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Decode google translate API response in JAVA

I need to write a small tool in JAVA which will translate text from English to French using the Google translate API. Everything works but I have an apostrophe decoding problem.
Original text:
Inherit Tax Rate
Text translated with Google translate API:
Taux d' imposition hérité
How it should be:
Taux d'imposition hérité
This is my translate method(sorry for the long method):
private String translate(String text, String from, String to) {
StringBuilder result = new StringBuilder();
try {
String encodedText = URLEncoder.encode(text, "UTF-8");
String urlStr = "https://www.googleapis.com/language/translate/v2?key=" + sKey + "&q=" + encodedText + "&target=" + to + "&source=" + from;
URL url = new URL(urlStr);
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
InputStream googleStream;
if (conn.getResponseCode() == 200) {
googleStream = conn.getInputStream(); //success
} else
googleStream = conn.getErrorStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(googleStream));
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
JsonParser parser = new JsonParser();
JsonElement element = parser.parse(result.toString());
if (element.isJsonObject()) {
JsonObject obj = element.getAsJsonObject();
if (obj.get("error") == null) {
String translatedText = obj.get("data").getAsJsonObject().
get("translations").getAsJsonArray().
get(0).getAsJsonObject().
get("translatedText").getAsString();
return translatedText;
}
}
if (conn.getResponseCode() != 200) {
System.err.println(result);
}
} catch (IOException | JsonSyntaxException ex) {
System.err.println(ex.getMessage());
}
return null;
}
I'm using an XML writer to write the text and first I though that this has a problem, but I observed that the text is returned like this in the stream so I introduced the encoding parameter when I initialise the InputStreamReader:
BufferedReader reader = new BufferedReader(new InputStreamReader(googleStream, "UTF-8"));
But I receive the string with the same problem. Any ideas about what I can do?

I think this problem is solved by using the format parameter (docs). It defaults to html, but you can change it to text to receive unencoded data. Your request should look like this:
String urlStr = "https://www.googleapis.com/language/translate/v2?key=" + sKey + "&q=" + encodedText + "&target=" + to + "&source=" + from + "&format=text";

Constant 401 error with OAuth1 (MCM API)

I've been trying to establish a connection with an API for more than a week now, to no avail. (Magic Card Market's, authentification documentation here and there). I'm supposed to receive a XML file.
I have what MCM call a "widget" access to their API, meaning that I don't have nor need a oauth_token (it's supposed to be an empty string) for the authorization header, and that I'm not supposed to receive nor use an access token/access secret.
The only things I do have are a consumer key (they call it app token sometimes) and a consumer secret.
Here is how I build my Authorization header :
private static String buildOAuthAuthorization(String method, String request)
throws UnsupportedEncodingException, NoSuchAlgorithmException, InvalidKeyException {
String mkmAppToken = APICredentials.appToken;
String mkmAppSecret = APICredentials.appSecret;
String realm = "https://www.mkmapi.eu/ws/v1.1/games";
String oauthVersion = "1.0";
String oauthConsumerKey = mkmAppToken;
String oauthToken = "";
String oauthSignatureMethod = "HMAC-SHA1";
String oauthTimestamp = Long.toString(System.currentTimeMillis() / 1000);
String oauthNonce = Long.toString(System.currentTimeMillis());
String paramString = "oauth_consumer_key=" + oauthConsumerKey
+ "oauth_nonce=" + oauthNonce
+ "oauth_signature_method=" + oauthSignatureMethod
+ "oauth_timestamp=" + oauthTimestamp
+ "oauth_token=" + oauthToken
+ "oauth_version=" + oauthVersion;
String baseString = method + "&" + rawUrlEncode(realm) + "&" + rawUrlEncode(paramString);
String signingKey = rawUrlEncode(mkmAppSecret) + "&";
Mac mac = Mac.getInstance("HMAC-SHA1");
SecretKeySpec secret = new SecretKeySpec(signingKey.getBytes(), mac.getAlgorithm());
mac.init(secret);
byte[] digest = mac.doFinal(baseString.getBytes());
byte[] oauthSignature = Base64.encode(digest, Base64.URL_SAFE);
String authorizationProperty = "OAuth "
+ "realm=\"" + realm + "\", "
+ "oauth_version=\"" + oauthVersion + "\", "
+ "oauth_timestamp=\"" + oauthTimestamp + "\", "
+ "oauth_nonce=\"" + oauthNonce + "\", "
+ "oauth_consumer_key=\"" + oauthConsumerKey + "\", "
+ "oauth_token=\""+ oauthToken + "\", "
+ "oauth_signature_method=\"" + oauthSignatureMethod + "\", "
+ "oauth_signature=\"" + oauthSignature + "\"";
System.out.println(authorizationProperty);
return authorizationProperty;
}
The actual request is in an AsyncTask :
public static class oAuthRequest extends AsyncTask<String, Integer, StringReader> {
private int lastCode;
#Override
protected StringReader doInBackground(String... requestURLs) {
String method = requestURLs[0];
String url = requestURLs[1];
StringReader result = null;
try {
String authProperty = buildOAuthAuthorization(method, url);
HttpURLConnection connection = (HttpURLConnection) new URL(url).openConnection();
connection.addRequestProperty("Authorization:", authProperty);
lastCode = connection.getResponseCode();
System.out.println("RESPONSE CODE 1 " + lastCode);
// Get content
BufferedReader rd = new BufferedReader(new InputStreamReader(lastCode == 200 ? connection.getInputStream() : connection.getErrorStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = rd.readLine()) != null) {
sb.append(line);
}
rd.close();
result = new StringReader(sb.toString());
} catch (NoSuchAlgorithmException | InvalidKeyException | IOException e) {
e.printStackTrace();
}
return result;
}
}
It seems like no matter what I change, I'm always getting a 401.
Things I've tried :
oauthSignature as a String using Base64.encodeToString()
Nonce generation using SecureRandom
With and without the empty oauthToken
Another timestamp generation method (can't remember what though)
signing key with and without app token (theorically I need only the consumer secret, but you never know)
Using HttpsURLConnection instead of HttpURLConnection (the URI start in https, so I thought, hey. But no)
At least 2-3 other different implementations (one who was basically a copy/paste of the Java example in the documentation of course -- it still kind of is one now)
(Probably a lot of things I can't even remember)
At this point I'm wondering if maybe the issue comes from my keys, as I've tried to use the Postman app to test requests with the same results.

Passing value from applet to PHP

I want to send values of two variables to a PHP file from a Java applet), and I tried the following code.
try {
URL url = new URL(getCodeBase(),"abc.php");
URLConnection con = url.openConnection();
con.setDoOutput(true);
PrintStream ps = new PrintStream(con.getOutputStream());
ps.print("score="+score);
ps.print("username="+username);
con.getInputStream();
ps.close();
} catch (Exception e) {
g.drawString(""+e, 200,100);
}
I got the following error:
java.net.UnknownServiceException:protocol doesn't support output

java.net.UnknownServiceException:protocol doesn't support output
Means that you are using a protocol that doesn't support output.
getCodeBase() refers to a file url, so something like
file:/path/to/the/applet
The protocol is file, which doesn't support outout. You are looking for a http protocol, which supports output.
Maybe you wanted getDocumentBase(), which actually returns the web page where the applet is, i.e.
http://www.path.to/the/applet

Here's some code I used with my own applet, to send values (via POST) to a PHP script on my server:
I would use it like this:
String content = "";
content = content + "a=update&gid=" + gid + "&map=" + getMapString();
content = content + "&left_to_deploy=" + leftToDeploy + "&playerColor=" + playerColor;
content = content + "&uid=" + uid + "&player_won=" + didWin;
content = content + "&last_action=" + lastActionCode + "&appletID=" + appletID;
String result = "";
try {
result = requestFromDB(content);
System.out.println("Sending - " + content);
} catch (Exception e) {
status = e.toString();
}
As you can see, I am adding up all my values to send into a "content" string, then calling my requestFromDB method (which posts my "request" values, and returns the server's response) :
public String requestFromDB(String request) throws Exception
{
// This will accept a formatted request string, send it to the
// PHP script, then collect the response and return it as a String.
URL url;
URLConnection urlConn;
DataOutputStream printout;
DataInputStream input;
// URL of CGI-Bin script.
url = new URL ("http://" + siteRoot + "/globalconquest/applet-update.php");
// URL connection channel.
urlConn = url.openConnection();
// Let the run-time system (RTS) know that we want input.
urlConn.setDoInput (true);
// Let the RTS know that we want to do output.
urlConn.setDoOutput (true);
// No caching, we want the real thing.
urlConn.setUseCaches (false);
// Specify the content type.
urlConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
// Send POST output.
printout = new DataOutputStream (urlConn.getOutputStream ());
printout.writeBytes (request);
printout.flush ();
printout.close ();
// Get response data.
input = new DataInputStream (urlConn.getInputStream ());
String str;
String a = "";
while (null != ((str = input.readLine())))
{
a = a + str;
}
input.close ();
System.out.println("Got " + a);
if (a.trim().equals("1")) {
// Error!
mode = "error";
}
return a;
} // requestFromDB
In my PHP script, I would only need to look at $_POST for my values. Then I would just print a response.
Note! Your PHP script MUST be on the same server as the applet for security reasons, or this will not work.

Sending post attributes and xml data with a post request?

New to java, GWT and interacting with APIs. I have what I hope is a simple question.
I have successfully interacted with a REST API using the following curl command:
curl -d "OPERATION_NAME=ADD_REQUEST&TECHNICIAN_KEY=xxxxxxxxxxx&INPUT_DATA=<?xml version=%221.0%22 encoding=%22utf-8%22?><Operation><Details><requester>Me</requester><subject>Test</subject><description>Testing curl input</description></Details></Operation>" http://xx.xx.xx.xx/sdpapi/request/
Now, from a tutorial, I have the following code that I am hoping will post a request to the remote server just like the curl command above.
What I am trying to figure out (with no love from google) is how I pass the OPERATION_NAME, TECHNICIAN_KEY and INPUT_DATA parameters in when I am sending the URL. Any suggestions, tutorials, etc. will be appreciated.
The following is from my server side implementation interface:
#Override
public String postToRemoteServer(String serviceUrl)
throws HelpDeskTestException {
try {
//dividing url into host: http://some.server
//path: a/path/in/it
//and parameters: this=that&those=others
int hostStart= serviceUrl.indexOf("//");
int pathStart= serviceUrl.substring(hostStart + 2).indexOf("/");
int parameterStart= serviceUrl.substring(hostStart + 2 + pathStart).indexOf("?");
final String serverHost= serviceUrl.substring(0, hostStart + pathStart + 2);
final String serverPath= serviceUrl.substring(hostStart + 3,
hostStart + pathStart + 2 + parameterStart);
final String serverParameters= serviceUrl.substring(hostStart + pathStart + 3 + parameterStart);
final URL url = new URL(serverHost);
final URLConnection connection= url.openConnection();
connection.setDoOutput(true);
final OutputStreamWriter out= new OutputStreamWriter(connection.getOutputStream());
final BufferedReader in= new BufferedReader(new InputStreamReader(
connection.getInputStream()));
out.write("POST " + serverPath + "\r\n");
out.write("Host: " + serverHost + "\r\n");
out.write("Accept-Encoding: identity\r\n");
out.write("Connection: close\r\n");
out.write("Content-Type: application/x-www-form-urlencoded\r\n");
out.write("Content-Length: " + serverParameters.length() + "\r\n\r\n" +
serverParameters + "\r\n");
String result = "";
String inputLine;
while ((inputLine=in.readLine()) != null) {
result+= inputLine;
}
in.close();
out.close();
return result;
} catch (final Exception e) {
throw new HelpDeskTestException();
}

Consider using this library: Apache HttpClient. Here is an example of making a POST request with it.

URL manipulation

I want to do a little manipulation with URLs.
It is required to add a sub domain in already created URL like shown below
Inputs
String inputURL = "http://www.myhost.com";
String subdomain = "newlocation";
output
String output = "http://www.newlocation.myhost.com";
I was thinking if there is any existing utility class that can do this for me. expert can have something to say.
Thanks for your help !

Note that "www" is also subdomain. So you are actually appending another subdomain.
String inputURL = "http://www.myhost.com";
String subdomain = "newlocation";
URL url = new URL(inputURL);
String[] domainParts = url.getHost().split("\\.");
StringBuilder sb = new StringBuilder();
for (int i = 0; i < domainParts.length; i ++) {
if (i == 1) {
sb.append(subdomain + ".");
}
sb.append(domainParts[i] + ".");
}
String query = "";
String port = "";
if (url.getQuery() != null) {
query = "?" + url.getQuery();
}
if (url.getPort() != -1) {
port = url.getPort() + "";
}
String output = url.getProtocol() + ":" + port + "//" + sb.toString() + "/" + url.getPath() + query;
System.out.println(output);

It is sufficient to parse only the host part of the URL and use the URI to render.
URL url = new URL(inputURL);
String host = url.getHost().replaceAll("(([.][^.]+){2,2})$", "." + subdomain + "$1");
String newUrl = new URI(url.getProtocol(), host, url.getPath(), url.getQuery(), null).toString();

Perhaps:
String output = inputURL.replaceAll("(http://[^.]+\\.)(.*)", "$1" + subdomain + ".$2");

Look at StringBuffer (Link to the Java API doc) and then you will probably need to use one of the insert() methods