" class="lib.Service2">
<constructor-arg ref="lib.service1"/>
</bean>
<bean id="lib.service3" class="lib.Service3">
<constructor-arg ref="lib.service1"/>
</bean>
<bean id="lib.service4" class="lib.Service3">
<constructor-arg ref="lib.service2"/>
<constructor-arg ref="lib.service3"/>
</bean>
<!-- other bean definitions -->
<bean id="lib.serviceN" class="lib.ServiceN">
<constructor-arg ref="lib.serviceX"/>
<constructor-arg ref="lib.serviceY"/>
<constructor-arg ref="lib.serviceZ"/>
<constructor-arg ref="lib.serviceK"/>
</bean>
<!-- other bean definitions -->
What I want:
I want to simplify my configuration to not to use bean IDs and ask spring to do constructor injection for me based on the type of arguments in the bean constructors. I can also ask library implementers to add #Inject annotation to the class constructors (the 99% of the classes have just one public constructor), but this is all that I can ask wrt refactoring of their library.
And eventually I want to have just following in my spring config (doesn't work, but illustrates the idea):
<bean class="lib.Service1"/>
<bean class="lib.Service2"/>
<bean class="lib.Service3"/>
<!-- ... -->
<bean class="lib.ServiceN"/>
Here I'm expecting Spring to figure out that I want to use constructor injection for all those beans and infer bean instances based on the constructor argument types.
Note that I cannot use component scan - they have one package (lib. in the example given above) and some classes in that package are useless for my application and too expensive to be needlessly created. Plus some classes that I'm not using are experimental and can be changed/renamed/removed without prior notice.

Add autowire="constructor", assuming these bean types only have one constructor and that the corresponding parameters match single beans.
<bean class="lib.Service1" autowire="constructor"/>
From the documentation
"constructor"
Analogous to "byType" for constructor arguments. If there
is not exactly one bean of the constructor argument type in the
bean factory, a fatal error is raised. Note that explicit
dependencies, i.e. "property" and "constructor-arg" elements, always
override autowiring. Note: This attribute will not be inherited by
child bean definitions. Hence, it needs to be specified per concrete
bean definition.

Spring annotation component

I'm having some problems understanding how to use annotations, especially with beans.
I have one component
#Component
public class CommonJMSProducer
And I want to use it in another class and i thought I could do that to have a unique object
public class ArjelMessageSenderThread extends Thread {
#Inject
CommonJMSProducer commonJMSProducer;
but commonJMSProducer is null.
In my appContext.xml I have this :
<context:component-scan base-package="com.carnot.amm" />
Thanks

You have to configure Spring to use this autowiring feature:
<context:annotation-config/>
You can find the details of annotation-based config here.
ArjelMessageSenderThread also have to be managed by Spring otherwise it won't tamper with its members since it does not know about it.
OR
if you cannot make it a managed bean then you can do something like this:
ApplicationContext ctx = ...
ArjelMessageSenderThread someBeanNotCreatedBySpring = ...
ctx.getAutowireCapableBeanFactory().autowireBeanProperties(
someBeanNotCreatedBySpring,
AutowireCapableBeanFactory.AUTOWIRE_AUTODETECT, true);
OR
as others pointed out you can use annotations to use dependency injection on objects which are not created by Spring with the #Configurable annotation.

It depends on how you create instances of ArjelMessageSenderThread.
If ArjelMessageSenderThread is a bean that should be created by spring you just have to add #Component (and make sure the package is picked up by the component scan).
However, since you extend Thread, I don't think this should be a standard Spring bean. If you create instances of ArjelMessageSenderThread yourself by using new you should add the #Configurable annotation to ArjelMessageSenderThread. With #Configurable dependencies will be injected even if the instance is not created by Spring. See the documentation of #Configurable for more details and make sure you enabled load time weaving.

I used XML instead of annotations. This seemed difficult for not a big thing. Currently, I just have this more in the xml
<bean id="jmsFactoryCoffre" class="org.apache.activemq.pool.PooledConnectionFactory"
destroy-method="stop">
<constructor-arg name="brokerURL" type="java.lang.String"
value="${brokerURL-coffre}" />
</bean>
<bean id="jmsTemplateCoffre" class="org.springframework.jms.core.JmsTemplate">
<property name="connectionFactory">
<ref local="jmsFactoryCoffre" />
</property>
</bean>
<bean id="commonJMSProducer"
class="com.carnot.CommonJMSProducer">
<property name="jmsTemplate" ref="jmsTemplateCoffre" />
</bean>
And another class to get the bean
#Component
public class ApplicationContextUtils implements ApplicationContextAware {
Thanks anyway

Spring injecting one property dynamically

I am new to Spring and i am stuck with a scenario where i need help.
My Scenario is i have a bean definition for some specific module like this.
<bean name="ruleEngineAction" class="com.xxxxx.yyyy.UserAction" scope="prototype">
<property name="userManager">
<ref bean="userManager" />
</property>
<property name="userDto">
<ref bean="userDto" />
</property>
</bean>
now within this bean i want to use one more property but that depends on the application flow like
<property name="roleManager">
<ref bean="roleManager">
</property>
so should i include this property with in the bean definition itself or i can do it dynamically in code because i don't want this property to be used a lot.
Please suggest me the right and efficient approach.

From what I understood from question, there is only one bean of type roleManager but the usage of roleManager is based on application flow.
In this scenario, I would recommend you to inject roleManager to ruleEngineAction as you would do with any other bean but use the bean only when it is necessary.
It is a bad practice to needless dependency to spring in normal classes like adding reference to applicationContext for fetching the bean dynamically at runtime.

Whether or not, you inject this bean, it'll anyways be created by Spring. Why not just include the property in your UserAction and whether to use it or not, can be decided in your class. No harm in having the bean injected, because you'll anyways use it for some scenarios.
Had the scenario been like, the object won't be created, if you don't inject/use, then it would make sense to consider this situation, but since Spring will create the object anyways, it really shouldn't be a problem to just inject it.

Well you need to add new property with getter and setter in your class com.xxxxx.yyyy.UserAction for roleManager like :
class UserAction {
// your previous properties userManager, userDto, etc.
private RoleManager roleManager; // assuming interface/class as RoleManager for roleManager
// getter and setter for roleManager
// your other action methods which will use roleManager
}

There is no problem if you inject also.Whenever you access that class only it will create the object of that class.

Setting Values of enum via Spring Integration

I have a system where I have an enum of Shops for example. These shows each have their own ShopCommand property (some of which share the same type of command class). from a method in the command class I then want to call send on a Spring Integration gateway. Where I'm confused is how to actually insantiate this gateway in spring. Ideally what I want is to construct the enum via XML configuration with command property being created also in spring, which has the property outGateway set via Spring. I'm not sure if I've made myself very clear with this descrition, if clarification is needed then just ask!

I think this is what you are asking for:
Say I have an enum for ShopType
public enum ShopType {
GROCERY, DEPARTMENT, MALL;
}
Then I have some Store bean that I want to setup via spring configuration. You can instantiate and use the enum like this:
<bean id="DEPTARTMENT_STORE" class="my.package.ShopType" factory-method="valueOf">
<constructor-arg value="DEPARTMENT"/>
</bean>
<bean id="searsStore" class="my.package.Store">
<property name="shopType" ref="DEPTARTMENT_STORE"/>
</bean>
The factory-method points to a static method that is used to create the object. So you can use the enum's method "valueOf" as a factory method.

Spring: Get inline bean by name

I would like to get inner bean by it's name. Is it possible with Spring API?
Right now I'm using such Spring 2.5 API
ConfigurableApplicationContext.getBean(String paramString)
Example of XML:
<bean id="parent" parent="t_Parent">
<property name="items">
<bean id="child" parent="t_Child">
<property name="ABC" value="test"/>
</bean>
</property>
</bean>
I would like to get inner (t_Child) bean by id "child". E.g. ConfigurableApplicationContext.getBean("child"). Spring can't find such bean (because it's inner). At the same time .getBean("parent") works fine.
Any thoughts?

You can't.
From the docs:
A element inside the or elements is used to define a so-called inner bean. An inner bean definition does not need to have any id or name defined, and it is best not to even specify any id or name value because the id or name value simply will be ignored by the container.
If you need it like that, define it as a regular bean.

You can't, but you can create you inner bean outside (so it's no longer an inner bean...) and then reference it inside the property:
<bean id="child" parent="t_Child">
<property name="ABC" value="test"/>
</bean>
<bean id="parent" parent="t_Parent">
<property name="items" ref="child"/>
</bean>

Apart from the other (mostly valid) answers and solutions, I guess the spring way would be to use the BeanWrapper interface:
final BeanWrapper bw =
new BeanWrapperImpl(applicationContext.getBean("parent"));
Object innerBean = bw.getPropertyValue("child");
But I guess that implies that there must be a getter for the property (not only a setter).
Reference:
BeanWrapper (javadoc, 2.5 version)
Bean manipulation and the BeanWrapper (reference, 2.5 version)

If you move up to Spring 3.x, you should be able to do this with the Spring Expression Language. There are examples of directly referencing a bean property from another property (like in link text). The code to do this from Java would be somewhat similar, although I can't find an exact example of this scenario.
However, I would say that if you're trying to use "getBean()", you're doing something wrong. You could just as easily use the SpEL in your context to define a bean or a bean property that references that inner bean.