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Replace Text inside PowerPoint using Java

I have a PPT containing values in the format: {VALUES}. I would like to replace the text of the file containing {SAMPLE} to SARAN and so on using Java. Earlier I tried with Apache poi and I had no solution but I could find that in Docx4j there is an method variableReplace() which will replace the text. I tried one sample but I don't see any text being replaced.
My code:
public static void main(String[] args) throws IOException, Docx4JException, Pptx4jException, JAXBException
{
String inputfilepath = "C:\\Work\\SampleTemplate.pptx";
PresentationMLPackage pptPackage
= PresentationMLPackage.load(new File(inputfilepath));
ThemePart themeSlidePart = (ThemePart)
pptPackage.getParts().getParts().get(new PartName("/ppt/theme/theme1.xml"));
Theme themeOfSlides = (Theme)themeSlidePart.getJaxbElement();
SlidePart slide = pptPackage.getMainPresentationPart().getSlide(0);
HashMap h = new HashMap<String, String>();
h.put("SlideTitleName", "SARANYA");
slide.variableReplace(h);
String outputfilepath = "C:\\Work\\24Jan2018_CheckOut\\dhl\\PPT-TRAILS\\SampleTemplate.pptx";
PresentationMLPackage pptPackagetoApply
= PresentationMLPackage.load(new File(outputfilepath));
ThemePart themeSlidePartToApply
= (ThemePart) pptPackagetoApply.getParts().getParts()
.get(new PartName("/ppt/theme/theme1.xml"));
themeSlidePartToApply.setJaxbElement(themeOfSlides);
SaveToZipFile saver = new SaveToZipFile(pptPackagetoApply);
saver.save(outputfilepath);
}
But still text is not being replaced. I tried with a new PPTX file with only text "${SlideTitleName}" inside it. But still it's not working.
I would like to add many rows to my pptx template using for loop, I tried the below,
Java:
if(majorAchievements.size()>0){
System.out.println("majorAchievements Size in Servlet is : "+majorAchievements.size() + " and value of get(0) is : "+ majorAchievements.get(0) );
for(int i=0;i<majorAchievements.size();i++){
achievements=(String) majorAchievements.get(i);
}
}
mappings.put("MajorAchievementText", achievements);
and inside my ppt file ,
i haved added two rows with same ${MajorAchievementText}.
The above list fetches 2 rows. But inside ppt it is not replace.
Please help me how to replace an text by iterating.
With Regards,
Saranya C

extract URL location from an xml link in java

I'm new in java and i have a link "https://moz.com/blog-sitemap.xml" that has URLs ,i want to get them and save them in a string vector/array.
i tried this first to see how i'm going to get the links
URL robotFile = new URL("https://moz.com/blog-sitemap.xml");
//read robot.txt line by line
Scanner robotScanner = new Scanner(robotFile.openStream());
while (robotScanner.hasNextLine()) {
System.out.println(robotScanner.nextLine());
}
this is the sample output
my answer is ,is there a simple easier way to get these links instead of looping on each line checking if it contains "https" so i can extract the link from it ?

You can use Jsoup to do this more easly:
List<String> urlList = new ArrayList<>();
Document doc = Jsoup.connect("https://moz.com/blog-sitemap.xml").get();
Elements urls = doc.getElementsByTag("loc");
for (Element url : urls) {
urlList.add(url.text());
}

Swing Code to copy data from 2 text area to clipboard

[![enter image description here][1]][1]I am new to Java Swing. I have a create a GUI layout will 2 text areas and a button "copy to clipboard". I have a code that will copy the contents of first text area to clipboard, but not sure how to add the content in second text area and the labels corresponding to jtext area.
String get= hActionText.getText();
StringSelection selec= new StringSelection(get);
Clipboard clipboard = Toolkit.getDefaultToolkit().getSystemClipboard();
clipboard.setContents(selec, selec);

If I understood what are you trying, you are trying to put the values of both of your fields on the clipboard, and than read them and populate the fields again.
The clipboard is way too simple for that, it can only hold one String basically. What I propose is to create a structure you will put on the clipboard, and which structure is better for describing data as a String than JSON :-) . Just create JSON content like this:
[
{
"label":"field1",
"content":"contentFromField1"
},
{
"label":"field2",
"content":"contentFromField2"
}
]
And put it on the clipboard. Of course, you always have to check after reading the clipboard is the content actually deserializable.
For creating content like this you can use a Java library like json-simple . A simple example with the content like above:
JSONObject obj1 = new JSONObject();
obj1.put("label", "field1");
obj1.put("content", "contentFromField1);
JSONObject obj2 = new JSONObject();
obj2.put("label", "field2");
obj2.put("content", "contentFromField2);
JSONArray list = new JSONArray();
list.add(obj1);
list.add(obj2);

please help me with concatenation?
This is basic java that I'm sure you use all the time:
String textForClipboard = label1.getText() + ":" + label2.getText();
Or you could use a StringBuilder:
StringBuilder sb = new StringBuilder();
sb.append( labe1.getText() );
sb.append( ":" );
sb.append( label2.getText() );
Then when you get the data from the clipboard you need to parse it. You could use the String.split(...) method.

java data structure to replace file io

My program goes to a my uni results page, finds all the links and saves to a file. Then I read the file and copy only lines which contain required links and save it to another file. Then I parse it again to extract required data
public class net {
public static void main(String[] args) throws Exception {
Document doc = Jsoup.connect("http://jntuconnect.net/results_archive/").get();
Elements links = doc.select("a");
File f1 = new File("flink.txt");
File f2 = new File("rlink.txt");
//write extracted links to f1 file
FileUtils.writeLines(f1, links);
// store each link from f1 file in string list
List<String> linklist = FileUtils.readLines(f1);
// second string list to store only required link elements
List<String> rlinklist = new ArrayList<String>();
// loop which finds required links and stores in rlinklist
for(String elem : linklist){
if(elem.contains("B.Tech") && (elem.contains("R07")||elem.contains("R09"))){
rlinklist.add(elem);
}
}
//store required links in f2 file
FileUtils.writeLines(f2, rlinklist);
// parse links from f2 file
Document rdoc = Jsoup.parse(f2, null);
Elements rlinks = rdoc.select("a");
// for storing hrefs and link text
List<String> rhref = new ArrayList<String>();
List<String> rtext = new ArrayList<String>();
for(Element rlink : rlinks){
rhref.add(rlink.attr("href"));
rtext.add(rlink.text());
}
}// end main
}
I don't want to create files to do this. Is there a better way to get hrefs and link texts of only specific urls without creating files?
It uses Apache commons fileutils, jsoup

Here's how you can get rid of the first file write/read:
Elements links = doc.select("a");
List<String> linklist = new ArrayList<String>();
for (Element elt : links) {
linklist.add(elt.toString());
}
The second round trip, if I understand the code, is intended to extract the links that meet a certain test. You can just do that in memory using the same technique.
I see you're relying on Jsoup.parse to extract the href and link text from the selected links. You can do that in memory by writing the selected nodes to a StringBuffer, convert it to a String by calling it's toString() method, and then using one of the Jsoup.parse methods that takes a String instead of a File argument.

xpath: write to a file

I'm developing Java code to get data from a website and store it in a file. I want to store the result of xpath into a file. Is there any way to save the output of the xpath? Please forgive for any mistakes; this is my first question.
public class TestScrapping {
public static void main(String[] args) throws MalformedURLException, IOException, XPatherException {
// URL to be fetched in the below url u can replace s=cantabil with company of ur choice
String url_fetch = "http://www.yahoo.com";
//create tagnode object to traverse XML using xpath
TagNode node;
String info = null;
//XPath of the data to be fetched.....use firefox's firepath addon or use firebug to fetch the required XPath.
//the below XPath will display the title of the company u have queried for
String name_xpath = "//div[1]/div[2]/div[2]/div[1]/div/div/div/div/table/tbody/tr[1]/td[2]/text()";
// declarations related to the api
HtmlCleaner cleaner = new HtmlCleaner();
CleanerProperties props = new CleanerProperties();
props.setAllowHtmlInsideAttributes(true);
props.setAllowMultiWordAttributes(true);
props.setRecognizeUnicodeChars(true);
props.setOmitComments(true);
//creating url object
URL url = new URL(url_fetch);
URLConnection conn = url.openConnection(); //opening connection
node = cleaner.clean(new InputStreamReader(conn.getInputStream()));//reading input stream
//storing the nodes belonging to the given xpath
Object[] info_nodes = node.evaluateXPath(name_xpath);
// String li= node.getAttributeByName(name_xpath);
//checking if something returned or not....if XPath invalid info_nodes.length=0
if (info_nodes.length > 0) {
//info_nodes[0] will return string buffer
StringBuffer str = new StringBuffer();
{
for(int i=0;i<info_nodes.length;i++)
System.out.println(info_nodes[i]);
}
/*str.append(info_nodes[0]);
System.out.println(str);
*/
}
}
}

You can "simply" print the nodes as strings, to console/or a file --
example in Perl:
my $all = $XML_OBJ->find('/'); # selecting all nodes from root
foreach my $node ($all->get_nodelist()) {
print XML::XPath::XMLParser::as_string($node);
}
note: this output however may not be nicely xml-formatted/indented

The output of an XPath in Java is a nodeset, so yes, once you have a nodeset you can do anything you want with it, save it to a file, process it some more.
Saving it to a file would involve the same steps in java that saving anything else to a file involve, there is no difference between that and and any other data. Select the nodeset, itterate through it, get the parts you want from it and write them to some kind of file stream.
However, if you mean is there a Nodeset.SaveToFile(), then no.

I would recommend you to take the NodeSet, which is a collection of Nodes, iterate on it, and add it to a created DOM document object.
After this, you can use the TransformerFactory to get a Transformer object, and to use its transform method. You should transform from a DOMSource to a StreamResult object which can be created based on FileOutputStream.