Bingo Card Game in Java - java

I created two methods for my Bingo Game in Java. One method creates a new board which populates the Bingo Board with integers according to the Bingo rule (1-75). My second method generates random numbers with a range of 1 - 75.
public static int drawNum(){
Random rand = new Random();
int num = rand.nextInt(75)+1;
return num;
}
public static void bingoCard(){
int [][]card=new int [5][5];
ArrayList<Integer> alreadyUsed = new ArrayList<Integer>();
boolean valid = false;
int tmp = 0;
for(int i = 0; i <= 4; i++){
for(int row = 0; row < card.length; row++){
while(!valid){
tmp = (int)(Math.random() * 15) + 1 + 15 * i;
if(!alreadyUsed.contains(tmp)){
valid = true;
alreadyUsed.add(tmp);
}
}
card[row][i] = tmp;
valid = false;
}
}
card[2][2] = 0;
//create array to make title.
String title []={"B","I","N","G","O"};
for(int i=0;i<title.length;i++){
System.out.print(title[i]+ "\t");
}
System.out.println();
for(int row=0;row<card.length;row++){
for(int col=0;col<card[row].length;col++){
System.out.print(card[row][col]+ "\t");
}
System.out.println();
}
}
What I need help with is, how do I check whether or not the drawNum() method corresponds to any values stored inside my bingoCard() array? If so, print out a new array with the integers filled in. If the condition is met for a bingo, then you win.
I hope I don't make it sound like I want you to do it for me, but I am confused as to how to start coding that part. Thank you.

This my recommendation - Learn Object Oriented Programming immediately
I see you are using objects provided in the JDK, so why not learn to make your own?
Make two classes with the following methods (-) and members (+) (PS. This is not a formal way to document code)
BingoCard
+list of numbers on card
-reset() : gets new numbers for this card
-test(BingoDrawer) : Tests to see if this card won on this drawing
-toString() : returns a String representation of this card
BingoDrawer
+list of numbers drawn
-reset() : draws new numbers
-hasNumber(int number) : tests if this number was drawn
-toString() : returns a String representation of this drawing
One more suggestions
Instead of keeping track of what you used, keep track of what you have not used, it will make things much easier because you can just choose stuff from that list randomly. Unlike your current action which is choosing (a logical number) from thin air and hoping (which causes issues) it is not a collision
If you follow my recommendation you can write code like this
public static void main(String[] args) {
BingoCard bc = new BingoCard();
BingoDrawer bd = new BingoDrawer();
while(thePlayerWantsToPlay()) { //function to be defined by you
bc.reset();
bd.reset();
System.out.println(bc);
System.out.println(bd);
System.out.println(bc.test(bd));
}
}
You can take it a step further and make a BingoGame class and do what I did in main there and just create an instance of BingoGame and call some start method on the object.

For checking if you have the number in your board, read through the board in a similar manner as you do for the already_used numbers, except with the number the user just entered.
The conditions for the user to win should be checked after the board has another number guessed.
There are a few ways to do this, a simple one would be to iterate over every possible pattern that could win, checking to see if there are tokens there.
All of this would be in a loop, that goes a little like this:
Set up board via user entering numbers.
Start loop
set either a timer to wait for, or wait for a keypress (so the game doesn't just play really fast)
Get random number
Possibly add to board
Check if winner
if winner, break the loop and do something else.
Print the new board out.
(end of loop)
If they got here, that could mean they won!
Wait to exit

You can just write it out as pseudo-code and fill in the methods after that. It usually helps to work on these things in a top-down fashion. So, for bingo you might have:
board = generateBoard();
while (!bingoFound(board)) {
number = drawNumber();
board = stampNumbers(board, number);
}
If that makes sense, you can go a step deeper and define each method. For example, bingoFound might look like:
public boolean bingoFound(int[][] board) {
boolean wasFound = bingoRowFound(board)
|| bingoColFound(board)
|| bingoDiagonalFound(board);
return wasFound;
}
Again, I've defined everything in (mostly) pseudo-code. If this looks ok, you can move a step deeper. Let's define the bingoRowFound method.
public boolean bingoRowFound(int[][] board) {
for (int row = 0; row < NUM_ROWS; row++) {
boolean rowIsABingo = true;
for (int col = 0; col < NUM_COLS; col++) {
// We have to check that everything up until this point has
// been marked off. I am using -1 to indicate that a spot has
// been marked.
rowIsABingo = rowIsABingo && board[row][col] == -1;
}
if (rowIsABingo) { return rowIsABingo; }
}
return false; // If we didn't find a bingo, return false.
}
Some of the methods (like drawNumber) will be really easy to implement. Others, like looking for a diagonal bingo might be a bit more difficult.

Feb 12 2014 Update:
Retracted code, since this was a college course assignment, and I want to prevent people just copying the code. I almost got in trouble for being accused of sharing code (which is a nono in assignments) when another student lifted my code from my Github repo and sent it in as their own.
There were two classes, one main class and a class to hold my methods and constructors.
BINGOFINAL.java was my main class.
Bingo_Card.java held my constructor and methods.
If you want to run this, make sure you create a new project called BINGOFINAL, and put Bingo_Card.java into that same */src/ extension.

Related

How to pull numbers from an array

I currently have java homework that I would appreciate some help with. We are to calculate a team record scenario.
We are given the following numbers:
Team1 Points
{23,45,65,20}
Opponent Points
{20,30,20,18}
I threw these into an array. I also created a public boolean. Basically, you are to pull these points from the array to the boolean? And let the boolean decide which team won? Obviously team1 has won, but we are supposed to let the computer decide, not the human.
Here is my code:
public class TeamScore {
public static boolean Winner(int team1Points, int opponentPoints) {
if (team1Points > opponentPoints) {
return true;
} else {
return false;
}
}
public static void main(String[] args) {
// Scanner in = new Scanner(System.in);
int[] team1Points = { 23, 45, 65, 20 };
int[] opponentPoints = { 20, 30, 20, 18 };
int team1 = 1;
int opponent = 1;
for (int i = 0; i < 5; i++) {
if (Winner(team1Points[i], opponentPoints[1])) {
team1 += 1;
} else {
opponent += 1;
}
}
for (int i = 0; i < 5; i++) {
if (team1 > 0 && opponent == 0) {
System.out.println("Team 1 has the perfect record!");
} else {
System.out.println("Win" + Arrays.toString(team1Points));
System.out.println("Loss" + Arrays.toString(opponentPoints));
}
}
}
Could anyone possibly help me? I am currently in programming II, but I did not have the best teacher in programming I. Any help would be appreciated!
EDIT:
I do not think this is a duplicate question because I already can fix it by changing the variable i-->1. My problem is that the computer thinks that team1 has already won regardless of the score.
When I run the code I am getting an java.lang.ArrayIndexOutOfBoundsException error. However when I change team1Points[i] to team1Points[1] then it goes okay and tells me that "Team 1 has the perfect record!". However, if I change some of the array values for team1Points to be less than opponentPoints then it still says "Team 1 has the perfect record!".
Not sure why you have a method Winner (also as Kevin said, it should be winner because of naming conventions) which turns ´(a > b)´ into a large if-statement. Similar stuff appear elsewhere in your code.
Your variables ´team1, opponent = 1´ inexplicably start with the value 1, am I to understand this as a way for your code to imply to a reader that both teams initialize at a win? Using 0 would probably make more sense.
Your game ought to crash from an indexoutofboundsexception at ´team1Points[i]´, as you have arrays of length 4, but your loops runs 5 times (the currently used range is [0-4], inclusive). Changing your loops to i=1 won't help, as the issue is that you eventually encounter team1Points[4] due to the i < 5 statement.
I don't know what game you are modelling or how it works, but the comparison ´Winner(team1Points[i],opponentPoints[1])´ looks like a blatant error to me (you always look at the opponents score for their second round).
Why are you printing your results 5 times? If you want to print the first message only when team1 won all rounds and the point for each round otherwise, you would need to use the loops counter as an index to the arrays in second case. First case should break loop so its not written five times, in addition you don't need to check team1>0 && opponent==0 as it's enough to only check if ´opponent==0´ (speaking of this conditional, it only works if you initialize the variables at 0 as I mentioned before). You could have checked if team1 equals size of the array instead, but imo thats more of a hassle than opponent==0.
Lastly, please fix your indenting. use the preview system so you can make double sure before posting.
Edit: Kevin also brings up a good point that you should be using the length of the array in your loops second statement.

How do I write an efficient/optimized loop for comparing several conditions at once? Badugi cardgame method

Say, I'm making a simple badugi card game where the Hand is represented by 10 characters in a string. E.g:
2s3h5dQs - 2 of spades, 3 of hearts, 5 of diamonds, Queen of spades
Now, in this badugi card game I want to create two loops where the first loop checks if all the ranks are different(none of them can be the same) and the other loop checks if all the suits are different. If both of these conditions return as true where they all have different ranks and suits, the hand has drawn a badugi(please excuse my lack of terminology where necessary.)
Now, how can I create an efficient loop for such a situation? I was thinking that I could create several if statements as such:
if (hand.charAt(0) != hand.charAt(2) && hand.charAt(0) != hand.charAt(4) && hand.charAt(0) != hand.charAt(6))
if (hand.charAt(2) != hand.charAt(0) && hand.charAt(2) != hand.charAt(4) && hand.charAt(2) != hand.charAt(6))
... and so forth comparing every single index to one another. But this gets tedious and seems very unprofessional. So my question is, how do I write an efficient loop for this scenario? How can I compare/check if there are no matches at these specific index points to one another?
If I haven't explained properly then please let me know.
Please keep in mind, I am not allowed freedom of how to formulate a hand. It has to be in the format above
You are putting your energy into the wrong place.
You do not need to worry about efficiency at all.
Instead, you should worry about creating a clean design (based on reasonable abstractions) and then write code that is super-easy to read and understand.
And your current approach fails both of those ideas; unfortunately completely.
In other words: you do not represent hands and values as characters within a String.
You create a class that abstracts a Card (with its value and face).
And then a "hand" becomes a List / array of such Card objects. And then you can use concepts such as Comparator to compare card values, or you can make use of equals() ...
And even when you wish to keep your (actually over-complex) naive, simple approach of using chars within a string; then you should at least use some kind of looping so that you don't compare charAt(0) against charAt(2); but maybe charAt(i) against charAt(j).
And following your edit and the excellent comment by jsheeran: even when you are forced to deal with this kind of "string notation"; you could still write reasonable code ... that takes such string as input, but transforms them into something that makes more sense.
For example, the Card class constructor could take two chars for suite/value.
But to get you going with your actual question; you could something like:
public boolean isCardDistinctFromAllOtherCards(int indexToCheck) {
for (int i=0; i<cardString.length-1; i+=2) {
if (i == indexToCheck) {
continue;
}
if (cardString.charAt(indexToCheck) == cardString.charAt(i)) {
return false;
}
}
return true;
}
( the above is just an idea how to write down a method that checks that all chars at 0, 2, 4, ... are not matching some index x).
You should really think about your design, like creating Card class etc., but back to the question now, since it's not gonna solve it.
I suggest adding all 4 values to a Set and then checking if size of the Set is 4. You can even shortcut it and while adding this yourSet.add(element) return false then it means there is already that element in the set and they are not unique. That hardly matters here since you only need to add 4 elements, but it may be useful in the future if you work with more elements.
I would advice creating an array with these chars you are referencing just to clean up the fact you are using indices. i.e create a vals array and a suits array.
This would be my suggestion by using a return or break the loop will stop this means when a match is found it wont have to loop through the rest of the elements .. Hope this helps !
private static int check(char[] vals, char[] suits){
int flag;
for(int i=0; i<=vals.length-2;i++){
for(int k=vals.length-1; k<=0;k++){
if(vals[i]==vals[k]){
flag=-1;
return flag;
}
if(suits[i]==suits[k]){
flag=1;
return flag;
}
}
}
return 0;
}
Why not simply iterate over your string and check for same ranks or suits:
public class NewClass {
public static void main(String[] args) {
System.out.println(checkRanks("2s3h5dQs"));
System.out.println(checkSuits("2s3h5dQs"));
}
public static boolean checkRanks(String hand){
List<Character> list = new ArrayList<>();
for (int i = 0; i< hand.length(); i+=2){
if (!list.contains(hand.charAt(i))){
list.add(hand.charAt(i));
}
else{
return false;
}
}
return true;
}
public static boolean checkSuits(String hand){
List<Character> list = new ArrayList<>();
for (int i = 1; i< hand.length(); i+=2){
if (!list.contains(hand.charAt(i))){
list.add(hand.charAt(i));
}
else{
return false;
}
}
return true;
}
}

How to make my room sorter more random?

So I'm working on a program which is supposed to randomly put people in 6 rooms (final input is the list of rooms with who is in each room). So I figured out how to do all that.
//this is the main sorting sequence:
for (int srtM = 0; srtM < Guys.length; srtM++) {
done = false;
People newMove = Guys[srtM]; //Guys is an array of People
while (!done) {
newMove.rndRoom(); //sets random number from 4 to 6
if (newMove.getRoom() == 4 && !room4.isFull()) {
room4.add(newMove); //adds person into the room4 object rList
done = true;
} else if (newMove.getRoom() == 5 && !room5.isFull()) {
room5.add(newMove);
done = true;
} else if (newMove.getRoom() == 6 && !room6.isFull()) {
room6.add(newMove);
done = true;
}
}
The problem now is that the code for reasons I don't completely understand (something with the way I wrote it here) is hardly random. It seems the same people are put into the same rooms almost every time I run the program. For example me, I'm almost always put by this program into room 6 together with another one friend (interestingly, we're both at the end of the Guys array). So how can I make it "truly" random? Or a lot more random than it is now?
Thanks in advance!
Forgot to mention that "rndRoom()" does indeed use the standard Random method (for 4-6) in the background:
public int rndRoom() {
if (this.gender == 'M') {
this.room = (rnd.nextInt((6 - 4) + 1)) + 4;
}
if (this.gender == 'F') {
this.room = (rnd.nextInt(((3 - 1) + 1))) + 1;
}
return this.room;
}
if you want it to be more random try doing something with the Random method, do something like this:
Random random = new Random();
for (int i = 0; i < 6; i++)
{
int roomChoice = random.nextInt(5) + 1;
roomChoice += 1;
}
of course this is not exactly the code you will want to use, this is just an example of how to use the Random method, change it to how you want to use it.
Also, the reason I did random.nextInt(5) + 1; is because if random.nextInt(5) + 1; gets you a random number from 0 to 5, so if you want a number from 1 to 6 you have to add 1, pretty self explanatory.
On another note, to get "truly" random is not as easy as it seems, when you generate a "random" number it will use something called Pseudo random number generation, this, is basically these programs produce endless strings of single-digit numbers, usually in base 10, known as the decimal system. When large samples of pseudo-random numbers are taken, each of the 10 digits in the set {0,1,2,3,4,5,6,7,8,9} occurs with equal frequency, even though they are not evenly distributed in the sequence.
There might be something wrong with code you didn't post.
I've build a working example with what your classes might be, and it is distributing pretty randomly:
http://pastebin.com/u8sZRxi6
OK so I figured out why the results don't seem very random. So the room sorter works based on an alphabetical people list of 18 guys. There are only 3 guy rooms (rooms 4, 5 and 6) So each guy has a 1 in 3 chance to be put in say, room 6. But each person could only possibly be in 2 of the 6 spots in each room (depending on where they are in the list).
The first two people for example, could each only be in either the first or second spot of each room. By "spot" I mean their place in the room list which is printed in the end. Me on the other hand am second last on the list, so at that point I could only be in either the last or second last spot of each room.
Sorry if it's confusing but I figured out this is the reason the generated room lists don't appear very random - it's because only the same few people could be put in each room spot every time. The lists are random though, it's just the order in which people appear in each list which is not random.
So in order to make the lists look more random I had to make people's positions in the room random too. So the way I solved this is by adding a shuffler action which mixes the Person arrays:
public static void shuffle(Person[] arr) {
Random rgen = new Random();
for (int i = 0; i < arr.length; i++) {
int randPos = rgen.nextInt(arr.length);
Person tmp = arr[i];
arr[i] = arr[randPos];
arr[randPos] = tmp;
}
}
TL;DR the generated room lists were random - but since the order of the people that got put into the rooms wasn't random the results didn't look very random. In order to solve this I shuffled the Person arrays.

connect 4 java issues: How do I do this?

I am a noob to java, as well as programming, and I am having large difficulties picturing how to actually execute each method in order to create the Connect Four game. There are 4 methods, main, printBoard, checkWinner, and playerMove. I may add more methods if necessary. I am overwhelmed and need a ton of guidance. how to approach each method? Sorry if this is a mammoth question, I am throughly confused.
import java.util.Scanner;
public class ConnectFour{
// We will represent the game board using a 2 dimensional integer array.
// Each entry of the array will contain a 0, 1, or -1.
// A 0 entry in the array represents an empty slot.
// A 1 entry represents Player 1's piece.
// A -1 entry represents Player 2's piece.
// Since most methods will need to access this board, we have decided to
// make it a global class variable.
import java.util.Scanner;
public class ConnectFour{
public static int[][] board = new int[6][7];
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
// initializing board
for(int i = 0; i < 6; i++){
for(int j = 0; j < 7; j++){
board[i][j] = 0;
}
}
// WRITE CODE HERE
if (j < 7 && j >= 0)
f[i][j] =".";
else f[i][j] = " ";
return board;
}
}
// This method prints the board on the screen.
// To represent Player 1's pieces, print 'X'.
// To represent Player 2's pieces, print 'O'.
// To represent an empty slot, print '.'.
public static void printBoard(){
// WRITE CODE HERE
for (int i = 0; i < 6; i++)
{
for (int j = 0;j < 7; j++)
{
System.out.print(f[i][j]);
}
System.out.println();
}
}
// This method scans the current board and checks if there is a winner.
// The method should return 1 if Player 1 has connected 4 pieces.
// It should return -1 if Player 2 has connected 4 pieces.
// It should return 0 if no player has connected 4 pieces.
public static int checkWinner(){
// WRITE CODE HERE
return;}
// This method implements a player's move and updates the board accordingly.
// The method has two integer inputs.
// The first input indicates the player (1 for Player 1, -1 for Player 2).
// The second input indicates the column number that the player has
// chosen to play.
// If the column number is out of range or the column is currently full,
// the method should return false.
// Otherwise, the board should be updated and the method should return true.
public static boolean playerMove(int player, int columnNum){
// WRITE CODE HERE
}
}
Think about how your program should work, logically. I would personally put your board in a separate class, but it's not too important, especially since the program is pretty small. This isn't really as much as a code problem as much as a logic one, so we'll walk through how the game works.
First off, what does each function do? We have checkWinner(), playerMove(), and printBoard(). So we'll have a loop until the game ends, which should be controlled by checkWinner(), like so
while !checkWinner
So the game will loop until a winner is found, and any code executed after the while loop is end game code. Inside our while loop should go all of code executed every frame while there is no winner, since that is how our while loop is setup now. So let's think about what should execute every frame of your game.
printBoard()? Yeah, probably, since we want to update the display every frame right?
playerMove()? Yeah, since if the game hasn't ended, we want the players to execute a move. However, you need to make sure that the code is functional for switching between players. If you do that, the basic game loop should be finished. Here's some psuedocode for that
//setup board here
while !checkWinner
printBoard
playerMove
//since checkwinner did not return 0, a player won. so we put in endgame code here
The main issue here is thinking out how your program should work, logically. So plan out which functions do what, and try to write it out.
Hope that helps.

Reassigning values in an array

Im trying to write a game of Yahtzee as part of an online course (not actually enrolled, just playing along at home) I have hit a bit of a wall manipulating values in the array that keeps track of the dice values. This is the section of code that seems to be causing trouble;
for (int i=0; i<N_DICE; i++){ //goes through each die.
if (display.isDieSelected(i) == false){ //checks if player wants to reroll the die.
dice [i] = dice[i];//problem line-should reassign the same value back to the die.
}
else {
dice [i] = rgen.nextInt(1, 6);
}
}
Assigning a new random number works, and if I roll all 5 dice every turn its happy.
I've changed the offending line to dice[i]=1 for testing purposes and while it takes some fun out of the game, the program works, so I'm thinking its something simple I'm doing wrong with that line.
I've tried assigning dice[i] to a temp variable (inside and out of the if loop) and then assigning temp back to dice[i].
I've tried just leaving the if loop empty.
I've tried setting it up as a multi dimesional array with a seperate array for each roll.
I've tried adding a cast (didnt think that'd do it but I was out of ideas).
All of these have had the same results.
Only been programming a few weeks, I'd be very gratefull if someone could tell me what I'm doing wrong.
Not sure what you're trying to do with that line:
dice[i] = dice[i];
Since it's a NOP, why not just omit it?
I don't really see the purpose of:
dice[i] = dice[i]
Can't you just use something like:
for (int i=0; i<N_DICE; i++){
if (display.isDieSelected(i)){
dice [i] = rgen.nextInt(1, 6);
}
}
The code looks completely correct, although I would write it a bit more compactly:
for (int i = 0; i < N_DICE; i++) {
if (display.isDieSelected(i)) {
dice[i] = rgen.nextInt(1, 6);
}
}
So your problem probably lies somewhere else. Is dice a new array, or is it always the same in the program? If it is a field in some class, it should have the final modifier, like this:
public class YahtzeeState {
private final int[] dice = new int[N_DICE];
}
This declaration makes sure that the dice array cannot be replaced later with a completely different array. The values in the array can still be changed though.
How is the dice-array initialized? I don't know your entire code but I could imagine that it doesn't work because the dice-array gets it values only in this loop?
Maybe you should try something like:
for (int i=0; i<N_DICE; i++){
if (display.isDieSelected(i) || dice[i] == null)
dice [i] = rgen.nextInt(1, 6);
}

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