Why do we need objects monitor if there is only thread - java

Running will start from the main method and if in some method i am using this.wait() without synchronized block, it will throw illegalStateMonitorException.
If there is only one thread why can't it wait, why should we use locking here. Thread is not going to perform any other task also. It could have waited there.
I am not understanding why locking is needed if there is single thread.
public class waitSleepCheck extends Thread{
public void method() throws InterruptedException ,IllegalMonitorStateException{
this.wait(1000);
}
public static void main(String args[]) throws InterruptedException{
waitSleepCheck object = new waitSleepCheck();
object.method();
}
}

Object.wait isn't "wait this long". It's "wait for some other thread to do something". The forms that take arguments are "wait for some other thread to do something, but get bored and stop after this long". You need to hold the object's lock to ensure proper synchronization with the thread that will notify you that the thing you're waiting for got done. It doesn't make sense to use the method in a single-threaded context.
If you just want to wait for a certain length of time, Thread.sleep is the method you want.

Because you have called a method that "causes the current thread to wait until another thread ...", and so isn't appropriate in the first place for a single-threaded application.

synch(lockObj) {Object.wait()} means that you wait until another thread signal you (see Object.notify()). In the underlying system, these methods are translated to wait(lockObj); and pulseevent(target); Which handles do yo think JVM will sumbit to them? If you do not specify the lock object then java has no idea which sync object (aka lock) you want to communicate over.

Related

Java multithreading error [duplicate]

The following code leads to java.lang.IllegalThreadStateException: Thread already started when I called start() method second time in program.
updateUI.join();
if (!updateUI.isAlive())
updateUI.start();
This happens the second time updateUI.start() is called. I've stepped through it multiple times and the thread is called and completly runs to completion before hitting updateUI.start().
Calling updateUI.run() avoids the error but causes the thread to run in the UI thread (the calling thread, as mentioned in other posts on SO), which is not what I want.
Can a Thread be started only once? If so than what do I do if I want to run the thread again? This particular thread is doing some calculation in the background, if I don't do it in the thread than it's done in the UI thread and the user has an unreasonably long wait.
From the Java API Specification for the Thread.start method:
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
Furthermore:
Throws:
IllegalThreadStateException - if the thread was already started.
So yes, a Thread can only be started once.
If so than what do I do if I want to
run the thread again?
If a Thread needs to be run more than once, then one should make an new instance of the Thread and call start on it.
Exactly right. From the documentation:
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
In terms of what you can do for repeated computation, it seems as if you could use SwingUtilities invokeLater method. You are already experimenting with calling run() directly, meaning you're already thinking about using a Runnable rather than a raw Thread. Try using the invokeLater method on just the Runnable task and see if that fits your mental pattern a little better.
Here is the example from the documentation:
Runnable doHelloWorld = new Runnable() {
public void run() {
// Put your UI update computations in here.
// BTW - remember to restrict Swing calls to the AWT Event thread.
System.out.println("Hello World on " + Thread.currentThread());
}
};
SwingUtilities.invokeLater(doHelloWorld);
System.out.println("This might well be displayed before the other message.");
If you replace that println call with your computation, it might just be exactly what you need.
EDIT: following up on the comment, I hadn't noticed the Android tag in the original post. The equivalent to invokeLater in the Android work is Handler.post(Runnable). From its javadoc:
/**
* Causes the Runnable r to be added to the message queue.
* The runnable will be run on the thread to which this handler is
* attached.
*
* #param r The Runnable that will be executed.
*
* #return Returns true if the Runnable was successfully placed in to the
* message queue. Returns false on failure, usually because the
* looper processing the message queue is exiting.
*/
So, in the Android world, you can use the same example as above, replacing the Swingutilities.invokeLater with the appropriate post to a Handler.
No, we cannot start Thread again, doing so will throw runtimeException java.lang.IllegalThreadStateException.
>
The reason is once run() method is executed by Thread, it goes into dead state.
Let’s take an example-
Thinking of starting thread again and calling start() method on it (which internally is going to call run() method) for us is some what like asking dead man to wake up and run. As, after completing his life person goes to dead state.
public class MyClass implements Runnable{
#Override
public void run() {
System.out.println("in run() method, method completed.");
}
public static void main(String[] args) {
MyClass obj=new MyClass();
Thread thread1=new Thread(obj,"Thread-1");
thread1.start();
thread1.start(); //will throw java.lang.IllegalThreadStateException at runtime
}
}
/*OUTPUT in run() method, method completed. Exception in thread
"main" java.lang.IllegalThreadStateException
at java.lang.Thread.start(Unknown Source)
*/
check this
The just-arrived answer covers why you shouldn't do what you're doing. Here are some options for solving your actual problem.
This particular thread is doing some
calculation in the background, if I
don't do it in the thread than it's
done in the UI thread and the user has
an unreasonably long wait.
Dump your own thread and use AsyncTask.
Or create a fresh thread when you need it.
Or set up your thread to operate off of a work queue (e.g., LinkedBlockingQueue) rather than restarting the thread.
What you should do is create a Runnable and wrap it with a new Thread each time you want to run the Runnable.
It would be really ugly to do but you can Wrap a thread with another thread to run the code for it again but only do this is you really have to.
It is as you said, a thread cannot be started more than once.
Straight from the horse's mouth: Java API Spec
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
If you need to re-run whatever is going on in your thread, you will have to create a new thread and run that.
To re-use a thread is illegal action in Java API.
However, you could wrap it into a runnable implement and re-run that instance again.
Yes we can't start already running thread.
It will throw IllegalThreadStateException at runtime - if the thread was already started.
What if you really need to Start thread:
Option 1 ) If a Thread needs to be run more than once, then one should make an new instance of the Thread and call start on it.
Can a Thread be started only once?
Yes. You can start it exactly once.
If so than what do I do if I want to run the thread again?This particular thread is doing some calculation in the background, if I don't do it in the thread than it's done in the UI thread and the user has an unreasonably long wait.
Don't run the Thread again. Instead create Runnable and post it on Handler of HandlerThread. You can submit multiple Runnable objects. If want to send data back to UI Thread, with-in your Runnable run() method, post a Message on Handler of UI Thread and process handleMessage
Refer to this post for example code:
Android: Toast in a thread
It would be really ugly to do but you can Wrap a thread with another thread to run the code for it again but only do this is you really have to.
I have had to fix a resource leak that was caused by a programmer who created a Thread but instead of start()ing it, he called the run()-method directly. So avoid it, unless you really really know what side effects it causes.
I don't know if it is good practice but when I let run() be called inside the run() method it throws no error and actually does exactly what I wanted.
I know it is not starting a thread again, but maybe this comes in handy for you.
public void run() {
LifeCycleComponent lifeCycleComponent = new LifeCycleComponent();
try {
NetworkState firstState = lifeCycleComponent.getCurrentNetworkState();
Thread.sleep(5000);
if (firstState != lifeCycleComponent.getCurrentNetworkState()) {
System.out.println("{There was a NetworkState change!}");
run();
} else {
run();
}
} catch (SocketException | InterruptedException e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
Thread checkingNetworkStates = new Thread(new LifeCycleComponent());
checkingNetworkStates.start();
}
Hope this helps, even if it is just a little.
Cheers

Thread with capability of stopping it in any duration of time

is there any kind of Runnable, Callable or Thread with capability of stopping it in any duration of time?
I wrote something like this
public class ThreadRunner {
private ExecutorService threadPoolExecutor;
ThreadRunner() {
threadPoolExecutor = Executors.newSingleThreadExecutor();
}
public void startThread(String endPoint, ProgressBar progressBar) {
Runnable task = () -> {
// some code which saves images from URL (1230 images) and updates progress bar
};
threadPoolExecutor.execute(task);
}
public void stopThread() {
threadPoolExecutor.shutdownNow();
}
}
Thread runs correctly, images are being saved, progress bar being updated, but when I want to stop thread (or maybe even pause process of saving if possible) by calling ThreadRunner class's method - nothing happens.
Am I doing something wrong - or most likely - what am I doing wrong?
is there any kind of Runnable, Callable or Thread with capability of stopping it in any duration of time?
You can implement such a thing yourself, but there is no generic support available for it, unless you count the long-deprecated Thread.stop() methods. Under no circumstances should you use those methods, but do read their API docs for a discussion of why they are deprecated and what you can do instead. You can find a longer-form version of the discussion in Java's technical notes.
The bottom line is that the computation you want to be able to stop needs to periodically check some shared variable or built-in condition to determine whether to do so. You arrange for that variable to be set when you want the thread to stop, and if you need to block until it does stop then you join() it. Under some circumstances, it can be helpful to interrupt() the thread to get it to check the variable (or being interrupted can itself serve as the termination condition). The user-facing end of this can be wrapped up in a method.
In any case, an ExecutorService cannot give you a handle on this. Requesting such a service to shut down will prevent it from dispatching any more tasks, but there is no safe, general-purpose mechanism by which it could force a premature shutdown of tasks that are already running.
Once started, a thread will run until Runnable.run() exits. Due to several issues you should never use Thread.stop() or Thread.interrupt().
Instead, you will have to implement your own logic for exit/pause. A few suggestions:
For stopping the thread, you can make a boolean variable shouldExit. In your thread, check this variable every now and then, and just do "return" or break the for/while loop when it becomes true. Setting this variable from another thread should now make the downloader exit. If necessary, you should surround access to this variable with synchronized block as to prevent any race conditions.
For pausing the thread, you can use a similar approach. When you set a certain variable to true (e.g. isPaused), make the thread react by going into an Object.sleep(). This way, it won't consume any CPU during sleep. You can then use Object.notify() from another thread to "kick" the sleeping thread out ouf sleep. You will need a synchronized block here, too.

Java Thread only works once [duplicate]

The following code leads to java.lang.IllegalThreadStateException: Thread already started when I called start() method second time in program.
updateUI.join();
if (!updateUI.isAlive())
updateUI.start();
This happens the second time updateUI.start() is called. I've stepped through it multiple times and the thread is called and completly runs to completion before hitting updateUI.start().
Calling updateUI.run() avoids the error but causes the thread to run in the UI thread (the calling thread, as mentioned in other posts on SO), which is not what I want.
Can a Thread be started only once? If so than what do I do if I want to run the thread again? This particular thread is doing some calculation in the background, if I don't do it in the thread than it's done in the UI thread and the user has an unreasonably long wait.
From the Java API Specification for the Thread.start method:
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
Furthermore:
Throws:
IllegalThreadStateException - if the thread was already started.
So yes, a Thread can only be started once.
If so than what do I do if I want to
run the thread again?
If a Thread needs to be run more than once, then one should make an new instance of the Thread and call start on it.
Exactly right. From the documentation:
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
In terms of what you can do for repeated computation, it seems as if you could use SwingUtilities invokeLater method. You are already experimenting with calling run() directly, meaning you're already thinking about using a Runnable rather than a raw Thread. Try using the invokeLater method on just the Runnable task and see if that fits your mental pattern a little better.
Here is the example from the documentation:
Runnable doHelloWorld = new Runnable() {
public void run() {
// Put your UI update computations in here.
// BTW - remember to restrict Swing calls to the AWT Event thread.
System.out.println("Hello World on " + Thread.currentThread());
}
};
SwingUtilities.invokeLater(doHelloWorld);
System.out.println("This might well be displayed before the other message.");
If you replace that println call with your computation, it might just be exactly what you need.
EDIT: following up on the comment, I hadn't noticed the Android tag in the original post. The equivalent to invokeLater in the Android work is Handler.post(Runnable). From its javadoc:
/**
* Causes the Runnable r to be added to the message queue.
* The runnable will be run on the thread to which this handler is
* attached.
*
* #param r The Runnable that will be executed.
*
* #return Returns true if the Runnable was successfully placed in to the
* message queue. Returns false on failure, usually because the
* looper processing the message queue is exiting.
*/
So, in the Android world, you can use the same example as above, replacing the Swingutilities.invokeLater with the appropriate post to a Handler.
No, we cannot start Thread again, doing so will throw runtimeException java.lang.IllegalThreadStateException.
>
The reason is once run() method is executed by Thread, it goes into dead state.
Let’s take an example-
Thinking of starting thread again and calling start() method on it (which internally is going to call run() method) for us is some what like asking dead man to wake up and run. As, after completing his life person goes to dead state.
public class MyClass implements Runnable{
#Override
public void run() {
System.out.println("in run() method, method completed.");
}
public static void main(String[] args) {
MyClass obj=new MyClass();
Thread thread1=new Thread(obj,"Thread-1");
thread1.start();
thread1.start(); //will throw java.lang.IllegalThreadStateException at runtime
}
}
/*OUTPUT in run() method, method completed. Exception in thread
"main" java.lang.IllegalThreadStateException
at java.lang.Thread.start(Unknown Source)
*/
check this
The just-arrived answer covers why you shouldn't do what you're doing. Here are some options for solving your actual problem.
This particular thread is doing some
calculation in the background, if I
don't do it in the thread than it's
done in the UI thread and the user has
an unreasonably long wait.
Dump your own thread and use AsyncTask.
Or create a fresh thread when you need it.
Or set up your thread to operate off of a work queue (e.g., LinkedBlockingQueue) rather than restarting the thread.
What you should do is create a Runnable and wrap it with a new Thread each time you want to run the Runnable.
It would be really ugly to do but you can Wrap a thread with another thread to run the code for it again but only do this is you really have to.
It is as you said, a thread cannot be started more than once.
Straight from the horse's mouth: Java API Spec
It is never legal to start a thread
more than once. In particular, a
thread may not be restarted once it
has completed execution.
If you need to re-run whatever is going on in your thread, you will have to create a new thread and run that.
To re-use a thread is illegal action in Java API.
However, you could wrap it into a runnable implement and re-run that instance again.
Yes we can't start already running thread.
It will throw IllegalThreadStateException at runtime - if the thread was already started.
What if you really need to Start thread:
Option 1 ) If a Thread needs to be run more than once, then one should make an new instance of the Thread and call start on it.
Can a Thread be started only once?
Yes. You can start it exactly once.
If so than what do I do if I want to run the thread again?This particular thread is doing some calculation in the background, if I don't do it in the thread than it's done in the UI thread and the user has an unreasonably long wait.
Don't run the Thread again. Instead create Runnable and post it on Handler of HandlerThread. You can submit multiple Runnable objects. If want to send data back to UI Thread, with-in your Runnable run() method, post a Message on Handler of UI Thread and process handleMessage
Refer to this post for example code:
Android: Toast in a thread
It would be really ugly to do but you can Wrap a thread with another thread to run the code for it again but only do this is you really have to.
I have had to fix a resource leak that was caused by a programmer who created a Thread but instead of start()ing it, he called the run()-method directly. So avoid it, unless you really really know what side effects it causes.
I don't know if it is good practice but when I let run() be called inside the run() method it throws no error and actually does exactly what I wanted.
I know it is not starting a thread again, but maybe this comes in handy for you.
public void run() {
LifeCycleComponent lifeCycleComponent = new LifeCycleComponent();
try {
NetworkState firstState = lifeCycleComponent.getCurrentNetworkState();
Thread.sleep(5000);
if (firstState != lifeCycleComponent.getCurrentNetworkState()) {
System.out.println("{There was a NetworkState change!}");
run();
} else {
run();
}
} catch (SocketException | InterruptedException e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
Thread checkingNetworkStates = new Thread(new LifeCycleComponent());
checkingNetworkStates.start();
}
Hope this helps, even if it is just a little.
Cheers

when the thread will release the lock on object?

I am new for multi-threading.currently i am learning lock and notify and synchronize block . i created a small program to check how wait and notify working with synchronize block , if i will not create any thread(i supposed main thread will get the lock). Below is the code for better understanding .
public class Problem1
{
public void waitForSignal() throws InterruptedException
{
Object obj=new Object();
synchronized (obj) {
obj.wait();
obj.notify();
}
}
public static void main(String args[]) throws InterruptedException
{
Problem1 pb=new Problem1();
pb.waitForSignal();
System.out.println("hello");//controll not come here
}
}
if i run the above program it will stuck. and control neither goes to notify() and nor it will exit the synchronize block. why code behave like this.
i tried to search on google and i found the below statement
wait( ) tells the calling thread to give up the monitor and go to
sleep until some other thread enters the same monitor and calls
notify( ).
what i understand from above statement that , for correct execution of my the program i have to create another thread, that will enter in the same monitor and interrupt the execution of the current lock holding thread. Please make me correct if i am wrong.
Please me to correct above code , so it will work fine without Stuck.
When you call wait, some other thread will have to acquire the lock on obj and call notify or notifyAll to signal the waiting thread to proceed. The easiest way to understand is in the context of the Consumer/Producer problem, and Oracle has a pretty good tutorial about that.
Thread interruption is something entirely different. It is a request for the interrupted thread to check its interrupted status and terminate processing. Brian Goetz has a great article about this in the context of properly handling InterruptedException.

Threads affected by Thread.yield()?

Here is a multi-threaded HelloWorld:
public class HelloWorld {
public static void main(String[] args) throws InterruptedException {
Thread myThread = new Thread() {
public void run() {
System.out.println("Hello World from new thread");
}
};
myThread.start();
Thread.yield();
System.out.println("Hello from main thread");
myThread.join();
}
}
As I understand, after the myThread.start(), there will be two threads running. One is the main thread, and the other is the newly-created myThread. Then, which thread is referred to in the Thread.yield()?
I checked the Java SE6 Doc, which says
Thread.yield(): Causes the currently executing thread object to
temporarily pause and allow other threads to execute
But in the codes, I can't see clearly what the currently excuting thread is, it looks that both threads are running at the same time.
Isn't it be more clear to say myThread.yield() instead of Thread.yield()? Does anyone have ideas about this?
With "current thread" in this context, the Javadoc means "the thread that called the method Thread.yield()"
In your case, this is the main thread that started your application.
As the Javadoc explains, there is normally no need to call Thread.yield(). It's not required to do anything:
A hint to the scheduler that the current thread is willing to yield
its current use of a processor. The scheduler is free to ignore this
hint.
It does seem to do something, at least up to Java 6 - couldn't find a reference for Java 7/8.
Windows:
The Hotspot VM now implements Thread.yield() using the Windows
SwitchToThread() API call. This call makes the current thread give up
its current timeslice, but not its entire quantum.
Linux:
Under Linux, Hotspot simply calls sched_yield(). The consequences of
this call are a little different, and possibly more severe than under
Windows.
Source: http://www.javamex.com/tutorials/threads/yield.shtml
The current thread is affected, i.e. the thread that calls the method.
Isn't it be more clear to say myThread.yield() instead of Thread.yield()? Does anyone have ideas about this?
No it isn't. It's a static method, and it's well-specified. In this case it would also convey the opposite of what actually happens.
But it's also pointless. yield() functions haven't done anything useful since the 16-bit part of Windows 98. Your thread will get rescheduled anyway as the scheduler sees fit.
The main thread will be affected.
You always can do Thread.currentThread().getName() to get the current thread name.
also you can do
Thread.currentThread().yield()
the other thread is running the run method until it finished and than exit.

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