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How do I make a program insert a new line every time it finds a space (or whitespace) within a string (in java)?

I'm a first year IT student and we recently had an activity that asks the programmer to create a program that will accept a sentence or a phrase, then detect if there is a space in that string and add a newline in between words that have a space after it.
For clarification, here's what the prompt should look like:
Enter a sentence or phrase: I am a student
then the output would be:
I
am
a
student
I tried to actually finish the code, but I was hit by a roadblock and got stuck. Here's my attempt though:
import java.util.*;
public class NumTwo{
public static void main (String[] args){
Scanner in = new Scanner(System.in);
String phr;
System.out.print("Enter a phrase: ");
phr = in.nextLine();
if(phr.contains(" ")){
System.out.print(phr + "\n");
}
else{
}
}
}
any comments to what i might have done wrong will be very much appreciated
EDIT:
I tried using sir Christoph Dahlen's solution which was to use String.replace, and it worked! Thank you very much.

You are currently checking weither the input line contains any spaces at all, but you have to react to every space instead.
One way would be to split phr by spaces and concatenating it with newlines.
String result = String.join(System.lineSeparator(), phr.split(" "))

How to print a line and type input in the same line [duplicate]

This question already has answers here:
How to keep my user input on the same line after an output?
(4 answers)
Closed 3 years ago.
I want to print a line like this:
Result: [the result are input here and after click on Enter to continue]
How can I do that?
EDIT:
This is what I want:
Scanner user1 = new Scanner(System.in);
int x = user1.nextInt();
System.out.println("Result: "+x);
But the last line won't print unless I type my input and press Enter.

Using java, you simply could use System.out.print(); to display it in console and after adding the capture info:
System.out.print("Result: ");
int x = user1.nextInt();

This is a very old thread but since there doesn't seem to be an accepted answer, I am answering. Hope it would help someone else...
Here is what you are looking for
Scanner input = new Scanner (System.in);
System.out.print("Enter a number : ");
int num = input.nextInt();
System.out.println("Hello you entered "+num);
Note that when you use println the cursor moves to next line.
If you use just print the next statement continues on the same line.

Hope this one will work. Please try
Input str =scanner. readLine("Result:" ) ;
Int inp =integer.parseInt(star) ;

The last line will not print unless you type an input and press enter as the code is run line by line. First you have to enter the value. Since it runs on console for the next step to be pressed you have to press enter.
So whatever you said will naturally happen and cannot be avoided.
Based on the code snippet you sent there is nothing wrong with the code and the logic in it and these are basic java steps.

Strange output when I read from scanner

I'm trying to create a videoStore with the basic CRUD operation. For creating each movie I need to read the title, the year and the gender as below:
System.out.print("name: ");
name = in.nextLine();
System.out.print("year: ");
year = in.nextInt();
in.nextLine();
System.out.print("gender: ");
gender = in.next();
When I enter the addMovie option, I get this print on the console
(name: year:)
Can someone explain to me why it happens as above?
Here is the rest of the method:
static ArrayList<Movie> movies = new ArrayList<Movie>();
static Scanner in = new Scanner(System.in);
public static void InserirFilme() {
String name;
int year;
String gender;
boolean existe = false;
System.out.print("name: ");
name = in.nextLine();
System.out.print("year: ");
year = in.nextInt();
in.nextLine();
System.out.print("gender: ");
gender = in.next();
Movie movie = new Movie(name, year, gender);
for(Movie m: movies)
{
if(movie == m)
{
existe = true;
}
}
if(!existe)
{
movies.add(movie);
}
else
{
System.out.println("the movie already exists in the videoStore");
}
}

Calling next does not remove the line break, which means the next time you call InserirFilme the call to read the name can complete immediately. Use nextLine.
System.out.print("gender: ");
gender = in.nextLine();
(You probably mean "genre" instead of "gender" though)
Also, as mentioned in the comments, this check will never succeed:
if(movie == f)

You run this method in loop (right?)
The first call reads input correctly, but it leaves the linebreak in System.in after the last in.next().
On next call the name: is printed, then scanner reads an empty string from System.in because the linebreak already exists here.
And after thet the year: is printed on the same line because no new linebreaks are entered.
So you just have to insert another in.nextLine() after reading gender (or genre :) )
Or use nextLine() for read genre instead of next(), because genre might have more than one word.
But there are some disadvantages with using fake nextLine() to 'eat' linebreak - there might be another text which you doesn't process. It's a bad practice - to loose the data user entered.
It is better to read all the data from line, then validate/parse it, check isn't there some extra data, and if the data is invalid show notification and let him try to enter the right value.
Here are some examples how to deal with user input manually - https://stackoverflow.com/a/3059367/1916536. This is helpful to teach yourself.
Try to generalize user input operations:
name = validatedReader.readPhrase("name: ");
year = validatedReader.readNumber("year: ");
genre = validatedReader.readWord("genre: ");
where ValidatedReader is a custom wrapper for Scanner which could use your own validation rules, and could gently re-ask user after a wrong input.
It could also validate dates, phone numbers, emails, url's or so
For production purposes, it is better to use validation frameworks with configurable validation rules. There are a lot of validation frameworks for different purposes - Web, UI, REST etc...

when i enter the addMovie option, i get this print on the console (name: year:) can someone explain me why it happens i already searched a lot and i cant understand why :S
The way i understood your question is that you are getting the output (name: year: ) in a line and want it in seperate lines? In that case you simply can use System.out.println(String); instead of System.out.print(String). On the other hand you can also use "\n" whenever you want a linebreak within a String. Hope i could help you :).
Edit: If this was not an answer to your question, feel free to tell me and clarify your question :)

For String name you are using in.nextLine(); i.e the data entered on the entire line will be added to name string.
After "name: " is displayed, enter some text and press enter key, so that the year and gender fields will get correct values.
The code written is correct but you are not giving appropriate input through the scanner.
I recommend to use
String name = in.next();//instead of String name = in.nextLine();

You may instantiate Scanner Class differently for String and Integer type input. It works for me :)
Example:
static Scanner in1 = new Scanner(System.in);
static Scanner in2 = new Scanner(System.in);
Please use nextLine() for 'name' and 'gender'. It may contain more than one word. Let me know if it works.
Example:
System.out.print("name: ");
name = in1.nextLine();
System.out.print("year: ");
year = in2.nextInt();
System.out.print("gender: ");
gender = in1.nextLine();

Java - Scanner execute only the Int and "skip" the Strings data types when i input String data before the Int ones [duplicate]

This question already has answers here:
Scanner is skipping nextLine() after using next() or nextFoo()?
(24 answers)
Closed 7 years ago.
While I'm working with java.util.Scanner, I tried to use integers and Strings at data input.
The problem that I faced is, when I input an Int data before a String one, the console skip the String data and go immediately to the next Int one.
Here is my simple problem where the problem is happening :
package justForTest;
import java.util.Scanner;
public class EmptySpaceWorkshop {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.print("- Enter your Name : ");
String name = input.nextLine();
System.out.print("- Enter your IC number : ");
int icNumber = input.nextInt();
System.out.print("- Enter your Place of birth : ");
String placeOfBirth = input.nextLine();
System.out.print("- Enter your Age : ");
int age = input.nextInt();
System.out.println("There once was a wonderful person named " + name+ ", His IC number is " + icNumber );
System.out.println(". He/She is " + age + " years old. She/He was born at " + placeOfBirth );
}
}
And here is my output:
- Enter your Name : Ali HISOKA
- Enter your IC number : 123456
- Enter your Place of birth : - Enter your Age :
I tried a lot to fix this problem. The only solution I could came up with is using input.next(); instead of input.nextLine(); . However, this solution is USELESS for me because as you guys know, when using input.next(); we can only type One Single Word, unlike input.nextLine(); we can type a lot of words which is the thing that I'm looking for. Also I DO NOT want to re-sort (re-arrange) my input and type the Strings data first, then following by the Int data to solve my problem. I want my data to be at the same sort as you seen above in my simple program ( Enter Name, Enter IC Number, Enter Place of Birth, then Enter age). So can I solve this problem ?
I searched a lot on the internet for someone got a problem as mine, but I couldn't find a question and solution for a problem looks exactly like mine.
I already know the reason and the explanation of my problem which is explained by
Joshua
"The reason for the error is that the nextInt only pulls the integer,
not the newline. If you add a in.nextLine() before your for loop, it
will eat the empty new line and allow you to enter 3 names."
but still it's not helpful for solving my problem.

Think of your input as a single string:
"Ali HISOKA\n123456\nPLACE\n99"
next() consumes the first word, up to first white space - e.g. " " or "\n"
nextLine() consumes the first word, up to first new line character
nextInt() consumes first word, as next(), and parses it to int - it will throw an exception if the word cannot be parsed.
Now, let's have a look what your calls are consuming:
nextLine() will return "Ali HISOKA", the remaining string is "123456\nPLACE\n99"
nextInt() will return int 123456, the remaining string is "\nPLACE\n99"
nextLine() will return empty string "", the remaining string is "PLACE\n99"
nextInt() will throw an exception, because it will try to parse "PLACE" to int.
The trick is in step 2 - although nextInt() consumes all white spaces between words, it however does not consume new line character, hence nextLine() in step 3 reads empty string because "\n" is first character in the remaining string.
There are two solutions:
Instead of using nextInt() you can read and parse the whole line Integer.parseInt(input.nextLine()). If the line contains a few words, e.g. "1234 abc" it will throw the exception.
Call input.nextLine() after calling nextInt(), so it consumes the remaining string up to first new line character. For input "1234 abc" it will ignore everything after the number.
I would recommend the first solution, because when you are asked for the number and you answer "123 abc", it is not a valid answer. In such case the user should be told that the input is invalid, instead of taking only a valid part from that answer - user would have no clue that part of his answer was ignored.

From what I can see it appears that the readLine() is just consuming the newline left after the int was taken from the buffer. A better way to fix this is to use nextLine() to get a string value and convert it:
int icNumber = Integer.parseInt(input.nextLine());

This is a bit confusing because the code you posted does not show your original problem, but the situation after putting in a workaround.
You need to skip the newline after nextInt()
System.out.print("- Enter your IC number : ");
int icNumber = input.nextInt();
input.skip("\\n");
Without the skip, input.newLine (for the place of birth) will match the newline after the entered IC number and you will be prompted for the age.

I tried your code at my machine without making any changes and Its working fine.Below is my output.
Enter your Name : yash
Enter your IC number : 12
Enter your Place of birth : alg
Enter your Age : 25
There once was a wonderful person named yash, His IC number is 12
. He/She is 25 years old. She/He was born at alg

Ignore space, blanks

Does anybody know how i could make scanner ignore space? I wanna type a first and second name, but scanner wont let me, i want to save the full name
String name;
System.out.print("Enter name: ");
name = scan.next(); //Ex: John Smith
System.out.println(name);
Edit:
New problem.. While using nextLine in my extended program, nextLine just ignores the whole question and moves on without a chance to scan the name.

Scanner#next() splits lines around whitespace. Scanner.nextLine() does not, therefore leaving spaces in.
name = scan.nextLine(); //Ex: John Smith

Well, first your System.out.print(); call is flawed. Everything inside must be inside quotations
System.out.print("Enter name: ");
scan.next() gets the next character in the stream, whereas scan.nextLine() gets the next line (terminated by an EOL character), which may be more helpful to you.
After that, you can create an array of words, like
String[] broken = name.split(" ");
which will place into broken all of the words that you've typed in delimited by spaces.
Then you can go something like
for(int i = 0; i < broken.size; i++)
{
System.out.print(broken[i] + " ");
}
System.out.println();

Scanner.next delimits using whitespaces, to read a full line you can use:
name = scan.nextLine();

use scanner.nextLine() which reads full line, instead of scan.next();
Example:
name = scan.nextLine();
Read oracle documentation for Scanner class for available methods.

sounds like you want to read the entire line (minus the line ending). if someone enters, "helen r. smith", you can read the line in with:
name = scan.nextLine();

YOU CAN DO LIKE THIS
import java.util.*;
class scanner2
{
public static void main(String args[])
{
Scanner in= new Scanner(System.in);
System.out.println("enter the name");
String name= in.nextLine();//for name with spaces with more than one word or for one word.
System.out.println("enter single word");
String rl= in.next();//single word name
System.out.println("name is "+name+" rl is "+rl);
}
}
Execute it you will get your answer.