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convert time(12h and 24h)

I'm writing a program that converts the time (12h and 24h).
The result I want to get is the following:
convertTime ("12:00") ➞ "0:00"
convertTime ("6:20 pm") ➞ "18:20"
convertTime ("21:00") ➞ "9:00 pm"
convertTime ("5:05") ➞ "5:05"
this is my code, unfortunately the result is not what I expected, in fact:
A time input of 12 hours will be indicated with an am or pm suffix.
An input time of 24 hours contains no suffix.
I would appreciate a help so much, thanks in advance!
public static String convertTime(String time) {
String hour = time.substring(0, time.indexOf(":"));
String min = time.substring(3, time.indexOf(":") + 3);
int hourInteger = Integer.parseInt(hour);
if (hourInteger > 12 && hourInteger < 24) {
hourInteger = hourInteger - 12;
}
if (hourInteger == 24) {
hourInteger = 0;
}
if (hourInteger < 12) {
return hourInteger + ":" + min + " AM";
}
if (hourInteger > 12)
return hourInteger + ":" + min + " PM";
return hourInteger;
}

You can use below code snippet, you can make additional changes accordingly as your wish. Using Date API to parse vise versa 12 <-> 24 Hours format.
public static String convertTime(String time) throws ParseException {
if (time.contains("am") || time.contains("pm")) {
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse(time);
return displayFormat.format(date);
} else {
SimpleDateFormat parseFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat displayFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse(time);
return displayFormat.format(date);
}
}

There were few problems with your code.
One is return hourInteger. As the convertTime() return type is String, you can't return an Integer. To convert it you can use,
String.valueOf(hourInteger);
Second in 24h clock format, there is no 24:00. A minute after 23:59 is 00:00. So,
if (hourInteger == 24) {
should be,
if (hourInteger == 0) {
Third,
if (hourInteger > 12 && hourInteger < 24) {
hourInteger = hourInteger - 12;
}
above code will convert all possible hours larger than 12 to hours smaller than 12. So after that line checking if(hourInteger>12) always returns false.
Below code will work for your situation.
public static String convertTime(String time) {
String hour = time.substring(0, time.indexOf(":"));
String min = time.substring(3, time.indexOf(":") + 3);
int hourInteger = Integer.parseInt(hour);
int newHour = hourInteger;
if (hourInteger > 12 && hourInteger < 24) {
newHour = hourInteger - 12;
}
if (hourInteger==0) {
newHour = 12;
}
if (hourInteger < 12) {
return newHour + ":" + min + " AM";
}else {
return newHour + ":" + min + " PM";
}
}

You can use StringTokenizer to split the string into tokens using delimiters : and , then convert based on number of tokens (2 for 24 hour format, 3 for 12 hour format):
import java.util.*;
public class Main
{
public static String convertTime(String time) {
StringTokenizer sb = new StringTokenizer(time, ": ");
if (sb.countTokens() == 2)
{
// 24 hr to 12 hr
int hour = Integer.parseInt(sb.nextToken());
int min = Integer.parseInt(sb.nextToken());
boolean isEvening = false;
if (hour >= 12 && hour <= 24)
{
hour -= 12;
if (hour != 0)
isEvening = true;
}
return String.format("%02d:%02d %s", hour, min, (isEvening ? "pm" : "am"));
}
else if (sb.countTokens() == 3)
{
// 12 hr to 24 hr
int hour = Integer.parseInt(sb.nextToken());
int min = Integer.parseInt(sb.nextToken());
boolean isEvening = sb.nextToken().equalsIgnoreCase("pm");
if (isEvening || hour == 0)
{
hour += 12;
}
return String.format("%02d:%02d", hour, min);
}
return "";
}
public static void main(String[] args) {
System.out.println(convertTime("12:00"));
System.out.println(convertTime("6:20 pm"));
System.out.println(convertTime("21:00"));
System.out.println(convertTime("5:05"));
}
}

Return value based on current month

I'm using this Java code to get price based on month start and end date.
public int getPrice()
{
java.util.Date today = Calendar.getInstance().getTime();
Calendar aumgc = new GregorianCalendar();
aumgc.set(Calendar.AUGUST, 8);
aumgc.set(Calendar.DAY_OF_MONTH, 1);
java.util.Date augustStart = aumgc.getTime();
Calendar emgc = new GregorianCalendar();
emgc.set(Calendar.AUGUST, 8);
emgc.set(Calendar.DAY_OF_MONTH, 31);
java.util.Date augustEnd = emgc.getTime();
Calendar sepmgc = new GregorianCalendar();
sepmgc.set(Calendar.SEPTEMBER, 9);
sepmgc.set(Calendar.DAY_OF_MONTH, 1);
java.util.Date septemberStart = sepmgc.getTime();
Calendar eomgc = new GregorianCalendar();
eomgc.set(Calendar.SEPTEMBER, 9);
eomgc.set(Calendar.DAY_OF_MONTH, 31);
java.util.Date septemberEnd = eomgc.getTime();
Calendar ocmgc = new GregorianCalendar();
ocmgc.set(Calendar.OCTOBER, 10);
ocmgc.set(Calendar.DAY_OF_MONTH, 1);
java.util.Date octoberStart = ocmgc.getTime();
Calendar eocmgc = new GregorianCalendar();
eocmgc.set(Calendar.OCTOBER, 10);
eocmgc.set(Calendar.DAY_OF_MONTH, 31);
java.util.Date octoberEnd = eocmgc.getTime();
if (!(today.before(augustStart) || today.after(augustEnd)))
{
return 30;
}
if (!(today.before(septemberStart) || today.after(septemberEnd)))
{
return 40;
}
if (!(today.before(octoberStart) || today.after(octoberEnd)))
{
return 50;
}
return 0;
}
As you can see I'm using a lot of code to get the price based on current month. How I can simplify the code and use SQL date?
Is there any already made solution implemented in JVM?

I would suggest to use latest API LocalDateTime from Java 8 to do this king of thing, easily :
import java.time.Month; // Enum use in `switch` statement.
public int getPrice() {
LocalDateTime now = LocalDateTime.now(); // line 2
switch (now.getMonth()) { // line 3
case AUGUST:
return 30;
case SEPTEMBER:
return 40;
case OCTOBER:
return 50;
default:
return 0;
}
}
// line 2&3 can be reduce in : // switch (LocalDateTime.now().getMonth()){
This would return the same :
public int getPrice() {
return (LocalDateTime.now().getMonthValue() - 8) * 10 + 30;
}
//or return (LocalDateTime.now().getMonthValue() - 5) * 10;

check if given date time is in scope (+/- 1 hours) of current date time

I have a given date, with the format dd. MMMM yyyy HH:mm 'Uhr'
Now I want to check this date with the current date, checking if its in the scope of +1 hour and -1 hour of the current date time, when its in this scope, the if condition should be statisfied.
I would appreciate it, when someone could help me!
Btw, I have no opportunity to use JODA.

Eric posted in another answer: Here's the link for credit. A rather simple method that get's the time apart using the Calendar class. If anything you can pick it apart to learn a bit about getting the differences between two times.
public static int hoursAgo(String datetime) {
Calendar date = Calendar.getInstance();
date.setTime(new SimpleDateFormat("yyyy/MM/dd HH:mm:ss", Locale.ENGLISH).parse(datetime)); // Parse into Date object
Calendar now = Calendar.getInstance(); // Get time now
long differenceInMillis = now.getTimeInMillis() - date.getTimeInMillis();
long differenceInHours = (differenceInMillis) / 1000L / 60L / 60L; // Divide by millis/sec, secs/min, mins/hr
return (int)differenceInHours;
}

DateFormat format = new SimpleDateFormat("dd. MM yyyy HH:mm");
String dateString= "16. 10 2015 11:05";
Date date = format.parse(dateString);
private static boolean DateInScope(Date date) {
Date currentTime = new Date();
long hours = TimeUnit.MILLISECONDS.toHours(currentTime.getTime());
long hours2 = TimeUnit.MILLISECONDS.toHours(date.getTime());
return hours - 1 == hours2 || hours + 1 == hours2;
}

May be the following method could help you.
public static String getDiffBtwnDates(Date date1, Date date2){
long date1InMillis = date1.getTime();
long date2InMillis;
if (date2==null){
date2InMillis = System.currentTimeMillis();
}else{
date2InMillis = date2.getTime();
}
long dateDiffInMillis = date2InMillis-date1InMillis;
StringBuffer sTimeSince = new StringBuffer("");
if(dateDiffInMillis > YEAR){
if(dateDiffInMillis/YEAR>1){
sTimeSince.append(dateDiffInMillis / YEAR).append(" Years ");
dateDiffInMillis %= YEAR;
}else {
sTimeSince.append(dateDiffInMillis / YEAR).append(" Year ");
dateDiffInMillis %= YEAR;
}
}
if (dateDiffInMillis > DAY) {
if(dateDiffInMillis/DAY > 1){
sTimeSince.append(dateDiffInMillis / DAY).append(" Days ");
dateDiffInMillis %= DAY;
}else {
sTimeSince.append(dateDiffInMillis / DAY).append(" Day ");
dateDiffInMillis %= DAY;
}
}
if (dateDiffInMillis > HOUR) {
if(dateDiffInMillis/HOUR>1){
sTimeSince.append(dateDiffInMillis / HOUR).append(" Hrs ");
dateDiffInMillis %= HOUR;
}else{
sTimeSince.append(dateDiffInMillis / HOUR).append(" Hr ");
dateDiffInMillis %= HOUR;
}
}
if (dateDiffInMillis > MINUTE) {
if (dateDiffInMillis / MINUTE > 1) {
sTimeSince.append(dateDiffInMillis / MINUTE).append(" Mins ");
dateDiffInMillis %= MINUTE;
} else {
sTimeSince.append(dateDiffInMillis / MINUTE).append(" Min ");
dateDiffInMillis %= MINUTE;
}
}
if (dateDiffInMillis > SECOND) {
sTimeSince.append(dateDiffInMillis / SECOND).append(" Sec ");
dateDiffInMillis %= SECOND;
}
sTimeSince.append(dateDiffInMillis + " ms");
sTimeSince.toString();
return sTimeSince.toString();
}

Here is a very simple method that does the exact comparison you need, i did some tests and it seems to work:
package test;
import java.text.SimpleDateFormat;
import java.util.Date;
import java.util.Locale;
public class TestDateDiff {
public static void main(String[] args) throws Exception {
if (isWhitinOneHOur("16. October 2015 16:30")) {
System.out.println("Date OK");
} else {
System.out.println("Date KO");
}
}
public static boolean isWhitinOneHOur(String dateAsStr) throws Exception {
SimpleDateFormat sdf= new SimpleDateFormat("dd. MMMM yyyy HH:mm", Locale.US);
Date date=sdf.parse(dateAsStr);
Date now=new Date();
long oneHour=1000*60*60;
if ((now.getTime()+oneHour)>=date.getTime() && (now.getTime()-oneHour)<=date.getTime()) {
return true;
} else {
return false;
}
}
}

Converting date into text format

How do I convert date into its text format..for ex:if updated today..then instead of date it must show "Today",one day after it must show "Yesterday",and then after two days..it must display the date in general form(//_) on which it was updated..i tried using SimpleDateFormat..but not working..
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
Date d= new Date();
//Convert Date object to string
String strDate = sdf.format(d);
System.out.println("Formated String is " + strDate);
d = sdf.parse("31-12-2009");
Plz help..
Thanks in advance..

Try this:
public class TimeUtils {
public final static long ONE_SECOND = 1000;
public final static long SECONDS = 60;
public final static long ONE_MINUTE = ONE_SECOND * 60;
public final static long MINUTES = 60;
public final static long ONE_HOUR = ONE_MINUTE * 60;
public final static long HOURS = 24;
public final static long ONE_DAY = ONE_HOUR * 24;
private TimeUtils() {
}
/**
* converts time (in milliseconds) to human-readable format
* "<w> days, <x> hours, <y> minutes and (z) seconds"
*/
public static String millisToLongDHMS(long duration) {
StringBuffer res = new StringBuffer();
long temp = 0;
if (duration >= ONE_SECOND) {
temp = duration / ONE_DAY;
if (temp > 0) {
duration -= temp * ONE_DAY;
res.append(temp).append(" day").append(temp > 1 ? "s" : "")
.append(duration >= ONE_MINUTE ? ", " : "");
}
temp = duration / ONE_HOUR;
if (temp > 0) {
duration -= temp * ONE_HOUR;
res.append(temp).append(" hour").append(temp > 1 ? "s" : "")
.append(duration >= ONE_MINUTE ? ", " : "");
}
temp = duration / ONE_MINUTE;
if (temp > 0) {
duration -= temp * ONE_MINUTE;
res.append(temp).append(" minute").append(temp > 1 ? "s" : "");
}
if (!res.toString().equals("") && duration >= ONE_SECOND) {
res.append(" and ");
}
temp = duration / ONE_SECOND;
if (temp > 0) {
res.append(temp).append(" second").append(temp > 1 ? "s" : "");
}
return res.toString();
} else {
return "0 second";
}
}
public static void main(String args[]) {
System.out.println(millisToLongDHMS(123));
System.out.println(millisToLongDHMS((5 * ONE_SECOND) + 123));
System.out.println(millisToLongDHMS(ONE_DAY + ONE_HOUR));
System.out.println(millisToLongDHMS(ONE_DAY + 2 * ONE_SECOND));
System.out.println(millisToLongDHMS(ONE_DAY + ONE_HOUR + (2 * ONE_MINUTE)));
System.out.println(millisToLongDHMS((4 * ONE_DAY) + (3 * ONE_HOUR)
+ (2 * ONE_MINUTE) + ONE_SECOND));
System.out.println(millisToLongDHMS((5 * ONE_DAY) + (4 * ONE_HOUR)
+ ONE_MINUTE + (23 * ONE_SECOND) + 123));
System.out.println(millisToLongDHMS(42 * ONE_DAY));
/*
output :
0 second
5 seconds
1 day, 1 hour
1 day and 2 seconds
1 day, 1 hour, 2 minutes
4 days, 3 hours, 2 minutes and 1 second
5 days, 4 hours, 1 minute and 23 seconds
42 days
*/
}
}

Take a look at the PrettyTime library.

You can check this Comparision of dates

import java.text.SimpleDateFormat;
import java.util.Date;
public class App {
SimpleDateFormat sdf = new SimpleDateFormat("dd-MM-yyyy");
public static long ms, s, m, h, d, w;
static {
ms = 1;
s = ms * 1000;
m = s * 60;
h = m * 60;
d = h * 24;
w = d * 7;
}
public App() {
Date now = new Date();
Date old = new Date();
try {
old = sdf.parse("12-11-2013");
} catch (Exception e) {
e.printStackTrace();
}
long diff = now.getTime() - old.getTime();
if (diff < this.d) {
System.out.println("Today");
}
else if (diff > this.d && diff < this.d*2) {
System.out.println("Yesterday");
}
System.out.println("Difference: " + msToHms(diff));
}
public String msToHms(long ms) {
int seconds = (int) (ms / this.s) % 60 ;
int minutes = (int) ((ms / this.m) % 60);
int hours = (int) ((ms / this.h) % 24);
return String.format("%02d:%02d:%02d", hours, minutes, seconds);
}
public static void main(String[] args) {
new App();
}
}
Output
Yesterday
Difference: 07:11:22

You have to implement your own logic based on the time difference and use the corresponding date format.
Lets assume you are getting a date from a server.
Get the device's time and compare to your date.
For your requirements there will be two cases.
The difference between the two date is less then a day, then return "Today" string.
The difference between the two date is grater then a day then use the Simple Date format to format your date as you want.

For comparing dates please see this entry: datecompare

Check if a given time lies between two times regardless of date

I have timespans:
String time1 = 01:00:00
String time2 = 05:00:00
I want to check if time1 and time2 both lies between 20:11:13 and 14:49:00.
Actually, 01:00:00 is greater than 20:11:13 and less than 14:49:00 considering 20:11:13 is always less than 14:49:00. This is given prerequisite.
So what I want is, 20:11:13 < 01:00:00 < 14:49:00.
So I need something like that:
public void getTimeSpans()
{
boolean firstTime = false, secondTime = false;
if(time1 > "20:11:13" && time1 < "14:49:00")
{
firstTime = true;
}
if(time2 > "20:11:13" && time2 < "14:49:00")
{
secondTime = true;
}
}
I know that this code does not give correct result as I am comparing the string objects.
How to do that as they are the timespans but not the strings to compare?

You can use the Calendar class in order to check.
For example:
try {
String string1 = "20:11:13";
Date time1 = new SimpleDateFormat("HH:mm:ss").parse(string1);
Calendar calendar1 = Calendar.getInstance();
calendar1.setTime(time1);
calendar1.add(Calendar.DATE, 1);
String string2 = "14:49:00";
Date time2 = new SimpleDateFormat("HH:mm:ss").parse(string2);
Calendar calendar2 = Calendar.getInstance();
calendar2.setTime(time2);
calendar2.add(Calendar.DATE, 1);
String someRandomTime = "01:00:00";
Date d = new SimpleDateFormat("HH:mm:ss").parse(someRandomTime);
Calendar calendar3 = Calendar.getInstance();
calendar3.setTime(d);
calendar3.add(Calendar.DATE, 1);
Date x = calendar3.getTime();
if (x.after(calendar1.getTime()) && x.before(calendar2.getTime())) {
//checkes whether the current time is between 14:49:00 and 20:11:13.
System.out.println(true);
}
} catch (ParseException e) {
e.printStackTrace();
}

tl;dr
20:11:13 < 01:00:00 < 14:49:00
LocalTime target = LocalTime.parse( "01:00:00" ) ;
Boolean targetInZone = (
target.isAfter( LocalTime.parse( "20:11:13" ) )
&&
target.isBefore( LocalTime.parse( "14:49:00" ) )
) ;
java.time.LocalTime
The java.time classes include LocalTime to represent a time-of-day only without a date and without a time zone.
So what I want is, 20:11:13 < 01:00:00 < 14:49:00.
First we define the boundaries. Your input strings happen to comply with standard ISO 8601 formats. The java.time classes use ISO 8601 formats by default, so no need to specify a formatting pattern.
LocalTime start = LocalTime.parse( "20:11:13" );
LocalTime stop = LocalTime.parse( "14:49:00" );
And define our test case, the target 01:00:00.
LocalTime target = LocalTime.parse( "01:00:00" );
Now we are set up to compare these LocalTime objects. We want to see if the target is after the later time but before the earlier time. That means middle of the night in this case, between approximately 8 PM and 3 AM the next morning.
Boolean isTargetAfterStartAndBeforeStop = ( target.isAfter( start ) && target.isBefore( stop ) ) ;
That test can be more simply stated as “not between 3 AM and 8 PM”. We could then generalize to any pair of LocalTime objects where we test for between if the start comes before the stop with a 24-hour clock, and not between if start comes after the stop (as in the case of this Question).
Further more, spans of time are usually handled with the Half-Open approach where the beginning is inclusive while the ending is exclusive. So a "between" comparison, strictly speaking, would be “is the target equal to or later than start AND the target is before stop”, or more simply, “is target not before start AND before stop”.
Boolean isBetweenStartAndStopStrictlySpeaking =
( ( ! target.isBefore( start ) && target.isBefore( stop ) ) ;
If the start is after the stop, within a 24-hour clock, then assume we want the logic suggested in the Question (is after 8 PM but before 3 AM).
if( start.isAfter( stop ) ) {
return ! isBetweenStartAndStopStrictlySpeaking ;
} else {
return isBetweenStartAndStopStrictlySpeaking ;
}
About java.time
The java.time framework is built into Java 8 and later. These classes supplant the troublesome old legacy date-time classes such as java.util.Date, Calendar, & SimpleDateFormat.
To learn more, see the Oracle Tutorial. And search Stack Overflow for many examples and explanations. Specification is JSR 310.
The Joda-Time project, now in maintenance mode, advises migration to the java.time classes.
You may exchange java.time objects directly with your database. Use a JDBC driver compliant with JDBC 4.2 or later. No need for strings, no need for java.sql.* classes. Hibernate 5 & JPA 2.2 support java.time.
Where to obtain the java.time classes?
Java SE 8, Java SE 9, Java SE 10, Java SE 11, and later - Part of the standard Java API with a bundled implementation.
Java 9 brought some minor features and fixes.
Java SE 6 and Java SE 7
Most of the java.time functionality is back-ported to Java 6 & 7 in ThreeTen-Backport.
Android
Later versions of Android (26+) bundle implementations of the java.time classes.
For earlier Android (<26), the process of API desugaring brings a subset of the java.time functionality not originally built into Android.
If the desugaring does not offer what you need, the ThreeTenABP project adapts ThreeTen-Backport (mentioned above) to Android. See How to use ThreeTenABP….

The answer given by #kocko works in only same day.
If start time "23:00:00" and end "02:00:00"[next day] and current time is "01:30:00" then result will false...
I modified the #kocko's answer to work perfectly
public static boolean isTimeBetweenTwoTime(String initialTime, String finalTime,
String currentTime) throws ParseException {
String reg = "^([0-1][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$";
if (initialTime.matches(reg) && finalTime.matches(reg) &&
currentTime.matches(reg))
{
boolean valid = false;
//Start Time
//all times are from java.util.Date
Date inTime = new SimpleDateFormat("HH:mm:ss").parse(initialTime);
Calendar calendar1 = Calendar.getInstance();
calendar1.setTime(inTime);
//Current Time
Date checkTime = new SimpleDateFormat("HH:mm:ss").parse(currentTime);
Calendar calendar3 = Calendar.getInstance();
calendar3.setTime(checkTime);
//End Time
Date finTime = new SimpleDateFormat("HH:mm:ss").parse(finalTime);
Calendar calendar2 = Calendar.getInstance();
calendar2.setTime(finTime);
if (finalTime.compareTo(initialTime) < 0)
{
calendar2.add(Calendar.DATE, 1);
calendar3.add(Calendar.DATE, 1);
}
java.util.Date actualTime = calendar3.getTime();
if ((actualTime.after(calendar1.getTime()) ||
actualTime.compareTo(calendar1.getTime()) == 0) &&
actualTime.before(calendar2.getTime()))
{
valid = true;
return valid;
} else {
throw new IllegalArgumentException("Not a valid time, expecting
HH:MM:SS format");
}
}
}
Output
"07:00:00" - "17:30:00" - "15:30:00" [current] - true
"17:00:00" - "21:30:00" - "16:30:00" [current] - false
"23:00:00" - "04:00:00" - "02:00:00" [current] - true
"00:30:00" - "06:00:00" - "06:00:00" [current] - false
(I have included lower limit value to [upper limit value-1])

Modified #Surendra Jnawali' code. It fails
if current time is 23:40:00 i.e greater than start time and less than equals to 23:59:59.
All credit goes to the real owner
This is how it should be :This works perfect
public static boolean isTimeBetweenTwoTime(String argStartTime,
String argEndTime, String argCurrentTime) throws ParseException {
String reg = "^([0-1][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$";
//
if (argStartTime.matches(reg) && argEndTime.matches(reg)
&& argCurrentTime.matches(reg)) {
boolean valid = false;
// Start Time
java.util.Date startTime = new SimpleDateFormat("HH:mm:ss")
.parse(argStartTime);
Calendar startCalendar = Calendar.getInstance();
startCalendar.setTime(startTime);
// Current Time
java.util.Date currentTime = new SimpleDateFormat("HH:mm:ss")
.parse(argCurrentTime);
Calendar currentCalendar = Calendar.getInstance();
currentCalendar.setTime(currentTime);
// End Time
java.util.Date endTime = new SimpleDateFormat("HH:mm:ss")
.parse(argEndTime);
Calendar endCalendar = Calendar.getInstance();
endCalendar.setTime(endTime);
//
if (currentTime.compareTo(endTime) < 0) {
currentCalendar.add(Calendar.DATE, 1);
currentTime = currentCalendar.getTime();
}
if (startTime.compareTo(endTime) < 0) {
startCalendar.add(Calendar.DATE, 1);
startTime = startCalendar.getTime();
}
//
if (currentTime.before(startTime)) {
System.out.println(" Time is Lesser ");
valid = false;
} else {
if (currentTime.after(endTime)) {
endCalendar.add(Calendar.DATE, 1);
endTime = endCalendar.getTime();
}
System.out.println("Comparing , Start Time /n " + startTime);
System.out.println("Comparing , End Time /n " + endTime);
System.out
.println("Comparing , Current Time /n " + currentTime);
if (currentTime.before(endTime)) {
System.out.println("RESULT, Time lies b/w");
valid = true;
} else {
valid = false;
System.out.println("RESULT, Time does not lies b/w");
}
}
return valid;
} else {
throw new IllegalArgumentException(
"Not a valid time, expecting HH:MM:SS format");
}
}
RESULT
Comparing , Start Time /n Thu Jan 01 23:00:00 IST 1970
Comparing , End Time /n Fri Jan 02 02:00:00 IST 1970
Comparing , Current Time /n Fri Jan 02 01:50:00 IST 1970
RESULT, Time lies b/w

Calendar now = Calendar.getInstance();
int hour = now.get(Calendar.HOUR_OF_DAY); // Get hour in 24 hour format
int minute = now.get(Calendar.MINUTE);
Date date = parseDate(hour + ":" + minute);
Date dateCompareOne = parseDate("08:00");
Date dateCompareTwo = parseDate("20:00");
if (dateCompareOne.before( date ) && dateCompareTwo.after(date)) {
//your logic
}
private Date parseDate(String date) {
final String inputFormat = "HH:mm";
SimpleDateFormat inputParser = new SimpleDateFormat(inputFormat, Locale.US);
try {
return inputParser.parse(date);
} catch (java.text.ParseException e) {
return new Date(0);
}
}
Further more, to be more precise,
If you compare a time between an interval more than 00:00 to 24:00 of that day,
you need to parse the day too.

There are lots of answers here but I want to provide a new one which is similar with Basil Bourque's answer but with a full code example. So please see the method below:
private static void checkTime(String startTime, String endTime, String checkTime) {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("HH:mm:ss", Locale.US);
LocalTime startLocalTime = LocalTime.parse(startTime, formatter);
LocalTime endLocalTime = LocalTime.parse(endTime, formatter);
LocalTime checkLocalTime = LocalTime.parse(checkTime, formatter);
boolean isInBetween = false;
if (endLocalTime.isAfter(startLocalTime)) {
if (startLocalTime.isBefore(checkLocalTime) && endLocalTime.isAfter(checkLocalTime)) {
isInBetween = true;
}
} else if (checkLocalTime.isAfter(startLocalTime) || checkLocalTime.isBefore(endLocalTime)) {
isInBetween = true;
}
if (isInBetween) {
System.out.println("Is in between!");
} else {
System.out.println("Is not in between!");
}
}
Either if you are calling this method using:
checkTime("20:11:13", "14:49:00", "01:00:00");
Or using:
checkTime("20:11:13", "14:49:00", "05:00:00");
The result will be:
Is in between!

Following method checks whether 'validateTime' is between 'startTime' & 'endTime' or not while considering possibility that 'endTime' can be a next day. To use it properly parse your dates in "HH:mm" formant.
public static final boolean isBetweenValidTime(Date startTime, Date endTime, Date validateTime)
{
boolean validTimeFlag = false;
if(endTime.compareTo(startTime) <= 0)
{
if(validateTime.compareTo(endTime) < 0 || validateTime.compareTo(startTime) >= 0)
{
validTimeFlag = true;
}
}
else if(validateTime.compareTo(endTime) < 0 && validateTime.compareTo(startTime) >= 0)
{
validTimeFlag = true;
}
return validTimeFlag;
}

Java 8 - LocalDateTime
What about this?
final LocalDateTime now = LocalDateTime.now();
final LocalDateTime minRange = LocalDateTime.of(now.getYear(), now.getMonth(), now.getDayOfMonth(), 22, 30); //Today, 10:30pm
LocalDateTime maxRange = LocalDateTime.of(now.getYear(), now.getMonth(), now.getDayOfMonth(), 6, 30); //Tomorrow, 6:30am
maxRange = maxRange.plusDays(1); //Ensures that you don't run into an exception if minRange is the last day in the month.
if (now.isAfter(minRange) && now.isBefore(maxRange)) {
//Action
}

Using LocalTime would simply ignore the Date value:
public class TimeIntervalChecker {
static final LocalTime time1 = LocalTime.parse( "20:11:13" ) ;
static final LocalTime time2 = LocalTime.parse( "14:49:00" ) ;
public static void main(String[] args) throws java.lang.Exception {
LocalTime nowUtcTime = LocalTime.now(Clock.systemUTC());
if (nowUtcTime.isAfter(time1) && nowUtcTime.isBefore(time2)){
System.out.println(nowUtcTime+" is after: "+ time1+" and before: "+ time2);
}
}

After reading a few replies, I feel the writing is too complicated. Try my code
public static boolean compare(String system_time, String currentTime, String endtimes) {
try {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("HH:mm:ss");
Date startime = simpleDateFormat.parse("19:25:00");
Date endtime = simpleDateFormat.parse("20:30:00");
//current time
Date current_time = simpleDateFormat.parse("20:00:00");
if (current_time.after(startime) && current_time.before(endtime)) {
System.out.println("Yes");
return true;
}
else if (current_time.after(startime) && current_time.after(endtime)) {
return true; //overlap condition check
}
else {
System.out.println("No");
return false;
}
} catch (ParseException e) {
e.printStackTrace();
}
return false;
}

As with the help of #kocko, the complete working code is as below:
try{
Date time11 = new SimpleDateFormat("HH:mm:ss").parse("20:11:13");
Calendar calendar1 = Calendar.getInstance();
calendar1.setTime(time11);
Date time22 = new SimpleDateFormat("HH:mm:ss").parse("14:49:00");
Calendar calendar2 = Calendar.getInstance();
calendar2.setTime(time22);
Date currentTime = new SimpleDateFormat("HH:mm:ss").parse("00:00:00");
Calendar startingCalendar = Calendar.getInstance();
startingCalendar.setTime(currentTime);
startingCalendar.add(Calendar.DATE, 1);
//let's say we have to check about 01:00:00
String someRandomTime = time1;
Date d = new SimpleDateFormat("HH:mm:ss").parse(someRandomTime);
Calendar calendar3 = Calendar.getInstance();
calendar3.setTime(d);
if(startingCalendar.getTime().after(calendar1.getTime()))
{
calendar2.add(Calendar.DATE, 1);
calendar3.add(Calendar.DATE, 1);
}
Date x = calendar3.getTime();
if (x.after(calendar1.getTime()) && x.before(calendar2.getTime()))
{
System.out.println("Time is in between..");
}
else
{
System.out.println("Time is not in between..");
}
} catch (ParseException e)
{
e.printStackTrace();
}

Sounds to me that your problem is an OR situation... You want to check if time1 > 20:11:13 OR time1 < 14:49:00.
There will never be a time greater to 20:11:13 that exceeds your range through the other end (14:49:00) and viceversa. Think of it as if you are checking that a time is NOT between a properly ordered couple of timestamps.

The Actual working function will be as follows
public static boolean isTimeBetweenTwoTime(Date startTime, Date stopTime, Date currentTime) {
//Start Time
Calendar StartTime = Calendar.getInstance();
StartTime.setTime(startTime);
//Current Time
Calendar CurrentTime = Calendar.getInstance();
CurrentTime.setTime(currentTime);
//Stop Time
Calendar StopTime = Calendar.getInstance();
StopTime.setTime(stopTime);
if (stopTime.compareTo(startTime) < 0) {
if (CurrentTime.compareTo(StopTime) < 0) {
CurrentTime.add(Calendar.DATE, 1);
}
StopTime.add(Calendar.DATE, 1);
}
return CurrentTime.compareTo(StartTime) >= 0 && CurrentTime.compareTo(StopTime) < 0;
}

In your case the starting time (20:11:13) is larger than the ending time (14:49:00). It is a reasonable assumption that you could solve the problem by adding a day on the ending time or subtracting a day from the starting time. if you do so, you will be trapped because you do not know on which day the testing time is.
You can avoid this trap by checking whether your testing time is between the ending time and starting time. If true, then result is "not in between"; else result is "well in between".
Here is the function in JAVA I have been using. It works so far for me. Good luck.
boolean IsTimeInBetween(Calendar startC, Calendar endC, Calendar testC){
// assume year, month and day of month are all equal.
startC.set(1,1,1);
endC.set(1,1,1);
testC.set(1,1,1);
if (endC.compareTo(startC) > 0) {
if ((testC.compareTo(startC)>=0) && (testC.compareTo(endC)<=0)) {
return true;
}else {
return false;
}
}else if (endC.compareTo(startC) < 0) {
if ((testC.compareTo(endC) >= 0) && (testC.compareTo(startC) <= 0)) {
return false;
} else {
return true;
}
} else{ // when endC.compareTo(startC)==0, I return a ture value. Change it if you have different application.
return true;
}
}
To create a Calender instance you can use:
Calendar startC = Calendar.getInstance();
startC.set(Calendar.HOUR_OF_DAY, 20);
startC.set(Calendar.MINUTE,11);
startC.set(Calendar.SECOND,13);

In the code snipet below, it is being verified that if the current time (can be any) exists between start and end time or not:
Calendar startTimeCal = Calendar.getInstance();
startTimeCal.setTime(startTime);
int startTimeHour = startTimeCal.get(Calendar.HOUR_OF_DAY);
if (startTimeHour == 0){
startTimeHour = 24;
}
int startTimeMinutes = startTimeCal.get(Calendar.MINUTE);
Calendar curTimeCal = Calendar.getInstance();
curTimeCal.setTime(currentTime);
int curTimeHour = curTimeCal.get(Calendar.HOUR_OF_DAY);
int curTimeMinutes = curTimeCal.get(Calendar.MINUTE);
Calendar endTimeCal = Calendar.getInstance();
endTimeCal.setTime(endTime);
int endTimeHour = endTimeCal.get(Calendar.HOUR_OF_DAY);
if (endTimeHour == 0) {
endTimeHour = 24;
}
int endTimeMinutes = endTimeCal.get(Calendar.MINUTE);
if (((curTimeHour > startTimeHour) || (curTimeHour == startTimeHour && curTimeMinutes >= startTimeMinutes)) &&
((curTimeHour < endTimeHour) || (curTimeHour == endTimeHour && curTimeMinutes <= endTimeHour))) {
//time exists between start and end time
} else {
//time doesn't exist between start and end time
}

As many people noticed, it's not a date problem, it's a logic problem.
Let's assume a day is splitted in two intervals: one lies between 20:11:13 and 14:49:00, while the other lies between 14:49:00 and 20:11:13 (which interval the extremes belong is up to you).
If you want to check if a certain time is included in the 20:11:13/14:49:00 one, the one you're interested of, just check if it's included in the other one, 14:49:00/20:11:13, which is much easier because the natural order of the numbers, and then negate the result.

I did it this way:
LocalTime time = LocalTime.now();
if (time.isAfter(LocalTime.of(02, 00)) && (time.isBefore(LocalTime.of(04, 00))))
{
log.info("Checking after 2AM, before 4AM!");
}
Edit:
String time1 = "01:00:00";
String time2 = "15:00:00";
LocalTime time = LocalTime.parse(time2);
if ((time.isAfter(LocalTime.of(20,11,13))) || (time.isBefore(LocalTime.of(14,49,0))))
{
System.out.println("true");
}
else
{
System.out.println("false");
}

Here is a solution that uses the new Java 8 classes, is compact, requires no regular expressions or manual arithmetic operations. My solution is coded for inclusive startTime and exclusive endTime, but can easily be modified for your needs.
private boolean isTimeBetween(String timeToTest, String startTime, String endTime) {
LocalTime timeToTestDt = LocalTime.parse(timeToTest, DateTimeFormatter.ISO_LOCAL_TIME);
LocalTime startTimeDt = LocalTime.parse(startTime, DateTimeFormatter.ISO_LOCAL_TIME);
LocalTime endTimeDt = LocalTime.parse(endTime, DateTimeFormatter.ISO_LOCAL_TIME);
if(startTime.equals(endTime)) {
return false;
}
else if(startTimeDt.isBefore(endTimeDt)) { // Period does not cross the day boundary
return (timeToTest.equals(startTime) || timeToTestDt.isAfter(startTimeDt))
&& timeToTestDt.isBefore(endTimeDt);
} else { // Time period spans two days, e.g. 23:00 to 2:00
return (!((timeToTestDt.isAfter(endTimeDt) || timeToTest.equals(endTime))
&& timeToTestDt.isBefore(startTimeDt)));
}
}
// getTimeSpans() from the original question would then look like this
public void getTimeSpans()
{
boolean firstTime = isTimeBetween("01:00:00", "20:11:13", "14:49:00");
boolean secondTime = isTimeBetween("05:00:00", "20:11:13", "14:49:00");
}

Simple solution for all gaps:
public boolean isNowTimeBetween(String startTime, String endTime) {
LocalTime start = LocalTime.parse(startTime);//"22:00"
LocalTime end = LocalTime.parse(endTime);//"10:00"
LocalTime now = LocalTime.now();
if (start.isBefore(end))
return now.isAfter(start) && now.isBefore(end);
return now.isBefore(start)
? now.isBefore(start) && now.isBefore(end)
: now.isAfter(start) && now.isAfter(end);
}

I've implemented it in kotlin, and it's works as expected:
fun isInBetween(startTime: String, endTime: String, checkTime: String, timeFormat: String = "HH:mm:ss"): Boolean {
val calendar1 = Calendar.getInstance().apply {
time = SimpleDateFormat(timeFormat, Locale.ENGLISH).parse(startTime)!!
add(Calendar.DATE, 1)
}
val calendar2 = Calendar.getInstance().apply {
time = SimpleDateFormat(timeFormat, Locale.ENGLISH).parse(endTime)!!
add(Calendar.DATE, 1)
}
val calendar3 = Calendar.getInstance().apply {
time = SimpleDateFormat(timeFormat, Locale.ENGLISH).parse(checkTime)!!
add(Calendar.DATE, 1)
}
if(calendar1.time > calendar2.time) {
calendar2.add(Calendar.DATE, 2)
calendar3.add(Calendar.DATE, 2)
}
val x = calendar3.time
return (x.after(calendar1.time) && x.before(calendar2.time))
}
And it's result as followings:
Log.d("TAG", "08:00, 22:00, 13:40: ${isInBetween("08:00", "22:00", "13:40")}") // true
Log.d("TAG", "22:00, 08:00, 13:40: ${isInBetween("22:00", "08:00", "13:40")}") // false
Log.d("TAG", "22:00, 08:00, 05:40: ${isInBetween("22:00", "08:00", "05:40")}") // true
Log.d("TAG", "22:00, 08:00, 10:40: ${isInBetween("22:00", "08:00", "10:40")}") // false
Log.d("TAG", "22:00, 22:00, 22:10: ${isInBetween("22:00", "22:00", "22:10")}") // false

In my situation, I'm not interested at all in date times.
So this is my solution which works solely on hours as integers:
boolean isInTimeRange(int startingHour, int endingHour, int hourOfDayToCheck) {
if (endingHour > startingHour) {
return hourOfDayToCheck >= startingHour && hourOfDayToCheck < endingHour;
} else {
return hourOfDayToCheck >= startingHour || hourOfDayToCheck < endingHour;
}
}

LocalTime now = LocalTime.now();
LocalTime startTime = LocalTime.parse("23:00:00");
LocalTime endTime = LocalTime.parse("05:00:00");
if (startTime.isAfter(endTime)) {
return !(now.isAfter(endTime) && now.isBefore(startTime));
} else {
return (now.isAfter(startTime) && now.isBefore(endTime));
}

The below solution should help in cases where StartTime is from the Previous Day, and EndTime is from the next day, and you want to check something in between.
boolean isInBetween = false;
if (endLocalTime.isAfter(startLocalTime)) {
if (!startLocalTime.isAfter(checkLocalTime) && endLocalTime.isAfter(checkLocalTime)) {
isInBetween = true;
}
} else if (checkLocalTime.isAfter(startLocalTime) || !checkLocalTime.isAfter(endLocalTime)) {
isInBetween = true;
}
return isInBetween;
}

strip colons from the $time, $to and $from strings, convert to int and then use the following condition to check if the time is between from and to. Example is in php, but shouldn't matter.
if(($to < $from && ($time >= $from || $time <= $to)) ||
($time >= $from && $time <= $to)) {
return true;
}

Logically if you do the following you should always be ok granted we use military time...
if start time is greater than end time add 24 to end time
else use times as is
compare current time to be inbetween start and end time.

Based on the ideas and solutions of most authors here, I'd like to share my refined solution with a presumably cleaner code:
/**
* Checks if some date is within a time window given by start and end dates
*
* #param checkDate - date to check if its hours and minutes is between the startDate and endDate
* #param startDate - startDate of the time window
* #param endDate - endDate of the time window
* #return - returns true if hours and minutes of checkDate is between startDate and endDate
*/
public static boolean isDateBetweenStartAndEndHoursAndMinutes(Date checkDate, Date startDate, Date endDate) {
if (startDate == null || endDate == null)
return false;
LocalDateTime checkLdt = LocalDateTime.ofInstant(Instant.ofEpochMilli(checkDate.getTime()), ZoneId.systemDefault());
LocalDateTime startLdt = LocalDateTime.ofInstant(Instant.ofEpochMilli(startDate.getTime()), ZoneId.systemDefault());
LocalDateTime endLdt = LocalDateTime.ofInstant(Instant.ofEpochMilli(endDate.getTime()), ZoneId.systemDefault());
// Table of situations:
// Input dates: start (a), end (b), check (c)
// Interpretations:
// t(x) = time of point x on timeline; v(x) = nominal value of x
// Situation A - crossing midnight:
// c INSIDE
// 1) t(a) < t(c) < t(b) | v(b) < v(a) < v(c) // e.g. a=22:00, b=03:00, c=23:00 (before midnight)
// 2) t(a) < t(c) < t(b) | v(c) < v(b) < v(a) // e.g. a=22:00, b=03:00, c=01:00 (after midnight)
// c OUTSIDE
// 3) t(c) < t(a) < t(b) | v(b) < v(c) < v(a) // e.g. a=22:00, b=03:00, c=21:00
// 4) t(a) < t(b) < t(c) | v(b) < v(c) < v(a) // e.g. a=22:00, b=03:00, c=04:00
// ^--- v(b) < v(a) always when shift spans around midnight!
// Situation B - after/before midnight:
// c INSIDE
// 1) t(a) = t(c) < t(b) | v(a) = v(c) < v(b) // e.g. a=06:00, b=14:00, c=06:00
// 2) t(a) < t(c) < t(b) | v(a) < v(c) < v(b) // e.g. a=06:00, b=14:00, c=08:00
// c OUTSIDE
// 3) t(c) < t(a) < t(b) | v(c) < v(a) < v(b) // e.g. a=06:00, b=14:00, c=05:00
// 4) t(a) < t(b) = t(c) | v(a) < v(b) = v(c) // e.g. a=06:00, b=14:00, c=14:00
// 5) t(a) < t(b) < t(c) | v(a) < v(b) < v(c) // e.g. a=06:00, b=14:00, c=15:00
// ^--- v(a) < v(b) if shift starts after midnight and ends before midnight!
// Check for situation A - crossing midnight?
boolean crossingMidnight = endLdt.isBefore(startLdt);
if (crossingMidnight) {
// A.1
if ((startLdt.isBefore(checkLdt) || startLdt.isEqual(checkLdt)) // t(a) < t(c)
&& checkLdt.isBefore(endLdt.plusDays(1))) // t(c) < t(b+1D)
return true;
// A.2
if (startLdt.isBefore(checkLdt.plusDays(1)) // t(a) < t(c+1D)
&& checkLdt.isBefore(endLdt)) // t(c) < t(b)
return true;
// A.3
if (startLdt.isBefore(endLdt.plusDays(1)) // t(a) < t(b+1D)
&& checkLdt.isBefore(startLdt)) // t(c) < t(a)
return false;
// A.4
if (startLdt.isBefore(endLdt.plusDays(1)) // t(a) < t(b+1D)
&& checkLdt.isAfter(endLdt)) // t(b) < t(c)
return false;
} else {
// B.1 + B.2
if ((startLdt.isEqual(checkLdt) || startLdt.isBefore(checkLdt)) // t(a) = t(c) || t(a) < t(c)
&& checkLdt.isBefore(endLdt)) // t(c) < t(b)
return true;
}
return false;
}
For the sake of completeness I've added the conditions of A.3 and A.4, but in productive code you can leave it out.
Now you can simply create your start and end dates, as well as your time you want to check and call this static method. The code would go then as follows:
Date check = new SimpleDateFormat("HH:mm:ss").parse("01:00:00");
Date start = new SimpleDateFormat("HH:mm:ss").parse("20:11:13");
Date end = new SimpleDateFormat("HH:mm:ss").parse("14:49:00");
if (isDateBetweenStartAndEndHoursAndMinutes(check, start, end)) {
Print("checkDate is within start and End date!"); // adjust this true condition to your needs
}
For the TDD aspect I've added unit tests for the scenarios A and B as given above. Please feel free to check it out and report back if you find any errors or spots for optimization.
import org.junit.jupiter.api.Test;
import java.time.LocalDateTime;
import java.time.ZoneId;
import java.util.Date;
import static org.junit.Assert.assertFalse;
import static org.junit.Assert.assertTrue;
class LogiqDateUtilsTest {
private LocalDateTime startShiftSituationALdt = LocalDateTime.of(0, 1, 1, 22, 0);
private Date startOfShiftSituationA = Date.from(startShiftSituationALdt.atZone(ZoneId.systemDefault()).toInstant());
private LocalDateTime endShiftSituationALdt = LocalDateTime.of(0, 1, 1, 3, 0);
private Date endOfShiftSituationA = Date.from(endShiftSituationALdt.atZone(ZoneId.systemDefault()).toInstant());
private LocalDateTime startShiftSituationBLdt = LocalDateTime.of(0, 1, 1, 6, 0);
private Date startOfShiftSituationB = Date.from(startShiftSituationBLdt.atZone(ZoneId.systemDefault()).toInstant());
private LocalDateTime endShiftSituationBLdt = LocalDateTime.of(0, 1, 1, 14, 0);
private Date endOfShiftSituationB = Date.from(endShiftSituationBLdt.atZone(ZoneId.systemDefault()).toInstant());
#Test
void testSituationA1() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 23, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertTrue(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationA, endOfShiftSituationA));
}
#Test
void testSituationA2() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 1, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertTrue(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationA, endOfShiftSituationA));
}
#Test
void testSituationA3() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 21, 1);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertFalse(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationA, endOfShiftSituationA));
}
#Test
void testSituationA4() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 4, 1);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertFalse(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationA, endOfShiftSituationA));
}
#Test
void testSituationB1() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 6, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertTrue(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationB, endOfShiftSituationB));
}
#Test
void testSituationB2() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 8, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertTrue(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationB, endOfShiftSituationB));
}
#Test
void testSituationB3() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 5, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertFalse(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationB, endOfShiftSituationB));
}
#Test
void testSituationB4() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 14, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertFalse(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationB, endOfShiftSituationB));
}
#Test
void testSituationB5() {
LocalDateTime checkLdt = LocalDateTime.of(0, 1, 1, 15, 0);
Date checkBetween = Date.from(checkLdt.atZone(ZoneId.systemDefault()).toInstant());
assertFalse(isDateBetweenStartAndEndHoursAndMinutes(checkBetween, startOfShiftSituationB, endOfShiftSituationB));
}
}
Cheers!

/**
* #param initialTime - in format HH:mm:ss
* #param finalTime - in format HH:mm:ss
* #param timeToCheck - in format HH:mm:ss
* #return initialTime <= timeToCheck < finalTime
* #throws IllegalArgumentException if passed date with wrong format
*/
public static boolean isTimeBetweenTwoTime(String initialTime, String finalTime, String timeToCheck) throws IllegalArgumentException {
String reg = "^([0-1][0-9]|2[0-3]):([0-5][0-9]):([0-5][0-9])$";
if (initialTime.matches(reg) && finalTime.matches(reg) && timeToCheck.matches(reg)) {
SimpleDateFormat dateFormat = new SimpleDateFormat("HH:mm:ss", Locale.getDefault());
Date inTime = parseDate(dateFormat, initialTime);
Date finTime = parseDate(dateFormat, finalTime);
Date checkedTime = parseDate(dateFormat, timeToCheck);
if (finalTime.compareTo(initialTime) < 0) {
Calendar calendar = Calendar.getInstance();
calendar.setTime(finTime);
calendar.add(Calendar.DAY_OF_YEAR, 1);
finTime = calendar.getTime();
if (timeToCheck.compareTo(initialTime) < 0) {
calendar.setTime(checkedTime);
calendar.add(Calendar.DAY_OF_YEAR, 1);
checkedTime = calendar.getTime();
}
}
return (checkedTime.after(inTime) || checkedTime.compareTo(inTime) == 0) && checkedTime.before(finTime);
} else {
throw new IllegalArgumentException("Not a valid time, expecting HH:MM:SS format");
}
}
/**
* #param initialTime - in format HH:mm:ss
* #param finalTime - in format HH:mm:ss
* #return initialTime <= now < finalTime
* #throws IllegalArgumentException if passed date with wrong format
*/
public static boolean isNowBetweenTwoTime(String initialTime, String finalTime) throws IllegalArgumentException {
return isTimeBetweenTwoTime(initialTime, finalTime,
String.valueOf(DateFormat.format("HH:mm:ss", new Date()))
);
}
private static Date parseDate(SimpleDateFormat dateFormat, String data) {
try {
return dateFormat.parse(data);
} catch (ParseException e) {
throw new IllegalArgumentException("Not a valid time");
}
}

This worked for me:
fun timeBetweenInterval(
openTime: String,
closeTime: String
): Boolean {
try {
val dateFormat = SimpleDateFormat(TIME_FORMAT)
val afterCalendar = Calendar.getInstance().apply {
time = dateFormat.parse(openTime)
add(Calendar.DATE, 1)
}
val beforeCalendar = Calendar.getInstance().apply {
time = dateFormat.parse(closeTime)
add(Calendar.DATE, 1)
}
val current = Calendar.getInstance().apply {
val localTime = dateFormat.format(timeInMillis)
time = dateFormat.parse(localTime)
add(Calendar.DATE, 1)
}
return current.time.after(afterCalendar.time) && current.time.before(beforeCalendar.time)
} catch (e: ParseException) {
e.printStackTrace()
return false
}
}

Based on Konstantin_Yovkov answer I would like to share my implementation which checks if current time will be in between given START and END time.
This implementation assumes that if given END time is 'before' the START time, then END must be meant to be tomorrow:
public static boolean currentTimeInBetween(String start, String end)
throws ParseException {
// start = "15:25";
java.util.Date starttime = new SimpleDateFormat("HH:mm").parse(start);
Calendar startcal = Calendar.getInstance();
startcal.setTime(starttime);
// end = "14:00";
java.util.Date endtime = new SimpleDateFormat("HH:mm").parse(end);
Calendar endcal = Calendar.getInstance();
endcal.setTime(endtime);
DateFormat dateFormat = new SimpleDateFormat("HH:mm:ss");
java.util.Date currenttime = dateFormat
.parse(dateFormat.format(new java.util.Date()));
Calendar currentcal = Calendar.getInstance();
currentcal.setTime(currenttime);
// If endTime < startTime, assume that endTime is 'tomorrow'
if (startcal.after(endcal)) {
endcal.add(Calendar.DATE, 1);
}
// System.out.println("START" + " System Date: " + startcal.getTime());
// System.out.println("END" + " System Date: " + endcal.getTime());
// System.out.println("Current" + " System Date: " + currentcal.getTime());
java.util.Date current = currentcal.getTime();
if (current.after(startcal.getTime())
&& current.before(endcal.getTime())) {
return true;
} else {
return false;
}
}

Solution function written in Kotlin
/**
* #param currentTime : Time to compare
* #param startTime: Start Hour in format like 10:00:00
* #param endTime: End Hour in format like 15:45:00
*/
fun isTimeInBetweenHours(currentDate: Date, startTime: String, endTime: String): Boolean {
val simpleDateFormat = SimpleDateFormat("HH:mm:ss", Locale.US)
try {
val startTimeCalendar = Calendar.getInstance()
startTimeCalendar.time = simpleDateFormat.parse(startTime)
startTimeCalendar.add(Calendar.DATE, 1)
val endTimeCalendar = Calendar.getInstance()
endTimeCalendar.time = simpleDateFormat.parse(endTime)
endTimeCalendar.add(Calendar.DATE, 1)
val currentTime = simpleDateFormat.format(currentDate) //"01:00:00"
val currentTimeCalendar = Calendar.getInstance()
currentTimeCalendar.time = simpleDateFormat.parse(currentTime)
currentTimeCalendar.add(Calendar.DATE, 1)
val x = currentTimeCalendar.time
return x.after(startTimeCalendar.time) && x.before(endTimeCalendar.time)
} catch (e: ParseException) {
return false
}
}
The formatter only takes HH:mm:ss, so it's agnostic of date. All the dates are computed as 1st Jan 1970 being the epoch start date. Hence the comparison of time happens with only the time as the date for all the cases here is 1st Jan 1970.
Note: Used legacy Java API's instead of the newer ones (LocalTime and DateTimeFormatter) since these newer API's are not supported on older devices like Android below version Oreo. If you are using some other platform where you can get the updated API's, please use them as they are more optimised and less buggy.