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How to get absolute path of existing folder

I have a test data folder in my java project... something like this
Project
src Folder
testData Folder
How can I get the data folder using java, previously we have a hardcoded the in a constant, but now we are using a CI tool and I want to avoid the hardcoded path.

its is very fine to hardcode the testdata folder, but the
point is that it should be a relative path:
At the top of the test class you can just write
static final String TEST_PATH = "./testdata/";
Note that this is relative to the project.
If you want to convert such a relative path to an absoulte one:
String absoluteTestPath = new File(TEST_PATH).getAbsolutePath();

Take the input parameter and create a new File Object. The Java file object will provide getPath(), getAbsolutePath(), and getCanonicalPath(). Be careful with the file systems. If you are swapping between Windows/Linux/Mac/etc, you may have issues with translating paths between source and destination. I assume you source and destination are on the same file system in the example below.
File f = new File(pathStr);
String absPath = f.getAbsolutePath();

How about using Paths?
Paths.get("your-relative-path-here").toAbsolutePath()

Well, I solved my issue in the following way
public static final String Path_TestData = System.getProperty("user.dir") + "\\TestData\\";

For src
static String SRC_PATH = new File(".").getCanonicalPath()+System.getParameter("file.separator")+SRC;
// where SRC is the name of your source folder
For testdata:-
static String TEST_PATH = "./testdata/";

Jump one folder up in a URL in Java

I have a URL that I get as below:
String jarFilePath = getClass().getProtectionDomain().getCodeSource().getLocation()
This would get me the complete path to the jar file. Now how do I jump one folder up and append some other path to it? For example., if the jarFilePath is something like:
c:/path/to/jar/file.jar
I want to jump one folder up and append another relative path like below:
c:/path/to/resources/path/to/resources/
Where the folders resources and jar are at the same directory level in the file system.

File f = new File("C:/path/to/jar/file.jar");
File dest = new File(f.getParentFile().getParentFile(), "resources/path/to/resources");

Just use the File-Object, that makes a lot of things easier:
import java.io.File;
String pathname = "c:/path/to/jar/file.jar";
File f = new File(pathname);
String p = f.getParent();

Try and use a File object:
File jarFile = new File(jarFilePath);
File newFolder = new File( jarFile.getParentFile().getParentFile(), "resources/path/to/resources");
If you want to use the path as a string, try using Apache Commons IO's FilenameUtils:
String resourcesPath = FilenameUtils.normalize( FilenameUtils.getPath(jarFilePath) + "/../resources/path/to/resources");

You have several ways.
You can split the path into it's elements and rebuild it until array.length -3 (-1 would be filename, -2 the last folder)
You could simple remove the file and append another ../ (which just means: "Go one directory back") (that would be something like this then: c:/path/to/jar/../resources/path/to/resources/)
You gould use a regex to get rid of the last folder and file. something like /[^/]+/[^/]+$

dynamic path in java application

I want to specify the path dynamically. myapp/CopyFolder and myapp/RunFolder's are inside application like myapp/WEB-INF. The code I have given below is in .java file(in eclipse) and in .class file(in tomcat inside myapp/WEB-INF/classname/packagename/). My deployment is in tomcat.
try {
functionNamesObject.Integration(
".txt",
path+"\\CopyFolder",
path+"\\RunFolder",
"app.exe",
"Input.txt"
);
I want path to be dynamic when I call above function. I tried with getResource("MyClass.class") ,new File("").getAbsolutePath(); and System.getProperty("user.dir") but no use. Is there any other way?

You can get the path value as below:
URL resource = getClass().getResource("/");
String path = resource.getPath();
This will return the absolute path to to your myApp/WEB-INF/classes directory.

how to get full path of the current file including the src file in java

I have a file dateTesting.java . the path's directory is as follows: D:\workspace\Project1\src\dateTesting.java . I want the full path of this file as "D:\workspace\Project1\src" itself but when I use any of the following code, i get only "D:\workspace\Project1" . the src part is not coming.
System.out.println(System.getProperty("user.dir"));
File dir2 = new File(".");
System.out.println(dir2.getCanonicalPath().toString());
System.out.println(dir2.getAbsolutePath());
How can I get the full path as "D:\workspace\Project1\src" ? I'm using eclipse ide 3.5
Thank you

dateTesting.java is a Java source file which is not available after compilation to bytecode. The source directory it was in is not available, too.
dir2 is the File of the directory you execute the .class file in. It seams that this happens to be D:\workspace\Project1 but you can't rely on this.

Your dir2 points to working directory (new File(".")). You can't get the location of your sources this way. Your file could sit inside the package (e.g. your.company.date.dateTesting). You should just manually concat the "src" to current working directory and then replace file package dots (.) with File.pathSeparator. In that way you will build the full path to your file.

String fullFilePath = "H:\\Shared\\Testing\\abcd.bmp";
File file = new File(fullFilePath);
String filePath = file.getAbsolutePath().substring(0,fullFilePath.lastIndexOf(File.separator));
System.out.println(filePath);
Output:
H:\Shared\Testing

If you are doing this to try to read a file from the classpath, then check out this answer:
How to really read text file from classpath in Java
Essentially you can do this
InputStream in = this.getClass().getClassLoader()
.getResourceAsStream("SomeTextFile.txt");
Otherwise, if you have some other requirement, one option is to pass through the src directory as a JVM arg when the application begins and then just read it back.

/** The actual file running */
public static final File JAR_FILE = new File(MyClass.class.getProtectionDomain().getCodeSource().getLocation().getPath();
/** The path to the main folder where the file .jar is run */
public static final String BASE_DIRECTORY = (JAR_FILE != null ? JAR_FILE.getAbsolutePath().replace(JAR_FILE.getName(), "") : "notFound");
This will work for you both in normal java execution and jar execution. This is the solution I am using in my project.

Get the absolute path of the currently edited file in Eclipse

I'd like to write a plugin that does something with the currently edited file in Eclipse. But I'm not sure how to properly get the file's full path.
This is what I do now:
IFile file = (IFile) window.getActivePage().getActiveEditor.getEditorInput().
getAdapter(IFile.class);
Now I have an IFile object, and I can retrieve it's path:
file.getFullPath().toOSString();
However this still only gives me the path relative to the workspace. How can I get the absolute path from that?

Looks like you want IResource.getRawLocation(). That returns an IPath, which also has a makeAbsolute() method if you want to be doubly sure you've got an absolute path.

I think a more Java friendly solution would be to do use the following:
IResource.getLocation().toFile()
This takes advantage of the IPath API (the getLocation() part) and will return a java.io.File instance. Of course the other answers will probably get you to where you want to be too.
On a tangential note, I find the IDE class (org.eclipse.ui.ide.IDE) a useful utility resource when it comes to editors.

The answer that worked for me (and I tested it!) was:
// Get the currently selected file from the editor
IWorkbenchPart workbenchPart = PlatformUI.getWorkbench().getActiveWorkbenchWindow().getActivePage().getActivePart();
IFile file = (IFile) workbenchPart.getSite().getPage().getActiveEditor().getEditorInput().getAdapter(IFile.class);
if (file == null) throw new FileNotFoundException();
String path = file.getRawLocation().toOSString();
System.out.println("path: " + path);

I usually call IFile.getLocation() which returns an IPath and then call IPath.toOSString().
file.getLocation().toOSString()

IWorkspace ws = ResourcesPlugin.getWorkspace();
IProject project = ws.getRoot().getProject("*project_name*");
IPath location = new Path(editor.getTitleToolTip());
IFile file = project.getFile(location.lastSegment());
into file.getLocationURI() it's the absolute path

For me, this run ok.
IWorkspaceRoot workSpaceRoot = ResourcesPlugin.getWorkspace().getRoot();
File file = workSpaceRoot.getRawLocation().makeAbsolute().toFile();
file list from this location:
File[] files = file.listFiles();