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APP_INDEX Column is not update properly

Currently I am working on a java project where they used hibernate with JPA. One of my table have a column APP_INDEX and this column automatically increase value when we do an insert. This order should not have gaps. But when I remove an record its not automatically change the order. so I am getting errors when I try to read records from the table. Just wonder why for delete APP_INDEX does not change properly. I just wonder I need to add any mapping for this according to JPA spec
Table data
id name APP_INDEX
001 AA 0
002 BB 1
003 CC 2
I am deleting 002 record
Expected result
id name APP_INDEX
001 AA 0
003 CC 1
But I am getting
id name APP_INDEX
001 AA 0
003 CC 2

Oracle order by via JPA with numeric first

I have column data like this in my db
data
-----
1
2
A
3
4
B
I have below nls settings in place
SELECT * From NLS_SESSION_PARAMETERS;
NLS_LANGUAGE AMERICAN
NLS_TERRITORY AMERICA
NLS_CURRENCY $
NLS_ISO_CURRENCY AMERICA
NLS_ISO_CURRENCY AMERICA
NLS_NUMERIC_CHARACTERS .,
NLS_CALENDAR GREGORIAN
NLS_DATE_FORMAT DD-MON-RR
NLS_DATE_LANGUAGE AMERICAN
NLS_SORT BINARY
NLS_COMP BINARY
When I query the db for **select data from <mytable> order by data ** I am getting the result as below
data
-----
1
2
3
4
A
B
The same query via hibernate is giving the results with alphabets first and numeric later
data
-----
A
B
1
2
3
4
But, I want column to be displayed with numbers first and alphabets later via hibernate
data
------
1
2
3
4
A
B
Can someone help me with this.

You can use regularexpressions to sort in such a way,
select data from <mytable> order by REGEXP_REPLACE(data ,'[^0-9]'), REGEXP_REPLACE(data ,'[0-9]')

That depends on NLS_SORT parameter's value. For example, in my database it is set to CROATIAN and the result is what you wanted:
SQL> select * From nls_session_parameters where parameter = 'NLS_SORT';
PARAMETER VALUE
-------------------- --------------------
NLS_SORT CROATIAN
SQL> with test (data) as
2 (select '1' from dual union all
3 select '2' from dual union all
4 select 'A' from dual union all
5 select '3' from dual union all
6 select '4' from dual union all
7 select 'B' from dual
8 )
9 select data
10 from test
11 order by data;
D
-
A
B
1
2
3
4
6 rows selected.
However, in your database, NLS_SORT = BINARY. Let's try it:
SQL> alter session set nls_sort = 'BINARY';
Session altered.
SQL> with test (data) as
2 (select '1' from dual union all
3 select '2' from dual union all
4 select 'A' from dual union all
5 select '3' from dual union all
6 select '4' from dual union all
7 select 'B' from dual
8 )
9 select data
10 from test
11 order by data;
D
-
1
2
3
4
A
B
6 rows selected.
SQL>
Right; the wrong result.
Therefore, modify NLS_SORT, if that's an option. See valid values by
SQL> select * From v$nls_valid_values where parameter = 'SORT';
PARAMETER VALUE ISDEP
-------------------- -------------------- -----
SORT BINARY FALSE
SORT WEST_EUROPEAN FALSE
SORT XWEST_EUROPEAN FALSE
SORT GERMAN FALSE
<snip>

I believe one of the two options below should work,
Use NLSSORT function in the order by clause explicitly.
select * from my_table order by NLSSORT(data,'NLS_SORT=BINARY');
Create a function based index on the column,
create index mytable_nlssort_index on my_table(nlssort(data, 'nls_sort=''BINARY'''))
Use the query as below when the column is indexed.
select data from my_table order by data;

FOREACH in cypher - neo4j

I am very new to CYPHER QUERY LANGUAGE AND i am working on relationships between nodes.
I have a CSV file of table containing multiple columns and 1000 rows.
Template of my table is :
cdrType ANUMBER BNUMBER DUARTION
2 123 456 10
2 890 456 5
2 123 666 2
2 123 709 7
2 345 789 20
I have used these commands to create nodes and property keys.
LOAD CSV WITH HEADERS FROM "file:///2.csv" AS ROW
CREATE (:ANUMBER {aNumber:ROW.aNumber} ),
CREATE (:BNUMBER {bNumber:ROW.bNumber} )
Now I need to create relation between all rows in the table and I think FOREACH loop is best in my case. I created this query but it gives me an error. Query is :
MATCH (a:ANUMBER),(b:BNUMBER)
FOREACH(i in RANGE(0, length(ANUMBER)) |
CREATE UNIQUE (ANUMBER[i])-[s:CALLED]->(BNUMBER[i]))
and the error is :
Invalid input '[': expected an identifier character, whitespace,
NodeLabel, a property map, ')' or a relationship pattern (line 3,
column 29 (offset: 100)) " CREATE UNIQUE
(a:ANUMBER[i])-[s:CALLED]->(b:BNUMBER[i]))"
I need relation for every row. like in my case. 123 - called -> 456 , 890 - called -> 456. So I need visual representation of this calling data that which number called which one. For this I need to create relation between all rows.
any one have idea how to solve this ?

What about :
LOAD CSV WITH HEADERS FROM "file:///2.csv" AS ROW
CREATE (a:ANUMBER {aNumber:ROW.aNumber} )
CREATE (b:BNUMBER {bNumber:ROW.bNumber} )
MERGE (a)-[:CALLED]->(b);
It's not more complex than that i.m.o.
Hope this helps !
Regards,
Tom

Hibernate criteria to fetch the records?

I have below records in table.
col1 col2 col3
------------------------
1 Abc IN
2 DEF CA
3 Xyz IN
4 Cae CA
5 Pty IN
6 Zwe DE
7 Zwf US
Here User sends an Input like IN or CA or DE etc. User input has to be mapped against col3. Now I need to query all the records from the table but the records matching the user input (IN or CA or DE) should appear first in the list then all other records should appear. How can I do it using hibernate criteria?
I need the results in below the order if user sends IN as an input.
1 Abc IN
5 Pty IN
3 Xyz IN
2 DEF CA
4 Cae CA
6 Zwe DE
7 Zwf US

You could try to use ORDER BY CASE construct:
order by case when <your entity>.col3 = :parameter then '0' else '1' end asc

There are two ways to solve this problem:
1. Create two queries one with equal to another with not equal to and all results for both in single list.
2. If you don't want to query database twice then you have to write algo in java that will remove elements for your input from list and add it another list and after iteration add remaining list at the end.

try the case ... when statements:
select *, ( case when col3=:input then '0' | col3 else col3 end) as sorter from table order by sorter asc
not sure, if it works, but if it does it would be exactly what you want

Select single row for column value

Here is sample table data which is dynamic.
ColId Name JobId Instance
1 aaaaaaaaa 1 2dc757b
2 bbbbbbbbb 1 2dc757b
3 aaaaaaaaa 1 010dbb8
4 bbbbbbbbb 1 010dbb8
5 bbbbbbbbb 1 faa2733
6 aaaaaaaaa 1 faa2733
7 aaaaaaaaa 1 bc13d69
8 aaaaaaaaa 1 9428f4d
I want output like
ColId Name JobId Instance
1 aaaaaaaaa 1 2dc757b
3 aaaaaaaaa 1 010dbb8
5 bbbbbbbbb 1 faa2733
7 aaaaaaaaa 1 bc13d69
8 aaaaaaaaa 1 9428f4d
What should be the JPA query so that I can retrieve entire row having only single 'Instance'(there is no max min condition involved).
I need one row for each 'Instance' value

FROM table t GROUP BY t.instance should suit your needs.

Something like JPQL "Select entity from Entity entity where entity.id in (select min(subinstance.id) from Entity subinstance group by subinstance.instance)"
Functions like count, min, avg etc are allowed over columns not included in the group by statement, so any such should work if it returns a single id value from the grouping.