Java Interfaces -- why not have private methods? - java

Why are methods on interfaces always public? Why can't they be private?

Because all methods on an interface are public. That's the point in having the interface -- technically it defines a contract for your class (which may have many, overlapping, contracts/interfaces). The client of your class should hold a reference to the interface and have access only to the class' published (public) methods through the interface.

I infer that you are referring to an interface declared thusly:
public interface MyInter
{
public void myFunc();
}
And the resulting error if you omit the public qualifier in your implementation:
MyClass.java:3: myFunc() in MyClass cannot implement myFunc() in MyInter; attempting to assign weaker access privileges; was public
void myFunc(){}
^
Say you could make myFunc private. You write the following code in a different class. This should complain about you trying to use a private function you didn't have access to:
MyClass foo = new MyClass();
foo.myFunc(); // Declared private, can't call it.
But what about this:
void doSomething(MyInter foo)
{
foo.myFunc(); // Declared public in interface, private in implementation.
}
Can we do this? According to the interface it's a public method so we should be good to go. But it's implemented as a private method so the class expects it never to be called from the outside like this, a restriction that should be enforced by the compiler. But the compiler doesn't even need to know about MyClass for this to compile. It could not even be written yet, or in an external library that may or may not ever be integrated.
Allowing implementations creates an internal inconsistency in the rules of allowable access, and the resolution to that inconsistency is to disallow the situation altogether. Anything that can call a method in an interface must be able to call it in any implementation.
The same argument holds true for overriding subclass methods. You can't "hide" them by overriding with more restrictive qualifiers.

Why is it so?
Because the JLS says so:
In the Chapter on interface declarations, JLS 9.4 says: "Every method declaration in the body of an interface is implicitly public."
In the Chapter on class declarations, JLS 8.4.8.3 says: "The access modifier (§6.6) of an overriding or hiding method must provide at least as much access as the overridden or hidden method, ..."
Engineer Dollery's answer explains why the language is designed this way.

Related

java : interface as input parameter in itself

The title is not quite clear, but I didn't see how to explain it in a short sentence.
I have an interface myInterface (This must be an interface, not an abstract, because enum will implement it).
I expect to have an attribute myAttribute (integer) which is not reachable from outside, except for the derivated classes from the interface (protected).
I want a method myMethod that contans myInterface as input parameter. But then, I have trouble when I try to implement it.
The method looks like this
boolean myMethod(myInterface interface)
{
return this.myAttribute>interface.myAttribute;
}
I can't define "myAttribute" as protected in "myInterface".
If I don't define "myAttribute" in "myInterface", I can't use it in the definition of myMethod, when I implement it in my derivated class : The signature should contain "myInterface" as input parameter, and this one doesn't have any "myAttribute" attribute.
The only solution I have now is to cast "myInterface" in its derivate, but I don't like it (Globally, I don't like casts). Does anyone has another idea?
You cannot.
Interfaces can only define (implicitly) public static final variables, otherwise said, public constants.
What you should do is define a method returning your attribute in your interface, which in turn, its implementing classes will be forced to implement (if they're not abstract).
The method will be implicitly public.
This will also enforce the encapsulation of the variable within the implementing classes.
You can then retrieve the value by virtually invoking the getter method on the interface: myInterface.getMyAttribute().
Edit
If your scope is to not be able to access the value an instance field outside classes that implement a common interface at all, you can proxy you hierarchy by having an abstract class in between the interface and your implementing classes.
In turn, the abstract class would implement none of the interface methods (hence still forcing the concrete classes to implement all), but instead feature a protected attribute that the concrete classes would all have access to.
Finally the concrete classes could decide whether or not to let other classes access that field.

Why a method must be public?

Consider the following classes:
class A {
void print() {
System.out.println("A");
}
}
class B extends A implements C {
}
public interface C {
void print();
}
I get this error:
The inherited method A.print() cannot hide the public abstract method
in C
Now, I understand that print() must be public in order the eliminate the compilation error, but what's the reason behind this?
The answer is simple interface methods are always public or else just use composition instead of inheritance. Also to note that while overriding a method you can not narrow down the access level of the method.
The Oracle Docs says:
The access modifier public (§6.6) pertains to every kind of interface
declaration.
B#print can never be truly private, because anyone can call it via the interface:
B b = new B();
C c = b;
c.print();
Java doesn't let you pretend it's private when it is effectively public. (C++ does; different languages make different trade-offs.)
The method void print() in class A is implementation for the interface method declaration. Now , in the interface C this method is public ( every interface method is public by default ) and the rules of OOP ( Liskov principle in particular ) dictates that the visibility of this method's implementation in class A cannot be lower than that in its interface - hence it has to be public.
Short answer is because Java doesn't allow it. According to the Java Language Specification under 9.1.1. Interface Modifiers - JLS-9.1.1,
The access modifier public (§6.6) pertains to every kind of interface declaration.
The access modifiers protected and private pertain only to member interfaces within a directly enclosing class or enum declaration (§8.5.1).
So if you don't specify an access modifier in your non-member interface (like void print()) it is public and your class which implements that interface must provide a public void print().
Well, think it this way: if an interface defined private methods then these methods would only be called by the class implementing the interface, and that doesn't make much sense, since (in Java) an interface defines the contracts between classes. When a class follows an interface then the methods defined in the interface can be called in the implementation by external classes.
In your case, your class B is extending A while class A is not implementing the interface C. So, by extending A it inherits a method that has less access than the one defined in the interface, and that is not allowed.
If your class A had implemented the interface you would have seen the error "Cannot reduce the visibility of the inherited method from C"
All the methods in an interface are implicitly public. The names and return types of the methods(the ones B inherits from A and C) are same in your case but the visibility modifiers are different. And if you change the visibility modifier of an inherited method the compiler will complain because you cannot reduce the visibility of an inherited member.

Why can't constructors be final, static, or abstract?

Why can't constructors be final, static, or abstract in Java?
For instance, can you explain to me why this is not valid?
public class K {
abstract public K() {
// ...
}
}
When you set a method as final it means: "I don't want any class override it." But according to the Java Language Specification:
JLS 8.8 - "Constructor declarations are not members. They are never inherited and therefore are not subject to hiding or overriding."
When you set a method as abstract it means: "This method doesn't have a body and it should be implemented in a child class." But the constructor is called implicitly when the new keyword is used so it can't lack a body.
When you set a method as static it means: "This method belongs to the class, not a particular object." But the constructor is implicitly called to initialize an object, so there is no purpose in having a static constructor.
The question really is why you want constructor to be static or abstract or final.
Constructors aren't inherited so can't be overridden so whats the use
to have final constructor
Constructor is called automatically when an instance of the class is
created, it has access to instance fields of the class. What will be
the use of a static constructor.
Constructor can't be overridden so what will you do with an abstract
constructor.
A Java constructor is implicitly final, the static / non-static aspects of its semantics are implicit1, and it is meaningless for a Java constructor to be abstract.
This means that the final and static modifiers would be redundant, and the abstract keyword would have no meaning at all.
Naturally, the Java designers didn't see in any point in allowing redundant and/or meaningless access modifiers on constructors ... so these are not allowed by the Java grammar.
Aside: It is a shame that they didn't make the same design call for interface methods where the public and abstract modifiers are also redundant, but allowed anyway. Perhaps there is some (ancient) historical reason for this. But either way, it cannot be fixed without rendering (probably) millions of existing Java programs uncompilable.
1 - Actually, constructors have a mixture of static and non-static semantics. You can't "call" a constructor on an instance, and it they are not inherited, or overridable. This is similar to the way static methods work. On the other hand, the body of a constructor can refer to this, and call instance methods ... like an instance method. And then there is constructor chaining, which is unique to constructors. But the real point is that these semantics are fixed, and there is no point allowing a redundant and probably confusing static modifier.
public constructor: Objects can be created anywhere.
default constructor: Objects can be created only in the same package.
protected constructor: Objects can be created by classes outside the package only if it's a subclass.
private constructor: Object can only be created inside the class (e.g., when implementing a singleton).
The static, final and abstract keywords are not meaningful for a constructor because:
static members belong to a class, but the constructor is needed to create an object.
An abstract class is a partially implemented class, which contains abstract methods to be implemented in child class.
final restricts modification: variables become constant, methods can't be overridden, and classes can't be inherited.
Final: Because you can't overwrite/extend a constructor anyway. You can extend a class (to prevent that you make it final) or overwrite a method (to prevent that you make it final), but there is nothing like this for constructors.
Static: If you look at the execution a constructor is not static (it can access instance fields), if you look at the caller side it is (kind of) static (you call it without having an instance. Its hard to imagine a constructor being completely static or not static and without having a semantic separation between those two things it doesn't make sense to distinguish them with a modifier.
Abstract: Abstract makes only sense in the presence of overwriting/extension, so the same argument as for 'final' applies
No Constructors can NEVER be declared as final. Your compiler will always give an error of the type "modifier final not allowed"
Final, when applied to methods, means that the method cannot be overridden in a subclass.
Constructors are NOT ordinary methods. (different rules apply)
Additionally, Constructors are NEVER inherited. So there is NO SENSE in declaring it final.
Constructors are NOT ordinary methods. (different rules apply)
Additionally, Constructors are NEVER inherited. So there is NO SENSE in declaring it final.
No Constructors can NEVER be declared final. YOur compiler will always give an error of the type "modifer final not allowed"
Check the JLS Section 8.8.3 (The JLS & API docs should be some of your primary sources of information).
JLS section 8 mentions this.
Constructors (§8.8) are similar to methods, but cannot be invoked
directly by a method call; they are used to initialize new class
instances. Like methods, they may be overloaded (§8.8.8).
But constructors per say are not regular methods. They can't be compared as such.
why constructor can not be static and final are well defined in above answers.
Abstract: "Abstract" means no implementation . and it can only be implemented via inheritance. So when we extends some class, all of parent class members are inherited in sub-class(child class) except "Constructor". So, lets suppose, you some how manage to declare constructor "Abstract", than how can you give its implementation in sub class, when constructor does not get inherit in child-class?
that's why constructor can't be
abstract .
lets see first
final public K(){
*above the modifier final is restrict 'cause if it final then some situation where in some other class or same class only we will override it so thats not gonna happen here proximately not final
eg:
we want public void(int i,String name){
//this code not allowed
let static,, static itz all about class level but we create the object based constructor by using 'new' keyword so,,,,,, thatsall
abstract itz worst about here not at 'cause not have any abstract method or any declared method
Unfortunately in PHP the compiler does not raise any issue for both abstract and final constructor.
<?php
abstract class AbstractClass
{
public abstract function __construct();
}
class NormalClass
{
public final function __construct() {
echo "Final constructor in a normal class!";
}
}
In PHP static constructor is not allowed and will raise fatal exception.
Here in AbstractClass obviously a constructor either can be declared as abstract plus not implemented or it can be declared as something among (final, public, private, protected) plus a function body.
Some other related facts on PHP:
In PHP having multiple constructor __construct() is not possible.
In PHP a constructor __construct() can be declared as abstract, final, public, private and protected!
This code was tested and stood true for in PHP versions from 5.6 up to 7.4!

Why are all fields in an interface implicitly static and final?

I am just trying to understand why all fields defined in an Interface are implicitly static and final. The idea of keeping fields static makes sense to me as you can't have objects of an interface but why they are final (implicitly)?
Any one knows why Java designers went with making the fields in an interface static and final?
An interface is intended to specify an interaction contract, not implementation details. A developer should be able to use an implementation just by looking at the interface, and not have to look inside the class which implements it.
An interface does not allow you to create an instance of it, because you cannot specify constructors. So it cannot have instance state, although interface fields can define constants, which are implicitly static and final.
You cannot specify method bodies or initializer blocks in an interface, although since Java 8 you can specify default methods with bodies. This feature is intended to allow new methods to be added to existing interfaces without having to update all the implementations. But you still cannot execute such a method, without first creating an instance implementing the interface.
Aside: Note that you can implement an interface with an anonymous inner class:
interface Foo {
String bar();
}
class FooBar {
Foo anonymous = new Foo() {
public String bar() {
return "The Laundromat Café";
};
}
You have to provide the full implementation of the interface for the anonymous inner class to compile.
new Foo() is initializing the anonymous inner class with its default constructor.
Reason for being final
Any implementations can change value of fields if they are not defined as final. Then they would become a part of the implementation. An interface is a pure specification without any implementation.
Reason for being static
If they are static, then they belong to the interface, and not the object, nor the run-time type of the object.
There are a couple of points glossed over here:
Just because fields in an interface are implicitly static final does not mean they must be compile-time constants, or even immutable. You can define e.g.
interface I {
String TOKEN = SomeOtherClass.heavyComputation();
JButton BAD_IDEA = new JButton("hello");
}
(Beware that doing this inside an annotation definition can confuse javac, relating to the fact that the above actually compiles to a static initializer.)
Also, the reason for this restriction is more stylistic than technical, and a lot of people would like to see it be relaxed.
The fields must be static because they can't be abstract (like methods can). Because they can't be abstract, the implementers will not be able to logically provide the different implementation of the fields.
The fields must be final, I think, because the fields may be accessed by many different implementers allows they to be changeable might be problematic (as synchronization). Also to avoid it to be re-implemented (hidden).
Just my thought.
I consider the requirement that the fields be final as unduly restrictive and a mistake by the Java language designers. There are times, e.g. tree handling, when you need to set constants in the implementation which are required to perform operations on an object of the interface type. Selecting a code path on the implementing class is a kludge. The workaround which I use is to define an interface function and implement it by returning a literal:
public interface iMine {
String __ImplementationConstant();
...
}
public class AClass implements iMine {
public String __ImplementationConstant(){
return "AClass value for the Implementation Constant";
}
...
}
public class BClass implements iMine {
public String __ImplementationConstant(){
return "BClass value for the Implementation Constant";
}
...
}
However, it would be simpler, clearer and less prone to aberrant implementation to use this syntax:
public interface iMine {
String __ImplementationConstant;
...
}
public class AClass implements iMine {
public static String __ImplementationConstant =
"AClass value for the Implementation Constant";
...
}
public class BClass implements iMine {
public static String __ImplementationConstant =
"BClass value for the Implementation Constant";
...
}
Specification, contracts... The machine instruction for field access uses object address plus field offset. Since classes can implement many interfaces, there is no way to make non-final interface field to have the same offset in all classes that extend this interface. Therefore different mechanism for field access must be implemented: two memory accesses (get field offset, get field value) instead of one plus maintaining kind of virtual field table (analog of virtual method table). Guess they just didn't want to complicate jvm for functionality that can be easily simulated via existing stuff (methods).
In scala we can have fields in interfaces, though internally they are implemented as I explained above (as methods).
static:
Anything (variable or method) that is static in Java can be invoked as Classname.variablename or Classname.methodname or directly. It is not compulsory to invoke it only by using object name.
In interface, objects cannot be declared and static makes it possible to invoke variables just through class name without the need of object name.
final:
It helps to maintain a constant value for a variable as it can't be overridden in its subclasses.

Why no static methods in Interfaces, but static fields and inner classes OK? [pre-Java8] [duplicate]

This question already has answers here:
Why can't I define a static method in a Java interface?
(24 answers)
Closed 3 years ago.
There have been a few questions asked here about why you can't define static methods within interfaces, but none of them address a basic inconsistency: why can you define static fields and static inner types within an interface, but not static methods?
Static inner types perhaps aren't a fair comparison, since that's just syntactic sugar that generates a new class, but why fields but not methods?
An argument against static methods within interfaces is that it breaks the virtual table resolution strategy used by the JVM, but shouldn't that apply equally to static fields, i.e. the compiler can just inline it?
Consistency is what I desire, and Java should have either supported no statics of any form within an interface, or it should be consistent and allow them.
An official proposal has been made to allow static methods in interfaces in Java 7. This proposal is being made under Project Coin.
My personal opinion is that it's a great idea. There is no technical difficulty in implementation, and it's a very logical, reasonable thing to do. There are several proposals in Project Coin that I hope will never become part of the Java language, but this is one that could clean up a lot of APIs. For example, the Collections class has static methods for manipulating any List implementation; those could be included in the List interface.
Update: In the Java Posse Podcast #234, Joe D'arcy mentioned the proposal briefly, saying that it was "complex" and probably would not make it in under Project Coin.
Update: While they didn't make it into Project Coin for Java 7, Java 8 does support static functions in interfaces.
I'm going to go with my pet theory with this one, which is that the lack of consistency in this case is a matter of convenience rather than design or necessity, since I've heard no convincing argument that it was either of those two.
Static fields are there (a) because they were there in JDK 1.0, and many dodgy decisions were made in JDK 1.0, and (b) static final fields in interfaces are the closest thing java had to constants at the time.
Static inner classes in interfaces were allowed because that's pure syntactic sugar - the inner class isn't actually anything to do with the parent class.
So static methods aren't allowed simply because there's no compelling reason to do so; consistency isn't sufficiently compelling to change the status quo.
Of course, this could be permitted in future JLS versions without breaking anything.
There is never a point to declaring a static method in an interface. They cannot be executed by the normal call MyInterface.staticMethod(). (EDIT:Since that last sentence confused some people, calling MyClass.staticMethod() executes precisely the implementation of staticMethod on MyClass, which if MyClass is an interface cannot exist!) If you call them by specifying the implementing class MyImplementor.staticMethod() then you must know the actual class, so it is irrelevant whether the interface contains it or not.
More importantly, static methods are never overridden, and if you try to do:
MyInterface var = new MyImplementingClass();
var.staticMethod();
the rules for static say that the method defined in the declared type of var must be executed. Since this is an interface, this is impossible.
You can of course always remove the static keyword from the method. Everything will work fine. You may have to suppress some warnings if it is called from an instance method.
To answer some of the comments below, the reason you can't execute "result=MyInterface.staticMethod()" is that it would have to execute the version of the method defined in MyInterface. But there can't be a version defined in MyInterface, because it's an interface. It doesn't have code by definition.
The purpose of interfaces is to define a contract without providing an implementation. Therefore, you can't have static methods, because they'd have to have an implementation already in the interface since you can't override static methods. As to fields, only static final fields are allowed, which are, essentially, constants (in 1.5+ you can also have enums in interfaces). The constants are there to help define the interface without magic numbers.
BTW, there's no need to explicitly specify static final modifiers for fields in interfaces, because only static final fields are allowed.
This is an old thread , but this is something very important question for all. Since i noticed this today only so i am trying to explain it in cleaner way:
The main purpose of interface is to provide something that is unimplementable, so if they provide
static methods to be allowed
then you can call that method using interfaceName.staticMethodName(), but this is unimplemented method and contains nothing. So it is useless to allow static methods. Therefore they do not provide this at all.
static fields are allowed
because fields are not implementable, by implementable i mean you can not perform any logical operation in field, you can do operation on field. So you are not changing behavior of field that is why they are allowed.
Inner classes are allowed
Inner classes are allowed because after compilation different class file of the Inner class is created say InterfaceName$InnerClassName.class , so basically you are providing implementation in different entity all together but not in interface. So implementation in Inner classes is provided.
I hope this would help.
Actually sometimes there are reasons someone can benefit from static methods. They can be used as factory methods for the classes that implement the interface. For example that's the reason we have Collection interface and the Collections class in openjdk now. So there are workarounds as always - provide another class with a private constructor which will serve as a "namespace" for the static methods.
Prior to Java 5, a common usage for static fields was:
interface HtmlConstants {
static String OPEN = "<";
static String SLASH_OPEN = "</";
static String CLOSE = ">";
static String SLASH_CLOSE = " />";
static String HTML = "html";
static String BODY = "body";
...
}
public class HtmlBuilder implements HtmlConstants { // implements ?!?
public String buildHtml() {
StringBuffer sb = new StringBuffer();
sb.append(OPEN).append(HTML).append(CLOSE);
sb.append(OPEN).append(BODY).append(CLOSE);
...
sb.append(SLASH_OPEN).append(BODY).append(CLOSE);
sb.append(SLASH_OPEN).append(HTML).append(CLOSE);
return sb.toString();
}
}
This meant HtmlBuilder would not have to qualify each constant, so it could use OPEN instead of HtmlConstants.OPEN
Using implements in this way is ultimately confusing.
Now with Java 5, we have the import static syntax to achieve the same effect:
private final class HtmlConstants {
...
private HtmlConstants() { /* empty */ }
}
import static HtmlConstants.*;
public class HtmlBuilder { // no longer uses implements
...
}
There is no real reason for not having static methods in interfaces except: the Java language designers did not want it like that.
From a technical standpoint it would make sense to allow them. After all an abstract class can have them as well. I assume but did not test it, that you can "hand craft" byte code where the interface has a static method and it should imho work with no problems to call the method and/or to use the interface as usually.
I often wonder why static methods at all? They do have their uses, but package/namespace level methods would probably cover 80 of what static methods are used for.
Two main reasons spring to mind:
Static methods in Java cannot be overridden by subclasses, and this is a much bigger deal for methods than static fields. In practice, I've never even wanted to override a field in a subclass, but I override methods all the time. So having static methods prevents a class implementing the interface from supplying its own implementation of that method, which largely defeats the purpose of using an interface.
Interfaces aren't supposed to have code; that's what abstract classes are for. The whole point of an interface is to let you talk about possibly-unrelated objects which happen to all have a certain set of methods. Actually providing an implementation of those methods is outside the bounds of what interfaces are intended to be.
Static methods are tied to a class. In Java, an interface is not technically a class, it is a type, but not a class (hence, the keyword implements, and interfaces do not extend Object). Because interfaces are not classes, they cannot have static methods, because there is no actual class to attach to.
You may call InterfaceName.class to get the Class Object corresponding to the interface, but the Class class specifically states that it represents classes and interfaces in a Java application. However, the interface itself is not treated as a class, and hence you cannot attach a static method.
Only static final fields may be declared in an interface (much like methods, which are public even if you don't include the "public" keyword, static fields are "final" with or without the keyword).
These are only values, and will be copied literally wherever they are used at compile time, so you never actually "call" static fields at runtime. Having a static method would not have the same semantics, since it would involve calling an interface without an implementation, which Java does not allow.
The reason is that all methods defined in an interface are abstract whether or not you explicitly declare that modifier. An abstract static method is not an allowable combination of modifiers since static methods are not able to be overridden.
As to why interfaces allow static fields. I have a feeling that should be considered a "feature". The only possibility I can think of would be to group constants that implementations of the interface would be interested in.
I agree that consistency would have been a better approach. No static members should be allowed in an interface.
I believe that static methods can be accessed without creating an object and the interface does not allow creating an object as to restrict the programmers from using the interface methods directly rather than from its implemented class.
But if you define a static method in an interface, you can access it directly without its implementation. Thus static methods are not allowed in interfaces.
I don't think that consistency should be a concern.
Java 1.8 interface static method is visible to interface methods only, if we remove the methodSta1() method from the InterfaceExample class,
we won’t be able to use it for the InterfaceExample object. However like other static methods, we can use interface static methods using class name.
For example, a valid statement will be:
exp1.methodSta1();
So after looking below example we can say :
1) Java interface static method is part of interface, we can’t use it for implementation class objects.
2) Java interface static methods are good for providing utility methods, for example null check, collection sorting ,log etc.
3) Java interface static method helps us in providing security by not allowing implementation classes (InterfaceExample) to override them.
4) We can’t define interface static method for Object class methods, we will get compiler error as “This static method cannot hide the instance method from Object”. This is because it’s not allowed in java, since Object is the base class for all the classes and we can’t have one class level static method and another instance method with same signature.
5) We can use java interface static methods to remove utility classes such as Collections and move all of it’s static methods to the corresponding interface,
that would be easy to find and use.
public class InterfaceExample implements exp1 {
#Override
public void method() {
System.out.println("From method()");
}
public static void main(String[] args) {
new InterfaceExample().method2();
InterfaceExample.methodSta2(); // <--------------------------- would not compile
// methodSta1(); // <--------------------------- would not compile
exp1.methodSta1();
}
static void methodSta2() { // <-- it compile successfully but it can't be overridden in child classes
System.out.println("========= InterfaceExample :: from methodSta2() ======");
}
}
interface exp1 {
void method();
//protected void method1(); // <-- error
//private void method2(); // <-- error
//static void methodSta1(); // <-- error it require body in java 1.8
static void methodSta1() { // <-- it compile successfully but it can't be overridden in child classes
System.out.println("========= exp1:: from methodSta1() ======");
}
static void methodSta2() { // <-- it compile successfully but it can't be overridden in child classes
System.out.println("========= exp1:: from methodSta2() ======");
}
default void method2() { System.out.println("--- exp1:: from method2() ---");}
//synchronized default void method3() { System.out.println("---");} // <-- Illegal modifier for the interface method method3; only public, abstract, default, static
// and strictfp are permitted
//final default void method3() { System.out.println("---");} // <-- error
}

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