This question already has answers here:
Convert string to date then format the date
(8 answers)
Closed 9 years ago.
Given DateTime, how to format date in the following format ?
12 JUL 2013
in c#, you do this
string formatedDateString = String.Format("{0:dd MMM yyyy}", myDateTime);
What is the equivalent code in JAVA ?
And date represents instance of java.util.Date
String formattedDate = new SimpleDateFormat("dd MMM yyyy").format(date);
Use a SimpleDateFormat. Along the lines of
(new SimpleDateFormat("dd MMM yyyy")).parse("12 JUL 2013");
(new SimpleDateFormat("dd MMM yyyy")).format(new Date());
I would use the localized approach as described here:
String formattedDate = DateFormat.getDateInstance().format(date);
Related
This question already has answers here:
Java convert date format [duplicate]
(3 answers)
display Java.util.Date in a specific format
(11 answers)
Closed 2 years ago.
I have string date 2020-07-05 22:44:59 in string format, I parse it with SimpleDateFormat with
"yyyy-MM-dd HH:mm:ss a z" date pattern but it gives me date like Sun Jul 05 22:44:59 IST 2020.
So how I can get date in "yyyy-MM-dd HH:mm:ss a z" format in date object.
Input : 2020-07-05 22:44:59
Output : 2020-07-05 22:44:59
I want output int the same format like input.
Thanks for Helping me.
String input = "2020-07-05 22:44:59";
DateFormat parser = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
Date date = parser.parse(input);
DateFormat formatter = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String output = formatter.format(date);
This question already has answers here:
How can I change the date format in Java? [duplicate]
(10 answers)
Change date format in a Java string
(22 answers)
Java string to date conversion
(17 answers)
Closed 4 years ago.
I am getting two date fields from JSON as text like this May 22 12:05:41 UTC 2018 and 2018-05-22 12:05:41.512 but I have to change to MM-dd-yyyy HH:mm:ss format.
Just to be clear - date/time objects are format agnostic. They are simply containers for the amount of time which has passed since a fixed point in time (usually the Unix Epoch), so you can't change their format per se.
However, you can, generate a String of a prescribed pattern.
When dealing with date/time in Java you should make use of the date/time APIs introduced in Java 8 (or the ThreeTen back port)
For example...
String date1 = "May 22 12:05:41 UTC 2018";
DateTimeFormatter format1 = DateTimeFormatter.ofPattern("MMM dd HH:mm:ss z yyyy", Locale.ENGLISH);
LocalDateTime ldt1 = LocalDateTime.parse(date1, format1);
String date2 = "2018-05-22 12:05:41.512";
DateTimeFormatter format2 = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss.SSS", Locale.ENGLISH);
LocalDateTime ldt2 = LocalDateTime.parse(date2, format2);
DateTimeFormatter format3 = DateTimeFormatter.ofPattern("MM-dd-yyyy HH:mm:ss", Locale.ENGLISH);
System.out.println(ldt1.format(format3));
System.out.println(ldt2.format(format3));
Which outputs...
05-22-2018 12:05:41
05-22-2018 12:05:41
Since one of your inputs has a timezone associated with it, it would be appropriate to take it into consideration
ZonedDateTime zdt = ZonedDateTime.parse(date1, format1);
LocalDateTime ldt1 = zdt.withZoneSameInstant(ZoneId.systemDefault()).toLocalDateTime();
which outputs (for my current location)
05-22-2018 22:05:41
You can use this code
DateFormat format = new SimpleDateFormat("MM-dd-yyyy HH:mm:ss");
DateFormat inputFormat1 = new SimpleDateFormat("MMM dd HH:mm:ss z yyyy");
DateFormat inputFormat2 = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSS");
String date1 = "May 22 12:05:41 UTC 2018";
String date2 = "2018-05-22 12:05:41.512";
System.out.println(format.format(inputFormat1.parse(date1)));
System.out.println(format.format(inputFormat2.parse(date2)));
This question already has answers here:
Setting date into "dd"-"mm"-"yy" format from "dd"-"mm"-"yyyy" in java
(4 answers)
Closed 6 years ago.
I have a date in the format 11-NOV-13
When i convert the date i get the value Sat Nov 11 00:00:00 IST 13.
But i want the converted date to be in the format Sat Nov 11 00:00:00 IST 2013.
Though i have used the dateformat it is not taking it. Can anyone point me where i am wrong?
Below is the code i have been working on
DateFormat format = new SimpleDateFormat("dd-MMM-yyyy", Locale.ENGLISH);
Date myDate = format.parse("11-NOV-13");
Change the format to:
DateFormat format = new SimpleDateFormat("dd-MMM-yy", Locale.ENGLISH);
You need to make the year 2 numbers:
DateFormat format = new SimpleDateFormat("dd-MMM-yy", Locale.ENGLISH);
You can reference the docs here.
As you are not providing the full year you need
DateFormat format = new SimpleDateFormat("dd-MMM-yy", Locale.ENGLISH);
Date myDate = format.parse("11-NOV-13");
System.out.println(myDate);
Change to this format:
SimpleDateFormat sdf = new SimpleDateFormat("EEE MMM dd HH:mm:ss z yyyy");
DateFormat format = new SimpleDateFormat("dd-MMM-yy", Locale.ENGLISH);
Date myDate = format.parse("11-NOV-13");
String formattedDate = sdf.format(myDate);
This question already has answers here:
Simple date format in java, Parse Exception
(3 answers)
Closed 7 years ago.
I´m getting a list of twitter dates via the search API of twitter.
String dateString = ((JSONObject)ar.get(i)).get("created_at").toString();
// Ej: "Tue May 12 19:58:26 +0000 2015"
String TWITTER="EEE MMM dd HH:mm:ss ZZZZZ yyyy";
SimpleDateFormat sf = new SimpleDateFormat(TWITTER);
Date d = sf.parse(dateString);
LocalDate localDate = LocalDate.parse( new SimpleDateFormat("yyyy-MM-dd").format(d) );
Can anyone help me see what I´m doing wrong?
I don´t see any errors in my date format. However, I´m getting an unparseable date Exception on the sf.parse(dateString); line.
SimpleDateFormat is Locale dependent, so just use an explicit english Locale:
String TWITTER="EEE MMM dd HH:mm:ss ZZZZZ yyyy";
SimpleDateFormat sf = new SimpleDateFormat(TWITTER,Locale.ENGLISH);
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
how to convert seconds_since_the_beginning_of_this_epoch to date format in java..?
hi i have "1304054138" in ssboetod . I want to display it in this "21 Apr 2011 11:46:00 AM IST" format. How i can do this in java code... ?
SimpleDateFormat sdf = new SimpleDateFormat("dd MM yyyy hh:mm:ss a z")
String result = sdf.format(new Date(timestamp));
if timestamp is a String, you can obtain the long version by calling Long.parseLong(string)
Like this:
// creat date format
DateFormat dateFormat = DateFormat.getDateTimeInstance(
DateFormat.LONG, DateFormat.LONG);
// set time zone
dateFormat.setTimeZone(TimeZone.getTimeZone("IST"));
// create and format date
String formattedDate = dateFormat.format(new Date(Long.valueOf("1304054138")));
// write out
System.out.println(formattedDate);