Its not coming out of the loop [closed] - java

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Hi in the below code mandatoryCount = 0 and it should be increased when an image is selected but its found to be always 1 and i cant exit the loop can any one help me. Here if mandatoryCount = 0 or mandatoryCount>=imageTypeMandatory.length. It must come out of loop. But this code is working if i comment the mandatory count ==0. I cannot find the exact error.
if (dataOne.getCount() >= 1) {
mandatoryCount=0;
dataOne.moveToFirst();
while(!dataOne.isAfterLast()){
for(int iCopy=0;iCopy<imageTypeMandatory.length;iCopy++){ if(imageTypeMandatory[iCopy].trim().equalsIgnoreCase(dataOne.getString(0).trim())){
mandatoryCount++; imageTypeMandatoryCopy[iCopy]="";
}}
dataOne.moveToNext();
}


The logic is testing the moveFirst/moveNext.
if (dataOne.moveToFirst()) {
do {
for(int iCopy=0;iCopy<imageTypeMandatory.length;iCopy++){
if(imageTypeMandatory[iCopy].trim().equalsIgnoreCase(dataOne.getString(0).trim())){
mandatoryCount++;
imageTypeMandatoryCopy[iCopy]="";
}
}
} while(dataOne.moveToNext());
}

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What does for(i = a; i> 0;i=i/10) do? [closed]

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So my program is working , the program is to check if a number is Automorphic,Trimorphic,Tri-Automorphic or its not a type of automorphic.
But I have a doubt , that is , what does this do:
for (I = a ; I> 0 ; I = I / 10 )
{
C++;
}
I tried to remove C++ but that didn't work.

Im not sure why this code is not working properly as it's supossed [closed]

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public String createHash()
{
String[] ALPHABET={"0","1","2","3","4","5","6","7","8","9","a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
String[] hash={"0","1","2","3","4","5","6","7"};
for(int var=0; var==61; var++)
{
hash[7]=ALPHABET[var];
System.out.print(hash[7]);
}
return "Success";
}
I'm not quiet sure how to explain what this code is supossed to do but I hope you get what I wanted it to do. It's supposed to take the value behinde index 7 of hash and replace it with the value behinde index "var" of ALPHABET.
So at the end it should print in the cosole something like this: "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
I'm not sure where the error is. It's probabbly something extremly basic but I'm quiet new to programming...

You're seeing "Success", aren't you? This may be because of the abort-variable. var is never 61 because this condition will be checked before your for-block is executed.
It will has to be
for(int var = 0; var <= 61; var++)
if you want 62 executions of your for loop.
Anyway, I don't understand the purpose.

How to write double number shorter in java? [closed]

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I have part of the code:
public void CollectorOrPocrushka(double output) {
if (output <= 0.4999999999999999999999)
System.out.println("покришка");
if (output > 0.5 && output <= 1.0)
System.out.println("колектор");
}
Can I write float number 0.4999999999999999999999 shorter?
Something like that:
0.49F
0.49e^10

If your question is about to simplify the first if condition and your goal is to check if the output is less than or equal 0.4999999999999999999999, you can easily write
if(output < 0.5)
System.out.println("покришка");

Return method return several times [closed]

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I want to make a method return that return several times a String from a list of String. any idea ??

How about something like this:
String getRandomString(List<String> list) {
return list.get(new Random().nextInt(list.size()));
}
This isn't the most efficient way, but should do the job.

how to calculate the time complexity for the following code? [closed]

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For (int i=1; i <=n;i/=2){
System.out.println(i);
}
For the time complexity about the above coding, is ot log (n)?
Thanks!

If n > 0: It's time complexity is O(∞) because the loop will never end
If n <= 0: It's time complexity is O(1)
because the loop will not be executed

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