Your program should print the following:
0 3 6 9 12 15 18 loop ended!
This is my code. May I know why can't I do the desired output?
int i = 0;
while(i%3 == 0 && i < 20 ) {
System.out.print(i);
i++;
}
System.out.print("loop ended!");
You have a condition in your while loop that must be satisfied for the while loop to continue running. When i increments to 1, the while loop condition fails and thus will stop running, so your program will only print 0. You instead should use an if statement inside the while loop with the mod condition:
int i = 0;
while(i < 20) {
if(i%3 == 0) {
System.out.print(i + " ");
}
i++;
}
System.out.print("loop ended!");
i % 3 == 0 && i < 20 - this condition evaluates to false when the value of i becomes 1. So loop only executes once.
You just need i < 20 as a loop condition and in each iteration of the loop, just add 3 in i.
int i = 0;
while(i < 20) {
System.out.print(i + " ");
i += 3;
}
System.out.print("loop ended!");
Output:
0 3 6 9 12 15 18 loop ended!
public static void main(String... args) {
int i = 0;
do {
System.out.print(i + " ");
} while ((i += 3) < 20);
System.out.print("loop ended!");
}
I offer to simplify your code with usein for loop:
public static void main(String... args) {
for (int i = 0; i < 20; i += 3)
System.out.print(i + " ");
System.out.print("loop ended!");
}
public class Test {
public static void main(String[] args) {
for (int i = 1; i <= 100; i++) {
int num = 0;
if (i % 3 == 0) {
System.out.println(i);
num++;
}
if (num == 5)
break;
}
}
}
Above is my code, but I got the result of all the integers that can be divided by 3 from 0 to 100.
I am a beginner for Java, so can somebody tell me where did I do wrong? (I am not seeking alternative solutions for this question, just explanation why the loop doesn't stop when num == 5).
Thanks in advance.
The reason you're getting all of the numbers divisible by 3 from 0-100 is because you're redefining num each iteration of the loop to zero. Just place the initialization outside of the loop, then increment like you are inside.
int num = 0;
for (int i = 0; i <= 100; i++) {
if (i % 3 == 0) {
System.out.println(i);
num++;
}
if (num == 5) break;
}
Why bother with answers you can mathematically prove are wrong?
int num = 3;
int count = 0;
while ((num < 100) && (count < 5)) {
System.out.println(num);
num+=3;
count++;
}
I am a Java student and I am having trouble with nesting the conditional statement of this program
Exercise CozaLozaWoza (Loop & Condition): Write a program called
CozaLozaWoza which prints the numbers 1 to 110, 11 numbers per line.
The program shall print "Coza" in place of the numbers which are
multiples of 3, "Loza" for multiples of 5, "Woza" for multiples of 7,
"CozaLoza" for multiples of 3 and 5, and so on. The output shall look
like:
1 2 Coza 4 Loza Coza Woza 8 Coza Loza 11
Coza 13 Woza CozaLoza 16 17 Coza 19 Loza CozaWoza 22
23 Coza Loza 26 Coza Woza 29 CozaLoza 31 32 Coza
......
I manage to do this
public class CozaLozaWoza {
public static void main(String[] args) {
for (int x = 1; x <= 110; x +=1) {
if (x % 3 == 0) {
System.out.print(" Coza");
}else if (x % 5 == 0) {
System.out.print(" Loza");
}else if (x % 7 == 0) {
System.out.print(" Woza");
}else if (x % 3 != 0 && x % 5 != 0 && x % 7 != 0) {
System.out.print(" " + x);
}
if (x % 11 == 0) {
System.out.println();
}
}
}
}
I can't merge the last if statement, can anyone help me? thank you
The if statements should be independent of each other, since more than one statement can be true for the same number (for example "CozaLoza" for multiples of 3 and 5).
for (int x = 1; x <= 110; x +=1) {
boolean regular = true;
System.out.print (" ");
if (x % 3 == 0) {
System.out.print("Coza");
regular = false;
}
if (x % 5 == 0) {
System.out.print("Loza");
regular = false;
}
if (x % 7 == 0) {
System.out.print("Woza");
regular = false;
}
if (regular) {
System.out.print(x);
}
if (x % 11 == 0) {
System.out.println();
}
}
package homePrac;
public class LOZAMOZACOZA
{
public static void main (String []args)
{
int max = 110;
for (int i=1; i<=max; i++)
{
if (i%3==0)
System.out.print("Coza");
else if (i%5==0)
System.out.print ("Woza");
else if (i%7==0)
System.out.print("CozaLoza");
else if (i%3!=0 || i%5!=0 || i%7!=0)
System.out.print(i);
if(i%11==0)
System.out.println("");
}
}
}
Here's my code so far
public class DivisibleBy5and6
{
public static void main (String []args)
{
for (int i = 100; i <= 200; i++)
{
boolean num = (i % 5 == 0 || i % 6 == 0) && !(i % 5 == 0 && i % 6 == 0);
if (num == true)
System.out.println(i + " is divisible");
}
}
}
Like stated previously how can I get the output to print out 10 items per line separated by a space?
How about:
int count = 0;
for (int i = 100; i <= 200; i++) {
boolean num = (i % 5 == 0 || i % 6 == 0) && !(i % 5 == 0 && i % 6 == 0);
if (num == true) {
count++;
System.out.print(i + " is divisible ");
if(count >= 10) {
System.out.println();
count -= 10;
}
}
}
This question already has answers here:
Conditional statement true in both parts of if-else-if ladder
(4 answers)
Closed 2 years ago.
For those who don't know, FizzBuzz is the following problem:
Write a program that prints the numbers from 1 to 100. But for
multiples of three print "Fizz" instead of the number and for the
multiples of five print "Buzz". For numbers which are multiples of
both three and five print "FizzBuzz".
Every FizzBuzz solution I find is either some crazy esoteric solution made for the sake of being original, or your basic if-else chain:
for(int i = 1; i <= 100; i++) {
if(i % 3 == 0 && i % 5 == 0) {
System.out.println("FizzBuzz");
} else if (i % 3 == 0) {
System.out.println("Fizz");
} else if (i % 5 == 0) {
System.out.println("Buzz");
} else {
System.out.println(i);
}
}
I am looking for a simple solution that aims to take out the "FizzBuzz" if statement. I have this in mind:
for(int i = 1; i <= 100; i++) {
if (i % 3 == 0)
System.out.print("Fizz");
if (i % 5 == 0)
System.out.println("Buzz")
else
System.out.println(i);
}
But this doesn't work. I assume it would be able to print FizzBuzz by entering both ifs, for Fizz and for Buzz, but if the number is, for example, 3, it would print Fizz3. How do I avoid this?
What you're trying to do is
if (a)
...
if (b)
...
else // if neigther a nor b
...
This is simply not possible. An else can only belong to a single if. You have to go with the slightly longer variant.
To avoid doing redundant evaluations of the modulo operator, you could formulate the loop body as
boolean fizz = i % 3 == 0;
boolean buzz = i % 5 == 0;
if (fizz)
System.out.print("Fizz");
if (buzz)
System.out.print("Buzz");
if (!(fizz || buzz))
System.out.print(i);
System.out.println();
Another one would be
String result = "";
if (i % 3 == 0) result = "Fizz";
if (i % 5 == 0) result += "Buzz";
if (result == "") result += i;
System.out.println(result);
Your first if statement is all alone.
So, your code hits the first statement, which is ONLY an if statement, and then goes on to the next, which is an if/else statement.
RosettaCode has a good example without using AND operators.
int i;
for (i = 0; i <= 100; i++) {
if ((i % 15) == 0)
cout << "FizzBuzz" << endl;
else if ((i % 3) == 0)
cout << "Fizz" << endl;
else if ((i % 5) == 0)
cout << "Buzz" << endl;
else
cout << i << endl;
}
If your only goal is to avoid using &&, you could use a double negation and DeMorgan's laws:
for(int i = 1; i <= 100; i++) {
if(!(i % 3 != 0 || i % 5 != 0)) {
System.out.println("FizzBuzz");
} else if (i % 3 == 0) {
System.out.println("Fizz");
} else if (i % 5 == 0) {
System.out.println("Buzz");
} else {
System.out.println(i);
}
}
You can avoid && using the fact that i % 3 == 0 and i % 5 == 0 implies i % 15 == 0, as per RFC1337's answer.
Another solution is to use a switch on the remainder (mod 15, which is 5 times 3):
for(int i = 1; i <= 100; i++) {
final int mod = i % 15;
switch (mod) {
case 0:
case 3:
case 6:
case 9:
case 12:
System.out.print("Fizz");
if (mod != 0) break;
case 5:
case 10:
System.out.print("Buzz");
break;
default:
System.out.print(i);
}
System.out.println();
}
This is my solution. Granted, it's a bit convoluted (as in roundabout), but I believe it suits your requirement.
int main()
{
char fizzpass=0;
unsigned short index=0;
for(index=1;index<=100;index++)
{
if(0 == (index%3))
{
printf("Fizz");
fizzpass = 1;
}
if(0 == (index%5))
{
if(1 == fizzpass)
{
fizzpass = 0;
}
printf("Buzz\n");
continue;
}
if(1 == fizzpass)
{
fizzpass = 0;
printf("\n");
continue;
}
printf("%d\n",index);
}
return 0;
}
Regards.
Just add a flag variable and use System.out.print:
package com.stackoverflow;
public class FizzBuzz {
public static void main(String[] args) {
for (int i = 1; i <= 100; i++) {
boolean printed = false;
if (i % 3 == 0) {
printed = true;
System.out.print("Fizz");
}
if (i % 5 == 0) {
printed = true;
System.out.print("Buzz");
}
if (printed) {
System.out.println();
} else {
System.out.println(i);
}
}
}
}
This doesn't take out the if statements but does not use the && (and) operator, you could flip the binary operators.
//FizzBuzz Case
if(!(a % 3 != 0 || a % 5 != 0)){ //flips
result[index] = "FizzBuzz";
index++;
}
Don't use an if statement at all.
import java.util.*;
import java.lang.*;
import java.io.*;
class FizzBuzz
{
public static void main (String[] args) throws java.lang.Exception
{
String[] words = {"", "Fizz", "Buzz"};
String[] nwords = {"", ""};
for(int i = 1; i < 101; ++i)
{
int fp = (i % 3 == 0) ? 1 : 0;
int bp = ((i % 5 == 0) ? 1 : 0) * 2;
int np = ((fp > 0 || bp > 0) ? 1: 0);
nwords[0] = Integer.toString(i);
System.out.print(words[fp]);
System.out.print(words[bp]);
System.out.println(nwords[np]);
}
}
}
See it on ideone.
public class fizzbuzz
{
public static void main(String[] args)
{
String result;
for(int i=1; i<=100;i++)
{
result=" ";
if(i%3==0)
{
result=result+"Fizz";
}
if(i%5==0)
{
result=result+"Buzz";
}
if (result==" ")
{
result=result+i;
}
System.out.println(result);
}
}
}
This is the most efficient way I could come up with. Hope it helps! :)
Crazy albeit unrelated solution done in Python3
#!/usr/bin/python3
for i in range(1,100):
msg = "Fizz" * bool(i%3==0)
msg += "Buzz" * bool(i%5==0)
if not msg:
msg = i
print(msg)