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Double with specific format and two decimals

I'm trying to format the numbers to look like a certain way.
So, I have like the number 1007,2, and I want it to look like 1 007,20
This has two factors needed:
Thousands format
Two decimal places
I have a code that sets the thousands format:
Double total_value = Double.valueOf(1007,2);
String formatedValue = NumberFormat.getNumberInstance(Locale.CANADA_FRENCH).format(total_value);
And the output is:
1 007,2€
And I have the code for the two decimal places:
Double total_value = Double.valueOf(1007,2);
String formatedValue = String.format("%.2f", total_value);
The problem is, for using this two format methods at the same time they get always problems, because the two of them return Strings, and both need to receive the values for formatting in Double.
If I receive one in String, when I try to parse the String to Double like String value = Double.parseDouble(formatedValue);or String value = Double.valueOf(formatedValue) they always get an error. I've already tried the DecimalFormat to but it returns a String too.
So, I dont know how to do to conjugue the two methods to work together!
If you have any idea please comment it :)

You don't want to combine NumberFormat and String.format().
You can further configure your NumberFormat object to tell it to use two decimal places:
NumberFormat numberFormat = NumberFormat.getNumberInstance(Locale.CANADA_FRENCH);
numberFormat.setMinimumFractionDigits(2);
assertThat(numberFormat.format(1007.2), is("1 007,20"));
(and possibly setMaximumFractionDigits() etc., depending on your needs -- see the Javadoc)
Take care - NumberFormat.format() is not thread-safe.
Alternatively you can use String.format(locale, format, args):
assertThat(String.format(Locale.CANADA_FRENCH, "%,.2f", 1007.2), is("1 007,20"));
The , flag in the format tells the formatter to use a thousands-separator, and the locale tells it that the separator is a space.

After setting the thousand format you could do someting like:
String[] splitter = formatedValue.split("\\,");
int decimalDigits = 0;
if (splitter.length > 1) {
formatedValue = splitter[1].length();
} else {
formatedValue += ",";
}
for (int i = 0; i < 2 - decimalDigits; i++) {
formatedValue += "0";
}
I have not tested this, and it is not the really pretty, but i am using something similar for the english format.
To make sure you have only two decimal digits you should probably round your total value at the beginning.

Java - How to convert a large number into a number with less digits and "E" as done by calculators?

I want to use mathematical expression in my Android app, I am using int data types only. But sometimes the output of the expression gets too big to hold by a int. What kind of data type should I use to convert the large output into a number with "E" in it?

Generally, If you want to store very big numbers in memory (that are too big for an int) and possibly do some math with them you'd have to use something like java.math.BigInteger:
import java.math.*;
BigInteger number = new BigInteger("12345678954646565757"); // very large number
BigInteger anotherNumber = new BigInteger("5");
number = number.add(anotherNumber);
Then, If you want to format this value with a scientific notation, use NumberFormatter:
NumberFormat formatter = new DecimalFormat("0.######E0");
String str = formatter.format(number);
System.out.println(str); // prints "1.234568E19"

Parse double from JFormattedTextField

I've got a bug or something. I have a method that saves an article, like this:
class SaveArticleListener implements ActionListener {
//....
String s = textArticlePrice.getText().replace(',','.').replaceAll("\\s","");
double price = Double.parseDouble(s);
//....
}
Where textArticlePrice is a JFormattedTextField which configured like:
NumberFormat priceFormat = NumberFormat.getNumberInstance();
priceFormat.setMaximumFractionDigits(2);
priceFormat.setMinimumFractionDigits(2);
textArticlePrice = new JFormattedTextField(priceFormat);
textArticlePrice.setColumns(10);
And in the parseDouble method I'm getting every time:
java.lang.NumberFormatException: For input string: "123 456 789.00"
So replace works with a dot, but not with whitespace... Why?

You'd be better off using your NumberFormat to parse the String. Keep a reference to priceFormat, and then use
double price = priceFormat.parse(textArticlePrice.getText()).doubleValue();
The formatter that's being used to display the number is the same one then used to turn it back into a double so you know it's going to be parsing it in a compatible way.
Best of all is
double price = ((Number) textArticlePrice.getValue()).doubleValue();
which should work without any need for conversion if you've set your JFormattedTextField up properly. (The getValue() call returns an Object, so you need to cast it. It might return a Double or a Long, depending on what's in the text field, so the safe way to get a double out of it is to treat it as a Number, which is the supertype of both, and invoke its .doubleValue() method.)
Writing something that converts it into something that can be parsed by Double.parseDouble() is really not the right way to go because it's too fragile if the formatting of your text field changes later on.

Regarding your question" why doesn't it work with white spaces". White spaces are chars just like a,l,#,?,¡, but it only recognises ,12345, numbers together as a number, you cant make an int variable 'int number = 1 234; Its the same with parsing. Rather try,
s = s.replace(',','.');
s = s.replace(" ","");
Price = Double.parseDouble(s);
Assuming that '123 456 789.00' is one number.
please comment if this helped.

I did this now, it worked fine
String strNumber = "1 2 3 4 5 6.789";
double DblNumber = Double.parseDouble(strNumber);
System.out.Println(DblNumber);// this displays the number if your IDE has an output window

Double value with specific precision in java

I'm programming a simple java program. I need to get a string from input and divide it into two parts: 1-double 2-string.
Then I need to do a simple calculation on the double and send the result to the output with specific precision(4). It works fine, but there is a problem when the input is 0, then it doesn't work properly.
For example for these input, output will be:
1 kg
output:2.2046
3.1 kg
output:6.8343
But when the input is 0, the output should be 0.0000, but it shows 0.0 .
What should I do to force it to show 0.0000?
I read similar post about double precision, they suggest something like BigDecimal class, but I can't use them in this case,
my code for doing this is:
line=input.nextLine();
array=line.split(" ");
value=Double.parseDouble(array[0]);
type=array[1];
value =value*2.2046;
String s = String.format("%.4f", value);
value = Double.parseDouble(s);
System.out.print(value+" kg\n");

DecimalFormat will allow you to define how many digits you want to display. A '0' will force an output of digits even if the value is zero, whereas a '#' will omit zeros.
System.out.print(new DecimalFormat("#0.0000").format(value)+" kg\n"); should to the trick.
See the documentation
Note: if used frequently, for performance reasons you should instantiate the formatter only once and store the reference: final DecimalFormat df = new DecimalFormat("#0.0000");. Then use df.format(value).

add this instance of DecimalFormat to the top of your method:
DecimalFormat four = new DecimalFormat("#0.0000"); // will round and display the number to four decimal places. No more, no less.
// the four zeros after the decimal point above specify how many decimal places to be accurate to.
// the zero to the left of the decimal place above makes it so that numbers that start with "0." will display "0.____" vs just ".____" If you don't want the "0.", replace that 0 to the left of the decimal point with "#"
then, call the instance "four" and pass your double value when displaying:
double value = 0;
System.out.print(four.format(value) + " kg/n"); // displays 0.0000

System.out.format("%.4f kg\n", 0.0d) prints '0.0000 kg'

I suggest you to use the BigDecimal class for calculating with floating point values. You will be able to control the precision of the floating point arithmetic. But back to the topic :)
You could use the following:
static void test(String stringVal) {
final BigDecimal value = new BigDecimal(stringVal).multiply(new BigDecimal("2.2046"));
DecimalFormat df = new DecimalFormat();
df.setMaximumFractionDigits(4);
df.setMinimumFractionDigits(4);
System.out.println(df.format(value) + " kg\n");
}
public static void main(String[] args) {
test("0");
test("1");
test("3.1");
}
will give you the following output:
0,0000 kg
2,2046 kg
6,8343 kg

String.format is just makign a String representation of the floating point value. If it doesnt provide a flag for a minimum precision, then just pad the end of the string with zeros.

Use DecimalFormat to format your double value to fixed precision string output.
DecimalFormat is a concrete subclass of NumberFormat that formats
decimal numbers. It has a variety of features designed to make it
possible to parse and format numbers in any locale, including support
for Western, Arabic, and Indic digits. It also supports different
kinds of numbers, including integers (123), fixed-point numbers
(123.4), scientific notation (1.23E4), percentages (12%), and currency
amounts ($123). All of these can be localized.
Example -
System.out.print(new DecimalFormat("##.##").format(value)+" kg\n");

How can I format a String number to have commas and round?

What is the best way to format the following number that is given to me as a String?
String number = "1000500000.574" //assume my value will always be a String
I want this to be a String with the value: 1,000,500,000.57
How can I format it as such?

You might want to look at the DecimalFormat class; it supports different locales (eg: in some countries that would get formatted as 1.000.500.000,57 instead).
You also need to convert that string into a number, this can be done with:
double amount = Double.parseDouble(number);
Code sample:
String number = "1000500000.574";
double amount = Double.parseDouble(number);
DecimalFormat formatter = new DecimalFormat("#,###.00");
System.out.println(formatter.format(amount));

This can also be accomplished using String.format(), which may be easier and/or more flexible if you are formatting multiple numbers in one string.
String number = "1000500000.574";
Double numParsed = Double.parseDouble(number);
System.out.println(String.format("The input number is: %,.2f", numParsed));
// Or
String numString = String.format("%,.2f", numParsed);
For the format string "%,.2f" - "," means separate digit groups with commas, and ".2" means round to two places after the decimal.
For reference on other formatting options, see https://docs.oracle.com/javase/tutorial/java/data/numberformat.html

Given this is the number one Google result for format number commas java, here's an answer that works for people who are working with whole numbers and don't care about decimals.
String.format("%,d", 2000000)
outputs:
2,000,000

Once you've converted your String to a number, you can use
// format the number for the default locale
NumberFormat.getInstance().format(num)
or
// format the number for a particular locale
NumberFormat.getInstance(locale).format(num)

I've created my own formatting utility. Which is extremely fast at processing the formatting along with giving you many features :)
It supports:
Comma Formatting E.g. 1234567 becomes 1,234,567.
Prefixing with "Thousand(K),Million(M),Billion(B),Trillion(T)".
Precision of 0 through 15.
Precision re-sizing (Means if you want 6 digit precision, but only have 3 available digits it forces it to 3).
Prefix lowering (Means if the prefix you choose is too large it lowers it to a more suitable prefix).
The code can be found here. You call it like this:
public static void main(String[])
{
int settings = ValueFormat.COMMAS | ValueFormat.PRECISION(2) | ValueFormat.MILLIONS;
String formatted = ValueFormat.format(1234567, settings);
}
I should also point out this doesn't handle decimal support, but is very useful for integer values. The above example would show "1.23M" as the output. I could probably add decimal support maybe, but didn't see too much use for it since then I might as well merge this into a BigInteger type of class that handles compressed char[] arrays for math computations.

you can also use the below solution
public static String getRoundOffValue(double value){
DecimalFormat df = new DecimalFormat("##,##,##,##,##,##,##0.00");
return df.format(value);
}

public void convert(int s)
{
System.out.println(NumberFormat.getNumberInstance(Locale.US).format(s));
}
public static void main(String args[])
{
LocalEx n=new LocalEx();
n.convert(10000);
}

You can do the entire conversion in one line, using the following code:
String number = "1000500000.574";
String convertedString = new DecimalFormat("#,###.##").format(Double.parseDouble(number));
The last two # signs in the DecimalFormat constructor can also be 0s. Either way works.

Here is the simplest way to get there:
String number = "10987655.876";
double result = Double.parseDouble(number);
System.out.println(String.format("%,.2f",result));
output:
10,987,655.88

The first answer works very well, but for ZERO / 0 it will format as .00
Hence the format #,##0.00 is working well for me.
Always test different numbers such as 0 / 100 / 2334.30 and negative numbers before deploying to production system.

According to chartGPT
Using DecimalFormat:
DecimalFormat df = new DecimalFormat("#,###.00");
String formattedNumber = df.format(yourNumber);
Using NumberFormat:
NumberFormat nf = NumberFormat.getNumberInstance();
nf.setGroupingUsed(true);
String formattedNumber = nf.format(yourNumber);
Using String.format():
String formattedNumber = String.format("%,.2f", yourNumber);
Note: In all the above examples, "yourNumber" is the double value that you want to format with a comma. The ".2f" in the format string indicates that the decimal places should be rounded to 2 decimal places. You can adjust this value as needed.