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How to send the Pre-populated text message to specific (intended) Whats-App user / users? [duplicate]

Since I found some older posts, that tell that whatsapp doesn't support this, I was wondering if something had changed and if there is a way to open a whatsapp 'chat' with a number that I'm sending through an intent?

UPDATE
Please refer to https://faq.whatsapp.com/en/android/26000030/?category=5245251
WhatsApp's Click to Chat feature allows you to begin a chat with
someone without having their phone number saved in your phone's
address book. As long as you know this person’s phone number, you can
create a link that will allow you to start a chat with them.
Use: https://wa.me/15551234567
Don't use: https://wa.me/+001-(555)1234567
Example: https://wa.me/15551234567?text=I'm%20interested%20in%20your%20car%20for%20sale
Original answer
Here is the solution
public void onClickWhatsApp(View view) {
PackageManager pm=getPackageManager();
try {
Intent waIntent = new Intent(Intent.ACTION_SEND);
waIntent.setType("text/plain");
String text = "YOUR TEXT HERE";
PackageInfo info=pm.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
//Check if package exists or not. If not then code
//in catch block will be called
waIntent.setPackage("com.whatsapp");
waIntent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(waIntent, "Share with"));
} catch (NameNotFoundException e) {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT)
.show();
}
}
Also see http://www.whatsapp.com/faq/en/android/28000012

With this code you can open the whatsapp chat with the given number.
void openWhatsappContact(String number) {
Uri uri = Uri.parse("smsto:" + number);
Intent i = new Intent(Intent.ACTION_SENDTO, uri);
i.setPackage("com.whatsapp");
startActivity(Intent.createChooser(i, ""));
}

Simple solution, try this.
String phoneNumberWithCountryCode = "+62820000000";
String message = "Hallo";
startActivity(
new Intent(Intent.ACTION_VIEW,
Uri.parse(
String.format("https://api.whatsapp.com/send?phone=%s&text=%s", phoneNumberWithCountryCode, message)
)
)
);

I found the following solution, first you'll need the whatsapp id:
Matching with reports from some other threads here and in other forums the login name I found was some sort of:
international area code without the 0's or + in the beginning + phone number without the first 0 + #s.whatsapp.net
For example if you live in the Netherlands and having the phone number 0612325032 it would be 31612325023#s.whatsapp.net -> +31 for the Netherlands without the 0's or + and the phone number without the 0.
public void sendWhatsAppMessageTo(String whatsappid) {
Cursor c = getSherlockActivity().getContentResolver().query(ContactsContract.Data.CONTENT_URI,
new String[] { ContactsContract.Contacts.Data._ID }, ContactsContract.Data.DATA1 + "=?",
new String[] { whatsappid }, null);
c.moveToFirst();
Intent whatsapp = new Intent(Intent.ACTION_VIEW, Uri.parse("content://com.android.contacts/data/" + c.getString(0)));
c.close();
if (whatsapp != null) {
startActivity(whatsapp);
} else {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT)
.show();
//download for example after dialog
Uri uri = Uri.parse("market://details?id=com.whatsapp");
Intent goToMarket = new Intent(Intent.ACTION_VIEW, uri);
}
}

This should work whether Whatsapp is installed or not.
boolean isWhatsappInstalled = whatsappInstalledOrNot("com.whatsapp");
if (isWhatsappInstalled) {
Uri uri = Uri.parse("smsto:" + "98*********7")
Intent sendIntent = new Intent(Intent.ACTION_SENDTO, uri);
sendIntent.putExtra(Intent.EXTRA_TEXT, "Hai Good Morning");
sendIntent.setPackage("com.whatsapp");
startActivity(sendIntent);
} else {
Toast.makeText(this, "WhatsApp not Installed", Toast.LENGTH_SHORT).show();
Uri uri = Uri.parse("market://details?id=com.whatsapp");
Intent goToMarket = new Intent(Intent.ACTION_VIEW, uri);
startActivity(goToMarket);
}
private boolean whatsappInstalledOrNot(String uri) {
PackageManager pm = getPackageManager();
boolean app_installed = false;
try {
pm.getPackageInfo(uri, PackageManager.GET_ACTIVITIES);
app_installed = true;
} catch (PackageManager.NameNotFoundException e) {
app_installed = false;
}
return app_installed;
}

Tested on Marshmallow S5 and it works!
Uri uri = Uri.parse("smsto:" + "phone number with country code");
Intent sendIntent = new Intent(Intent.ACTION_SENDTO, uri);
sendIntent.setPackage("com.whatsapp");
startActivity(sendIntent);
This will open a direct chat with a person, if whatsapp not installed this will throw exception, if phone number not known to whatsapp they will offer to send invite via sms or simple sms message

use this singleline code use to Sending message through WhatsApp
//NOTE : please use with country code first 2digits without plus signed
try {
String mobile = "911234567890";
String msg = "Its Working";
startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse("https://api.whatsapp.com/send?phone=" + mobile + "&text=" + msg)));
}catch (Exception e){
//whatsapp app not install
}

Here is the latest way to send a message via Whatsapp, even if the receiver's phone number is not in your Whatsapp chat or phone's Contacts list.
private fun openWhatsApp(number: String) {
try {
packageManager.getPackageInfo("com.whatsapp", PackageManager.GET_ACTIVITIES)
val intent = Intent(
Intent.ACTION_VIEW,
Uri.parse("https://wa.me/$number?text=I'm%20interested%20in%20your%20car%20for%20sale")
)
intent.setPackage("com.whatsapp")
startActivity(intent)
} catch (e: PackageManager.NameNotFoundException) {
Toast.makeText(
this,
"Whatsapp app not installed in your phone",
Toast.LENGTH_SHORT
).show()
e.printStackTrace()
}
}
intent.setPackage("com.whatsapp") will help you to avoid Open With chooser and open Whatsapp directly.
Importent Note: If You are ending in catch statement, even if Whatsapp is installed. Please add queries to manifest.xml as follows:
<queries>
<package android:name="com.whatsapp" />
</queries>
Please see this answer for more details.

To check if WhatsApp is installed in device and initiate "click to chat" in WhatsApp:
Kotlin:
try {
// Check if whatsapp is installed
context?.packageManager?.getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA)
val intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://wa.me/$internationalPhoneNumber"))
startActivity(intent)
} catch (e: NameNotFoundException) {
Toast.makeText(context, "WhatsApp not Installed", Toast.LENGTH_SHORT).show()
}
Java:
try {
// Check if whatsapp is installed
getPackageManager().getPackageInfo("com.whatsapp", PackageManager.GET_META_DATA);
Intent intent = Intent(Intent.ACTION_VIEW, Uri.parse("https://wa.me/" + internationalPhoneNumber));
startActivity(intent);
} catch (NameNotFoundException e) {
Toast.makeText(context, "WhatsApp not Installed", Toast.LENGTH_SHORT).show();
}
getPackageInfo() throws NameNotFoundException if WhatsApp is not installed.
The internationalPhoneNumber variable is used to access the phone number.
Reference:
https://faq.whatsapp.com/general/chats/how-to-use-click-to-chat?category=5245251
https://stackoverflow.com/a/2201999/9636037
https://stackoverflow.com/a/15931345/9636037

The following code is used by Google Now App and will NOT work for any other application.
I'm writing this post because it makes me angry, that WhatsApp does not allow any other developers to send messages directly except for Google.
And I want other freelance-developers to know, that this kind of cooperation is going on, while Google keeps talking about "open for anybody" and WhatsApp says they don't want to provide any access to developers.
Recently WhatsApp has added an Intent specially for Google Now, which should look like following:
Intent intent = new Intent("com.google.android.voicesearch.SEND_MESSAGE_TO_CONTACTS");
intent.setPackage("com.whatsapp");
intent.setComponent(new ComponentName("com.whatsapp", "com.whatsapp.VoiceMessagingActivity"));
intent.putExtra("com.google.android.voicesearch.extra.RECIPIENT_CONTACT_CHAT_ID", number);
intent.putExtra("android.intent.extra.TEXT", text);
intent.putExtra("search_action_token", ?????);
I could also find out that "search_action_token" is a PendingIntent
that contains an IBinder-Object, which is sent back to Google App and checked, if it was created by Google Now.
Otherwise WhatsApp will not accept the message.

Currently, the only official API that you may make a GET request to:
https://api.whatsapp.com/send?phone=919773207706&text=Hello
Anyways, there is a secret API program already being ran by WhatsApp

As the documentation says you can just use an URL like:
https://wa.me/15551234567
Where the last segment is the number in in E164 Format
Uri uri = Uri.parse("https://wa.me/15551234567");
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);

This is what worked for me :
Uri uri = Uri.parse("https://api.whatsapp.com/send?phone=" + "<number>" + "&text=" + "Hello WhatsApp!!");
Intent sendIntent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(sendIntent);

This works to me:
PackageManager pm = context.getPackageManager();
try {
pm.getPackageInfo("com.whatsapp", PackageManager.GET_ACTIVITIES);
Intent intent = new Intent();
intent.setComponent(new ComponentName(packageName,
ri.activityInfo.name));
intent.setType("text/plain");
intent.putExtra(Intent.EXTRA_TEXT, element);
} catch (NameNotFoundException e) {
ToastHelper.MakeShortText("Whatsapp have not been installed.");
}

Use direct URL of whatsapp
String url = "https://api.whatsapp.com/send?phone="+number;
Intent i = new Intent(Intent.ACTION_VIEW);
i.setData(Uri.parse(url));
startActivity(i);

You'll want to use a URL in the following format...
https://api.whatsapp.com/send?text=text
Then you can have it send whatever text you'd like. You also have the option to specify a phone number...
https://api.whatsapp.com/send?text=text&phone=1234
What you CANNOT DO is use the following:
https://wa.me/send?text=text
You will get...
We couldn't find the page you were looking for
wa.me, though, will work if you supply both a phone number and text. But, for the most part, if you're trying to make a sharing link, you really don't want to indicate the phone number, because you want the user to select someone. In that event, if you don't supply the number and use wa.me as URL, all of your sharing links will fail. Please use app.whatsapp.com.

this is much lengthy but surly working.
enjoy your code:)
//method used to show IMs
private void show_custom_chooser(String value) {
List<ResolveInfo> list = null;
final Intent email = new Intent(Intent.ACTION_SEND);
email.setData(Uri.parse("sms:"));
email.putExtra(Intent.EXTRA_TEXT, "" + value);
email.setType("text/plain"); // vnd.android-dir/mms-sms
WindowManager.LayoutParams WMLP = dialogCustomChooser.getWindow()
.getAttributes();
WMLP.gravity = Gravity.CENTER;
dialogCustomChooser.getWindow().setAttributes(WMLP);
dialogCustomChooser.getWindow().setBackgroundDrawable(
new ColorDrawable(android.graphics.Color.TRANSPARENT));
dialogCustomChooser.setCanceledOnTouchOutside(true);
dialogCustomChooser.setContentView(R.layout.about_dialog);
dialogCustomChooser.setCancelable(true);
ListView lvOfIms = (ListView) dialogCustomChooser
.findViewById(R.id.listView1);
PackageManager pm = getPackageManager();
List<ResolveInfo> launchables = pm.queryIntentActivities(email, 0);
// ////////////new
list = new ArrayList<ResolveInfo>();
for (int i = 0; i < launchables.size(); i++) {
String string = launchables.get(i).toString();
Log.d("heh", string);
//check only messangers
if (string.contains("whatsapp")) {
list.add(launchables.get(i));
}
}
Collections.sort(list, new ResolveInfo.DisplayNameComparator(pm));
int size = launchables.size();
adapter = new AppAdapter(pm, list, MainActivity.this);
lvOfIms.setAdapter(adapter);
lvOfIms.setOnItemClickListener(new OnItemClickListener() {
#Override
public void onItemClick(AdapterView<?> arg0, View arg1,
int position, long arg3) {
ResolveInfo launchable = adapter.getItem(position);
ActivityInfo activity = launchable.activityInfo;
ComponentName name = new ComponentName(
activity.applicationInfo.packageName, activity.name);
email.addCategory(Intent.CATEGORY_LAUNCHER);
email.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK
| Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
email.setComponent(name);
startActivity(email);
dialogCustomChooser.dismiss();
}
});
dialogCustomChooser.show();
}

I'm really late here but I believe that nowadays we have shorter and better solutions to send messages through WhatsApp.
You can use the following to call the system picker, then choose which app you will use to share whatever you want.
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "This is my text to send.");
sendIntent.setType("text/plain");
startActivity(sendIntent);
If you are really need to send through WhatsApp all you need to do is the following (You will skip the system picker)
Intent sendIntent = new Intent();
sendIntent.setAction(Intent.ACTION_SEND);
sendIntent.putExtra(Intent.EXTRA_TEXT, "This is my text to send.");
sendIntent.setType("text/plain");
// Put this line here
sendIntent.setPackage("com.whatsapp");
//
startActivity(sendIntent);
If you need more information you can find it here: WhatsApp FAQ

private fun sendWhatsappMessage(phoneNumber:String, text:String) {
val url = if (Intent().setPackage("com.whatsapp").resolveActivity(packageManager) != null) {
"whatsapp://send?text=Hello&phone=$phoneNumber"
} else {
"https://api.whatsapp.com/send?phone=$phoneNumber&text=$text"
}
val browserIntent = Intent(Intent.ACTION_VIEW, Uri.parse(url))
startActivity(browserIntent)
}
This is a much easier way to achieve this. This code checks if whatsapp is installed on the device. If it is installed, it bypasses the system picker and goes to the contact on whatsapp and prefields the text in the chat. If not installed it opens whatsapp link on your web browser.

Sending to WhatsApp Number that exist in your contact list.
Notice that we are using ACTION_SEND
Intent whatsappIntent = new Intent(Intent.ACTION_SEND);
whatsappIntent.setType("text/plain");
whatsappIntent.setPackage("com.whatsapp");
whatsappIntent.putExtra(Intent.EXTRA_TEXT, "SMS TEXT, TEXT THAT YOU NEED TO SEND");
try {
startActivityForResult(whatsappIntent, 100);
} catch (Exception e) {
Toast.makeText(YourActivity.this, "App is not installed", Toast.LENGTH_SHORT).show();
}
If Number doesn't exist in contact list. Use WhatsApp API.
String number = number_phone.getText().toString(); // I toke it from Dialog box
number = number.substring(1); // To remove 0 at the begging of number (Optional) but needed in my case
number = "962" + number; // Replace it with your country code
String url = "https://api.whatsapp.com/send?phone=" + number + "&text=" + Uri.parse("Text that you want to send to the current user");
Intent whatsappIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(url));
whatsappIntent.setPackage("com.whatsapp");
whatsappIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
try {
context.startActivity(whatsappIntent);
} catch (android.content.ActivityNotFoundException ex) {
Toast.makeText(YourActivity.this, "App is not installed", Toast.LENGTH_SHORT).show();
}

Check this code,
public void share(String subject,String text) {
final Intent intent = new Intent(Intent.ACTION_SEND);
String score=1000;
intent.setType("text/plain");
intent.putExtra(Intent.EXTRA_SUBJECT, score);
intent.putExtra(Intent.EXTRA_TEXT, text);
startActivity(Intent.createChooser(intent, getString(R.string.share)));
}

This works to me:
public static void shareWhatsApp(Activity appActivity, String texto) {
Intent sendIntent = new Intent(Intent.ACTION_SEND);
sendIntent.setType("text/plain");
sendIntent.putExtra(android.content.Intent.EXTRA_TEXT, texto);
PackageManager pm = appActivity.getApplicationContext().getPackageManager();
final List<ResolveInfo> matches = pm.queryIntentActivities(sendIntent, 0);
boolean temWhatsApp = false;
for (final ResolveInfo info : matches) {
if (info.activityInfo.packageName.startsWith("com.whatsapp")) {
final ComponentName name = new ComponentName(info.activityInfo.applicationInfo.packageName, info.activityInfo.name);
sendIntent.addCategory(Intent.CATEGORY_LAUNCHER);
sendIntent.setFlags(Intent.FLAG_ACTIVITY_NO_HISTORY | Intent.FLAG_ACTIVITY_NEW_TASK);
sendIntent.setComponent(name);
temWhatsApp = true;
break;
}
}
if(temWhatsApp) {
//abre whatsapp
appActivity.startActivity(sendIntent);
} else {
//alerta - você deve ter o whatsapp instalado
Toast.makeText(appActivity, appActivity.getString(R.string.share_whatsapp), Toast.LENGTH_SHORT).show();
}
}

get the contact number whom you want to send the message and create uri for whatsapp, here c is a Cursor returning the selected contact.
Uri.parse("content://com.android.contacts/data/" + c.getString(0)));
i.setType("text/plain");
i.setPackage("com.whatsapp"); // so that only Whatsapp reacts and not the chooser
i.putExtra(Intent.EXTRA_SUBJECT, "Subject");
i.putExtra(Intent.EXTRA_TEXT, "I'm the body.");
startActivity(i);

From the documentation
To create your own link with a pre-filled message that will
automatically appear in the text field of a chat, use
https://wa.me/whatsappphonenumber/?text=urlencodedtext where
whatsappphonenumber is a full phone number in international format and
URL-encodedtext is the URL-encoded pre-filled message.
Example:https://wa.me/15551234567?text=I'm%20interested%20in%20your%20car%20for%20sale
Code example
val phoneNumber = "13492838472"
val text = "Hey, you know... I love StackOverflow :)"
val uri = Uri.parse("https://wa.me/$phoneNumber/?text=$text")
val sendIntent = Intent(Intent.ACTION_VIEW, uri)
startActivity(sendIntent)

This one worked finally for me in Kotlin:
private fun navigateToWhatsApp() {
try {
val url = "https://api.whatsapp.com/send?phone=+91${getString(R.string.contact)}"
startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(url)).setPackage("com.whatsapp"))
} catch (e: Exception) {
showToast("Whatsapp app not installed in your device")
}
}

The following API can be used in c++ as shown in my article.
You need to define several constants:
//
#define    GroupAdmin                <YOUR GROUP ADMIN MOBILE PHONE>
#define GroupName                <YOUR GROUP NAME>
#define CLIENT_ID                <YOUR CLIENT ID>
#define CLIENT_SECRET            <YOUR CLIENT SECRET>
#define GROUP_API_SERVER        L"api.whatsmate.net"
#define GROUP_API_PATH          L"/v3/whatsapp/group/text/message/12"
#define IMAGE_SINGLE_API_URL    L"http://api.whatsmate.net/v3/whatsapp/group/image/message/12"
//
Then you connect to the API’s endpoint.
hOpenHandle = InternetOpen(_T("HTTP"), INTERNET_OPEN_TYPE_DIRECT, NULL, NULL, 0);
if (hOpenHandle == NULL)
{
return false;
}
hConnectHandle = InternetConnect(hOpenHandle,
GROUP_API_SERVER,
INTERNET_DEFAULT_HTTP_PORT,
NULL, NULL, INTERNET_SERVICE_HTTP,
0, 1);
if (hConnectHandle == NULL)
{
InternetCloseHandle(hOpenHandle);
return false;
}
Then send both header and body and wait for the result that needs to be “OK”.
Step 1 - open an HTTP request:
const wchar_t *AcceptTypes[] = { _T("application/json"),NULL };
HINTERNET hRequest = HttpOpenRequest(hConnectHandle, _T("POST"), GROUP_API_PATH, NULL, NULL, AcceptTypes, 0, 0);
if (hRequest == NULL)
{
InternetCloseHandle(hConnectHandle);
InternetCloseHandle(hOpenHandle);
return false;
}
Step 2 - send the header:
std::wstring HeaderData;
HeaderData += _T("X-WM-CLIENT-ID: ");
HeaderData += _T(CLIENT_ID);
HeaderData += _T("\r\nX-WM-CLIENT-SECRET: ");
HeaderData += _T(CLIENT_SECRET);
HeaderData += _T("\r\n");
HttpAddRequestHeaders(hRequest, HeaderData.c_str(), HeaderData.size(), NULL);
Step 3 - send the message:
std::wstring WJsonData;
WJsonData += _T("{");
WJsonData += _T("\"group_admin\":\"");
WJsonData += groupAdmin;
WJsonData += _T("\",");
WJsonData += _T("\"group_name\":\"");
WJsonData += groupName;
WJsonData += _T("\",");
WJsonData += _T("\"message\":\"");
WJsonData += message;
WJsonData += _T("\"");
WJsonData += _T("}");
const std::string JsonData(WJsonData.begin(), WJsonData.end());
bResults = HttpSendRequest(hRequest, NULL, 0, (LPVOID)(JsonData.c_str()), JsonData.size());
Now just check the result:
TCHAR StatusText[BUFFER_LENGTH] = { 0 };
DWORD StatusTextLen = BUFFER_LENGTH;
HttpQueryInfo(hRequest, HTTP_QUERY_STATUS_TEXT, &StatusText, &StatusTextLen, NULL);
bResults = (StatusTextLen && wcscmp(StatusText, L"OK")==FALSE);

How to find active app name?

I have this code that when I copy some text in clipboard this program paste text and application name automatically in the text box.I want paste app's name that running/on top
myClipboard.addPrimaryClipChangedListener(new ClipboardManager.OnPrimaryClipChangedListener() {
#Override
public void onPrimaryClipChanged()
{
PackageManager pm = getApplicationContext().getPackageManager();
ApplicationInfo ai;
try {
ai = pm.getApplicationInfo(getPackageName(), 0);
} catch (final PackageManager.NameNotFoundException e) {
ai = null;
}
final String applicationName = (String) (ai != null ? pm.getApplicationLabel(ai) : "(unknown)");
ClipData cp = myClipboard.getPrimaryClip();
ClipData.Item item = cp.getItemAt(0);
String text1 = item.getText().toString();
pastetext.setText(text1+"---"+applicationName);
}
});

To get the list of activities/applications installed on Android :
final Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
final List pkgAppsList = context.getPackageManager().queryIntentActivities( mainIntent, 0);
To check all running applications
ActivityManager actvityManager = (ActivityManager)
this.getSystemService( ACTIVITY_SERVICE );
List<RunningAppProcessInfo> procInfos = actvityManager.getRunningAppProcesses();
If you want to fetch the package name of your app or currently opened app in android, than refer this http://shortcutsandroid.blogspot.in/2015/02/how-to-get-package-name-in-android.html
Hope this helps...

Open Application in Android by label name, and unknowing package name.

First of all, I searching for my question many times in Google but I didn't find what I want.
My Question is: Is there any way to open application in Android by "label name" where on the other hand the package name is "knowing" ?
My approach that I used to do this is by creating two ArrayList and store the package name and label name in each one, then, I matching the label name with package name after I converted them to lowercase in order to be the same letters to see if there are matching, if matching , then I launch the application by getting its package name.
the problem that I faced it, the package name sometimes didn't have or matching the same name in label name, based on the application developer what he had write the package name.
for example: if I want to open gmail , based on my method I cannot because the package name is com.google.android.gm and label name is gmail , I apologized to the prolongation ,thanks in advanced.
My code:
private void getAllApps() {
final Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
List<ResolveInfo> activities = getPackageManager()
.queryIntentActivities(mainIntent, 0);
for (ResolveInfo resolveInfo : activities) {
appsName.add(resolveInfo.loadLabel(getPackageManager()).toString()
.toLowerCase());
pkgsName.add(resolveInfo.activityInfo.packageName.toString());
}
}
private void openApplication(String appName) {
String packageName = null, appNameLowerCase = null, pkgNameLowerCase = null;
// matching the package name with label name
if (appsName.contains(appName)) {
appNameLowerCase = appName.trim().replace(" ", "");
for (int i = 0; i < pkgsName.size(); i++) {
pkgNameLowerCase = pkgsName.get(i).trim().toLowerCase();
if (pkgNameLowerCase
.matches("(.*)" + appNameLowerCase + "(.*)")) {
packageName = pkgsName.get(i);
break;
}
}
}
// to launch the application
Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage(packageName);
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
} catch (PackageManager.NameNotFoundException e) {
}
}

thanks for all replies, i solve it by #CommonsWare solution and it works correctly :
class Applications {
private String packageName;
private String labelName;
}
private void getAllApps() {
final Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
List<ResolveInfo> activities = getPackageManager()
.queryIntentActivities(mainIntent, 0);
for (ResolveInfo resolveInfo : activities) {
Applications applications = new Applications();
applications.labelName = resolveInfo.loadLabel(getPackageManager())
.toString().toLowerCase();
applications.packageName = resolveInfo.activityInfo.packageName
.toString();
applicationsArrayList.add(applications);
}
}
private void openApplication(String appName) {
String packageName = null;
// matching the package name with label name
for (int i = 0; i < applicationsArrayList.size(); i++) {
if (applicationsArrayList.get(i).labelName.trim().equals(
appName.trim())) {
packageName = applicationsArrayList.get(i).packageName;
break;
}
}
// to launch the application
Intent i;
PackageManager manager = getPackageManager();
try {
i = manager.getLaunchIntentForPackage(packageName);
if (i == null)
throw new PackageManager.NameNotFoundException();
i.addCategory(Intent.CATEGORY_LAUNCHER);
startActivity(i);
} catch (PackageManager.NameNotFoundException e) {
}
}

Try this
public List<ApplicationInfo> getApplicationList(Context con){
PackageManager p = con.getPackageManager();
List<ApplicationInfo> info = p.getInstalledApplications(0);
String example = info.get(0).packageName.toString();
return info;
}

how i can start application info screen in android?

I want to start manage application (Settings -> Application -> manage application -> Application info) screen programmatically. I'm unable to do it. Can anyone please help me?
Thanks in advance.

as per this link
In Android 2.3, you can use startActivity() on an ACTION_APPLICATION_DETAILS_SETTINGS Intent, with a proper Uri, to bring up your app's "manage" screen
or
private static final String SCHEME = "package";
private static final String APP_PKG_NAME_21 = "com.android.settings.ApplicationPkgName";
private static final String APP_PKG_NAME_22 = "pkg";
private static final String APP_DETAILS_PACKAGE_NAME = "com.android.settings";
private static final String APP_DETAILS_CLASS_NAME = "com.android.settings.InstalledAppDetails";
public static void showInstalledAppDetails(Context context, String packageName) {
Intent intent = new Intent();
final int apiLevel = Build.VERSION.SDK_INT;
if (apiLevel >= 9) { // above 2.3
intent.setAction(Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
Uri uri = Uri.fromParts(SCHEME, packageName, null);
intent.setData(uri);
} else { // below 2.3
final String appPkgName = (apiLevel == 8 ? APP_PKG_NAME_22
: APP_PKG_NAME_21);
intent.setAction(Intent.ACTION_VIEW);
intent.setClassName(APP_DETAILS_PACKAGE_NAME,
APP_DETAILS_CLASS_NAME);
intent.putExtra(appPkgName, packageName);
}
context.startActivity(intent);
}

From API Level 9 (Android 2.3) you can start an Intent with android.provider.Settings.ACTION_APPLICATION_DETAILS_SETTINGS. Thus:
packageName = "your.package.name.here"
try {
//Open the specific App Info page:
Intent intent = new Intent(android.provider.Settings.ACTION_APPLICATION_DETAILS_SETTINGS);
intent.setData(Uri.parse("package:" + packageName));
startActivity(intent);
} catch ( ActivityNotFoundException e ) {
//e.printStackTrace();
//Open the generic Apps page:
Intent intent = new Intent(android.provider.Settings.ACTION_MANAGE_APPLICATIONS_SETTINGS);
startActivity(intent);
}

Optimal way to create shorcut for other package activity

I'm trying to create programmability a home shortcut for any installed application.
Considering that the only thing I would have available would the application name, let's say for example the Calculator com.android.calculator2 (1.5).
I'm using current code bellow, shortcut is created successfully but activity cannot be launched from shortcut (wrong activity class name I guess) and also sometimes the icon seems to be corrupted.
Also add com.android.launcher.permission.INSTALL_SHORTCUT to manifest.xml.
Is there a optimal way to achieved this?
String appName = "com.android.calculator2";
Context newAppContext = null;
// Get other package context
try {
newAppContext =
context.createPackageContext(appName, Context.CONTEXT_IGNORE_SECURITY);
} catch (NameNotFoundException e) {
e.printStackTrace();
}
// Create shortcut
if(newAppContext != null) {
// Get Application Name
PackageManager pm = context.getPackageManager();
ApplicationInfo ai;
try {
ai = pm.getApplicationInfo(appName, 0);
} catch (final NameNotFoundException e) {
ai = null;
}
// Get application label
String applicationName = (String) (ai != null ? pm.getApplicationLabel(ai) : "(unknown)");
// Shortcut intent
Intent shortcutIntent = new Intent (Intent.ACTION_MAIN);
/** Problem in here **
shortcutIntent.setClassName(newAppContext, newAppContext.getClass().getName());
*********************/
shortcutIntent.addCategory(Intent.CATEGORY_LAUNCHER);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
// Create intent
final Intent putShortCutIntent = new Intent();
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent);
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_NAME, applicationName);
putShortCutIntent.putExtra(Intent.EXTRA_SHORTCUT_ICON_RESOURCE,
Intent.ShortcutIconResource.fromContext(newAppContext,
R.drawable.icon));
putShortCutIntent.setAction("com.android.launcher.action.INSTALL_SHORTCUT");
// Broadcast intent
context.sendBroadcast(putShortCutIntent);
}
EDIT:
Managed to achieve this by getting the Intent from PackageManager.getLaunchIntentForPackage(String packageName).
So:
// Intent shortcutIntent = new Intent (Intent.ACTION_MAIN);
// shortcutIntent.setClassName(newAppContext, newAppContext.getClass().getName());
// shortcutIntent.addCategory(Intent.CATEGORY_LAUNCHER);
// shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
// shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
Intent shorcutIntent = pm.getLaunchIntentForPackage(appName);

You will get "wrong activity class name", when it cannot find the main activity class in the package. It needs that info so that it can launch the correct Activity in the correct package. So in your example, it should be:
shortcutIntent.setClassName("com.android.calculator2", "ClassName");
I don't know what the "ClassName" should be for the Calculator application(maybe you can check its source code), but it should be something like "com.android.calculator2.MainActivity"
EDIT:
Ok, it seems it is possible to get the "ClassName" dynamically:
PackageManager packageManager = context.getPackageManager();
ResolveInfo info = packageManager.resolveActivity(shortcutIntent, 0);
if(info != null) {
shortcutIntent.setClassName(info.activityInfo.packageName, info.activityInfo.name);
}